5. Write a C++ program that can display the output as shown below. Your
program will calculate the price after discount. User will input the
price and the discount is 20%


​

Answer:

Explanation:

The objective of this program we are to develop is to compute a C++ program and a flowchart that calculates a cost to replace all tablets and desktop computers in a business.

C++ Program

#include<iostream>

#include<iomanip>

using namespace std;

/*

⦁ // Name:

⦁ // Date:

⦁ // Program Name:

⦁ // Description:

*/

int main()

{

const double SalesTaxRate = .075, DiscountPercent = .10, FinanceCharge = .15;

const double TABLET = 320.00, DESKTOP = 800.00;

double total = 0.0, subTotal = 0.0,avg=0.0;

int numberOfTablets, numberOfDesktop;

cout << "-------------- Welcome to Computer Selling Company ------------------ ";

cout << "Enter number of tablets: ";

cin >> numberOfTablets;

cout << "Enter number of desktops: ";

cin >> numberOfDesktop;

subTotal = TABLET * numberOfTablets + numberOfDesktop * DESKTOP;

char choice;

cout << "Paying cash or financing: (c/f): ";

cin >> choice;

cout << fixed << setprecision(2);

if (choice == 'c' || choice == 'C')

{

cout << "You have choosen paying cash." << endl;

total = subTotal - subTotal * DiscountPercent;

cout << "Discount you get $" << subTotal * DiscountPercent<<endl;

cout << "Sales Tax: $" << SalesTaxRate * total << endl;

total = total + total * SalesTaxRate;

cout << "Total computers' Cost: $" << total << endl;

avg = total / (numberOfDesktop + numberOfTablets);

cout << "Average computer cost: $ " << avg << endl;

}

else if (choice == 'f' || choice == 'F')

{

cout << "You have choosen Finance option." << endl;

total = subTotal + subTotal * FinanceCharge;

cout << "Finance Charge $" << subTotal * FinanceCharge << endl;

cout << "Sales Tax: $" << SalesTaxRate * total << endl;

total = total + total * SalesTaxRate;

cout << "Total computers' Cost: $" << total << endl;

avg = total / (numberOfDesktop + numberOfTablets);

cout << "Average computer cost: $ " << avg << endl;

}

else

{

cout << "Wrong choice.......Existing.... ";

system("pause");

}

//to hold the output screen

system("pause");

} }

OUTPUT:

The Output of the program is shown in the first data file attached below:

FLOWCHART:

See the second diagram attached for the designed flowchart.

Answer:

Raid

Explanation:

Answer:

C

Explanation:

Accessories are in Microsoft windows, a set of programs and applications that help users with some basic tasks

Find the given attachments

Answer:

i think html

Explanation:

Answer:

Web browser

Explanation:

Answer: Provided in the explanation section

Explanation:

Code to use;

# Define the main() function.

def main():

   # Declare the required variables.

   stack_cars = []

   move_time = 1

   retrieve_time = 2

   # Start the loop to display the menu.

   while True:

       # Display the choices to the user.

       print("\n\t\t\t Car Stack Menu")

       print("\n1. Add a car")

       print("2. Retrieve a car")

       print("3. Show the car stack")

       print("4. Exit")

       # Prompt the user to enter the input.

       choice = input("\nEnter your choice: ")

       # Append the car in the stack if the choice is 1.

       if choice == '1':

           car = input("Enter the car name to add: ")

           stack_cars.append(car)

       # Remove the car from the stack if the choice is 2.

       elif choice == '2':

           car = input("Enter the car name to retrieve: ")

           # Display the error message if the car is not present.

           if car not in stack_cars:

               print(car + " is not present in the stack.")

