William travels only on Saturdays and Sundays and has flown 400 miles this month. Jason travels every weekday and has flown 500 miles this month. Who travels more miles per day for this month? Explain.

Therefore, the speed of the bird is 55.44 kilometers per hour.

We know that speed is given by the formula distance travelled divided by the time taken.

Here distance = 46.2 meters and time = 3 seconds.

We are asked to find the speed in terms of kilometers per hour.

So, we need to convert the meters into kilometres and the seconds into hours.

We know that 1 kilometer is equal to 1000 meters.

⇒ 1 meter = (1/1000) kilometer

⇒ 1 meter = 0.001 kilometer

Therefore, 46.2 meters = 46.2 × (0.001) kilometers = 0.0462 kilometers

We know that 1 hour is equal to 3600 seconds.

⇒ 1 second = (1/3600) hours

⇒ 3 seconds = (3/3600) hours

Therefore the speed of the bird is equal to

speed = 0.0462 ÷ (3/3600) kilometers per hour

⇒ speed = 3600 × 0.0462 ÷ 3 kilometers per hour

⇒ speed = 3600 × 0.0154 kilometers per hour

⇒ speed = 55.44 kilometers per hour

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Disclaimer:

The question is not complete.

Assuming the following as the complete question for answering.

An eagle flies 46.2 meters in 3 seconds. We need to find the speed of the eagle in kilometers per hour.

Answer:

Option D) 6.8 × 10⁻²

Answer:

D

Step-by-step explanation:

The age distribution of nurses in Great Britain at the time of Florence Nightingale will be 30 - 39, 40 - 49, etc.

Age distribution, also known as age composition, is the proportion of people in each age group within a given population in population studies. The main reason why age distributions vary between nations is because of variations in fertility rates and trends.

It can be estimated by dividing the populations of those aged 0 to 14, and 65 and older, by those aged 15 to 64. Example: In a town, there are 6,800 people over the age of 65 and 41,650 children under the age of 14.

The percentages of people in a population who are a certain age have a significant impact on how quickly that population grows.

In conclusion, the age distribution of nurses in Great Britain at the time of Florence Nightingale will be 30 - 39, 40 - 49, etc.

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Answer:

The answers to the question in reference to the graph are mentioned below.

Step-by-step explanation:

It is given that we need to find the mentioned questions alongside the graphs of the functions;

Now, let us consider the first question given herein;

Now, let us consider the second part of the question;

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Answer: 12328 is the answer

Step-by-step explanation:

You put the 536 on top and 23 on the bottom and you multiply 3 first to get 1608 then you multiply 2 to get 10720. You add these two numbers and you get 12328 as your answer! :D

The product of 23 multiplied by 536 is 12,328.

We have,

The concept used to find the product of 23 multiplied by 536 is basic multiplication.

Start with the rightmost digit of the bottom number (536), which is 6.

Multiply 6 by the top number (23). We have 6 multiplied by 3, which equals 18.

Write down the rightmost digit of the result (8) under the line.

Carry over the remaining digit, which is 1, to the next column.

Now, multiply the carried-over digit (1) by the top number (23). We have 1 multiplied by 3, which equals 3.

Add the carried-over digit (1) to the result (3), which gives us 4.

Write down the rightmost digit of this new result (4) next to the previous digit (8), giving us 48.

Finally, multiply the leftmost digit of the bottom number (5) by the top number (23). We have 5 multiplied by 3, which equals 15.

Write down this result (15) shifted one place to the left, giving us 150.

Add the two partial products: 48 + 150 = 198.

Therefore,

The product of 23 multiplied by 536 is 198.

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The total amount of that Harry will need for the project is nineteen and seven twentieth feet. option A

Wood 1:

Total = Length of each × Number of pieces

= 2 5/8 × 6

= 21/8 × 6

= 126 / 8

= 15 3/4 meters

Wood 2:

Total = Length of each × Number of pieces

= 1 1/5 × 3

= 6/5 × 3

= 18/5

= 3 3/5 meters

Total amount of wood needed for the project = 15 3/4 meters + 3 3/5 meters

= 126/8 + 18/5

= (630+144) / 40

= 774/40

= 19 14/40

= 19 7/20 meters

Therefore, the total amount of wood that Harry will need for the project is nineteen and seven twentieths feet. option A

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Answer:-32 -0.46x is ur answer

Step-by-step explanation:

In linear equation, n = 15 is the value of equation .

What in mathematics is a linear equation?

What is the linear equation's formula?

A linear equation has the slope-intercept form y = mx + b. Variables in the equation are x and y. When x is 0, the integers m and b provide the line's slope (m) and the value of y. (b).

