5. A uniform solid ring of mass M = 10 kg and radius R = 2 m is initially rotating in mid-air with angular speed 20 rad/s [the Before state in figure (I) below]. It is then placed in contact with a surface (assume that the surface immediately feels the full weight of the ring). (1) M Before Wi (II) wf V Ө ə Ө After Ө wf H ? (a) What kind of frictional force acts on the ring upon contact with the surface? (b) If the ring begins to roll smoothly to the right with speed v = 10 m/s after 5 seconds of contact (the After state), find the coefficient of friction corresponding to the frictional force you mentioned in (a). (c) What is the increase in the thermal energy of the ring/surface system from right before the ring contacts the surface, to when the ring starts to roll smoothly? The ring then rolls smoothly up a ramp of 0 = π/6 rad and H = 5 m [see figure (II)] (d) What is the horizontal distance, from the end of the ramp, at which the ring lands?
Answers
(a) The kind of frictional force acts on the ring upon contact with the surface is kinetic friction before rolling and afterwards it is static friction.
(b) If the ring begins to roll smoothly to the right with speed v = 10 m/s after 5 seconds of contact (the After state), the coefficient of friction corresponding to the frictional force is 0.612
(c) The increase in the thermal energy of the ring/surface system from right before the ring contacts the surface, to when the ring starts to roll smoothly is 7500 J.
(d) The horizontal distance, from the end of the ramp, at which the ring lands is 7.78 m
What is frictional force?When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction force.
Given is a uniform solid ring of mass M = 10 kg and radius R = 2 m is initially rotating in mid-air with angular speed 20 rad/s [the Before state in figure (I) below]. It is then placed in contact with a surface (assume that the surface immediately feels the full weight of the ring).
(a) The kind of frictional force acts on the ring upon contact with the surface is kinetic friction before rolling and afterwards it is static friction.
(b) angular frequency = velocity / radius
ωf = 10/2 = 5 rad/s and ωi = 20 rad/s
Angular acceleration, α = ωf - ωi /t
Put the values, we get
α = -15/5 = -3 rad/s²
Coefficient of friction, μ = a/g = rα/g
Plug the values, we get
μ = 0.612
Thus, the coefficient of friction corresponding to the frictional force is 0.612.
(c) The energy lost = heat generated
energy lost = 1/2 Iω² + 1/2 Mv²
energy lost = 1/2 MR²ω² + 1/2 Mv²
Plug the values, we get
energy lost = 7500 J
Thus, the increase in the thermal energy is 7500 J.
(d) The horizontal distance, from the end of the ramp, at which the ring lands
s= (v- 2gH) sin2θ /g
s = (10 - 2x (-9.81)x5 ) sin (2x π/6) / 9.81
s = 7.78m
Thus, the horizontal distance is 7.78 m
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Related Questions
A single Oreo cookie provides 53 kcal of energy. An athlete does an exercise that involves repeatedly lifting (without acceleration) a 100-kilogram weight 2-decimeters above the ground with an energy efficiency of 25%. How many repetitions can she do with the energy supplied from a single Oreo cookie? What happens to the number of repetitions that can be done if the efficiency increases?
Answers
Answer:
Approximately [tex]325[/tex] (rounded down,) assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].
The number of repetitions would increase if efficiency increases.
Explanation:
Ensure that all quantities involved are in standard units:
Energy from the cookie (should be in joules, [tex]{\rm J}[/tex]):
[tex]\begin{aligned} & 53\; {\rm kCal} \times \frac{1\; {\rm kJ}}{4.184\; {\rm kCal}} \times \frac{1000\; {\rm J}}{1\; {\rm kJ}} \approx 2.551 \times 10^{5}\; {\rm J} \end{aligned}[/tex].
Height of the weight (should be in meters, [tex]{\rm m}[/tex]):
[tex]\begin{aligned} h &= 2\; {\rm dm} \times \frac{1\; {\rm m}}{10\; {\rm dm}} = 0.2\; {\rm m}\end{aligned}[/tex].
Energy required to lift the weight by [tex]\Delta h = 0.2\; {\rm m}[/tex] without acceleration:
[tex]\begin{aligned} W &= m\, g\, \Delta h \\ &= 100\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times 0.2\; {\rm m} \\ &= 196\; {\rm N \cdot m} \\ &= 196\; {\rm J} \end{aligned}[/tex].