           # Otherwise, compute the time to retrieve a car.

           else:

               # Declare a temp stack to move the cars.

               temp = []

               x = stack_cars.pop()

               count = 0

               # Start the loop to pop the cars from the stack

               # until the car to be retrieved is found.

               while x != car:

                   count += 1

                   # Store the car in the temp stack.

                   temp.append(x)

                   x = stack_cars.pop()

               # Start the loop to move the cars back in the

               # original stack.

               while len(temp) != 0:

                   stack_cars.append(temp.pop())

               # Compute and display the total time.

               total_time = move_time * count + retrieve_time

               print("Total time to retrieve", car, "=", total_time)

       # Display the stack if the choice is 3.

       elif choice == '3':

           print("Car stack =", stack_cars)

       # Return from the funtion if the choice is 4.

       elif choice == '4':

           print("Exiting from the program...")

           return

       # Display the message for invalid input.

       else:

           print("Error: Invalid choice!")

# Call the main() function.

if __name__ == "__main__":

   main()

Answer:

Explanation:

The vertices of a square is one such set of points. Either diagonal will bring the degree of the points involved to 3 = 4-1.

The vertices of a regular pentagon is another such set of points. After joining the points in a convex hull, any interior connection will create a triangle and a quadrilateral. The diagonal of the quadrilateral will bring the degree of at least one of the points to 4 = 5-1.

Answer:

The database can include the fields related to the Author such as name and address, related to Publisher such as publisher's name and address, related to book such as title and ISBN of the book and related to contract such as payment schedule, contract start and end.

Explanation:

The following fields can be needed for this database:

Answer:

Explanation:

(a) The recurrence relation for the given problem is :

T(n) = T(n-1) + T(n-4) + 1

(b) The O(n) time recursive algorithm with memoization for the above recurrence is given below :

Create a 1-d array 'memo' of size, n (1-based indexing) and initialize its elements with -1.

func : a recursive function that accepts the cost array and startingJobNo and returns the minimum cost for doing the jobs from startingJobNo to n.

Algorithm :

func(costArr[], startingJobNo){

if(startingJobNo>n)

then return 0

END if

if(memo[startingJobNo] != -1)

then return memo[startingJobNo];

END if

int ans1 = func(costArr, startingJobNo+1) + costArr[startingJobNo]

int ans2 = func(costArr, startingJobNo+4) + h

memo[startingJobNo] = min(ans1,ans2);

return memo[startingJobNo];

}

(c)

First, Create a 1-d array 'dp' of size, N+1.

dp[0] = 0

bottomUp(int c[]){

for  i=1 till i = n

DO

dp[i] = min(dp[i-1] + c[i], dp[max(0,i-4)] + h);

END FOR

return dp[n];

}

(d)

Modifying the algorithm given in part (b) as follows to know which job to do yourself and in which jobs we need to hire a handyman.

First, Create a 1-d array 'memo' of size, n (1-based indexing) and initialize its elements with -1.

Next, Create another 1-d array 'worker' of size,n (1-based indexing) and initialize its elements with character 'y' representing yourself.

Algorithm :

func(costArr[], startingJobNo){

if(startingJobNo>n)

then return 0

END if

if(memo[startingJobNo] != -1)

then return memo[startingJobNo];

END if

int ans1 = func(costArr, startingJobNo+1) + costArr[startingJobNo]

int ans2 = func(costArr, startingJobNo+4) + h

if(ans2 < ans1)

THEN

for (i = startingJobNo; i<startingJobNo+4 and i<=n; i++)

DO

// mark worker[i] with 'h' representing that we need to hire a mechanic for that job

worker[i] = 'h';

END for

END if

memo[startingJobNo] = min(ans1,ans2);

return memo[startingJobNo];

}

//the worker array will contain 'y' or 'h' representing whether the ith job is to be done 'yourself' or by 'hired man' respectively.

Answer:

The csharp program is as follows.

