The given situation is because of the phenomena of Doppler's Effect.
How does the sound gets faint ?You may have observed that the pitch of a siren decreases sharply as it passes you at a high rate of speed. When the pitch is higher, the siren first approaches you. The siren is moving away from you and becomes quieter once it has passed you. The Doppler effect is manifested in this way.
The region that the sound waves cover grows as one gets farther from the source of the sound. The intensity and loudness of the sound are reduced because the same quantity of energy is dispersed over a larger region. This explains why, as you get further away from the source, even strong noises start to diminish.
To know more about doppler's effect you may visit the link:
https://brainly.com/question/15318474
#SPJ4
A 2.3 kg , 20-cm-diameter turntable rotates at 150rpm on frictionless bearings. Two 550 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.What is the turntable's angular velocity, in rpm, just after this event
The turntable's angular velocity, in rpm, just after this event is ω(f) = 78.40 rpm
I'll suppose that the turntable is a solid disc with a moment of inertia of 0.5Mr2 and that the blocks stick out from the edge of the turntable, each 10cm (0.10 m) from the turntable's centre. This is the conservation equation:
0.5Mr²ω(i) = 0.5Mr²ω(f) + m₁r²ω(f) + m₂r²ω(f) ----(but m₁ = m₂ = m)
Mr²ω(i) = Mr²ω(f) + 4mr²ω(f)
Mr²ω(i) = ω(f)r²(M + 4m)
ω(f) = Mω(i) / (M + 4m)
ω(f) = (2.3kg)(150 rpm) / [2.3kg + (4 x 0.55 kg)]
The turntable's angular velocity, in rpm, just after this event is ω(f) = 78.40 rpm
Learn more about Angular velocity here:
https://brainly.com/question/29557272
#SPJ4
What is the density of a cube that has a mass of 12.6 and a measured side length of 4.1 cm?
Answer: 0.183 g/cm³
Explanation:
density = mass/volume = m/v
m = 12.6 g (I assume grams? you didn't provide the unit)
cube has equal sides, so volume of the cube = 4.1³ = 68.9 cm³
density = 12.6g/68.9 cm³ = 0.183 g/cm³
the fact that the force times the distance on one side of a lever's fulcrum equals the force times the distance on the other side of the fulcrum, is represented in the .
The force times the distance on the other side of the fulcrum, is represented in the moments.
What is fulcrum equals?
Calculate the mechanical advantage [tex]MA[/tex]using the equation [tex]MA = Fr/Fe.[/tex] For a class I lever, calculate the distance [tex]dr[/tex] of the fulcrum from the load using[tex]dr= L / (MA + 1)[/tex]. For a class II lever, determine the distance [tex]dr[/tex]of the fulcrum from the load using [tex]dr = L / MA[/tex].
How do you calculate the force of a fulcrum?
Class I Levers trial one: de = dr
In a class one lever the force of the effort (Fe) multiplied by the distance of the effort from the fulcrum (de) is equal to the force of the resistance (Fr) multiplied by the distance of the resistance from the fulcrum (dr).
To learn more about fulcrum equals ?
visit https://brainly.com/question/19874084
#SPJ4.
a rock climber stands on top of a 50 m -high cliff overhanging a pool of water. he throws two stones vertically downward 1.0 s apart and observes that they cause a single splash. the initial speed of the first stone was 1.6 m/s.
A) How long after the release of the first stone does the second stone hit the water? (in seconds) B) What was the initial speed of the second stone? (in m/s) C) What is the speed of the first stone as it hits the water? (in m/s) D) What is the speed of the second stone as it hits the water? (in m/s)
(a) The second stone hit after 2.91 seconds
(b) The initial velocity of the second stone must be 15.8 m/s vertically downward.
