Dams on rivers are thicker at the bottom than the top because the majority of the force exerted on the dam is from the weight of the water pushing down on it. The water exerts more pressure on the lower part of the dam than the upper part, so the bottom of the dam must be stronger and thicker to withstand this pressure. Additionally, the bottom of the dam is also more susceptible to erosion from the water flow, so it also needs to be thicker to resist erosion. The thicker bottom also helps to counterbalance the hydrostatic pressure and provide stability to the dam.
Dams on the rivers are thicker at the bottom than that of the top because of the pressure which is exerted by liquids increases with depth. The walls are made thicker at the bottom, so that they can handle the pressure exerted by water.
What are dams?A dam is a barrier which stops or restricts the flow of surface water or underground streams on the planet. Reservoirs are created by dams not only to suppress floods but also to provide water for activities such as irrigation, human consumption, industrial use, aquaculture, and for the navigability.
Dams made on the rivers are generally thicker at the bottom than at the top because the pressure at a point inside a liquid depends on the depth from the free surface, therefore, the pressure is very high at the bottom of the dam. To tolerate this pressure, the walls of a dam are made thicker at the bottom. As we move upwards in the river, the pressure goes on decreasing, so the thickness of wall is made smaller and smaller. That is why, the walls of a dam are made thinner at the bottom .
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Refers to electricity that is produced at large power plants and transmitted great
distances through power lines to the end user.
When connecting asynchronous grids together or transferring significant amounts of electricity across long distances, high-voltage direct current (HVDC) is employed.
Why is electricity transported in this way over such distances, and how is it transmitted?Order to be transported across great distances via high-voltage transmission power lines, a transformer at a power plant raises the voltage of generated power by thousands of volts. Transmission lines, often called conductor bundles, are used to transport electric electricity from power plants to far-off substations.
Transmission lines use what kind of power?In an electric power system, transmission lines move electric energy from one location to another. They can transport direct current, alternating current, or a system that combines both. Also, overhead or subsurface wires can both carry electric current.
Which kind of electricity is most suitable for long-distance transmission?When opposed to alternating current transmission systems, high-voltage direct current (HVDC) technology has several benefits. For instance, it enables longer-distance bulk power transfer that is more effective.
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Two 3.3 kg physical science textbooks on a bookshelf are 0.33 m apart. What is the magnitude of the gravitational attraction between the books?
Answer:
below
Explanation:
You will need this equation:
F = G m1 m2 / r^2 G = gravitational constant = 6.6743 x10^-11 m^3/(kg s^2)
Plugging in the values
6.6743 x 10^-11 * 3.3 * 3.3 / ( .33^2) = 6.67 x 10 ^-9 N
Explain what is meant by resolution of an instrument
A. Explain the difference between procision and
accuracy of a measurment.
B. During experiment to find the stiffness constant of a
spring, the following graph was obtained. By comparing
the theoretical equation to that of a straight line y=mx+c find the string constant.
The resolution of an instrument is the smallest increment of measurement that can be reliably distinguished. It is a measure of the precision of the instrument.
What is resolution?
Resolution is the process of making a decision or reaching an agreement about a problem or dispute. It is the act of solving a problem or coming to an agreement. It is a process of defining the problem, gathering relevant information, analyzing the data, generating possible solutions, evaluating the solutions, and selecting the most appropriate option.
Accuracy is the degree to which a measured value corresponds to the true value of the quantity being measured. In the example given, the resolution of the instrument would be the smallest increment of the measurement of the stiffness constant of the spring that could be reliably distinguished. The accuracy of the measurement would be determined by comparing the theoretical equation to that of a straight line y=mx+c to find the string constant.
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A car accelerates uniformly from rest and
reaches a speed of 28.7 m/s in 6 s. The
diameter of a tire is 58 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slipping.
Answer in units of rev
The number of revolutions the tire makes in 6 s is
N = (58π)/(12π) = 4.83 rev.
