Woof Chow Dog Food Company believes that it has a market share of 25 percent. It surveys n = 100 dog owners and ask whether or not Woof Chow is their regular brand of dog food, and 23 people say yes. Based upon this information, what is the critical value if the hypothesis is to be tested at the 0.05 level of significance?a. 1.28.b. 1.645.
c. 1.96.
d. 2.575.

The expression that represents that number of items collected by Team A is a=2b+4.

Given that in a hunt, two teams collected a number of items for their teams. Now the items collected by team A is 4 more than the twice of the items collected by the team B. Let the items collected by team A be 'a' and the items collected by team B will be 'b'.

Now, team A collected items are 4 more than the doubled value of team B.

The expression that represents the items collected by the second team, that is Team A is:

a=2b+4

Therefore the expression that represents items collected by team A is a=2b+4.

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The calculated test statistic (t = -0.527) is not less than -1.894 or greater than 1.894.

A hypothesis test can be performed to determine whether the mean volume of beverage in the cans differs from 12 ounces using the following steps:

(1)State the null hypothesis and the alternative hypothesis.

The null hypothesis is that the mean volume of beverage in the cans is equal to 12 ounces (μ = 12). The alternative hypothesis is that the mean volume of beverage in the cans is not equal to 12 ounces (μ ≠ 12).

(2)Select a level of significance (α).

In this case, the level of significance is α = 0.05.

(3)Calculate the sample mean and standard deviation.

The sample mean can be calculated as:

mean = (11.96 + 12.10 + 12.04 + 12.13 + 11.98 + 12.05 + 11.91 + 12.03) / 8 = 12.04375

The sample standard deviation can be calculated as:

[tex]s=\sqrt((11.96 - 12.04375)^2 + (12.10 - 12.04375)^2 + (12.04 - 12.04375)^2 + (12.13 - 12.04375)^2 + (11.98 - 12.04375)^2 + (12.05 - 12.04375)^2 + (11.91 - 12.04375)^2 + (12.03 - 12.04375)^2) / (8 - 1))[/tex] [tex]s=0.277764079[/tex]

(4)Calculate the test statistic.

The test statistic can be calculated as:

t = (mean - 12) / (s / sqrt(8))

(5)Determine the critical value(s) from the t-distribution table with 7 degrees of freedom (8 - 1).

At a significance level of 0.05 and 7 degrees of freedom, the critical value from the t-distribution table is approximately ±1.894.

(6)Compare the test statistic to the critical value(s).

If the test statistic is less than -1.894 or greater than 1.894, then the null hypothesis can be rejected. Otherwise, the null hypothesis cannot be rejected.

(7)Conclude the hypothesis test.

In this case, the calculated test statistic (t = -0.527) is not less than -1.894 or greater than 1.894. Therefore, we cannot reject the null hypothesis. This means that there is not enough evidence to conclude that the mean volume of beverage in the cans is different from 12 ounces.

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The value of the probability is 0.09

from the question, we have the following parameters that can be used in our computation:

P(A) = 0.42, P(B) = 0.14, and P(A or B) = 0.47

Using the above as a guide, we have the following:

P(A and B) = P(A) + P(B) - P(A or B)

substitute the known values in the above equation, so, we have the following representation

P(A and B) = 0.14 + 0.42 - 0.47

Evaluate the expression

P(A and B) = 0.09

Hence, teh probability is 0.09

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The most precise of the measures given 44mm. Hence option B is the correct answer.

The closeness of measured values is referred to as precision. We require the lowest scale attainable to measure in order to measure a value accurately.

Different scales of measures are presented to us. Any of these scales can be used to calculate the distance between two places. But we need to utilize the lowest scale in order to acquire an exact measurement. The millimetre (mm) is the lowest used scale in the options, making the measurement

Thus for the given options the smallest and the precise measure is obtained at 44mm.

Hence option B is the correct answer.

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The mean, median, range, and standard deviation are all measures that can be used to calculate information about a set of numbers, such as the ages of ten randomly selected students.

The mean is the result of totaling the ages of ten randomly selected students and then dividing by ten. This calculation is also known as the average. To calculate the mean, first add up all of the ages, which gives us the sum. Then divide the sum by the number of students, which in this case is 10. The result is the mean, or the average age of the group.

The median is the middle value of a group of numbers. To calculate the median, first put the ages in order from least to greatest. Then find the middle value. If there is an even number of values, then the median is the average of the two middle values.

