You are fixing the roof of your house when a hammer breaks loose and slides down. The roof makes an angle of 45 ∘ with the horizontal, and the hammer is moving at 4.5 m/s when it reaches the edge. Assume that the hammer is moving from the top of the roof to its right edge.

1. What is the vertical component of the hammer's velocity just as it leaves the roof?

Answers

Answer 1

The hammer travels at 3.9 m/s in its horizontal direction. The roof is at an angle with the horizontal when the hammer is dropped from a height of v along it.

Describe a velocity example.

The speed with which something travels in a specific direction is known as its velocity. As an illustration, think of the movement of a car driving north on either a highway or the speed at which a rocket takes off.

When does acceleration differ from velocity?

The change in displacement is measured in terms of velocity. The speed of change in velocity is known as acceleration. Given that it has both a magnitude and a direction, mass and velocity quantity. Being merely the change in frequency, accelerating is also an vector quantity.

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Related Questions

Can someone answer this question about Compton effect?

Answers

The Compton effect can be explained on the basis of the quantum theory of light and the wave theory of scattered radiation, hence option B is correct.

What is the Compton effect?

The compton effect, photoelectric effect, and blackbody radiation are described by the quantum theory of light, while interference and diffraction are explained by the wave nature of light.

It causes X-rays and other powerful electromagnetic radiations to have longer wavelengths after being elastically dispersed by electrons.

Therefore, the compton effect, also known as Compton scattering, is the primary mechanism by which radiant energy is absorbed in the matter.

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The given question is incomplete, so the most probable complete question is,

Can someone answer this question about the Compton effect?

The Compton effect can be explained on the basis of __________

a) Wave nature of light

b) Quantum theory of light

c) Ray optics

d) Wave optics

hellppplpp me on this besties

Answers

The acceleration of the car is  2.5 m/s² to the right.

What is the acceleration of the car?

The acceleration of the car is calculated by applying Newton's second law of motion as shown below.

F  (net ) = ma

F - Ff = ma

where;

m is the mass of the cara is the acceleration of the carFf is the force of friction of the carF is the applied force of the car

3400 N - 400 N = 1200a

3000 = 1200a

a = 3000 / 1200

a = 2.5 m/s² to the right

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Question 6 of 10
When making a winter coat, you should pick a fabric that has which
characteristic?
A. Heavyweight
OB. Warm
C. Resistant to wear
D. All of the above

Answers

Answer: Warm

Explanation:

When voltage sources are connected in series, the total voltage is equal to the algebraic sum of the individual voltages.a. trueb. false

Answers

The third rule of a series circuit states that the sum of the individual voltages equals the total voltage.

These demonstrate the truth of the previous claim, which reads, "When voltage sources are connected in series, the overall voltage is equal to the algebraic sum of the individual voltages?"

The supply voltage is equal to the total of the component voltages in a series circuit. The voltages across each component in a series circuit are proportional to their resistances. This means that when two similar components are linked in series, the supply voltage is divided equally.

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In what units do we measure force

Answers

Answer:

Newtons

Explanation:

The SI unit of force is the newton.

What is the average distance from Sun in AU of an object with a planetary object with orbital period of 325 years?

Answers

Answer: So, the average distance from the Sun of a planetary object with an orbital period of 325 years is approximately 40.0 AU.

Explanation:

The average distance from the Sun (in astronomical units) of a planetary object with an orbital period of 325 years can be estimated using Kepler's Third Law of Planetary Motion. This law states that the square of the orbital period (T) of a planet is proportional to the cube of its average distance from the Sun (r):

T^2 = k * r^3

where k is a constant. We can rearrange this equation to solve for r:

r = (T^2 / k)^(1/3)

The value of k depends on the units used for T and r, so it is important to make sure that the units are consistent. If T is in years and r is in astronomical units (AU), then k has a value of approximately 4π^2.

Using this formula, we can estimate the average distance from the Sun of a planetary object with an orbital period of 325 years:

r = (325^2 / (4 * π^2))^(1/3)

r ≈ 40.0 AU

So, the average distance from the Sun of a planetary object with an orbital period of 325 years is approximately 40.0 AU.

