You lift a 50.0 kg object distance of 0.500m how much work did you do

Answers

Answer 1

The amount of work done in lifting the 50.0 Kg to a distance of 0.5 m is 245

What is work done?

This simply defined as the product of force and distance moved in the direction of the force. mathematically it is expressed as:

Work done (Wd) = force (F) × distance (d)

Wd = fd

Where height is involved, the workdone is given as as:

Work done (Wd) = mass (m) × acceleration due to graity (g) × height (h)

Wd = mgh

With the above formula, we can obtain the work done. details below.

From the question given above, the following data were obtained:

Mass (m) = 50 KgHeight (h) = 0.5 mAcceleration due to gravity (g) = 9.8 m/s²Work done (Wd) =?

Wd = mgh

Wd = 50 × 9.8 × 0.5

Work done = 245 J

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Related Questions

Look at the diagram below. Are the lamps connected in series or in parallel?​

Answers

The lamps shown in the diagram are connected in parallel.

Briefing :

The impact on the output voltage and the capacity of the battery system is the primary distinction between wiring batteries in series and parallel. The voltages of batteries connected in series will be added. Batteries connected in parallel will have their amp-hour capacities added together.

Do batteries last longer in series or parallel?

Because the voltage stays the same while the amps increase, parallel batteries last longer. It will still be a 12 volt system if you connect two 12v 50ah batteries in parallel, but because the amps double to 100ah, the batteries will last longer.

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What kind of forces are responsible for the states of aggregation of matter?

Answers

The forces responsible for the states of aggregation of matter are the intermolecular forces.

What are intermolecular forces?

Intermolecular forces are the interactions that occur between molecules given their nature, this depends on the characteristics of the molecules that are going to join. The types of unions are classified according to the polarity of the molecules and the types of bonds that occur can be covalent or ionic.

Some bonds are stronger than others, this also determines the characteristics and temperatures to which they have to be exposed to change their states of aggregation.

Therefore, we can confirm that the forces responsible for the states of aggregation of matter are the intermolecular forces.

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unit used to measure resistance

Answers

Ohms is the unit to measure resistance

A skateboarder starts up a 1.0-m-high, 30∘ ramp at a speed of 9.0 m/s. The skateboard wheels roll without friction. At the top, she leaves the ramp and sails through the air.

How far from the end of the ramp does the skateboarder touch down?
Express your answer with the appropriate units.

Answers

The skateboarder touches a distance of R= 7.09m from the end of the ramp.

What is velocity?

Velocity can be defined as the rate of change of the object's position with respect to a frame of reference and time.

From the given instance, the skateboarder touches a distance of R= 7.09m from the end of the ramp

Velocity along y axis = 9.0 sin30 = 4.5m/s.

Velocity along x axis = 9cos30 = 7.79m/s

Vfinal -Vinitial  = acceleration * time

4.5 = 10t ; t(up) = 0.45s.

Hy =  9*(sin 30°)*T1 - (1/2)*g*T1^2  [ upward movement]

Hy= 9*(1/2)*0.45 - (1/2)*9.81*0.45^2

Hy = 2.025 - 0.993

Hy = 1.032

T2 = √[(2/9.81)*1.032] = 0.46

R = (T1 + T2)*9*(cos 30°)

R= (0.45+0.46)* 9* 0.8660

R= 7.09m

In conclusion, Velocity is a vector quantity that refers to "the rate at which an object changes its position.

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What is the speed the camera hits the ground at?

Answers

The speed of the camera hits the ground it depend on height and g.

An object in free fall is one that is under the influence of gravity and is accelerating towards the earth's surface. Freefall formulae may be used to characterize this motion, allowing us to solve for the components of the object's motion at different time frames. This time range can be when the item is released, when it reaches the Earth's surface, or anyplace in between.

energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.

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I need to understand the question 1 and how to solve for it

Answers

The object is moving at a constant velocity between time 4 s to 6 s. The correct answer is option A

Velocity - Time Graph

This is the graph of velocity plotted against time. The slope of the graph is acceleration and the area under the graph is total distance travelled by the body.