At an efficiency of [tex]0.25[/tex], the actual amount of energy required to raise this weight to that height would be:
[tex]\begin{aligned} \text{Energy Input} &= \frac{\text{Useful Work Output}}{\text{Efficiency}} \\ &= \frac{196\; {\rm J}}{0.25} \\ &=784\; {\rm J}\end{aligned}[/tex].
Divide [tex]2.551 \times 10^{5}\; {\rm J}[/tex] by [tex]784\; {\rm J}[/tex] to find the number of times this weight could be lifted up within that energy budget:
[tex]\begin{aligned} \frac{2.551 \times 10^{5}\; {\rm J}}{784\; {\rm J}} &\approx 325 \end{aligned}[/tex].
Increasing the efficiency (the denominator) would reduce the amount of energy input required to achieve the same amount of useful work. Thus, the same energy budget would allow this weight to be lifted up for more times.
What are some words that have changed meaning due to technological advances in the last 20 years?
Answers
Some words that have changed meaning due to technological advances are dial, type, tweet, drone, and spam.
The value of acceleration due to gravity (g) on Pluto is about 0.61 meters/second2. How much will an object that weighs 250 newtons on Earth weigh on Pluto? Note that the value of acceleration due to gravity on Earth is 9.8 meters/second2.
Answers
The weight of the object on pluto will be 15.56 N
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Given data;
[tex]\rm g_e[/tex] is the acceleration due to gravity on earth.
m is the mass of an object
[tex]\rm g_p[/tex] is the acceleration due to gravity on pluto.
[tex]\rm W_e[/tex] is the weight of the object on earth
[tex]\rm W_ p[/tex] is the weight of an object on pluto
The mass of the object on the earth's surface is found as;
We = m × ge
m = W / ge
m = 250 / 9.81
m = 25.51 kg
The weight of the object on pluto.
Wp = m × gp
Wp = 25.51 kg × 0.61 m/s²
Wp =15.56 N.
Hence the weight of the object on pluto will be 15.56 N
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Answer: B.
15.6 newtons
Explanation: edmentum
A rocket is fired with an initial Velocity OF 100m/s at an angle OF 55 above the horizontal, It explodes on the mountain Side 12s after its Firing What is x-and y-coordinates of the rocket relative to its Firing point?
Answers
Answer:
( 688.29 , 276.66 ) meters
Explanation:
Break into horizontal and vertical components
x = 100 cos 55 = 57.36 m/s
the x coordinate is then 12 seconds * 57.36 m/s = 688.29 meters
y coordinate is a bit more complex because of the curved path due to gravity
Original y velocity = 100 sin 55
y = vo t - 1/2 (9.81)(t^2)
y = 100 sin 55 (12) - 1/2 (9.81) (12)^2
yf = 276.66 meters
state how the centripetal force is provided in a c held on a playground roundabout
Answers
The centripetal force is obtained by its formulas is,[tex]\rm F_C= \frac{mv^2}{r}[/tex]
What is centripetal acceleration?The acceleration needed to move a body in a curved way is understood as centripetal acceleration.
The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.
The formula for the centripetal force is ;
[tex]\rm F_C= \frac{mv^2}{r}[/tex]
Where,
r is the radius
v is the linear speed
m is the mass of an object
Hence, the centripetal force obtained by its formulas as,[tex]\rm F_C= \frac{mv^2}{r}[/tex]
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A body moves in an x-y plane with a velocity vm/s. The component of v are Vx=5m/s, Vy=7m/s along x and y axis respectively. What is the magnitude and direction of the velocity
Answers
the answer is in the picture ok
good luck don't worry it's a correct
#carry on learning
identity the sentence that uses quotas and interviews.
A. let us all learn from the history of our country.
B. the guests arrived on time.
C. "My dream is to build my own mansion, "Adrian answered.
D. Teacher Cellyn Kyre ensures that her classroom is always ready for the face to face classes
Answers
Teacher Cellyn Kyre ensures that her classroom is always ready for the face to face classes is the sentence used in quotas and interviews.
What is interview?Interview is the examination of the candidate from which a person identifies the candidate is fit for the organization o r not. Maximum interview happened between the interviewer and the candidate. or sometime more people can also be present.
Thus, option D is correct.
