[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\texttt{Yes, there's a local maximum at -9,} [/tex] [tex] \texttt{and it is 9} [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
By Observing the graph, we can easily conclude that there's a local maxima at -9
[tex] \textsf{And f(-9) = 9} [/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
I need help with number 10 please
Answer:
Liz
Step-by-step explanation:
if the chart is correct only 3 people spent more than 2 1/2 hours on homework when 9 people spent less than 2 1/2 hours on homework
Given market demand Qd=50-p, and market supply p=Qs+5.what would be the state of the market if market price was fixed at Birr 25 per unit?
The state of the market if market price was fixed at Birr 25 per unit is excess demand
Quantity demandedQd = 50 - p
p = Qs + 5
p - 5 = Qs
if market price was fixed at Birr 25 per unit?
Qd = 50 - p
= 50 - 25
Qd = 25
Qs = p - 5
= 25 - 5
Qs = 20
The state of the market if market price was fixed at Birr 25 per unit is excess demand (demand greater than supply) leading to an increase in price.
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Find the midpoint of the line segment whose endpoints are given. (9,3), (10,- 10)
Answer:
Step-by-step explanation:
(xm , ym ) = x1 + x2 / 2 and y1 + y2 / 2
= 9 +3 / 2 = 10 -10 / 2
= 12/2 = 0/2
= 6 = 0
So midpoints are (6 , 0)
Answer:
midpoint = [tex](9\frac{1}{2} , -3\frac{1}{2} )[/tex]
Step-by-step explanation:
To find the midpoint of a line segment, you have to find the average of the x and y-values of the end-points, i.e., add the x-coordinate values and divide the answer by 2, and do the same for the y-coordinate values.
• midpoint = [tex](\frac{x_{2} + x_1}{2}, \frac{y_2 + y_1}{2} )[/tex]
= [tex](\frac{9 + 10}{2}, \frac{3 + (-10)}{2} )[/tex]
= [tex](\frac{19}{2}, \frac{-7}{2} )[/tex]
= [tex](9\frac{1}{2} , -3\frac{1}{2} )[/tex]
What is the value for y?
What is the value of x?
Enter your answer in the box.
x =
Equiangular triangle A B C. Angles A, B, and C are marked congruent. The length of side A C is labeled as 5 x minus 22. The length of side A B is labeled as 4 x minus 10. The length of side B C is labeled as 3 x plus 2.
Enter your answer in the box.
y =
An isosceles triangle A B C with horizontal base B C and vertex A is above the base. Side A C and C B are labeled with single tick mark. All the three angles are labeled. Base angles C A B is labeled as 50 degrees and angle C B A is labeled as 2x degrees. The angle A C B is labeled left parenthesis 5 y plus 10 right parenthesis degrees.
1. The value of x in the equilateral triangle is: 12
2. x = 25; y = 14
What is an Equilateral Triangle?If a triangle has three sides that are marked congruent, then the triangle is an equilateral triangle.
1. Since triangle ABC is an equilateral triangle and its sides are equal, therefore:
5x - 22 = 3x + 2 [congruent sides]
Solve for x
5x - 3x = 22 + 2
2x = 24
2x/2 = 24/2
x = 12
The value of x is: 12.
2. Base angles of an isosceles triangle are congruent, therefore:
2x = 50
x = 50/2
x = 25
Thus, using the triangle sum theorem, we have:
2x + 50 + 5y + 10 = 180
Plug in the value of x and find y
2(25) + 50 + 5y + 10 = 180
50 + 50 + 5y + 10 = 180
110 + 5y = 180
5y = 180 - 110
5y = 70
y = 70/5
y = 14
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whats the answer? :(
Answer:
D) 8[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
5[tex]\frac{2}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex] = 8[tex]\frac{1}{2}[/tex]
Statement: "Three less than four times a number is greater
than or equal to 41."
Answer:
x≥11
Step-by-step explanation:
4x-3≥41
4x≥41+3 -44
x≥44/4 = 11
Question
Find the distance between the points (-5, 8) and (-3,0).