(c) The velocity of each stone when they reach the water is: First stone : -30.7 m/s Second stone: -34.5 m/s
The height and velocity of the stones can be calculated using the following equations:
y = y0 + v0 · t + 1/2 · g · t²
v = v0 + g · t
Where:
y = height at time "t".
y0 = initial height.
v0 = initial velocity.
t = time.
g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).
v = velocity at time "t".
a) If we place the origin of the frame of reference on the water, then, the height of both stones when they hit the water will be 0. Using the equation of height for the first stone, we can obtain the time when the height is 0:
y = y0 + v0 · t + 1/2 · g · t²
0 = 50.0 m -1.91m/s · t - 1/2 · 9.81 m/s² · t²
0 = 50.0 m - 1.91 m/s · t - 1.6 m/s² · t²
Solving the quadratic equation:
t = 2.91 s
The two stones hit the water 2.91 s after the release of the first stone.
b) The second stone reaches the water in (2.91 s - 1.00 s) 1.91 s after released (remember that it was released 1.00 s after the first stone but both reached the water simultaneously). Then, using the equation of height, we can obtain the initial velocity knowing that at t = 1.91 s, y = 0:
y = y0 + v0 · t + 1/2 · g · t²
0 = 48.0 m + v0 · 1.91 s - 1/2 · 9.81 m/s² · (1.91 s)²
(-48.0 m + 1/2 · 9.81 m/s² · (1.91 s)²) / 1.91 s = v0
v0 = -15.8 m/s
The initial velocity of the second stone must be 15.8 m/s vertically downward.
c) We have to use the equation of velocity for each stone. We already know the time when the stones reach the water and the initial velocities:
First stone:
v = v0 + g · t
v = -2.18 m/s - 9.81 m/s² · 2.91 s
v = -30.7 m/s
Second stone:
v = v0 + g · t
v = -15.8 m/s - 9.81 m/s² · 1.91 s
v = -34.5 m/s
The velocity of each stone when they reach the water is:
First stone : -30.7 m/s
Second stone: -34.5 m/s
Therefore, the velocity of the first and second stones are -30.7 m/s and -34.5 m/s.
To know more about velocity, refer: https://brainly.com/question/17003580
#SPJ4
based on fundamental laws of motion and gravity, which of the following best explains why kepler's second law (planets move faster in the parts of their orbit that are closer to the sun and slower when they are farther from the sun) is true? based on fundamental laws of motion and gravity, which of the following best explains why kepler's second law (planets move faster in the parts of their orbit that are closer to the sun and slower when they are farther from the sun) is true? the strength of gravity is inversely proportional to the square of the distance between two objects. the speed of a planet at any point in its orbit depends on its temperature, which varies with distance from the sun. the gravitational influence of other planets determines the speed of any particular planet's orbit. a planet's angular momentum must be conserved as it moves around its orbit.
The strength of gravity is inversely proportional to the square of the distance between two objects.
Kepler's Second Law characterizes the the rate of a planet alongside its elliptical path. Kepler's Second Law says says that a line jogging from the solar to the planet sweeps out same regions of the ellipse in same times. This manner that the planet hastens because it tactics the solar and slows down because it departs from it.
Newton's regulation states: The gravitational appeal pressure among factor loads is immediately proportional to the made from their loads and inversely proportional to the rectangular in their separation distance. The pressure is usually appealing and acts alongside the road becoming a member of them.
For the planets, as they cross across the Sun, their loads do not extrade however their distances from the Sun do. As they get in the direction of the Sun (distance receives smaller) they orbit faster (better velocity). The product of those portions stays unchanged, therefore angular momentum is conserved.
Learn more about Kepler's Law here https://brainly.com/question/25900771
#SPJ4
a long straight wire is in the plane of a rectangular conducting loop. the straight wire initially carries a constant current iin the direction shown. while the current i is being shut off, the current in the loop is:
The current in the rectangular conducting loop will be in the clockwise direction because of the long straight wire.
The long straight wire is carrying the current and it is in the Plane of the rectangular conducting loop.
The wire is carrying the current in the upward direction with respect to the plane of the paper.
When there is a current in the long straight wire there will be a magnetic field around the wire. When the current in the wire is being shut off the magnetic field will start to decrease as a result of the change in magnetic flux because of the change in magnetic field.
The induced current in the loop will generated in such a way that the decrease in magnetic field is opposed.
So, the current in the loop will be in the clockwise direction.