What is revolutions?
Revolutions min physics is the study of the physical aspects of revolutions, including the forces and motions that cause them, the structures and systems that are produced in their wake, and the physical processes that lead to their initiation and termination. It has roots in the study of revolutions in the social sciences, but has developed its own principles and techniques to study physical phenomena related to revolutions. These techniques include the use of mathematical models, experiments, numerical simulations, and computer visualizations.
The linear velocity of a point on the tire's circumference is given by
v = (dπ)/t
where d is the diameter of the tire and t is the time.
Substituting d = 58 cm and t = 6 s, the linear velocity of a point on the tire's circumference is
v = (58π)/6 m/s.
The number of revolutions the tire makes in 6 s is given by
N = (v/2π)
Substituting v = (58π)/6 m/s, the number of revolutions the tire makes in 6 s is
N = (58π)/(12π) = 4.83 rev.
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A boy of weight 300n climbs to the top of a hill of height 20 m. The work done by the boy against the force of gravity is
Given,
W = 300N
S = 20 m
Work = force x Displacement.
= 300 x 20
= 6000 Joules.
P.S
Many people get fonfused as to why i took the goven weight as the force. Its because weight is also a force exerted by objects on earth.
ALL THE BEST
Formula for work:
[tex]w=Fd[/tex]
work(measured in joules) = force(measured in newtons) * distance(measured in meters)
__________________________________________________________
Given:
[tex]F=300N[/tex]
[tex]d=20m[/tex]
[tex]w=?[/tex]
__________________________________________________________
Finding work:
[tex]w=Fd[/tex]
[tex]w=300\times20[/tex]
__________________________________________________________
Answer:
[tex]\fbox{w = 6000 Joules}[/tex]
Which principle is used to make hydraulic machines work
Hydraulic machines work based on the principle of Pascal's Law, which states that the pressure exerted on a confined fluid is transmitted equally in all directions. This means that the pressure applied to one part of a confined fluid is transmitted throughout the entire fluid, regardless of the shape or size of the container. This principle is used in hydraulic machines to transfer force from one point to another by using a fluid, usually oil or water, in a closed system of pipes or cylinders.
The force applied to the small piston of a hydraulic machine is transmitted through the fluid, and it is amplified on the larger piston due to the difference in area between the two pistons. This allows a small force to be amplified into a much larger force, making the machine able to lift or move heavy loads with minimal effort.
This is the basic principle that makes hydraulic systems, such as car brakes, lift, cranes, excavators, and many other machines work.
Dimension of G = fr² /mm
Our missions to Mars have allowed us to observe the skies from the surface of another planet. From a martian point of view, what do you predict we would see in this geocentric solar system, but not in our heliocentric solar system?
If we observe the skies from the surface of another planet, we can see heliocentric solar system, that is, all the planets are rotating around the sun.
What is heliocentric solar system?The Heliocentric model is an astronomy theory that places the Sun at the centre of the cosmos, with the Earth and other planets revolving around it. In the past, geocentrism, which put the Earth at its center, was countered by heliocentrism.
Aristarchus of Samos first offered the idea that the Earth revolves around the Sun in the third century BC after being influenced by a theory put forth by Philolaus of Croton (c. 470 – 385 BC).
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Calculate the magnitude of the resultant moment exerted at O, for the configuration given in the Figure. The magnitude of F1 is F1=4N. Provide your answer in Newtons.meters (N.m).
The magnitude of the resultant moment exerted at O, for the configuration given in the Figure is 0.63 Nm.
What is the magnitude of the resultant displacement?
The magnitude of the resultant displacement of the object is calculated by applying the formula of Pythagoras theorem as shown below.
d = √ (dx² + dy² )
where;
dx is the displacement of the object is x directiondy is the displacement of the object is y directiond = √ (0.05² + 0.15² )
d = 0.158 m
The magnitude of the resultant moment exerted at O, for the configuration given in the Figure is calculated by applying the formula for torque or moment.
