23. A hydraulic (water power) press consists of 1 cm and 5 cm diameter pistons. (a) What force must be applied on the small piston so that the large piston will be able to raise 10 N load? (b) To what height would the load be raised when the small piston has moved 0.1 m?​

Answers

Answer 1

a. The force required on the small piston to raise a 10 N load on the large piston is 0.403 N.

b.  The load would be raised to a height of 63.13 cm when the small piston has moved 0.1 m.

How to calculate?

The formula is F1 / F2 = A2 / A1

where F1 is the force applied on the small piston, F2 is the force exerted on the large piston, A1 is the area of the small piston, and A2 is the area of the large piston.

A1 = (π / 4) * (1 cm)^2 = 0.0079 cm^2

A2 = (π / 4) * (5 cm)^2 = 0.196 cm^2

F1 / F2 = 0.0079 cm^2 / 0.196 cm^2 = 0.0403

F2 = 10 N

F1 = F2 * (A1 / A2) = 10 N * 0.0403 = 0.403 N

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Related Questions

how many times more light can a telescope with a diameter of 17 inches gather compared to one that has a diameter of 3 inches?

Answers

Answer:

The telescope with a 17-inch diameter can gather more than 60 times more light than the one with a 3-inch diameter.

Explanation:

28. Batman is sitting in the Batmobile at a stoplight.
As the light turns green, Robin passes Batman in his lime-green Pinto at a constant speed of 60 km/h. If Batman gives chase. accelerating at a constant rate of 10 km/h/s. determine
a) now long 1t takes batman to attain the
same speed as Robin.
b) how far Batman travels in this time.
c) how long it takes for Batman to catch up
to Robin.

Answers

If Batman gives chase and  accelerating at a constant rate of 10 km/h/s then:
a) 6 seconds
b) 360 meters
c) 12 seconds

What is Accelerating?

Accelerating is a process whereby an object, or a system of objects, increases its speed or rate of change. It is a fundamental concept in physics and is used to describe the motion of objects, such as an acceleration due to a force, or the rate of change in velocity. Accelerations can also be caused by a change in direction, or due to changes in gravity, such as when accelerating towards the surface of a planet.

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Two blocks are connected by a massless rope over a massless, frictionless pulley. The mass of block 2 is 2=12.1 kg, and the coefficient of kinetic friction between block 2 and the incline is =0.200 . The angle of the incline is 29.5° . If block 2 is moving up the incline at constant speed, what is the mass 1 of block 1?

Answers

The 3.3kg  is the mass 1 of block 1 .

What is mass ?

The amount of matter in a body is referred to as its mass. The kilogramme is the kilograms, which is the SI unit of mass (kg). Mass is defined as: Mass = Density/Volume.

What is speed ?

The rate of a directionally changing object's location. The SI unit of speed is created by combining the fundamental units of length and time. Meters per second (m/s) is the unit of speed in the metric system.

Therefore, The 3.3kg  is the mass 1 of block 1 .

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Calculate the total work done on a mass m as it moves from position x1 = 0 m to x2 = 40 m
F1 = 5 N F2 = 6 N angle between them 50 degree
F3 = 2 N F4 = 2 N Angle Between them 20 Degree

Answers

The total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.

What is Work Done?

Work is a physical quantity that describes the amount of energy transferred when a force acts on an object and causes it to move. When a force acts on an object and causes it to move in the direction of the force, work is said to be done on the object. Mathematically, work is defined as the dot product of force and displacement:

Work = Force x Displacement x cos(theta)

To calculate the total work done on the mass as it moves from position x1 to x2, we need to find the net work done by all the forces on the mass. The net work done by a force is given by the formula:

W = F * d * cos(theta)

where W is the work done, F is the force, d is the displacement of the mass, and theta is the angle between the force and the displacement.

First, we can calculate the work done by each force separately and then add them up to find the total work done.

Work done by F1:

W1 = F1 * (x2 - x1) * cos(0) = 5 N * 40 m * cos(0) = 200 J

Work done by F2:

W2 = F2 * (x2 - x1) * cos(50°) = 6 N * 40 m * cos(50°) ≈ 165.41 J

Work done by F3:

W3 = F3 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J

Work done by F4:

W4 = F4 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J

The total work done on the mass is the sum of the work done by each force:

W_total = W1 + W2 + W3 + W4 ≈ 515.17 J

Therefore, the total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.

