WILL GIVE BRAINLYEST
Find measure of X and Y
X=

Y=

Part B:
Choose the correct degree measure for JKL
A. 98
B. 65.5
C. 262
D. 24.5

Answer: No solution

Step-by-step explanation:

Both of these equations have the same number as to coefficient of x (-6) but have a different constant (-8 and 8). This means that there are no solutions to this system of equations.

The coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2). Then the correct option is D.

The complete options are given below.

1. (-11/2) -(11/2)

2.(-5/2)-(3/2)

3.(-5/2-(11/2)

4. (-11/2) -(-3/2)

Let C be the mid-point of the line segment AB.

A = (x₁, y₁)

B = (x₂, y₂)

C = (x, y)

Then the midpoint will be

x = (x₁ + x₂) / 2

y = (y₁ + y₂) / 2

The end points are given below.

(-3, -7) and (-8, 4)

We have

(x₁, y₁) = (-3, -7)

(x₂, y₂) = (-8, 4)

Then the mid-point will be

x = (- 3 - 8) / 2

x = -11 / 2

y = (-7 + 4) / 2

y = -3/2

Then the coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2).

Then the correct option is D.

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Answer:

-5x=-23

Or

X=23/5

Step-by-step explanation:

The transformation is non-rigid because the side lengths are not preserved.

The drop-down menus and the image of the triangles are not given.

However, the question can still be solved using the available parameters.

The given parameters are:

Pre-image: 6, 10, 8

Image: 3, 5, 8

See that the side lengths of the image and the pre-image are not the same

This means that the transformation is a non-rigid transformation

Hence, the complete statement is the transformation is non-rigid because the side lengths are not preserved.

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The  is probability P(B|A) expressed in simplest form is 1/2 (Option B) See computation below.

P (A) = [[tex][\mathrm{C}_{5}^{1} \mathrm{C}_{8}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 8)/(9 x 8)

P (A) = '5/9

P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 4)/(9 x 8)

= '5/18

P(B|A) = P (AB)/P(A)

= ('5/18)/('5/9)

P(B|A)  = 1/2

From the above we already have P (AB)

this is given as

P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 4)/(9 x 8)

P(AB) = '5/18

Note that:

Event A = drawing a white marble on the first draw

Event B = drawing a red marble on the second draw

P(A) = 8/13; while

P (B) = (5/12) because the first marble was not replaced, thus reducing th sample to 12.

Thus

P(A and B) = P(A)*P(B) = 8/13 * 5/12

P(A and B) =  10/39 (Option B)

Event A - Probability of Drawing a Green Marble is 8/20

Event B - Probability of Drawing a Blue Marble is 5/19

Thus P(B|A) = (8/20) * (5/19)

= [tex]\frac{8 * 5 }{20 * 19}[/tex]

= 40/380; divide numerator and denominator by 20

P(B|A) = 2/19 (Option A)

Event A = Probability of Drawing a red ball = 3/12

Event A = Probability of Drawing a pink ball without replacing the read in Event A = 3/11

Thus P (B and A) =

3/12 x 3/11

P (B and A) = 3/44 (Option A)

The conditions given are as follows:

The sum total of ways thus is

9 x 8

= 72 ways........X

Recall that

Event A is defined as selecting 8 as the first numeral

The only way to select this is one way

Event B is defined as choosing a number less than 6 as the second digit, that is 1, 2, 3, 4, 5

Thus, the possible number of ways to fill second digit = 5/8

Thus, the possible number of ways to form two digits 'AnB' =
('AnB') = 1 x 5 = 5 .................y

Hence Probability (AnB) = 5/72 (Option B)

Given that the non-zero digits are in a combination are not repeated and range from 3 through 8, thus the odd numbers between 3 and 8 are:

3, 5, 7

total numbers is 3, 4, 5, 6, 7, 8

Hence; Event A = choosing an odd number for the first digit = 3/6

Event B = choosing an odd number for the second digit (recall that the numbers are not repeated) = 2/5

= [tex]\frac{2*3}{3*6}[/tex]

= 6/30

= 1/5 (Option A)

If a combination is picked at random with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?