-17 = 1/5n - 20

- 17 + 20 = 1/5n

3 = n/5

n = 15

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The animal is 150 inches tall .

Scale Factor = ( scale / actual )

Given : Scale Factor = ( 1 / 30 )

To find : the actual height of animal .

Let t be the actual height of animal .

Therefore Scale Factor comes out to be ( 5 / t ) .

Equating both the scale factors and hence finding the value of t ,

( 1 / 30 ) = ( 5 / t )

t = 150 inches .

Therefore , the animal is 150 inches tall .

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Answer:

21 dollars

Step-by-step explanation:

Cents ÷ 100 = Dollars

2100 ÷ 100 = 21

Hope this helped! (๑>◡<๑) xx

Answer:  Draw a straight line through (0, 16) and (1, 14)

The graph is below.

=========================================================

Explanation:

There are at least two approaches we can take

-----------------

Method 1

Plug in x = 0 to find that....

y = -2x+16

y = -2(0)+16

y = 16

The point (x,y) = (0,16) is on the line. This is the y intercept

Repeat similar steps for x = 1

y = -2x+16

y = -2(1)+16

y = 14

The point (1, 14) is also on the line

Plot the points (0, 16) and (1, 14). Then draw a straight line through them to complete the graph for y = -2x+16

You only need 2 points at minimum to draw a linear graph.

The graph is shown below. Ignore the stuff in red.

-----------------

Method 2

Compare y = -2x+16 to the form y = mx+b

The y intercept is where the graph crosses the y axis. In this case, it's at the location (0, 16)

Start at this point and move down 2 units and to the right 1 unit to arrive at (1, 14) which is another point on the line.

The stuff in red shows this motion of "down 2, right 1"

note that slope = -2 = -2/1 = rise/run

rise/run = -2/1

rise = -2 = go down 2

run = 1 = go to the right 1

-----------------

Side note: You can use a graphing tool like Desmos or GeoGebra to graph quickly. I used GeoGebra to make the diagram below. Though it's handy to have practice to do it by hand.

Answer:

False

Step-by-step explanation:

This applies perfectly when x and y are negative.

What if both x and y are positive??

x=4, y=3.

4>3 which is true

but |4|<|3| = 4<3 ==> not true.

Hence, the answer is false

Answer: 12,186.96

Step-by-step explanation:

Final Correct Answer:

14n - 16g + 8

Hope this helps :)

Error:

The error was that I'm the first step where they distributed -4 to the numbers - 3n, + 4g, - 2 wrong. They multiplied with the wrong integer rules.

Real answer - how to solve:

- 4 multiply by - 3n would be + 12n (Negative times Negative equals Positive).

-4 multiply by + 4g would be - 16g (Negative times Positive equals Negative).

- 4 multiply by - 2 would be + 8 (Negative times Negative equals Positive).

So that was the error.

Step-by-step explanation:

1. Distribute.

2n - 4( - 3n + 4g - 2)

2n + 12n - 16g + 8

2. Combine Like Terms (CLT).

2n + 12n - 16g + 8

14n - 16g + 8

Using the Empirical Rule, the percentages are given as follows:

a) 99.7%.

b) 49.85%.

c) 0.15%.

It states that, for a normally distributed random variable:

In this problem, we have that:

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Answer:In his equation height is given by h(t) and t represents time. The shape of this equation is that of a downward facing parabola because the coefficient of the first term is negative. Therefore, the maximum height is found by determining the vertex of the parabola which is given by b/2a or 50/(16*2). Thus after, 1.5625 seconds the ball reaches it maximum height of 44 feet (plug 1.5625 into formula.)

Notice that the formula has a constant of 5 in it meaning that the ball was throw up at a 5 foot starting position above the ground. Thus, for the ball to hit the ground h(t) = -5. So, what is the value of t that gives that value? Here we just use the quadratic formula and find that t = 3.31 seconds. That makes sense doesn't it? 2*1.5625 would get the ball back to the starting position ( 3.125 sec) and the ball needs another .185 sec to fall the last 5 feet. What speed is that in MPH? That would be 5/.185*(3600/5280) = 18.4 MPH. That is a lot slower than a 95 MPH fast ball.

