.. who. staple. food of the Vedic Aryan was ?

A) Barley and rice. B) MMilk

The distance from point A to point B measures is 1,269.9 feet.

Trigonometric ratios for a right angled triangle are from the perspective of a particular non-right angle.

In a right angled triangle, two such angles are there which are not right angled(not of 90 degrees).

The slant side is called hypotenuse.

From the considered angle, the side opposite to it is called perpendicular, and the remaining side will be called base.

From that angle (suppose its measure is θ),

[tex]\sin(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of Hypotenuse}}\\\cos(\theta) = \dfrac{\text{Length of Base }}{\text{Length of Hypotenuse}}\\\\\tan(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of base}}\\\\\cot(\theta) = \dfrac{\text{Length of base}}{\text{Length of perpendicular}}\\\\\sec(\theta) = \dfrac{\text{Length of Hypotenuse}}{\text{Length of base}}\\\\\csc(\theta) = \dfrac{\text{Length of Hypotenuse}}{\text{Length of perpendicular}}\\[/tex]

Given;

The horizontal distance= 1196ft

Angle of elevation to the lighthouse’s=13°

Angle of elevation from point B =3 °

Now,

Distance from A to B = D;

D = Horizontal distance from B to LH - Horizontal distance from A to LH

Distance from A to B = 2237.9 feet - 968 feet ≈ 1269.9 feet;

Therefore, by the trigonometric ratios the distance from point A to point B, D will be 1,269.9feet;

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The elements of the set A are given as follows:

A = {January, February, March, April, May, June, July, August, September, October, November, December}.

The set A in the context of this problem is defined as follows:

A = {x | x is a month of the year.}

Hence the set A is composed by 12 elements, which are all the months of an year, as follows:

A = {January, February, March, April, May, June, July, August, September, October, November, December}.

The problem asks for all the elements of the set A, given as follows:

A = {x | x is a month of the year.}

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By using the composition of functions, we can find valid decompositions of c(x) using f(x) = [tex](x+1)^{1/3}.[/tex] and g(x) = x²

A function is a rule that takes an input value and produces an output value.

One way to do this is to use the composition of functions. The composition of two functions f(x) and g(x) is denoted as f(g(x)). This means that we first apply g(x) to the input, and then apply f(x) to the output of g(x). In other words, we first evaluate g(x), and then plug that result into f(x) to get the final output.

Using this concept, let's look at the first set of functions. We are given

=> c(x) = f ◦ g (x) = (x²) f(x) = [tex](x+1)^{1/3}.[/tex]

This means that c(x) is the composition of two functions, f(x) and g(x). We can see that g(x) = x², and f(x) = [tex](x+1)^{1/3}.[/tex] This is a valid decomposition of c(x).

Similarly, in the second set of functions, we have

=> c(x) = f ◦ g (x) = [tex](x+1)^{1/3}[/tex] g(x) = x² + 1.

This means that c(x) is the composition of two functions, f(x) and g(x). We can see that g(x) = x² + 1, and [tex](x+1)^{1/3}.[/tex] This is also a valid decomposition of c(x).

In the third set of functions, we have

=> c(x) = f ◦ g (x) = [tex](x+1)^{1/3}[/tex] g(x) = x + 1, and f(x) = [tex](x^2)^{1/3}=x^{2/3}[/tex]

This is another valid decomposition of c(x).

Finally, in the fourth set of functions, we have

=> c(x) = f ◦ g (x) = x² g(x) = [tex](x+1)^{1/3}[/tex], and f(x) = [tex]x^{2/3}[/tex].

This is yet another valid decomposition of c(x).

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Answer:

been a while, so I'd check w someone else too, but hope this helps

Step-by-step explanation:

So here we have a hole in a steel plate with a diameter of 1.166 cm. So we need to find the temperature at what temperature is the diameter of full equal to 1.165 cm. So you're given is D. I. That is equal to initial diameter. That is equal to 1.166 cm. and temporary Germany shirt temperature is equal to 23°C and DF is equal to 1.165 m. This is the final diameter. So you only need to find the value of P. F. So we know that whole diameter very nice linearly with And nature. So here we can say DFS equal to D. I multiplied by one plus alpha. They're dirty. Yeah, I'll find that coefficient of thermal expansion. So here we can say it this is for steel And the value of alpha is equal to 13, multiplied by 10, raised to -6. So D F. Is equal to B. I multiplied plus the I'm multiplied by alpha, multiplied by delta T. So here we can see it D F minus D. I. That is the initial final diameter minus initial diameter divided by D. I. Alpha. That is equal to delta P. So this will be where to tell 30. That is equal to -6.59717. multiplied by 10° to -5 divided by And there's do -6. So here the key Is equal to -65.9717 degree. So here P f minus T I is equal to minus 65.9717 degree. The T.F will be equal to 23 -65.9717. So therefore final temperature that this T.F is equal to -42.8717 degrees Celsius. So therefore this is the answer to the question. So here we can say hands, final temperature Is equal to -42.8717°C.

