Felipe walks from the house to his truck on the way to work. He walks 20m to the truck and another 60m in his truck for a total of 20s. What is Felipes average velocity over the 20s period? What is Felipes average speed over the 20s period?
Answer:
Felipe's average speed over the 20s period is 14.4 km/h.
Explanation:
To determine the speed at which Felipe has walked, the distance traveled and the time it took him must be considered.
Thus, Felipe walked 80 meters (20 towards the truck, and 60 inside it) in a total of 20 seconds. That is, he traveled 4 meters per second (80/20 = 4).
Now, to transfer said speed to kilometers per hour, the following calculation must be performed:
1 hour = 60 minutes
1 = 60 seconds
Number of seconds in an hour: 60 x 60 = 3600
Thus, Felipe has walked at an average speed of 14,400 meters per hour (4 x 3,600 = 14,400). So, since a kilometer consists of 1000 meters, its average speed in kilometers per hour was 14.4 km / h (14,440 / 1,000 = 14.4).
Answer: the answer is 4.0 for both
Explanation: on khan academy !!!
10. An object accelerates 2.0 m/s2 when a force of 12.0 newtons is applied
to it. What is the mass of the object?|
Explanation:
F = ma
m = F/a
= 12N / 2m/s2
= 6kg
The mass of the object is 6kg.
What is Force?A force is defined as an effect that can change the motion of an object by which an object with mass can change its velocity, that is, accelerate. Force can also be described simply as a push or pull. A force has both magnitude and direction which makes it a vector quantity.
According to the Newton's second law of motion is F = ma, or force is equal to mass times acceleration.
Where, F= Force applied
m= mass of the object
a= acceleration
For above given information,
F= 12 N
Acceleration= [tex]2 m/s^2[/tex]
So, mass will be m=F/a
m= 12/2 = 6kg
Thus, the mass of the object is 6kg.
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Notice that in each conversion factor the numerator equals the denominator when units are taken into account. A common error in dealing with squares is to square the units inside the parentheses while forgetting to square the numbers! QUESTION What is the numerical part of the time conversion factor, apart from units, that would be used to further convert the answer to km/h2
Answer:
he factor for the temporal part 1.296 107 s² = h²
m / s² = 12960 km / h²
Explanation:
This is a unit conversion exercise.
In the unit conversion, the size of the object is not changed, only the value with respect to which it is measured is changed, for this reason in the conversion the amount that is in parentheses must be worth one.
In this case, it is requested to convert a measure km/h²
Unfortunately, it is not clearly indicated what measure it is, but the most used unit in physics is m / s² , which is a measure of acceleration. Let's cut this down
the factor for the distance is 1000 m = 1 km
the factor for time is 3600 s = 1 h
let's make the conversion
m / s² (1km / 1000 m) (3600 s / 1h)²
note that as time is squared the conversion factor is also squared
m / s² = 12960 km / h²
the factor for the temporal part 1.29 107 s² = h²
Mass of mercury = 57 g Volume of mercury = 4.2 mL
Impulse is the______of the force and time of contact
Answer:
Product
Explanation:
Impulse is defined as the average force acting on an object times the time the force acts:
Impulse = F · Δt
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT, then the rod’s length changes by ΔL=????L0ΔT, where ???? is the thermal expansion coefficient. For steel, ????=1.24×10−5∘C−1. (a) A steel rod has length L0=70cm at T0=70∘C. What is its length at T=110∘C?
Answer:
[tex]\Rightarrow L=70 .03472 cm[/tex]
Explanation:
For convenience, let's represent the thermal expansion coefficient by [tex]\alpha[/tex], i.e. [tex]????=\alpha[/tex].
Given that, for steel [tex]\alpha =1.24\times 10^{-5}[/tex] °[tex]C^{-1}[/tex],
initial length, [tex]L_0=70 cm[/tex], initial temperature, [tex]T_0=70[/tex] °[tex]C[/tex], and the final temperature, [tex]T=110[/tex] °[tex]C[/tex].