τ = Fd
where;
F is the applied forced is the resultant displacement at point Oτ = ( 4 N ) x ( 0.158 m )
τ = 0.63 Nm
Thus, the resultant moment is a function of the applied force and the resultant displacement.
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A student lifts a 4.10-kg box of books vertically from rest with an upward force of 52.7 N. The distance of the lift is 1.60 m. Find: (a) the work done by the student. (b) the work done by gravity. (c) the final speed of the box
The work done in each case is;
a) 84.32 J done by the student.
b) 64.3 J done by gravity as described.
c)2.77 m/s is the final speed of the box.
What is the work done?We know that the work that is done is the product of the mass and the acceleration of the object. The work that is done by gravity would depend on the depend on the height of the object that is in question.
Now we know that;
a) Work done by the student = Force * distance
= 52.7 N * 1.60 m
= 84.32 J
b) Work done by gravity = mass * acceleration due to gravity * height
= 4.1 Kg * 9.8 m/s^2 * 1.6 m
= 64.3 J
c) The speed of the box;
64.3 J = 1/2mv^2
v = √2 * 64.3/4.1
v = 2.77 m/s
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4 points
A hydraulic system contains one small piston with a area of 5.33 square inches and one large piston with an area of 10 square inches. If a force of 70 pounds
is applied to the small piston, what will the system pressure be?
A: 99.7 psi
B: 640.3 psi
C: 1,822 psi
D: 13.13 psi
Answer:
C
Explanation:
The system pressure will be equal to 70 pounds divided by the area of the small piston, which is 5.33 square inches. This gives a pressure of 13.13 psi (pounds per square inch).
An object is dropped off a cliff . Assume there is no air resistance, so it accelerates at -9.8m/sec/sec what is the velocity at the end of 2 seconds?
The velocity of an object dropped off a cliff can be calculated using the equation:
v = v0 + at
Given:
v0 = 0 m/s (initial velocity)
a = -9.8 m/s^2 (acceleration due to gravity)
At the end of 2 seconds:
t = 2 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 2 s = -19.6 m/s
The velocity of the object at the end of 2 seconds is -19.6 m/s, downward.
At the end of 5 seconds:
t = 5 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 5 s = -49 m/s
The velocity of the object at the end of 5 seconds is -49 m/s, downward.
At the end of 12 seconds:
t = 12 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 12 s = -117.6 m/s
The velocity of the object at the end of 12 seconds is -117.6 m/s, downward.
It's worth mentioning that in the case of an object falling freely under the influence of gravity alone, the velocity will continue to increase
Describing Physical Changes
Define kinetic energy and thermal energy. Describe what
happens to each as the temperature of a substances
increases.
During Physical Changes, kinetic energy and thermal energy. of the material changes as well as temperature of the substances also changes.
What is Physical Changes?Physical changes are those that affect a chemical substance's form but not its chemical content. Physical changes may normally be used to separate compounds into chemical elements or simpler compounds, but they cannot be used to separate mixtures into their component compounds.
When something changes physically but not chemically, it is said to have undergone a physical change. Physical means can be used to undo a physical alteration.
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Which one is correct?
The correct description of X is that it is a neutron (option C).
What is nuclear reaction?A nuclear reaction is a process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and/or subatomic particles in which the number of protons and/or neutrons in a nucleus changes.
In a nuclear reaction, the reaction products may contain a different element or a different isotope of the same element.
Certain particles are emitted or reacted with in a nuclear reaction. Examples of those particles are neutron, alpha particle, electron.
A neutron is a subatomic particle forming part of the nucleus of an atom and having no charge. A neutron posseses a mass number of 1 and atomic number of 0.
According to this question, uranium with mass number 235 and atomic number 92 undergoes a nuclear reaction with a particle with mass number 1 and atomic number 0.
The particle represented by X in this reaction is a neutron.
