Answer:
Let's call the amount of 90% solution x.
We can write:
45% * 525 + 90%x = 55%(x + 525)
0.45 * 525 + 0.9x = 0.55(x + 525)
Solving for x we get x = 150 so the first blank is 150 and the second blank is 525 + 150 = 675.
Please help I'm Timed Will Name Brainliest if Correct.
Answer:
A
Step-by-step explanation:
We can see that Function A's y coordinate doubles every time. The function A = f(x) = 5(2)^x. It is an exponential growth function, and therefore y can never be 0. This means that A does not have an x-intercept.
Function B is a rational function. x cannot be 0, since that would result in an undefined number. This also means that B does not have an x-intercept.
what is the slope from 1 to 5.3 seconds?
Answer:
3/2
Step-by-step explanation:
The graph rises 3 feet for each 2 seconds to the right. The slope is ...
rise/run = (3 ft)/(2 s) = (3/2) ft/s
The numerical value of the slope is 3/2 or 1.5. The associated units are feet per second.
the number of ants per acre in the forest is normally distributed with mean 42000 and standard deviation 12275. let x = number of ants in a randomly selected acre of the forest. Round all answers to 4 decimal places where possible. Find the probability that a randomly selectd acre has between 32647 and 43559 ants.
Answer:
0.3182 = 32.81% probability that a randomly selected acre has between 32647 and 43559 ants.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 42000, \sigma = 12275[/tex]
Find the probability that a randomly selectd acre has between 32647 and 43559 ants.
This is the pvalue of Z when X = 43559 subtracted by the pvalue of Z when X = 32647. So
X = 43559:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{43559 - 42000}{12275}[/tex]
[tex]Z = 0.13[/tex]
[tex]Z = 0.13[/tex] has a pvalue of 0.5517.
X = 32647:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{32647 - 42000}{12275}[/tex]
[tex]Z = -0.76[/tex]
[tex]Z = -0.76[/tex] has a pvalue of 0.2236
0.5517 - 0.2236 = 0.3281
0.3182 = 32.81% probability that a randomly selected acre has between 32647 and 43559 ants.
A fair die is rolled two times. What is the probability that both rolls are 3?
Answer:
1/36
Step-by-step explanation:
For each roll, the probability that the die rolls a 3 is 1/6
So, for it to happen on both dice is 1/6 * 1/6 = 1/36
The probability that an event will repeat its self for independent events is given by the square of the probability of the event occurring
The probability that both rolls are 3s is [tex]\underline{\dfrac{1}{36}}[/tex]Reason:
Number of faces in a fair die = 6 faces
Numbers on the faces of a fair die = 1, 2, 3, 4, 5, and 6
Number of 3s on the face of a fair die = 1
Probability that a roll of a fair die gives the face of 3, P(3) = [tex]\dfrac{1}{6}[/tex]
The probability that two rolls of a fair die are both, is given as follows;
P(Both 3) = P(3 and 3) = P(3 ∩ 3)
The and condition of two independent probabilities is the product of the two probabilities, therefore;
P(3 ∩ 3) = [tex]\dfrac{1}{6} \times \dfrac{1}{6} = \dfrac{1}{36}[/tex]
The probability that both rolls are 3s P(Both 3s) = [tex]\underline{\dfrac{1}{36}}[/tex]
Learn more here:
https://brainly.com/question/16543402
List the steps taken and find the area of the figure below
6cm
6 CM
6 cm
6 cm
Answer:
36 cm
Step-by-step explanation:
Since all measurements of the figure are the same, that means that this figure is a square. To find the area of a figure multiply length by width. Since this figure is a square and all sides are equal, we multiply 6 by 6 for an area of 36 cm.
What is the area of the figure?
A figure can be broken into a rectangle and triangle. The rectangle has a base of 5 feet and height of one-third feet. The triangle has a base of 3 and two-thirds feet and height of 2 feet.
5One-third ft2
6 and two-thirds ft2
7 ft2
9 ft2
plzzzz help in a test!!! i only have 18 pts sry!!!