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(2 of 5)
Now, decrease the planet size by sliding the Planet Properties 'radius' slider to the left until
it is one-tenth (0.100) the radius of Jupiter. For this configuration, the normalized flux
(relative amount of star light reaching an observer on Earth) when the planet is off to he
side (not transiting) is. while the normalized flux when the planet is transiting is
O 1.000, 0.990
O 0.990,1.000
O 1.00000, 0.99990
O 0.99990,1.00000

Answers

Its normalized flux for this configuration while the planet is off to the side is, and the normalized flux whenever the planet equals transiting is, respectively, 1.00000 and 0.99990.

What defines a planet?

It specifies three requirements for a planet: It must move about a sun. It must be large enough for gravity to pull it in a spherical direction. It must be massive sufficient that its gravity wiped away any other things of a similarly sized in its circle of the Sun.

What is a planet made of?

Earth is formed of rock, as are the three inner planets of the solar system (Mercury, Venus, and Mars), which also contain metals like aluminum and aluminum as well as typical minerals like feldspar.

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Answer:

1.00000,0.99990 (correct)

Explanation:

Unit 3
The Flow of Energy in Systems
EVIDENCE NOTEBOOK
11. How could the surfaces and structures in an urban area be related to the
urban heat island effect? Record your evidence

Answers

Answer:

The surfaces and structures in an urban area can have a significant influence on the urban heat island effect. For example, paved surfaces like roads and buildings absorb more heat than surfaces covered in vegetation, and structures like high-rise buildings can trap and reflect heat, resulting in higher temperatures in the urban area. Additionally, urban areas usually have less vegetation than their rural counterparts, meaning there is less vegetation to absorb heat from the sun and provide shade, further contributing to the urban heat island effect. Evidence of this can be seen in research at louisvilleky.gov/government/sustainability/urban-heat-island-project.

A blue marble of mass 0.350 kg traveling at 2.60 m/s to the left collides with a red marble of mass 0.350 kg that is initially at rest. After the collision, the blue marble is at rest. What is the new velocity of the red marble that is now moving in the same direction?
A.2.60 m/s to the left
B.0.350 m/s to the right
C.5.20 m/s to the left
D.0.91 m/s to the left​

Answers

Answer:

[tex]2.60\; {\rm m\cdot s^{-1}}[/tex] to the left.

Explanation:

When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum of that object would be [tex]p = m\, v[/tex]. Note that since velocity is a vector quantity (has a direction) while mass is a scalar, the direction of momentum would be the same as that of velocity.

Before the collision:

Momentum of the blue marble: [tex](0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}})[/tex] to the left.Momentum of the red marble would be [tex]0\; {\rm kg\cdot m\cdot s^{-1}}[/tex] since velocity was [tex]0\; {\rm m\cdot s^{-1}}[/tex].

Immediately after the collision:

Momentum of the blue marble would be [tex]0\; {\rm kg\cdot m\cdot s^{-1}}[/tex].The momentum of the red marble needs to be found.

Momentum is conserved immediately before and after the collision. In other words, the total momentum immediately after the collision would be the same as that immediately before the collision.

In this example, total momentum was [tex](0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}})[/tex] to the left immediately before the collision. Hence, the total momentum immediately after the collision would also be [tex](0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}})\![/tex] to the left.

Subtract the momentum of the blue marble ([tex]0\; {\rm kg\cdot m\cdot s^{-1}}[/tex]) from the total momentum to find the momentum of the red marble:

[tex]\begin{aligned}& (0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) - 0\; {\rm kg\cdot m\cdot s^{-1}} \\ =\; & (0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) && (\text{to the left}) \end{aligned}[/tex].

Divide momentum by mass to find velocity:

[tex]\begin{aligned} v &= \frac{p}{m} \\ &= \frac{(0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) }{0.350\; {\rm kg}}&& \genfrac{}{}{0em}{}{(\text{to the left})}{} \\ &= 2.60\; {\rm m\cdot s^{-1}} && (\text{to the left})\end{aligned}[/tex].