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two Forces one of 12 N and another 24 N acts on abody in such away that they make angie 90° with each other Find the resultant a = (1/4)b=(7/5)and C=(-9/2)
According to the question of forces, the resultant a will be 28N.
What is resultant?
Resultant is a term that is used to describe the combined effect of two or more forces acting on an object. It is the vector sum of the individual forces. Resultant force is the single force that replaces the action of several forces acting on a body. Calculating the resultant force of multiple forces can be done by using the components of the forces in the x and y directions, then using basic vector addition to calculate the resultant force. The resultant force is the combination of the individual forces and the magnitude and direction of the resultant force is determined by the direction and magnitude of the individual forces.
The resultant force of the two forces is equal to the square root of the sum of the squares of the magnitudes of the two forces.
Therefore, the resultant force is equal to √(12^2 + 24^2) = 28 N.
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In a position time graph, we plot the _______ of am object or a person against elapsed ________. The person's position is the distance from the __________ ____________. The shape of the graph shows the kind of motiin.
In a position-time graph, we plot the position of an object or a person against elapsed time. The person's position is the distance from the reference point. The shape of the graph shows the kind of motion.
What is a position time graph?A position-time graph is a type of graph used to represent the motion of an object over time. It plots the position of an object on the y-axis and the time elapsed on the x-axis. The position is usually represented as a distance from a reference point, such as the origin of a coordinate system.
The shape of the graph can provide insight into the nature of the object's motion. For example, a straight line on the position-time graph indicates that the object is moving at a constant velocity. A parabolic shape of the graph shows that the object is accelerating, and a curved line on the graph shows that the object is moving at a non-constant velocity.
It's a powerful tool to understand the motion of an object and its dynamics, it allows you to see the relationship between position, velocity and acceleration, and how they change over time.
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A radioactive substance of mass 800g has half life of 4 years, how many years those it have with only 8g undecayed
It will take approximately 8 years for a radioactive substance of mass 800g to have 8g undecayed.
What is the half-life of the radioactive substance in question?The half-life of the radioactive substance in question is 4 years. The half-life of a radioactive substance is the amount of time it takes for half of the original amount of the substance to decay. In this case, after 4 years, half of the initial 800g of the radioactive substance will have decayed, leaving 400g remaining. This means that the decay rate of the radioactive substance is 50% per 4 years. The half-life is a constant for a specific radioactive substance and it does not change, this means that if we wait another 4 years, half of the remaining 400g will decay leaving only 200g, and so on.
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The world’s tallest lighthouse is located in Japan and is 106 m tall. A winch that provides 3.00 × 10^2 W of power is used to raise 14.0 kg of equipment to the lighthouse top at a constant velocity. How long does it take the equipment to reach the lighthouse top?
To find out how long it takes for the equipment to reach the lighthouse top, we can use the work-energy principle which states that the work done on an object is equal to the change in its kinetic energy. Since the velocity is constant, the change in kinetic energy is zero.
Therefore, the work done on the object is equal to the force required to lift it multiplied by the distance it is lifted. We can use the formula:
Work = force x distance
We know that the work done is equal to the power multiplied by the time, so we can use this formula as well:
Work = Power x time
We can use these two formulas to find the time it takes to raise the equipment to the lighthouse top:
force = mg = (14.0 kg)(9.8 m/s^2) = 137.2 N
distance = 106 m
Work = force x distance = 137.2 N x 106 m = 14,532.8 J
Power = 3.00 x 10^2 W
We can now substitute these values into the second formula:
Work = Power x time
14,532.8 J = 3.00 x 10^2 W x time
time = Work / Power = (14,532.8 J) / (3.00 x 10^2 W) = 484.4 seconds
So, it takes the equipment approximately 484.4 seconds (8 minutes and 4.4 seconds) to reach the lighthouse top.
