25. Given: TE= RI, TI = RE,
Proof
LTDI and LROE are right /
Prove: TD=RO

The coordinates of the point that is 4/5 of the way from T to S is (2,10)

The given parameters are:

T = (6,-2)

S = (1,13)

Location = 4/5

The location 4/5 means

Ratio, m : n = 4 : 1

The coordinate is then calculated as:

[tex](x,y) = \frac{1}{m +n} * (mx_2 + nx_1,my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{4 +1} * (4 * 1 + 1 * 6 , 4 * 13 + 1 * -2)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (10 , 50)[/tex]

This gives

(x,y) =  (2,10)

Hence, the coordinates of the point that is 4/5 of the way from T to S is (2,10)

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Answer:

c =2.5

Step-by-step explanation

1.5×1.5=2.25

2×2=4

4+2.25=6.25

√6.25=2.5

c=2.5

The important similarity between the uniform and normal probability distributions is that the mean and the median of both distributions are equal

In a normal probability distribution, we have:

Mean = Median

In a uniform probability distribution, we have:

Mean = Median

This means that:

In both distributions, the mean and the median are equal

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The percentage increase is 22.72%

The given parameters are:

Initial = 440 coins

Final = 540 coins

The percentage increase is calculated as:

%Increase = (Final - Initial)/Initial * 100%

So, we have:

%Increase = (540 - 440)/440 * 100%

Evaluate the difference

%Increase = 100/440 * 100%

Evaluate the quotient

%Increase = 0.2272 * 100%

Evaluate the product

%Increase = 22.72%

Hence, the percentage increase is 22.72%

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[tex]\\ \rm\Rrightarrow log_5512[/tex]

[tex]\\ \rm\Rrightarrow log_52^9[/tex]

[tex]\\ \rm\Rrightarrow 9log_52[/tex]

[tex]\\ \rm\Rrightarrow 9\dfrac{log2}{log5}[/tex]

[tex]\\ \rm\Rrightarrow 3.876[/tex]

If your question is something different let me know by which I can change my answer

Answer:

3.876  (3 d.p.)

Step-by-step explanation:

Given:

Please note:  The question gives two values of log base 10 which should be used to help find the value of [tex]\log_5512[/tex]

Log Law:  Change of Base

[tex]\log_ba=\dfrac{\log_xa}{\log_xb}[/tex]

Change the given expression to log base 10:

[tex]\implies \log_5512=\dfrac{\log_{10}512}{\log_{10}5}[/tex]

Replace 512 with 2⁹, and 5 with 10/2:

[tex]\implies \dfrac{\log_{10}{2^9}}{\log_{10}\frac{10}{2}}[/tex]

[tex]\textsf{Apply the Power Log law}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies \dfrac{9\log_{10}{2}}{\log_{10}\frac{10}{2}}[/tex]

[tex]\textsf{Apply the Log Quotient law}: \quad \log_a\frac{x}{y}=\log_ax - \log_ay[/tex]

[tex]\implies \dfrac{9\log_{10}{2}}{\log_{10}10-\log_{10}2}[/tex]

[tex]\textsf{Apply log law}: \quad \log_aa=1[/tex]

[tex]\implies \dfrac{9\log_{10}{2}}{1-\log_{10}2}[/tex]

Given:

Substitute this into the expression and simplify:

[tex]\implies \dfrac{9(0.3010)}{1-0.3010}[/tex]

[tex]\implies \dfrac{2.709}{0.699}[/tex]

[tex]\implies 3.876\:(\sf 3\: d.p.)[/tex]

Answer:

D

Step-by-step explanation:

interior angles = 180

180-72

Answer:

Step-by-step explanation:

[tex]\bf 2(xy-7)[/tex]  [tex]\bf when[/tex]  [tex]\bf x=-1/y=3[/tex]

Substitute with x and y with 3:-

[tex]\bf 2\left(\left(-1\right)(3)-7\right)[/tex]

First, Multiply -1 and 3 = -3

[tex]\bf 2(-3-7)[/tex]

Subtract  7 from -3 = -10

[tex]\bf 2(-10)[/tex]

Multiply 2 and -10 = -20

[tex]\bf -20[/tex]

Step-by-step explanation:

the product of segments theorem :

products of segments of intersecting chords are equal.

the 2 chords helping us are

the "4 + 25" chord.

the "x + x" chord (that connects then outwards to the 20 segment).

so, based on that theorem

4 × 25 = x × x

100 = x²

x = sqrt(100) = 10

The steps are shown below: -5<x<1

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Given:

|x +2 | <-3

If we take the module is positive,

x+2 -2 < -3-2

x < -5

If we take the module is negative,

-( x+2)  < -3

-x -2 < -3

-x -2 +2 < -3 +2

-x< -1

x>1

Combining the inequalities,

-5<x<1

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Answer:

60

Step-by-step explanation:

Total degree of triangle interior angles is 180

So x+2x+3x=180

6x=180

x=30

Measurement of angle C is 2x which is 60 degree

The chance of not throwing the ball to a receiver on either throw is 0.0375, or 3.75 per cent.

