Answer:
Explanation:
Growing Peas
Planting depth should be roughly 2 inches with a spacing of about 2 inches apart. Water well at planting and provide at least 1 inch of water per week, particularly during the flowering and pod production stages. As the temperature rises, the vines may need to be deeply watered almost every day.
Make sure to moniter it and change the water depending on how dry or overwatered it looks like. :)
g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertainty (grams) of calcium in each average calcium mass of the sample? Assume that the relative uncertainties in atomic mass are small compared the uncertainty of the total mass.
Answer:
The value is [tex]L = 0.985 \pm 0.00801 \ g[/tex]
Explanation:
From the question we are told that
The molar mass of [tex]CaCO_3[/tex] is [tex]MW = 100.085 \ g/mol[/tex]
The total mass is [tex]m_g = 12.3 \ g[/tex]
The uncertainty of the total mass is [tex]\Delta g = 0.1[/tex]
Generally the molar weight of calcium is [tex]M_c = 40 g/mol[/tex]
The percentage of calcium in calcite is mathematically represented as
[tex]C = \frac{40.07}{100.085} * 100[/tex]
[tex]C = 40.03 \% [/tex]
Generally the mass of each sample is mathematically represented as
[tex]m= \frac{m_g}{5}[/tex]
[tex]m= \frac{12.3}{5}[/tex]
[tex]m= 2.46 \ g [/tex]
Generally mass of calcium present in a single sample is mathematically represented as
[tex]m_c = 2.46 * \frac{40.04}{100}[/tex]
[tex]m_c = 0.985 \ g [/tex]
The uncertainty of mass of a single sample is mathematically represented as
[tex]k = \frac{\Delta g }{5}[/tex]
[tex]k = \frac{0.1 }{5}[/tex]
[tex]k = 0.02\ g [/tex]
The uncertainty of mass of calcium in a single sample is mathematically represent
[tex]G = \frac{0.02 * 40.04}{ 100}[/tex]
[tex]G = 0.00801 \ g [/tex]
Generally the average mass of calcium in each sample is
[tex]L = 0.985 \pm 0.00801[/tex]
construct
an isotope has 17 protons 20 neutrons and 18 electrons
To solve this we must be knowing each and every concept related to isotope and its example. Therefore, the corresponding isotope is ₁₇Cl³⁷.
What are isotope?Each atom contains the exact same quantity of electrons like protons, but isotopes differ somewhat; they contain the very same amount of electrons as well as protons but differing quantities of neutrons.
Isotopes, on the other hand, possess the same atomic number as well as the same location in the periodic table, but they have unique atomic weights. These isotopes will deteriorate over time and transform into some other isotope or element. The majority of elements discovered in nature are composed of stable isotopes.
number of proton +number of neutrons = Mass number = 37
number of proton=atomic number= 17
The corresponding isotope is ₁₇Cl³⁷.
Therefore, the corresponding isotope is ₁₇Cl³⁷.
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what density will an object have if the mass of it ia 46g and it takes up 561 mL of space?
It took 73.2 J of heat to raise the temperature of 10.0g of a substance 8.58°C. What is the
specific heat of the substance?
Answer:
[tex] \boxed{\sf Specific \ heat \ of \ the \ substance \ (c) = 0.85 \: J/g \degree C } [/tex]
Given:
Mass (m) = 10.0 g
Rise in temperature (∆T) = 8.58°C
Energy required (Q) = 73.2 J
To Find:
Specific heat of the substance (c)
Explanation:
Specific heat (c) of a substance is the energy required to raise the temperature of one gram of the substance by one degree Celsius.
Formula of specific heat is given as:
[tex] \boxed{ \bold{c = \frac{Q}{m\Delta T}}}[/tex]
By substituting value of Q, m & ∆T in the formula we get:
[tex] \sf \implies c = \frac{73.2}{10 \times 8.58} \\ \\ \sf \implies c = \frac{73.2}{85.8} \\ \\ \sf \implies c = 0.85 \: J/g \degree C [/tex]
A 250ml aqueous solution contains 45.1microgram of pesticide.express the pesticide concentration in:
1 .weight percent
2.parts per thousand
3.parts per million
please help its urgent
Answer:
1. 1.80x10⁻⁵ (w/w %).
