2 ft
4.5 ft
6 ft
A) 38 cubic feet
B) 54 cubic feet
C)
66 cubic feet
D) 125 cubic feet
What is the volume?

Answers

Answer 1

Answer:

B

Step-by-step explanation:We know Volume = (a*b*c)

Answer 2

Answer:

B) 54 cubic feet

Step-by-step explanation:


Related Questions

what is the first shape

Answers

Answer:

The first type of solid shapes to be discovered are known as Platonic solids, which include the cube, the tetrahedron, the octahedron, the dodecahedron, and the icosahedron

Expert Mathematicians, please help!

Answers

Answer:

Two functions which satisfies the H(x) are f(x) = 2x - 4, (x)    = x⁵  and

f(x)  = 2x,  g(x)  = x⁵ - 2

Step-by-step explanation:

The given question is based on the decomposition of a given function into two functions

Decomposition of a function :- functional decomposition is the process of resolving a functional relationship into its constituent parts in such a way that the original function can be reconstructed from those parts by function composition

so the function given in the question is H(x) = 2x⁵ - 4

now by using the concept of decomposition of a function we can find two functions f and g

therefore,

f(x) = 2x - 4

and    g(x)    = x⁵

similarly we can find another pair which satisfies the function H(x)

f(x)  = 2x

and g(x)  = x⁵ - 2

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Hamish and Harry work as plumbers. harry earns a dollar more than 5/4 the amount Hamish earns per hour. the amount Harry earns per hour is 2$ less than 7/5 the amount Hamish earns per hour. how much to both of them earn per hour? ​

Answers

Answer:

Hamish earns $20 per hour, and Harry earns $26 per hour.

Step-by-step explanation:

Harry earns

$1+(5/4)•x and also (7/5)•x-$2

$1+(5/4)•x = (7/5)•x-$2

$1+$2= (7/5)•x-(5/4)•x

3=(7•4•x-5•5•x)/20

3=3x/20

3•20=3x

X=20, Hamish earns $20

Substitute x in one of the expressions

1+(5/4)•20=1+25=26, Harry earns $26

A rake is priced at $28.49. Tax is $1.85. What is
the total cost of the rake?

Answers

28.49+1.85 =30.34 is the correct answer

how much would $500 invested at 3% interest compounded continuously be worth after 6 years? Round your answer to the nearest cent. Use 2.718 for e. A(t)=Pe^(rt)

Answers

You are given the equation

A(t) = P*e^(rt)

Where P = Principal

r = interest rate

t = time

e is a mathematical constant equivalent to approx 2.71828

You're told the initial Principal is $500, the interest rate is 3%, over 6 years. So you have everything that you need to solve the problem, just plug in the values and solve for A(6)

A(t) = P*e^(rt)

A(6) = 500 * e^(0.03 * 6)

A(6) = 500 * e^(0.18)

A(6) = 500 * 2.71828^(0.18)

A(6) = 500 * 1.19721

A(6) = 598.60861

So $500 invested 6 years ago at 3% would be worth $598.61 today.

what is −4/5​+40/75​+100%=

Answers

-0.8+1.875+100%

1.05+100%

0.1

Which of the following statements is true?

Answers

Answer:

B

Step-by-step explanation:

1/9 can be simplified to 1/3 as 1/3 x 1/3 = 1/9  and 49/25 can be simplified to 7/5 as 7/5 x 7/5 = 49/25.

Now looking at both the fraction 1/3 and 7/5

1/3 simplifies to 0.34

It is an irrational value as the 3 keeps repeating.

7/5 simplifies to 1.4

It is a rational value as the decimal value is not repeating.

Thus making the second option the answer.

528 a weekend.
10% of 480 is 48
480 + 48 = 528

Answers

Answer:

ffhjjrhjzxuzdjzdjzsjezjdifi

What is the perimeter in units ?