The probability that the sample proportion is less than 0.33 is approximately 0.7422.

The sample proportion of first-time customers can be modeled by a normal distribution with mean p, the true proportion of first-time customers, and standard deviation [tex]\sqrt{\frac{p(1-p)}{n}}[/tex], where n is the sample size.

In this case, p = 0.32, n = 80, and we want to find [tex]P(\hat{p} < 0.33)[/tex].

The standardized version of [tex]\hat{p}[/tex] is given by:

[tex]z = \frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

Substituting the values, we get:

[tex]z = \frac{0.33-0.32}{\sqrt{\frac{0.32(1-0.32)}{80}}} \approx 0.6579[/tex]

Using a standard normal distribution table (or a calculator or statistical software), we find that the probability of z being less than 0.6579 is approximately 0.7422.

Therefore, the probability that the sample proportion is less than 0.33 is approximately 0.7422.

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Answer:

chapter 1

Step-by-step explanation:

The volume of this cylinder is 1.5 times that of the cone. The cylinder volume is 452.4 in³ while the cone volume is 301.6 in³

An equation is an expression that shows how numbers and variables are linked together using mathematical operations such as addition, subtraction, multiplication and division.

A cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 9 inches. The height of the cone is 18 inches.

Radius of cone/cylinder = diameter/2 = 8 in/2 = 4 in.

Volume of cylinder = π * radius² * height = π * (4)² * 9 = 452.4 in³

Volume of cone = (1/3) * π * radius² * height = (1/3) * π * (4)² * 18 = 301.6 in³

The volume of this cylinder is 1.5 times that of the cone

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Answer:

There are 12 desktop computers and 20 laptop computers.

Step-by-step explanation:

32:2=16

8:2=4

16-4=12

16+4=20

Answer:

KL - slope 6/5 , length 7.8

LM - slope -5/6 , length 7.8

MN - slope 6/5 , length 7.8

NK - slope -5/6 , length 7.8

Step-by-step explanation:

square :3

PLEASE GIVE BRAINLIEST!
thank you and have a good day :)

Answer:

x = -5

Step-by-step explanation:

15 - 2x = -4(x+1) + 9

-4(x+1) can be distributed and simplified to -4x - 4

15 - 2x = -4x - 4 + 9

15 - 2x = -4x +5

-2x + 4x = 5 - 15

2x = -10

x = -5

Answer:

[tex]x=-5[/tex]

Step-by-step explanation:

Given

[tex]15-2x=-4(x+1)+9[/tex]

Simplify the right side by applying the distributive property.

[tex]15-2x=(-4*x)+(-4*1)+9[/tex]

[tex]15-2x=-4x-4+9[/tex]

Add [tex]-4[/tex] and 9.

[tex]15-2x=-4x+5[/tex]

Add [tex]4x[/tex] to both sides of the equation.

[tex]15-2x+4x=5[/tex]

Add [tex]-2x[/tex] and [tex]4x[/tex].

[tex]15+2x=5[/tex]

Subtract [tex]15[/tex] from both sides of the equation.

[tex]2x=-10[/tex]

Divide both sides of the equation by [tex]2[/tex].

[tex]x=-5[/tex]

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The ratio 8.64 : 37.76 as a fraction will be 27/118.

What precisely is ratio?

Ratios and proportions are typically described using fractions. When a fraction is presented as a:b, a ratio is shown, whereas a percentage suggests that two ratios are equal. In this case, a and b can be any two numbers. The ratio and proportion are two essential notions that serve as a foundation for understanding other concepts in mathematics and science.

In our daily lives, we apply the notion of ratio and proportion, such as in business when dealing with money or in cooking.

As a consequence, when b is greater than zero, the ratio specifies the connection between two variables, such as a:b. The 2:4 ratio, for example, is written as 2:4 = 1:2. 

Now,

Given ratio is  8.64 : 37.76

we can write this as 8.64/37.76

=864/3776

=432/1888

=216/944

=54/236

=27/118

Hence,

             The ratio 8.64 : 37.76, as a fraction will be 27/118.

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Answer:B

Step-by-step explanation:

area of triangle is (10*11)/2=55

area of semicircle is

[tex]d=2r\\r=10/2=5\\s=\pi r^{2} /2=25\pi /2=39.25\\39.25+55=94.25[/tex]

The two integers that are between -83 and +83 are -82 and +82.

What is integers ?