2. 1.80x10⁻⁴ parts per thousand
3. 0.18 parts per million
Explanation:
The solution contains 45.1μg / 250mL.
1. Weight percent (100 times mass in grams of solute per gram of solution, as there are 250mL of water = 250g):
45.1x10⁻⁶g / 250g * 100 =
1.80x10⁻⁵ (w/w %)2. Parts per thousand (mg of solute per g of solution).
45.1μg * (1x10⁻³mg / 1μg) = 0.0451mg.
0.0451mg / 250g =
1.80x10⁻⁴ parts per thousand3. Parts per million (μg of solute per g of solution):
45.1μg / 250g =
0.18 parts per millionIf a soft-drink bottle whose volume is 1.10 L is completely filled with water and then frozen to -10 ∘C, what volume does the ice occupy? Water has a density of 0.997 g/cm3 at 25 ∘C; ice has a density of 0.917 g/cm3 at -10 ∘C.
Answer:
The ice occupies a volume of 1.196 liters at -10 ºC.
Explanation:
We must remember that density ([tex]\rho[/tex]), measured in grams per cubic centimeters, is the ratio of mass ([tex]m[/tex]), measured in grams, to occupied volume ([tex]V[/tex]), measured in cubic centimeters, that is:
[tex]\rho = \frac{m}{V}[/tex]
We clear the mass within the formula:
[tex]m = \rho\cdot V[/tex]
The mass of the water inside the soft-drink bottle is: ([tex]\rho = 0.997\,\frac{g}{cm^{3}}[/tex] and [tex]V = 1100\,cm^{3}[/tex])
[tex]m =\left(0.997\,\frac{g}{cm^{3}} \right)\cdot (1100\,cm^{3})[/tex]
[tex]m = 1096.7\,g[/tex]
There are 1096.7 grams of water filling the soft-drink bottle completely.
Then, the water is frozen to -10 ºC and transformed into ice, the volume occupied by the ice which we can deduct from definition of density. That is:
[tex]V = \frac{m}{\rho}[/tex]
The volume occupied by the ice inside the soft-drink bottle is: ([tex]m = 1096.7\,g[/tex] and [tex]\rho = 0.917\,\frac{g}{cm^{3}}[/tex])
[tex]V = \frac{1096.7\,g}{0.917\,\frac{g}{cm^{3}} }[/tex]
[tex]V = 1195.965\,cm^{3}\,(1.196\,L)[/tex]
The ice occupies a volume of 1.196 liters at -10 ºC.
Separate the list P, F, V, v, rho, T, a, m, L , and t into intensive properties, extensive properties and non-properties.
Answer:
Generally intensive properties are properties that are dependent on mass
So from the list given in the question we see that
P => pressure
V => volume
[tex]\rho[/tex] => density
T => tension
Are intensive properties
Generally extensive properties are properties that are increase or decreased by mass i.e that scale with mass i.e the are properties that their value is proportional to the quantity of matter(mass) in the system
So from the list given in the question we see that
m => mass
V => volume
Non -properties are
F => Force
a = > acceleration
L => length
t => time
v => velocity
Explanation:
As per the question separate the P, V, F, v and rho and T a and m and L then we have intensive properties and an extensive property and a non extensive property
Generally intensive properties are properties that are dependent on mass So from the list given in the question we see that P => pressure V => volume D => density T => tension Are intensive properties.Learn more about the list P, F, V, v, rho, T, a, m, L.
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Identify the control group the experimental group the independent variable and the dependent variable
A company wants to test a new dog food that’s aid supposed to help overweight dogs lose weight. 50 dogs are chosen to get the new food and 50 more continue their normal diets after one month the dogs are checked to see if they lose any weight
A hiker caught in a thunderstorm loses heat when her clothing becomes wet. She has emergency rations that if completely metabolized will release 35 kJ of heat per gram of rations consumed. How much rations must the hiker consume to avoid a reduction in body temperature of 2.5 K as a result of heat loss? Assume the heat capacity of the body equals that of water and that the hiker weighs 50.0 kg. State any additional assumptions.
