1. A student measures the mass of a solution before and after a chemical reaction takes place. In both cases the student measures the mass to be 50.25 g on an electronic balance with an uncertainty of 0.05 g. The student realizes that the ranges of uncertainty for each measurement overlap exactly. Which claim can the student make?(a) The mass definitely stayed the same because the ranges of uncertainty overlap exactly.(b) We can't know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainity overlap.(c) The mass definitely stayed the same because the measurement of 50.25 g was obtained each time.2. In the previous question you learned that a measurement system can be accurate but not precise, precise but not accurate, neither, or both. If an equipment contains a systematic error, then increasing the sample size will in general:(a) improve both accuracy and precision.(b) have no effect on either accuracy and precision.(c) improve accuracy but will not increase precision.(d) increase precision but will not improve accuracy.3. The cloth tape measure that you use to measure the length of an object had been stretched out from years of use. As a result, all of your length measurements were too small. How could you compensate for the incorrect results of using the stretched out tape measure?(a) There is no way to compensate for the incorrect result.(b) This is due to systematic error. Assuming that a new tape is more accurate, compare the stretched tape to a new tape to see how much the measurements are off. This difference will tell you how much to correct each original length measurement causing the systematic error to be minimized.(c) This is due to random error. Take more measurements until you get enough data to average and reduce the error.(d) This stretch is due to random error, so it can be ignored.

Answers

Answer 1

a) The claim student can make is - We can't know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainity overlap.

b)  increasing the sample size will in general - increase precision but will not improve accuracy.

c) incorrect results of using the stretched out tape measure- This is due to systematic error. Assuming that a new tape is more accurate, compare the stretched tape to a new tape to see how much the measurements are off. This difference will tell you how much to correct each original length measurement causing the systematic error to be minimized.

a) Since the pupil used the same electronic balance with an query of0.05 g to weigh the mass of the result ahead and later, we can say that the millions are the same within the query of the balance.

b) Precision is the degree to which unborn measures yield the same results. delicacy, on the other hand, is a measure of how nearly the results agree with a true value. By adding the sample size the standard error is dropped meaning that unborn measures will probably fall near to the average. However, also taking further measures won't address this error and ameliorate delicacy as each dimension will be" off" by the same quantum from the true value, If methodical error is present. rather the methodical error needs to be removed, if possible, and this will ameliorate delicacy.

c) The stretching of the tape recording measure introduces a methodical error which could be corrected by comparing the tape recording with a different tape recording( essence or new). Once the pupil knows how important each dimension is out, the pupil can acclimate the original measures consequently. Performing further measures simply reduces the arbitrary error caused by the person reading the scale and won't affect the delicacy of the dimension.

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semiconductors can simplistically be thought of as an intermediate state between insulators and conductors. in a semiconductor, charges are normally bound in place (like in an insulator), but when injected with enough energy, the charges can move freely (like in a conductor). given what we have observed about the behavior of conductors and insulators in this exploration, what would happen if we replaced the pvc rod with a semiconductor material? what mechanisms could we employ to inject energy into the bound charges in the semiconductor to force it to act like more of a conductor?

Answers

Replacing PVC rod with semiconductor material, its behavior would depend on specific properties. To inject energy we can apply a voltage.

If we replaced the PVC rod with a semiconductor material, the behavior of the rod would depend on the specific properties of the semiconductor. Semiconductors have a unique property called the bandgap, which is the energy difference between the highest occupied energy level (valence band) and the lowest unoccupied energy level (conduction band). When an external energy source, such as heat or light, is applied to a semiconductor, it can promote electrons from the valence band to the conduction band, creating a flow of free electrons that can conduct electricity.

To inject energy into the bound charges in the semiconductor and force it to act more like a conductor, we could use several mechanisms. One common approach is to apply a voltage across the semiconductor, which creates an electric field that can promote electron movement. Another approach is to expose the semiconductor to light, which can excite electrons to higher energy levels and promote conduction. Additionally, thermal energy can cause the semiconductor to act more like a conductor by promoting electron movement. These mechanisms can be used to tailor the conductivity of semiconductors, which is the foundation of many modern technologies such as transistors, solar cells, and light-emitting diodes (LEDs).

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Which of these is constant for ALL types of electromagnetic radiation in a vacuum?

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In a vacuum, the Velocity of ALL forms of electromagnetic radiation remains constant. In contrast to mechanical waves, electromagnetic waves may travel without a medium.

This indicates that electromagnetic waves are capable of passing not just through solid objects like air and rock but also through a vacuum like space.

At the speed of light (2.998 108 m/s), electromagnetic radiation is an electric and magnetic disturbance that travels through space. It moves in radiant energy packets called photons or quanta and has neither mass nor charge. X-rays, infrared, ultraviolet, gamma, and radio waves are all types of electromagnetic radiation. The sun and other celestial bodies, radioactive substances, and man-made gadgets are some examples of sources of EM radiation. EM displays both a wave and a particle nature.

The medium's electric and magnetic characteristics affect the velocity of electromagnetic waves.

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show answer no attempt 50% part (b) how much energy is lost to friction if the motorcycle only gains an altitude of 21 m before coming to rest?

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From the information provided, the energy lost to friction if the motorcycle only gains an altitude of 21 m before coming to rest is approximately 65,954.64 J.

To calculate the energy lost to friction, we need to first determine the initial total mechanical energy of the motorcycle and the final total mechanical energy of the motorcycle after it has climbed to a height of 21 meters and come to rest. The difference between the initial and final energies will give us the energy lost to friction.

The initial total mechanical energy of the motorcycle is given by:

Ei = (1/2)mv² + mgh + 2(1/2)Iw²

where m is the mass of the motorcycle, v is its initial speed, h is the height it climbs, g is the acceleration due to gravity, I is the moment of inertia of the wheels, and w is their initial angular velocity.

We need to calculate the moment of inertia of each wheel:

I = (1/2)mr²

where m is the mass of the wheel and r is its radius. Substituting the given values, we get:

I = (1/2)(12 kg)(0.33 m)² = 0.6534 kg m²

The initial angular velocity of each wheel is not given, so we can assume that it is initially at rest (i.e., w = 0).

Substituting the given values into the equation for E, we get:

Ei = (1/2)(180 kg)(25 m/s)² + (180 kg)(9.81 m/s²)(36 m) + 2(1/2)(0.6534 kg m²)(0)²

= 101,812.44 J

The final total mechanical energy of the motorcycle is given by:

Ef = mgh

where m, g, and h are as before, and the speed and rotational energy of the wheels are both zero.

Substituting the given values, we get:

Ef = (180 kg)(9.81 m/s²)(21 m) = 35,857.8 J

The energy lost to friction is the difference between the initial and final energies:

Energy lost = Ei - Ef = 101,812.44 J - 35,857.8 J = 65,954.64 J

Question - Suppose a 180 kg motorcycle is heading toward a hill at aspeed of 25 m/s. The two wheels weigh 12 kg each and are each annular rings with an inner radius of 0.280 m and an outer radius of 0.330 m. Randomized Variables m 180 kg ˇ-25 m/s h 36 m. how much energy is lost to friction if the motorcycle only gains an altitude of 21 m before coming to rest?

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