Let the length of the rod at [tex]T=110[/tex] °[tex]C[/tex] be [tex]L[/tex].
Now, change in length, [tex]\Delta L=\alpha L_0 \Delta T[/tex]
[tex]\Rightarrow \Delta L=\alpha L_0 (T-T_0)[/tex]
[tex]\Rightarrow L-L_0=1.24\times 10^{-5}\times 70 (110-70)[/tex]
[tex]\Rightarrow L-70=1.24\times 10^{-5}\times 70 \times 40[/tex]
[tex]\Rightarrow L=70 + 0.03472 cm[/tex]
[tex]\Rightarrow L=70 .03472 cm[/tex]
Hence, the length of the rod at [tex]T=110[/tex] °[tex]C[/tex] be [tex]70.03472 cm[/tex].
I need help asap on these definitions if anyone could help me please :(
I'll give 20 points to whoever helps me!!
Answer:
Inertia: a tendency to do nothing or to remain unchanged; momentum:the quantity of motion of a moving body; velocity:the speed of something in a given direction; acceleration: a vehicles capacity to gain speed within a short time
What is the definition of Acceleration? In science?
Answer:
The definition of acceleration is is a vector quantity that is defined as the rate at which an object changes its velocity.
Explanation:
Answer:
DescriptionIn mechanics, acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
Explanation:
A piece of wood that floats on water has a mass of 0.0175 kg. A lead weight is tied to the wood, and the apparent mass with the wood in air and the lead weight submerged in water is 0.0765 kg. The apparent mass with the wood and the lead weight both submerged in water is 0.0452 kg. What is the specific gravity of the wood
Answer:
Specific gravity is 0.56
Explanation:
We know that
mass of water displaced by the wood is, m1( apparent mass when wood in air and lead is submerged in water) - m2(the apparent mass when wood and lead both are submerged in water)
= 0.0765 - 0.0452 = 0.0313 Kg
So the specific gravity of the wood is, = mass of wood / mass of water displaced by the wood
= 0.0175/0.0313
=0.56
How does the use of vectors
allow you to compare,
translate, and determine the
motion of a object?
Answer:
Explanation:
A vector is any substance that has both magnitude and direction. lndeed a vector quantity has both magnitude and direction. Example of a vector quantity is velocity. Determining the velocity of an object allows one to determine how fast and in what direction the object moves. Velocity also affords the opportunity to compare the motion of more than one vectors.
Which of the following does not serve as a way to neutralize the charge in a body?
A. Adding more protons to a positively charged body until the number of protons matches the number of elec
B. Adding free electrons to a positively charged body
C. Allowing free electrons to escape from a negatively charged body
D. Bringing the charged body into contact with another body having an equal but opposite charge
Answer:
B. Adding more protons to a positively charged body until the number of protons matches the number of electrons
Explanation:
wire 1 and 2 are made of the same metal. wire 2 has twice the length and diameter of the of wire 1.what is the ratio R2/R1 of the resistance of two wire ?
The 45-g Wood Thrush migrates every spring from Central America to the United States to breed. The bird leaves its winter
home in Belize and travels 1422 km across the Gulf of Mexico to Louisiana. It then flies an additional 1343 km to reach
Virginia, where it spends the summer. The trip takes approximately 171 hours, flying mostly at night.
What is the average speed of the Wood Thrush?
Answer:
v = 16.16 km/h
Explanation:
Distance covered by Wood Thrush is 1422 km across the Gulf of Mexico to Louisiana + 1343 km to reach Virginia, where it spends the summer.
d = 1422 km + 1343 km
d = 2765 km
The trip takes approximately 171 hours, flying mostly at night, t = 171 hours
We need to find the average speed of the Wood Thrush. It can be given by :
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{2765\ km}{171\ h}\\\\v=16.16\ km/h[/tex]
So, the average speed of the Wood Thrush is 16.16 km/h.
which statement illustrates a chemical change?
