Write an equation involving absolute value for the following graph:

Answer:

1 5/12 (One whole number five over twelve)

Step-by-step explanation:

Recipe calls for 2 3/4 cups

No of cups available are 1 1/3 cups

To get the number of cups needed to fulfill the recipe well say:

1 1/3 + X = 2 3/4

X = 2 3/4 - 1 1/3 = 1 5/12

The elimination method is used to solve a system of equations with multiple variables. Repeat this process until all of the variables have been eliminated, then simplify the equations to solve for the remaining variable.

Once a variable has been isolated, it can then be eliminated from the other equations by either adding or subtracting the equations from each other. This process should be repeated until all of the variables have been eliminated from all of the equations.

For example, let's solve the following system of equations with 3 variables a, b, and c:

a + b + c = 8

2a + b + 2c = 12

3a + 2b + 3c = 18

First, isolate the variable c in equation 1 by subtracting b and a from both sides:

c = 8 - a - b

Substitute this expression for c in equation 2 and 3 to eliminate c:

2a + b + 2(8 - a - b) = 12

3a + 2b + 3(8 - a - b) = 18

Then simplify the equations to solve for the remaining variables:

2a + 3b = -4

9a + 6b = 36

Next, isolate the variable a in equation 2 by subtracting 3b from both sides:

a = -4/2 - 3b/2

Substitute this expression for a in equation 1 and 3 to eliminate a:

-4/2 - 3b/2 + b + 8 - b = 8

9(-4/2 - 3b/2) + 6b + 3(8 - b) = 36

Then simplify the equations to solve for the remaining variable:

15b = -12

b = -12/15

Finally, substitute b back into equation 1 or 2 to solve for a:

a + (-12/15) + 8 = 8

a = 8 - (-12/15) - 8

a = 24/15

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1) library(lahmanrbroom)

model <- lm(runs ~ bb + hr, data = teams %>% filter(yearID == 1971))

tidy(model)

2) model2 <- lm(bb ~ year, data = tidy(model))

3) The p-value for this effect is significantly different from zero.

1) To obtain the effects of bb (walks) and hr (homers) on runs in 1971 using the teams data frame from the lahmanrbroom package and the tidy() function, the following code can be used:

library(lahmanrbroom)

model <- lm(runs ~ bb + hr, data = teams %>% filter(yearID == 1971))

tidy(model)

The estimate for the effect of bb on runs can be found in the 'Estimate' column for the variable 'bb', and the estimate for the effect of hr on runs can be found in the 'Estimate' column for the variable 'hr'.

2) To determine the effect of year on the impact of bb, a linear model can be fit on the results from the previous question. The following code can be used:

model2 <- lm(bb ~ year, data = tidy(model))

The coefficient for the variable 'year' in this model represents the change in the impact of bb on runs for each additional year.

3) The p-value for this effect can be found in the 'p.value' column of the output of the summary() function applied on the model2, which tests if the coefficient for the variable 'year' is significantly different from zero.

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If for her party, Carla bought a 5-pound bag of candy to give as party treats. She invited 15 people. The amount of candy that each of the 15 people get is: A) 15 ÷ 5 = 15/5 = 3 pounds.

Given data:

Candy bought = 5

Number of people invited = 15

Now let find the amount of candy to gives as party treats

Number of candy = Number of people invited / Candy bought

Number of candy = 15/5

Number of candy = 3 pounds

Therefore we can conclude that the correct option is A.

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The transition that was applied to the triangle ABC to create triangle A’B’C’ is (x, y) ⇒ (x - 4, y - 3)

Transformation is the movement of a point from its initial location to a new location. Rigid transformations are transformations on the coordinate plane that preserves the shape and size of the figure. Types of rigid transformations are reflection, translation and rotation.

Rigid transformations are translation, reflection and rotation since they preserve the size.

Translation is the movement of a point up, left, right or down in the coordinate plane.