To calculate the distance between two points we use this formula:
[tex] \boxed{ \boxed{{d \: = \: \sqrt{(x_2 \: - \: x_1)^{2} \: + \: (y_2 \: - \: y_1)^{2} } }}}[/tex]
______________________We organize the values:x₁ = -5 x₂ = -3 y₁ = 8 y₂ = 0______________________
We apply the values already obtained to the formula to get the distance:
[tex]d \: = \: \sqrt{( - 3 \: - \:( - 5))^{2} \: + \: (0 \: - \: 8)^{2} }[/tex]
[tex]d \: = \: \sqrt{( - 3 \: - \: ( - 5))^{2} \: + \: ( - 8)^{2} }[/tex]
[tex]d \: = \: \sqrt{( - 3 \: + \: 5) ^{2} \: + \: 64 } [/tex]
[tex]d \: = \: \sqrt{ {2}^{2} \: + \: 64 } [/tex]
[tex]d \: = \: \sqrt{4 \: + \: 64} [/tex]
[tex]d \: = \: \sqrt{68} [/tex]
[tex]d \: = \boxed{ \bold{ \: 2 \sqrt{17} \: units}}[/tex]
Answer:[tex] \huge{\boxed{ \bold{2 \sqrt{17} \: units }}}[/tex]
MissSpanishJack has a rectangular piece of land, the area of which is represented by a₁ = 9.5%. His brother has a different rectangular piece of land, the area of which is represented by a2 = 14-). Let a represent the area in square meters and /represent the length in meters of the pieces of land. The two equations plotted on a graph meet at a point as shown in the image.
Answer:
yea that’s right
Step-by-step explanation:
226,710 - 724,435 =
How to work this out without calculator
help
You invest $1000 in an account that has an annual interest rate of 4%, compounded monthly for 12 years. What is the equivalent interest rate and how many times will the money be compounded?
The equivalent interest rate is 4.07%.
The money will be compounded 12 times.
What is the equivalent interest rate?
The equivalent interest rate is the actual interest rate that an account earns after accounting for number of compounding.
Effective interest rate = (1 + APR / m ) ^m - 1
M = number of compounding
(1 + 0.04/12)^12 - 1 = 4.07%
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Which of the following linear equations represents the data chart?
X Y
1 6
2 5
3 4
4 3
y=x+5
y=x+3
y = -x + 7
None of these choices are correct.
Answer: y = -x + 7
Step-by-step explanation:
The slope is [tex]\frac{5-6}{2-1}=-1[/tex], so we know the equation is of the form [tex]y=-x+b[/tex].
Substituting in the coordinates (1,6) to find b,
[tex]6=-1+b\\\\b=7[/tex]
Thus, the equation is y = -x + 7
Find how many numbers between 23^2 and 25^2.
Answer:
Step-by-step explanation:
We know that, 252 = 625
And, 262 = 676
Now, 676 - 625 = 51
So, there are 51 - 1 = 50 numbers lying between 252 and 262
What is one possible value of 2x
Answer:
really good
Step-by-step explanation:
thanks for your help you with that do not have a copy of the receipt for your time to help you with the2
What is the equation of the line that is perpendicular to y=x+4 and that passes through (5,-4)?
--5v-20
K
Perpendicular lines have slopes that are negative reciprocals of each other, so since the slope of the given line is 1, the slope of the line we want to find is -1.
Substituting into point-slope form,
[tex]y+4=-1(x-5)\\\\y+4=-x+5\\\\\boxed{y=-x+1}[/tex]
Find all real zeros of the function.
Answer:
Zeros: 0, 1, and 7
Step-by-step explanation:
Given function: f(x) = 3x(x - 1)²(x - 7)²
To find the zeros (also known as the x-intercepts) of the function, first substitute f(x) = 0 into the equation and simplify.
