How does the mother get nutrients and oxygen to the embryo?
Answer:
Oxygen and nutrients from the mother's blood are transferred across the placenta to the fetus through the umbilical cord. This enriched blood flows through the umbilical vein toward the baby's liver. There it moves through a shunt called the ductus venosus. This allows some of the blood to go to the liver.
the major factor in the development of a constitution is
Answer:
Below are some of the important dates that led to the creation of the Constitution: 1775 — The Revolutionary War between the Colonies and Britain begins. ... 1781 — The last battle of the Revolutionary War takes place; the 13 states set up a federal government under laws called the Articles of Confederation.
Explanation:
please give me a heart
Explain in detail what happens to the motion of particles in a metal tray as it is placed into the hot oven
Answer:
The particles gain more kinetic energy and begin to move faster
Explanation:
Based on the kinetic theory of matter, matter is made up of particles, which are in a constant state of random motion.
This means that the tiny particles of the metal tray are continuously moving about. Furthermore, for the particles to move about, they need energy. This can come in various forms. It can be chemical, kinetic, or light, etc.
Once the metal tray is placed in the oven the particles get some kinetic energy from the heat of the hot oven. The metal particles begin to vibrate about their mean position a lot quicker than ever before. This leads to an increase in the temperature of the metal tray.
If this continues, they will be able to break the metallic bonds holding them together, causing a change of state from solid to liquid, which we will be able to perceive as the melting of the tray.
Helpppp
What occurs when someone places an ice pack on an injured ankle?
A. Conduction causes ice pack to lose thermal energy.
B. Conduction causes the ankle to gain thermal energy.
C. Cold from the ice pack is transferred to the ankle.
D. Heat from the ankle is transferred to the ice pack.
Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes .
Complete question :
Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes . Find how much petrol he uses using the information in the table.
Requires table to answer question is attached below
Answer:
2.64 gallons
Explanation:
Given that:
First 13 miles takes 13 minutes
Average rate = 13 miles / 13 minutes = 1mile/minute ; Average rate per hour = (1 mile /minute * 60) = 60 miles /hour
If average speed = 65mph or less ; 50 miles per gallon (it uses 1 gallon for 50 miles)
Hence, since first phase rate is 60 mph,; then miles per gallon is 50 miles
Therefore,gallon of petrol used for 13 miles will be :
13 miles / 50 mpg = 0.26 gallons
2nd phase:
Average rate of 68 mph for 1 hour 24 minutes (1.4 hours)
Here, miles per gallon = 40 (that is; 40 miles for 1 gallon).
Total distance covered = 68 * 1.4 = 95.2 miles
Petrol used = 95.2 miles / 40 mpg = 2.38 gallons
Hence,
Total petrol used : (0.26 + 2.38) = 2.64 gallons
The number of planets, besides the earth, that are visible to the unaided eye is
Which is an example of a physical change?
cake baking
gasoline combusting
salt dissolving
iron rusting
Answer:
salt dissolving
Explanation:
hope it helps
the maximum range of a projectile is 2÷√3 times its actual range what is the angle of the projection for the actual range
Answer:
The actual angle is 30°
Explanation:
Equation of projectile:y axis:[tex]v_y(t)=vo*sin(A)-g*t[/tex]
the velocity is Zero when the projectile reach in the maximum altitude:
[tex]0=vo-gt\\t=\frac{vo}{g}[/tex]
When the time is vo/g the projectile are in the middle of the range.
x axis:[tex]d_x(t)=vo*cos(A)*t\\[/tex]
R=Range
[tex]R=d_x(t=2*\frac{vo}{g})[/tex]
[tex]R=vo*cos(A)*2\frac{vo}{g} \\\\R=\frac{(vo)^{2}*2* sin(A)cos(A)}{g} \\\\R=\frac{(vo)^{2} sin(2A)}{g}[/tex]
**sin(2A)=2sin(A)cos(A)
The maximum range occurs when A=45°(because sin(90°)=1)The actual range R'=(2/√3)R:Let B the actual angle of projectile
[tex]\frac{vo^{2} }{g} =(\frac{2}{\sqrt{3} }) \frac{vo^{2} *sin(2B)}{g}\\\\1= \frac{2 }{\sqrt{3}} *sin(2B)\\\\sin(2B)=\frac{\sqrt{3}}{2}\\\\[/tex]
2B=60°
B=30°
Can y’all help me with Number 3 please for right now
Describe the sequence of mechanical energy events that lets you hear the
muffled sound of a radio from inside your neighbor's closed house.
Answer:
Starting from the beginning.
There is a radio signal that is received by the radio.
