4. Three weeks later, you find a scooter on sale for $399.99, which reflects a discount rate of 30%.
What percentage of the original price is $399.99? Show the proportion to solve the equation.
What was the original price? (Hint, you will need to perform subtraction, similar to the
example).

Answer:

15a^5 b^10

Step-by-step explanation:

The product is 15a⁵b¹⁰.

Exponentiation is one of the mathematics operations.

Let mᵃ, where m and a are the real numbers.

And m is multiplied by a times to itself.

So, a is the exponent of m.

When multiplying two terms with the same base, you add the exponents. Therefore:

(3a²b⁷)(5a³b³) = 3 x 5 x a⁵ x b ¹⁰

= 15a⁵b¹⁰.

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Step-by-step explanation:

[tex] = \tan(5\pi) [/tex]

[tex] = \tan(\pi + 4\pi) [/tex]

[tex] = \tan(\pi) [/tex]

[tex] = \tan(180 \degree) [/tex]

[tex] = 0[/tex]

The answer is A.

The probabilities for various binomial distribution have been determined.

The complete question is

About 5% of hourly paid workers in a region earn the prevailing minimum wage or less. A grocery chain offers discount rates to companies that have at least 30 employees who earn the prevailing minimum wage or less. Complete parts (a) through (c) below.

(a) Company A has 285 employees. What is the probability that Company A will get the discount? (Round to four decimal places as needed.)

(b) Company B has 502 employees. What is the probability that Company B will get the discount? (Round to four decimal places as needed.)

(c) Company C has 1033 employees. What is the probability that Company C will get the discount? (Round to four decimal places as needed.)

Probability is a stream in mathematics that study the likeliness of an event to happen .

On the basis of the given data

(a) Let X is a random variable that denotes the number of employees that earn less than prevailing average.

Here X has binomial distribution with

n=285 and p=0.05.

As np and n(1-p) are greater than 5 so using normal approximation X has normal distribution with parameters

μ=  np-285 * 0.05

= 14.25

standard deviation is given by

[tex]\sigma=\sqrt{np(1-p)}=\sqrt{285* 0.05* 0.95}\\\\=3.6793[/tex]

Applying continuity correction.

The z-score for X = 30-0.5 = 29.5 is

[tex]z=\dfrac{29.5-14.25}{3.6793}\\\\=4.14[/tex]

The probability that Company A will get the discount is given by

[tex]P(X\geq 30)=P(z > 4.14)=0.0000[/tex]

(b) Let X is a random variable that denotes the number of employees that earn less than prevailing average.Here X has binomial distribution with

n=502 and p=0.05.

[tex]\rm \mu=np=502* 0.05=25.1[/tex]

standard deviation

[tex]\rm \sigma=\sqrt{np(1-p)}=\sqrt{502\cdot 0.05\cdot 0.95}=4.8831[/tex]

Applying continuity correction.

The z-score for X = 30-0.5 = 29.5 is

[tex]\rm z=\dfrac{29.5-25.1}{4.8831}=0.90[/tex]

The probability that Company B will get the discount is

[tex]P(X\geq 30)=P(z > 0.90)=0.1841[/tex]

(c)Let X is a random variable that denotes the number of employees that earn less than prevailing average.Here X has binomial distribution with

n=1033 and p=0.05.

[tex]\mu=np=1033\cdot 0.05=51.65[/tex]

standard deviation

[tex]\rm \sigma=\sqrt{np(1-p)}=\sqrt{1033*0.05* 0.95}=7.0048[/tex]

Applying continuity correction.

The z-score for X = 30-0.5 = 29.5 is

[tex]\rm z=\dfrac{29.5-51.65}{7.0048}=-3.16[/tex]

The probability that Company C will get the discount is

[tex]\rm P(X\geq 30)=P(z > -3.16)=0.9992[/tex]

Therefore the probabilities for various binomial distribution have been determined.

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Answer:

[tex]x\geq 12[/tex]

Step-by-step explanation:

[tex]-3/4x + 2 \leq -7\\-3/4x \leq -9\\x \geq 12[/tex]

Answer:

JN = 32

Step-by-step explanation:

Δ JMN and Δ JKL are similar ( AA postulate )

then the ratios of corresponding sides are in proportion, that is

[tex]\frac{JM}{JK}[/tex] = [tex]\frac{JN}{JL}[/tex] ( substitute values )

[tex]\frac{24}{33}[/tex] = [tex]\frac{JN}{JN+12}[/tex]

[tex]\frac{8}{11}[/tex] = [tex]\frac{JN}{JN+12}[/tex] ( cross- multiply )

11 JN  = 8(JN + 12)

11 JN = 8 JN + 96 ( subtract 8 JN from both sides )

3 JN = 96 ( divide both sides by 3 )

JN = 32

7 = Tenth

7 is the first decimal of the number making it a tenth.