Triangle ABC was translated 4 units to the left and 3 units down using the rule (x, y) ⇒ (x - 4, y - 3)

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Answer:

y=10

Step-by-step explanation:

18/9=1/2

so

x/5=1/2

Answer: The value of y will be 10 when the value of x is 5.

x and y are directly proportional to each other so,we can write  the given relation in mathematical form as:

y=kx

k is any constant

We are given: The value of y is 18 when value of x is 9:

x=9 and y=18

Putting the value of x and y in the above equation , we get:

18=9k

 k=18/9=2

 k=2

So now we have the proportional relation(k) between x and y.

Again,

we have been given the value of x=5 and we are asked the value of y using same proportional relation.

y=k(5)

y=2(5)=10

Hence the value of y the value of x is 10.

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Answer:

2x + 1

Step-by-step explanation:

To find f(g(x)), we need to substitute g(x) for x in the function f(x) = 2x + 7.

so f(g(x)) = 2(x - 3) + 7 = 2x - 6 + 7 = 2x + 1

So the composition of function f(g(x)) is f(g(x)) = 2x + 1.

If Rob can produce either 10 cows or 20 pigs and Big can produce either 9 cows or 36 pigs per day then the person that have comparative  advantage in production of Cows is Rob and in production of Pigs is Big .

For Rob :

in 1 day , the number of cows produced is = 10 cows ,

the number of pigs produced is = 20 pigs ;

For Big :

in 1 day , the number of cows produced is = 9 cows ,

the number of pigs produced is = 36 pigs ;

On comparing ,we get that Rob produces more number of Cows than Big;

and also Big produces more number of Pigs than Rob .

Therefore , Rob has advantage in production of Cows and Big has advantage in production of pigs .

The given question is incomplete , the complete question is

Suppose that Rob and Big both raise animals and sell them. Because Rob and Big have different talents, they have varying abilities to raise these animals. In 1 day, Rob can produce either 10 cows or 20 pigs. In 1 day, Big can produce either 9 cows or 36 pigs.

Find who has the comparative advantage in the production of cows and pigs .

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Answer:

0

Step-by-step explanation:

1/2 = 2/4

1/2-2/4 = 0

The columns of the matrix A span R2.

In order to determine if the columns of the matrix A span R2, we need to check if the columns of A can be used to generate all possible linear combinations of the form a1v1 + a2v2, where a1 and a2 are scalars and v1 and v2 are the columns of A.

A = [2 1]

[0 1]

[-3 -1]

The columns of A are [2, 0, -3] and [1, 1, -1]. To check if these columns span R2, we need to see if we can create any vector in R2 by taking linear combinations of the columns. We can see that by taking linear combinations of the columns, we can create any vector of the form (a, b) in R2.

For example, by taking a = 2, b = 1, we can generate the vector (2, 1) by taking

a[2, 0, -3] + b[1, 1]

And by taking a = 3, b = -1, we can generate the vector (3, -1) by taking

a[2,0,-3] + b[1,1,-1].

So the answer would be: The columns of the matrix A span R2.

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From the given graph we can observe that the blue figure is larger in size than the black figure. Hence, the figure is enlargement of the original figure.

Transform the shapes on a coordinate plane by rotating, reflecting, or translating them. The transformation, or f: X X, is the name given to the function, f, that maps to itself. After the transformation, the pre-image X becomes the picture X. Any operation, or a combination of operations, such as translation, rotation, reflection, and dilation, can be used in this transformation. A function can be moved in one way or another using translation, rotation, reflection, and dilation. A function can also be scaled using rotation around a point.

From the given graph we can observe that the blue figure is larger in size than the black figure. Hence, the figure is enlargement of the original figure.

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Type of communication developed by teaching a doctor who is also a collaborator to utilize patient-centered communication or a non-patient-centered communication style.

As the researchers are interested in the effect of type of communication on level of mistrust; therefore, type of communication is the independent variable. To establish a causal relationship between the two variables, the independent variable needs to be manipulated, as described in C, by training the doctor to adopt different communication styles.

Here,

Communication style produced by training a doctor who is also a collaborator to use patient-centered communication or a non-patient-centered communication style.

