22. On a day the wind is blowing toward the south at 3m/s, a runner jogs west at 4m/s. What is the velocity of the air relative to the runner?

The gauge pressure at bottom of vaccine solution will be 16 kPa

Positive pressure is another name for gauge pressure. When a system's internal pressure exceeds that of its surroundings, it is said to be under positive pressure. Any leak that develops in the positively pressured system will therefore escape into the outside world. In contrast, a negative pressure chamber draws air into it.

Given As seen in the illustration, a syringe is held vertically. The container carries a 3 cm tall column of vaccine solution and has an open inner diameter of 1 cm. The needle contains a 2 cm column of vaccine solution and has an open inner diameter of 0.5 mm. At the needle's open end, the solution is exposed to the air. The vaccination solution has a density of 1200 kg/m3.

We have to find the gauge pressure at bottom of vaccine solution

Since the 5N force is applied to vaccine solution the pressure exerted will be much more

Hence the gauge pressure at bottom of vaccine solution will be 16 kPa

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The statement best describes how upwelling occurs is Upwelling causes nutrients, minerals, and tiny organisms to rise. The correct option is C.

Upwelling occurs when winds push surface water away from the shore and deeper water rises to fill the gap.

The upwelling is a cycle that shows up in the water bodies all over the planet. This cycle is basically addressing the ascending of the virus waters towards the surface where there's hotter environment, subsequently hotter water also.

With the ascent of the virus waters towards the surface, everything with it ascend also. The virus waters are plentiful in supplements and minerals, as well as minuscule creatures, like the Phyto-microscopic fishes.

This is a cycle that is vital for the presence of the environments in the bigger water bodies.

Thus, the correct option is C.

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Answer:

A venturi meter is used to measure the flow speed of a fluid in a pipe. The meter is connected between two sections of the pipe (the figure); the cross-sectional area A of the entrance and exit of the meter matches the pipe's cross-sectional area. Between the entrance and exit, the fluid flows from the pipe with speed V and then through a narrow ''throat'' of cross-sectional area a with speed v. A manometer connects the wider portion of the meter to the narrower portion. The change in the fluid's speed is accompanied by a change Δp in the fluid's pressure, which causes a height difference h of the liquid in the two arms of the manometer. (Here Δp means pressure in the throat minus pressure in the pipe.) Let A equal 5·a. Suppose the pressure p1 at A is 2.1 atm.

Compute the values of (a) the speed V at A and (b) the speed v at a that make the pressure p2 at a equal to zero.

(c) Compute the corresponding volume flow rate if the diameter at A is 4.0 cm.The phenomenon that occurs at a when p2 falls to nearly zero is known as cavitation. Please assume that the fluid is water. The water vaporizes into small bubbles.

The type of power plant burns material to make electricity is Fossil fuel. The correct option is C.

Energy is the ability to do work.

There are different kind of energies like kinetic energy, potential energy, gravitational energy and  heat energy.

The energy obtained from burning different type of materials like Coal, gas and oil and produces heat.

Fossil fuel power plants burn coal or oil to create heat and generate steam to run turbines which generate electricity.

Thus, the correct option is C.

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Answer:

Explanation:

There are different ways to investigate the factors that affect resistance. In this practical activity, it is important to:record the length of the wire accuratelymeasure and observe the potential difference and currentuse appropriate apparatus and methods to measure current and potential difference to work out the resistance

With the help of a transformer  input voltage is transformed into an output voltage

​

Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.

In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.

Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.

The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.

Hence with the help of a transformer input voltage is transformed into an output voltage.

​

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The radius of a helium atom 4.8 times bigger  then the radius of an alpha particle.

The structure of alpha particles, also known as alpha rays and alpha radiation, is similar to that of the helium-4 nucleus and has been made up of two protons as well as two neutrons bonded together.

For welding metals like aluminum, helium was utilized as an inert gas environment. It is also employed in rocket propulsion.

The radius of a helium atom 4.8 times bigger  then the radius of an alpha particle. More precisely than it's ever been, the diameter of the helium atom's nucleus, the alpha particle, had also been measured. Outcomes just point to a size of 1.6782 femtometers, 4.8 times more accurate than earlier readings.

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(a)The value of W for the given condition will be 237.3 N.

(b)The distance must the fulcrum be moved to restore balance will be 0.070 m.

A location is established in relation to an object or set of objects in the center of mass. It is the system's average position across all of its components.