Answer:
Amount of required rations ≥ 15 g
Other assumptions made:
1. All the energy released from the rations is converted to heat
2. All the rations is completely metabolized to release energy
3. No other heat losses occur in the body except due to wetness of her clothing.
Explanation:
Using H = mcθ
where m is mass of the hiker in Kg,
c is specific heat capacity of water/hiker = 4200 JKg⁻¹K⁻¹
θ is temperature change in K
Note : heat capacity of water = specific heat capacity x molar mass
specific heat capacity = heat capacity / molar mass
c = 75.348 JK⁻¹mol⁻¹/18 x 10⁻³ Kgmol⁻¹ = 4186 JKg⁻¹K⁻¹ ≅ 4200 JKg⁻¹K⁻¹
Heat lost, H = 50.0 Kg x 4200 JKg⁻¹K⁻¹ x 2.5 K
H = 5.25 x 10⁵ J = 525 KJ
To avoid this heat loss, the hiker must consume enough emergency rations that releases heat equal to or greater than the heat loss due to wetness of her clothing.
Energy per gram of rations = 35 KJ
Amount of required rations ≥ 525 KJ / 35 KJ/g
Amount of required rations ≥ 15 g
Therefore, the hiker must consume 15 g or more of her emergency rations.
Other assumptions made:
1. All the energy released from the rations is converted to heat
2. All the rations is completely metabolized to release energy
3. No other heat losses occur in the body except due to wetness of her clothing.
how far can you travel in 7 hours if you are driving at a rate of 55 mph
the answer is 385 miles
2. A student wishes to find the density of an irregularly shaped rock. He finds the mass to be 12.34
g. He fills a graduated cylinder to the 50.0 mL mark and drops in the rock. The fluid level rises to
54.5 mL. What is the density of the rock? (Show all work, with units, for credit.)
Answer:
The answer is
2.74 g/mLExplanation:
The Density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} [/tex]
From the question
mass of rock = 12.34 g
volume = final volume of water - initial volume of water
volume = 54.5 mL - 50 mL = 4.5 mL
So the density is
[tex]density = \frac{12.34}{4.5} \\ = 2.744444444...[/tex]
We have the final answer as
2.74 g/mLHope this helps you
0.73 grams of toluene was reacted with 2.0 grams of potassium permanganate in presence of 7.0 mL of 6 Molar potassium hydroxide and 30 mL of water. After refluxing for 1 hour the reaction mixture was treated with 6 Molar sulfuric acid to pH~ 2.0 followed by oxalic acid. On cooling this solution in an ice bath 0.633 grams of pure benzoic acid was obtained. Calculate the % yield of benzoic acid in this reaction.
Answer:
The value is [tex]k =66\%[/tex]
Explanation:
From the question we are told that
The mass of toluene [tex] m_t =0.73 \ g [/tex]
The mass of potassium permanganate is [tex] m =2.0 \ g [/tex]
The volume of potassium hydroxide V = 7.0 mL
The concentration of potassium hydroxide C = 6 M
The mass of benzoic acid is [tex]m_b = 0.633 \ g[/tex]
Generally the % yield of benzoic acid is mathematically represented as
[tex]k = \frac{m_b}{Z} * 100[/tex]
Here Z is the theoretical yield which is mathematically represented as
[tex]Z = \frac{E}{W} * m_t [/tex]
Here W is the molecular weight of product (benzoic acid) with value
W = 92.14 \ g
E is the molecular weight of reactant (toluene)with a constant value of
E = 122.12 g
So
[tex]Z = \frac{122.12 }{92.14} * 0.73 [/tex]
=> [tex]Z = 0.968 \ g [/tex]
So
[tex]k = \frac{0.633}{0.968} * 100[/tex]
=> [tex]k =66\%[/tex]
What assumptions do we make in order to use the Henderson-Hasselbalch equation? a. Both the weak acid and its conjugate base are present initially. b. x (or the change in the reaction) is approximately zero, that is we use the weak acid approximation. c. The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation. d. We only have the weak acid initially.
Answer:
The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation.
Explanation:
The Henderson-Hasselbalch is used to calculate the pH of a buffer solution. It depends on the weak acid approximation.
Since the weak acid ionizes only to a small extent, then we can say that [HA] ≈ [HA]i
Where [HA] = final concentration of the acid and [HA]i = initial concentration of the acid.