Therefore, the velocity of the red marble would be [tex]2.60\; {\rm m\cdot s^{-1}}[/tex] to the left immediately after the collision.

pls helpp
Heidi sees a bowl of apples sitting on a table. She knows that if no force acts on that bowl, it will stay right where it is. Which part of Newton's laws of
motion explains why the bowl will stay at rest?
A Objects at rest tend to stay at rest.
OB. Objects in motion tend to stay in motion.
OC. Every action has an equal and opposite reaction.
OD. Larger objects require greater amounts of force to move.

Answers

Objects at rest tend to stay at rest as per the Newton's laws of motion. The correct option is A.

What is Newton's laws of motion?

The basic three fundamental laws of classical mechanics referred to as Newton's laws of motion describe the ways in which an object's motion and the forces acting on it interact.

The first statement of Newton's laws of motion, which states that "Objects at rest tend to stay at rest, and objects in motion tend to stay in motion, with not only the same speed but also in the same direction.

It takes place unless acted upon by an external force," will lead the bowl of apples to remain at rest.

This rule, often known as the law of inertia, holds that unless an outside force acts upon an object, it will continue to move uniformly in a straight line or be at rest. Since no force is operating on the bowl of apples, it will continue to be at rest.

Thus, the right response is A.

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Using the internet to help answer this question...Does a Komodo Dragon reproduce sexually or asexually

Answers

Komodo's dragons reproduce through both sexual reproduction and a form of asexual reproduction called parthenogenesis.

What is parthenogenesis?

A zygote lacking gametes forms during parthenogenesis. Invertebrates and lower plants frequently exhibit it.

As it turns out, the Komodo dragon is capable of both sexual and asexual reproduction, depending on the circumstances. The majority of zoos keep female dragons alone and apart from the males.

Therefore, both sexual reproduction and parthenogenesis, a type of asexual reproduction, are used by Komodo dragons to breed.

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W
Question 9
1 pts
The initial vertical velocity (Vyi) needed to raise your center of mass from an initial
height (yi) of 1.2 m to a peak height (yf) of 1.8 m is

Answers

The initial vertical velocity needed to raise the center of mass from 1.2 m to a peak height of 1.8 m is approximately 3.43 m/s.

What is the initial velocity?

The initial vertical velocity needed to reach a peak height can be calculated using the equation of motion for a projectile under constant gravity:

Vyi = √(2 * g * (yf - yi))

where:

g is the acceleration due to gravity (approximately 9.8 m/s^2)yi is the initial height (1.2 m)yf is the peak height (1.8 m)

Plugging in the values, we get:

Vyi = √(2 * 9.8 * (1.8 - 1.2))

Vyi = √(2 * 9.8 * 0.6)

Vyi = √(11.76)

Vyi = 3.43 m/s

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You are fixing the roof of your house when a hammer breaks loose and slides down. The roof makes an angle of 45 ∘ with the horizontal, and the hammer is moving at 4.5 m/s when it reaches the edge. Assume that the hammer is moving from the top of the roof to its right edge.

1. What is the vertical component of the hammer's velocity just as it leaves the roof?

Answers

The hammer travels at 3.9 m/s in its horizontal direction. The roof is at an angle with the horizontal when the hammer is dropped from a height of v along it.

Describe a velocity example.

The speed with which something travels in a specific direction is known as its velocity. As an illustration, think of the movement of a car driving north on either a highway or the speed at which a rocket takes off.

When does acceleration differ from velocity?

The change in displacement is measured in terms of velocity. The speed of change in velocity is known as acceleration. Given that it has both a magnitude and a direction, mass and velocity quantity. Being merely the change in frequency, accelerating is also an vector quantity.

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Two blocks are attached to either end of a light rope that passes over a light, frictionless pulley suspended from the ceiling. One block has mass 8. 00 kg , and the other has mass 6. 00 kg. The blocks are released from rest.