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;  

namespace WindowsFormsApplication1

{

   public partial class Form1 : Form

   {

       public Form1()

       {

           InitializeComponent();

       }

private void button1_Click(object sender, EventArgs e)

       {

           string word = textBox1.Text;

               string  ch = word.Substring(0, 1);

               string str = word.Substring(1, word.Length-1);

               string s = str.Insert(str.Length, ch);

               textBox2.Text = s.Insert(s.Length, "ay");            

       }

     private void button3_Click(object sender, EventArgs e)

       {

           Close();

       }

       private void button2_Click(object sender, EventArgs e)

       {

           textBox1.Text = "";

           textBox2.Text = "";

       }

   }

}

Explanation:

1. A string variable to hold the user input is declared and initialized accordingly. The user inputted string is taken from textbox1.

string word = textBox1.Text;

2. A string variable to hold the first character of the user inputted string is declared and initialized.

string  ch = word.Substring(0, 1);

3. A string variable to hold the user inputted string without the first character is declared and initialized accordingly.

string str = word.Substring(1, word.Length-1);

4. A string variable to hold the substring from step 3 along with the inserted characters at the end, is declared and initialized accordingly.

string s = str.Insert(str.Length, ch);

5. The final string is assigned to the textbox 2, which is the PigLatin conversion of the user inputted string.

textBox2.Text = s.Insert(s.Length, "ay");

6. All the above take place when the user clicks Convert to PigLatin button.

7. Two additional buttons, clear and exit are also included in the form.  

8. When the user clicks clear button, both the textboxes are initialized to empty string thus clearing both the textboxes.

 textBox1.Text = "";

           textBox2.Text = "";

9. When the user clicks the exit button, the application closes using the Close() method.

10. The program is done in Visual Studio.

11. The output of the program is attached.

12. The program can be tested for any type of string and any length of the string.

Answer:

def to_pig_latin(word):

   new_word = word[1:] + word[0] + "ay"

   return new_word

print(to_pig_latin("hello"))

print(to_pig_latin("latin"))

Explanation:

Create a function called to_pig_latin that takes one parameter, word

Inside the function, create a new_word variable and set it to the characters that are between the second character and the last character (both included) of the word (use slicing) + first character of the word + "ay". Then, return the new_word.

Call the to_pig_latin function twice, first pass the "hello" as parameter, and then pass the "latin" as parameter

Answer:

...huh?

Explanation:

Answer:

Following are the code to this question:

import java.util.*; //importing package for user input

public class Main //defining class

{

public static void main(String []ar) //defining main method

{

double investment_amount,interest_rate,future_investment_value; //defining double variables

int years; //defining integer variable

Scanner obx=new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter invest value: "); //print message

investment_amount=obx.nextDouble(); //input value

System.out.print("Enter interest rate: ");//print message

interest_rate=obx.nextDouble();//input value

System.out.print("Enter number of years: ");//print message

years=obx.nextInt();//input value

future_investment_value=investment_amount*Math.pow((1+interest_rate/1200.),years*12); //calculating value by apply formula

System.out.println("you enter amount: $"+investment_amount); //print calculated value

System.out.println("annual interest rate:"+interest_rate+"%");//print calculated value

System.out.printf("Number of years: "+years+" the future investment value is :$%.2f\n",future_investment_value);//print calculated value

}

}

output:

please find the attachment.

Explanation:

Program Description:

Answer:

C. improve data quality and reduce redundancies, reduce increased and staggering storage management costs

Explanation:

Excess data retention can lead to retention of redundant and irrelevant data, which can reduce data handling and processing efficiency, while at the same time increasing the cost of data storage and management. This can be curbed be reducing data to the right size by using data governance techniques like data cleansing and de-duplication

Answer:

w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]

for i in range (len(w)):

   print(w[i].upper())

Explanation:

every element needs to be upper cased

A loop that prints the words in uppercase letters is written below with the help of Python.

Simply said, a function is a "chunk" of code that you may reuse repeatedly so instead of having to write it out several times. Software developers can divide an issue into smaller, more manageable parts, which can each carry out a specific task, using functions.

A function, according to a technical definition, is a relationship between an amount of parameters and a set of potential outputs, where every other input is connected to precisely one output.