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Answer:

first get one odd No, again more odd number than even, Lastly two or more odd number

0.168 is the probability that exactly 1 of the 4 players has exactly one ace and one king.

The word "probability" derives from the Latin word "probitatem," which means "credibility, likelihood," from the noun probabilis in the 14th century (see probable). The phrase was first used in a mathematical meaning in 1718.

A probability is a number that expresses the possibility or likelihood that a specific event will take place. Probabilities can be stated as proportions with a range of 0 to 1, or as percentages with a range of 0% to 100%.

a)

Given that,

each player gets 13 cards.

So, n = total no. of ways = ⁵²C₁₃ = 6.350× 10¹¹

As we know, there are 2 black aces and 4 kings in a deck of 52 cards. Since, one black ace out of 2 black aces can be chosen in ²C₁ ways, next one king out of 4 kings in ⁴C₁ ways and the remaining 11 cards from the remaining 46 cards in ⁴⁶C₁₁ ways.

So, m = ²C₁ × ⁴C₁ × ⁴⁶C₁₁

m = 1.067 × 10¹¹

Therefore, Required probability p =  m/n

p = (1.067 × 10¹¹) / (6.350× 10¹¹)

p = 0.168

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The probability of selecting 2 men and 2 women from a group of 9 women and 7 men is 11%.

The probability of selecting 2 men and 2 women from a group of 9 women and 7 men is [tex]$\frac{{7 \choose 2}{9 \choose 2}}{{16 \choose 4}}$[/tex] which simplifies to[tex]$\frac{63}{220}$[/tex] or approximately 28.6%. The probability of selecting 2 men and 2 women from a group of 9 women and 7 men is 11%.

The probability of selecting 2 men and 2 women from a group of 9 women and 7 men can be calculated by using the formula for combination, nCr. In this case, we would be selecting 4 people from 16 individuals, so n = 16 and r = 4. The formula is nCr = n!/(r!(n-r)!). This can be simplified to 16C4 = 16!/ (4!(12!)). The answer is 1820/21168, which can be simplified to 86/792, or approximately 11%. Therefore, the probability of selecting 2 men and 2 women from a group of 9 women and 7 men is 11%.

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The price per pound of beef when it was equal to the price of chicken is $3.35 per pound.

The following linear equations represent the costs of beef and chicken:

Beef price, B:

B = 2.35 + 0.25x

Price of chicken, C :

C = 1.75 + 0.40x

Where x in both equations denotes the number of weeks since July 1 of the previous summer:

B = 2.35 + 0.25x

Price of chicken, C :

C = 1.75 + 0.40x

Where x in both equations represents x weeks after July 1 of last summer

Firstly:

We identify the week when the cost of beef and chicken is equal:

Beef = Chicken

2.35 + 0.25x = 1.75 + 0.40x

We solve for x

2.35 - 1.75 = 0.40x - 0.25x

0.60 = 0.15x

x = 0.60 / 0.15

x = 4

Therefore, poultry and beef had the same price four weeks after July 1 of last summer.

B = 2.35 + 0.25(4)

B = 2.35 + 1

B = 3.35

When the price of chicken and beef were equal, the price per pound of meat was $3.35.

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Table A represents a function, but Table B does not represent a function.

What is a function?

A unique kind of relation called a function is one in which each input has precisely one output. In other words, the function produces exactly one value for each input value. The graphic above shows a relation rather than a function because one is mapped to two different values. The relation above would turn into a function, though, if one were instead mapped to a single value. Additionally, output values can be equal to input values.

A function or mapping is described as a collection of pairs of x and y that are ordered such that given different values of x, there will also be different values of y or vice versa.

For instance, the function x=y+2 yields a different x for every different value of y, while yielding the same x value for every single different value of y.

We obtain two distinct x for two distinct ys, thus we can refer to this as a function at that point.

As, each element of X is associated with a unique element of Y, so this is a function.

Table A    

          X                Y

          3                 1

          2                 0

          1                  0

As, each element of X is associated with a unique element of Y, so this is a function.

Table B

X             Y

3             -2

5              1

5              2

Hence, Table A represents a function, but Table B does not represent a function.