The range is the difference between the highest and lowest values. To calculate the range, just subtract the smallest number from the largest.

The standard deviation is a measure of variation in a set of numbers. To calculate standard deviation, first subtract the mean from each value, then square each of those differences. Add up these squared differences and divide by the number of values. Then take the square root of that number. The result is the standard deviation.

The mean, median, range, and standard deviation are all measures that can be used to calculate information about a set of numbers, such as the ages of ten randomly selected students.

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Answer:

[tex]10^{1}[/tex]

Step-by-step explanation:

13 + 9 - 1 - 11

Add 13 and 9 to get 22.

22 - 1 - 11

Subtract 1 from 22 to get 21.

21 - 11

Subtract 11 from 21 to get 10.

10

When given expression (4x⁴-7x³+7x²-12x+15)/(x-1) is solved, result in the form q(x)+r(x)/b(x) will be -7x² + 4 + 19/(x-1).

Expressions in mathematics are mathematical statements that are made up of at least two sentences that contain numbers, variables, or both, and are connected by an operator. Addition, subtraction, multiplication, and division are examples of mathematical operations. For example, x + y is an equation that separates the terms x and y by an addition operator. There are two sorts of expressions in mathematics: numerical expressions, which include simply numbers, and algebraic expressions, which contain both numbers and variables.

e.g. A number is 6 times larger than another number, x. This statement may be expressed mathematically as x/2 + 6. Complex issues are solved using mathematical expressions.

Now,

Given expression to solve is (4x⁴-7x³+7x²-12x+15)/(x-1)

then dividing this

=4x⁴/x-1-7x³/x-1+7x²/x-1-12x/x-1+15/x-1

=4x³-3x²+4x-8+7/x-1  in form of  q(x)+r(x)/b(x)

= 4x⁴/x-1-7x³/x-1+7x²/x-1-12x/x-1+15/x-1

= -7x² + 4 + 19/(x-1)

hence,

          When given expression (4x⁴-7x³+7x²-12x+15)/(x-1) is solved, result in the form q(x)+r(x)/b(x) will be -7x² + 4 + 19/(x-1).

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The probability that a student choosen at random likes english but not maths is 299/676.

Let A be the event that a student likes math, and B be the event that a student likes English.

From the given information, we know that:

P(A) = 15/26

P(B) = 13/26

P(neither A nor B) = 9/26

To find the probability that a student chosen at random likes English but not math, we can use the formula:

P(B and not A) = P(B) - P(A and B)

The probability of A and B can be found by multiplying the probabilities of A and B together, since they are not independent:

P(A and B) = P(A) × P(B) = (15/26) × (13/26) = 195/676

Substituting the given probabilities into the formula, we get:

P(B and not A) = (13/26) - (195/676)

Simplifying, we get:

P(B and not A) = 299/676

Therefore, the probability that a student chosen at random likes English but not math is 299/676.

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Answer:

To solve it, you need to use vectors. Let me show you how.

To find the vector that describes the translation, we need to subtract the coordinates of point A from the coordinates of the translated point. Let the vector be v. Then we have:

v = (-1, -3) - (-4, 2)

v = (-1 + 4, -3 - 2)

v = (3, -5)

To write this vector as a column vector, we write it vertically with square brackets. So we have:

v = [3

   -5]

Therefore, the vector that describes the translation is [3

   -5].

Step-by-step explanation:

The probability that a randomly selected adult has an IQ less than 140 is 97.72%.

What is the standard deviation?

The standard deviation is a statistic that expresses how much variation or dispersion there is in a set of values. While a high standard deviation suggests that the values are dispersed over a wider range, a low standard deviation suggests that the values tend to be close to the set mean.

Given that the mean of adults' IQ is μ=100 and the standard deviation is σ=20.

The formula of z-score is z = (X - μ)/σ

Putting the value of μ = 100, σ=20, and X = 140:

z = (140 - 100)/20

z = 40/20

z = 2

From z table, we get the value of z is 0.9772 = 97.72%

P(X<140) = P(z = 2.0) = 97.72%

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The density of water is 1 g/mL, so for this problem, we would multiply 103.8 mL by 1 g/mL to get our answer of 103.8 grams.