To know more about induced current, visit,
https://brainly.com/question/29356852
#SPJ4
Three enemy spacecraft have been causing trouble in the asteroid belt. They always travel in a line, evenly spaced apart, attempting to chase down local spacecraft to steal their goods. The local asteroid colonists have decided to set a trap to capture these three spacecraft. They'll get them to chase one of their fastest ships into an asteroid with a large hole in it and, once the three enemy ships are inside, close two giant trapdoors on each side of the asteroid to catch them. These spacecraft all travel close to the speed of light so the locals will have to take relativity into account. Intelligence about the enemy spacecraft reveals that, in their reference frame, they always travel 90 m behind their teammate, each spacecraft is 10 m in length, and their maximum velocity is 90% the speed of light (relative to the asteroids). The asteroid tunnel is only 215 m in length. In this problem we will analyze whether the locals will be able to capture the enemy spacecraft after taking into account relativity.
Part A: If the spacecraft are traveling at 90% the speed of light, what is the total length L of the three-spacecraft team as observed from the asteroid?
Part B: Suppose the trigger is set so that the moment the first enemy spacecraft enters the asteroid a signal is sent at the speed of light to the other end of the asteroid to trigger the rear trapdoor. How long a time will this signal take to get to the rear of the asteroid?
Part C:How close d_rear to the rear of the asteroid will the first enemy spacecraft be when the trapdoors close?
Part D:One of the local students had been studying relativity and began to question the plan. How would this all appear to the enemy spacecraft as they flew through the asteroid? Specifically, if the spacecraft were in an inertial frame (i.e., one with no acceleration) how long would the asteroid tunnel appear to be in their rest frame?
Part A: If the spacecraft is traveling at 90% the speed of light, the total length L of the three-spacecraft team as observed from the asteroid is 31 meters.
Part B: The signal will take 0.732 seconds to reach the rear of the asteroid.
Part C: The first enemy spacecraft will be 7.3 meters from the rear of the asteroid when the trapdoors close.
Part D: In the inertial frame of the enemy spacecraft, the asteroid tunnel would appear to be 639 meters long.
For more questions like Spacecraft click the link below:
https://brainly.com/question/10049508
the correct relation for the emissive power of a diffuse, gray surface, where t is the absolute temperature is___
When t is the absolute temperature, the appropriate relationship for a diffuse, gray surface's emissive power is E = εσT^4
The energy emitted by a body per unit surface area within a unit wavelength range is known as its emissive power at a specific temperature. Stefan's constant, emissivity, and absolute temperature are all present in this equation. Kirchhoff's law states that the emissive power of a perfectly black body at a given temperature is equal to the ratio of emissive power to absorptive power for a given wavelength at a given temperature for all bodies. The diffuse-gray surface theory applies to surfaces where is wavelength-independent.
To learn more about emissive power click here https://brainly.com/question/27816922
#SPJ4
how fast would a(n) 73 kgkg man need to run in order to have the same kinetic energy as an 8.0 gg bullet fired at 430 m/sm/s ?
The velocity of the 73 Kg man needed for him to have the same kinetic energy as the 8.0 g bullet fired at 430 m/s is 4.5 m/s
How do I determine the velocity of the man?First, we shall obtain the kinetic energy of the bullet. This can be obtained as follow:
Mass (m) = 8 g = 8 / 1000 = 0.008 KgVelocity (v) = 430 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 0.008 × 430²
KE = 739.6 J
Finally, we shall determine the velocity of the 73 Kg man. Details below:
Mass of man (m) = 73 KgKinetic energy (KE) = 739.6 JVelocity of man (v) = ?KE = ½mv²
739.6 = ½ × 73 × v²
739.6 = 36.5 × v²
Divide both side by 36.5
v² = 739.6 / 36.5
Take the square root of both side
v = √(739.6 / 36.5)
v = 4.5 m/s
Thus, the velocity man is 4.5 m/s
Learn more about kinetic energy and velocity:
https://brainly.com/question/10703928
#SPJ1
an experienced astronomer can take one look at the h-r diagram of a star cluster and immediately estimate its age. select the statement that explains how this is possible.
The most massive stars remaining on the main sequence indicate the cluster's age.
What is the approximate age of the star cluster in the HR diagram quizlet?