Answer:
5 one-third ft²
Step-by-step explanation:
rectangle=5ft (base) / 1/3ft (height)
triangle1=3ft (base) / 2ft (height)
triangle2=2/3ft (base) / 2ft (height)
area of rectangle=5x1/3
=5/3ft²
area of triangle1=3x2(1/2)
=3ft²
area of triangle2=2/3x2(1/2)
=2/3ft²
Total area=5/3+6+2/3
=16/3ft² or 5 one-third ft²
Answer:
A
Step-by-step explanation:
took the test on edg 2021
Find the linearization L(x,y,z) at P_0. Then find the upper bound for the magnitude of the error E in the approximation f(x,y,z) = L(x,y,z) over the region R.
The linearization of f(x,y,z) at Po is L(xyz)=_______
Answer:
L(xyz) = ( 1 , 3 , -7 )
L = x + 3y - 7z -3
Step-by-step explanation:
f (x,y,z) = xy + 2yz - 3xz
f (3,1,0) = (3) (1) + 2 (1) (0) - 3 (3) (0)
f (3,1,0) = 3
fx = y - 3z
f (3,1,0) = (1) - 3 (0)
fx = 1
fy = x + 2z
f (3,1,0) = (3) - 2 (0)
fy = 3
fz = 2y - 3x
f (3,1,0) = 2 (1) - 3 (3)
fz = -7
Need help finding the answer
Answer:
D
Step-by-step explanation:
When there is an negative sign inside in a radical, then we remove that and put out of the radical classifying as "i". Then, reduce 63 into smallest form and we can write it as 9 and 7. 9 is a perfect square of 3 so we put it outside and the answer is D.
The length of the sides of a square are initially 0 cm and increase at a constant rate of 8 cm per second. Write a formula that expresses the side length of the square, s (in cm), in terms of the number of seconds, t , since the square's side lengths began growing. s
Answer:
s(t)=8t
Step-by-step explanation:
The length of the sides of a square are initially 0 cm and increase at a constant rate of 8 cm per second.
Let the length of the Square = s
[tex]\dfrac{ds}{dt}=8 $cm/seconds, s_0=0 cm[/tex]
We solve the differential equation above subject to the given initial condition.
[tex]\dfrac{ds}{dt}=8\\ds=8$ dt\\Take the integral of both sides\\\int ds=\int 8$ dt\\s(t)=8t+C, where C is the constant of integration\\When t=0, s=0cm\\s(0)=0=8(0)+C\\C=0\\Therefore, s(t)=8t[/tex]
The formula that expresses the side length of the square, s (in cm), in terms of the number of seconds, t , since the square's side lengths began growing is:
s(t)=8t (in cm)
Sean tossed a coin off a bridge into the stream below. The path of the coin can be represented by the equation h = -16t2 + 72t + 100. what is the height of the bridge
Answer:
100
Step-by-step explanation:
When t=0 (no time has passed), the coin is at height 100. This means the bridge must be 100 units high for this to be possible.
Answer:
100
Step-by-step explanation:
:3
Please answer this correctly
Answer:
20-39 => 2
40-59 => 1
60-79 => 1
80-99 => 6
100-119 => 5
Answer: 2, 1, 1, 6, 5
Step-by-step explanation:
20-39
2 | 3
3 | 9
40-59
5 | 0
60-79
7 | 5
80-99
8 | 1 2 4
9 | 3 9 9
100-119
10 | 1 1 5 6
11 | 1
What’s the correct explanation for this question?
