3/2 x 7/2= 2^x

A. X= 1

B. X= 3

C. X= 5

D. X= 8

Answer:

2/5

Step-by-step explanation:

Answer:

The first statement is true so Shannon is incorrect.

Step-by-step explanation:

Volume of the pyramid with base  20 and h = 6

= 1/3 * base area * height

= 1/3 * 20 * 6

= 40 unit^3.

Answer:

19-73 19-73 and a very nice little

Step-by-step explanation:

19-73 19-73 and he changed

Answer:

Domain: All real numbers

Range: y≤4

The correct option is Option A: [tex]16^{3x/4}[/tex] is equivalent to the expression  [tex](\sqrt[4]{16})^{3x[/tex].

The rules of the exponent are

(a) [tex]a^m*a^n=a^{m+n[/tex]

(b)[tex]a^m/a^n=a^{m-n[/tex]

(c)[tex](a^b)^c=a^{bc}[/tex]

(d) [tex]\sqrt[n]{a}=a^{1/n[/tex]

here the given expression is [tex]16^{3x/4}[/tex]

we can rewrite the expression as

[tex]16^{3x/4}[/tex]

as we know by the rule of the exponent that    [tex](a^b)^c=a^{bc}[/tex]

=[tex](16^{1/4})^{3x[/tex]

as we know by the rule of the exponent  [tex]\sqrt[n]{a}=a^{1/n[/tex]

=[tex](\sqrt[4]{16})^{3x[/tex]

Therefore the correct option is Option A: [tex](\sqrt[4]{16})^{3x[/tex]

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Answer:

6

Explanation:

[tex]\textsf {The range of a data representation refers to difference of the smallest and }\\\textsf {greatest possible values. }[/tex]

[tex]\textsf {Here :}[/tex]

[tex]\textsf {smallest value = 5}\\\textsf {greatest value = 11}[/tex]

[tex]\textsf {Then the range will be :}\\\implies \textsf {greatest value - smallest value}\\\implies \mathsf {11 - 5}\\\implies \mathsf {6}[/tex]

The solution for the given inequality will be x≤ -3 or x≥ 5. Thus, the correct option is B.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

For the given inequality the solution can be found as,

         3|x-1| ≥ 12

         x-1 ≥ 4

         x ≥ 5

         3|x-1| ≥ 12

         - x + 1 ≥ 4

         -x ≥ 3

         x ≤ -3

Hence, the solution for the given inequality will be x≤ -3 or x≥ 5. Thus, the correct option is B.

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Answer:

  256,000

Step-by-step explanation:

If the culture doubles in size every 30 minutes, it doubles 2 times per hour. In 4 hours it will have doubled 2×4 = 8 times. Each doubling multiplies the number by 2, so 8 doublings will multiply the number by 2^8.

The population will be ...

  1000×2^8 = 256,000 . . . bacteria present after 4 hours

The value of x for the equation to the true is 2/3

Given the following functions

f f(x) = −3x + 4 and;

g(x) = 2

If the functions are equal, then;

-3x + 4 = 2

Subtract 4 from both sides

-3x = 2 - 4

-3x = -2

x = 2/3

Hence the value of x for the equation to the true is 2/3

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The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in the opposite side of the axis as if we're seeing it in a mirror.

If you study it more, you will find that it's symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

Thus, if you're reflecting a point (x,y) along the x-axis, then its x abscissa will stay the same but y coordinates will negate.

Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along the y -axis, the resultant image of the point will be (-x,y).

The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.

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The reflection of letter M is (A)

A figure is said to be a reflection of the other figure, then every point in a figure is at equidistant from each corresponding point in another figure.

According to the graph the reflection of Of letter M is with same coordinates but with x as positive and y as negative.

Hence the reflection is (A).

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The function that best models the scenario is as follows;

x < 5 :  C(x) = 3.45x + 1

x ≥ 5  : C(x) = 3x + 1

A local candy shop sells boxes of chocolate for $3.45 each.

This is when the consumer purchase less than 5 boxes of chocolates.