All the functions are to be written in uppercase:

w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]

for i in range (len(w)):

  print(w[i].upper())

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Answer:

Explanation:

PROGRAM

main.c

#include <fcntl.h>

#include <stdio.h>

#include <stdlib.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <unistd.h>

#include "myio.h"

int checkInt(char *arg);

int main(int argc, char *argv[]) {

  int doubles, i, ints, lines;

  char newline;

  FILE *out;

  int x, y, z;

  newline = '\n';

  if (argc != 5) {

     printf("Usage is x y z output_filename\n");

     return 0;

  }

  if (checkInt(argv[1]) != 0)

     return 0;

  ints = atoi(argv[1]);

  if (checkInt(argv[2]) != 0)

     return 0;

  doubles = atoi(argv[2]);

  if (checkInt(argv[3]) != 0)

     return 0;

  lines = atoi(argv[3]);

  out = fopen(argv[4], "a");

  if (out == NULL) {

     perror("File could not be opened");

     return 0;

  }

  for (x = 0; x < ints; x++) {

     int n = ReadInteger();

     printf("%d\n", n);

     fprintf(out, "%d\n", n);

  }

  for (y = 0; y < doubles; y++) {

     double d = ReadDouble();

     printf("%lf\n", d);

     fprintf(out, "%lf\n", d);

  }

  for (z = 0; z < lines; z++) {

     char *l = ReadLine();

     printf("%s\n", l);

     fprintf(out, "%s\n", l);

     free(l);

  }

  fclose(out);

  return 0;

}

int checkInt(char *arg) {

  int x;

  x = 0;

  while (arg[x] != '\0') {

     if (arg[x] > '9' || arg[x] < '0') {

        printf("Improper input. x, y, and z must be ints.\n");

        return -1;

     }

     x++;

  }

  return 0;

}

myio.c

#include <limits.h>

#include <stdio.h>

#include <stdlib.h>

#include <unistd.h>

char *ReadInput(int fd) {

  char buf[BUFSIZ];

  int i;

  char *input;

  int r, ret, x;

  i = 1;

  r = 0;

  ret = 1;

  input = calloc(BUFSIZ, sizeof(char));

  while (ret > 0) {

     ret = read(fd, &buf, BUFSIZ);

     for (x = 0; x < BUFSIZ; x++) {

        if (buf[x] == '\n' || buf[x] == EOF) {

           ret = -1;

           break;

        }

        input[x*i] = buf[x];

        r++;

     }

     i++;

     if (ret != -1)

        input = realloc(input, BUFSIZ*i);

  }

  if (r == 0)

     return NULL;

  input[r] = '\0';

  input = realloc(input, r+1);

  return(input);

}

int ReadInteger() {

  char *input;

  int go, num, x;

  go = 0;

  do {

     go = 0;

     printf("Input an integer\n");

     input = ReadInput(STDIN_FILENO);

     for (x = 0; x < INT_MAX; x++) {

        if (x == 0&& input[x] == '-')

           continue;

        if (input[x] == 0)

           break;

        else if (input[x]> '9' || input[x] < '0') {

           go = 1;

           printf("Improper input\n");

           break;

        }

    }

  } while (go == 1);

  num = atoi(input);

  free(input);

  return num;

}

double ReadDouble(void) {

  int dec, exp;

  char *input;

  int go;

  double num;

  int x;

  do {

     go = 0;

     dec = 0;

     exp = 0;

     printf("Input a double\n");

     input = ReadInput(STDIN_FILENO);

     for (x = 0; x < INT_MAX; x++) {

        if (x == 0&& input[x] == '-')

           continue;

        if (input[x] == 0)

           break;

        else if (input[x] == '.' && dec == 0)

           dec = 1;

        else if (x != 0&& (input[x] == 'e' || input[x] == 'E') && exp == 0) {

           dec = 1;

           exp = 1;

        }

        else if (input[x]> '9' || input[x] < '0') {

           go = 1;

           printf("Improper input\n");

           break;

        }

     }

  } while (go == 1);

  num = strtod(input, NULL);

  free(input);

  return num;

}

char *ReadLine(void) {

  printf("Input a line\n");

  return(ReadInput(STDIN_FILENO));

}

char *ReadLineFile(FILE *infile) {

  int fd;

  fd = fileno(infile);

  return(ReadInput(fd));

}

myio.h

#ifndef _myio_h

#define _myio_h

/*

* Function: ReadInteger

* Usage: i = ReadInteger();

* ------------------------

* ReadInteger reads a line of text from standard input and scans

* it as an integer. The integer value is returned. If an

* integer cannot be scanned or if more characters follow the

* number, the user is given a chance to retry.