The density of water is 1 gram per milliliter (1 g/mL). This means that for every milliliter of water, there is 1 gram. Therefore, to answer the question of how many grams of C12H24012 is needed to acquire the needed volume of water (103.8 mL), we need to multiply the volume of water by the density of water. To do this, we will use the equation: Mass (g) = Volume (mL) x Density (g/mL). For this problem, the equation would be: Mass (g) = 103.8 mL x 1 g/mL.Therefore, the answer to the question is 103.8 grams of C12H24012 is needed to acquire the needed volume of water.In conclusion, to figure out how many grams of C12H24012 is needed to acquire the needed volume of water, we need to multiply the volume of water (in mL) by the density of water (in g/mL). The density of water is 1 g/mL, so for this problem, we would multiply 103.8 mL by 1 g/mL to get our answer of 103.8 grams.

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After finding the sides of the triangle using sine law, we found that the height of the flagpole is found to be 110.89 ft.

What is meant by sine law?

The law of sines specifies how many sides there are in a triangle and how their individual sine angles are equal. The sine law, sine rule, and sine formula are additional names for the sine law.

The side or unknown angle of an oblique triangle is found using the law of sine. Any triangle that is not a right triangle is referred to as an oblique triangle. At least two angles and their corresponding side measurements should be used at once for the sine law to function.

Given,

 The distance between two observers = 600 ft

The angle of elevation of the first observer = 19°

The angle of elevation of the second observer = 21°

We are asked to find the height of the flagpole.

The figure is given below.

There are 2 right triangles, ΔABD and ΔCBD.

We will start with ΔABC.

∠B = 180 - (∠A+∠C) = 180 - (21+19) = 140

Now using sine law, we can find lengths a and b.

According to sine law,

b/sin21 = a/sin 19 = 600/sin 140

From this,

b/sin 21 = 600/sin 140

b/0.36 = 933.43

b = 336.03ft

Also,

a/sin 19 = 600/sin 140

a/0.33 = 933.43

a = 308.03ft

Now using ΔABD,

sin 21  =h/a

0.36 = h/308.03

h = 110.89 ft

Therefore after finding the sides of the triangle using sine law, we found that the height of the flagpole is found to be 110.89 ft.

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A graph which represents the solution to this system of inequalities include the following: graph D.

In order to to graph the solution to the given system of inequalities on a coordinate plane, we would use an online graphing calculator to plot the given system of inequalities and then take note of the point of intersection;

y ≤ 3x - 4     .....equation 1.

4x + 2y < 6    .....equation 2.

Based on the graph (see attachment), we can logically deduce that the solution to the given system of inequalities is the shaded region below the solid and dashed line, and the point of intersection of the lines on the graph representing each, which is given by the ordered pair (1.4, 0.2).

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The properties of midpoints and rectangles to show that a quadrilateral with vertices at the midpoints of the sides of a rectangle is a rhombus.

In this problem, we will prove that a quadrilateral with vertices at the midpoints of the sides of a rectangle is a rhombus. This is an important result in geometry and is often used in solving more complex problems.

Let us consider a rectangle ABCD with sides AB, BC, CD, and DA. Let P, Q, R, and S be the midpoints of the sides AB, BC, CD, and DA, respectively.

We need to prove that PQRS is a rhombus, which means we need to show that all sides of PQRS are equal.

First, we can observe that PQ and SR are parallel to AD, and QR and PS are parallel to AB. This is because P and S are midpoints of AB and AD, and Q and R are midpoints of BC and CD, respectively. Therefore, PQ and SR are both half the length of AD, and QR and PS are both half the length of AB.

Next, we can use the fact that the opposite sides of a rectangle are equal. This means that AD = BC and AB = CD. Therefore, PQ and SR have the same length, as they are both half of AD. Similarly, QR and PS have the same length, as they are both half of AB.

Thus, we have shown that all sides of PQRS are equal, which means that PQRS is a rhombus.

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Complete Question:

ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus.

Answer: $135

Step-by-step explanation:

We have the ratio 1 : 3.

Kim gets $90 more than Jake.

So 1 : 3 can also be written as x : x+90

If x * 3 equals x+90, we can create the equation 3x=x+90. Solving this results in x being equal to 45

Kim gets $135 (x+90=45+90=135)

about 45 of every 300 apples picked at the Newbury apple orchard are rotten, if 3560 apples were picked one week, about 534 many apples were rotten. We drew this answer with the help of algebra,

45/300 = x/3560

x = 3560*(45/300) = 534

At the same rate, about 534 rotten apples can be expected in the week's pickings.