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After the terrorist attacks of September 11th, 2001, the National Center on the Psychology of Terrorism was founded to research psychological aspects of terrorism. This is an example of how __________ affect theories and perspectives in psychology.
A.
current events
B.
new discoveries
C.
oppositions
D.
personal ideologies
Answers
A pendulum bob executing simple harmonic motion has 2cm and 12Hz as amplitude and frequency respectively. Calculate the period of the motion
Answers
Answer:
Explanation:
The amplitude is extraneous information for this question.
Period (T) is simply a measure of time (how long it takes to complete a full cycle).
The frequency (f), is the reciprocal (how many cycles it can complete per unit of time).
The frequency reported is 12Hz. Hz is a unit meaning "cycles per second"
Thus 12cycles = 1second.
To find the number of seconds per cycle, simply create the other unit fraction and simplify:
[tex]T=\frac{1second}{12cycles}\\T=0.8\bar{3}\frac{seconds}{cycle}\\[/tex]
[tex]T=0.83seconds[/tex]
Point P is on the rim of a wheel of radius 2.0 m. At time t = 0, the wheel is at rest, and P is on the x-axis. The wheel undergoes a uniform
angular acceleration of 0.01 rad/s² about the centre
Answers
Answer:
r = 2.0m
when t = 0, the angular displacement is zero.
Explanation:
When the angular acceleration is 0.01 m/s2, you can calculate
angular acceleration = change in angular velocity/ time
yhisriyftt
carzy and want one g come 6x 10-1'coulomb or one unit. The ratio, mass for each of the particle is 9.58 x 10" per gram. Hence, the mass
Answers
A hollow conducting sphere has an inside radius of r1 = 0.17 m and an outside radius of r2 = 0.28 m. The sphere has a net charge of Q = 4.8E-06 C. What is the magnitude of the field, in newtons per coulomb, at a distance of 0.05 m from the center of the sphere?
Answers
Explanation:
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How many minutes would be required for a 300.0 W (i.e., power=energy per second=300 J/s)
immersion heater to heat 0.25 kg of water from 20.0°C to 100.0°C? (Note: The specific heat of water
is 4184 J/kg°C)
Answers
Hence, the time required is approximately equal to 4 minutes and 39 seconds.
Given, Power, P = 300 W= 300J/s
Power= Energy per second
Mass, m= 0.25 kg
Initial Temperature= 20.0°C
Final Temperature= 100.0°C
Temperature difference, T =( 100-20)°C= 80.0°C
Specific heat of water, S= 4184 J/kg°C
Energy can be represented as
E=mST
where E is the energy, m is the mass, S is the specific heat of water and T is the temperature difference.
As Energy can be written as the product of time and power, E=Pt
Pt=mST
So,
t=(msT)/P
t=(0.25×4184×80)/300
Time, t = 278.934 seconds= 4 minutes and 39 seconds.
Hence, 4 minutes and 39 seconds will be required for a 300.0 W immersion heater to heat 0.25 kg of water from 20.0°C to 100.0°C.
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5, the following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
Answers
Explanation:
hi
please help me. ineed answers
Gerund/Infinitive
1. Put the verbs in brackets into the correct infinitive form or the -ing form.
1. Jane went on____(sleep) for another two hours.
2. He told us his name and went on____ (introduce) us to his wife.
3. She tried (finish) her homework, but it was too difficult.
4. You should try (eat) more fruit. It's good for your health.
5. He regrets (argue) with his best friend.
6.We regret (inform) you that tonight's performance will be cancelled.
7. Oh, no! I forgot____(lock) the front door.
8. I'll never forget_(meet) my favourite film star.
9.Claire likes (ski). She says it's very exciting.
10. I like__(go) to the dentist every six months.
11.I must remember (post) these letters today.
12. I remember__(read) the book, but I don't know who wrote it.
13. I'm sorry for___(forget) your birthday. It was awful of me.
14. I'm sorry.(say) that you have failed the exam.
15. She is afraid___(climb) the tree in case she falls.
16.Mary never wears her diamond ring. She is afraid of (lose) it.
17. I have stopped . (buy) some food before continuing our journey.
18. We stopped (watch) horror films because they give me nightmares
19. Tom stopped__(pick up) his washing on the way home.
20 If you don't stop. (smoke), you'll make yourself ill.
21.Will you quit___(complain)! It doesn't help.___(solve) the problem.