Spectral types O and B main sequence stars have a core hydrogen supply that is enough for around 350 million years; types A and F, for about 2 billion years; type G, for about 10 billion years; and types K and M, for about 30 billion years.
Astronomers can establish the age of a globular cluster by plotting the stars in the cluster on a Hertzprung-Russell diagram and comparing the main sequence turnoff point with stellar evolution models.
Similar to our Sun, main sequence stars consume hydrogen. The upper left of the strip is home to hotter, more massive main sequence stars. Cooler, less massive stars can be observed at bottom right. Massive stars swiftly exhaust all of their hydrogen in a few of million years.
To learn more about Astronomers visit:https://brainly.com/question/14853303
#SPJ4
measure and record the output voltage from the rc low-pass fi lter for each of the frequencies listed below. (use the oscilloscope to measure the output voltage.) next, calculate the decibel attenuation offered by the fi lter at each frequency.
Passive RC filters “filter-out” unwanted signals by separating and allowing to pass only sinusoidal input signals based upon their frequency. Here the most simple passive low pass filter network is utilized.
Filters are named according to the frequency range of signals allowed to pass through them, while blocking or “attenuating” the rest. Here are some common filter designs.
The Low Pass Filter : only allows low frequency signals from 0Hz to its cut-off frequency.
The High Pass Filter : only allows high frequency signals from its cut-off frequency.
The Band Pass Filter : allows signals falling within a certain frequency band setup between two points to pass through.
The question is incomplete. Answer is written giving basics of the concepts used in the question.
To know more about RC filters here
brainly.com/question/14865465
#SPJ4
this photograph shows three rock layers separated by two disconformities, as exposed in the walls of the grand canyon. one disconformity is above the reddish lens of devonian sedimentary rocks, and the other disconformity is below the reddish lens of devonian sedimentary rocks. drag the events so that they are in the correct order, from oldest at the bottom (6) to youngest at the top (1).
1 . Erosion that formed the Grand Canyon in which the layers are exposed
2. Deposition of Devonian ‘sedimentary rocksDeposition of the Mississippian Limestone .
3 .Withdrawal of the seas and erosion that formed the lower disconformity
4. Deposition of Cambrian Limestone.
Sedimentary rocks form at or near the surface of the earth, in contrast to metamorphic or igneous rocks that form deep within the earth. The main geological processes leading to the formation of sedimentary rocks are erosion, weathering, dissolution, precipitation and petrification.
Erosion and weathering include the effects of wind and rain that slowly break large rocks down into smaller rocks. Erosion and weathering turn rocks and even mountains into sediments such as sand and mud. Dissolution is a form of weathering, chemical weathering. During this process, the slightly acidic water slowly wears away the stone. These three processes create new sedimentary rock sources.
Learn more about Sedimentary rocks here : https://brainly.com/question/7437433
#SPJ4
A metal object with a mass 5.50 kg is connected to a spring with a force constant of 225 N/m, and it oscillates horizontally with an amplitude of 4.20 cm. (a) What is the total mechanical energy (in J) of the object-spring system? (b) What is the maximum speed (in m/s) of the oscillating object? m/s (c) What is the maximum magnitude of acceleration (in m/s) of the oscillating object? m/s²
a) Total mechanical energy of the object-spring system = 0.198 J
b) Maximum speed of the oscillating object = 0.269 m/s
c) Maximum magnitude of acceleration of the oscillating object = 1.72 m/s2
What is acceleration?
Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both.
Mass of the object = m = 5.5 kg
Force constant of the spring = k = 225 N/m
Amplitude of the motion = A = 4.2 cm = 0.042 m
Total mechanical energy of the object-spring system = E
Total mechanical energy is equal to the maximum potential the spring can store in this motion.