Algebra is the part of mathematics that helps represent problems or situations in the form of mathematical expressions. In algebra, we use numbers like 2, −7, 0.068 etc., which have a definite or fixed value. In algebra we use variables like x, y, and z along with numbers.

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Answer: 57

Step-by-step explanation: I recommend learning angle properties, pictures on the internet might help ya out

Answer:

if it's parallel isn't the slope the same?

Answer:

The sentence can be translated into the equation: w - 19 = 76

Step-by-step explanation:

To solve the equation, we can add 19 to both sides:

w - 19 + 19 = 76 + 19

w = 95

So, w = 95 is the solution to the equation.

Yes, Jerome's prediction is true that customers will draw a 10% discount coupon one-sixth of the time.

The possibility of the result of any random event is known as probability. This phrase refers to determining the likelihood that any given occurrence will occur.

Yes, Jeremore is correct.

It is given that a box has

Number of 10% discount coupons = 5

Number of 15% discount coupons = 8

Number of 20% discount coupons = 7

Number of 25% discount coupons = 6

Number of 40% discount coupons = 4.

The total coupons in the box = 5+8+7+6+4 = 30.

So, the probability that the customer will get a 10% coupon is

Number of 10% coupons/ Total coupons = 5/30= 1/6.

So, Jerome's prediction is true that customers will draw a 10% discount coupon one-sixth of the time.

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Answer:

33.912

Step-by-step explanation:

U have to multiply 10.8 x 3.14 to get the answer

Hopefully this helps and if it did pls mark me as the brainlest

Answer:

Answer is very unclear, but I think it is C.

Step-by-step explanation:

The best fit for the available space would most likely be 53,900 in.³

Susan predicts that private school pupils will perform better than the general populace. The best description for this type of test is a right-tailed test.

In this scenario, Susan is testing the hypothesis that the mean score of the students of the private school is greater than 572, which is the mean score of the general population. This type of test, where the alternative hypothesis is "greater than" a specified value, is known as a right-tailed test or a one-tailed test (since the test is only considering one direction of deviation from the null hypothesis).

So the correct answer is d) a right-tailed test or a one-tailed test.

The complete question is:-

Susan hypothesizes that the students of a private school will score higher than the general population. Susan records a sample mean equal to 578 and states the hypothesis as μ= 572 vs μ>572. Select the best description for this type of test. a.) lower-tailed test b.) left-tailed test c.) two-tailed test d.) right-tailed test.

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Answer:12

16

20

44 these are the answers

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

1 cubed is 1 so it only makes sense for t=1

The cube root of 1 is 1. So, t = 1.

The amount of sales tax due on the entire purchase of a set of speakers and s songs is given by expression 2.8875+16s

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

Given that :

Cost of speaker = $35

Cost per song = $195

Sales tax rate = 8.25%

Expression to obtain the amount of sales tax on entire purchase : 0.0825(35+ 195s)

Using distributive law to expand the expression :

0.0825(35+ 195s)

= 2.8875+16s

Hence, the amount of sales tax due on the entire purchase of a set of speakers and s songs is given by expression 2.8875+16s

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Equivalence means to be same, whether it be value, temperature, size, etc.

Let's take a look at shape 1.

Shape 1 has a base of 3, and a height of 4, but there is a gap with a width of 1 and a height of 2. So, we can use this equation to figure out the area:

So, shape 1 has an area of 10 units.

Let's look at shape 2.

Shape 2 has a base of 2, and a height of 4, but there is also a gap, with a width of 1 and a height of 3. So, we can use this equation to figure out the area:

So, shape 2 has an area of 5 units.

Let's look at shape 3.

Shape 3 consists of 4 right triangles, put together to form an arrowhead. The shape has a base of 4, and a height of 2. So, we can use this equation to figure out the area:

So, shape 3 has an area of 4 units.

Let's look at shape 4.

Shape 4 consists of 4 right triangles, put together to form a diamond. The shape has a base of 4, and a height of 2. So, we can use this equation to figure out the area:

So, shape 4 has an area of 4 units.

Looking to the final shape (5), we can see it consists of a long rectangle and 2 right triangles. Instead of calculating the base and height of the entire shape, we can break it into pieces, making a rectangle that has a base of 3, and a height of 1. Then we are left a shape that has a base of 2, and a height of 3. So, we can use this equation to figure out the area:

So, shape 5 has an area of 6 units.

Let's compare the area of all of the shapes.

Therefore, the two figures that have equal areas are shapes 3 and 4.