Answers

Answer:

12 + [tex]4\sqrt{5}[/tex] approximates to 20.944

Step-by-step explanation:

VU - 8 units

UW - 4 units

VW - [tex]\sqrt{64+16} = \sqrt{80} =4\sqrt{5}[/tex]

12 + 4sqrt(5)

Answer:

6 (2 + √5) units

Step-by-step explanation:

Finding the length of the 3rd side :

*Applying Pythagorean Theorem*

VW² = 4² + 8²VW² = 16 + 64VW = √80VW = 6√5

The perimeter :

4 + 8 + 6√512 + 6√56 (2 + √5) units

If y = 2x-3, then which of the following ordered pairs lies on the graph?
O (-3,0)
O (1,-1)
O (5,4)

Answers

Plug in the points and see if they satisfy the equation.

y = 2x - 3

(1, -1)

-1 = 2(1) - 3

-1 = 2 - 3

-1 = -1

So (1, -1) satisfies the equation.

(-3, 0)

0 = 2(-3) - 3

0 = -6 - 3

0 = -9

So (-3, 0) does not satisfy the equation.

(5, 4)

4 = 2(5) - 3

4 = 10 - 3

4 = 7

So (5, 4) does not satisfy the equation.

Therefore your answer is (1, -1).

Answer:

the answer is 5,4

I WILL GIVE BRAINLIEST
Which is true of dependent events?
ANSWER CHOICES:
The probability of all dependent events can be calculated using the OR formula P(A+B) =P(A) +P(B)-P(A and B) .

You can use a two-way frequency table to calculate the conditional probability of events that are dependent.

You can find the AND probability of dependent events using the formula P(A or B)= P(A) times P(B) .

The outcome of one event has no effect on the outcome of a second event.

Answers

Probability helps us to know the chances of an event occurring. The correct option is A.

What is Probability?

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

Dependent events are those events in which the outcome of the first event affects the outcome of the second event. The statement that is correct about the dependent event is that the probability of all dependent events can be calculated using the "OR" formula P(A+B) =P(A) +P(B)-P(A and B).

Hence, the correct option is A.

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I WILL GIVE BRAINLIEST
PLEASE LOOK AT PICTURE
What are the foci of this ellipse?

ANSWER CHOICES: are in picture

Answers

The foci of the ellipse lie on the major axis of the ellipse and are equidistant from the origin.

Integration by Parts Evaluate e-2x cos(2x) dx.​

Answers

Let

[tex]I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]tex

Integrate by parts:

[tex]\displaystyle \int u \, dv = uv - \int v \, du[/tex]

with

[tex]u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)[/tex]

Then

[tex]\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C[/tex]

Integrate by parts again, this time with

[tex]u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)[/tex]

so that

[tex]\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}[/tex]

On Sunday, a local hamburger shop sold a combined total of 512 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Sunday?

Answers

Answer:

512? xd

Step-by-step explanation:

Answer:

128

Step-1by-step explanation:

An easy way of solving these sort of problems is to set up an equation

Since we have a total, that being 512 burgers, we can set an equation equal to that number.

We can say that hamburgers is represented by x. Since we sold 3 times more cheeseburgers than the amount of hamburgers, we can represent this as 3x.

Since these totals are combined, we can represent this via an equation:

512 = x + 3x

Solve for x accordingly, and we are given 128, which is equal to the amount of hamburgers.

Determine the equation of the tangent line in both cases


1. x^2/x+2 at (2,1)


2. x^3+2y^2=10y at (2,1)

Answers

Differentiate the function/equation with respect to x and solve for the derivative, dy/dx. The value of dy/dx at the given point is the slope of the tangent line to the curve at that point. Then use the point-slope formula to get the equation of the tangent.

1.

[tex]y = \dfrac{x^2}{x+2} \implies \dfrac{dy}{dx} = \dfrac{2x\times(x+2) - x\times1}{(x+2)^2} = \dfrac{x(x+4)}{(x+2)^2}[/tex]

When x = 2, the derivative is

[tex]\dfrac{dy}{dx}\bigg|_{x=2} = \dfrac{2(2+4)}{(2+2)^2} = \dfrac34[/tex]

Then the equation of the tangent line at (2, 1) is

[tex]y - 1 = \dfrac34 (x - 2) \implies \boxed{y = \dfrac{3x}4 - \dfrac12}[/tex]

2.