Step-by-step explanation:

Answer:

l = [tex]\frac{S-\pi r^2}{\pi r}[/tex]

Step-by-step explanation:

S = πr² + πrl ( subtract πr² from both sides )

S - πr² = πrl ( isolate l by dividing both sides by πr )

[tex]\frac{S-\pi r^2}{\pi r}[/tex] = l

Answer:

[tex] l = \dfrac{S - \pi r^2}{\pi r} [/tex]

Step-by-step explanation:

[tex]S = \pi r^2+\pi rl[/tex]

[tex]\pi r^2+\pi rl = S[/tex]

[tex]\pi rl = S - \pi r^2[/tex]

[tex] l = \dfrac{S - \pi r^2}{\pi r} [/tex]

Answer:

candies bought = 3

price of 1 candy = $2.50

price of 3 candies =$(3*2.50)

Step-by-step explanation:

byeeee

Answer: 50/100=0.5

100/10=10

Step-by-step explanation:

50/100=

1/2=0.5

100/10=

10^2 / 10^1 =

10^(2-1)=

10^1=10

50/100=0.5

100/10=10

Answer: 88.4 centimeters

Step-by-step explanation:

Let's make a proportion:

412 m - 82.4 cm

442 m - x cm

Hence,

[tex]\displaystyle\\x=\frac{442*82,4}{412} \\\\x=\frac{442*82.4}{82.4*5} \\\\x=\frac{442}{5}=\\\\x=\frac{88,4*5}{5}=\\\\x=88,4\ cm[/tex]

20 is the value in the given data set which have a relative frequency of 30%.

Given,

The data set as,

10, 20, 20, 50, 30, 20, 10, 50, 60, 70.

We have to find the value from the above given data set which have a relative frequency of 30%.

Relative frequency = (subgroup count / total count) × 100

Here, 20 is the most repeating value. So we can calculate with it.

There are three 20's in the set.

So, subgroup count = 3

Total count = 10

Then,

Relative frequency = (3/10) × 100 = 30

Hence, we can conclude that 20 is the value in the given data set which have a relative frequency of 30%

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Answer: A

Step-by-step explanation:

Answer:

15m⁹

Step-by-step explanation:

-3m² × -5m⁷ multiply bases (-3×-5=15). when multiplying bases you add exponents (2+7=9)

= 15m⁹

[tex]5x+y=35 \implies 15x+3y=105 \\ \\ \implies (15x+3y)+(7x-3y)=105+27 \\ \\ 22x=132 \\ \\ \boxed{x=6} \implies 7(6)-3y=27 \\ \\ -3y=-15 \\ \\ \boxed{y=5}[/tex]

Using the Fundamental Counting Theorem, there is a 0.7143 = 71.43% probability that the code either starts with an 'A' or ends with an even digit.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem, we have that the code has:

Hence the number of codes is:

N = 14 x 5 x 14 x 5 x 14 x 5 = 343,000.

The number of codes starting with an A is:

Na = 5 x 14 x 5 x 14 x 5 = 24,500.

The number of codes ending with an even digit(0, 2 or 4) is:

Ne = 14 x 5 x 14 x 5 x 14 x 3 = 205,800.

The number of codes starting with an A and ending with an even digit is:

Nae = 5 x 14 x 5 x 14 x 3 = 14,700.

The number of desired outcomes is:

24500 + 205800 + 14700 = 245,000.

Hence the probability is:

245,000/343,000 = 0.7143.

0.7143 = 71.43% probability that the code either starts with an 'A' or ends with an even digit.

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[tex]\textit{sum of all interior angles}\\\\ S=180(n - 2) ~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n=5 \end{cases}\implies S=180(5-2)\implies S=540 \\\\[-0.35em] ~\dotfill\\\\ 105+118+75+130+x~~ = ~~540\implies 428+x=540\implies x=112[/tex]

Answer:

we conclude that if JKL is rotated 180° clockwise about the origin, what are the new coordinates of point J(-4, 6) will be: J' (4, -6)

Hence, the answer choice (B) is correct.

Step-by-step explanation:

The rule of rotating a point 180° clockwise about the origin states that if we rotate a point P(x, y) 180° clockwise about the origin, it would take a new position with the coordinates P'(-x, y).

In other words, the sign of its x and y coordinates change.

Thus, the rule is:

P(x, y) → P'(-x, -y)

Given the triangle ΔJKL with the coordinates

J(-4, 6)

K(-1, 2)

J(-4, 2)

Thus, according to the rule:

P(x, y) → P'(-x, -y)

The new position of point J (-4, 6) will be J' (4, -6)

The new position of point K (-1, 2) will be K' (1, -2)

The new position of point L (-4, 2) will be L'  (4, -2)

Finally, we conclude that if JKL is rotated 180° clockwise about the origin, what are the new coordinates of point J(-4, 6) will be: J' (4, -6)

Hence, the answer choice (B) is correct.