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

This is event A when he misses the first throw. P(A) = 25%, or 0.25 Because event B takes place only after event A. When he misses on the second throw, event B occurs. P(B/A) = 15% or 0.15

P(A[tex]\cap[/tex]B) = P(A) P(B/A) P(A[tex]\cap[/tex]B)

P(A[tex]\cap[/tex]B) = (0.25)x(0.15) P(ANB)

P(A[tex]\cap[/tex]B) = 0.0375

Therefore the chance of not throwing the ball to a receiver on either throw is 0.0375, or 3.75 per cent.

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The equation is y = 250(0.89)^x and the decay rate is 11%.

The initial value will be:

= 250(0.89)^x

= 250(0.89^0)

= 250

The decay rate will be:

= 1 - 0.89

= 0.11

= 11%

In conclusion, the equation is y = 250(0.89)^x and the decay rate is 11%.

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Answer:

4y⁷x²

Step-by-step explanation:

    Prime factorize each expression.

28y⁷x² = 2 * 2 * 7 * y⁷ * x²

8y⁸v⁴x⁶ = 2 * 2 * 2 * y⁸ * v⁴ * x⁶

GCF = 2 * 2 *y⁷*x²

        = 4y⁷x²

Answer:

D. None of the above.

Step-by-step explanation:

Supplementary angles must add up to 180 degrees.

Complementary angles must add up to 90 degrees.

Vertical angles are opposite of each other.

Hope this helps!

If not, I am sorry.

The value of y is 11 if the measure of the angle (x + 6y) is 90 degree and x = 24 option first is correct.

Lines that intersect at a right angle are named perpendicular lines. Lines that are always the same distance apart from each other known as parallel lines.

We have a perpendicular line shown in the picture.

The measure of the angle (4x - 6) is equal to 90 degree.

4x - 6 = 90

4x = 96

x = 24

Similarly, the measure of the angle (x + 6y) is equal to 90 degree:

x + 6y = 90

Plug x = 24

24 + 6y = 90

y = 11

Thus, the value of y is 11 if the measure of the angle (x + 6y) is 90 degree and x = 24 option first is correct.

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Is that expression a polynomial expression?

yes because they are terms linked into one expression.

What if she wrote - signs between the expressions instead?

it would still be considered a polynomial.

What if she wrote × signs between the expressions instead?

no because it would be one huge term

Answer:

  (b)  8.9 m

Step-by-step explanation:

The mirror ensures that angle 1 is congruent to angle 2, so the triangles in the diagram are similar. The ratios of height to mirror distance are proportional.

__

The height of the object is proportional to its distance from the mirror, so we have ...

  (tree height)/(tree-to-mirror) = (person height)/(person-to-mirror)

  (tree height)/(2.5 m) = (1.78 m)/(0.5 m)

Multiplying this proportion by 2.5 m, we find ...

  tree height = (2.5 m)(1.78/0.5) = 8.9 m

The height of the palm tree is 8.9 meters.

Answer:

D. 531[tex]in^{2}[/tex]

Step-by-step explanation:

I suppose these are rectangles and not triangles.

Area of Rectangle = Length x Breadth

Area of Large Rectangle = 21 x 18

= 378[tex]in^{2}[/tex]

Area of Small Rectangle = 17 x 9

= 153[tex]in^{2}[/tex]

Total Area = Area of Large Rectangle + Area of Small Rectangle

= 378 + 153

= 531[tex]in^{2}[/tex]

The equivalent expression of [tex](3m^{-4})^3 * (3m^3)[/tex] is [tex]729m^{-9}[/tex]

The expression is given as:

[tex](3m^{-4})^3 * (3m^3)[/tex]

Expand the brackets

[tex]27m^{-12} * 27m^3[/tex]

Apply the law of indices

[tex]729m^{-12+3}[/tex]

Evaluate the sum

[tex]729m^{-9}[/tex]

Hence, the equivalent expression of [tex](3m^{-4})^3 * (3m^3)[/tex] is [tex]729m^{-9}[/tex]

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Answer:

Jane is 11 1/4 years old.

Step-by-step explanation:

Subtract all of the numbers given.