*/

int ReadInteger(void);

/*

* Function: ReadDouble

* Usage: x = ReadDouble();

* ---------------------

* ReadDouble reads a line of text from standard input and scans

* it as a double. If the number cannot be scanned or if extra

* characters follow after the number ends, the user is given

* a chance to reenter the value.

*/

double ReadDouble(void);

/*

* Function: ReadLine

* Usage: s = ReadLine();

* ---------------------

* ReadLine reads a line of text from standard input and returns

* the line as a string. The newline character that terminates

* the input is not stored as part of the string.

*/

char *ReadLine(void);

/*

* Function: ReadLine

* Usage: s = ReadLine(infile);

* ----------------------------

* ReadLineFile reads a line of text from the input file and

* returns the line as a string. The newline character

* that terminates the input is not stored as part of the

* string. The ReadLine function returns NULL if infile

* is at the end-of-file position. Actually, above ReadLine();

* can simply be implemented as return(ReadLineFile(stdin)); */

char *ReadLineFile(FILE *infile);

Answer:

Network Operating System (NOS)

Explanation:

A network operating system (NOS) is an operating system that makes different computer devices connect to a common network in order to communicate and share resources with each other using a server. A network operating system can be used by printers, computers, file sever among others, and they are connected together using a local area network. This local area network which they are connected to works as the server.

The NOS also acts as a network security because it could be used as an access control or even user authentication.

There are two types of NOS

1) Peer to peer network operating system.

2) Client/server network operating system

A network operating system (NOS) is a server-based operating system oriented to computer networking and may include directory services, network management, network monitoring, network policies, user group management, network security, and other network-related functions.

Explanation:

search engine because it helps to search find what you are expecting to search in the google.

Explanation:

A transaction is a very small system unit that can contain many low-level tasks. A transaction in a database system should maintain, Atomicity, Consistency, Isolation, and Durability − these are commonly known as ACID properties − in order to ensure accuracy, completeness, and integrity of the data.

An example of a simple transaction is as below,  Suppose a bank employee transfers Rs 500 from A's account to B's account.

A’s Account

Open_Account(A)

Old_Balance = A.balance

New_Balance = Old_Balance - 500

A.balance = New_Balance

Close_Account(A)

B’s Account

Open_Account(B)

Old_Balance = B.balance

New_Balance = Old_Balance + 500

B.balance = New_Balance

Close_Account(B)

Answer:

import java.util.Scanner;

public class UnitTesting {

   // Function returns origNum cubed

   public static int cubeNum(int origNum) {

       return origNum * origNum * origNum;

   }

   public static void main (String [] args) {

       System.out.println("Testing started");

       System.out.println("2, expecting 8, got: " + cubeNum(2));

       System.out.println("3, expecting 27, got: " + cubeNum(3));

       System.out.println("-1, expecting -1, got: " + cubeNum(-1));

       System.out.println("Testing completed");

       return;

   }

}

Explanation:

Added statements are highlighted.

Since the cubeNum function calculates the cube of the given number and we are asked to write two statements to test inputs 3 and -1, pass the parameters 3 and -1 to the function called cubeNum and print the results using print statements

Answer:

cyberspace

Explanation:

It is the notional environment in which communication over computer networks occurs.

It is imperative that we safeguard this domain known as cyberspace.

The meaning of the cyberspace is the climate of the Internet.

There is large network of computers connected together in offices or organizations to explore the internet. The cyberspace has formed the first important needed thing in this century without which nothing can be done in personal space or in any companies.

The U.S. continues to become more dependent on the global domain within the information environment consisting of the interdependent network of information technology infrastructures, including the Internet, telecommunications networks, computer systems, and embedded processors and controllers.