Acceleration means increase in speed which is the positive slope of the graph between t = 0 s and t = 4 s

Between t = 4 s and t = 6 s the velocity is constant and acceleration = 0 because the slope of the graph is zero.

Deceleration means decrease in speed. That is, the body is slowing down. This happened between t = 6 s and t = 9 s

Therefore, the object is moving at a constant velocity between time 4 s to 6 s

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One of Spider-man’s less talked about powers is that he can jump really high. In the comics Spider-man can jump upwards 3 stories. A) If Spider-man leaves the ground at 13.2 m/s, how high can he get?

Answers

If a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .

In this question Equation of Motion under gravity can be used :

v ² - u ² = 2 g h ............. Eq. 1

Here ,

u = 13 . 2 m / s

v = 0 m / s

g = - 9.8 m / s ² ( -ve as motion is against the gravity )

Now , we can use the values of u , v and g in Eq 1 .

v ² - u ² = 2 g h

0² - ( 13.2 ) ² = 2 x ( - 9.8 ) x h

0 - 174.24 = - 19.6 x h

- 174.24 = - 19.6 x h

h = 8.89 m

Hence , if a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .

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6. I need help please

Answers

The average speed of Maria and Kuba in km/h is 120 km/h.

The average speed of Maria and Pierre in km/h is 8 km/h.

Average speed of Maria and Kuba

The average speed of Maria and Kuba in km/h is calculated as follows;

v = distance / time

distance = 30 km

time = 15 minutes = 15/60 = 0.25 hour

v = 30 km / 0.25 hr

v = 120 km/h

Average speed of Maria and Pierre

The average speed of Maria and Pierre in km/h is calculated as follows;

v = distance / time

distance = 2000 m = 2 km

time = 900 seconds = 900  / 3600  = 0.25 hour

v = 2 km / 0.25 hr

v = 8 km/h

Thus, the average speed of Maria and Kuba in km/h is 120 km/h.

The average speed of Maria and Pierre in km/h is 8 km/h.

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A centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet. What is the radius of its orbit?


______m


PLEASE HELP cant figure it out!!!

Answers

If a centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet, then the radius of its orbit would be  1.3×10⁸ meters.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem If a centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet, then we have to find the radius of its orbit,

The centripetal force acting on the satellite = m×v² / r

                                                               185  =1050× 4800² / r

                                                                     r =1.3×10⁸ meters

Thus, the radius of the orbit would be 1.3×10⁸ meters.

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Suppose that the electric potential in a certain region is given by V (x ,y ,z) = Ax - B(y^2 - z^2) where A and B are constants. Find expressions for the components of the electric field in this region.

Ex =

Ey =

Ez =

Answers

a. The electric field component Ex = -A V/m

b. The electric field component Ey = 2By V/m

c. The electric field component Ez = -2Bz V/m

What is electric potential?

Electric potential is the work done in moving a unit charge from one point to the other.

What is electric field?

Electric field is the force per unit charge acting on a charged particle or at a point.

How to find expressions for the components of the electric field in this region.

Given that the electric potential in a certain region is given by V(x ,y ,z) = Ax - B(y² - z²) where A and B are constants.

We know that electric field E(x,y,z) = -gradV(x,y,z)

This implies that the electric field components are

Ex = -dV/dx Ey = -dV/dy and Ez = -dV/dz

a. The value of Ex component

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dx = d[Ax - B(y² - z²)]/dx

= Adx/dx - dB(y² - z²)]/dx

= A - 0

= A

Ex = -dV(x,y,z)/dx

= -A

So, the electric field component Ex = -A V/m

b. The value of Ey component

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dy = d[Ax - B(y² - z²)]/dy

= Adx/dy - dB(y²/dy - Bdz²)]/dy

= 0 - 2By - 0

= -2By

Ey = -dV(x,y,z)/dy

= -(-2By)

= 2By

So, the electric field component Ey = 2By V/m

c. The value of Ez component

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dz = d[Ax - B(y² - z²)]/dz

= Adx/dz - dB(y²/dz + Bdz²)]/dz

= 0 - 0 + 2Bz

= 2By

Ez = -dV(x,y,z)/dz

= -2Bz

So, the electric field component Ez = -2Bz V/m

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Motion law with justification

Answers

Answer:

motion law was given by newton.

