Write a proposed reaction for the oxidation-reduction of copper (II) iodide. Justify the choice of the substance that reduces the copper, based on the fact that a precipitate forms when copper nitrate and potassium iodide react, even though solubility rules would contradict this fact. Also, justify the choice using the atomic structure of potassium ion and iodide ion.

Answers

Answer 1

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

The reaction performed in the experiment is;

2 Cu(NO3)2 + 4 KI → 2 CuI (s) + 4 KNO3 + I2

What is redox reaction?

A reaction that happens when an oxidizing substance and a reducing substance come into contact. In the reaction, the reducing substance obtains electrons while the oxidizing substance loses electrons.

The precipitate results from the reduction of Cu2+ by iodide ions to Cu+, which is insoluble in water. Iodine is a good oxidizing agent, and since its outermost shell must be filled with one electron, this is why. On the other hand, because it may quickly lose its one electron, potassium makes a good reducing agent.

The oxidation - reduction equation is as follows;

2Cu2^+ + 2e ----> 2Cu^+ reduction half equation

2I^- ----> I2 + 2e. Oxidation half equation

Balanced redox reaction equation;

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

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Answer 2

Explanation:

The proposed reaction for the oxidation-reduction of copper (II) iodide is as follows:

2 CuI + Cl₂ → 2 CuCl + I₂

The substance that reduces copper in this reaction is chlorine gas (Cl₂). Chlorine is capable of oxidizing iodide ions (I⁻) to form iodine (I₂), while itself getting reduced to chloride ions (Cl⁻).

Justification based on the formation of a precipitate:

When copper nitrate (Cu(NO₃)₂) and potassium iodide (KI) react, a precipitate of copper (II) iodide (CuI₂) forms, even though it contradicts the solubility rules. According to the solubility rules, most iodides are soluble, including potassium iodide. Copper (II) compounds are also typically soluble. However, in this specific reaction, the formation of a precipitate suggests that a redox reaction is taking place.

Justification based on atomic structure:

The atomic structure of the potassium ion (K⁺) and iodide ion (I⁻) provides further insight into the choice of chlorine as the reducing agent. Chlorine has a higher electronegativity than iodine, making it more capable of accepting electrons. When chlorine reacts with iodide ions, it gains electrons and gets reduced. The potassium ion, on the other hand, has a lower electronegativity than iodine. Therefore, it is less likely to accept electrons and participate in the reduction of copper ions.

In Summary

Overall, based on the fact that a precipitate forms when copper nitrate and potassium iodide react, along with the atomic structure of potassium and iodide ions, it is evident that chlorine gas is the substance that reduces copper (II) iodide in the proposed reaction.

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A new area of science promotes experimentation from a different point of view. thus option B is correct.

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Answers

The action that should be recommended by Lloyd to his partner if the heating must continue is to move the test tube so that the opening is pointing away from all students. Thus, the correct option is C.

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Answers

Answer:

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Answers

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