I hope this helps :)
Two smooth round objects of equal density are kicked with the same amount of force. One accelerates faster and travels further than the other. Explain why and list a real-life explains of this scenario. (No, one object does not hit a wall or anything…but good try)
Answer:
The object that accelerates faster and travels further is likely to have a smaller mass or a larger surface area.
A real-life example of this scenario could be a soccer ball and a bowling ball. Both are smooth, round objects of equal density, but the soccer ball has a smaller mass and larger surface area, which allows it to accelerate faster and travel further when kicked with the same amount of force.
Find the value of T₁ and T2 in the figure below. A t 27° T₁ B BRAJE 38° T₂ C 12g N Hint: Apply triangle of forces rule or sine and cosine rules
Answer:
The tension in [tex]T_1[/tex] is 0.1024 Newtons.
The tension in [tex]T_2[/tex] is 0.1157 Newtons.
Explanation:
Lets create a free body diagram showing all of the forces; we need to show the vertical and horizontal components of the tension.
I will attach a picture of my free body diagram. Notice I created 2 new triangles with the adjacent angles of angle A and C from the original picture.
Lets make a list of all the variables we have now. Also lets write down the information we are given.
[tex]A=27\\C=38\\m=12\\g=9.81\\W\\T_{1} \\T_{1x} \\T_{1y}\\T_{2} \\T_{2x} \\T_{2y} \\[/tex]
In this situation the sum of of the vertical tension components must support the weight. To find the vertical components we can use the SIN function.
[tex]sin(x)=\frac{O}{H} \\O=Hsin(x)[/tex]
Therefore we can write that the sum of the forces in the y direction is
[tex]\sum F_y=T_1sin(A)+T_2sin(C)=W[/tex]
This system is in equilibrium; the object should not move along the x-axis. Therefore, the horizontal components of [tex]T_1[/tex] and [tex]T_2[/tex] must then equal each other. To find the horizontal components we can use the COS function.
[tex]cos(x)=\frac{A}{H} \\A=Hcos(x)[/tex]
Therefore we can write that the sum of the forces in the x direction is
[tex]\sum F_x=T_1cos(A)=T_2cos(C)[/tex]
Now we have to equations to help us solve the problem.
[tex]T_1cos(A)=T_2cos(C)[/tex]
[tex]T_1sin(A)+T_2sin(C)=W[/tex]
We do not know the numerical values of [tex]T_1[/tex] and [tex]T_2[/tex] so we will have to manipulate algebraically to solve them.
In the first equation lets solve for [tex]T_1[/tex].
[tex]T_1cos(A)=T_2cos(C)[/tex]
Divide both sides by [tex]cos(A)[/tex].
[tex]T_1=\frac{T_2cos(C)}{cos(A)}[/tex]
Separate the right side into two fractions.
[tex]T_1=\frac{T_2}{1} *\frac{cos(C)}{cos(A)}[/tex]
Use the reciprocal trig identity for cosine.
[tex]sec(x)=\frac{1}{cos(x)}[/tex]
[tex]T_1=\frac{T_2}{1} *cos(C)}*sec(A)[/tex]
[tex]T_1=T_2*cos(C)}*sec(A)[/tex]
Now insert our answer for [tex]T_1[/tex] into the second equation.
[tex]T_2*cos(C)}*sec(A)*sin(A)+T_2*sin(C)=W[/tex]
Solve for [tex]T_2[/tex]. Lets replace each trig function with its own variable to make this easier.
[tex]T_2*cos(C)}*sec(A)*sin(A)+T_2*sin(C)=W[/tex]
[tex]cos(C)=x\\sec(A)=y\\sin(A)=z\\sin(C)=u[/tex]
[tex]T_2*x*y*z+T_2*u=W\\T_2xyz+T_2u=W[/tex]
Now lets solve for [tex]T_2[/tex].
Factor [tex]T_2[/tex] out of each term.
[tex]T_2(xyz)+T_2(u)=W[/tex]
Factor [tex]T_2[/tex] out of each term.