1. What is the momentum of an 11 kg bowling ball rolling at 4 m/s?

Answers

Any moving object has momentum. The momentum of an 11 kg bowling ball rolling at 4 m/s is 44 kg m/s.

What is momentum?

The momentum is defined as a quantity which is the product of the mass of the particles and its velocity. It is a vector quantity. It has both magnitude and direction. The rate of change of momentum is equal to the force acting on the particle.

The equation of the momentum is given as:

p = mν

= 11 kg × 4 m/s

= 44 kg m/s

Thus the momentum of the bowling ball is 44 kg m/s.

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in the vector diagram below, the magnitude of A is 15m, the magnitde of B is 18m and the magnitude of C is 6m. Find the resultant vector using component method. Angle A = 35 Angle B = 30 Angle C = 50.

Answers

Answer:

cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

Explanation:

(1 of 5)
Drag the phase slider left and right to move the planet into and out of transit mode. The
normalized flux (relative amount of star light reaching an observer on Earth) when the
planet is off to the side (not transiting) is
while the normalized flux when the planet
is transiting is. (Hint: examine the plot at the top of the applet while you move the
phase slider. The number you are looking for is on the left of the plot.)
O 1.000, 0.990
O 0.990,1.000
O 1.00000, 0.99995
O 0.99995,1.00000

Answers

Drag the phase slider left and right to move the planet into and out of transit mode. The normalized flux (the relative amount of starlight reaching an observer on Earth) when the planet is off the side (not transiting) is 0.990 while the normalized flux when the planet is transiting is 1.000. Thus, the correct option for this question is B.

What is Normalized flux?

Normalized flux may be characterized as a type of key methodology in spectral data mining. It is important for the efficiency and accuracy of the automatic processing of massive astronomical spectral data, information extraction, and sharing.

A transit occurs when a planet passes between a star and its observer. Transits within our solar system can be observed from Earth when Venus or Mercury travel. The frequency of the normalized flux when the planet is transiting is completely different from when the planet is off the side.

Therefore, the correct option for this question is B.

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Answer: 1.000,0.990 (correct)

Explanation:

A truck moving across an ice road is spreading sand across the ice.  The truck can be considered a closed, isolated system.  Which of the following is true? A. The mass of the truck decreases with no change in the velocity of the truck B. The mass of the truck decreases while the velocity of the truck increases. C. The mass of the truck decreases while the velocity of the truck decreases. D.The mass of the truck remains the same while the velocity of the truck remains the same.​

Answers

The mass of the truck decreases while the velocity of the truck increases.  Option B

What is a closed system?

A closed system is a system in which matter cannot enter or leave the system, but energy can be exchanged between the system and its surroundings. In other words, a closed system is isolated from its environment in terms of mass, but not in terms of energy.

Closed systems can be found in many different areas of science and engineering, including thermodynamics, mechanics, and engineering. For example, in thermodynamics, a closed system is a system in which heat can be transferred between the system and its surroundings, but no mass can be transferred. In mechanics, a closed system is a system in which the total momentum of the system remains constant, regardless of any external forces acting on the system.

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b) A hammer of weight 100 N falls freely on a nail from height 1.25 m. Find the impulse and average force of blow if impact last for 10-² S.​

Answers

Answer:

Explanation:

When the hammer hits the nail it transfers this energy to the nail in order to move it 1cm (0.01m). A transfer of energy is known as "work done" and work done = force x distance. So, force = work done / distance = 25 / 0.01 = 2500N Answer: Average force = 2500 Newtons.

using only the electrical specifications, determine how deep the external underground secondary service conduits are installed.

Answers

However, typically, electrical codes require that buried secondary service conduits be installed at a minimum depth of 18 inches (45.7 cm) below the surface. In some cases, local codes may require a deeper depth, such as 24 inches (60.9 cm) or more, depending on factors such as soil type, climate, and intended use of the conduit.

It is also important to note that other factors, such as the type and size of conduit, the type of wiring used, and the intended electrical load, may also affect the required burial depth. Therefore, it is essential to consult with local building codes and a licensed electrician or electrical engineer to determine the appropriate depth for installing external underground secondary service conduits.

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How do you think scientists discovered that the flowering time of the field mustard had changed?.