Step-by-step explanation:
=> The volume of a triangular pyramid can be found using the formula V = 1/3AH where A = area of the triangle base, and H = height of the pyramid
=> The volume of a cone can be found by V = 1/3(Ab)(H) where Ab is base area and H is the height of the cone
The difference between both is that is it's base. A cone has a polygonal base while a pyramid has a tetragonal base
Please answer this correctly
Answer:
0-4: Make it 1 unit tall
5-9: Make it 5 units tall
10-14: Make it 4 units tall
15-19: Make it 1 unit tall
20-24: Make it 2 units tall
Step-by-step explanation:
0-4: 3 (1 number)
5-9: 5, 5, 7, 8, 8 (5 numbers)
10-14: 10, 11, 12, 13 (4 numbers)
15-19: 17 (1 number)
20-24: 22, 23 (2 numbers)
A florist currently makes a profit of $20 on each of her celebration bouquets and sells a average of 30 bouquets every week
Answer:
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW;
A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week. She noticed that when she reduces the price such that she earns $1 less in profit from each bouquet, she then sells three more bouquets per week. The relationship between her weekly profit, P(x), after x one-dollar decreases is shown in the graph below.
CHECK THE ATTACHMENT FOR THE GRAPH
EXPLANATION;
FIRST QUESTION:
From the graph maximum profit is the value gotten where p(X) has maximum value, and the maximum value is observed at y- axis at P(X)to be 675.
Thefore, maximum profit the florist will earn from celebration bouquet is $675.
SECOND QUESTION:
Break even is the exact point that profit p(x) is observed as zero.
Checking the given g graph the point where there is zero value of p(X) is observed at x=20 and x= -10 but we can only pick the positive value which is x=20
Therefore, the florist will break even after 20 one- dollar decreases
THIRD QUESTION;
The interval of number of one dollar decreases can be observed at the point where we have the value of P(x) been more than zero, looking at the given graph, the P(x) has its value greater than zero at the interval 0 to 20.Therefore, it can be concluded that the interval of number of one dollar decreases for which the florist makes a profit from celebration bouquet is (0, 20)
Answer:
Step-by-step explanation:
Any help would be great
Answer:
[tex]\frac{56}{96}[/tex] is your answer
Step-by-step explanation:
[tex]\frac{7}{12}[/tex]=[tex]\frac{x}{96}[/tex]
to get to 96 you must multiply by 8
and since you did that for the bottom then you need to do the same for the top,
[tex]\frac{56}{96}[/tex] is your answer
Given f(x) and g(x) = k⋅f(x), use the graph to determine the value of k. Two lines labeled f(x) and g(x). Line f(x) passes through points (-4, 0) and (-3, 1). Line g(x) passes through points (-4, 0) and (-3, -3).
A.) 3
B.) 1/3
C.) -1/3
D.) −3
Answer:
Option D.
Step-by-step explanation:
If a line passing through two points, then the equation of line is
[tex](y-y_1)=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
It is given that Line f(x) passes through points (-4, 0) and (-3, 1). So, equation of line f(x) is
[tex](y-0)=\dfrac{1-0}{-3-(-4)}(x-(-4))[/tex]
[tex]y=1(x+4)[/tex]
So, function f(x) is
[tex]f(x)=(x+4)[/tex] ...(1)
Line g(x) passes through points (-4, 0) and (-3, -3). So, equation of line f(x) is
[tex](y-0)=\dfrac{-3-0}{-3-(-4)}(x-(-4))[/tex]
[tex]y=-3(x+4)[/tex]
So, function g(x) is
[tex]g(x)=-3(x+4)[/tex] ...(2)
Using (1) and (2), we get
[tex]g(x)=-3f(x)[/tex] ...(3)
It is given that
[tex]g(x)=kf(x)[/tex] ...(4)
On comparing (3) and (4), we get
[tex]k=-3[/tex]
Therefore, the correct option is D.
Identify the word form of this number: 139,204,539,912
One hundred thirty-nine billion, two hundred four million, five hundred thirty-nine thousand, nine hundred twelve.
Hope this helped!
Convert 5613, base 10 to
base 8
Answer:
12755 base-8
Step-by-step explanation:
You’re welcome :) please brainliest me btw.
g Suppose the company operates mine #1 for x1 days and mine #2 for x2 days. Write a vector equation in terms of v1 and v2 whose solution gives the number of days each mine should operate in order to produce 296 tons of copper and 2454 kilograms of silver. Do not solve the equation.