Therefore,

x = number of boxes

when x < 5

C(x) = 3.45x + 1

If a customer purchases five or more boxes, the cost is only $3 per box. Therefore,

when x ≥ 5

C(x) = 3x + 1

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The values of the angles based on the information will be:

Angle 2 = 110°

Angle 3 = 70°

Angle 4 = 70°

From the information given, angle 1 is 110° and the horizontal lines n and m are intersected by lines q and p.

In this case, it should be noted that vertcally opposite angles are equal. Hence, angle 2 is also 110°.

Angle 3 will be:

= 180° - 110° = 70° (angle on a straight line).

Angle 4 will also be 70° as a vertically opposite angle to angle 3.

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Answer:

The values of the angles based on the information will be:

Angle 2 = 110°

Angle 3 = 70°

Angle 4 = 70°

Step-by-step explanation:

Answer:

83 x 391 - 83 x 15 = 83 x (391 - 15)

Step-by-step explanation:

BODMAS is stands for Bracket Of Division Multiplication Addition and Subtraction.

left hand side:

83 × 391 - 83 × ____   = 32453 - 83 × ____

right hand side:

83  × (391 - 15) = 83 × 376 = 31208

equating both sides

32453 - 83 × ____ = 31208

32453 - 31208 = 83 × ____

1245 ÷ 83 = 15

hence the answer is 15.

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Answer:

7/9

Step-by-step explanation:

Divide the numerator and denominator by 4.

28/36 = 7/9

Answer:

7/9

Step-by-step explanation:

28 and 36 are both divisible by 4.

28÷4 is 7 and

36÷4 is 9

28/36 = 7/9

Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about point P at; D: 105°

From the given image, If we connect points C of the blue quadrilateral to point C' of the rotated quadrilateral using the center of rotation P, then we will notice that ∠CPC' will be greater than 90°.

Now, the rotation is counterclockwise and it therefore means that the angle of rotation is will be positive and since ∠CPC' is greater than 90°, then we can say that the only correct option is Option D which is 105°

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Answer:

1a7

Step-by-step explanation:

26+-25=1

The distance Leah would have to walk home is 1.5 miles

From the question, we are to determine the distance Leah will have to walk home

From the given information,

Price of journey in pounds = 3 + 2 × distance in miles

Let the distance be d

Then,

Price of journey in pounds = 3 + 2d

Since Leah has £5, we can write that

5 = 3 + 2d

5 - 3 = 2d

2 = 2d

∴ d = 2/2

d = 1 mile

This means her money can only cover 1 mile

But the journey to her home is 2.5 miles

Therefore, she will have to walk

2.5 mile - 1 mile  = 1.5 miles

Hence, the distance Leah would have to walk home is 1.5 miles

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Answer:

Angles G and H are congruent.

Step-by-step explanation:

Answer: In between the red and yellow ribbons

Step-by-step explanation:

When something is rotated 180 degrees, you basically just mirror it. Since this pinwheel has an uneven amount of ribbons, there isn't a ribbon opposite of it, so it would be between red and yellow.

Answer:

11

Step-by-step explanation:

Answer:

26 gm

Step-by-step explanation:

Tin is   1   out of (9+1)   = 1/10 th

1/10th * 260 gm  =   26 gm

Answer:38.9

Step-by-step explanation:

Answer:

None of the options are correct

О E. 289.2 cm

Step-by-step explanation:

Volume of a cylinder = v = л r² h

л = 3.1416     (aprox)

r = radius

h = height

8177 = 3.1416 * 3² * h

8177 = 3.1416 * 9 * h

8177 = 28.2744 * h

8177/282744 = h

h = 289.2 cm

the conversion is:

0.50 sen /g = 5 RM/kg

First, we know that

1sen = 0.01RM

Then we can change:

0.50 sen /g = 0.50*(0.01 RM) /g = 0.005 RM/g

Now we use the relation:

1g = 0.001kg

So we can rewrite:

0.005 RM/g = 0.005 RM/(0.001kg) = 5 RM/kg

So the conversion is:

0.50 sen /g = 5 RM/kg

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Answer:

1/6

Step-by-step explanation:

As usual in trigonometry, there are so many relationships between the trigonometric functions, there is bound to be more than one method to arrive at the answer.