Answers

Two blocks are attached to either end of a light rope that passes over a light, the change in gravitational PE is 11.76, -15.68j,  0.2T, -0.2T and speed is 0.7483 m/s.

partA] change in gravitational PE :

U6 = m1gh = 6*9.8*0.2 = 11.76 J

 U8 = -m2gh = -8*9.8*0.2 = -15.68 J

ANSWER = 11.76, -15.68

partB] W6 = T*0.2 = 0.2T

W8 = T*-0.2 = -0.2T

  answer = 0.2T, -0.2T

partC] WT = 0.2T-0.2T = 0

    deltaUg = 11.76-15.68 = -3.92 J

   increase in KE = 3.92J

   speed v = sqrt(2KE/(m1+m2))= sqrt(2*3.92/14) = 0.7483 m/s

  answer = 0,-3.92, 0.7483

The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.

In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.

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How can scientists determine whether an extinct animal gave birth on land or underwater?.

Answers

The correct option is C. Position of the head of the fetus of an extinct animal that gave birth on land or underwater.

In human prenatal development, fetal development starts offevolved from the 9th week after fertilization (or eleventh week gestational age) and maintains till birth.

Prenatal improvement is a continuum, with no clear defining characteristic distinguishing an embryo from a fetus. however, a fetus is characterized by the presence of all the most important body organs, though they will now not yet be completely advanced and practical and some not but situated in their very last anatomical vicinity. An unborn offspring develops and grows within the uterus (womb) of humans and different mammals. In human beings, the fetal duration begins at 9 weeks after fertilization of an egg by using sperm and ends at the time of delivery.

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Complete Question:

1. How can scientists determine whether an extinct animal gave birth on land or underwater?

a. Location of the hind limbs of the fetus

b. Position of the nostrils

c. Position of the head of the fetus

d. Location of the fossils

N₂O4(9) 2NO₂(g)
Colorless Brown
Keq = 6.16 x 10.3
What is the predicted direction of change?
Setup 1:
Setup 2:
Setup 3:
DONE ✔
Setup #
1
2
3
[N₂04]
0.098 M
0.150 M
0.420 M
[NO₂]
0.0064 M
0.0304 M
0.230 M

Answers

Here, when , the reaction quotient is less than the equilibrium constant, then, the reaction will move to the right. In the first set up, the reaction quotient is less than Keq. Then, the reaction moves to right.

What is reaction quotient ?

The reaction quotient of a reaction is the ratio of molar concentration of the product to the molar concentration of the reactants.

In the first setup.

Keq = 6.16 x 10⁻³

Q = [0.0064]²/[0.098] = 4.18 × 10⁻⁴

Q<K⇒The reaction moved to the right (products)

Setup 2 :

Q = [0.0304]²/[0.150]

   = 6.16 x 10⁻³

Q=K⇒the system at equilibrium

Setup 3 :

Q =  [0.230]²/[0.420]

   = 0.126

Q>K⇒The reaction moved to the left (reactants)

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Answer: products, equilibrium, reactants

Explanation:

its right on edge 2023

a wheel has angular velocity 4.00 rad/s. which of the following is closest to the number of revolutions that the wheel makes in 15.0 s?
a.10 revolutions
b.20 revolutions
c.15revolutions
d.25 revolutions
e. 5 revolutions
f. i dont know yet

Answers

Answer:

10 revolutions

Explanation:

By using the equation Δ=Δ, we get that Δ=(4.00rad/s)(15.0s)=60.0rad. Since there are 2 radians per revolution, this angular displacement corresponds to (60.0rad)/(2rad/rev)=9.55rev.

The angular velocity of the wheel is 4 rad/s and the time interval is 15 s. Then the number of rotations in radians is 60 radians. This is equal to 9.5 revolutions.

What is angular velocity ?

Angular velocity is a physical quantity that describes the speed of an object in an angular path. It is the rotational o revolutional analogue of of the linear velocity.

The angular velocity of an object is the product of the linear velocity and the radius of the angular path.

Given that, the angular velocity of the wheel = 4 rad/s

time  = 15 s

then, number of radians = 4 rad/s × 15 s = 60 radians.

1 revolution  = 2π radians.

then 60 radians = 60/2π = 9.5 revolutions.

Therefore, the number of revolutions for the wheel in 15 s is 9.5 revolutions.

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Calculate the total work done on a mass m as it moves from position x1 = 0 m to x2 = 40 m
F1 = 5 N F2 = 6 N angle between them 50 degree
F3 = 2 N F4 = 2 N Angle Between them 20 Degree

Answers

The total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.

What is Work Done?