[tex]13\frac{5}{6} -1\frac{1}{3} -1\frac{1}{4}[/tex].

To subtract this, we need to find a common denominator.

A common denominator in this situation is 12. To do this multiply the 5 and the 6 of 5/6 by 2. Multiply the 1 and the 3 of 1/3 by 4. And multiply the 1 and the 4 1/4 by 3.

The new expression will look like this:

[tex]13\frac{10}{12} -1\frac{4}{12} -1\frac{3}{12}[/tex].

Now we can subtract.

[tex]13\frac{10}{12} -1\frac{4}{12} -1\frac{3}{12}=11\frac{3}{12}[/tex]

Reduce the answer.

[tex]11\frac{3}{12}=11\frac{1}{4}[/tex]

In decimal form 11.25

Hope this helps!

If not, I am sorry.

The volume of the copper wire is 226.080 cm³ and the mass of the wire is 2,012.112 g/cm³.

Given that, the length of copper wire=200 m=200000 mm and the diameter of the copper wire=1.2 mm.

We need to find the volume of the copper wire.

The formula to find the volume of a cylinder is πr²h.

Now, the volume of the copper wire=πr²h=[tex]\frac{22}{7} \times (0.6)^{2} \times 200000=2,26,080[/tex] mm³=226.080 cm³

If the density of copper is 8.9 g/cm³, find the mass of the wire.

We know that [tex]Density=\frac{Mass}{Volume} }[/tex].

⇒8.9 g/cm³=[tex]\frac{Mass}{226.080}[/tex]

⇒Mass=2,012.112 g/cm³

Therefore, the volume of the copper wire is 226.080 cm³ and the mass of the wire is 2,012.112 g/cm³.

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Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

It is defined as the difference between the maximum value in the data set to the minimum value in the data set.

We have:

The amount of money in tips earned by four restaurant servers waiting on 10 tables is represented by the following data sets:

Alyssa {3, 6, 2, 8, 12, 14, 5, 7, 7, 8}

Bryant {9, 2, 7, 50, 0, 5, 2, 8, 6, 8}

Camila {1, 9, 10, 3, 0, 12, 10, 9, 8, 2}

Devon {4, 2, 8, 15, 20, 7, 5, 0, 6, 2}

The IQR for Alyssa:

IQR = Q3 - Q1

IQR = 8 - 5 = 3

The IQR for Bryant:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

The IQR for Camila:

IQR = Q3 - Q1

IQR = 10 - 2 = 8

The IQR for Devon:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

Thus, Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

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The graphed that represents the new function with the same slope and y-intercept is: graph Y.

Slope = rise/run along a line.

Y-intercept is the y-value of the point on the y-axis that the line intercepts.

Slope of the function given = rise/run = 2/1 = 2

2 multiplied by 1/2 = 2/2 = 1.

Y-intercept of the given function is: 1

1 increased by 3 units is: 1 + 3 = 4

The slope of graph Y = rise/run = 2/2/ = 1

The y-intercept is also 4

Therefore, the answer is: Graph Y

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The difference of the polynomials is [tex]1.3t^{3}-0.2t^{2}-6t-8[/tex] and the additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].

The given polynomials are [tex](1.3t^{3}+0.4t^{2} -24t )[/tex] and [tex]0.6t^{2} +8-18t[/tex].

We need to find the additive inverse of the polynomial being subtracted.

In mathematics, the additive inverse of a number a is the number that, when added to a yields zero. This number is also known as the opposite, sign change, and negation.

Now, [tex](1.3t^{3}+0.4t^{2} -24t )-(0.6t^{2} +8-18t)[/tex]

[tex]=1.3t^{3}+0.4t^{2}-0.6t^{2}-24t+18t-8[/tex]

[tex]=1.3t^{3}-0.2t^{2}-6t-8[/tex]

The additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].

Therefore, the difference of the polynomials is [tex]1.3t^{3}-0.2t^{2}-6t-8[/tex] and the additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].

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[tex]a\cdot b=(7)(4)+(3)(-1)=25\\\\|a|=\sqrt{7^{2}+3^{2}}=\sqrt{58}\\\\|b|=\sqrt{4^{2}+(-1)^{2}}=\sqrt{17}\\\\\cos \theta=\frac{25}{\sqrt{58}\sqrt{17}}\\\\\theta=\cos^{-1} \left(\frac{25}{\sqrt{58}\sqrt{17}} \right) \approx 37.235^{\circ}[/tex]

Answer:

Step-by-step explanation:

Comment

If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)

Givens

Arc EG = 127

Arc DF = 49

Solution

<DCF = 1/2(127 - 49)

<DCF = 1/2(78)

<DCF = 39