(a) [tex]$E=\frac{1}{2} \times 300 \times 0.037^2$[/tex]
[tex]$$E=0.20535 \text { Joules }$$[/tex]
Maxmium speed, [tex]$v_{\max }=$[/tex] AeO
[tex]$$\begin{gathered}\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{300}{5.5}} \\\omega=7.3855 \mathrm{rad} / \mathrm{s} \\v_{\max }=0.037 \times 7.3855 \\V=0.273 \mathrm{~m} / \mathrm{s}\end{gathered}$$[/tex]
(C) Maximim acceleration, [tex]$a_m=A \omega^2$[/tex]
[tex]$$\begin{aligned}a_{\max } & =0.037 \times 7.3855^2 \\a_{\max } & =2.018 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$[/tex]
To learn more about acceleration visit:https://brainly.com/question/12550364
#SPJ4
The equilibrium constant is equal to 5.00 at 1300 K for the reaction: 2 SO2(g) + O2(g) ⇌ 2 SO3(g). If initial concentrations are [SO2] = 2.40 M, [O2] = 0.45 M, and [SO3] = 3.60 M, the system is The equilibrium constant is equal to 5.00 at 1300 K for the reaction: 2 SO2(g) + O2(g) ⇌ 2 SO3(g). If initial concentrations are [SO2] = 2.40 M, [O2] = 0.45 M, and [SO3] = 3.60 M, A.the system is not at equilibrium and will shift to the right to achieve an equilibrium state. B.not at equilibrium and will remain in an unequilibrated state. C.at equilibrium. D.not at equilibrium and will shift to the left to achieve an equilibrium state
Option (C) is correct.
The given equation [tex]2SO_{2(g)} +O_{2(g)}[/tex] ⇄ [tex]2SO_{3(g)}[/tex] is at equilibrium.
Given equation,
[tex]2SO_{2(g)} +O_{2(g)}[/tex] ⇄ [tex]2SO_{3(g)}[/tex]
and
[tex]K_{c} =5.00[/tex] at 1300 K
To determine whether the reaction is at equilibrium or will shift to left or right, determine the Reaction Quotient, which is calculated at any instant of time,
Given,
[tex][SO_{2} ]=2.40M[/tex]
[tex][O_{2} ]=0.45M[/tex]
[tex][SO_{3} ]=3.60M[/tex]
[tex]Q_{c} =\frac{[SO_{3} ]^2}{[SO_{2} ]^2[O_{2} ]}[/tex]
[tex]Q_{c} =\frac{(3.60)^2}{(2.40)^2(0.45)}[/tex]
[tex]Q_{c} =5[/tex]
Since,
[tex]K_{c} =5.00[/tex] = [tex]Q_{c}[/tex]
The given reaction is at equilibrium.
Learn more about Equilibrium here
https://brainly.com/question/517289
#SPJ4
a free-falling object has a speed of 30 m/s at one instant. exactly 2 seconds later its speed will be
The velocity of the freely falling body after the time 2 second is found as 49.6 m/s.
Explain the term acceleration due to gravity?Gravitational acceleration is the rate at which the speed of a body falling freely increases. Gravitational acceleration is measured in SI units of m/s², m/s², m/s².A body is considered to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.For the given question-
The freely falling body has the speed at an instant as u = 30 m/s.
Acceleration due to gravity g = 9.8 m/s².
After time t = 2 sec, the final velocity v m/s.
Using equation of motion,
v = u + gt
v = 30 + 9.8 x 2
v = 49.6 m/s.
Thus, the velocity of the freely falling body after the time 2 second is found as 49.6 m/s.
To know more about the acceleration due to gravity, here
https://brainly.com/question/88039
#SPJ4
archimedes' principle can be used to calculate the density of a fluid as well as that of a solid. suppose a chunk of copper with a mass of 400.0 g in air is found to have an apparent mass of 354.5 g when completely submerged in an unknown liquid.
The magnitude of net buoyant force in the liquid will be 1.029 N.
Whenever an object is submerged into water, the water exerts a force on an object in the upward direction. When an object push water, water pushes it back with more force. Basically buoyant force is the weight of fluid displaced by the object submerged in water.
B = weight of object in air - weight of object in water
Converting gram into N
We know that 1 kg = 9.8 N
Changing kg into gram by multiplying both sides with 1x10¯³
1 g = 9.8x10¯³ N
400 g = 400x9.8x10¯³N
400 g = 4.214 N
354.5 g = 354.5x9. 8x10¯³ N
354.5 g = 3.185 N
Now, finding buoyant force
B = weight of object in air - weight of object in water
B = 4.214 - 3.185
B = 1.029 N
Therefore the magnitude of net buoyant force in the liquid will be 1.029 N.