Given data;

Weight is applied to the right end of the rod, W₁= 225 N

Rod's weight,W₂ = 255

W₃ is the Weight at "x" distance from the left end.

x1  is the location of W₁ with respect to the left end, where L = 1.80 m

m is the location of the rod's center of mass from the left end.

The position of W from the left end; x₃ = 50 cm = 0.50 m

Xcm is the position of the center of gravity of the rod at the fulcrum from the left end;

Given that the fulcrum is balanced in this situation, the rod's center of gravity will be there.

Xcm= L - 75 cm

Xcm=1.80 m - 0.75 m

Xcm= 1.05 m

The value of x₂

x₂= 1.80 m/2 = 0.90 m

Currently, the horizontal center of gravity is determined by

[tex]\rm X_{cm} =\frac{ (W_1x_1 + W_2x_2 + W_3*x_3)}{(W_1 + W_2 + W_3)}[/tex]

Substitute the values we get;

[tex]\rm 1.05 = \fraca{ (225 \times 1.80 + 255\times 0.90 + W\times 0.50)}{(225 + 255 + W)}\\\\ W = \frac{ (225\times 1.80 + 255\times 0.90 - 480 \times 1.05)}{(1.05 - 0.50)}\\\\ W = 237.3 \ N[/tex]

After moving the fulcrum 20.0 cm to the right,

The location of the W from the left end;

x₃ = .50 cm + 20 cm

x₃  = 70 cm

x₃  = 0.70 m

W₁, W₂, W, x₁, and x₂ have fixed values. Therefore, based on these values, the new center of gravity will be:

[tex]\rm X_{cm} =\frac{ (W_1x_1 + W_2x_2 + W_3*x_3)}{(W_1 + W_2 + W_3)}[/tex]

[tex]\rm X_{cm} = \frac{(225\times 1.80 + 255\times 0.90 + 237.3\times 0.70)}{(225 + 255 + 237.3)}\\\\ X_{cm} = 1.12 m[/tex]

Fulcrum must be shifted by;

Y = (1.12 - 1.05)

Y= 0.070 meters.

W has been moved in the appropriate direction, thus the fulcrum should likewise be moved in the appropriate direction.

Hence, the value of W for the given condition will be 237.3 N. and the distance must the fulcrum be moved to restore balance will be 0.070 m.

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The initial speed v,  the mass m should be given at the bottom, so that the string reaches a maximum angle is  2.16 m/s.

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

Given is a small mass of m = 187 g hangs from a string of length l = 1.21 m. The string reaches a maximum angle of θ = 36.5.  The acceleration due to gravity, g = 9.8 m/s²

The vertical height of the point mass h = l- lcosθ

h = 1.21 - (1.21cos 36.5°)

h = 0.2373 m

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

Kinetic energy  = Potential energy

1/2 mv²= mgh

Substituting the values, we have

1/2 x v² = 9.8 x  0.2373

v = sqrt [2 x9.8 x  0.2373]

v= 2.16 m/s

Thus, the initial speed v the mass m should be given at the bottom, so that the string reaches a maximum angle is 2.16 m/s.

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The corresponding downward force on the top of a horizontal square is 375 lb.in

The pressure is the amount of force applied per unit area. It is represented as

Pressure p = Force/Area

If the atmospheric pressure is 15 lb/in and  area 5 inches on each side is

A = 5² = 25  in²

The force applied is

15 lb/in = F /25 in²

F = 375 lb.in

Hence, the corresponding downward force on the top of a horizontal square is 375 lb.in

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Answer:

D. s=3x+4y

Explanation:

The line is at the 3rd column in the 4th row.

The charge on each sphere is 742 n

In physics, Charge, also known as electric charge is a electrical charge, or electrostatic charge and symbolized q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.

According to the question,

Distance = 15cm or 0.15m

Force =  0.22N

[tex]K=9*10^{9} kgm^2/c^2[/tex] ( this is a constant value of K)

By using the formula,

F = [tex]\frac{kQq}{d^{2} }[/tex]

0.220 N = 8.99

N·m²/C² * Q² / (0.15m)²

Q = 7.42e-7

C = 742 n

C is the charge of each sphere .

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Answer:

CSP

Explanation:

CSP systems store energy through Thermal Energy Storage technologies (TES), so power can be used when there isn't enough sunlight. PV systems, however, can't store thermal energy because they use direct sunlight, rather than heat. For this reason, CSP systems are better for energy storage and efficiency.