Knowing values for the sine and cosine function for certain angles on the unit circle proves to be quite helpful.  In general, I recommend 0°, 30°, 45°, 60°, and 90° at a minimum.

Recall the following 6 things:

Knowing these 6 things (4 things from the unit circle, a way to write the tangent function in terms of sine and cosine, and the definition of a squared trig function), we can simplify the given expression down to a single number:

The definition of the tangent squared function is that the output of the tangent function is squared...

[tex]\dfrac{1-\tan^2(30^o)}{1+\tan^2(60^o)}=\dfrac{1-(\tan(30^o))^2}{1+(\tan(60^o))^2}[/tex]

Using fact 5, and turning the tangent function into sines and cosines...

[tex]=\dfrac{1-\left(\frac{\sin(30^o)}{\cos(30^o)}\right)^2}{1+\left(\frac{\sin(60^o)}{\cos(60^o)}\right)^2}[/tex]

Using facts 1-4, and substituting known values for sines and cosines...

[tex]=\dfrac{1-\left(\frac{(\frac{1}{2})}{(\frac{\sqrt{3}}{2})}\right)^2}{1+\left(\frac{(\frac{\sqrt{3}}{2})}{(\frac{1}{2})}\right)^2}[/tex]

Division is multiplication by the reciprocal...

[tex]=\dfrac{1-\left(\frac{1}{2}*\frac{2}{\sqrt{3}}\right)^2}{1+\left(\frac{\sqrt{3}}{2}*\frac{2}{1}\right)^2}[/tex]

Reducing/simplifying common factors of 2...

[tex]=\dfrac{1-\left(\frac{1}{\sqrt{3}}\right)^2}{1+(\sqrt{3})^2}[/tex]

Squaring a square root...

[tex]=\dfrac{1-\left(\frac{1}{3}\right)}{1+(3)}[/tex]

Finding a common denominator...

[tex]=\dfrac{\frac{3}{3}-\frac{1}{3}}{4}[/tex]

Definition of subtracting fractions...

[tex]=\dfrac{\frac{3-1}{3}}{4}[/tex]

Arithmetic...

[tex]=\dfrac{\frac{2}{3}}{4}[/tex]

Division is multiplication by a reciprocal...

[tex]=\dfrac{2}{3}*\dfrac{1}{4}[/tex]

Simplification and reducing the fraction...

[tex]=\dfrac{1}{6}[/tex]

So, [tex]\dfrac{1-\tan^2(30^o)}{1+\tan^2(60^o)}=\dfrac{1}{6}[/tex]

Answer:

Step-by-step explanation:

given

cos(30°) = [tex]\frac{adjacent}{hypotenuse} \\[/tex]

cos(30°) = [tex]\frac{b}{c} \\[/tex]

cos(30°)=[tex]\frac{b}{16}[/tex]

b = 16cos(30°)

b [tex]16(\frac{\sqrt{3} }{2})\\ = 8\sqrt{3}[/tex]

Step-by-step explanation:

x=66°

180-118=62°

180-52+62=66°

hope this helps

Answer:

[tex]\frac{q+p}{2(p-q)}[/tex]

Step-by-step explanation:

[tex]\frac{4(p+q)}{p-q} *\frac{q+p}{8(p+q)}[/tex]

We will cancel out like terms.

[tex]\frac{4}{p-q} *\frac{q+p}{8}\\=\frac{4(q+p)}{8(p-q)} \\=\frac{q+p}{2(p-q)}[/tex]

The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)

The equation can be split as follows:

y = 1 - cos(x)

y = 2 - 2sin²(x)

Next, we plot the graph of the above equations (see graph 1)

Under the domain interval (-π, π), the curves of the equations intersect at:

(-π/3, 0.5) and (π/3, 0.5)

Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)

The equation can be split as follows:

y = 4cos⁴(x) - 5cos²(x) + 1

y = o

Next, we plot the graph of the above equations (see graph 2)

Under the domain interval [0, 2π), the curves of the equations intersect at:

(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

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