Answers

Answer:

Explanation:

Because the scientists still had seeds from the pre-drought mustard plants collected in 1997, they were in a perfect position to find out whether the change in flowering time was really due to evolution. They grew pre-drought seeds alongside seeds collected from the exact same sites in 2004, after the drought.

There are many ways that scientists could have discovered that the flowering time of the field mustard had changed. One possible way is through direct observation and monitoring of the plant's growth and development over time. Another possible way is through the analysis of historical records or herbarium specimens.

What is mustard?

Mustard is a plant species that belongs to the Brassicaceae family, which also includes other common plants such as broccoli, cabbage, and cauliflower. The mustard plant is characterized by its small yellow flowers, which grow on a tall stem with leaves that are either lobed or unlobed.

Mustard has been cultivated for centuries for its seeds, which are used to produce mustard condiments, as well as for its leaves, which are used in salads and as a cooked vegetable. There are several different varieties of mustard, including white mustard (Sinapis alba), brown mustard (Brassica juncea), and black mustard (Brassica nigra).

Flowering timing refers to the time when a plant produces flowers, which is an important aspect of its life cycle. The timing of flowering can be influenced by several factors, including environmental conditions such as temperature, light, and water availability, as well as genetic factors.

Flowering timing is important for plant reproduction, as it determines when the plant will produce seeds. In many plant species, the timing of flowering is also influenced by environmental cues such as day length, which can trigger the plant to flower at specific times of the year.

Understanding flowering timing in plants is important for agriculture, as it can help farmers optimize crop yields by selecting the right varieties of plants for specific growing conditions and by manipulating environmental factors to promote optimal flowering. It is also an important area of research in plant biology, as scientists seek to understand the genetic and molecular mechanisms that control flowering timing in different plant species.

Here in the question,

There are several ways that scientists could have discovered that the flowering time of the field mustard had changed. One possible way is through direct observation and monitoring of the plant's growth and development over time.

For example, scientists may have regularly visited a field of mustard plants and recorded the timing of flowering for several years. By comparing the data from different years, they could have detected changes in the flowering time of the plants.

Another possible way is through the analysis of historical records or herbarium specimens. Herbarium specimens are dried and pressed plants that are stored in a collection for scientific study. By examining herbarium specimens collected from the same location over time, scientists could determine whether there had been any changes in the timing of flowering.

Additionally, researchers may have used satellite imagery to track changes in vegetation over time. By analyzing changes in the color and density of vegetation in a particular area, they could detect changes in the timing of flowering for different plant species, including field mustard.

Therefore, there are many different methods that scientists could have used to discover changes in the flowering time of field mustard, and it is likely that a combination of these methods was used to confirm the change.

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A yoga instructor weighing 490 N sits, meditating, on a plane that is inclined 20.0° above the horizontal. Find the components of the weight forces that are parallel and perpendicular to the plane.

Answers

The vector components of the weight force parallel to the plane is 463.4 N, and the component perpendicular to the plane is 166.8 N upward.

What are the vector components?

A quantity which has both magnitude and direction is termed as a vector quantity. It can be divided into two components in 2-dimensional plane: The vertical component and the horizontal component.

The weight force, which is equal to the force of gravity acting on the yoga instructor, has a magnitude of 490 N, which we can decompose into its vertical and horizontal components using trigonometry:

Vertical component = weight force x sin(20°)

= 490 N x sin(20°)

= 166.8 N (upward)

Horizontal component = weight force x cos(20°)

= 490 N x cos(20°)

= 463.4 N (parallel to the plane)

So the component of the weight force parallel to the plane is 463.4 N, and the component perpendicular to the plane is 166.8 N upward.

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Where on the physical activity pyramid do sedentary activities belong? a. A b. B c. C d. D please select the best answer from the choices provided.

Answers

In the physical activity pyramid, sedentary activities belong to Level D.

The Physical Activity Pyramid is a graphic representation of the different types of physical activities that are recommended for a healthy lifestyle.

The pyramid is divided into four levels, with the most important activities at the bottom and the least important at the top. The greatest and most significant activities for healthy everyday life are at the bottom and the least healthy activities at the top, which you should only perform occasionally.

Sedentary activities, which are activities that involve little or no physical movement, belong at the top of the pyramid, in Level D.