[tex]x^3 + 2y^2 = 10y \implies 3x^2 + 4y \dfrac{dy}{dx} = 10 \dfrac{dy}{dx} \implies \dfrac{dy}{dx} = \dfrac{3x^2}{10-4y}[/tex]

When x = 2 and y = 1, the derivative is

[tex]\dfrac{dy}{dx}\bigg|_{(x,y)=(2,1)} = \dfrac{3\times2^2}{10-4\times1} = 2[/tex]

Then the tangent at (2, 1) has equation

[tex]y - 1 = 2 (x - 2) \implies \boxed{y = 2x - 3}[/tex]

in need of assistance

Answers

Answer:

60

Step-by-step explanation:

_---&$'_-4$':/-&$$--(:'##4--&&4___&$$_666&4&&&&&

Answer: 489.8 in

Step-by-Step Explanation:

Diameter (d) = 26 in
Radius (r) = 26/2 = 13 in

No. Of Revolutions = 6

We know, that the length around the tire is nothing but the perimeter of the tire.

Perimeter = 2πr

Therefore,
= 2πr
= 2 * π * r
= 2 * 3.14 * 13
= 6.28 * 13
=> 81.64

Perimeter = 81.64 in

Distance Travelled after 6 Revolutions of the Tire = Perimeter * 6

Therefore,
= 81.64 * 6
=> 489.8

Distance Travelled after 6 Revolutions of the Tire = 489.8 in

Use a calculator to graph the functions y=-3x-21 and y=x³-3x-3. How many points of intersection do the
functions share?
0
1
2
3

Answers

Answer:

1

Step-by-step explanation:

When you graph the functions they intersect at one point

(-3.368119, -31.10436)

Raul's pet store has a play area that can fit up to 30 cats and dogs. His son is allergic to cats so the pet store never has more than 8 cats in the play areas.

How many of each type of pet can they have at the
pet store?
Write a system of inequalities.

Answers

Answer:

Step-by-step explanation:

Let :

C = number of cats

D = number of dogs

Raul's pet store has a play area that can fit up to 30 cats and dogs.

C + D = 30

The pet store never has more than 8 cats in the play areas.

C < 9

(there can never be 9 or more cats)

As or the number of dogs :

C + D = 30

C = 30 - D

Since we know that C < 9. To get the number of dogs allowed, we just plug in 30 - D for C.

30 - D < 9

30 - 9 < D

or

D > 21

(dogs have to be 22 or more)

How many yards are in 1 mile 60 feet?

Answers

The answer for how many yards are in 1 mile 60 feet is 1780

Answer:

1780

Step-by-step explanation:

multiply the length value by 1760

and then divide the length value by 3

work hours

frequency

0 - <10

45

10 - <20

33

20 - <30

20

30 - <40

7

40 - <50

8

Use your calculator to find the mean and standard deviation

Answers

The mean and the standard deviation are 16.15 and 12.03, respectively

How to determine the mean and the standard deviation?

The table of values is given as:

Work hours           Frequency

0 - <10                        45

10 - <20                      33

20 - <30                     20

30 - <40                       7

40 - <50                      8

Start by rewriting the table using the midpoint of each class

x      f

5     45

15    33

25    20

35    7

45    8

The mean is then calculated as:

[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]

This gives

[tex]\bar x = \frac{5 * 45 + 15 * 33 + 25 * 20 35 * 7 + 45 * 8}{45 + 33 + 20 + 7 + 8}[/tex]

Evaluate the sum and the products

[tex]\bar x = \frac{1825}{113}[/tex]

Divide

[tex]\bar x = 16.15[/tex]

The standard deviation is:

[tex]\sigma =\sqrt{\frac{\sum f(x - \bar x)^2}{\sum f}}[/tex]

This gives

[tex]\sigma= \sqrt{\frac{45 * (5 - 16.15)^2 + 33 * (15 - 16.15)^2 + 20 * (25 - 16.15)^2 + 7 * (35 - 16.15)^2 + 8 * (45 - 16.15)^2 }{45 + 33 + 20 + 7 + 8}}[/tex]

Evaluate the sum and the products

[tex]\sigma= \sqrt{\frac{16350.4425}{113}}[/tex]

Divide

[tex]\sigma= \sqrt{144.694181416}[/tex]

Take the square root

[tex]\sigma= 12.03[/tex]

Hence, the mean and the standard deviation are 16.15 and 12.03, respectively

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PLEASE HELP!!!!!!!!!