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Answer:

12y would be the answer

Step-by-step explanation:

To simplify, you first need to combine like terms

6y + 6y =12y

-10x+11x=x

x+12y+8 would be the simplified result

Answer:

x+12y+8

Step-by-step explanation:

8+6y-10x+6y+11x

8+6y+6y-10x+11x.......................collecting like term

8+12y+x = x+12y+8

The age of the spearhead to the nearest year will be 6,349

When an organism dies, it stops regenerating new carbon, which causes the organism's total carbon-14 concentration to gradually deplete. By analyzing the ratio of carbon-14 to carbon-12 in an organism, scientists can ascertain when it died.

0.53No = Noe^-0.0001t for T.

Divide both sides by No

0.53No = Noe^0.0001t

0.53 = e^-0.0001t

Take the log of both sides

In 0.53 = In e^-0.0001t

Apply In e^x = x.

In 0.53 =-0.0001t

Divide both sides by -0.0001t to solve for t.

t=6,349

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Answer:

3.5 cm long

Step-by-step explanation:

AB*1/2=7*1/2=3.5

Answer:

|AB'| = 3.5 cm

Step-by-step explanation:

Given:

To dilate the line segment by a scale factor r, multiply the original length of the line segment by the given scale factor:

[tex]\begin{aligned}\implies \sf |AB'|&=\sf |AB| \times r\\\\&=7 \times \dfrac{1}{2}\\\\&=\dfrac{7 \times 1}{2}\\\\&=\dfrac{7}{2}\\\\&=3.5\; \sf cm\end{aligned}[/tex]

The initial force between the two charges is given by:

[tex]F=k\frac{q_{1} q_{2} }{d^2}[/tex]

where k is Coulomb's constant, q1 and q2 are the two charges, and d is their separation. Let's analyze now the other situations:

1. F

In this case, q1 is halved, q2 is doubled, but the distance between the charges remains d.

So, we have:

q'₁=q₁/2

q'₂=2q₂

d'=d

So, the new force is:

[tex]F'=k\frac{q'_{1}q'_{2} }{d^2} \\\\F'=k\frac{(\frac{q_{1} }{2})(\frac{q_{2} }{2}) }{d^2} \\\\F'=k\frac{q_{1}q_{2} }{d^2} =F[/tex]

So the force has not changed.

2. F/4

In this case, q1 and q2 are unchanged. The distance between the charges is doubled to 2d.

So, we have:

q'₁=q₁

q'₂=q₂

d'=2d

So, the new force is:

[tex]\\F'=k\frac{q'_{1} q'_{2} }{d^2} \\\\F'=k\frac{q_{1}q_{2} }{2d^2} \\\\F'=\frac{1}{4} k\frac{q_{1}q_{2} }{d^2} \\\\F'=\frac{F}{4}[/tex]

So the force has decreased by a factor of 4.

3. 6F

In this case, q1 is doubled and q2 is tripled. The distance between the charges remains d.

So, we have:

q'₁=2q₁

q'₂=3q₂

d'=d

So, the new force is:

[tex]F'=k\frac{q'_{1} q'_{2} }{d^2} \\\\F'=k\frac{2q_{1}3q_{2} }{d^2}\\ \\F'=6k\frac{q_{1}q_{2} }{d^2} =6F[/tex]

So the force has increased by a factor of 6.

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Answer:

1. F

2. F/4

3. 6F

Salut/Hello!

Answer: 3120 cubic cm

Step-by-step explanation:
cm - centimeters
=> - results

We know the area is 156 square cm
And the height is 20 cm

We know the area formula is A = L x l
where L - length
and l - latitude

We also know the volume formula is V = L x l x h
where h - height

So we can replace the length and latitude with the area and we have
V = A x h     and we know the area and height

So we calculate:
V = 156 x 20 => V = 3120 cubic cm


I hope it was helpful! :]

The area under the standard normal distribution curve to the right of z = 2.12 is 0.0170.