The radio interprets the signal and produces a current in response to it.
That current goes to a membrane that oscillates producing sound, the oscillation of the membrane is the first mechanical energy event here.
These oscillations can travel in material mediums, for example, the air. Then there is a production of waves (soundwaves) that travel in the air (second event).
Those waves now hit the wall that separates you and your neighbor, as the wall is made of a material, the soundwaves can travel through it, but they will be dispersed (a part of the waves rebounds on the wall, and another part is dissipated as the wave travels through the wall), there is also a transmitted part of the wave, that is now in your house. (this change of medium will be the third event). Now only the lower frequencies survive, this is why the sound is "muffled".
Those remaining frequencies now travel in your house, and when they reach your ear, your ear sends a signal to your brain and your brain interprets them as sound. The wave interacting with your ear will be the fourth and last mechanical energy event.
I load a 0.4 kg marble into a slingshot and shoot it directly upward by applying a 36.2 N force
stretching it a distance of 10 cm. How fast is the marble traveling when it is initially released from
the slingshot? How high does the marble go?
Answer:50mph
Explanation:
A brass rod is encased in aluminum. What happens to the speed of a sound
wave when it passes through the rod and moves from the brass into the
aluminum?
Aluminum
Copper
Lead
Brass
(70% Cu,
30% Zn)
6,420
4,700
5,010
1,960
Speed of
sound
(m/s)
A. Its speed decreases.
OB. Its speed increases.
ООО
O C. Its speed falls to zero.
OD. Its speed stays the same.
PREVIOUS
Answer:
B. its speed increases
Explanation:
A brass rod is encased in aluminium. The speed of a sound wave in this decreases when it moves from the aluminium into the brass medium. Thus, the correct option is A.
What factors affect speed of sound?Sound travels in different mediums in the form of waves. The speed of sound is the speed with which the sound wave travels in a medium. The speed of the wave depends on the density and the elasticity of the medium through which the sound waves travel. In general, the sound wave travels faster in the liquid mediums in comparison to the gas medium and these are quicker in solid mediums than in liquid mediums. Thus, the greater the elasticity and the lower the density of the waves, the faster the sound waves travel in that medium.
The speed of sound in aluminium is 5100m/s and in the brass medium, it is 6,923. So, if the sound wave is moving from aluminum metal to the brass medium, we can clearly observe that there is decrease in the speed of sound. So, we can say here that is the speed is decreases.
Therefore, the correct option is A.
Learn more about Sound here:
https://brainly.com/question/29707602
#SPJ5
The higher temperature, the more blank particles have
Answer:Stronger they are
(I think...)
demonstrate how you can derive our 9.8m/s^2 from Newton's general law of gravity.
Answer:
[tex]g=G\frac{m_E}{r^2}[/tex]
Explanation:
Using Newton's Law of Universal Gravitation, we can write:
[tex]F=G\frac{m_E}{r^2}[/tex], where [tex]G[/tex] is gravitational constant [tex]6.67\cdot 10^{-11}[/tex], [tex]m_E[/tex] is Earth's mass, and [tex]r[/tex] is Earth's radius.
Using these measured values, we have:
[tex]F=6.67\cdot 10^{-11}\frac{5.97\cdot 10^{24}}{(6.38\cdot10^6)^2},\\g\approx \fbox{$9.8\:\mathrm{m/s^2}$}[/tex].
900n pushes a wedge 0.10 m into a log, if the work done on the log is 50j what is the efficiency of the wedge
Answer:
100
Explanation:
mark me brainliest
Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0∘ west of north. Jane walks 12.0 m in a direction 30.0∘ south of west. They then stop and turn to face each oth
Answer:
a) 24.33 m of distance.
b) 34.55° east of the south.
Explanation:
The question is incomplete. The whole exercise is the following:
"Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0° west of north. Jane walks 12.0 m in a direction 30.0° south of west. They then stop and turn to face each other.
(a) What is the distance between them?
(b) In what direction should Ricardo walk to go directly toward Jane?"
Now that we know what we need to do in this question, let's head for every part of the problem.
a) Distance between Ricardo and Jane
In this case, we need to analyze the given data:
Ricardo (which we will call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 12 m at 30° south of west. So the distance between them, will be the point where they both stop and face each other. This point can be seen in the image attached (See picture).
Let's call the distance between them as "D", to get the distance of D, according to the picture will be:
D = J - R (1)
However, as they are facing in different angles and directions, we cannot do the difference of their values distance just like that. In order to do that, we need to calculate the components in the "x" and "y" axis of each vector. In that way, we can get the components of x and y of the Distance D, and then, the whole distance between them will be:
D = √Dx² + Dy² (2)
So, let's get the components of x and y of R and J.