It also follows that [A^-] ≈ [A^-]i where [A^-] and[A^-]i refer to final and initial concentrations of the conjugate base hence the answer above.
Six atoms of the peptide bond group are always planar due to the ____________. Dipole of amide linkage of a peptide bond is due to partially ___________charged carbonyl oxygen and partially ___________ charged amide nitrogen. Select one: a. phi and psi angles; negatively; positively b. trans position between amide hydrogen and carbonyl oxygen; positively; negatively c. resonance structure; negatively; positively d. resonance structure; positively; negatively e. trans position between amide hydrogen and carbonyl oxygen; negatively; positively
Answer:
D
Explanation:
Resonance because the lone pairs undergo resonance due tothe partial bond relationship BTW Carbon - Nitrogen bond so the bond length shortens making the six atoms of peptide bond planar
And positive because The dipole of amide linkage of a peptide bond is as a result of the partially positively charged carbonyl oxygen and partially positively charged amide oxygen.
And the negative because The carboxylic acid group -COOH is an acid donates H+ and -NH2 being a base is H+ so causes a partial negative charge to develop on -COO(-) and partial positive charge to develop on -NH3(+).l
Which of the following describes a particle that contains
36 electrons, 49 neutrons, and 38 protons?
an ion with a charge of 2-
an ion with a charge of 2+
an atom with a mass of 38 amu
an atom with a mass of 49 amu
Od
Answer:
an ion with charge of 2+
Explanation:
proton and electron numbers do not cancel out...
it has 2 more protons than electrons.
since protons carry a positive charge, a charge of 2+ is now carried by the ion.
it is no longer called an atom as the charges do not cancel out.
Answer: An ion with a charge of +2.
Explanation:
Electrons are embedded in a mass of positively
charged matter.
Answer:
plum pudding model .
Explanation:
the electrons were 'like plums embedded in a pudding'. Also called the Raisin Bread Model.
3. Classify each of the following as a physical or a
chemical property
a. Iron and oxygen form rust.
b. Iron is more dense than aluminum.
C. Magnesium burns brightly when ignited.
d. Oil and water do not mix.
e Mercury melts at -39°C.
The classification of the following elements as a physical or chemical property is shown below
a) iron and oxygen form rust
b)iron is more dense than aluminum
c) magnesium burns brightly when ignited
d)oil and water do not mix
e)mercury melts as -39 C
A. Chemical
B. Physical
C. Chemical
D. Physical
E. Physical
For better understanding let's explain what the statement that
Physical Property is simply known as any features of a material that can be observed or measured even without changing the composition of the substances in the materialChemical Property is commonly known as a features of matter that can be observed as it alters to a different type of matter.From the above we can therefore say that the answer The classification of the following elements as a physical or chemical property is shown below;
a) iron and oxygen form rust
b)iron is more dense than aluminum
c) magnesium burns brightly when ignited
d)oil and water do not mix
e)mercury melts as -39 C
A. Chemical
B. Physical
C. Chemical
D. Physical
E. Physical
is correct
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For double-helix formation, change in Gibbs free energy, ΔG, can be measured to be −54 kJ⋅mol−1 (−13 kcal⋅mol−1) at pH 7.0 in 1 M NaCl at 25 °C (298 K). The heat released indicates an enthalpy change of -251 kJ/mol (-60 kcal/mol). For this process, calculate the entropy change for the system and the entropy change for the surroundings.
Answer:
Explanation:
Entropy change in the system : --
ΔG = −54 kJ⋅mol−1 (−13 kcal⋅mol−1) = −54 kJ⋅mol−1 (−13 x 4.2 kJ⋅mol−1)
= - 108.6 KJ / mol
ΔH = -251 kJ/mol (-60 kcal/mol) = -251 kJ/mol (-60 x 4.2 kJ/mol)
= - 503 KJ / mol
ΔG = ΔH - TΔS
ΔS = ( ΔH - ΔG ) / T
= - 503 + 108.6 / ( 273 + 25 ) KJ / mol k⁻¹
= - 1323.48 J / mol k⁻¹
Entropy change in the surrounding
+ 1323.48 J / mol k⁻¹
in an investigation that uses the scientific method which step immediately follows asking a question
Answer:
Infer and form a hypothesis
A certain sample of rubidium has just two isotopes, 85Rb (mass = 84.911amu) and 87Rb (mass = 86.909amu). The atomic mass of this sample is 86.231 amu. What are the percentages of the isotopes in this sample?