Event A = the first digit is an odd number

Event B = the second digit is an odd number

The numbers from 2 to 9 are:
2,3,4,5,6,7,8,9

The odd numbers between 2 and 9 are:

3,5,7,9

P (A) = 4/8

P (B) = 3/7

P(B|A) = (3/7)/(4/8)

P(B|A) = 3/7

Event A = drawing a white tile on the first draw

Event B = drawing a purple tile on the second draw

|n| = 15 * 14 = 210

| A| = 3*14 = 42

| AnB| = 3*7 = 21

P (A) = 42/210 = 6/30

P (AnB) = 21/210 = 1/10

P(B|A) = (1/10)/6/30)

P(B|A) = 1/10 * 30/6

P(B|A) = 30/60
P(B|A) = 1/2 (Option D)

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Answer:

2 hours

Step-by-step explanation:

you can write two linear equations and then set them equal to each other to see when they intersect. so for the first equation which will be representing the junior space cadets distance from his house. this can be written as

d = 50t + 50

where t represents time and d represents distance. there is 50 being added to the equation since he had already been traveling for an hour

the second equation which will represent his sister Gwen can be represented as

d = 75t

Now we set them equal to each other

50t + 50 = 75t

50 = 25t

2 = t

Answer: $625

Step-by-step explanation:

Total beverage sales = $2,500

Beverage cost = 25%

So, $2,500 x 25% = $2,500 x 0.25 = $625

The equation which relates the mass and length according to the task content is; l = (3/10)m.

From the task content, it follows that the proportional relationship is direct. Hence, the constant of proportionality k can be evaluated as follows;

l = k × m

Hence, k = l/m = 9/30 = 3/10.

Therefore, the proportional relationship is given by the equation; l = (3/10)m

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Answer:

2/5

Step-by-step explanation:

22/11=2

55/11=5

[tex]f(x) = {x}^{2} - 3x + 2 [/tex]

put x = (-1)

[tex] f( - 1) = {( - 1)}^{2} - 3 \times ( - 1) + 2 \\ \\ 1 + 3 + 2 \\ \\ 6.[/tex]

put x = (z)

[tex] f(z) = {z}^{2} - 3 \times z + 2 \\ \\ {z}^{2} - 3z + 2 \\ \\ {z}^{2} - 2z - z + 2 \\ \\ z(z - 2) - 1(z - 2) \\ \\ (z - 1)( z -2 ) \\ \\ (z - 1) = 0 \: \: , \: \: (z - 2) = 0\\ \\ z = 1 \:, \: 2[/tex]

put x = (x+1)

[tex]f(x + 1) = {x}^{2} - 3x + 2 \\ \\ {(x + 1)}^{2} - 3 (x + 1) + 2 \\ \\ {x}^{2} + 1 + 2x - 3x - 3 + 2 \\ \\ {x}^{2} - x \\ \\ x(x - 1) \\ \\ x(x - 1) = 0 \\ \\ x - 1 = \frac{0}{x} \\ \\ x - 1 = 0 \\ \\ x = 1.[/tex]

put x = (√2 + 1 )

[tex]f( \sqrt{2} + 1) = {x}^{2} - 3x + 2 \\ \\ {( \sqrt{2} + 1) }^{2} - 3( \sqrt{2} + 1) + 2 \\ \\ 2 + 1 + 2\sqrt{2} - 3 \sqrt{2} - 3 + 2 \\ \\ 3 - 1 \sqrt{2} - 1 \\ \\ 2 - \sqrt{2} \\ \\ 2 - 1.4 (optional \: \: \: steps)\\ \\ 0.6 \: \: [/tex]

Answer:

A

Step-by-step explanation:

Given:

[tex]8-3x > 2(3x-5)[/tex]

Simplify by distributing:

[tex]8-3x > 6x-10[/tex]

Add 10 to left side and add 3x to the right side:

[tex]18 > 9x[/tex]

Answer:

Option B is correct

Answer:

B there is enough raspberries to make 4 pie they can 6 pies if they 2 more of raspberries

#1

Correct version

[tex]\\ \rm\Rrightarrow (x^3+2x^2-x)-(3x^3-3x^2+2x-4)[/tex]

[tex]\\ \rm\Rrightarrow x^3+2x^2-x-3x^3+3x^2-2x+4[/tex]

[tex]\\ \rm\Rrightarrow x^3+5x^2-3x+4[/tex]

#2

[tex]\\ \rm\Rrightarrow (x^2-3x+2)(x+1)[/tex]

[tex]\\ \rm\Rrightarrow x(x^2-3x+2)+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-3x^2+2x+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-2x^2-x+2[/tex]

Answer:

Step-by-step explanation:

We got two shapes in the given figure,on the right we got a rectangle and on the left we have a square.