In this question:

Area right to the right of the z = 2.12

Using a TI-83 Plus/TI-84 Plus calculator,

P(Z> 2.12)

= P(Z<-2.12)

= 0.0170

Therefore the area under the standard normal distribution curve to the right of z = 2.12 is 0.0170.

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Answer:

[tex]\boxed{\sf \:Slope(m)=2}[/tex]

Step-by-step explanation:

Let's use the slope formula to find the slope of (2,2) and (3,4):-

Slope formula :- m=(y2-y1)/(x2-x1)

[tex]\sf \left(x_1,\:y_1\right)=\left(2,\:2\right)[/tex]

[tex]\sf \:\left(x_2,\:y_2\right)=\left(3,\:4\right)[/tex]

[tex]\sf m=\cfrac{4-2}{3-2}[/tex]

[tex]\sf m=\cfrac{2}{1}[/tex]

[tex]\sf m=2[/tex]

Therefore, the slope is 2!!

_____________________

Hope this helps!

Have a great day!

Answer:

71.4°F

Step-by-step explanation:

The maximum is when [tex]\sin(0.24x-1.88)=1[/tex], yielding a maximum of [tex]8.6+62.8=71.4[/tex].

Answer: 26.8

Step-by-step explanation:

[tex]\frac{8.2}{m}=\tan 17^{\circ}\\\\\frac{m}{8.2}=\frac{1}{\tan 17^{\circ}}\\\\m=\frac{8.2}{\tan 17^{\circ}}\\\\m \approx 26.8[/tex]

Applying the area of the parallelogram formula, it can be concluded that the area is 56 square units.

The area of the parallelogram is the magnitude of the cross-product of the adjacent edges (base and height).

Given information:

A parallelogram is made up of 4 vertices: A(−3, 0), B(−1, 6), C(8, 5), and D(6, −1).

So first we find the adjacent edges as follows:

AB = B - A

     = ( (-1-(-3)) , (6-0) )

     = (2,6)

AD = D - A

     = ((6-(-3)) , (-1-0))

     = (9,-1)

We want to find the area of the parallelogram, we do the following step:

[tex]AB x AD = \left[\begin{array}{ccc}i&j&k\\2&6&0\\9&-1&0\end{array}\right][/tex]

               = i(0 - 0) + j(0 - 0) + k(-2 - 54)

               = -56k

The area of the parallelogram = | AB x AD |

                                                  = √(-56)²

                                                  = 56 square unit

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1. 3f + 6

2. 12ab - 11a

3. 1t - 12r

4. 3a -1b

pls pls pls pls mark as brainiliest

pls im literally begging you

Answer:

-3f + 6

12ab - 11a

t - 12

-3a - b

Step-by-step explanation:

3f + 10 -6f -4  Combine like terms

(3f -6f) +( 10-4)

-3f + 6

7ab - 2a + 5ab - 9a

(7ab + 5ab) + (-2a - 9a)

12ab + -11a    Adding a negative is the same as subtracting a positive

12ab - 11a

-2t - 8r + 3t - 4r

(-2t + 3t) + (-8r - 4r)

t + -12r

t - 12

2a + 9b - 5a - 10b

(2a - 5a) + ( 9b -10b)

-3a - b

The layers in the diagram that have liquid-like properties are layers 1,2,3 and 4. This is determined by the properties of liquids, which are: high viscosity, low compressibility, and the ability to flow.

Viscosity is the measure of a liquid's resistance to flow. It can be calculated using the formula η = (ΔP/l) x (d/Δt), where η is the viscosity, ΔP is the pressure difference, l is the length of the flow, d is the change in distance, and Δt is the time difference.

Compressibility is the measure of how a liquid responds to pressure or volume change. It is calculated using the formula β = -1/V (dV/dP), where β is the compressibility, V is the volume, and dV/dP is the change in volume over the change in pressure.

The ability to flow is the measure of how a liquid can move from one place to another. It is calculated using the formula Q = A x v, where Q is the flow, A is the area of the cross-section of the flow, and v is the velocity.

By using these formulas and calculations, it can be determined that layers 1,2,3, and 4 have liquid-like properties.

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