Why does the moon appear to be bright from Earth yet appears dark from space?

The work done is four times greater when the car is moving at 20 m/s than when it is moving at 10 m/s.

According to the work-energy theorem, the work generated by the net force applied on a body equals the change in kinetic energy. W = kf - ki is the simplest way to express it. The work-energy theorem equation is the one presented above. Net work done W turns negative if the body's kinetic energy diminishes.

Kinetic energy:

KE = 1/2 * m * v^2

where m is the mass of the car and v is the velocity,

KE at 10 m/s = 1/2 * m * 10^2 = 1/2 * m * 100

KE at 20 m/s = 1/2 * m * 20^2 = 1/2 * m* 400

work done

Work (w) = KE_f - KE_i

KE_f = final kinetic energy

KE_i = initial kinetic energy

Work = KE at 20 m/s - KE at 0 m/s

Work = 1/2 * m * 400 - 1/2 * m * 0

Work = 1/2 * m * 400

Hence,  a car moving at 20 m/s has four times the that of the same car moving at 10 m/s when starting from rest.

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The magnitude of the electric field between the plates, from least to greatest is shown by option C.

We know that when two plates that are conducting are arranged in such a way that a gap is left in between them, the we have a capacitor. The electric potential of the capacitor would have a lot to do with the distance of the separation of the plates.

As such, the closer the plates are together, the greater the electric potential of the plates and the more the plates are apart, the lesser the electric potential of the plates.

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In two stones thrown vertically upward problem, it will take the slower stone 3.67 seconds to return and faster to go 303.6 m high. In vehicles overtaking problem, automobile overtakes the truck 60.16m beyond, and is traveling at 14.7m/s when it overtakes the truck.

Two stones thrown vertically upward problem:

A) To solve this problem we need to use the equation of motion for free fall under gravity: h = -1/2 gt^2 + vt + h0, where h is the height of the stone, g is the acceleration due to gravity, t is the time, and h0 is the initial height. Since we know that the stone is thrown vertically upward from the ground, the initial height h0 is 0.

We also know that the stone is in free fall, so the velocity v is 0 and the final height h is also 0.

We can use this information to find the time it takes for the faster stone to return to the ground:

h = -1/2 gt^2 => 0 = -1/2 (9.8 m/s^2) t^2 => t = √(2h/g) => t = √(2*0/9.8) => t = 0

Now, we know that the faster stone takes 11.0s to return to the ground, and that the faster stone has 3 times the initial speed of the slower stone.

So, the slower stone will take (11.0s/3) = 3.67s to return to the ground.

B) If the slower stone reaches a maximum height of h, then the faster stone will go 3h high.

We can use the equation of motion for free fall under gravity to find the maximum height of the slower stone:

h = -1/2 gt^2 + vt + h0 => 0 = -1/2 gt^2 + 0 + 0 => h = -1/2 gt^2 => h = -1/2 (9.8 m/s^2) (3.67 s)^2 => h = -1/2 (9.8 m/s^2) (13.41 s^2) => h = -1/2 (9.8 m/s^2) (13.41 s^2) => h = -101.2 m

So, the faster stone will go 3*101.2 m = 303.6 m high.

Automobile and truck problem:

We can use the equations of motion for constant acceleration.

First, we need to find the time it takes for the automobile to overtake the truck. We can use the equation: v = u + at, where v is the final velocity, u is the initial velocity (0 m/s for the automobile), a is the acceleration (2.7 m/s^2) and t is the time.

So, v = 0 + 2.7t

Next, we can use the equation of motion for relative motion: v = v_t - v_a, where v_t is the velocity of the truck and v_a is the velocity of the automobile. So, v = 14.7 - 2.7t

We can now set the two equations equal to each other: 14.7 = 2.7t. So, t = 5.44 seconds.

To find the distance the automobile travels before overtaking the truck, we can use the equation: s = ut + (1/2)at^2. Plugging in the known values, s = (1/2) (2.7 m/s^2) (5.44 s)^2 = 60.16 m

To find the velocity of the automobile when it overtakes the truck, we can use the equation: v = u + at. Plugging in the known values, v = 0 + 2.7 (5.44 s) = 14.7 m/s

So, the automobile overtakes the truck 60.16m beyond its starting point and the automobile is traveling at 14.7m/s when it overtakes the truck.

