Note about the question:
Among the (observed-expected)² list, there is one value missing. This value corresponds to round yellow gray plants, and equals 0.002. This number was included in the explanation of the problem.
Answer:
The chi-square value is X² = 2.6813.
Explanation:
Available information:
Observed individuals numbers:
Total number in the population: 639Round yellow gray 269 round yellow-white 98 round green, gray 86 wrinkled yellow gray 88 round green white 27 wrinkled yellow white 34 wrinkled green gray 30 wrinkled green white 7The expected numbers
ratio 27:9:9:9:3:3:3:1 round yellow gray 269.58 round yellow white 89.86 round green gray 89.86 wrinkled yellow gray 89.86 round green white 29.95 wrinkled yellow white 29.95 wrinkled green gray 29.95 wrinkled green white 9.98The (observed-expected) ² numbers
round yellow gray 0.002round yellow white 65.61 round green gray 15.2wrinkled yellow gray 3.61 round green white 8.41 wrinkled yellow white 16.81 wrinkled green gray 0.01 wrinkled green white 9.00To get the chi-square value, we just need to replace the terms in the following equation.
Chi square= ∑ ((O-E)²/E)
Where,
∑ is the sum of the terms O refers to the Observed number of individual E refers to the Expected numbers of individualsX² = ∑ ((O-E)²/E)
X² = (0.002/269.58) + (65.61/89.86) + (15.2/89.86) + (3.61/89.86) + (8.41/29.95) + (16.81/29.95) + (0.01/29.95) + (9/9.98)
X² = 0.0000074 + 0.73 + 0.17 + 0.04 + 0.28 + 0.561 + 0.0003 + 0.9
X² = 2.6813
Among the (observed-anticipated)² list, there's one price missing. This price corresponds to spherical yellow-grey plants and equals 0.002. This variety became protected withinside the clarification of the problem.
The chi-square value is [tex]X^ 2 =2.6813.[/tex]
Information given.
Observed people numbers:
Total variety withinside the population: [tex]639[/tex]
Round yellow grey [tex]269[/tex]
spherical yellow-white 98
spherical inexperienced, grey 86
wrinkled yellow grey 88
spherical inexperienced white 27
wrinkled inexperienced grey 30
wrinkled inexperienced white 7
wrinkled yellow white 34
The anticipated numbers
ratio 27:9:9:9:3:3:3:1
spherical yellow grey 269.58
spherical yellow white 89.86
spherical inexperienced grey 89.86
wrinkled yellow grey 89.86
spherical inexperienced white 29.9!
wrinkled yellow white 29.95
wrinkled inexperienced grey 29.95
wrinkled inexperienced white 9.98
The (observed-anticipated) 2 numbers
spherical yellow grey 0.002
spherical yellow white 65.61
spherical inexperienced grey 15.2
wrinkled yellow grey 3.61 spherical inexperienced white 8.41
wrinkled yellow white 16.81
wrinkled inexperienced grey 0.01
wrinkled inexperienced white 9.00
To get the chi-square value, we simply want to update the phrases withinside the following equation.
[tex]Chi square = Sigma((O - E) ^ 2 / E)[/tex]
Where,
[tex]Σ[/tex] is the sum of the phrases
O refers back to the Observed variety of individual
E refers back to the Expected numbers of people
[tex]X ^ 2 = Sigma((O - E) ^ 2 / E)[/tex]
[tex]X^ 2 =(0.002/269.58)+(65.61/89.86)+ Chi quare = Sigma((O - E) ^ 2 / E)[/tex]
Where,
Σ is the sum of the phrases
O refers back to the Observed variety of individual
E refers back to the Expected numbers of people
[tex]X ^ 2 = Sigma((O - E) ^ 2 / E)[/tex]
[tex]X^ 2 =(0.002 / 9.58)+(65.61/ 89.86) + (15.2/89.86)+(3.61/89.86)+(8.41/29.95)+ (16.81/29.95) + (0.01/29.95) + (9/9.98)[/tex]
[tex]X^ 2 =0.0000074+0.73+0.17+0.04+ 0.28 + 0.561 + 0.0003 + 0.9[/tex]
[tex]X ^ 2 = 2.6813[/tex]
What is chi-square?