To know more about force, refer: https://brainly.com/question/14500845
#SPJ4
he pushed the car beyond the tollgate and poured a bucket of water on the smoking hood. previousnext
He moved the car past the toll booth and doused the flaming hood with water using the comma.
What makes water vital to life?Chemical processes are necessary for life to produce energy, grow, and eliminate waste. Water is a liquid that facilitates the chemistry of life. Additionally, because it is a polar molecule, most other molecules can dissolve in it. As a result, we refer to water as a "solvent".
How does science define water?Water is a substance that exists in gaseous, fluid, and solid phases and is made up of the molecular elements both hydrogen and oxygen. One of the prevalent and necessary substances is it. a liquid that is flavorless and odorless at ambient temperature.
To know more about water visit:
https://brainly.com/question/11885065
#SPJ1
Help please!
Zach drives his car with an average velocity of 24 m/s toward the east. How long will it take him to drive 560 km on a perfectly straight highway?
Which of the following is the same for all kinds of electromagnetic waves?
frequency
speed
energy
transmission
wavelength
Out of The following speed is the same for all kinds of electromagnetic waves.
Electromagnetic waves travel at the same speed through space. That speed, also known as the speed of light is approximately 300 million meters per moment which are 3.0 x 108 m/s...Although all electromagnetic waves travel at the same speed over space, they may vary in their wavelengths, frequencies, and energy levels. Wavelength is the distance between comparing focuses of adjacent waves. Frequencies of electromagnetic waves run from thousands of waves per second to trillions of waves per second. The energy of electromagnetic waves depends on their frequency. Low-frequency waves have small energy and are ordinarily safe. High-frequency waves have a lot of energy.
To know more about electromagnetic waves refer to the link brainly.com/question/3101711
#SPJ4
which of these is a risk of speeding? a. Tire Damage b.Greater likelihood of being distracted c.longer barking distance d.mechanical failure
All of the above are risks of speeding.
Speeding is a type of aggressive driving behavior. Speeding is more than just breaking the law. The consequences are far-ranging:
Greater potential for loss of vehicle control;Reduced effectiveness of occupant protection equipment;Increased stopping distance after the driver perceives a danger;Increased degree of crash severity leading to more severe injuries;Economic implications of a speed-related crash; andIncreased fuel consumption/cost.Speed also affects your safety even when you are driving at the speed limit but too fast for road conditions, such as during bad weather, when a road is under repair, or in an area at night that isn’t well lit.
Speeding endangers not only the life of the speeder, but all of the people on the road around them, including law enforcement officers. It is a problem we all need to help solve.
To know more about speeding visit:
https://brainly.com/question/12939615
#SPJ4
if a capacitor is connected across the feedback resistor, the circuit acts as a practical integrated circuit.T/F
if a capacitor is connected across the feedback resistor, the circuit acts as a practical integrated circuit.is FALSE
What is practical integrated?
Because the mental process and learning information are applied, practical and integrated learning is the best type of learning. Because they are actively involved in the learning process, practical and integrated learning encourages students to greatly develop their learning skills.
The practical integrator is also called as lossy integrator as it integrates only frequencies greater than fa (i.e. higher frequencies) effectively. Thus we can have following observations from frequency response of practical integrator
To learn more about practical integrated visit
https://brainly.com/question/13477978
#SPJ4
A child is flying a kite. If the kite is 90 feet above the child's hand level and the wind is blowing it on a horizontal course at 5 feet per second, the child is letting out cord at _____ feet per second when 245 feet of cord are out. Assume that the cord remains straight from hand to kite.
If the kite is 90 feet above the child's hand level and the wind is blowing it on a horizontal course at 5 feet per second, The child is letting out cord at 150 feet per second.
It's miles the price of growth of y as t increases. Loosely positioned, it is the size of the tiny increase in y that could rise up from making a tiny increase to t and setting that in the components for y.
In newtonian notation and dy/dx is leibniz notation. Newton and Leibniz independently invented calculus across the equal time so they used distinct notation to represent the equal thing (rate of change in this example).