Answer:

.9 inches

Step-by-step explanation:

Set up and solve this proportion:

[tex] \frac{1.2}{400} = \frac{x}{300} [/tex]

[tex]400x = 360[/tex]

[tex]x = .9[/tex]

Answer:

Hello,

Answer 207

Step-by-step explanation:

[5, 29, 47, 61, 83, 225]

[5, 29, 41, 67, 83, 225]

[5, 23, 47, 61, 89, 225]

[5, 23, 41, 67, 89, 225]

[2, 5, 7, 43, 61, 89, 207]

[2, 3, 5, 47, 61, 89, 207]

[2, 3, 5, 41, 67, 89, 207]

import sys

#-------------------------------------------------------

def see(txt,arr):

   print (txt,"=",end =" ")

   for i in range(1,10 ):

       if arr[i]:

           print (i,end=" ")

   print ()

#-------------------------------------------------------

def libre(p):

   if p==0:

       return True

   if p<10:

       a=p

       if not(used[a]):

           return True

   else:

       a=p//10

       b=p%10

       if not(used[a]) and not(used[b] ):

           return True

   return False

#-------------------------------------------------------

def store(p):

# on ne stock pas 0

   global used

   #print ("in store ",p)

   if p==0:

       return

   if p<10:

       used[p]=True

   else:

       a=p//10

       b=p%10

       used[a]=True

       used[b]=True

   return            

def isSol():

   global mini,k,mini_set,all_mini_set

   for i in range(1,10):

       if not used[i]:

           return False

   s=i_1+i_2+i_3+i_4+i_5+i_6+i_7+i_8+i_9

   if s <= mini[0]:

       if s < mini[0]:

           k=k+1

       mini[0]=s

       mini[1]=i_1

       mini[2]=i_2

       mini[3]=i_3

       mini[4]=i_4

       mini[5]=i_5

       mini[6]=i_6

       mini[7]=i_7

       mini[8]=i_8

       mini[9]=i_9

       a_set=sorted(set([i for i in mini if i >0] ))

       if (a_set not in all_mini_set):

           mini_set=a_set.copy()

           all_mini_set.append(a_set)

           print (a_set)

       #print (mini,end="")

       """

       see("used ",used)

       see("sav_9",sav_9)

       see("sav_8",sav_8)

       see("sav_7",sav_7)

       see("sav_6",sav_6)

       see("sav_5",sav_5)

       see("sav_4",sav_4)

       see("sav_3",sav_3)

       see("sav_2",sav_2)

       see("sav_1",sav_1)

       """

       #if k>2:

       #    sys.exit(0)

   return True

#-------------------------------------------------------

#╚ 0 : ne pas utiliser

jeu=[

    [],

    [0,13, 17, 19, 31, 41, 61, 71],

    [0,2,23,29],

    [0,3,13,23,31,37,43,53,73,83],

    [0,41,43,47],

    [0,5,53,59],

    [0,61,67],

    [0,7,17,37,47,67,71,73,79,97],

    [0,83,89],

    [0,19,29,59,79,89,97]

    ]

print ("-------------------------------------------")

for i in range(10):

   print (jeu[i])

print ("-------------------------------------------")

mini=[1000]+[0 for i in range(1,10) ]

mini_set={}    

all_mini_set=[]

used=[False for i in range(10 )]

sav_1=used.copy()

k=0

for i_1 in jeu[1]:

   used=sav_1.copy()

   if libre(i_1):

       store(i_1)

       sav_2=used.copy()

       for i_2 in jeu[2]:

           used=sav_2.copy()

           if libre(i_2):

               store(i_2)

               sav_3=used.copy()

               for i_3 in jeu[3]:

                   used=sav_3.copy()

                   if libre(i_3):

                       store(i_3)

                       sav_4=used.copy()

                       for i_4 in jeu[4]:

                           used=sav_4.copy()

                           if libre(i_4):

                               store(i_4)

                               sav_5=used.copy()

                               for i_5 in jeu[5]:

                                   used=sav_5.copy()

                                   if libre(i_5):

                                       store(i_5)

                                       sav_6=used.copy()

                                       for i_6 in jeu[6]:

                                           used=sav_6.copy()

                                           if libre(i_6):

                                               store(i_6)

                                               sav_7=used.copy()

                                               for i_7 in jeu[7]:

                                                   used=sav_7.copy()

                                                   if libre(i_7):

                                                       store(i_7)

                                                       sav_8=used.copy()

                                                       for i_8 in jeu[8]:

                                                           used=sav_8.copy()

                                                           if libre(i_8):

                                                               store(i_8)

                                                               sav_9=used.copy()

                                                               for i_9 in jeu[9]:

                                                                   used=sav_9.copy()

                                                                   if libre(i_9):

                                                                       store(i_9)

                                                                       isSol()

                                                               used=sav_9.copy()