1. Substitute f(x) = 0:
[tex]\sf f(x) = 3x(x - 1)^2(x - 7)^2\\\\\Rightarrow 0 = 3x(x - 1)^2(x - 7)^2[/tex]
2. Divide both sides by 3:
[tex]\sf \dfrac{0}{3} = \dfrac{3x(x - 1)^2(x - 7)^2}{3}\\\\\Rightarrow 0=x(x-1)^2(x-7)^2[/tex]
3. Separate into possible cases:
[tex]\sf a)\ x = 0\\b)\ (x - 1)^2 = 0\\c)\ (x - 7)^2 = 0[/tex]
4. Simplify:
[tex]\sf a)\ x = 0\ \textsf{[ already simplified ]}[/tex]
[tex]\sf b)\ (x - 1)^2=0\ \textsf{[ take the square root of both sides ]}\\\\\sqrt{(x - 1)^2}=\sqrt{0}\\\\\Rightarrow x-1=0\ \textsf{[ add 1 to both sides ]}\\\\x-1+1=0+1\\\\\Rightarrow x=1[/tex]
[tex]\sf c)\ (x - 7)^2=0\ \textsf{[ take the square root of both sides ]}\\\\\sqrt{(x - 7)^2}=\sqrt{0}\\\\\Rightarrow x-7=0\ \textsf{[ add 7 to both sides ]}\\\\x-7+7=0+7\\\\\Rightarrow x=7[/tex]
Therefore, the zeros of this function are: 0, 1, and 7.
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solve for x -
[tex]\bold{x {}^{2} - 4 = 0}[/tex]
ty! ~
Answer:
x² - 4 = 0
x² = 4
x =± √4
x = +2 or x = -2.
Answer:
2 and -2 (±2)
Step-by-step explanation:
Step 1: Move -4 to the other side of the equal sign; we get x² = 4.
Step 2: A lot of people miss the negative answer! The square root of 4 is equal to both positive 2 and negative 2.
Hope this helped! Please mark me as Brainliest b/c I really need it!!!What number comes next in the sequence?
1, 1, 2, 3, 5, 8, 13, 21, 34, ?
Answer:
55
Step-by-step explanation:
1+1 = 2
1+2 = 3
2+3 = 5
3+5 = 8
5+8 = 13
8+13 = 21
13+21 = 34
21 +34 = 55
PLEASE GIVE BRAINLIEST
Dwayne is selling hamburgers and cheeseburgers. he has 100 burger buns. each hamburger sells for $3, and each cheeseburger sells for $3.50. which system of inequalities represents the number of hamburgers, h, and the number of cheeseburgers, c, he must sell to have sales of at least $80? h c ≤ 80 3h 3.5c ≤ 100 h c ≤ 80 3h 3.5c ≥ 100 h c ≤ 100 3h 3.5c ≤ 80 h c ≤ 100 3h 3.5c ≥ 80
Let h represent hamburgers and c represent cheeseburgers
h + c ≤ 100 - The number of burgers sold
3h + 3.5c ≥ 80 - Amount that each burger sells for
Solve the linear programming problem.
Minimize and maximize
P = 10x + 5y
Subject to
2x+3y 230
2x+y ≤ 26
-2x+3y ≤ 30
x, y 20
The minimized value is 50 and the maximized value is 130
How to minimize and maximize the function?The objective function is:
P = 10x + 5y
Subject to
2x+3y ≤30
2x+y ≤ 26
-2x+3y ≤ 30
x, y >0
Next, we plot the graph of the constraints (see attachment)
From the graph, the vertices of the feasible regions are:
(0, 10),(12, 2) and (6,14)
Substitute these values in P = 10x + 5y
P = 10(0) + 5(10) = 50
P = 10(12) + 5(2) = 130
P = 10(6) + 5(14) = 130
Hence, the minimized value is 50 and the maximized value is 130
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6z + 10= -2 solve this problem
Answer:
z = -2
Step-by-step explanation:
Answer:
[tex]\boxed{\bf z = - 2}[/tex]
Step-by-step explanation:
[tex]\bf 6z + 10 = - 2[/tex]
Subtract 10 from both sides.