For Ricardo (R):
Rx = R sin60° = 28 sin60° = -24.25 m
Ry = R cos60° = 28 cos60° = 14 m
The sign "-" it's because R it's on the second quadrant, therefore in x, we'll have to add the negative.
For Jane (J):
Jx = J cos30° = 12 cos30° = -10.39 m
Jy = J sin30° = 12 sin30° = -6 m
Again, the negative is added because J is on the third quadrant.
Now that we have the components, let's calculate vector D using expression (1):
Dx = -10.39 - (-24.25) = 13.86 m
Dy = -6 - 14 = -20 m
Now, using expression (2) we can finally know the distance between Jane And Ricardo:
D = √(-20)² + (13.86)²
D = 24.33 mThis is the distance between Jane and Ricardo.
b) Direction of Ricardo walking to Jane
In this case, we already have the components of x and y of the distance between them, so, to know the direction:
Tanα = Dy/Dx
α = tan⁻¹ (Dy/Dx)
Replacing the values we have:
α = tan⁻¹ (-20/13.86)
α = 55.45°
Which should south of east or:
β = 90 - 55.45
β = 34.55°Ricardo should walk 34.55° east of south
Hope this helps
A car travels 9km southwards, followed by another 5km southwards. What is the magnitude of its
distance and displacement?
Select one:
a. Distance: 14 km Displacement: 14 km
b. Distance: 14 km Displacement: 4 km
c. Distance: 4 km Displacement: 14 km
d. Distance: 4 km Displacement: 4 km
Answer:
A
Explanation:
No change in direction, and travel was in a straight line, and total distance travelled is 9+5=14
if the mass of an object is 35kg on venus what is its mass on the sun
Answer:
Venus is only 95% the size of Earth, and 81% of its mass. With the smaller size and mass, the force of gravity pulling you on the surface is lower. To get your weight on Venus, just multiply your current weight by 0.9. That's why 100 pounds becomes 90 pounds
If the mass of an object is 35kg on Venus Its mass on the Sun remains the same hence the object's mass om sun in 35 kg. The mass of an object is an intrinsic property and remains the same regardless of the gravitational field.
The mass of an object does not change depending on its location. The mass of an object is an intrinsic property and remains the same regardless of the gravitational field it is in or its location within the universe.
However, it is important to note that an object's weight, which is the force of gravity acting on it, would be different on Venus and the Sun due to the variations in gravitational pull.
Therefore, if the mass of an object is 35 kg on Venus, its mass would still be 35 kg on the Sun.
To know more about the mass in different locations:
https://brainly.com/question/29414101
#SPJ5
will mark brainlist
Calculate the kinetic energy of a 100.0-kg meteor approaching the Earth at a speed of 10.0 km/s. Remember that 1 km = 1000 m.
O 1.00 x 10^8j
O 5.00 x 10^9 j
O 10 x 10^7 j
O 50.0 x 10^8 j
Answer:
5.00 x 10^9 j
Explanation:
mass = 100 kg
speed / velocity = 10 km/s x 1000 = 10,000m
K.E =
[tex] \frac{m{v}^{2} }{2} [/tex]
10,000x 100/ 2
= 5000000000
= 5.0 x 10^9j
Velocity includes both speed and
Velocity includes both speed and direction.
What is Velocity?Velocity of a particle is its speed and the direction in which it is moving.
It can also be described as the instantaneous rate of change of the particle's distance traveled, and the direction in which the distance is changing, velocity is basically speeding in a specific direction. It is a vector quantity, which means we need both magnitude (speed) and direction to define velocity. The SI unit of it is metre per second (ms-1). If there is a change in magnitude or the direction of the velocity of a body, then it is said to be accelerating.
Learn more about velocity here: https://brainly.com/question/80295?source=archive
#SPJ1
tourist travels 1500 miles using two planes. The second plane averages 50 miles per hour faster than the first plane. The tourist uses the slower plane for the first 500 and the faster plane for the next 1000 miles. The total flying time is 6.5 hours. What is the speed of the first plane?
Answer:
V₁ = 200 mi/h
Explanation:
To do this, we need to analyze the given data.
We have a total distance and time of 1500 mi and 6.5 h. We also know that the second plane goes 50 mi/h faster than the first plane, (V₂ = V₁ + 50). The firsts 500 miles were on the first plane and the remaining 1000 mi with the second plane.
Using the expression of distance, and assuming a constant speed in both planes we have:
d = V * t (1)
Replacing this expression for both planes we have:
d₁ = V₁ * t₁
d₂ = (V₁+50) * t₂
WE are missing several data, because we do not know the times for each plane, but we can have a clue.