Pearson's chi-square test is utilized to inspect the job of chance in creating deviations among noticed and anticipated values. The test relies upon extraneous speculation since it requires hypothetical anticipated that values should be determined.
Hence it clearly calculates the value of chi-square.
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which list shows the phase of mitosis in the correct order
Answer: The answer is B. prophase, metaphase, anaphase, telophase
Explanation:
Which location would u most likely NOT expect an earth quake
Location 1
Location 2
Location 3
Location 4
Answer:
Location 4
Explanation:
The closest you are to a tectonic plate, the most likely is to expect an earthquake. Note how Location 3 is over California. So, location 4 is away from the tectonic plates.
HELPPPPP
How many grams of LiCl are in 235.0 mL of 1.80 M lithium chloride solution?
1
Show Your Work
Answer:
Mass of LiCi = 17.9352 gm
Explanation:
Given:
Volume of LiCi = 235 ml
Molarity = 1.80 M
Find:
Mass of LiCi
Computation:
Atomic mass of LiCi = 6.9 + 365.5 = 42.4 gm
Mole(n) = Weight / Atomic mass
1.80 = [W / (42.4 x 235)]1000
Mass of LiCi = 17.9352 gm
Which process is represented by the picture below?
A. Vegetative Propagation
B. Meiosis
C. Fertilization
D. Binary Fission
HELPP MEEE
Answer:
Meiosis is the correct answer
Can you help me with 1 please
which products of photosynthesis are necessary for human life ?
a) carbon dioxide for us to breathe in, as well as sunlight and water.
b) oxygen for us to breathe in , as well as sunlight and water.
c) oxygen for us to breathe in , as well as glucose forcus to consume for energy.
d) carbon dioxide for us to breathe in, as well as glucose for us to consume for energy.
.
What is a concept?
1.a fact that has been proven
2.the answer to a scientific question
3.an idea that can be used to talk about the world
4.a set of questions related to one topic
Answer:
an idea that can be used to talk about the world
Explanation:
helpp please !!! thanks
Answer: it would be b!
Explanation:
If you tossed a coin a total of ten times and got a total of three
heads, what is the probability of tossing heads in your next
toss?
Answer:
The probability of exactly 3 heads in 10 tosses is 1201024.
The probability that result will be head in the next toss is 1/2.
What is Probability?This is a mathematical term which is used to describe how likely an event is to occur or how true a proposition is. In this scenario, we have two variables which are head and tail.
The probability probability of tossing heads in your next toss is therefore
1/2 = 50% chance.
Read more about Probability here brainly.com/question/24756209
A woman with a straight hairline has as child with a man who is heterozygous
and has a widow's peak.
What is the mother's genotype?
Answer:
aa
Explanation:
A widow's peak is the dominant genotype so one must not have that trait. If it was presented then the woman would have the genotype.
A widow's peak is dominant so the man would be either AA or Aa. Since it stated that his is heterozygous (Hetero meaning two different), his genotype would be Aa (again since a widow's peak is the dominant, it only needs one dominant genotype)
PLZ HELPPPPPPPPPPPP
Answer:
you're correct
Explanation:
Answer:
楽しい時間楽しい時間楽しい時間
Explanation:
4. Free or low-cost apps have few of the same benefits as fitness trackers.
True
False
The given statemnet is false because Free or low-cost apps can provide many of the same benefits as fitness trackers, albeit with some limitations.Option B
Fitness trackers are dedicated devices designed specifically for monitoring physical activity and collecting data related to fitness goals. They often include features like step counting, heart rate monitoring, sleep tracking, and GPS tracking. These devices may offer a more seamless and integrated user experience, with optimized hardware and software for tracking and analyzing fitness data.