So, we safeguard this domain known a cyberspace.

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Answer:

dependability

Explanation:

devon keeps his commitment

The personal skill that's demonstrated by Devin is dependability.

Dependability simply means when an individual is trustworthy and reliable. Dependability simply means when a person can be counted on and relied upon.

In this case, since Devon keeps his commitments, submits work when it's due, and shows up when scheduled, it shows that he's dependable.

It should be noted that employers love the people that are dependable as they can be trusted to have a positive impact on an organization.

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Answer:

The correct answer is option (c) 4950 cipher keys

Explanation:

Solution

Given that:

From the given question we have that if there are 100 computers in a LAN, then each computer should have how many keys.

Now,

The number of computers available = 100

The number of keys used in  symmetric key cipher for N parties is given as follows:

= N(N-1)/2

= 100 * (100 -1)/2

= 50 * 99

= 4950 cipher keys

Answer: you want to list all LC structers

Explanation:

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Answer:

B. Aside element

Explanation:

The options for this question are missing, the options are:

A. ​article element

B. ​aside element

C. ​section element

D. ​content element

An aside element is defined as a section of a page that has content that is tangentially related to the content around the element. In other words, the aside element represents content that is indirectly related to the main content of the page. Therefore, we can say that the correct answer to this question is B. Aside element.

Answer:

I would say cclrearner

Explanation:

This is what helped me with my computer so it may help you but try which one works for you

Answer:

When you sign into a website, you have to enter a password and username most of the time, which will allow the website to know that you have checked in and it is you, who is using your account.

Answer:

Sorted Array A { } = { 1, 4, 23, 32, 34, 34, 67, 78, 89, 100 }

Explanation:

Binary tree is drawn given that the binary tree do not follow both minimum heap and maximum heap property, therefore, it is not a heap.

See attached picture.

Answer:

The cpp program for the given scenario is as follows.

#include <iostream>

#include <iterator>

using namespace std;

int main()

{

   //boolean variable declared and initialized  

   bool sorted=true;

   //integer array declared and initialized

   int arr[] = {1, 2, 3, 4, 5};

   //integer variables declared and initialized to length of the array, arr

   int len = std::end(arr) - std::begin(arr);

       //array tested for being sorted

    for(int idx=0; idx<len-1; idx++)

    {

        if(arr[idx] < arr[idx+1])

           {

               sorted=false;

            break;

           }

    }

    //message displayed  

    if(sorted == false)

     cout<< "UNSORTED" <<endl;

 else

    cout<< "UNSORTED" <<endl;

return 0;

}

OUTPUT

UNSORTED

Explanation:

1. An integer array, arr, is declared and initialized as shown.

int arr[] = {1, 2, 3, 4, 5};

2. An integer variable, len, is declared and initialized to the size of the array created above.

int len = std::end(arr) - std::begin(arr);

3. A Boolean variable, sorted, is declared and initialized to true.

bool sorted=true;  

4. All the variables and array are declared inside main().

5. Inside for loop, the array, arr, is tested for being sorted or unsorted.  The for loop executes over an integer variable, idx, which ranges from 0 till the length of the array, arr.

6. The array is assumed to be sorted if all the elements of the array are in descending order.

7. If the elements of the array are in ascending order, the Boolean variable, sorted, is assigned the value false and for loop is exited using break keyword. The testing is done using if statement.

8. Based on the value of the Boolean variable, sorted, a message is displayed to the user.

9. The program can be tested for any size of the array and for any order of the elements, ascending or descending. The program can also be tested for array of other numeric data type including float and double.

10. All the code is written inside the main().

11. The length of the array is found using begin() and end() methods as shown previously. For this, the iterator header file is included in the program.

Answer:

a) tie the exception condition to a processing step

Explanation:

Numbering exception conditions, in a fully developed use case description is helpful to tie the exception condition to a processing step

The fully developed use case description is useful for the documentation of the context, purpose, description, conditions, and workflow of each use case. Activity diagrams give a graphical image of the use case workflow and serve the purpose of illustrating the alternative paths through a business process.