Work is a physical quantity that describes the amount of energy transferred when a force acts on an object and causes it to move. When a force acts on an object and causes it to move in the direction of the force, work is said to be done on the object. Mathematically, work is defined as the dot product of force and displacement:

Work = Force x Displacement x cos(theta)

To calculate the total work done on the mass as it moves from position x1 to x2, we need to find the net work done by all the forces on the mass. The net work done by a force is given by the formula:

W = F * d * cos(theta)

where W is the work done, F is the force, d is the displacement of the mass, and theta is the angle between the force and the displacement.

First, we can calculate the work done by each force separately and then add them up to find the total work done.

Work done by F1:

W1 = F1 * (x2 - x1) * cos(0) = 5 N * 40 m * cos(0) = 200 J

Work done by F2:

W2 = F2 * (x2 - x1) * cos(50°) = 6 N * 40 m * cos(50°) ≈ 165.41 J

Work done by F3:

W3 = F3 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J

Work done by F4:

W4 = F4 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J

The total work done on the mass is the sum of the work done by each force:

W_total = W1 + W2 + W3 + W4 ≈ 515.17 J

Therefore, the total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.

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One pipe can fill a tank in 3 hours, and another pipe can fill the tank in 6 hours. How long will it take to fill the tank if both pipes are used at the same time?

Answers

It will take both pipes working together 2 hours to fill the tank. As in general, when two pipes or machines are working together to complete a task, their combined rate is the sum of their individual rates.

Let's assume that the tank has a volume of 1 unit (you can use any unit you prefer).

The first pipe can fill the tank in 3 hours, which means it can fill 1/3 of the tank in one hour. Similarly, the second pipe can fill the tank in 6 hours, which means it can fill 1/6 of the tank in one hour.

If both pipes are used at the same time, the rate at which they fill the tank is the sum of their individual rates. So, the combined rate at which they fill the tank is:

1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2

This means that both pipes together can fill half of the tank in one hour. To fill the entire tank, we need to multiply this rate by the time it takes to fill the tank, which we'll call "t":

1/2 * t = 1

Solving for "t", we get:

t = 2 hours

Therefore, it will take both pipes working together 2 hours to fill the tank.

This same concept can be applied to many different types of problems involving pipes, machines, or workers working together to complete a task. The key is to find the individual rates of each pipe or machine and add them together to get the combined rate. Then, you can use the combined rate to find the time it takes to complete the task.

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Compute the density in g/cm3 of a piece of metal that has a mass of 0.500 kg and a volume of 63 cm3.

Answers

Answer: ~7.94g/cm^3

Explanation: To find the density we first must make sure all the units are correct:

0.500kg x 1000g = 500g

500g / 63 cm^3 will give you units in g/cm^3, and the answer: 7.9365g/cm^3.

A truck moving across an ice road is spreading sand across the ice.  The truck can be considered a closed, isolated system.  Which of the following is true? * a. The mass of the truck decreases with no change in the velocity of the truck b.The mass of the truck decreases while the velocity of the truck increases. C.The mass of the truck decreases while the velocity of the truck decreases. D. The mass of the truck remains the same while the velocity of the truck remains the same.​

Answers

Answer:

D

Explanation:

The mass of the truck remains the same while the velocity of the truck remains the same.

The concept of a closed, isolated system means that the system is considered to be completely enclosed and does not exchange energy or matter with its surroundings. In this case, the truck is spreading sand across the ice, but it is still considered a closed, isolated system because it is not exchanging matter with its surroundings. The mass of the truck, which includes the truck and the sand inside, remains constant.

Therefore, option D, "The mass of the truck remains the same while the velocity of the truck remains the same" is true.

A 25kg turkey is fired from a 1.2x10^3 kg turkey launcher.  If the horizontal velocity of the turkey is 245m/s east, what is the recoil of the launcher?
A.) 9.38 m/s
B.) 7325 m/s
C.) 4925 m/s
D.) 5.1 m/s​

Answers

The recoil velocity of the launcher is 5.1 m/s.

option D.

What is the recoil velocity of the launcher?

To calculate the recoil velocity of the launcher, we can use the law of conservation of momentum.