[tex]T_2(xyz+u)=W[/tex]
Divide each side by [tex]xyz+u[/tex].
[tex]T_2=\frac{W}{xyz+u}[/tex]
Lets substitute the trig functions back in for the variables
[tex]T_2=\frac{W}{cos(C)*sec(A)*sin(A)+sin(C)}[/tex]
[tex]W[/tex] is the weight.
The formula for weight is [tex]W=mg[/tex]. Where [tex]m[/tex] is the mass in kilograms.
12 grams is 0.012 kilograms.
[tex]W=0.012*9.81[/tex]
[tex]W=0.11772[/tex]
Numerical Evaluation
Lets evaluate [tex]T_2[/tex].
[tex]T_2=\frac{0.11772}{cos(38)*sec(27)*sin(27)+sin(38)}[/tex]
[tex]T_2=0.11573[/tex]
Lets evaluate [tex]T_1[/tex].
[tex]T_1cos(A)=T_2cos(C)[/tex]
[tex]T_1*cos(27)=0.11573*cos(38)\\T_1=0.10235443[/tex]
A rating/review would be much appreciated.
Answer:
T₁ = 102.25 N (2 d.p.)
T₂ = 115.61 N (2 d.p.)
Explanation:
The diagram shows a body of mass 12 kg (weight = 12g N) held in equilibrium by two light, inextensible strings. One string makes an angle of 27° with the positive horizontal and the other string makes an angle of 38° with the negative horizontal.
The body is in equilibrium, so both the horizontal and vertical components of the forces must sum to zero.
Resolving horizontally, taking (→) as positive:
[tex]\implies -T_1 \cos (27^{\circ})+T_2 \cos (38^{\circ})=0[/tex]
[tex]\implies T_1 \cos (27^{\circ})=T_2 \cos (38^{\circ})[/tex]
[tex]\implies T_1=\dfrac{T_2 \cos (38^{\circ})}{ \cos (27^{\circ})}[/tex]
Resolving vertically, taking (↑) as positive:
[tex]\implies T_1 \sin(27^{\circ})+T_2 \sin(38^{\circ})-12\text{g}=0[/tex]
[tex]\implies T_1 \sin(27^{\circ})+T_2 \sin(38^{\circ})=12\text{g}[/tex]
Substitute the found expression for T₁ into the second equation and take g = 9.8 ms⁻²:
[tex]\implies \left(\dfrac{T_2 \cos (38^{\circ})}{ \cos (27^{\circ})}\right) \sin(27^{\circ})+T_2 \sin(38^{\circ})=12\text{g}[/tex]
[tex]\implies T_2 \cos (38^{\circ})\tan(27^{\circ})+T_2 \sin(38^{\circ})=12\text{g}[/tex]
[tex]\implies T_2 \left(\cos (38^{\circ})\tan(27^{\circ})+ \sin(38^{\circ})\right)=12\text{g}[/tex]
[tex]\implies T_2 =\dfrac{12\text{g}}{\cos (38^{\circ})\tan(27^{\circ})+ \sin(38^{\circ})}[/tex]
[tex]\implies T_2=115.614550...\:\text{N}[/tex]
Substitute the found value of T₂ into the equation for T₁ and take g = 9.8 ms⁻²:
[tex]\implies T_1=\dfrac{\left(\dfrac{12\text{g}}{\cos (38^{\circ})\tan(27^{\circ})+ \sin(38^{\circ})}\right) \cos (38^{\circ})}{ \cos (27^{\circ})}[/tex]
[tex]\implies T_1=102.250103...\text{N}[/tex]
Therefore, the value of T₁ and T₂ in the given diagram is:
T₁ = 102.25 N (2 d.p.)T₂ = 115.61 N (2 d.p.)A 3kg book is resting high on a book shelf. If the book has 73.5 J of potential energy, how high is the shelf?
_____ m
If this book slipped off the shelf and fell all the way to the ground, how much kinetic energy would it have the instant it hit the ground (if we ignore air resistance)?