[tex]\bf 6z + 10 - 10= - 2 - 10[/tex]Simplify.
[tex]\bf 6z = - 12[/tex]Divide both sides by 6.
[tex]\bf \cfrac{6z}{6} = \cfrac{ - 12}{6} [/tex]Simplify.
[tex]\bf z = - 2[/tex]_________________________
I will give lots of points please help
Answer:
a) 81π in³
b) 27 in³
c) divide the volume of the slice of cake by the volume of the whole cake
d) 10.6%
e) see explanation
Step-by-step explanation:
Part (a)The cake can be modeled as a cylinder with:
diameter = 9 inheight = 4 in[tex]\sf Radius=\dfrac{1}{2}diameter \implies r=4.5\:in[/tex]
[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]
[tex]\begin{aligned}\sf \implies \textsf{Volume of the cake} & =\pi (4.5)^2(4)\\ & = \sf \pi (20.25)(4)\\ & = \sf81 \pi \:\: in^3\end{aligned}[/tex]
Part (b)[tex]\begin{aligned}\textsf{Circumference of the cake} & = \sf \pi d\\& = \sf 9 \pi \:\:in\end{aligned}[/tex]
If each slice of cake has an arc length of 3 in, then the volume of each slice is 3/9π of the entire volume of the cake.
[tex]\begin{aligned}\implies \textsf{Volume of slice of cake} & = \sf \dfrac{3}{9 \pi} \times \textsf{volume of cake}\\\\& = \sf \dfrac{3}{9 \pi} \times 81 \pi\\\\& = \sf \dfrac{243 \pi}{9 \pi}\\\\& = \sf 27\:\:in^3\end{aligned}[/tex]
Part (c)The volume of each slice of cake is 27 in³.
The volume of the whole cake is 81π in³.
To calculate the probability that the first slice of cake will have the marble, divide the volume of a slice by the volume of the whole cake:
[tex]\begin{aligned}\implies \sf Probability & = \sf \dfrac{27}{81 \pi}\\\\& = \sf 0.1061032954...\\\\ & = \sf 10.6\% \:\:(1\:d.p.)\end{aligned}[/tex]
Part (d)Probability is approximately 10.6% (see above for calculation)
Part (e)If the four slices of cake are cut and passed out before anyone eats or looks for the marble, the probability of getting the marble is the same for everyone. If one slice of cake is cut and checked for the marble before the next slice is cut, the probability will increase as the volume of the entire cake decreases, until the marble is found. So it depends upon how the cake is cut and distributed as to whether Hattie's strategy makes sense.
Which expression is equivalent to this quotient?
Answer: C
Step-by-step explanation:
[tex]\frac{3x^{2}-3}{x^{2}+3x}=\frac{3(x^{2}-1)}{x(x+3)}=\frac{3(x-1)(x+1)}{x(x+3)}[/tex]
So, the original fraction is equal to
[tex]\frac{\frac{3(x-1)(x+1)}{x(x+3)}}{\frac{x+1}{x(x+3)}}=\boxed{3(x-1)}[/tex]
A kitchen measures 20 feet long and 10 feet wide. A scale drawing is made using a scale factor of 124.
What is the length of the kitchen in the scale drawing?
5/12
5/6
5/4
Drag and drop a number to correctly complete the statement.
The length of the kitchen in the scale drawing is Response area ft.
The length of the kitchen in the drawing using the scale factor is: B. 5/6.
How to Find Length Using Scale Factor?We are given a scale factor of 1:24.
Let the length of the kitchen in the drawing = x
Actual length of kitchen = 20 ft.
Using the scale factor, we have:
1/24(20) = 20/24
= 5/6
The length of the kitchen in the drawing is: B. 5/6.
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Plot the complex number and find its absolute value 2−i
The absolute value of the complex number is √2. The graph is plotted and attached.
What is the complex number?A complex number is one that has both a real and an imaginary component, both of which are preceded by the letter I which stands for the square root of -1.