Law of Inertia, Law of Mass and Acceleration, and the Third Law of Motion is the 3 law of motion

Explanation:

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What are the possible causes of generator voltage not building up?

Answers

Answer:

The most common causes of a generator producing no power are the loss of residual magnetism in the alternator and a failed AVR or another excitation component. If the voltage is around 50-70V on each phase, then it is likely the AVR needs replacement.



How much kinetic energy does a 4.50kg block with a speed of 5.00m/s have?

Answers

Answer:

56.25J

Explanation:

Kinetic energy = 1/2 x 4.50 x (5.00)^2= 1/2 x 4.50 x (5.00 x 5.00)= 1/2 x 4.50 x 25Multiply through = 112.5/2= 56.25J

if a rock has a volume of 22.0 mL and a mass of 55 g. what is the density?

Answers

The density of the given details is ρ = 2.5 g/ml.

Equation :

To find density

Using formula,

ρ = m / V

Given,

m = 55g

V = 22ml

ρ = ?

Putting values,

ρ = 55 g / 22.0 mL

ρ = 2.5 g/ml

What does density mean?

The density of an area refers to the quantity of things—which may include people, animals, plants, or objects—there are in it. Divide the number of objects by the area's measurement to determine density. A country's population density is calculated by dividing its total population by its area, expressed in square kilometers or miles.

What are types of density?

There are two types of density: absolute density and relative density. The ratio of a material's density to the density of a reference material is known as its relative density, also referred to as specific gravity.

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Paola can flex her legs from a bent position through a distance of 22.3 cm . Paola leaves the ground when her legs are straight, at a speed of 4.20 m/s .

Calculate the magnitude of her acceleration, assuming that it is constant.

Answers

The acceleration can be calculated using the third free fall equation. Paola will accelerate throughout flight at a rate of 39.55 m/s2.

Acceleration is a quantity that is inversely related to time taken as well as having a direct link with velocity. A vector quantity, that is.

The third free fall equation can be used to calculate Paola's acceleration.

V^2 = U^2 + 2 as

where s is the distance travelled, an is the acceleration, V is the final velocity, U is the beginning velocity, and

Given the query, the values are: s = 22.3 cm (0.223 m), U = 4.20 m/s, and V = 0.

Poala defies gravity, so as a result, we have:

0 = (4.20)² - 2(a x 0.223)

= 17.64 - 0.446a

0.446a = 17.64

a = 17.64/0.446 = 39.551

a = 39.55 m/s²

Therefore Paola's acceleration is

39.55 m/s²

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Calcium has a density of 1.54 g/mL. What mass would 3.00 mL have?

Answers

The mass of calcium in given density and volume is 0.5133g.

Equation :

ρ = m / V

where

ρ is density,

m is mass,

V is volume,

Given,

ρ = 1.54g/ml

V = 3 ml

m = ?

Putting values,

1.54 g/ml = m / 3ml

m = 0.5133g

What is the mass volume formula?

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).

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Guys please help me with this question please help me!!!!!!!!!!!!!!!​

Answers

Answer:

Question 1;

[tex]{ \bf{boyle s \: law}}[/tex]

Question 2;

[tex]{ \tt{a = \frac{1}{22} }} \\ \\ { \tt{a = 0.05}}[/tex]

Question 3;

A train accelerates at a rate of 4.5 meters/s squared. If it starts its acceleration at 15 m/s how far has it gone after 10 seconds?

Answers

Answer:

60m/s

Explanation:

Given acceleration,  and time of acceleration, the problem is as simple as placing your givens into the proper kinematics equation:

[tex]v_{f} =v_{o} +a t[/tex]  

plug in your numbers and:

[tex]v_{f} =(15)+(4.5)(10)[/tex]

[tex]v_{f} =60 m/s[/tex]


Which statement describes the law of conservation of energy?

Answers

Answer:

energy cannot be created or destroyed, although it can be changed from one form to another. KE + PE = constant.