Area of rectangle:-

Area of square :-

Total area :-

Answer:

Step-by-step explanation:

you have two rectangles, the bigest has the base of 6cm and the height of 4cm, the area is 6 * 4 = 24cm ^ 2, the other rectangle has the base of 6 - 4 = 2 and the height of 5 - 4 = 1, 2*1=2.

we add the dimensions and we have the area of ​​the complete figure 24 + 2 =

26 cm ^ 2

Answer:

1. [tex]x = 2.45s[/tex]

2. The diving board is 45 ft high.

Step-by-step explanation:

• When Lindsey is 30 feet in the air, y = 30.

[tex]30 = -16x^2 + 33x +45\\\\-16x^2 + 33x +15 = 0\\\\16x^2 - 33x -15 = 0\\[/tex]

Using quadratic formula, solve for x:

[tex]x = \frac{33 + \sqrt[]{(-33)^2 - 4(16)(-15)} }{2(16)}[/tex]

[tex]x = 2.45s[/tex]

• If we calculate the height of Lindsey in the air when she is standing on the diving board, we can find the height of the diving board above the ground.

When she is standing on the board, x = 0 as no time has passed after jumping.

[tex]y = -16(0)^2 + 33(0) +45\\\\y = 45 ft[/tex]

The path straight to the end of the hike is 6 km farther than past the scenic lookout.

The map is not given, but the question can still be answered

From the question, the positions are given as::

Maria = (4, -4)

Scenic = (2, 3)

End = (-5, 5)

The distance between Maria and the end point is calculated using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]Route\ 1 = \sqrt{(4 + 5)^2 + (-4 -5)^2}[/tex]

[tex]Route\ 1 = 13[/tex]

The distance between Maria and the scenic lookout is calculated using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]Route\ 2 = \sqrt{(4 - 2)^2 + (-4 -3)^2}[/tex]

[tex]Route\ 2 = 7[/tex]

The distance between both routes is:

Distance = 13 - 7

Evaluate

Distance = 6

Hence, the path straight to the end of the hike is 6 km farther than past the scenic lookout.

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Answer:

(a)9×3=37' 97 and 8 are factors of 37

Answer:

x > 9

Step-by-step explanation:

for this inequality, we want to isolate x, so that we know the inequality of x

5x + 3 > 48

     - 3      -3        {subtract 3 from both sides to get x alone}

5x > 45

/5      /5                {divide both sides by 5 to find 1x}

x > 9

So , x > 9 is the inequality in terms of x {is the solution}

hope this helps! :)

Answer:

[tex]\huge\boxed{\sf x > 9}[/tex]

Step-by-step explanation:

5x + 3 > 48

Subtract 3 to both sides

5x > 48 - 3

5x > 45

Divide 5 to both sides

x > 9

[tex]\rule[225]{225}{2}[/tex]

Let's see

[tex]\boxed{\sf log_aa=1}[/tex]

Now

[tex]\\ \rm\Rrightarrow log_{10}0.0001)[/tex]

[tex]\\ \rm\Rrightarrow log_{10}10^{-4}[/tex]

[tex]\\ \rm\Rrightarrow -4log_{10}10[/tex]

[tex]\\ \rm\Rrightarrow -4[/tex]

Answer:

This has already been answered correctly, but I'll add an additional perspective.  The log of (0.0001 to the base 10 is -4.

Step-by-step explanation:

log(base 10) says give us an exponent, x, that would be required to make [tex]10^{x}[/tex] equal to a specified number, in this case 0.0001.

[tex]10^{0}[/tex] = 1

[tex]10^{1}[/tex] = 10

[tex]10^{-1}[/tex] = 0.1

[tex]10^{-2}[/tex] = 0.01

[tex]10^{-4}[/tex] = 0.0001

The log of (0.0001) to the base 10 is -4.

Answer:

6 green marbles should be added.