Answer:

the answer is D)

a multiple of thirty

Answer:

(-2, 1)

Step-by-step explanation:

You can read the solution from graph. The solution is where the two lines intersect. That happens in point (-2, 1).

---

Alternative:

If you want to be sure, you can alway double check by solving the system of equations.

First equation: [tex]y = \frac{1}{2}x + 2[/tex]

Second equation: [tex]y = -\frac{1}{2}x[/tex]

Substituting y in first equation with y from second.

[tex]y = \frac{1}{2}x + 2[/tex]

[tex]-\frac{1}{2}x = \frac{1}{2}x + 2[/tex]

Adding [tex]\frac{1}{2}x[/tex] on both sides.

[tex]-\frac{1}{2}x + \frac{1}{2}x = \frac{1}{2}x + 2 + \frac{1}{2}x[/tex]

[tex]0 = 1x + 2[/tex]

[tex]0 = x + 2[/tex]

[tex]-2 = x[/tex]

Substituting x with -2.

[tex]y = -\frac{1}{2}x[/tex]

[tex]y = -\frac{1}{2}(-2)[/tex]

[tex]y = 1[/tex]

As you see you get the same result as from reading the graph, (-2, 1).

Total area = 104+24 = 128 sq.in ,  Option C is the right answer.

The missing figure is attached with the answer.

The space occupied by a two dimensional figure is called Area.

The figure given in the question can be divided into two figure

A rectangle of 8 * 13 inch

and a triangle of 8 * 6 inch

The area of a rectangle is given by

Length * Breadth

8 * 13

= 104 sq.inch

The area of the triangle is given by

(1/2) * base * height

= (1/2) * 8 * 6

= 24 sq.inch

Total area = 104+24 = 128 sq.in

Therefore Option C is the right answer.

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We conclude that 515 student tickets were sold, and 58 adult tickets.

Let's define the variables:

We can write the system of equations:

x = 9*y - 7

x*5 + y*8 = 3039

Now we can replace the first equation into the second one:

(9*y - 7)*5 + y*8 = 3039

45y + 8y  - 35 = 3039

53y = 3074

y = 3074/53 = 58

Now we can use:

x = 9y - 7 = 9*58 - 7 = 515

We conclude that 515 student tickets were sold, and 58 adult tickets.

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The inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

a(n) =  3n - 30

To find make subject n and solve

a(n) + 30 = 3n

[tex]\rm n = \dfrac{a(n) + 30}{3}[/tex]

Plug n = n(a) and a(n) = a

[tex]\rm n(a) = \dfrac{a + 30}{3}[/tex]

Thus, the inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.

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Answer:

hope it helps.good day

in case you don't understand anywhere feel free to ask

Answer:

(x-1) and (x-5)

Answer:

3 months

Step-by-step explanation:

The first runner: $110 + $45 = $155 starting out, plus 25x for $25 each month.

The second runner: $50 starting out, plus 60x for $60 each month.

To find out when both runners have the same amount of money, we will set the expressions equal to each other and solve.

155 + 25x = 60x + 50

105 = 35x

x = 3

Brainliest, please :)

The number of students will be 642 and the number of the adults will be 59.

The solution of the equation means the value of the unknown or variable.

Tickets for a soccer game cost $5 for students and $8 for adults.

The number of students was 7 less than 11 times the numbers of adults.

The amount of the money from tickets was 3682.

Let x be the number of students and y be the number of the adults.

Then the equation will be

x = 11y – 7  …1

5x + 8y = 3682 …2

From equation 1 and 2, we have

5(11y – 7) + 8y = 3682

55y + 8y – 35 = 3682

                63y = 3717

                    y = 59

Then the value of x will be

x = 11 × 59 – 7

x = 642

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Answer:

[tex]\left[\begin{array}{cccc}-1\\1\\1\\0\end{array}\right][/tex], [tex]\left[\begin{array}{cccc}0\\2\\0\\1\end{array}\right][/tex] Are two vectors which are basis of null space of A

Step-by-step explanation:

Basis of a null space is a vector matrix which when multiplied by the reduced echelon form of the matrix gives null matrix or 0 matrix

So, to find the reduced echelon form we apply the row operations :

R₁ = R₁/2

[tex]\left[\begin{array}{cccc}1&-2&3&4\\2&-1&3&2\\4&-5&9&10\\0&-1&1&2\end{array}\right][/tex]

R₂ = R₂ - 2R₁

[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&3&-3&-6\\4&-5&9&10\\0&-1&1&2\end{array}\right][/tex]

R₃ = R₃ - 4R₁

[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&3&-3&-6\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]

R₂ = R₂/3

[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&1&-1&-2\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]

R₁ = R₁ + 2R₂

[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]

R₃ = R₃ - 3R₂

[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&-1&1&2\end{array}\right][/tex]