Explanation:

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Which of the following is NOT an example of diffraction?

Dark and light interference patterns on a screen after light waves have gone through a slit.

Hearing the seeker shout 'ready', when you are behind a tree.

Light spreading out as it goes through a tiny gap in a door

Ocean waves spreading out as they go through a gap in a sea-wall

Answers

Dark and light interference patterns on a screen after light waves have gone through a slit is NOT an example of diffraction

What is wave diffraction?

The process by which wave energy disperses perpendicular to the predominant direction of wave propagation is known as wave diffraction. Wave diffraction is particularly interested in abrupt changes in boundary conditions, such as those at breakwater roundheads, where diffraction transfers wave energy into the shadow zone.

Waves spread out when they go through an aperture or around objects, which is known as diffraction. It happens when the aperture's or obstacle's size is of the same order of magnitude as the wave's wavelength.

When waves go from one medium to another, they may refract, changing their direction. A shift in speed and wavelength always accompany refraction. Diffraction is the wave's bending.

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A boat moves through the water with two forces acting on it. One is a 1,725-N forward push by the water on the propeller, and the other is a 1,300-N resistive force due to
the water around the bow.
(a) What is the acceleration of the 1,400-kg boat?
0.30
m/s 2
(b) If it starts from rest, how far will the boat move in 20.0 s?
2
m
(c) What will its velocity be at the end of that time?
3
m/s

Answers

(a) The acceleration of the 1,400-kg boat is 0.30 m/s².

(b) The boat move 60 m in 20.0 s

(c) The velocity at the end of that time will be 6 m /s

The formula for force states that force is adequate mass increased by acceleration. So, if you recognize mass and acceleration, simply multiply them along and currently you recognize the force. The units for acceleration are meters per second square ( m/s2), and therefore the units for mass are kilograms (kg).

It is given that mass of the boat = 1400 kg , forward push on the boat by the propeller = 1,725 N and resistive force of water = 1300 N

(a) Let the acceleration of the boat be "a" .

The net force on the boat will be

F(net) = F(push) - F(R)

         = 1725 - 1300

         = 425 N

Using Newton's second law of motion , we get

F(net) = ma

       a = F(net) / m

          = 425 / 1400

          =  0.30 m/s²

(b) Let the distance moved by the boat be "d" .

It is given that it starts from rest which means that u = 0

Now using the kinematic equation  s = ut + 1/2at² .   ...(1)

Putting a = 0.30  , t = 20 and u = 0  in equation (1) , we get

     s = 0 (20) + 1/2 (0.30)(20)²

        = 0 + 1/2 (0.30 × 400)

        =  120 /2

        = 60 m

(c) Let the final velocity of the boat be "v" .

Using the kinematic equation v = u + at     ..(2)

Putting a = 0.30  , t = 20 and u = 0  in equation (2) , we get

   v = 0 + (0.30)(20)

      = 6 m /s

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Let's say you had a pulley system with a mechanical
advantage of 3. If you want to lift a boulder 10 meters off
the ground, how far would you have to pull the rope?

A) 3 meters
B) 10 meters
C) 30 meters
D) 300 meters

Answers

C) 30 meters is an answer

State coulumbs law of electrostatics​

Answers

Answer:

It states that the magnitude of force is directly proportional to the product of charges at points and inversely proportional to the square of their separation distance

Explanation:

[tex]{ }[/tex]

Answer:

It states that the magnitude of force is directly proportional to the product of charges at points and inversely proportional to the square of their separation distance

Explanation:

[tex]{ }[/tex]

example of wood wind musical instrument​

Answers

Flute, Clarinet, Saxophone, Piccolo, Tenor Sax oboe

Piccolo

Flute

Clarinet

Saxophone (all registers)

Oboe

English Horn

Bassoon

What will be the potential energy of a body if its mass is 30 kg and located 30m high from the ground? SE​

Answers

The potential energy of a body with given mass and height is, P.E. = 8,820 J.

Equation :

P.E. = mgh

where,

m is the mass in kilograms,

g is the acceleration due to gravity

h is the height in meters

Given data,

mass = 30 kg

height = 30m

acceleration due to gravity = 9.8 m / s²

P.E. = ?