Answer:
[tex]\%_{Rb-85}=33.9\%[/tex]
[tex]\%_{Rb-87}=66.1\%[/tex]
Explanation:
Hello,
In this case, for the natural occurring isotopes we equal the average atomic mass via:
[tex]86.231=84.911*\%_{Rb-85}+86.909*\%_{Rb-87}[/tex]
Thus, since both percentages of abundance must turn out 100%, we can write:
[tex]\%_{Rb-85}+\%_{Rb-87}=100\%\\\\\%_{Rb-85}=100\%-\%_{Rb-87}[/tex]
So we can write:
[tex]86.231=84.911*(100\%-\%_{Rb-87})+86.909*\%_{Rb-87}[/tex]
Solving for the percentage of abundance of Rb-87:
[tex]86.231=84911.00\%-84.911\%_{Rb-87}+86.909*\%_{Rb-87}\\\\\%_{Rb-87}=\frac{86.231-84.911}{-84.911+86.909}\\ \\\%_{Rb-87}=66.1\%[/tex]
Therefore, the percentage of abundance of Rb-85 turns out:
[tex]\%_{Rb-85}=100\%-66.1\%\\\\\%_{Rb-85}=33.9\%[/tex]
Best regards.
Considering the definition of atomic mass, isotopes and atomic mass of an element, the percentages of the isotopes in this sample are:
percent of Rb-87= 66.07%percent of Rb-85 = 33.93%
First of all, the atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.
The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.
On the other hand, the atomic mass of an element is the weighted average mass of its natural isotopes. In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.
In this case, a certain sample of rubidium has just two isotopes, 85Rb (mass = 84.911amu) and 87Rb (mass = 86.909amu). Then, the average mass of lithium can be calculated as:
84.911× percent of Rb-85 + 86.909× percent of Rb-87= 86.231
Since both abundance percentages must be 100%, you can write:
percent of Rb-85 + percent of Rb-87= 100
Then:
percent of Rb-85 = 100% - percent of Rb-87
So, replacing this expression in the first equation:
84.911× (100% - percent of Rb-87) + 86.909× percent of Rb-87= 86.231
Solving:
84.911×100% - 84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231
8491.1% -84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231
-84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231 - 8491.1%
-84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231 - 84.911
1.998× percent of Rb-87= 86.231 - 84.911
1.998× percent of Rb-87= 1.32
percent of Rb-87= 1.32÷ 1.998
percent of Rb-87= 0.6607
percent of Rb-87= 66.07%
Therefore, the percentage of abundance of Rb-85 is:
percent of Rb-85 = 100% - percent of Rb-87
percent of Rb-85 = 100% - 66.07%
percent of Rb-85 = 33.93%
Finally, the percentages of the isotopes in this sample are:
percent of Rb-87= 66.07%percent of Rb-85 = 33.93%Learn more:
brainly.com/question/14403750?referrer=searchResults brainly.com/question/10043246?referrer=searchResults brainly.com/question/15553207?referrer=searchResultsWhich of the scientists reponsible for cell theory would be the most likely to write a book titled cells come from cells
Answer:
Matthias Schleiden and Theodor Schwann. However, many other scientists like Rudolf Virchow contributed to the theory.
Explanation:
Answer:Theodor Shwann
Explanation:
which choice is not an example of a molecule
Mn
O3
KOH
H2S
Answer:
The answer to your question is A | Mn
Which particles affect the stability in of the atom
The stability of an atom is affected by the balance between the electrons, protons, and neutrons in an atom.
What are sub-atomic particles?A particle less than an atom is referred to as a subatomic particle. A subatomic particle can either be an elementary particle, which is not made of other particles, or a composite particle, which is composed of other particles, according to the Standard Model of particle physics.
Particles smaller than an atom are referred to as subatomic particles. The three primary subatomic particles present in an atom are protons, neutrons, and electrons.