A differential dx isn't always a actual wide variety or variable. alternatively, it is a convenient notation in calculus. it can intuitively be notion of as "a completely small alternate in x", and it makes plenty of the notation in calculus appear extra realistic.
Learn more about dy/dt here:- https://brainly.com/question/29439892
#SPJ4
A solenoidal coil with 30 turns of wire is wound tightly around another coil with 350 turns, The inner solenoid is 20.0 cm long and has a diameter of 2.10 cm. At a certain time, the current in the inner solenoid is 0.100 A and is increasing at a rate of 1500 A/s
Part A
For this time, calculate the average magnetic flux through each turn of the inner solenoid.
Part B
For this time, calculate the mutual inductance of the two solenoids.
The average magnetic flux passing through each inner solenoid turn is 8.45966*10(-8). Because a 350-turn solenoidal coil with 30 turns of wire is firmly twisted around it.
How many magnetic lines of force are present in a specific area is determined by the magnetic flux. For instance, the magnetic flux density is lower if fewer magnetic lines cross a large area of cross section. Knowing the magnetic flux also enables us to make an educated guess about the magnitude of the magnetic field in a particular area.
Inner solenoid has a certain number of turns.
N1 = 300
In an outer solenoid, there are
N2 = 30
Internal solenoid length is
L = 21.0[cm] = 0.21[m] .21[m]
Radius of the internal solenoid
r = diameter/2=2.00[cm]/2=1.00[cm] = 0 .01[m]
Current flowing through the inner solenoid
I = 0.150[A] .150[A]
the current's rate of growth is
di/dt equals 1800[A/s].
The inner solenoid's average magnetic flux through each revolution is
B.A is equal to μ*(N/L)*i.A is equal to [4(pi)*10-7]*[300/0.21]*[0.15]*&
pi;*(0.01) = 8.45966*10^(-8)
Learn more about solenoid here
https://brainly.com/question/15504705
#SPJ4
A sound wave travels through water. What best describes the direction of the water particles?
The water particles move perpendicular to the source of the sound wave.
The water particles move in the same direction as the vibrating source of the sound wave.
The water particles move in random patterns because the sound is diffracted in many directions.
The water particles do not move because the sound wave does not have enough energy.
Answer:
The water particles move in the same direction as the vibrating source of the sound wave.
Explanation:
Answer:
The correct option is B.
Explanation:
Wheel A has three times the moment of inertia about its axis of rotation as wheel B. Wheel B's angular speed is four times that of wheel A.
A) Which wheel has the greater rotational kinetic energy? A,B, Both wheels have the same rotational KE
B) If KA and KB are the rotational kinetic energies of the wheels, what is KA/KB?(express answer to 4 sig fig)
Wheel A has 3 times the moment of inertia as wheel B. Meanwhile Wheel B's angular speed is 4 times that of wheel A.
Wheel B has the greater rotational kinetic energyIf KA and KB are the rotational kinetic energies of the wheels, KA/KB is 0.188The moment of inertia is a quantitative measur of the rotational inertia of a body. The moment of inertia (I) is always specified with respect to the rotation axis.
Rotational kinetic energy is a form of kinetic energy that is caused by the rtation of an object. Rotational kinetic energy formula is:
K = 1/2 Iω²
where:
I = the moment of inertia
ω = angular velocity
From the case, we know that:
I(A) = 3 x I(B)
ω(B) = 4 x ω(A)
Using the Rotational kinetic energy formula, we could find the rotational kinetic energy for each wheelsby respecting the result to wheel B:
Wheel A
K(A) = 1/2 I(A).ω(A)²
K(A) = 1/2 [3I(B)] [1/4.ω(B)]²
K(A) = 1/2 [3I(B)] [1/16.ω(B)²]
K(A) = 3/32 I(B).ω(B)²
K(A) = 0.094 I(B).ω(B)²
Wheel B
K(B) = 1/2 I(B)ω(B)²
K(B) = 0.5 I(B)ω(B)²
From the comparison between both rotational kinetic energi, we know that K(A)<K(B). Hence wheel B has the greater rotational kinetic energy.