A) shredding paper
B) smashing a soda can
C) burning wood*
D) chopping wood
Answer:
The answer is C burning the wood
A soda has mass of 1500 g and a density of 2.9 g/ml . What is the volume?
The density of the substance is its mass divided by volume. Thus, the volume of 1500 g soda with a density of 2.9 g/ml is 517.2 g/ml.
What is density?Density of a substance is the measure of its mass per unit volume. The density of a substance depends on its bond type, temperature and pressure as well.
The volume of a substance is the space occupied by its particles. The volume of the substance is the mass divided by density.
Volume is generally expressed in units of liters or milliliters.
Given that, mass of soda = 1500 g
density = 2.9 g/ml
volume = mass/ density
v = 1500 g/ 2.9 g/ml = 517.2 ml.
Therefore, the volume of soda is 517.2 ml.
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When a star is moving away from Earth, does the color of the star actually change? Explain - PLZZ HELP:)
Answer:
Yes the color changes. If the star is moving away from the earth the color of the star is shifted towards red (red-shift).
This is similar to the change in sound from an approaching train whistle (higher pitch) or a receding train whistle (lower pitch) - the Doppler Effect.
Note that the equations for the Doppler Effect for sound and for light are different - sound travels thru air but no such medium can be identified for light.
A tow truck is using a cable to pull the classic car up a 15o hill. If the classic car weighs 4000 lbs and the cable has a diameter of 3/4 inch, find the stress in the cable when the truck comes to a stop while on the hill. Ignore friction between the car and the pavement
Answer:
the stress in the cable at the time when the truck is stop is 2,344.57 lb/m^2
Explanation:
The computation of the stress in the cable when the truck comes to a stop is shown below:
We used the following formula
[tex]T = mg\times sin\theta\\\\= 4,000 \times sin15^{\circ}[/tex]
= 1,035.28
Now the stress in the cable is
Before calculating it first determined the area which is
[tex]Area = \frac{\pi}{4}\times (\frac{3}{4})^2 \\\\= \frac{9\pi}{64}[/tex]
So, the stress is
[tex]= \frac{T}{area}\\\\ = \frac{1,035.28}{\frac{9\pi}{64} }[/tex]
= 2,344.57 lb/m^2
Hence, the stress in the cable at the time when the truck is stop is 2,344.57 lb/m^2
What is the field outside the capacitor plates in a parallel capacitor?
Answer:
Zero
Explanation:
If using an ideal parallel plate capacitor, the electric field outside should be nearly zero.
4800 g to kg? With the work pls
Answer:
[See Below]
Explanation:
✦ Formula = [tex]Mass / 1000[/tex]
✧ [tex]4800 / 1000 = 4.8[/tex]
So [tex]4800[/tex] grams is equal to [tex]4.8[/tex] kilograms.
~Hope this helps Mate. If you need anything feel free to message me.
A boy walked 22 m East then 43 m West , and then 3 meters East. What is the sum of the boys motion.
Given :
A boy walked 22 m East then 43 m West , and then 3 meters East.
To Find :
What is the sum of the boys motion.
Solution :
We need to find the sum of all the motion of boy .
So , we need to find the distance covered by the boy .
We know , total distance covered is absolute sum of all the motion .
[tex]D=22+43+3\\\\D=68\ meters[/tex]
Therefore , total distance covered is 68 meters .
Hence , this is the required solution .
Answer:
It's 18m West.
Explanation:
Imagine you have a number line. your starting point was 22 east of origin. Then you went 43 meters west which leaves you at 21m west. Then you go back east 3 meters. Which leaves you at 18 m west. I hope this helps.