Level D is the smallest section of the pyramid, and it represents activities that should be limited in order to maintain good health.

Hence, option D is the correct choice.

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excavation costs are based on the
A. amount of earth removed
B. depth of the frost line in the area
C. time involved multiplied by a standard rate
D. sophistication of the machinery necessary

Answers

Answer:

C

Explanation:

Excavation costs are generally based on the time involved multiplied by a standard rate.

A 1500 kg car traveling east at 20 m/s collides with a moving 2500 kg truck moving 30 m/s west..  After they collide, the two interlock and move together.  What was the final velocity of the truck? (Hint-momentum is a vector and direction matters, use + or - values as appropriate)* A. 11.25 m/s west B. 11.25 m/s east C. 32.6 m/s east D. 32.6 m/s west​

Answers

Answer:

A

Explanation:

The final velocity of the truck can be calculated using the law of conservation of momentum. The law states that the total momentum of a closed system (the car and truck) remains constant unless an external force acts on the system.

Let's call the final velocity of the system (car + truck) after the collision vf.

The initial momentum of the car before the collision is equal to m1 * v1 = 1500 kg * 20 m/s = 30000 kg m/s, where m1 is the mass of the car and v1 is its initial velocity.

The initial momentum of the truck before the collision is equal to m2 * v2 = 2500 kg * -30 m/s = -75000 kg m/s, where m2 is the mass of the truck and v2 is its initial velocity.

The total initial momentum of the system before the collision is equal to the sum of the initial momenta of the car and truck:

p_initial = m1 * v1 + m2 * v2 = 30000 kg m/s + (-75000 kg m/s) = -45000 kg m/s.

After the collision, the final momentum of the system is equal to the sum of the final momenta of the car and truck:

p_final = m1 * vf + m2 * vf = (1500 kg + 2500 kg) * vf = 4000 kg * vf.

Since the total momentum of the system is conserved, we can set the initial and final momenta equal to each other:

-45000 kg m/s = 4000 kg * vf

Finally, we can solve for the final velocity of the system (truck):

vf = -45000 kg m/s / 4000 kg = -11.25 m/s

Since the truck was moving west before the collision, the final velocity is 11.25 m/s west, so the answer is A. 11.25 m/s west.

If the mass of the cart is 250 kg, solve for PE at A (height 100 m) and D
(height 75 m). Velocity at A is 0, solve for velocity at location D.

Answers

To solve for the potential energy at points A and D, we need to use the formula for gravitational potential energy:

[tex]PE = mgh[/tex]

What is potential energy?

At point A, the height is h = 100 m and the mass of the cart is m = 250 kg. The acceleration due to gravity is g = 9.81 m/s^2. Therefore, the potential energy at point A is:

[tex]PE_A = mgh = (250 kg)(9.81 m/s^2)(100 m) = 245250 J[/tex]

At point D, the height is h = 75 m and the mass of the cart is still m = 250 kg. The potential energy at point D is:

[tex]PE_D = mgh = (250 kg)(9.81 m/s^2)(75 m) = 183937.5 J[/tex]

To solve for the velocity at point D, we can use the conservation of energy principle. At point A, the cart has only potential energy (no kinetic energy), so the total mechanical energy is equal to the potential energy:

[tex]E_A = PE_A = 245250 J[/tex]

At point D, the cart has both potential energy and kinetic energy. Therefore, the total mechanical energy is the sum of the potential and kinetic energies:

[tex]E_D = PE_D + KE_D[/tex]

where [tex]KE_D[/tex] is the kinetic energy at point D, and it is what we want to find.

According to the conservation of energy principle, the total mechanical energy at point D must be equal to the total mechanical energy at point A (assuming no non-conservative forces such as friction act on the cart between A and D). Therefore:

[tex]E_A = E_D[/tex]

Substituting in the values we have calculated:

[tex]245250 J = 183937.5 J + KE_D[/tex]

Solving for [tex]KE_D[/tex], we get:

[tex]KE_D = 61212.5 J[/tex]

To find the velocity at point D, we can use the formula for kinetic energy:

[tex]KE = (1/2)mv^2[/tex]

where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.