According to this law, the total momentum of the system (turkey + launcher) before the launch is equal to the total momentum after the launch.

initial momentum of the turkey = final momentum of the launcher

( 25 kg x 245 m/s ) = 1,200 kg (v)

where;

v is the recoil velocity of the launcher

v = ( 6125 kgm/s) / ( 1,200 kg )

v = 5.1 m/s

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If an object is dropped how long will it take to attain a velocity of 127.4 m/s

Answers

The time it takes for an object to attain a velocity of 127.4 m/s is 13 seconds.

What is the  time of motion of the object?

The time it takes for an object to attain a velocity of 127.4 m/s after being dropped depends on several factors, including the object's mass, the strength of air resistance, and the acceleration due to gravity.

In the absence of air resistance, an object dropped from rest would attain a velocity of 127.4 m/s at a time, t calculated as;

v = u + gt

v = 0 + gt

v = gt

t = v/g

where;

g is acceleration due to gravity

t = ( 127.4 ) / (9.8)

t = 13 seconds

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1) How do we calculate a metal density’s “fractional error” (write the formula)?

2) What is “Zero reading” or “Zero error” and how to find it for “Micrometer caliper”?

3) What is “fractional error” for the following formula?
Z= 2/3 X2Y3 , X= 7m , Y= 4m, σx=0.2m , σy=0.1m
σZ=?

Answers

Answer:

no zero error

Explanation:

Which of the following statements best describes the relationship between atoms and conductivity?(1 point)
Responses

Atoms with a nearly empty valence shell make good conductors.


Atoms with many electrons make good insulators.


Atoms with a full valence shell make good conductors.


Atoms with few electrons make good conductors.

Answers

The statement that describes the relationship between atoms and conductivity is as follows: Atoms with a full valence shell make good conductors (option C).

What is conductivity?

Conductivity is the ability of a material to conduct electricity, heat, fluid or sound.

Conductivity is determined by the types of atoms in a material (the number of protons in each atom's nucleus determines its chemical identity) and how the atoms are linked together with one another.

The atoms which have fewer electronic shells have, the lower the electrical conductivity it has and vice versa.

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Conductors and Insulators Quick Check

100% true

C. The electrons in copper (Cu) are loosely bound to the nucleus.

A. An electrical current that flows in one direction.

A. aluminum (Al)

B. Opposite charges attract one another.

C. Atoms with a nearly empty valence shell make good conductors.

C.

A.

A.

B.

C.

the combined effect of all forces acting on an object is the ___ force

Answers

Answer:

net force

Explanation:

Class work 6 1. A 1 kg wooden block is stationary on a desk tip. The coefficient of static friction for the two surfaces is 0.2. a) b) Find the normal force experienced by the block. Determine the maximum static frictional force for this situation c) What force will get the block to move? d) Calculate the kinetic frictional for if the coefficient of kinetic friction is 0.19​

Answers

(a) The normal force experienced by the block is 9.8 N.

(b) The maximum static frictional force is 1.96 N.

(c) The minimum force required to move the block is 1.96 N.

(d) The kinetic friction force is 1.862 N.

What is the normal force?

The normal force experienced by the block is equal to the weight of the block and is given by:

F_normal = mg

where;

m is the mass of the block (1 kg) and g is the acceleration due to gravity (9.8 m/s^2).

F_normal = 1 kg x 9.8 m/s^2 = 9.8 N

The maximum static frictional force is given by:

F_friction_max = μ_s x F_normal

where;

μ_s is the coefficient of static friction (0.2).

F_friction_max = 0.2  x 9.8 N = 1.96 N

To get the block to move, a horizohntal force greater than the maximum static frictional force must be applied. The minimum force required to move the block is given by:

F_min = F_friction_max + ε

where;

ε is a small positive value to account for any slight inaccuracies.

The kinetic friction force is given by:

F_friction_kinetic = μ_k x F_normal

where;

μ_k is the coefficient of kinetic friction (0.19).

F_friction_kinetic = 0.19 x 9.8 N = 1.862 N

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Jackie studied stresses that affect earth's crust. How is compression of rock different from shearing?.

Answers

"Compression of rock is nothing but squeezing the rock together and shearing is pushing the rock in opposing directions."

It squeezes the boulder as a whole and should cause the pulls to shear. This is because compression causes the weight necessary for rocks to be squeezed. Additionally, the rock's draws shouldn't be spaced apart. It shouldn't be going in opposing ways either.