Answers

Answer:

correct answer is B.

Step-by-step explanation:

for more information see the attachment.

Answer:

no 2/B is the correct answer

find the indicated side of the right triangle

Answers

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:x = 3\sqrt3 [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: \tan(60) = \cfrac{x}{3} [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{3} = \dfrac{x}{3} [/tex]

[tex]\qquad \tt \rightarrow \: x = 3 \sqrt{3} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

This is from Khan academy I have to attach a PNG if you can help me solve it! Thank you!

Answers

Step-by-step explanation:

[tex] \frac{5 {}^{ - 4x + 7} }{125 {}^{x} } [/tex]

[tex] \frac{5 {}^{ - 4x + 7} }{5 {}^{3x} } [/tex]

[tex]5 {}^{ - 4x + 7 - 3x} [/tex]

[tex]5 {}^{ - 7x + 7} [/tex]

Find the value of c that makes the expression a perfect square trinomial. x2 + 9 4 x + c
A) 9/16
B) 9/64
C) 81/16
D) 81/64

Answers

The value of c is 81/64 for the expression a perfect square trinomial.

What is an Expression?

An expression can be defined as a mathematical statement that consists of variables, constants and mathematical operators simultaneously.

It is given that an expression

x² +9/4x +c is a perfect square polynomial

c =?

(a+b)² = a² +2ab+b²

2ab = 9/4

b = 9/8

c = b² = 81/64

Therefore the value of c is 81/64 for the expression a perfect square trinomial.

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the data below shows the number of workers employed in the various section s of each a construction company in the Lagos

Carpenter 24
plumber 12
labourers 27
plasterers 15
painters 9
Messengers 3
bricklayers 18

if the Worker is retrenched, what is the probability that he is a plumber or a plasterer?​

Answers

If the Worker is retrenched, the probability that he is a plumber or a plasterer will be  0.0152.

What is probability?

The chances of an event occurring are defined by probability. Probability has several uses in games, in business to create probability-based forecasts,

The probability that the employee is a plumber;

[tex]\rm P(plumber)= \frac{No \ of \ plumber}{Total \ number \ of \ employ} \\\\ P(plumber)=\frac{12}{108} \\\\\ P(plumber)= 0.11[/tex]

The probability that the employee is a plasterer;

[tex]\rm P(plasterers )= \frac{No \ of \ plasterers }{Total \ number \ of \ employ} \\\\ P(plasterers )=\frac{15}{108} \\\\\ P(plasterers )= 0.13[/tex]

The probability that he is a plumber or a plasterer:

P = 0.13 × 0.11

P= 0.0152

Hence, if the worker is retrenched, the probability that he is a plumber or a plasterer will be  0.0152.

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The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative 5, 0), has a vertex at (negative 2, 9), and goes through (1, 0). Which statement about the function is true? The domain of the function is all real numbers less than or equal to −2. The domain of the function is all real numbers less than or equal to 9. The range of the function is all real numbers less than or equal to −2. The range of the function is all real numbers less than or equal to 9.

Answers

The true statement is:

"The range of the function is all real numbers less than or equal to 9."

Which statements are true?

Here we have the quadratic function:

[tex]f(x) = -x^2 - 4x + 5[/tex]

And we want to see which of the given statements are true.

The first one is:

"The domain is al real numbers less than or equal to -2"

This is false, for all quadratic functions the domain is the set of all real numbers (unless the domain is defined).

The second statement is:

" The domain of the function is all real numbers less than or equal to 9."

Also false

Third one:

" The range of the function is all real numbers less than or equal to −2"

The range of a quadratic function with a negative leading coefficient will be the set of all the values smaller than the y-value of the vertex.

In this case, the quadratic function is:

[tex]f(x) = -x^2 - 4x + 5[/tex]

So the vertex is at:

[tex]x = 4/(2*-1) = -2\\[/tex]

Then the y-value of the vertex is:

[tex]f(-2) = -(-2)^2 - 4*(-2) + 5 = -4 + 8 + 5 = 9[/tex]

So the range is the set of all real numbers less than or equal to 9.