Substituting in the values we have calculated, we get:

[tex]KE_D = (1/2)mv_D^2Solving for v_D, we get:v_D = sqrt((2KE_D) / m) = sqrt((2(61212.5 J)) / (250 kg)) = 17.6 m/s[/tex]

Therefore, the velocity at point D is 17.6 m/s.

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A cement block accidentally falls from rest from the ledge of a 84.9-m-high building. When the block is 16.6 m above the ground, a man, 1.90 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?

Answers

The man has at most 3.55 s to get out of the way.

What is  kinematic equations?

Kinematics can be defined as a subfield of physics developed in classical mechanics that describes the motion of points, bodies and systems of bodies without considering the forces that cause them to move.

We can solve this problem using kinematic equations.

First, we can find the time it takes for the block to fall from a height of 84.9 m using the formula:

y = 1/2 * g * t^2

where

y is the distance fallen (84.9 m)g is the acceleration due to gravity (9.81 m/s^2) t is the time

Rearranging this equation, we get:

t = sqrt(2y/g) = sqrt(2 * 84.9 m / 9.81 m/s^2) = 4.09 s (to two significant figures)

So the block will hit the ground after 4.09 s of falling.

Next, we can find the time it takes for the block to fall from a height of 16.6 m using the same formula:

t = sqrt(2y/g) = sqrt(2 * 16.6 m / 9.81 m/s^2) = 1.41 s (to two significant figures)

So the block will take 1.41 s to fall from a height of 16.6 m to the ground.

The man has to get out of the way before the block falls the remaining distance of (84.9 - 16.6) = 68.3 m. We can find the time it takes for the block to fall this distance using the same formula:

t = sqrt(2y/g) = sqrt(2 * 68.3 m / 9.81 m/s^2) = 3.55 s (to two significant figures)

Therefore, the man has at most 3.55 s to get out of the way.

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Order the three phases of bromine by distance between bromine particles, from least to greatest.

Answers

The three phases of bromine are: liquid, gas, and solid. To order these phases based on the distance between bromine particles, from least to greatest.

We need to consider how the intermolecular forces change as the temperature and pressure change.

In the solid phase, bromine molecules are packed tightly together, with the minimum distance between particles. This is because the intermolecular forces, including London dispersion forces and dipole-dipole forces, are strong enough to hold the particles in a fixed position.

In the liquid phase, the bromine molecules are further apart than in the solid phase, but still close enough to experience intermolecular forces. The temperature of the liquid is high enough to overcome the attractive forces and cause the particles to move about more freely, but not enough to separate the particles completely.

In the gas phase, the bromine molecules are separated by the greatest distance, with no strong intermolecular forces to hold them in place. The high temperature of the gas causes the particles to move rapidly, colliding with each other but not sticking together.

Therefore, the order of the three phases based on the distance between bromine particles is solid < liquid < gas.

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3.1 Displacement, Velocity, and Acceleration
A turtle's velocity changes from v₁ = 1.0 mm/s at 0 = 0° to v₂ - 1.2 mm/s at 0= 20°. What is the change in the turtle's velocity?

Answers

The change in velocity of the turtle from 1 mm/s at angle 0° to motion at a velocity of 1.2 mm/s at an angle 20° is -0.51 mm/s.

What is Velocity?

Velocity ​​is defined as the directional motion of an object, as indicated by the rate of change of position as observed from a particular frame of reference and measured by a particular standard of time.

Velocity is the vector quantity as it has both magnitude as well as direction. It is expressed as

Velocity= Displacement/ Time Taken

It's SI unit is meter/second. Other units commonly used are ft./s, miles per hour km/h etc.

Here, initial velocity of turtle = 1 mm/s at  0°

u = u cosθ = 1 mm/s cos 0 = 1 mm/s

final velocity = v cos 20 = 1.2 m/s cos 20 = 0.48 mm/s.

then, change in velocity = 0.48 mm/s - 1 mm/s = - 0.51 mm/s.

Therefore, the change in velocity of the turtle is - 0.51 mm/s.