When rocks are compressed together, they fold, fracture, or even shatter. Compression stress is the most prevalent stress at convergent plate boundaries. There is stress when rocks are being torn apart. Under stress, rocks either lengthen or fragment.

Due to the compression pushing the hanging wall up in relation to the footwall, if the fault arises in a scenario of compression, it will be a reverse fault.

Compressional stresses cause a rock to shorten. A rock elongates or pulls apart as a result of tensional pressures. Shear forces cause rocks to slide past one another.

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A ball tossed vertically upward from the ground next to a building passes the bottom of a window 1.7 s after being tossed and passes the top of the window 0.30 s
later. The window is 2.0 m high from top to bottom. What was the ball's initial velocity? How far is the bottom of the window from the launch position? How high does the ball rise above the launch position?

Answers

The initial velocity of the ball is v₀ = (2*2.0)/0.30 = 13.3 m/s. and the height of the ball above the launch position is h = (13.3*1.7) - (0.5*9.81*(1.7)²) = 15.1 m.

What is initial velocity?

Initial velocity is the speed and direction of an object at the start of its motion. It is usually designated by vector notation, with the direction of motion indicated by an arrow.

The initial velocity of the ball can be calculated using the equation v₀ = (2h)/t, where h is the height of the window (2.0 m) and t is the time it took for the ball to reach the top of the window (0.30 s).
Thus, the initial velocity of the ball is v₀ = (2*2.0)/0.30 = 13.3 m/s.

The bottom of the window is 1.7 m above the launch position.
The height of the ball above the launch position can be calculated using the equation h = v₀t - 0.5gt².
Here, v₀ is the initial velocity (13.3 m/s),
t is the time it took for the ball to pass the bottom of the window (1.7 s),
and g is the acceleration due to gravity (9.81 m/s²).
Thus, the height of the ball above the launch position is h = (13.3*1.7) - (0.5*9.81*(1.7)²) = 15.1 m.

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States of matter that can become part a
Solution are
Solids =
Liquids =
Gases =
Saltwater
Vapors
=

Answers

Conversion of liquid into vapor or gas. - (b) Vaporization

Conversion of liquid into solid. - (d) Freezing

Conversion of solid into a liquid on heating. - (a) Melting

What is liquid?

A liquid is a nearly incompressible fluid with a (almost) constant volume regardless of pressure that adapts to the shape of its container. Being the only form with a set volume but no fixed shape, it is one of the four fundamental states of matter (the others being solid, gas, and plasma). A liquid can flow and assume a container-like shape, much like a gas can. A liquid keeps a relatively constant density and does not disperse to cover every space in a container like a gas does. a distinguishing quality of it.

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A toy car of mass 50g travels down a smooth incline at 30 degrees to

the horizontal. Calculate:

(a) The net force acting on the car as it rolls down the slope, and

(b) The force of the incline on the car as it travels down the slope.

Answers

The only force causing the car to slide down the incline is the gravitational force component, or "mg sin," because the surface is frictionless (smooth), or Ff = 0.

What is Force?

a) F = mg sin θ.

F = 50 * 10−3 9.8 * 1/2

= 0.245 N

If the slope is 30 degrees, the top corner will be 90 30 degrees, and the normal to the vertical force will also be 90 60 degrees, thus we will use mg cos 30 perpendicular to the slope.

b) FN = mg cos θ

= m × g × cos θ

= 50 × 10−3 × 9.8 × cos 30

= 0.43N

Therefore, The only force causing the car to slide down the incline is the gravitational force component, or "mg sin," because the surface is frictionless (smooth), or Ff = 0.

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sun why it that the higher you go to the becomes cold.

Answers

The temperature drops as you go higher into the atmosphere because you are moving away from the Earth's surface, where the majority of the planet's heat is generated.

What happens when we go higher?

As you move higher, the air pressure and density decrease, and there is less of the Earth's atmosphere to absorb and retain heat. This results in a lower overall temperature.

Additionally, the sun's rays become more intense at higher altitudes due to the lack of air molecules to scatter the sunlight. This can cause a heating effect, but it's usually not enough to offset the cooling effect caused by the decrease in atmospheric pressure.

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