Two supports, made of the same material and initially of equal length, are 2.0 m apart. A stiff board with a length of 4.0 m and a mass of 10 kg is placed on the supports, with one support at the left end and the other at the midpoint. A block is placed on the board a distance of 0.50 m from left end. As a result the board is horizontal (that is, the downward force on each support is the same). The mass of the block is:
Answer:
20 kg
Explanation:
Assuming that the board remains horizontal with the unknown mass on it, then F = kx
If we add the vertical forces to zero, we have something like this
2F - (M + 10)g = 0
2F = (M + 10)g, next, divide both sides by 2
F = (M + 10)g/2
Since we were able to sum the moments at the right end of the board to zero, we then proceed to find the unknown mass M
To start, we say, Let the clockwise moment is positive, and so
F * 4 + F * 2 - Mg * 3.5 - 10 * g * 2 = 0
4F + 2F - 3.5Mg - 10 * 2 * g = 0
6F - 3.5Mg - 10 * 2 * g = 0,
Remember from above, we say that
F = M + 10)g/2, now, all we do is substitute it inside this equation
6 * (M + 10)g/2 - 3.5Mg - 10 * 2 * g = 0
3 * (M + 10)g - 3.5Mg - 10 * g * 2 = 0, divide all sides by g(so as to eliminate it)
3 (M + 10) - 3.5M - 10 * 2= 0
3M + 30 - 3.5M - 20 = 0
-0.5M + 10 = 0
0.5M = 10
M = 10/0.5
M = 20 kg
The mass of the block that was placed on the board is; M = 20 kg
Since the two supports are the same, then it means their forces will be the same.
Thus;
Force at left support = F
Force at right support = F
Now, we are told that a block of unknown mass is placed on the stiff board. This means that the sum of the weight of the board and and the block on it will be; (M + 10)g
where M is the mass of the block.
Now, from equilibrium we know that sum of upward forces is equal to sum of downward forces. Thus;
F + F = (M + 10)g
Thus;
2F = (M + 10)g
F = ¹/₂(M + 10)g
Now, taking moments about the right end gives;
(F × 4) + (F × 2) - (M × 3.5)g - (10 × 2)g = 0
6F - 3.5Mg - 20g = 0
Put ¹/₂(M + 10)g for F to get;
6(¹/₂(M + 10)g) - 3.5Mg - 20g = 0
Divide through by g to get;
3(M + 10) - 3.5M = 20
3M + 30 - 3.5M = 20
3.5M - 3M = 30 - 20
0.5M = 10
M = 10/0.5
M = 20 kg
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Consider three identical metal spheres, A, B, and C. Sphere A carries a charge of 9q. Sphere B carries a charge of -q. Sphere C carries no net charge. Spheres A and B are touched together and then separated. Sphere C is then touched to sphere A and separated from it. Lastly, sphere C is touched to sphere B and separated from it. (a) What is the ratio of the final charge on sphere C to q
Answer:
Explanation:
A and B are touched .
charge on each of them after touching = (9q - q) / 2 = 4q
when C is touched with A
charge on A and C each after touching
= 4q + 0 / 2 = 2q
When C is touched with B
charge on each of them
(2q + 4q ) / 2 = 3 q
Final charge on C = 3q
Answer:
✔ A and D
✔ B
✔ C
Explanation: because i said so
The driver of a truck has an acceleration of 0.3 g as the truck passes over the top of a hump in the road at a constant speed. The radius of curvature of the road at the top of the road is 98 m, and the center of mass G of the driver, who can be considered a particle, is 2 m above the road. What is the speed of the truck
Answer:
17.115m/s
Explanation:
The formula that will be used to calculate the speed of the truck is expressed as shown:
v = √ar
a is the acceleration of the truck
r is the radius of curvature of the road at the top of the road plus centre of mass G who can be considered a particle, is 2 m
v = √a(R+G)
Given parameters
a = 0.3g (g is the acceleration due to gravity)
R = 98m
G = 2m
Substituting the values into the formula:
v = √0.3(9.81){98+2}
v = √0.3×9.81×100
v = √294.3
v = 17.155m/s
Hence the speed of the truck is 17.155m/s
Calculate the volume of this regular solid,
What is the volume of the sphere? Round your answer
to the nearest tenth.
cm
8 cm
Answer:
2144.7
Explanation:
Which statement describes a characteristic of an experimental design that
will improve the quality of the results?
Answer:
A.
Ok, suppose an experiment where you have a lot of dependent variables.
something like the variables y, z and k that change when you change the variable x.