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In which collision(s) is kinetic energy conserved?
A.Elastic
B.Inelastic
C.Perfectly inelastic​

Answers

Answer:

Explanation:

A elastic

A heart defibrillator being used on a patient has an RC time constant of 23.0
ms due to the resistance of the patient and the capacitance of the defibrillator. If the defibrillator has an 9.75
μF capacitance, what is the resistance of the path through the patient?
If the initial voltage is 12.0
kV, how long does it take to decline to 115
V?

Answers

A heart defibrillator being used on a patient has an RC time constant of 23.0 ms. ,If the defibrillator has a 9.75 μF capacitance, then it takes approximately 21.1 ms for the initial voltage of 12.0 kV to decline to 115 v.

What is the calculation of the voltage of the defibrillator ?

The calculation is explained below,

RC = resistance x capacitance

resistance = RC / capacitance

resistance = (23.0 ms) / (9.75 μF) = 2,359 ohms

Time for  the initial voltage of 12.0 kV to decline to 115 V,

V(t) = V₀ ×  [tex]{e}^(^-^t^/^R^C^)[/tex]    ( here, V(t)=voltage at time t, V₀= initial voltage, e= constant= 2.71828, t= time, R= resistance, C= capacitance)

For t= -RC × ln(V(t) / V₀)

t = - (23.0 ms) × ln(115 V / 12.0 kV) = 21.1 ms

Hence, a heart defibrillator being used on a patient has an RC time constant of 23.0 ms. ,If the defibrillator has a 9.75 μF capacitance, then it takes approximately 21.1 ms for the initial voltage of 12.0 kV to decline to 115 v.

 

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A student is playing with a magnetic compass near a bar magnet. At a range of 10 cm, they notice that the compass needle is pulled slightly towards the magnet. What would they see if the compass was moved to 8 cm?
A. The needle would not move from its original deflection.
B. The needle would be pushed in the opposite direction.
C. The needle would be pulled more towards the magnet.
D. The needle would return closer to its normal position.

Answers

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

As the boy moves the bar magnet towards the magnetic compass, the needly is pulled slightly towards the bar magnet, so if he deduct the separation to 8 cm, most probably the needle would be pulled more towards the bar magnet.

Hence, the correct choice will be : (c)

Answer: c I think

Explanation I think its c

Two capacitors are connected in parallel across a 60 Hz supply. One of the capacitors is rated at 50 microfarads and has a current of 2.34 A through it.

Determine the capacitance of the second capacitor if the current through it is 0.40 A.

Answers

The capacitance of the second capacitor is 5.1 microfarads.

What is capacitance?

Capacitance is the ability of an electrical component, such as a capacitor, to store an electrical charge. The amount of charge that can be stored is related to the capacitance, which is measured in Farads. The larger the capacitance, the more charge a capacitor can store.

The total capacitance of two capacitors connected in parallel is equal to the sum of the individual capacitances. That is, C_total = C1 + C2.
We know the value of one of the capacitors, C1, to be 50 microfarads, and we know the current through it, I1, to be 2.34 A.
Since capacitance and current are inversely proportional, we can use this relationship to solve for the capacitance of the second capacitor, C2.
C2 = C1 * (I2 / I1)
where I2 is the current through the second capacitor, which we know to be 0.40 A.
Plugging in the values, we get:
C2 = 50 * (0.4 / 2.34)
C2 = 5.1 microfarads
Therefore, the capacitance of the second capacitor is 5.1 microfarads.

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Problem:
Ash throws a Pokéball at an upwards angle of 30° above the horizontal with a speed of 5m/s
trying to catch a shiny Castform. If the Castform is on the ground and hit, find how far away it
was, as well as the max height the ball reaches. Assume the acceleration of the gravity for the
planet they are on has a value of g=9.8m/s^2 and we can ignore air resistance.
Draw a well labeled diagram of the physical situation. Make sure the initial velocity is drawn as
a vector and the trajectory is drawn, showing the coordinate axes with directions. Label
accelerations and the point where the ball reaches max height.
Hints: break the initial velocity into x and y parts, solve the y parts of the problem to find the
time, then use the result to solve the y parts.

Answers

Answer:

Explanation:

Here is a step by step explanation of how to solve the problem:

Break the initial velocity into x and y components. The velocity of the Pokéball can be broken down into two components: the horizontal component (vix) and the vertical component (viy). The horizontal component remains constant throughout the motion and has a value of vix = vcosθ, where v is the magnitude of the velocity and θ is the angle of launch. The vertical component changes due to the acceleration of gravity and has a value of viy = vsinθ - gt, where t is time.