Answer:

enable us to take in a wide variety of information, and process it based on our past experience and values.

Explanation:

Answer:

28

Explanation:

Or from this equation, when we can write the magnification of talents is F times F plus the object distance knowledge, substitute the value to find out the magnification and that equals minus 54 centimeters Over -54 minus 26 centimeters. And we got the magnification of the image produced by The lens is 0.675.

The final speed of the nickel at the given quantity of heat is determined as 202.1  m/s.

Apply the principle of conservation of energy.

Q = mcΔθ

Q = (18)(0.444)(66 - 20)

Q = 367.63 J

Q = K.E = ¹/₂mv²

2K.E = mv²

v = √(2K.E/m)

where;

v = √(2 x 367.63)/(0.018))

v = 202.1 m/s

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Answer:

1.1299 x 10^-8   second    

Explanation:

Period = 1 / f = 1 / (8.85 * 10^7) = 1.1299 x 01^-8  sec

Answer:

(D)6 times

Explanation:

Hello !

Because when we see the equation of momentum P=mv, where p=momentum

m=mass of the object&

v=velocity of the object

And, p is directly propositional to both mass and velocity.

Thus, p=mv

Therefore, we can conclude by when the mass is tripled and the velocity is doubled the momentum is increased by 6 units.

The time for which the baseball remains in the air will be 9.37 sec. Option C is correct.

It is the height achieved by the body when a body is thrown at the same angle and the body is attaining the projectile motion.

From Newton's first equation of motion;

[tex]\rm v_y= u_y+gt \\\\ 0 = usin \theta - gt \\\\ t = \frac{u sin\theta }{g}\\\\t = 4.68 \ sec[/tex]

The time the baseball remains in the air will be twice the time he travels for one side motion;

T' = 2t

T'=2 × 4.68 sec

T'= 9.37 sec

Hence for 9.37 sec, the baseball willl remains in the air. Option C is correct.

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Answer:

Approximately [tex]3.14\; {\rm rad \cdot s^{-1}}[/tex].

Explanation:

Fact: the angular velocity [tex]\omega[/tex] of a simple harmonic oscillator is the ratio between the maximum velocity [tex]v_{\text{max}}[/tex] and the maximum displacement [tex]x_\text{max}[/tex] of this oscillator. In other words:

[tex]\begin{aligned} \omega &= \frac{v_{\text{max}}}{x_{\text{max}}}\end{aligned}[/tex].

Derivation of the previous equation:

Let [tex]A[/tex] denote the amplitude of this oscillation, and let [tex]\omega[/tex] denote the angular velocity.

The displacement of the oscillator at time [tex]t[/tex] would be:

[tex]x(t) = A\, \sin(\omega\, t)[/tex].

The maximum displacement of this oscillator would be [tex]x_\text{max} = A[/tex].

The velocity of this oscillator at time [tex]t[/tex] is the derivative of displacement with respect to time:

[tex]\begin{aligned} v(t) &= \frac{d}{d t}\, [x(t)] \\ &= \frac{d}{d t} [A\, \sin(\omega\, t)] \\ &= A\, \omega\, \cos(\omega\, t)\end{aligned}[/tex].

The maximum velocity of this oscillator would be [tex]v_\text{max} = A\, \omega[/tex].

Notice that dividing [tex]v_\text{max} = A\, \omega[/tex] by [tex]x_\text{max} = A[/tex] would give:

[tex]\displaystyle \frac{v_\text{max}}{x_\text{max}} = \frac{A\, \omega}{A} = \omega[/tex].

It is given that [tex]v_\text{max} = 2.76\; {\rm m\cdot s^{-1}}[/tex] while [tex]x_\text{max} = 0.0880\; {\rm m}[/tex]. Therefore:

[tex]\begin{aligned} \omega &= \frac{v_{\text{max}}}{x_{\text{max}}} \\ &= \frac{2.76\; {\rm m\cdot s^{-1}}}{0.0880\; {\rm m}} \\ &\approx 3.14\; {\rm s^{-1}}\end{aligned}[/tex].

(Radians per second.)

If Ross takes two months off from training, his fitness level will reduce in comparison to what it was two months ago.