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A certain gas obeys the van der Waals equation with a = 0.50 m6 Pa mol−2. Its molar volume is found to be 5.00 × 10–4 m3 mol−1 at 273 K and 3.0 MPa. From this information calculate the van der Waals constant b. What is the compression factor for this gas at the prevailing temperature and pressure?
Answer:
a
The value is [tex]b = 4.61 *10^{-5} \ m^3 /mol[/tex]
b
[tex]Z = 0.66[/tex]
Explanation:
Generally the pressure of the gas is mathematically represented as
[tex]P = \frac{RT}{V_m -b} - \frac{a}{(V_m)^2}[/tex]
Substituting [tex]8.314 \ m^3\cdot Pa\cdot K^{-1}\cdot mol^{-1}[/tex] for R , 273K for T , [tex]5.00 * 10^{-4} m^3[/tex] for [tex]V_m[/tex] , [tex]0.50 \ m^6 \cdot Pa\cdot mol^{-2}[/tex] for a and [tex]3.0 MPa = 3.0*10^{9} \ Pa[/tex] for P
We have
[tex]3*10^6 = \frac{8.314 * 273}{5.00*10^{-4} - b} - \frac{0.50}{(5.00*10^{-4})^2 }[/tex]
=> [tex]b = 4.61 *10^{-5} \ m^3 /mol[/tex]
Generally the compression factor is mathematically represented as
[tex]Z = \frac{P* V_m }{RT}[/tex]
=> [tex]Z = \frac{3.0 *10^{6}* 5.0 *10^{-4} }{8.314 *273}[/tex]
=> [tex]Z = 0.66[/tex]
The mass of the whole watermelon is 300g.
What is the mass of all 6 watermelon slices?
What do sponges eat?
Answer:
crabby patties I'm not good at english probably spelled that wrong
How many moles are there in 2.59x1024 molecules CO2?
Answer:
2.59
x
1024
=
C
O
2
=
Explanation:
1. Convert each of the following into scientific notation.
Answer:
[tex]7.27[/tex] x [tex]10^{2}[/tex]
[tex]1.72[/tex] x [tex]10^{5}[/tex]
[tex]9.84[/tex] x [tex]10^{-4}[/tex]
[tex]2[/tex] x [tex]10^{4}[/tex]
[tex]1.4[/tex] x [tex]10^{0}[/tex]
[tex]2.560[/tex] x [tex]10^{33}[/tex]
Transpiration is the loss of water from the leaves of plants. The stomata of leaves must open to allow
carbon dioxide to enter the leaf for photosynthesis, but when they are open, water vapor escapes into
the atmosphere.
HYPOTHESIS: As the intensity of light is increased, the rate of transpiration will increase, as
measured in by the loss of mass of the plant.
Independent variable:
Dependent variable:
Answer:
Independent variable: The light intensity (what YOU CHANGE)
Dependent variable: The rate of transpiration (what YOU MEASURE)
Independent variable are the light intensity that what we change and dependent variable are the rate of transpiration that what we measure.
What is photosynthesis ?Photosynthesis is the process that can be used by the plants and other animals to covert light energy into the chemical energy. Photosynthesis is the main source of food in the earth.
Photosynthesis is the process in which oxygen is released. For survival oxygen is very important, from this process we obtain sufficient amount of oxygen.
The dependent variable is the rate of transpiration and the independent variable is time.The dependent variable is the rate of transportation because it is depends on the environmental factor the plant is placed.
Thus,Independent variable are the light intensity that what we change and dependent variable are the rate of transpiration that what we measure.
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The United Nations hires a global firm to study digital communications around the world. Here is what that firm wrote based on its research. Many people in the world have little experience with computers, and only one-fifth of the world’s population has Internet access. The differences in the ability to use this technology make it challenging to reach people from around the world. The firm’s findings are best described as the digital divide. inequality divide. Internet divide. computer divide.
Answer:
The answer is digital divide.
Explanation:
Digital divide is the answer because if there is only one-fifth of the world that has computers then the United Nations cannot communicate with everyone ,so there is a digital divide and that is your answer. Also, I took the test and I got the question right.
Answer:
The answer is digital divide.
Explanation:
Digital divide is the answer because if there is only one-fifth of the world that has computers then the United Nations cannot communicate with everyone ,so there is a digital divide and that is your answer. Also, I took the test and I got the question right.