Now, as you play with the variable x, you will notice changes in the variables z, y and k.
But there is now a question (a lot actually)
if the change in k was actually caused by the change in z?
Then you need to try to find a way of changing the value of z for a fixed value of x (designing an experiment) and see how k reacts.
This may be really hard, so as few responding variables you have, the simpler is the experiment, and easier will be to collect good data.
Now we also could discard the other options:
B: If the procedure is complex, then there are more ways in which the scientist can make a mistake that will introduce error to the data, so this will not improve the quality.
C: A larger sample will allow you to have more precision, as more subjects are being observed.
D: When we manipulate one variable, we may be actually introducing some quantity of error to the data.
For example, if the quantity is the voltage for an experiment, we actually do not know the exact voltage tath comes from the source, so there is a small source of error. Now as we start adding more and more independent variables, we also are adding more of these sources of errors, so an experiment with several independent variables will not improve the quality of the results.
0.000609 in scientific notation
Answer: hey!
i believe your answer is 6.09 times 10^-4
Explanation:
the exponent is negative 4 have a good day
An object of mass kg is released from rest m above the ground and allowed to fall under the influence of gravity. Assuming the force due to air resistance is proportional to the velocity of the object with proportionality constant b N-sec/m, determine the equation of motion of the object. When will the object strike the ground? Assume that the acceleration due to gravity is and let x(t) represent the distance the object has fallen in t second
Answer:
Explanation:
From, the given information: we are not given any value for the mass, the proportionality constant and the distance
Assuming that:
the mass = 5 kg and the proportionality constant = 50 kg
the distance of the mass above the ground x(t) = 1000 m
Let's recall that:
[tex]v(t) = \dfrac{mg}{b}+ (v_o - \dfrac{mg}{b})^e^{-bt/m}[/tex]
Similarly, The equation of mption:
[tex]x(t) = \dfrac{mg}{b}t+\dfrac{m}{b} (v_o - \dfrac{mg}{b}) (1-e^{-bt/m})[/tex]
replacing our assumed values:
where [tex]v_=0 \ and \ g= 9.81[/tex]
[tex]x(t) = \dfrac{5 \times 9.81}{50}t+\dfrac{5}{50} (0 - \dfrac{(5)(9.81)}{50}) (1-e^{-(50)t/5})[/tex]
[tex]x(t) = 0.981t+0.1 (0 - 0.981) (1-e^{-(10)t}) \ m[/tex]
[tex]\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}[/tex]
So, when the object hits the ground when x(t) = 1000
Then from above derived equation:
[tex]\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}[/tex]
[tex]1000= 0.981t-0.981(1-e^{-(10)t}) \ m[/tex]
By diregarding [tex]e^{-(10)t} \ m[/tex]
[tex]1000= 0.981t-0.981[/tex]
1000 + 0.981 = 0.981 t
1000.981 = 0.981 t
t = 1000.981/0.981
t = 1020.36 sec
How much work is done on a small car of a 1000 N force is exerted to move it 75 m to the side of the road?
Answer:
7500j
Explanation:
Work :
W = Fd (work = force x distance)
Force :
F = W/d
Distance :
d = W/F
A car is traveling 16 m/s East. If the car then speeds up at a constant acceleration, what is the direction of the car’s acceleration?
1.How far is Object Z from the origin at t = 3 seconds?
2.Which object takes the least time to reach a position 4 meters from the origin?
3.Which object is farthest from the origin at t = 2 seconds?
Show work
Answer:
Please find the answer in the explanation
Explanation:
1.) How far is Object Z from the origin at t = 3 seconds
The distance of the object Z from the origin will be the slope of the graph.
Slope = 4/2 = 2m
2.) Which object takes the least time to reach a position 4 meters from the origin ?
According to the graph given to the question above, object Z has the list time which is 2 seconds since object X does not start from the origin.
3.) Which object is farthest from the origin at t = 2 seconds?
The correct answer is still object Z because it has the highest slope.