R₄ = R₄  + R₂

[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&0&0&0\end{array}\right][/tex]

which is a reduced echelon form of the matrix A

now ,

[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&0&0&0\end{array}\right][/tex]    [tex]\left[\begin{array}{cccc}x1\\x2\\x3\\x4\end{array}\right][/tex]  [tex]=\left[\begin{array}{cccc}0\\0\\0\\0\end{array}\right][/tex]

therefore,

x₁ + x₃ = 0

x₁  = -x₃

x₂ - x₃ - 2x₄ = 0

x₂ = x₃ + 2x₄

so now replacing values of x₁ , x₂ in the vector matrix

[tex]\left[\begin{array}{cccc}-x3\\x3 + 2x4\\x3\\x4\end{array}\right][/tex]

we can write the above matrix as,

[tex]x3\left[\begin{array}{cccc}-1\\1\\1\\0\end{array}\right][/tex] [tex]+ x4\left[\begin{array}{cccc}0\\2\\0\\1\end{array}\right][/tex]

therefore we can say that above mentioned vector matrices are the basis of the null space of matrix A

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Answer:

C.  It is in Quadrant I

D.  It starts at the origin

Step-by-step explanation:

Parent function:  [tex]f(x)=\sqrt{x}[/tex]

Domain: set of all possible input values (x-values)

As the square root of a negative number does not exist in the set of Real Numbers, the domain for the parent function is:

Range: set of all possible output values (y-values)

As the domain of the parent function is x ≥ 0, the range will be:

As the range and domain both begin at zero, the graph of the parent function starts at the origin (0, 0).

Quadrant: a region of the Cartesian plane formed when the x-axis and y-axis intersect each other.

Quadrant I:  (x, y)

Quadrant II:  (-x, y)

Quadrant III: (-x, -y)

Quadrant IV:  (x, -y)

Therefore, as the range and domain of the parent function are positive, the graph is in Quadrant I.

The correct answer is option A which is the number of cars sold for the price range of $4000 to $4999 will be 15.

A histogram is a graph for the representation of the data on the plot of the rectangular boxes. It has the data sets on the horizontal and the vertical axes.

As we can see from the histogram data we will conclude that the price range of $4000 to $4999 is shown by the third block and this third block reaches the height of 15.

Therefore the correct answer is option A which is the number of cars sold in the price range of $4000 to $4999 will be 15.

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The statements which are true among the answer choices are;

In the concept of straight line graphs (linear graphs) the statements are evaluated as follows;

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Answer:

C

Step-by-step explanation:

C is the correct answer as both triangles have a similar angle of 105⁰ and both side lengths of triangle ABC are being divided by 4 to have the same two side lengths as triangle DEF

The triangles ΔABC and ΔDEF are similar triangles by SAS theorem

If two triangles' corresponding angles are congruent and their corresponding sides are proportional, they are said to be similar triangles. In other words, similar triangles have the same shape but may or may not be the same size. The triangles are congruent if their corresponding sides are also of identical length.

Corresponding sides of similar triangles are in the same ratio. The ratio of area of similar triangles is the same as the ratio of the square of any pair of their corresponding sides

Given data ,

Let the first triangle be ΔABC

The measure of side AB = 16

The measure of side AC = 36

And , the measure of ∠ABC = 105°

Let the first triangle be ΔDEF

The measure of side DE = 16

The measure of side DF = 36

And , the measure of ∠DEF = 105°

Now , the ratio of sides of the triangles is given by

AB / DE = AC / DF

4/16 = 9/36

1/4 = 1/4

So , corresponding sides of similar triangles are in the same ratio

And , the measure of angles = 105°

Therefore , by SAS , Two sides are equal and the angle between the two sides is equal (SAS: side, angle, side)

Hence , they are similar triangles

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multiply the actual length by the scale:

9 x 1/12 = 9/12 = 3/4

Answer: 3/4

Answer:

50 people are working in the office

Answer:

It makes sense for Phil to sell his products online.

Step-by-step explanation:

Answer:

C) 20cm

Step-by-step explanation:

Perimeter is the distance around the edge of the shape.

8 + 7 + 5 = 20

Answer:

20 is answer

Step-by-step explanation:

as perimeter= sum of all side

= 8 +7+5=2ocm

Answer:

it is 2 spaces away. a positive number from zero would be +2 and a negative number would be -2

Step-by-step explanation:

Answer:

28 cm

Step-by-step explanation:

The corner to corner cut is a hypotenuse. We know one leg, 45cm. So use Pythagorean theorem to solve for the other leg. See image.

Yes, by using the factor theorem and synthetic division method, x + 3 is a factor of -x³ + 4x - 15.

According to the factor theorem, a given polynomial of f(x) has a factor if and only if f=0.

From the given information:

Using the synthetic division method:

[tex]\mathbf{= \dfrac{-x^3+4x - 5}{x+3} }[/tex]

[tex]\mathbf{\implies \dfrac{-(x+3) (x^2-3x + 5)}{x+3} }[/tex]

Cancel out the common factors, we have:

[tex]\mathbf{\implies - (x^2-3x + 5)}[/tex]

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