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The kinetic energy and speed of arrows that have the most potential energy at the beginning are the highest at the end.

As a result, the order is C = F > A = E > B = D.

Potential energy is stored energy that is affected by the relative location of various components in a system. When a spring is squeezed or extended, its potential energy increases. A steel ball has higher potential energy when lifted above ground than when it falls to Earth. It can do more work in the elevated position. Potential energy is a property of a system, not an individual substance or particle; for example, the system made of Earth and the elevated ball has greater potential energy as the two are separated.

Potential energy is created in systems having pieces that exert forces on each other with varying magnitudes depending on the arrangement.

Correct question is:

Attached as a image with diagram

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The answers are A)and B) both toy cars will acquire equal but opposite momenta and  both toy cars will acquire equal kinetic energies

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The force that Sally experiences due to the presence of the asteroid Ceres is 3.8 x 10⁻⁸ N.

To determine the force Sally experiences due to the presence of the asteroid Ceres, we can use the formula for gravitational force:

F = G x (m₁ x m₂) / r²

where F is the gravitational force, G is the gravitational constant (6.67 x 10⁻¹¹ Nx(m²)/(kg²)), m1 is the mass of Sally, m₂ is the mass of Ceres, and r is the distance between the two masses.Given that:

m₁ = 62 kg (mass of Sally)

m₂ = 8.7 x 10²⁰ kg (mass of Ceres)

r = 17,000 km = 17,000,000 meters

F = (6.67 x 10⁻¹¹ Nx(m²)/(kg²)) x (62 kg x 8.7 x 10²⁰ kg) / (17,000,000 m)²

F = (6.67 x 10⁻¹¹ Nx(m²)/(kg²)) x (62 kg x 8.7 x 10²⁰ kg) / 2,89,000,000,000,000 m²

F = 3.8 x 10⁻⁸ N

So the force that Sally experiences due to the presence of the asteroid Ceres is 3.8 x 10⁻⁸ N.

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The acceleration of the boat if there is a forward force of 360 N from the fan is calculated as : 0.05 m/s^2.

Newton's second law of motion states that net force acting on object is equal to mass of the object multiplied by acceleration. Net force acting on the boat is sum of the force from the fan and the force of the current against the motion of the boat.

As, Net force = ma

Given,  m is the mass of the boat (220 kg)

Net force = ma = (360 N) - (250 N) = 110 N

a = Net force/m = 110 N/ 220 kg = 0.05 m/s^2

So, acceleration of the boat is 0.05 m/s^2

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Answer:

25 seconds

Explanation:

Answer:

t = distance ÷ speed

t = 1000 cm ÷ 40 cm/s

t = 25 s

So it would take 25 seconds to cover a distance of 1000 cm at a speed of 40 cm/s. It's important to note that the units of distance and speed must be the same in order for the calculation to be correct. Also, this is a basic equation which is based on the distance-time-speed relationship. This equation can be used for various other calculations and can be helpful in determining the time required to reach a certain distance at a certain speed.

a) Points "B" and "E" are in stable equilibrium.

b) In this curve , points A and C are in unstable equilibrium.

c) There is no point which in neutral equilibrium.

When a system is in equilibrium, neither its internal energy state nor its state of motion tend to change over time. A simple mechanical body is said to be in equilibrium if it neither experiences linear acceleration nor angular acceleration; unless it is disturbed by an external force, it will remain in that state indefinitely. If all of the forces acting on a single particle are vector summated to zero, equilibrium results.

a)

Stable equilibrium point is surrounded by points of higher potential energy.

Points "B" and "E" are in stable equilibrium.

b)

Unstable equilibrium point is surrounded by points of lower potential energy.

In this curve , points A and C are in unstable equilibrium.

c)

Neutral Equilibrium Point : This point is surrounded by points of same potential energy.

There is no point which in neutral equilibrium.

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Complete question:

We have used the state-vector notation established with in Representing Qubit Environments section to express the state of our qubits throughout the bulk of Qiskit textbook.

A qubit quantum bit is the fundamental building block containing information in quantum computing, much as a binary bit is in regular traditional computing. New discoveries in health, economics, environmental systems, advanced materials, and other fields are being sparked by quantum computing.