Answer:
The vector equation in terms of v1 and v2 is x₁v₁ +x₂v₂ = [296 2454]
Step-by-step explanation:
Solution
The aim is to write down a vector equation in terms of v1 and v2, when solution gives the number of days each mine should operate in order to produce 296 tons of copper and 2454 kilograms of silver.
Thus,
Suppose that b = [ 296 2454] is the corresponding vector which is representing the total needed output.
Now,
If the company operates mine 1 for x1 days and mine #2 for x2 days
Then,
The total output becomes x₁v₁ +x₂v₂ which is the same output to b = [296 2454]
Hence, x₁ and x₂ should be satisfactory to the needed vector equation x₁v₁ +x₂v₂ = [296 2454]
So, the vector equation becomes x₁v₁ +x₂v₂ = [296 2454]
The expression 12g12g12, g gives the number of kilometers a car can travel using ggg liters of gasoline.
How far can this car travel on 5 \dfrac125
2
1
5, start fraction, 1, divided by, 2, end fraction liters of gasoline?
Answer:
Which of these factors will affect the friction on a road
Step-by-step explanation:
Answer:
66
Step-by-step explanation:
leave answer in simplest radical form
Answer:
[tex]\dfrac{5\pm\sqrt{47}}{6}[/tex]
Step-by-step explanation:
Let's start by setting y to 0 to find the roots of the quadratic.
[tex]x=\dfrac{5\pm \sqrt{25+12}}{6}=\\\\\dfrac{5\pm\sqrt{47}}{6}[/tex]
Hope this helps!
Shanda has 14.7 yards of fabric remaining after
using 8.1 yards to make pillows. How many yards
of fabric did Shanda have before making the
pillows?
Answer:
1-2 yards
Step-by-step explanation:
For most decorative throw pillows you will need 1-2 yards , depending on the size and details you choose to include
The length of a rectangular driveway is five feet more than three times the width. The area is 350ft2. Find the width and length of the driveway.
Answer:
width -- 10 ftlength -- 35 ftStep-by-step explanation:
We can let x represent the width. Then the length will be represented by (3x+5), a value 5 more than 3 times the width.
The area is the product of length and width, so is ...
A = (3x +5)(x) = 3x^2 +5x
To make the area 350, we can find the value of x from ...
3x^2 +5x = 350
This can be solved a number of ways. One of them is "completing the square".
3(x^2 +5/3x) = 350
We choose to divide by 3 and add the square of half the x-coefficient.
x^2 +5/3x +(5/6)^2 = (350/3) + (5/6)^2
(x +5/6)^2 = 4225/36 . . . . simplify
x +5/6 = ±√(4225/36) = ±10 5/6 . . . . take the square root
x = 10 or -11 2/3 . . . . subtract 5/6
The positive solution is the one of interest: x = 10.
The driveway is 10 ft wide and 35 ft long.
Combine these radicals. -3sqrt(of81)+sqrt(of16)
Answer:
-23
Step-by-step explanation:
An architect creates a scale model. The volume of the scale model is 0.1 cubic meters. The volume of the real-world
building is 100,000 cubic meters. What is the ratio of corresponding sides from model to real world?
Answer:
1:0.4641
Step-by-step explanation:
We are told that the scale of the model with respect to the real world is 0.1 cubic meter. This means that for every 1 cubic meter in the real world the model represents 0.1.
They tell us that the real world volume is 100,000, that if we assume a cube, we have to:
V = l ^ 3
l = 100000 ^ (1/3)
l = 46.41
46.41 meters would be each side, now the volume of the model would be:
100,000 * 0.1 = 10,000
Which means that its sides would be:
V = l ^ 3
l = 100000 ^ (1/3)
l = 21.54
We calculate the scale of the sides:
21.54 / 46.41 = 0.4641
Which means that for every 1 meter in the real world the model represents 0.4641 meters.
At a basketball game, for every 2 baskets team a scored, team b scored 5 baskets. The ratio of the number of baskets scored by team a to the number of baskets for team b is
Answer:
Another way of saying since the number of baskets scored by team A is 2, and the number of baskets scored by team B is 3, the answer is
C. 2 to 3. :)
Step-by-step explanation:
2 number cubes are rolled
what is the probability that the first lands on an odd number and the second lands on an even number?