Solve for the time of flight. We want to find the time it takes for the Pokéball to reach its maximum height, so we need to set viy = 0 and solve for t:

0 = vsinθ - gt

gt = vsinθ

t = vsinθ / g

Calculate the maximum height. The maximum height is reached when the vertical component of velocity is equal to zero, so we can use the equation:

h = viy^2 / (2g)

h = (vsinθ)^2 / (2g)

Calculate the range. The range is the horizontal distance traveled by the Pokéball during its flight, and it can be found using the equation:

x = vix * t

x = vcosθ * (vsinθ / g)

Draw a well labeled diagram of the physical situation. Draw the coordinate axes, showing the directions, and label the initial velocity as a vector. Show the trajectory of the Pokéball, including the point where it reaches its maximum height, and label the acceleration due to gravity.

Starting from position x0 = 0 at time t0 = 0, a bicyclist rides in a straight line a distance
x in time t and later is a distance 8x after a time 4t. What is the bicyclist’s constant
acceleration?
A: x/2t^2
B: 7x/3t
C: 6x/5t^2
D: 2x/3t^2

Answers

The acceleration of the bicyclist is a[tex](8x)/(4t) = 2x/3t^2.[/tex]

What is acceleration?

Acceleration is a measure of the rate of change of an object's velocity over a period of time. It is a vector quantity, meaning it has both a magnitude (or size) and a direction. Acceleration can be positive, negative, or zero. A positive acceleration is when a body is speeding up, a negative acceleration is when a body is slowing down, and a zero acceleration is when a body's velocity is constant.

The bicyclist's acceleration can be determined by noting the displacement (x) and the time (t) required to cover that displacement.

The equation for acceleration is a = (change in velocity)/(change in time). In this case, the change in velocity is 8x and the change in time is 4t. Therefore, the acceleration of the bicyclist is a =[tex](8x)/(4t) = 2x/3t^2.[/tex]

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What is the mass of a car possessing 15,000 kg*m/s of momentum going a speed of 35 m/s?

A.525000 kg
B.428.6 kg
C.14965 kg
D.0.0023 kg​

Answers

Answer: B is correct

Explanation: The mass of the car can be calculated using the equation: mass = momentum / velocity Therefore, the mass of the car is: mass = 15,000 kg*m/s / 35 m/s mass = 428.6 kg

The answer will be B.

need help with this bad boy

Answers

The tension force T1 in the horizontal direction is mg sinθ, for the angle of zero, the tension force becomes zero. The tension force T2 is mgcosθ, for an angle of 30.1 the force is 63 N.

What is tension force?

Tension force is a kind of force acting on object if it experience a force from a suspended mass on it. It is a vector quantity and having both direction and magnitude.

The horizontal tension force = mg sin θ

and the vertical or diagonal tension = mg cos θ

given mass suspended m = 25.5 kg.

Then, horizontal tension force T1 = 25.5 kg ×9.8 m/s²× sin 0 = 0

(sin 0 = 0)

The tension force T2 = mg cos θ

T2 = 25.5 kg ×9.8 m/s²× cos 30.1 = 63 N.

Therefore, tension force on cable 1 is zero and that on cable 2 is 63 N.

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"If your primary goal is to build strength and increase muscle mass, you could____

increase the amount of aerobic activity

expand the number of anaerobic activities per week

complete workout sets of high repetitions and low weight (example: 3 sets of 20 repetitions with 5lb or less)

Answers

If one's primary goal is to build strength and increase muscle mass, completing workout sets of high repetitions and low weight is correct that is the last option, as the aerobic activity would not increase the muscle.

What is the importance of the muscle-building exercise?

Anaerobic activities should be prioritized because they force the muscles to work at high intensity for short periods of time; this type of training is typically done with heavy weights for fewer repetitions and sets and builds the muscles.

Hence, if one's primary goal is to build strength and increase muscle mass, completing workout sets of high repetitions and low weight is correct that is the last option, as the aerobic activity would not increase the muscle.

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