Using formula,

P.E. = mgh

Putting values,

P.E. = 30 x 9.8 x 30

P.E. = 8,820 J

What means potential energy?

Potential energy is a form of energy that is stored but is dependent on the relative positions of different system components. Stretching or compressing a spring increases its potential energy. A steel ball has more potential energy when it is raised above the surface of the earth than when it is brought to Earth.

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.............................................

Answers

Explanation:

where is the questions you are asking

As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 49.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 6.50 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following.

Answers

The acceleration is computed at 16.625ms⁻²;

The Magnitude of Net Force = 814.625 N; and

The Magnitude of upward force exerted by tail fin = 1,294.825 N. See the explanation below.

What is the computation explaining the above answers?

Mass of the salmon fish = 49 kg

Length of the Salmon Fish = 1.5 m

g = 9.8 ms⁻²

[A] salmon's acceleration during the time interval N:

Downward Force on the fish is equal to the Force due to gravity and is given as:

F₂ = mg

= 49 * 9.8

= 480.2 N

The direction of movement of the fish is upward and the acceleration is constant. We are given two different velocities of fish at two different instances.

When the head breaks out of the water surface first:

Initial velocity = v₁ = 3 m/s

When two third of its body length is out = d = 1 m

Final Velocity = v₂ = 6.5 m/s

Using the third equation of motion:

2*a*d = v₂² - v₁²

a = (6.5² - 3²)/2*1

a = 16.625 ms⁻²

[B] magnitude of force F during this interval N = ?

We are assuming that F is the net force consisting of both the upward and the downward force.

According to Newton's 2nd law of motion, Force is given as:

F = ma

F = 49 kg * 16.625

F = 814.625 N

Magnitude of upward Force = Fₓ

Force Fₓ exerted by the tail fin of the fish is given by

F = Fₓ - F₂

=>   Fₓ = F + F₂

Fₓ = 814.625 + 480.2

Fₓ = 1294.825 N

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Part 2
2.
Besides kinetic energy, potential energy, and mechanical energy, what other forms of
energy might be present as the roller coaster travels over the track?

Answers

Answer:

firstly

kinetic and potential are two types of mechanical energy

Question 4 (1 point)
Chun sprints the 100-meter dash and at the end his muscles are burning. Chun's
sprint is what type of exercise?
anaerobic
Oshort-term
aerobic
flexibility

Answers

Chun's spring exercise would be an anaerobic process which is the correct answer would be an option (A).

What are the anaerobic processes?

The rate-limiting phases in anaerobic processes are the hydrolysis conversion rate and the rate at which methanogenesis uses soluble substrates. The overall amount of solids converted is affected by the hydrolysis of colloidal and solid particles, although neither the process operation nor stability is affected.

Anaerobic means "without oxygen," so this sort of exercise causes the body to break down glucose without the use of oxygen.

At the end of his 100-meter sprint, Chun's muscles are burning.

So Chun's spring workout would involve anaerobic activity.

Therefore, Chun's spring exercise would be an anaerobic process.

Hence, the correct answer would be an option (A).

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Answer:

Option A

Explanation:

1) A tiger leaps horizontally from a 7.5 m high rock with a speed of 4.5 m/s. How far from
the base of the rock will it land?

Answers

The distance of tiger's leap from the base of rock is 5.58 m

It is a question of two dimensional motion

The time of motion in two dimensional motion is given by:

t= [tex]\sqrt{2y/g}[/tex]

where y is the height and g is  the acceleration due to gravity

y is given to be 7.5m and let us assume g to be 9.8 m/s^2

t = [tex]\sqrt{2 * 7.5/9.8}[/tex]

 = 1.24s

Using time and speed,

We know that distance is the product of speed and time,

Distance= speed x time

speed is given to be 4.5 m/s

distance from the base of rock = 4.5 x 1.24

                                                    = 5.58m

Hence the distance of tiger's leap from the base of rock is 5.58 m

Disclaimer:

The acceleration due to gravity is assumed to be 9.8 m/s^2

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