22.If you ever decide___(sell) your car, let me____(know).
23.I would like you.__(water) the plants for me at the weekend.
24.I clearly remember__(set) my alarm clock before__(go) to bed last night.
25. These plants require(water) every day.
26. I resent you (speak) to me like that! Have some respect.
27. It would be good for the children__ (play) outdoors more often.
28. I promised __(take) Jill to the party, but I don't feel like__(go) now.
29. Don't waste your time (look for) the document.Ask Mr Gale.
30. Please, excuse his__(leave) so early. He wants __(catch up) with his (study).
31. Try__(phone) John at the office if he's not at home.
32. I tried my best__(finish), but there just wasn't enough time.
33. He was promoted in 1990 and went on__(become) a company director.
34. The band went on__(play) even after the lights had gone out.
35. "Why is the baby crying?" "I think he wants (feed)."
36. Sharon wants__(talk) to you.
37. Jane was afraid__(show) her school report to her parents.
38. I'm afraid of__(lose) my way in the forest.
39. I regret__ (inform) you that your husband has been arrested.
which of the following statements is true about the suns energy and earth
Answers
The correct statement about the sun and the earth is that only about half of the suns energy hits the earths surface.
What is the sun?The sun is the source through which energy reaches the earth. The sun is a large star that produces energy by the process of nuclear fusion.
Hence, the correct statement about the sun and the earth is that only about half of the suns energy hits the earths surface.
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Helium is the second most abundant element on Jupiter (and in the Universe overall). But it's rare on Earth, being only 0.0005% of the atmosphere. Why is this?
A) Jupiter's stronger gravity results in a faster escape velocity, and almost no helium atoms are moving fast enough to escape its gravity. Earth's escape velocity is lower, so a few helium atoms at a time are moving fast enough to escape, causing Earth to slowly lose its helium.
B) Jupiter's core continually generates helium, while the Earth's core does not.
C) Jupiter has a powerful magnetic field that can attract helium atoms. Earth has a magnetic field as well, but it's not strong enough.
Answers
Answer:
Explanation:
Comment
I think the best answer is probably A. It's not the best reason for Earth loosing it's helium, but it is the only one that is close. The Earth derives some of its Helium (most) by the decomposition process of radio active high weight chemical that break down. Helium combines with practically nothing so once it gets moving, very little will stop it. That's the way we loose our Helium.
Still answer A.
suppose a uniform electric field 4 N/C is in the positive x-direction .
Answers
The magnitude of the electric field at x =4m on the x axis at this time 1 N/C.
Electric field at position 4 mElectric field at a given distance is calculated as follows;
E = kq/r²
E₂ = (9 x 10⁹ x q)/(2²)
E₂ = 2.25 x 10⁹q
E₂ + E₀ = 0
2.25 x 10⁹q + 4 = 0
2.25 x 10⁹q = - 4
q = -4 / (2.25 x 10⁹)
q = -1.78 x 10⁻⁹
E₄ = (9 x 10⁹ x (-1.78 x 10⁻⁹) ) / (4²)
E₄ = - 1 N/C
|E₄| = 1 N/C
Thus, the magnitude of the electric field at x =4m on the x axis at this time 1 N/C.
The complete question is below:
Suppose a uniform electric field of 4N/C is in the positive x direction. When a charge is placed and at a fixed to the origin, the resulting electric field on the x axis at x =2m becomes zero. What is the magnitude of the electric field at x =4m on the x axis at this time?
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A penny is dropped so that it reaches a terminal velocity of 13.3m/s. If the momentum is measured to be 0.0332kgm/s, what is the mass of the penny
Answers
Answer:
2.5 grams
Explanation:
p = mv
m = p/v
m = 0.0332 / 13.3
m = 0.0025kg
0.0025 x 1000 = 2.5
m = 2.5g
Question 3 of 10
The Moon has much less gravitational force than Earth. What would happen
if you went to the Moon?
OA. Your mass would decrease.
O
B. Your weight would increase.
O
C. Your mass would increase.
O
D. Your weight would decrease.
SUBMIT
Answers
Answer:
D
Explanation:
Mass is the amount of matter your body has ....does not change on the Moon.
there is less gravity .....so your WEIGHT would decrease
An arrow is shot horizontally from the top of a building and it lands 200m from the foot of the building after 10s.Assuming air resistance is negligible,calculate the initial velocity of the arrow and the height of the building?