With Qiskit, users may conduct experiments at home using cutting-edge quantum devices. That experimental quantum theory that underpins quantum computing is also taught in the textbook. It offers resources for developing, modifying, and executing quantum applications on

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The coefficient  of static  friction between the book and the coin is the tangent of the angle of inclination. Hence, the coefficient  is 6.4.

Friction is the resistive force acting on an object. Static friction is the opposing force acting on a stationary object. It is always negative. The coefficient of friction is the ratio of frictional force to the normal force.

Here, the angle of inclination  θ = 30°

The normal force acting in the x direction of the coin  = Fx = Mg Sinθ

normal fore from y direction is  = Fy = Mg cosθ

Now, frictional force Fs = μ Fx = Fy

then  μ cos θ  = sin θ.

Then, the  coefficient  of static  friction μ = sin θ/cos θ

μ = tan 30 = 6.4 .

Therefore, the  coefficient  of static  friction between the book and the coin is 6.4.

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A bob is the mass on the end of a pendulum found most commonly, but not exclusively, in pendulum clocks.

A basic pendulum consists of a light, flexible, inextensible thread with a heavy but tiny item, known as a "bob," at one end. Graph: Pendulum clocks employ it. It's used to calculate the acceleration caused by gravity.

Clock pendulums are typically composed of a weight or bob attached to the bottom end of a rod, with the top linked to a pivot so it can swing, despite the fact that a pendulum's shape or any rigid item hanging on a pivot is theoretically possible.

The benefit of this design is that it places the centre of mass farthest from the pivot, nearer to the actual end of the pendulum. This reduces the length of the pendulum needed for a specific period and increases moment of inertia. 

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The wire is stretched and tied down at points 75.0 cm apart, and it vibrates in its fundamental mode with a frequency of 64.0 Hz and an amplitude of 0.320 cm at the anti nodes is 259200.0 g cm/s².

From this information, we can use the following equations to calculate the wavelength, velocity, and tension of the wire:

Wavelength: λ = 2L/n, where L is the distance between the fixed points and n is the number of anti nodes (in this case, n = 1 for the fundamental mode). Therefore, λ = 2(75.0 cm)/1 = 150.0 cm.

Velocity: v = fλ, where f is the frequency and λ is the wavelength. Therefore, v = 64.0 Hz x 150.0 cm = 9600.0 cm/s.

Tension: T = (mv²)/λ, where m is the mass of the wire and v is the velocity. Therefore, T = (45.0 g x 9600.0 cm/s²)/150.0 cm = 259200.0 g cm/s².

It is important to note that the above calculations are based on the assumption that the wire behaves as a simple harmonic oscillator, meaning that it oscillates with a constant amplitude and frequency.

Additionally, it is also important to note that the tension in the wire is what causes the wire to oscillate, and it is also what allows the wire to transmit sound waves.

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Temperature, density, color, electric current, heating value, as well as other characteristics are all intense attributes since they are unaffected by changes in the size or quantity of the substance.

A property of that is intensive depends solely on the type of matter in a sample and not on the quantity. Examples of intense qualities include color, temperature, and solubility.

intense qualities. The rate of electron passage in a conductor is known as electric current. Intensive qualities are those that exist regardless of the quantity of a substance or substances in the system.

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Yes, it is possible to convert wasted heat into useful work, energy, or electricity using a device called a thermoelectric generator (TEG), etc.

TEGs work by using the difference in temperature between two sides of the device to generate electricity. This process is known as the Seebeck effect. TEGs have been used to convert the wasted heat from car engines and industrial processes into electricity, for example.

Another way of converting wasted heat into electricity is using Organic Rankine Cycle (ORC) which is similar to the Rankine Cycle used in traditional power plants, but it uses an organic fluid with a lower boiling point. This allows for the use of lower temperature heat sources, such as industrial waste heat or solar thermal energy, to generate electricity.

Additionally, the use of waste heat recovery system (WHRS) can also be used to recover heat from industrial processes, power generation, and other sources, and convert it into electricity.

So yes, it is possible to convert wasted heat into useful energy, and various methods have been developed to do so, it is just a matter of cost-effectiveness and practicality in the specific case of Pakistan.

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The particle comes to rest before reaching the position x=4m.

The connection between the potential energy function U(x) and the conservative force F(x)  is given by Eq.:F(x)=−dU/dx.

A positive slope of U(x) at a point means that F(x) is negative, and vice versa.