Step-by-step explanation:

If the probability of drawing a blue marble from 18 marbles is 2/3 then there are 12 blue marbles because 18 times 2/3 is 12. This means that to reduce this probability to 1/2 you need to add 6 more marbles to the total amount to get it to 24. Now the probability of getting a blue marble is 12/24 which is 1/2.

Answer:

x ≈ 1.1

Step-by-step explanation:

using the cosine ratio in the right triangle

cos41° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{0.8}{x}[/tex] ( multiply both sides by x )

x × cos41° = 0.8 ( divide both sides by cos41° )

x = [tex]\frac{0.8}{cos41}[/tex] ≈ 1.1 ( to the nearest tenth )

Answer:

5/18

Step-by-step explanation:

The LCD of 9, 3, and 6 is 18.

1 - 2/9 - 1/3 - 1/6 =

= 18/18 - 4/18 - 6/18 - 3/18

= 5/18

Answer: 5/18

Step-by-step explanation:

1/1 - 2/9 - 1/3 - 1/6

18 - 4 - 6 - 3/18

5/18

Answer:

[tex]7\sqrt{3}[/tex]

Step-by-step explanation:

This is a special triangle with the angles being 30-60-90. The adjacent side to the angle of 30 degrees has a length of x * sqrt(3). The opposite side has a length of x. Since the opposite side has a length of 7 here you simply plug that into x * sqrt(3) to find the length of the adjacent side of the angle 30 degrees which gives you 7 * sqrt(3)

Answer:

The dog is 16 years old.

Step-by-step explanation:

X/4 + 6 = X/8 + 8

X/4-X/8 = 8-6

0.125X = 2

X = 2/0.125

X = 16

Answer:

16 years old

Step-by-step explanation

Dividing the dog’s age by 4 and adding 6

D÷4  + 6

dividing the dog’s age by 8 and adding 8

D÷8  + 8

equating both

D÷4  + 6 = D÷8 + 8

=> D÷4 - D÷8  = 2

multiplying by 8 both sides

=> 2D - D = 16

=> D = 16

hence, the dog is 16 years old

Answer:

1. 4

2. 10

3. 14

Step-by-step explanation:

A = -6

B = 0

C = 4

D = 8

1. BC = |0 - 4| = 4

2. AC = |-6 - 4| = |-10| = 10

3. AD = |-6 - 8| = |-14| = 14

Answer:

1.  BC = 4

2.  AC = 10

3.  AD = 14

Step-by-step explanation:

Ruler Postulate

The distance between any two points on a number line is their difference.

Question 1

Given:

Therefore, using the Ruler Postulate:

⇒ BC = |b - c|

⇒ BC = |0 - 4|

⇒ BC = |-4|

⇒ BC = 4

Question 2

Given:

Therefore, using the Ruler Postulate:

⇒ AC = |a - c|

⇒ AC = |-6 - 4|

⇒ AC = |-10|

⇒ AC = 10

Question 3

Given:

Therefore, using the Ruler Postulate:

⇒ AD = |a - d|

⇒ AD = |-6 - 8|

⇒ AD = |-14|

⇒ AD = 14

Answer:

x=1

Step-by-step explanation:

8x-5(x-3) = 18

The first step is to distribute

8x -5x+15 = 18

Combine like terms

3x+15 = 18

Subtract 15 from each side

3x+15-15=18-15

3x=3

Divide by 3

3x/3 =3/3

x=1

Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

Helpful fact:  Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

Option 1.  m∠R > 90°

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

Option 2.  m∠S + m∠T < 90°

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) >  m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

Option 3.  m∠S = m∠T

Not necessarily.  While m∠S could equal m∠T, it doesn't have to.  

Example 1:  m∠S = m∠T = 10°;  By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2:  m∠S = 15°, and m∠T = 10°;  By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

Option 4.  m∠R > m∠T

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

Option 5.  m∠R > m∠S

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

Option 6.  m∠S > m∠T

Not necessarily.  While m∠S could be greater than m∠T, it doesn't have to be.  (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

Answer: Option 1, 2, 4, & 5  or  

A. m∠R > 90°;  B. m∠S + m∠T < 90°;  D. m∠R > m∠T;  & E. m∠R > m∠S

Step-by-step explanation:   Trust Me!  

If you are working on Edge the answer is correct. The proof is down below. I hope someone finds this helpful.

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