However, free or low-cost apps can offer similar benefits and functionalities, albeit with some trade-offs. Many smartphone apps are available that can track steps, monitor heart rate, record workouts, and provide guidance for various exercises. These apps can be downloaded and installed on smartphones, making them accessible and convenient for users.
While some features might be more accurate or reliable in dedicated fitness trackers due to specialized sensors, smartphone apps can still provide valuable data and insights for tracking fitness progress. They can offer personalized workout plans, track progress over time, provide reminders and notifications, and offer social features for sharing achievements and connecting with others.
Moreover, free or low-cost apps often come with the advantage of being customizable, allowing users to choose the features and functionalities that are most relevant to their specific fitness goals and preferences. They can be easily updated and expanded with new features as technology advances.
In conclusion, while dedicated fitness trackers may offer a more comprehensive and optimized experience, free or low-cost apps can still provide many of the same benefits, making them a viable alternative for individuals seeking fitness tracking capabilities.
Option B
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#SPJ8
Which statement best describes the evolution of hominid structure over time?
The size of the skull decreased.
O The size of the brain cavity increased.
O The shape of the head became flatter.
The shape of the teeth became more pointed.
Answer:
The size of the brain cavity increased.
Explanation:
Over the years the brain cavity got bigger and so did our brain and that is why humans are smarter
The evolution of hominid structure over time involved the increase in the size of the brain cavity.
What is evolution?Evolution refers to the gradual and cumulative changes that occurred in organisms over a long period of time which made them more complex and which they were able to transmit to their offspring.
The hominids were the ancestors of the modern day humans.
Through the process of evolution, the size of the brain cavity increased in hominids resulting in larger brains and more complexity as seen in modern humans today.
Therefore, the increase in the brain cavity of hominids occurred through the process of evolution.
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In cocker spaniels, black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s). In the F 2 generation of a cross between BB ss with bb SS, what fraction of the offspring would be expected to be black and spotted
Answer:
The correct answer is -3/16
Explanation:
The cross between BBss and bbSS In cocker spaniels will form gametes that are - Bs and bS. As it is given that black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s) then f1 gen would be :
Bs Bs
bS BbSs BbSs
bS BbSs BbSs
Now F2 generation;
BS Bs bS bs
BS BBSS BBSs BbSS BbSs
Bs BBSs BBss BbSs Bbss
bS BbSS BbSs bbSS bbSs
bs BbSs Bbss bbSs bbss
Here black-spotted that is possible only in two cases, BBss or Bbss, are 3/16
The diagram below shows a cell placed in a solution.
A cell is shown placed inside a beaker. It is labeled Cell. The solution inside the beaker is labeled 2% salt solution and the solution inside the cell is labeled 4% salt solution.
What will most likely happen to the cell?
It will expand as water moves out of it.
It will shrink as water moves out of it.
It will expand as water moves into it.
It will shrink as water moves into it.
The most likely to happen to the cell is ; ( C ) It will expand as water moves into it
The movement of water in and out of a cell is based on osmosis .The cell membrane of the cell will regulate the movement of water molecules in and out of the cell. based on the solute concentration inside the cell and outside the cell.
When a cell is placed in a hypotonic solution ( i.e. a solution with a lower solute concentration as seen in the 2% salt solution ) the water molecules from the hypotonic solution will move into the cell which will cause the cell to be Turgid/expand over time.
Hence we can conclude that the most likely thing to happen to the cell is ; It will expand as water moves into it
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Which of these is NOT found in a bone?