The total time of flight was 6.5 h, this is equivalent to just sum both times of both planes, so:
t = t₁ + t₂ (3)
From the expressions of distance for both planes, we can solve for time, and then replace in the above expression of the total time. In that way we can solve for the speed of the plane. Let's solve for both times in the planes:
t₁ = d₁ / V₁ = 500/V₁ (4)
t₂ = d₂ / V₁+50 = 1000/ V₁ + 50 (5)
Now, all we have to do is replace (4) and (5) into (3) and solve for V₁:
6.5 = [(500/V₁) + (1000/V₁ + 50)
6.5 = [500*(V₁+50) + 1000V₁ / V₁(V₁+50)]
6.5 = [500V₁ + 25000 + 1000V₁ / V₁² + 50V₁
6.5(V₁² + 50V₁) = 1500V₁ + 25000
6.5V₁² + 325V₁ - 1500V₁ - 25000 = 0
6.5V₁² - 1175V₁ - 25000 = 0
From here, we use the quadratic equation to solve for V₁:
X = 1175 ± √(1175)² + 4 * 6.5 * 25000 / 2 * 6.5
X = 1175 ± √1380625 + 650000 / 13
X = 1175 ± 1425 / 13
X₁ = 1175 + 1425 / 13 = 200
X₂ = 1175 - 1425 / 13 = -19.23
So, it's very clear that the speed cannot be negative, so we stick with the first value. Therefore the speed pf the first plane is:
V₁ = 200 mi/hV₂ = 250 mi/hHope this helps
The speed of the first plane is 77.02 mph.
The given parameters:
Total distance traveled, d = 1500 milesDistance by the slower plane = 500 milesDistance by the faster plane = 1000 milesTotal time of motion, t = 6.5 hoursLet the average speed of the first plane = v
Then, average speed of the second plane = 50 + v
The speed of the first plane is calculated as follows;
[tex]\frac{500}{v} + \frac{100}{50 + v} = 6.5\\\\\frac{500(50 + v) + v}{v(50 + v)} = 6.5\\\\500(50 + v) + v = 6.5(50v + v^2)\\\\25000+ 500v + v = 325 v + 6.5v^2\\\\6.5v^2 -176 v - 25000 = 0\\\\a = 6.5, \ b = -176, \ c = -25000\\\\v = \frac{-b \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\v = 77.02 \ mph[/tex]
Thus, the speed of the first plane is 77.02 mph.
Learn more about average speed here: https://brainly.com/question/6504879
Please help me. I will do what I can to get you points.
Answer:
the last one
Explanation:
its the sun when the earth turns towards the sun it gives us heat not solar radiation.
An object moves with a constant speed of 20 m/s on a circular track of radius 100 m. What is the tangential acceleration of the object?
Answer:4s^-1
Explanation:Tangential Acceleration=v^2/r=(20)²/100=400/100
Ram has power of 550 watt. What does it mean?
What's the gravity?
Answer:
gravity is the force by which a planet or another body draws objects towards its Centre. the force of gravity keeps all of the planets in an orbit around the sun.
Explanation:
what is gravity made of?
gravity are made of proposed gravity parts that are made quantum particles which called gravitational anywhere there is gravitation there is gravity like on Earth in the Solar System most importantly in the minisclue infant and intervention universe .
PLEASE HELP ASAP I'LL GIVE BRAINLY!!
Answer: b or c
Explanation: on khan academy
10
A5 kilogram gun fires a 0.02 bullet with a velocity of 380 m/s. What is the recoil velocity of the gun?
A) - 1900 m/s
B - 1.5 m/s
C -7.6 m/s
D - 0.1 m/s
Aww
What pattern did you observe when the tape was at
different distances from the Van de Graaff machine?
PLS HELP
How long would a pendulum have to be in order to have a period of 10.0 s? Use a value of 9.81 m/s2 for the local acceleration due to gravity. Give your answer to one decimal place.
3. A car has a mass of 2.50 x 10^3 kg. If the force acting on the car is 7.65 x 10^3 N to the
east, what is the car's acceleration?
Answer:
3.06m/s² to the east
Explanation:
Given parameters:
Mass of car = 2.5 x 10³kg
Force acting on the car = 7.65 x 10³N
Unknown:
Acceleration of the car = ?
Solution:
From Newton's second law of motion:
Force = mass x acceleration
Acceleration = [tex]\frac{Force }{mass}[/tex] = [tex]\frac{7.65 x 10^{3} }{2.5 x 10^{3} }[/tex] = 3.06m/s² to the east