So the above statement is false, and the final one:

"The range of the function is all real numbers less than or equal to 9."

Is the true statement.

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Superman needs to save lois from the clutches of lex luthor. It take superman 5 seconds to get to Lois who is 210 feet away. What is supermans rate?

Answers

Answer:

42 ft/s

Step-by-step explanation:

if superman travels 210 feet in 5 seconds, he will travel a fifth of 210 ft in 1 second

a fifth of 210ft is 210/5=42

hence 42ft/s is his rate.


The difference between two numbers is -1 and their sum is 1. Find the two numbers.

Answers

Answer:

Let the no. be X and Y

X - Y = (-1)

X + Y = 1

X = (-1)+ Y

X = 1 - y

- 1.+ y = 1 - y

Y + Y = 1 + 1

2y = 2

Y = 1

X = 0

Answer:

x = 0 (first number), y = 1 (second number)

Step-by-step explanation:

x will represent the first number, and y will represent the second.

x - y = -1

x + y = 1

Now, it's time to get y by itself in one equation so that we can substitute.

x - y = -1 (subtract x from both sides)

-y = -1 - x (multiply both sides by -1)

y = x + 1

Plug in x + 1 for y in the second equation.

x + x + 1 = 1 (combine the x with the x)

2x + 1 = 1 (subtract 1 from both sides)

2x = 0 (divide both sides by 2)

x = 0

Since x = 0, we can plug 0 in for x into any equation to solve for y.

0 + y = 1

y = 1

Brainliest, please :)

need help with this please

Answers

The values of x and y at t=3 are -4.95 and 0.423 respectively.

The value of dx/dt and dy/dt are 0.71 and -2.97 respectively.

The value of the tangent slope at t=3 is 4.21.

The speed at t=3 is 3.05 units/sec.

Given the equation of x as the function of t is

x= 5 cos t

similarly, the equation of y as the function of t is

y= 3 sin t

At t=3 the value of x will be

x (at t=3) = 5 cos 3= 5(-0.989)= -4.95

At t=3 the value of y will be

y (at t=3) = 3 sin 3= 3(0.141)= 0.423

The derivative of the function of x with respect to t will be

dx/dt= d(5 cos t)/dt= 5d(cos t)/dt= -5 sin t

at t=3 the value of dx/dt will be

dx/dt (at t=3) = -5 sin 3= -5(0.141)= 0.71

The derivative of the function of y with respect to t will be

dy/dt= d(3 sin t)/dt= 3d(sin t)/dt= 3 cos t

at t=3 the value of dy/dt will be

dy/dt (at t=3) = 3 cos t= 3(-0.989)= -2.97

The tangent slope is dy/dx which can be calculated by

dy/dx= (dy/dt)(dt/dx)= (dy/dt)/(dx/dt)= 3 cos t/ -5 sin t=  (-3/5) cot t

at t=3 the value of tangent slope will be

dy/dx (at t=3) = (-3/5) cot 3= 4.21

The speed at t=3 will be

speed v= [tex]\sqrt{v_{x} ^{2} + v_{y} ^{2} }[/tex]

= √(dx/dt)²+(dy/dt)²

at t=3

= √(0.71)²+(-2.97)²

= √9.325

= 3.05 unit/sec

Therefore the values of x and y at t=3 are -4.95 and 0.423 respectively.

The value of dx/dt and dy/dt are 0.71 and -2.97 respectively.

The value of the tangent slope at t=3 is 4.21.

The speed at t=3 is 3.05 units/sec.

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Dr. Hick writes an order for Amoxicillian 300 mg by mouth daily. Pharmacy dispenses 200 mg/2 mL. How many mL per dose?

a. 4
b. 3
c. 2
d. 1

Answers

Answer:

b

Step-by-step explanation:

2 ml/200 mg so divide and you get 1 ml per 100 mg then multiply that my 3 to get 3ml/300 mg therefore the answer is b

Answer:

b. 3 ml

Step-by-step explanation:

300 mg  / 200 mg/ 2 ml   =   300 * 2  / 200 ml = 3 ml

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