A) cells
B) muscle tissue
C) blood cells
D) nerve tissue
Answer:
D. Nerve tissue
Explanation:
A geneticist is mapping the chromosomes of the newly captured gremlin. Stripe is heterozygous for three linked genes with alleles Ee, Hh, and Bb, that determine if gremlins are evil (E), have hair (H), and biting teeth (B). In order to determine if the three genes are linked, a standard testcross was done, and the 1000 offspring had the following genotypes: 48 ee Hh bb 36 ee hh Bb 400 ee Hh Bb 4 Ee Hh Bb 426 Ee hh bb 46 Ee hh Bb 38 Ee Hh bb 2 ee hh bb What is the recombination frequency between genes E and H
Recombination frequency determines if two genes are linked or if they segregate independently from each other. The recombination frequency between E and H is 8%
What are linked genes?Linked genes are those that are too close to each other in the same chromosome and they do not segregate independently.
These are the linked genes that do not exhibit an independent distribution, and they are inherited together more frequently.
What is recombination frequency?Recombination frequency can be defined as the crossing over events frequency occurring between two genes.
The value of recombination frequency indicates weather genes are linked or not. The maximum recombination frequency is always 50%.
When RF is 50% or more, we can assume that genes are not linked.
In the exposed example, we can recognize the parental gametes in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent.
Parental)
400 ee Hh Bb
426 Ee hh bb
Double recombinant)
4 Ee Hh Bb
2 ee hh bb
Simple recombinant)
48 ee Hh bb
36 ee hh Bb
46 Ee hh Bb
38 Ee Hh bb
We will call Region I to the area between genes E and H and Region II to the area between genes H and B.
------------E------------H--------------B-----------
/---RI------//------RII-----/
To calculate the recombination frequency between E and H we just need to consider region I. We will call P1 to the recombination frequency in this region.
P1 = (R + DR) / N
Where:
R is the number of simple recombinants in this region, DR is the number of double recombinants in each region, and N is the total number of individuals.Now, let us analyze the information.
We know that individuals carrying double recombinant gametes are
Ee Hh Bbee hh bbWe know that the recessive parent from the testcross could only provide the following gametes ⇒ ehb
This leads us to assume that the followings are the double recombinant gametes from the trihybrid parent,
EHBehbSince these gametes are the product of a double recombination event in region I and II, we can assume that the parental gametes of the trihybrid individual are
eHbEhBHence the simple recombinant gametes in region I are
EHbehBNow, according to this analysis, we know that
Simple recombinants in region I
36 ee hh Bb
38 Ee Hh bb
Double recombinants
4 Ee Hh Bb
2 ee hh bb
Total number of individuals
N = 1000
Recombination frequency in Region I
P1 = (R + DR) / N
P1 = (38 + 36 + 4 + 2) / 1000
P1 = 80 / 1000
P1 = 0.08 = 8%
The recombination frequency between genes E and H is P1 = 8%
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All cells have DNA that must be replicated True or false
The answer is True.
‼️‼️‼️‼️HELP HELP HELP HELP HELP WHOEVER CAN PLEASE‼️‼️‼️‼️
Answer: i would say b!
Explanation:
hope i helped! :D
Why do multicellular cells communicate together?
1. To maintain strength and shape
2. To be more organized
3. To maintain homeostasis
Answer:
I think 3 because I had the same thing but eah
Point mutations resulting in a single amino acid substitution provided evidence that: Select one: A. The genetic code is a triplet code. B. The genetic code is overlapping. C. The genetic code is not overlapping. D. The genetic code is degenerate. E. tRNAs recognize codons.
Answer:
C. The genetic code is not overlapping.
Explanation:
The genetic code is nonoverlapping because each nucleotide can be part of only one codon or 'codeword' during protein synthesis. Therefore, a particular point mutation in the nucleotide sequence can result in only one amino acid modification. A nonoverlapping genetic code indicates that the same letter (i.e., the same nucleotide) can not be used for two different codons. The non-overlapping nature of the genetic code was discovered by Tsugita and Fraenkel-Conrat (1960) by observing point mutations in the tobacco mosaic virus.
A change or modification in the single nucleotide base of the genetic material is called a point mutation. It can be either addition, deletion or inversion.
The correct answer is:
Option C. The genetic code is not overlapping.