Need an answer urgently please
Answers
The initial velocity of the arrow and the height of the building will be 29.05 m/s² and 781 m respectively.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is;
u is the initial velocity of fall = ? m/sec
h is the distance of fall = 200 m
g is the acceleration of free fall = 9.81 m/sec²
H is the height of the building
t is the time period = 10 second
According to Newton's second equation of motion,
[tex]\rm h= ut+\frac{1}{2} gt^2 \\\\\ h-\frac{1}{2} gt^2 =ut \\\\ 200 - 0.5 \times(9.81) \times 10^2 = 10 u \\\\ u = - 29.05 \ m/sec[/tex]
- ve shows the direction is downward.The magnitude of the initial velocity is found as;
u = 29.05 m/sec
The height of the building
[tex]\rm H= ut+\frac{1}{2} gt^2 \\\\\ H = 29.05 \times 10 + 0.5 \times 9.81 \times 10^2 \\\\ H = 781 \ m[/tex]
Hence the initial velocity of the arrow and the height of the building will be 29.05 m/s² and 781 m respectively.
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Compute the speed of sound waves in air at room temperature (T=200C) and find the range of wavelengths in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive. The mean molar mass of air (a mixture of principally nitrogen and oxygen) is 28.8 x 10-3kg/mol and the ratio of heat capacity is ϒ = 1.40.
Answers
The speed of sound waves in air at room temperature T=20° is 344.035 m/s.
The range of wavelength in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive is 17.20 m to 0.0172 m.
What is wavelength?The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.
Wavelength λ = c/f
where c is the speed of sound wave.
Given the room temperature T = 20 +273 = 293K
The velocity of sound wave is given by
v = √(γRT/m)
where γ =1.4 , m = 28.8×10⁻³ kg/mol R = 8.31 J/K.mol
Substituting the values, we get
v = 344.035 m/s
Thus, the speed of sound wave is 344.035 m/s
The human ear can hear frequencies in the range of 20 – 20,000Hz.
The wavelength corresponding to 20Hz is
λ = c/f
λ = 344.035 /20
λ = 17.20 m
The wavelength corresponding to 20,000Hz is
λ = 344.035 /20000
λ = 0.0172 m
Thus, the range of wavelength is 17.20 m to 0.0172 m sensitive to human ear.
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A radioactive contaminant gives an unfortunate lab rat a dose of 1500 rem in just 1 minute. Assuming that the half life of the radioactive isotope in the contaminant is much longer than 1 minute.What would the activity of the contaminant be if the contaminant is 1.1MeV Beta Emitter?
Answers
The activity of the contaminant will be 3.5 ×10⁻¹⁰ Bq if the contaminant is 1.1MeV Beta Emitter.
Disclaimer, here the m is taken as 0.5kg.
Given, REM = 1500
Time, t= 1 minute =60 seconds
For beta particles,
RBE (Relative Biological Effectiveness) =2.
Absorbed dose, D =REM/RBE= 1500/2 = 750rad
As 100 rad=1 J/kg,
750 rad=7.5 J/kg
So, D=7.5 J/kg
D= total energy absorbed (E)/mass (m)
7.5 J/kg=E/m
E =7.5 ×0.5 = 3.75J
Therefore, the number of beta particles absorbed is 3.75 J.
The number of beta particles absorbed,
As 1 MeV= 1.6 ×10⁻¹³J
So, converting 1.1 MeV in J, 1.1×1.6 ×10⁻¹³J=1.76×10⁻¹³J
Numbers of beta particles,
n=3.75J/1.76×10⁻¹³J
n=2.13×10⁻¹²
Hence, the number of beta particles is 2.13×10⁻¹².
Activity, A= n/t
where n is the number of beta particles and t is the time.
A= n/t=(2.13×10⁻¹²)/60
A= 3.5 ×10⁻¹⁰ Bq
So, the activity is 3.5 ×10⁻¹⁰ Bq.
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A pendulum swings to and fro every 2.0 s. The period of the swing is.
O 2 Hz
2 s
O 0.5 s
O 0.5 Hz
Answers
Answer:
Explanation:
Solution
In physics, a period is a measurement of time. The answer must be either B or C. It is a direct measurement of time, not its reciprocal. So the answer is B. A and D is a measurement of the actual cycle that it takes before the motion begins to repeat itself.