The given complex number as;
2−i
The absolute value is found as;
[tex]\rm R = \sqrt{1^2 +(-1)^2 } \\\\ R = \sqrt 2[/tex]
The graph for the complex number is attached.
Hence the absolute value of the complex number is √2.
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e total cost, in dollars, for a company to produce r headsets per day is modeled by the function C,
where C(r) = (-5)2 + 35 for 5 < r ≤ 25. The company sells each headset for $20. On one day, the
company produced 15 headsets. According to the model, what will be the profit on the sale of these
headsets? (Profit equals total sales minus total cost.)
O $215
O $225
O $240
O $300
‐10+35=25 and 25 × 20=300
Simplify the following expression to its simplest form
Step-by-step explanation:
[tex] \sin(\pi - x) + \tan(x) \cos(x) (x - \frac{\pi}{2} [/tex]
[tex] \sin( - x + \pi ) + \tan(x) ( \cos(x - \frac{\pi}{2} ) )[/tex]
Sin is odd function, so if you add pi to it, it would become switch it sign.
[tex] - \sin( - x) + \tan(x) \cos(x - \frac{\pi}{2} ) [/tex]
Also since sin is again, a odd function, we can just multiply the inside and outside by -1, and it would stay the same.
[tex] \sin(x) + \tan(x) \cos(x - \frac{\pi}{2} ) [/tex]
Cosine is basically a sine function translated pi/2 units to the right or left so
[tex] \sin(x) + \tan(x) \sin(x) [/tex]
[tex] \sin(x) ( 1 + \tan(x) )[/tex]
FAST!
A right rectangular prism has a square base and a height of 2.5 meters. If the length of a side of the square base is 4 meters, what is the volume of the prism?
Answer:
69 there hope it helps ;)
Step-by-step explanation:
420
Math: One to One function...help!
A one-to-one function has an inverse. The inverse is another function that undoes the action of the first one, so if we evaluate a function [tex]f[/tex] at some point [tex]x[/tex] to get the number [tex]f(x)[/tex], evaluating the inverse at [tex]f(x)[/tex] will recover the original input [tex]x[/tex]. In other words,
[tex]f^{-1}(f(x)) = x[/tex]
The process works in the opposite direction, too:
[tex]f\left(f^{-1}(x)\right) = x[/tex]
From the given definition of [tex]g[/tex], we have [tex]g(-4) = 3[/tex], so taking inverses on both sides, we find
[tex]g(-4) = 3 \implies g^{-1}(g(-4)) = g^{-1}(3) \implies \boxed{g^{-1}(3) = -4}[/tex]
Given [tex]h(x)=2x-13[/tex], evaluating [tex]h[/tex] at its inverse will recover [tex]x[/tex], so that
[tex]h\left(h^{-1}(x)\right) = x \implies 2h^{-1}(x) - 13 = x \implies \boxed{h^{-1}(x) = \dfrac{x+13}2}[/tex]
[tex](h\circ h^{-1})(x)[/tex] is another way of writing the compound function [tex]h\left(h^{-1}(x)\right)[/tex]. As already discussed, this reduces to [tex]x[/tex], so
[tex]\boxed{\left(h\circ h^{-1}\right)(-9) = -9}[/tex]
6(2x² - 5) = [?]
x = -3
x = -3
[tex]6( {2x}^{2} - 5) \\ \\ 6(2 \times { (- 3)}^{2} - 5) \\ \\ 6(2 \times ( 9) - 5) \\ \\ 6( 18 - 5) \\ \\ 6 \times ( 13) \\ \\ 78.[/tex]
If the odds against an event are 3:5, then the probability that the event will fail to occur is
Answer:
3/8
Step-by-step explanation:
probability = wanted outcomes / total outcomes
odds = wanted outcomes / unwanted outcomes
Odds of 3:5 losing means 3 losing outcomes and 5 winning outcomes.
The total outcomes is 8
The probability of losing which is the probability that the event will fail to occur is 3/8.