____
Answer:
below
Explanation:
Potential Energy = mgh
73.5 = 3 kg * 9.81 m/s^2 * h
h = 2.5 m
when the book hits it will have the PE all converted to KE = 73.5 J
The front 1.20 m of a 1,350-kg car is designed as a "crumple zone" that collapses to absorb the shock of a collision. (a) If a car traveling 27.0 m/s stops uniformly in 1.20 m, how long does the collision last?
Answer:
Explanation:(a) If a car traveling 22.0 ms stops uniformly in 1.20 m, how long does the collision last?(b) What is the magnitude of the average force on the car?(c) What is the magnitude of the acceleration of the car? Express the acceleration as a multiple of the acceleration of gravity.
Help, I have no clue what the answer is
Answer:
A. 1
B. n
C. 0
Explanation:
The numbers to the right of the symbols represent the [tex]\frac{mass\ number}{atomic\ number}[/tex]. Recall that the mass number is the sum of the number of neutrons and the number of protons in an atom's nucleus. The atomic number is the number of protons in an atom's nucleus. For this equation to be true, both sides must agree on the total number of subatomic particles. So, for the mass number:
[tex](1+235)=(99+133+4A)\\236=232+4A\\4=4A\\1=A[/tex]
This means the sum of the protons and neutrons in the particle is 1.
For the atomic number:
[tex](0+92)=(41+51+4C)\\92=92+4C\\0=4C\\0=C[/tex]
This means there are 0 protons in the particle.
The two derived values indicate that the particle is a lone neutron. So, the answer to B is n.
Let to the right be the positive direction.
A 25.8 g marble sliding to the right at 21.0
cm/s overtakes and collides with a 12.4 g
marble moving in the same direction at 13.8
cm/s. After the collision, the 12.4 g marble
moves to the right at 23.9 cm/s.
Find the velocity of the 25.8 g marble after
the collision.
Answer in units of cm/s. Answer in units
of cm/s.
The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.
What is the velocity of the 25.8 g marble after the collision?
The velocity of the 25.8 g marble after the collision is calculated as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of 25.8 g marblem₂ is the mass of 12.4 g marbleu is their initial speedsv is their final speedsThe final velocity of the 25.8 g marble after the collision is calculated as;
( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )
712.92 = 296.36 + 25.8v
25.8v = 416.56
v = 416.56 / 25.8
v = 16.15 cm/s
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can you help me with that?
Answer:
no I can’t help you
Explanation:
I can’t help you because I don’t know the answer
1. A lever system of velocity ratio 45 overcomes a load of 4500 N when an effort of 105 N is applied to it. Calculate:Its efficiency.
Efficiency= mechanical advantage ÷velocity ratio
Efficiency= M.A/V.R
and M.A was not given
to calculate M.A= force of object (Fb)÷ effort to overcome the force (Fa)
i.e M.A= Fb/Fa
4500/105=42.9
Efficiency=M.A/V.R
=42.9/45
=0.95
The efficiency of the lever system is approximately 4285.71%. Efficiency greater than 100% is not physically possible, so there may be an error in the data provided, or the lever system might not be operating ideally.
To calculate the efficiency of the lever system, we can use the formula:
Efficiency = (Output force / Input force) * 100%
Given that the velocity ratio is 45, the output force (load) is 4500 N, and the input force (effort) is 105 N.
Efficiency = (4500 N / 105 N) * 100% ≈ 4285.71%
In real-world situations, factors like friction and other losses would contribute to the efficiency being less than 100%.