Answer
B
all elements in the same group have the same number of?
electrons
energy levels
electrons in the outermost energy level
bonds
Answers
All elements in the same group have the same number of electrons in the outermost energy level. Option C is correct.
What is a periodic table?The periodic table is an organization of all known elements in order of increasing atomic number and repeating chemical characteristics.
They are organized in a tabular format, with a row representing an era and a column representing a group. E elements are ordered in increasing atomic number order from left to right and top to bottom.
Thus, Elements of the same group will have the same valence electron configuration and, as a result, will have comparable chemical characteristics.
Each set of elements has an equal amount of electrons in the outer orbital. Valence electrons are another name for the outer electrons.
They are the electrons interacting with other elements in chemical bonding. Each element in group one, the first column, has one electron in its outer shell.
Hence option C is correct.
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How to magnetic stripes provide evidence of seafloor spreading
Answers
Magnetic stripes provide evidence of seafloor spreading due to their occurrence in the region of sea floor.
How to magnetic stripes provide evidence of seafloor spreading?When the Earth's magnetic field reverses, a new stripe starts to form. Such magnetic patterns enable the scientist to recognize the occurrence of sea-floor spreading and provides strongest evidence for the theory of plate tectonics.
So we can conclude that magnetic stripes provide evidence of seafloor spreading due to their occurrence in the region of sea floor.
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A grocery cart is pushed with a force of 21.4 N. If 1,974 J of work is done in pushing the grocery cart through the store, what is the total distance that the grocery cart has traveled?
Answers
Answer:
Given - Force = 21.4 N
Work done = 1974 J
To find - Distance
Solution -
Work done = Force * displacement
1974 j = 21.4 N * displacement
1974/21.4 = displacement
92.24
[tex]\\ \rm\Rrightarrow Work=Force\times Displacement [/tex]
[tex]\\ \rm\Rrightarrow 1974=21.4×Displacement[/tex]
[tex]\\ \rm\Rrightarrow Displacement=92.24m[/tex]
what are risk factors of an autoimmune disease
Answers
Explanation:
Your Sex. Overall, 78% of people affected by autoimmune disease are female (1). ...Genetics. Certain disorders, such as lupus and multiple sclerosis, tend to run in families (3, 4). ...Having an autoimmune disease. ...Obesity. ...Smoking and Exposure to Toxic Agents. ...Certain Medications. ...Infections.The high point of the ripple seen in a pond after throwing in a pebble is the...
Select one:
a. crest.
b. trough.
c. wavelength.
d. A & B
Answers
The crest is the highest point of a pebble-induced ripple in a body of water. Option a is correct.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength. The highest point of the wave is the crest, while the trough is the lowest.
The high point of the ripple seen in a pond after throwing in a pebble is the crest.
Hence option a is correct.
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Part A
Calculate the spring constant.
• Look at the graph of x vs. t graph. (You may want to double-click on
it to examine it in the Data Tool view.)
. From the graph, determine the period T.
• The first video frame lists the mass.
• Use the equation below to solve for the spring constant k. Show
your work below.
m
T = 2π√√T
Answers
Answer:
Using 3 periods to get an accurate reading:
3T = (6.40 S - 0.90 s) = 5.50 S So, T = 1.83 s
m = 0.250 kg
Using algebra:
k= [tex]\frac{4\pi ^{2}m }{T^{2} }[/tex]=[tex]\frac{4\pi ^{2}0.250 }{1.90^{2} }[/tex]=2.95kg/sec
Calculate the height of stairs a 60 kg student would have to run in order to burn off 1 Calorie of food energy, which is the equivalent of 4190 Joules.
Answers
The height of stairs a 60 kg student would have to run in order to burn off 1 Calorie of food energy will be 7.1 meters.
What is potential energy?The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.
Given data;
Mass of student,m = 60 kg
Energy,E = 4190 J
Height of stairs,h=?
The potential energy is mainly dependent upon the height of the object. The potential energy is found as;
Potential energy = mgh
E=mgh
h=E/mg
h= 4190 J / (60 kg× 9.81 m/s²)
h = 7.1 metre
Hence the height of the stairs will be 7.1 meters.
To learn more about the potential energy, refer to the link;
https://brainly.com/question/24284560
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