In mathematics, integers are a set of whole numbers that include positive numbers, negative numbers, and zero. Integers do not include fractional or decimal parts, they are the numbers in the set {..., -3, -2, -1, 0, 1, 2, 3, ...}. Integers are commonly used in many areas of mathematics, including arithmetic, algebra, and number theory.

There are multiple pairs of integers that are between -83 and 83.

Here are two examples:

-50 and 50: These are integers that are between -83 and 83. Any integer between -83 and -50, or between 50 and 83, is also between -83 and 83. We can represent this range on a number line as follows:

-83 -50 0 50 83

|----------------|----------------|----------------|----------------|

The integers between -83 and 83 are represented by the shaded portion of the number line.

-75 and 75: These are also integers that are between -83 and 83. Any integer between -83 and -75, or between 75 and 83, is also between -83 and 83. We can represent this range on a number line as follows:

-83 -75 0 75 83

|----------------|----------------|----------------|----------------|

The integers between -83 and 83 are represented by the shaded portion of the number line.

In general, any pair of integers that are equidistant from 0 and within a range of 83 from 0 will be between -83 and 83.

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The given differential equation:

y''' − 2y'' + y' = 2 − 24ex + 40e5x,

y(0) = 1/2, y'(0) = 5/2, y''(0) = −11/2

Therefore, the next solution is 13/2

Differential Equation:

In mathematics, a differential equation is an equation relating one or more unknown functions to their derivatives. In applications, functions usually represent physical quantities, derivatives represent rates of change, and differential equations define the relationship between them. These relationships are common.

Now,

Given differential equation is

y''' - 2y'' +y' = 2- 24eˣ +40e⁵ˣ                 ------------ (1)

Auxiliary equation is m³ - 2m² +2m = 0

Now,

   m(m² - 2m +2) = 0

⇒ m(m-1)² = 0

Therefore, m = 0,1,1

Therefore,

[tex]y_{c} = c_{1}+ c_{2} e^{x} + c_{2}x e^{x}[/tex]

Now, we have to find the particular solution by method of undetermined coefficient.

   [tex]y'_{y} = a + b(x^{2} e^{x} +2xe^{x} ) +5ce^{x}[/tex]

⇒ [tex]y''_{p} = a + bx^{2} e^{x} +2bxe^{x} +5ce^{x}[/tex]

⇒ [tex]y''_{p} = b(x^{2} e^{x} +2xe^{x}) + 2b(ex^{x}+ e^{x} +25ce^{x}[/tex]

⇒ [tex]y'''_{p} = bx^{2} e^{x} +6bxe^{x} +6be^{x} +125ce^{5x}[/tex]

Putting these values in differential equation (1), we get:

y'''(0) = 13/2

Complete Question:

Solve the given initial-value problem. y''' ? 2y'' + y' = 2 ? 24ex + 40e5x, y(0) = 1 2 , y'(0) = 5/ 2 , y''(0) = ? 13/ 2

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1. The height of the cone is, 22.18 mm.

2. The slant height is, 28.14 mm.

3. The ant crawl to get from the base of the cone to the top of the hill is, 28.14 mm.

In mathematics, Space occupied by three dimensional objects is called Volume. Basically it is a space within a closed region of every three dimensional object.

The volume of cone V = (1/3)πr²h

Given that,

The volume  = 8792 mm³

1. by using the formula to solve for h,

we get h = (3V)/(πr²).

Plugging in the values given,

we have h = (3(8792 mm³))/(π(20 mm)²) ≈ 22.18 mm.

Therefore, the height of the cone is approximately 22.18 mm.

2. it is known that, from the Pythagoras theorem

s² = h² + r²,

where s is the slant height, h is the height, and r is the radius.

Plugging in the values we found in part 1,

we have s² = (22.18 mm)² + (20 mm)² ≈ 791.88 mm².

Taking the square root of both sides, we get s ≈ 28.14 mm.

Therefore, the slant height is approximately 28.14 mm.

3. To find the distance the ant crawls to get from the base of the cone to the top of the hill, we need to find the length of the slant height.

Using the value we found in part 2,

the length of the slant height is approximately 28.14 mm.

Therefore, that is the distance the ant would crawl to get from the base of the cone to the top of the hill.

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The answers include the following:

This is referred to as the ratio of distance to the time in which the distance was covered and it is a scalar quantity.

From the graph, we can deduce that Runner A won the race because it attained a greater distance when compared to the time for all the other runners.

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7.21 × 10⁻⁷

Step-by-step explanation:

(6.94 × 10⁻⁷) + (2.7 × 10⁻⁸) = 7.21 × 10⁻⁷

Answer:

Shortage

Step-by-step explanation:

If the market price of a product is set below the equilibrium price, it will create a shortage of the product because the demand exceeds the supply.