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It then can be stated:

[tex]\large\red\hookrightarrow \rm \large \: \:X_m \: = \: \frac{X_1 \: + \: \: X_2 }{2} \: \: \: \: \: \: \: \:... (1) \\ [/tex]

[tex]\large\red\hookrightarrow \rm \large \: \:Y_m \: = \: \frac{Y_1 \: + \: \: Y_2 }{2} \: \: \: \: \: \: \: \:... (2)\\ [/tex]

Since, Xm = -1 and X1 = 1 we can write equation (1) as

[tex]\large\purple\longrightarrow \rm \large \: \:-1 \: = \: \frac{1 \: + \: \: X_2 }{2} \: \: \: \: \: \: \: \:... (1) \\ [/tex]

[tex]\large\purple\longrightarrow \rm \large \: \:-2 \: = \:1 \: + \: X_2[/tex]

[tex]\large\purple\longrightarrow \rm \large \: \: - 2 \: - 1 \: = \: X_2[/tex]

[tex]\large\purple\longrightarrow \rm \large \: \: - 3 \: = \: X_2[/tex]

Since , Ym = 4 and Y1 = 2 we can write the equation (2) as

[tex]\large\purple\longrightarrow \rm \large \: \:4 \: = \: \frac{2 \: + \: \: Y_2 }{2} \: \: \: \: \: \: \: \:... (2)\\ [/tex]

[tex]\large\purple\longrightarrow \rm \large \: \:8 \: = \: 2 \: + \: Y_2[/tex]

[tex]\large\purple\longrightarrow \rm \large \: \:8 \: - \: 2 \: = \: Y_2[/tex]

[tex]\large\purple\longrightarrow \rm \large \: \:6 \: = \: Y_2[/tex]

Therefore the other endpoint of the line (X2, Y2) is (-3 , 6)

Answer:

F = G M m / R^2        gravitational force on satellite of mass m

Fma / Fmb = (ma / Ra^2) \ (mb / Rb^2) = (ma / mb) * (Rb / Ra)^2

Fma / Fmb = 1 * 4 = 4

The force on A is 4 times the force on B

Answer:

50J

Explanation:

Work done=Fd

=5×10

=50J

The total time the ball is in the air is 1.47 s and the maximum horizontal distance covered is 58.7 m.

The time of motion of the ball is calculated as follows;

h = vt + ¹/₂gt²

55 = (50sin37)t + ¹/₂(9.8)t²

55 = 30.1t + 4.9t²

4.9t² + 30.1t - 55 = 0

Solve using formula method;

t = 1.47 s

X = vxt

where;

X = (50 x cos37) x 1.47

X = 58.7 m

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The work done by the force is 7. 89 * 10^8 Joules and the magnitude of the force is 3. 3* 10 ^7 Newton

a. Work done = force * change in velocity = Impulse

Note that:

Force = mg

mass = 3.8x 104 kg

g = 10m/s²

Substitute into the formula for force

Force = 3.8* 10^4 * 10= 3.8* 10^5 Newton

Change in velocity = 6700 - 4600 = 2100 m/s

Work done = force *change in velocity

Work done =  3.8* 10^5 * 2100

Work done =  7. 89 * 10^8 Joules

b. Magnitude of the force = work done ÷ distance

Force = [tex]\frac{7. 89 * 10^8 }{2.4* 10}[/tex]

Force = 3. 3* 10 ^7 Newton

Therefore, the work done by the force is 7. 89 * 10^8 Joules and the magnitude of the force is 3. 3* 10 ^7 Newton

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Evidence might be used to demonstrate their falsity. must apply to all potential solutions to a scientific topic.Option A is correct.

A scientific hypothesis is the main element in the scientific method and experiment.

It is said that a hypothesis is a scientific hypothesis. The majority must agree on it, or it must be done after thorough experimentation.

Only scientific inquiries can have their answers provided by scientific endeavor. Scientific concerns have an impact on the research's design as well.

Evidence might be used to demonstrate their falsity. must apply to all potential solutions to a scientific question.

Hence option A is correct.

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If the displacement is tripled then the spring force also is tripled.

The amount of force required to stretch or compress the spring is known as the spring force. Its unit is Newton(N).

Froom the hooks law;

F = kx

Where,

F is the applied force

x is the displacement in case 1

Case 2;

x'=3x

F'=kx'

F'=3KX

F'=3x'

Where,

x' is the displacement when the force is tripled

F' is the force in the case2

Hence, if the displacement is tripled then the spring force also be tripled.

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Answer:

it alters the rate of chemical reaction

hope it is useful