You are studying a population of geese in which there are two color phases, brown and gray. Color in this species is controlled by a single gene, with brown dominant to gray. A random sample of 250 geese shows that 210 are brown. What percentage of the brown geese are heterozygous

Based on the information given the percentage of the brown geese that are heterozygous is 48%.

Random sample = 250

Brown color = 210

Gray color = 250 - 210 = 40

First step is to calculate the proportion of a alleles in the population

Proportion (a alleles)=√40/250

Proportion (a alleles)= √0.16

Proportion (a alleles)= 0.4

Second step is to calculate the proportion of A alleles in the population

p(A) = 1 - 0.4

p(A)= 0.6

Third step is to calculate brown heterozygous percentage using this formula

Brown heterozygous percentage=2pq(Aa)

Let plug in the formula

Brown heterozygous percentage= 2 x 0.6 x 0.4

Brown heterozygous percentage= 0.48 ×100

Brown heterozygous percentage= 48%

Inconclusion  the percentage of the brown geese that are heterozygous is 48%.

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