Answer:
1/4
Step-by-step explanation:
1/2 times 1/2
1/2 because there is 3 odds and 3 evens
the total is 6
3/6 equals to 1/2
so 1/2 times 1/2 is 1/4
if p=7,q=5,r=3 find value of p2+q2-r2
Answer: The value is 18.
Step-by-step explanation:
Since we already know what p, q, and r equal, we can use what we know and plug in the numbers:
p=7, q=5, and r=3,
p2=7*2=14
q2=5*2=10
r2=3*2=6
In conclusion, 14+10-6=18
The value of p2+q2-r2 is 18.
Answer:
Just simply change the variables with their values
7 x 2 + 5 x 2 - 3 x 2
14 + 10 - 6
24 - 6 = 18
18 is the answer
Hope this helps
Step-by-step explanation:
The average math SAT score is 511 with a standard deviation of 119. A particular high school claims that its students have unusually high math SAT scores. A random sample of 55 students from this school was selected, and the mean math SAT score was 528. Is the high school justified in its claim? Explain. ▼ No Yes , because the z-score ( nothing) is ▼ unusual not unusual since it ▼ does not lie lies within the range of a usual event, namely within ▼ 1 standard deviation 2 standard deviations 3 standard deviations of the mean of the sample means. (Round to two decimal places as needed.)
Answer:
No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Unusual
If X is more than two standard deviations from the mean, x is considered unusual.
In this question:
[tex]\mu = 511, \sigma = 119, n = 55, s = \frac{119}{\sqrt{55}} = 16.046[/tex]
A random sample of 55 students from this school was selected, and the mean math SAT score was 528. Is the high school justified in its claim?
If Z is equal or greater than 2, the claim is justified.
Lets find Z.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{528 - 511}{16.046}[/tex]
[tex]Z = 1.06[/tex]
1.06 < 2, so 528 is not unusually high.
The answer is:
No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
The statement that could be made regarding the high school about the justification of its claim would be:
- No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
Given that,
μ = 511
σ = 119
Sample(n) = 55
and
s = [tex]119/\sqrt{55}[/tex]
[tex]= 16.046[/tex]
As we know,
The claim of the high school could be valid and justified only when
[tex]Z > 2[/tex]
To find,
The value of Z
So,
[tex]Z = (X -[/tex] μ )/σ
by putting the values using Central Limit Theorem,
[tex]Z = (528 - 511)/16.046[/tex]
∵ [tex]Z = 1.06[/tex]
Since [tex]Z < 2[/tex], the claim is not justified.
Learn more about "Standard Deviation" here:
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A rope, attached to a weight, goes up through a pulley at the ceiling and back down to a worker. The worker holds the rope at the same height as the connection point between the rope and weight. The distance from the connection point to the ceiling is 30 ft. Suppose the worker stands directly next to the weight (i.e., a total rope length of 60 ft) and begins to walk away at a constant rate of 2 ft/s. How fast is the weight rising when the worker has walked:
Answer: 0.66 ft
Step-by-step explanation:
Let assume that the initial position of the worker is x.
Given that the worker walks away with a constant speed of 2 ft/s. Therefore, dx/dt = 2
As the worker moves away, the rope makes a triangle, with width length x and the height length will be 30.
Using pythagorean theorem, the length of rope on this side of the pulley will be √(x² + 30²)
Also, the length of rope on the other side will be 60 - √(x² + 30²),
and the height h of the weight will be 30 - (60 - √(x² + 30²)) = √(x² + 30²) - 30
dh/dt = dx/dt × x/√(x² + 30²)
= 4x/√(x² + 30²)
dh/dt = 4x/√(x² + 30²)
If the worker moves 5ft away, then
dh/dt = (4×5)/√(5² + 30²)
dh/dt = 20/√(25 + 900)
dh/dt = 0.66 ft