The cash flow statement shows the cash the business has generated from operations, investments, and financing. Net cash flow is the name given to this sum.

In financial accounting, a cash flow statement, often called a statement of cash flows, is a financial statement that breaks down the analysis into operating, investing, and financing operations. It illustrates how changes in balance sheet accounts and income effect cash and cash equivalents.

A cash flow statement lists all of an organization's cash inflows from current operations and outside investment sources. The cash flow statement shows the cash the business has generated from operations, investments, and financing. Net cash flow is the name given to this sum.

Functionally speaking, cash flows are categorized according to the nature of the underlying transaction. The statement's main goal is to give pertinent details about the agency's cash inflows and outflows during a given time period.

Therefore, the correct answer is option d) Determine the change in cash.

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The relative frequency of sophomores at this high school is 39/128.

Relative frequency is the ratio of the considered sub group's count to the total count. (so its frequency of the considered sub group relative to the total frequency).

We are given that;

Total students=1152

Freshmen=391

Sophomores=351

Juniors=208

Seniors=202

Now, to find frequency of sophomores

=number of sophomores/total number of students

=351/1152

=117/384

=39/128

Therefore, the relative frequency will be 39/128.

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[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{25\% of 14}}{\left( \cfrac{25}{100} \right)14}\implies \text{\LARGE 3.5}[/tex]

The value of summation of ( x-2)² is 973

A summation, also called a sum, is the result of arithmetically adding numbers or quantities. A summation always contains a whole number of terms. There can be as few as two terms, or as many as a hundred, a thousand, or a million. Some summations contain infinitely many terms.

if

x (x-2) ( x-2)²

15 13 169

13 11 121

13 11 121

4 2 4

19 17 289

12 10 100

6 4 16

5 3 9

14 12 144

Therefore the summation of (x-2)²

= 169+121+121+4+289+100+16+9+144 = 973

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Answer:answer

Step-by-step explanation:

The value of summation of ( x-2)² is 973

Answer:

[tex] \frac {3}{8} + \frac{2}{8} = \frac{5}{8} = 1 \frac{3}{8} [/tex]

[tex] = \frac{5}{ \\ 8} = 1 \frac{3}{8} [/tex]

Answer: Since the speed of personal computers is expected to double every 18 months, we can use exponential growth to calculate the increase in speed over time. We can start by finding the growth factor, which is equal to 2 raised to the power of the number of doublings. In this case, the number of doublings over 6 years can be calculated as follows:

6 years / 1.5 years = 4 doublings

So the growth factor is:

2^4 = 16

This means that the speed of personal computers will be 16 times faster in 6 years compared to now.

Step-by-step explanation:

The area of the given composite figure with a side length of 14mm and an edge length of 8mm is 158.2 mm².

What is a composite figure?

A two-dimensional figure built up of fundamental two-dimensional shapes like triangles, rectangles, circles, semicircles, etc. is known as a composite shape or composite figure. A variety of forms that we encounter every day are composite figures that can be created from two or more fundamental figures.

The figure is given below.

From the figure, we can see that the sides of a triangle at the top and bottom are the same.

So the triangle cut from the bottom is placed at the top of the figure.

When the cut triangle is placed back at the bottom, we get a rectangle of length 14 mm and breadth 11.3 mm, as given below.

So the area of the given composite figure is the same as the area of the rectangle.

The area of the rectangle = length * breadth = 14 * 11.3 = 158.2 mm²

Therefore the area of the given composite figure is 158.2 mm².

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Answer:

= 7022cm

Step-by-step explanation:

The Perimeter of a rectangle =

[tex] = 2(l) + 2(w)[/tex]

From the question

L= 15.47m

w= 19.64m

therefore perimeter of a rectangle

=

[tex] = 2(15.47) + 2(19.64) \\ = 30.94 + 39.28 \\ = 70.22 m[/tex]

Also since rectangle are in centimetres

than if. 1 m = 100cm

than 70.22m = ?

therefore 70.22/1 = 100cm

=7022cm

therefore the Perimeter of a rectangle = 7022

Answer:

{30.1,30.7}

Step-by-step explanation:

[tex]\displaystyle CI=\bar{x}\pm z\frac{s}{\sqrt{n}}\\\\CI_{90\%}=30.4\pm1.645\biggr(\frac{5.5}{\sqrt{686}}\biggr)\\\\CI_{90\%}\approx30.4\pm 0.3\\\\CI_{90\%}=\{30.1,30.7\}[/tex]

Thus, we are 90% confident that the true amount of mmHg that is lowered will be between 30.1 and 30.7 mmHg.

Answer:

qr rs st qt are the line hope it helped