The force at x=2.0m is

[tex]$\mathrm{F}=-\frac{\mathrm{dU}}{\mathrm{dx}} \approx-\frac{\Delta \mathrm{U}}{\Delta \mathrm{x}}=-\frac{\mathrm{U}(\mathrm{x}=4 \mathrm{~m})-\mathrm{U}(\mathrm{x}=1 \mathrm{~m})}{4.0 \mathrm{~m}-1.0 \mathrm{~m}}$[/tex]

[tex]$=-\frac{-(17.5 \mathrm{~J})-(-2.8 \mathrm{~J})}{4.0 \mathrm{~m}-1.0 \mathrm{~m}}=4.9 \mathrm{~N}$[/tex]

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The work done by using a lever with an effort arm of 12 meters and a load arm of 6 meters is 72 Joules. The force must have applied is 1600 N.

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A satellite following an elliptical orbit around Earth will have different velocities at different points in its orbit, specifically at its perigee (the point in its orbit where it is closest to Earth) and at its apogee (the point in its orbit where it is farthest from Earth).

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The normal force of a 42-N block when pulled along a horizontal surface by a force of 28-N is 411.6 N.

The normal force is the force that acts perpendicular to the surface the object is on. In this case, the normal force is equal to the weight of the block, which is equal to the mass of the block multiplied by the acceleration due to gravity.

The weight of the block can be calculated using the formula: weight = mass * gravity

The mass of the block is 42 N, and the acceleration due to gravity is 9.8 m/s^2 (on earth)

So, the weight of the block is 42 N * 9.8 m/s^2 = 411.6 N

Therefore, the normal force of a 42-N block when pulled along a horizontal surface by a force of 28-N is 411.6 N.

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To start and maintain combustion, three conditions must be met: heat, fuel, and oxygen.

a chemical interaction between different compounds, generally including oxygen, that produces heat in the kind of flames. burning coal or wood of any type to heat our home. Buses and cars utilize gasoline or diesel to operate. Your cooktop is powered by natural gas or LPG. The burning of these gases facilitates cooking.

To sum up, three elements must be present for combustion to take place: a fuel to be destroyed, a source of carbon, and a sources of heat. Combustion results in the production of exhausts and the release of heat.

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Answer:

A good brick should have a low thermal conductivity, allowing the house to be cool in the summer and warm in the winter. Hence, bricks are not good conductors of heat.

Explanation:

The answers include the following:

This is referred to as long-term shifts in temperatures and weather patterns and is caused by factors.

They include the emission of greenhouse gases such as carbon dioxide due to burning of fossil fuel which is associated with technological advances.

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Newton horizontal force is exerted upon a 3.1-kg box to move it across a level surface at a constant velocity of 1.4 m/s. The force of friction encountered by the box is 4.84N.

Explain force of friction?

Friction is a force that resists the movement of two objects that are in contact with each other. Friction is a force that can be beneficial or detrimental depending on the situation.

Now,

F = ma

F = 3.1 kg * 1.4 m/s^2

F = 4.84 N

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Answer:244 m/s

Explanation: Vf= Vi+a.t

Vf= 8.33+(42 x 5.6)

Vf=243.53 m/s

Answer:

a) 1.05rad/s

b) 1.38J

Explanation:

The vector quantity velocity (v), denoted by the expression v = s/t, quantifies displacement (or motion, s), over change in time (t).

Negative Velocity: If an object's position is shifting negatively as time passes, it has negative velocity. The airspeed is negative when any graph of displacement against time has a negative slope.

Depending on the co - ordinate system used to define the position, the velocity's sign can change. A positive velocity merely indicates that a moving object is moving throughout the coordinate system's positive direction, whereas a negative velocity denotes that the item is going in the opposite direction.

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If a simple pendulum oscillates with small amplitude and its length is doubled, the frequency of its motion remains same.

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Momentum is always conserved when two separate objects collide. Only elastic collisions preserve kinetic energy.

Momentum is conserved for any collision in an isolated system. Before and after the collision, the collection of items in the system had an equal amount of total momentum.

According to the collision theory, for a reaction to take place, there must be interactions between different molecules. It's not necessary for every molecular collisions to result in a product. Only when the chemical reactions have energy over the threshold energy will the product develop.

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Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration [tex]* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a[/tex] Since the car moved 2.0 meters in the first second, it means the acceleration is[tex]2m/s^2[/tex], and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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