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There is a +1.0 mC charge at the origin and a +3.0 mC charge at (x, y) =(2.0 m, 0), a. Find the force on the +3.0 mC charge. b. Calculate the electric field at (x, y) = (1.00 m, 0.50 m). c. Find a point where the electric field is zero (other than at infinity). d. What is the potential at the point found in part c?
a. The force on the +3.0 mC charge is 1.35 x 10^-6 N.
b. The electric field at (x, y) = (1.00 m, 0.50 m) is 5.49 x 10^5 N/C
c. The point where the bc is zero (other than at infinity) is located on the line that connects the two charges and at the midpoint of the line segment connecting them.
d. The potential at the point found in part c is at point zero
What is electric field?An electric field is described as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.
a. we need to use Coulomb's law, which states that the force between two charges is given by:
F = k * (q1 * q2) / r^2
F = k * (q1 * q2) / r^2 = 8.99 x 10^9 Nm^2/C^2 * (1.0 x 10^-3 C * 3.0 x 10^-3 C) / (2.0 m)^2 = 1.35 x 10^-6 N
b. To calculate the electric field at (x, y) = (1.00 m, 0.50 m), we use the equation for the electric field due to a point charge:
E = k * q / r^2
The distance from the point charge is:
r = sqrt((1.00 m - 2.0 m)^2 + (0.50 m - 0 m)^2) = sqrt(3.25 m^2) = 1.8 m
Therefore, the electric field at (x, y) = (1.00 m, 0.50 m) is:
E = k * q / r^2 = 8.99 x 10^9 Nm^2/C^2 * (3.0 x 10^-3 C) / (1.8 m)^2 = 5.49 x 10^5 N/C
c. This point is located on the line that connects the two charges and at the midpoint of the line segment connecting them.
d. At the point found in c, the electric field is zero, so the work done to move a test charge from infinity to that point is also zero.
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) The graph in the figure shows the position of a particle as a function of time as it travels along the x-axis.
What is the average velocity of the particle between t = 2.0 s and t = 4.0 s?
The average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.
What is average velocity?Average velocity is the rate of change of an object's position, expressed as a vector quantity that tells both the speed and direction of the object's motion.
The average velocity of the particle between t = 2.0 s and t = 4.0 s can be calculated by taking the difference in the x-position of the particle at t = 4.0 s and t = 2.0 s, and dividing it by the difference in the time.
The x-position of the particle at t = 2.0 s is 4 m and the x-position of the particle at t = 4.0 s is 8 m.
Therefore, the difference in the x-position is 8 m - 4 m = 4 m.
The difference in time is 4.0 s - 2.0 s = 2.0 s. Therefore, the average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.
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This is actually science
PLEASE ASAAAAAPJust do the last part
Fill in the last one please
Explanation:
The distance to the epicenter (km) can be calculated using the equation:
Distance = (S-P arrival time (minutes) / P-wave velocity (km/s)) x (60 seconds/minute)
Using the information provided, the distance to the epicenter would be:
Distance = (8.08 - 8.07) / 5.8 x (60) = approximately 1300 km
It is given that the distance to epicenter is 1300km using the chart.
A student wants to investigate the motion of a ball by conducting two different experiments, as shown in Figure 1 and Figure 2 above. In Experiment 1, the student releases a ball from rest and uses a slow-motion camera to film the ball as it falls to the ground. Using video analysis, the student is able to plot the ball’s horizontal position x and vertical position y as a function of time t . In Experiment 2, the student horizontally rolls the same ball off a table, and uses video analysis to plot the ball’s horizontal position x and vertical position y as a function of time t starting from the instant the ball leaves the table. The graphs from each experiment are shown above along with each graph’s best-fit curve line.
The student can conclude that in Experiment 1, the ball is following a parabolic path, demonstrated by the best-fit curve line. In Experiment 2, the ball is following a linear path, demonstrated by the best-fit curve line.
What is curve?
A curve is a line in a two-dimensional plane that is bent or curved. It is often used to describe the shape of objects or mathematical functions. It is often used to study changes in data over time and to understand the behavior of functions and equations. Curves can be described using a variety of mathematical equations and equations can be used to predict the behavior of a curve. Additionally, curves can be used to describe the motion of physical objects and to help visualize the relationships between the objects.
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