Then, KA/KB is:
KA = 0.094 I(B).ω(B)²
KB 0.5 I(B).ω(B)²
KA/KB = 0.188
Learn more about Rotational Kinetic Energy here: https://brainly.com/question/28767837
#SPJ4
determine the modulus of elasticity of a composite material if the strain on the material was 0.09 and the following data are known:
If a composite material underwent a 0.09 strain, the material's modulus of elasticity be is 6.48*10⁶ psi
Ef=10.5*10⁶ psi
Em=0.45*10⁶ psi
Vf=0.6
Vm=1-Vf=0.4
Modulus of elasticity is
E=Vf.Ef+Vm.Em
=0.6*10.5*10⁶ psi+0.4*0.45*10⁶
=6.48*10⁶ psi
Therefore Modulus of elasticity E is 6.48*10⁶ psi
Young's modulus, also known as elastic modulus, tensile modulus, or modulus of elasticity in tension, is the ratio of stress to strain and is equivalent to the slope of a material's stress-strain diagram. Young's modulus is sometimes referred to as the modulus of elasticity and is equal to the longitudinal stress divided by the strain.
Learn more about modulus of elasticity here:
https://brainly.com/question/18993970
#SPJ4
the vectors d and e are [-4,1] and [1,4] respectively .find the angle b/n and e (Use dot product )
(True or False) the energy carried by a photon of ir radiation is greater than the energy carried by a photon of uv radiation.
Answer:
false
ir = infrared radiation ....? right?
Miguel (m=72) and Fernando (89 kg) board the bumper cars at the local carnival. Miguel is moving at a velocity of 4 m/s when he rear-ends Fernando who is at rest in his path. Fernando and his 125-kg car lunge forward at 2 m/s. Determine the post-collision velocity of Miguel and his 125-kg car.
Moving at 1.2 m/s inside the opposite direction following the collision.
Define collision.
A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.
The law of momentum conservation can be used to calculate Miguel's post-collision velocity.
Mass times velocity equals momentum, that is a vector quantity (p=mv). Well before collision, the system's momentum.
Miguel and Fernando's car—was equal to 782 kg*m/s (m1=72 kg) (v1=4 m/s) + (m2=125 kg) (v2=0 m/s). Just after collision,
The system's momentum is equal to 782 kg*m/s (m1=72 kg) (v1=? m/s) + (m2=125 kg) (v2=2 m/s).
We can calculate Miguel's post-collision velocity to be -1.2 m/s by solving for v1.
Miguel is therefore moving at 1.2 m/s inside the opposite direction following the collision.
To know more about collision :
https://brainly.com/question/28820754
#SPJ1
imagine a satellite in low-earth circular orbit, i.e., approximately 300 km above the surface of the earth. if the radius of the earth is 6.37 x 106 meters, and we assume the gravitational force on the satellite is approximately equal to mg with g
Mass of the Earth, M = 6 * 10²⁴
m = 200 kg
R = 6.4 * 10⁶
G = 6.67 * 10¹¹ Nm²/kg²
Height of the satellite, h = 300 km = 3 * 10⁵ m
Total energy of the satellite at height h = 1/2mv² + [G(M*m)/(R+h)]
Orbital velocity of the satellite, v = √[ (G*M) / (R+h) ]
Total energy at height h = 1/2[ (G*M) / (R+h) ]
The negative sign indicates that the satellite is bound to the Earth.
Energy required to send the satellite out of its orbit = – (Bound energy)
= GM*m/ 2(R+h)
= 6.67*10⁻¹¹ * 6*10²⁴* 200 / 2(6.4*10⁶ + 0.3*10⁶)
= 11.9*10⁹ J
If the satellite just escapes from the gravitational field, then total energy of the satellite is zero.
Therefore, we have to supply 11.9*10⁹ J of energy to just escape it.
To learn more about energy, refer: https://brainly.com/question/1932868
#SPJ4
[NOTE:THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: imagine a satellite in low-earth circular orbit, i.e., approximately 300 km above the surface of the earth. if the radius of the earth is 6.37 x 106 meters, and we assume the gravitational force on the satellite is approximately equal to mg with g. The mass of satellite is 200 kg. How much energy must be expended to rocket the satellite out of the earth's gravitational influence?]