This can be explained as:
The point mutation in the amino sequence tells that the codons are not overlapping and a single nucleotide is a part of only a single type of codon.A single nucleotide can't be included in two codons.The same letters of the bases purines and pyrimidines are not a part of two different triplets.Therefore, point mutation tells that the genetic code is non-overlapping.
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The process of water moving from the Earth to the atmosphere and back again is called the
A. Earth cycle
B. Atmosphere cycle
C. life cycle
D. water cycle
The movement of glucose across a plasma membrane is achieved by
Answer:
facilitated diffusion
Explanation:
What does DNA do for our bodies? 'T
DNA contains the instructions for an needed for an organism to develop, survive, and reproduce.
The...........is also known as the tympanum.
1)eardrum
2)stapes
3)cochlea
4)malleus
Answer and I will give you brainiliest
Answer:
1
djdhdbbdbdbsbdbdbsb
Meiosis consists of _________ division(s) of the nucleus.
a. one
b. two
c. three
d. four
Answer:
the answer is two for this question
Please :( Based on your knowledge of evolution, are humans evolving? Support your answer with factual evidence as to
why or why not
Answer:
Jesus made every one evalution is false
When Charles Darwin introduced the theory of evolution through natural selection 158 years ago, the scientists of the day argued over it fiercely, but the massing evidence from paleontology, genetics, zoology, molecular biology and other fields gradually established evolution's truth beyond reasonable doubt. Today that battle has been won everywhere—except in the public imagination. Embarrassingly, in the 21st century, in the most scientifically advanced nation the world has ever known, creationists can still persuade politicians, judges and ordinary citizens that evolution is a flawed, poorly supported fantasy. They lobby for creationist ideas such as “intelligent design” to be taught as alternatives to evolution in science classrooms. When this article first went to press in 2002, the Ohio Board of Education was debating whether to mandate such a change. Prominent antievolutionists of the day, such as Philip E. Johnson, a law professor at the University of California, Berkeley, and author of Darwin on Trial, admitted that they intended for intelligent-design theory to serve as a “wedge” for reopening science classrooms to discussions of God.
The good news is that in 2005 the landmark legal case Kitzmiller v. Dover in Harrisburg, Pa., set binding precedent that the teaching of intelligent design in U.S. public schools is unconstitutional because the idea is fundamentally religious, not scientific. The bad news is that in response, creationists have reinvented their movement and pressed on. When they lost the ability to claim that creationist ideas are valid science, they switched to arguing that they were only supporting “academic freedom.” Worse, to further obscure the religious roots of their resistance, they now push for “critical analysis” of climate change, cloning research and other scientific endeavors that they paint as culturally oppressive.Explanation:
6 In the condition hyperthyroidism, patients have elevated levels of both T3 and 14 due to a malfunction of the
immune system that causes the thyroid gland to overproduce thyroid hormones. Do you think the negative
feedback loops would lead to high levels of TSH or low levels of TSH? Explain.
which of the following would be produced during mitosis
Answer:
mitosis is a process of cell division in which one cell is divided into two and the two cells produced are exacty similar to the parent cell. chromosome number cell size remains same.
mitosis plays an important role in growth of organisms.
Explanation:
The area of the picture highlighted by the green square is a monomer of nucleic acids(DNA/RNA). Which of the following is the name for that monomer?
A. phosphate backbone
B. thymine
C. nucleotide
Answer:
C. Nucleotide
Explanation:
There are four types of biological molecules existing in nature. These are: carbohydrates, proteins, lipids, and nucleic acids. Nucleic acids are biological polymers made up of monomeric units called NUCLEOTIDES.
A nucleotide as depicted in the attached image is a molecule made up of three components namely; Penrose sugar, phosphate group, and nitrogenous base (adenine, guanine, cytosine and thymine). Based on the image in this question;
A represents ADENINE
S represents SUGAR
P represents PHOSPHATE GROUP
Hence, the monomer is a NUCLEOTIDE.
