6. Five years ago, Ross was N times as old as
Amanda was. If Amanda is now 19 years old,
how old is Ross now in terms of N?

Answer:

F.  31.4 ft

Step-by-step explanation:

The distance around the edge of a circle is called the circumference.

Formula for the circumference of a circle

[tex]\sf Circumference\:of\:a\:circle=2 \pi r[/tex]

(where r is the radius)

Given values:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \sf circumference & = \sf 2 \cdot 3.14 \cdot 5\\ & = \sf 31.4\:ft \end{aligned}[/tex]

Therefore, the distance around the edge of the circular patio is 31.4 ft.

The distance around the edge of the patio is 31.4 feet, which is determined by the circumference of a circle. The correct answer is option (F).

To find the distance around the edge of the circular patio, we need to calculate the circumference of the circle.

The formula for the circumference of a circle is given by:

Circumference = 2 × π × radius

Given that the radius of the patio is 5 feet and using the approximate value of π as 3.14, we can now calculate the circumference:

Circumference = 2 × 3.14 × 5

Circumference = 31.4 feet

Therefore, the distance around the edge of the patio is 31.4 feet.

Hence, the correct answer is option (F).

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Answer:

[tex] \boxed{f(6) =2 4}[/tex]

Step-by-step explanation:

Given function:

[tex]f(x) = x² - 2x[/tex]

Solution:

ATP,it is that x = 6. So substitute 6 on the function.

[tex]f(6) = 6 {}^{2} - 2(6)[/tex]

Simplifying using PEMDAS,we obtain:

[tex]f(6) = 6 \times 6- 12[/tex]

[tex]f(6) = 36 - 12[/tex]

[tex] \boxed{f(6) =2 4}[/tex]

Hence,f(6) = 24.

Answer:

A. 4/5

Step-by-step explanation:

Answer:

4/5  (option a)

Step-by-step explanation:

by following the exponent rule of [tex]a^1 = a[/tex], we know that

[tex](\frac{4}{5} )^1[/tex] = [tex]\frac{4}{5}[/tex]

So, the value of

[tex]\frac{4}{5}^{1}[/tex]  is  4/5

Answer:

x = ±5

Step-by-step explanation:

x² - 25 = 0

x² = 25

√x² = √25

x = ±5

Check:

5² - 25 = 0

-5² - 25 = 0

25 - 25 = 0

Answer:

B.a numerical expression

The function of f(4) = g(x+1) gives the value of x that is -1/5.

It is the addition of two functions similar to the addition of any two polynomial functions.

Given;

F(x)=x+1

g(x)=5x+1

We need to find f(4)=g(x+1)

First substitute x = 4 in f(x)

F(x)=x+1

F(4) = 4 + 1

F(4) =  5

Now substitute x = x + 1 in g(x)

g(x)=5x+1

g(x + 1) = 5(x + 1) + 1

g(x + 1) = 5(x + 1) + 1

g(x + 1) = 5x + 5 + 1

g(x + 1) = 5x + 6

Then ,

F(4) = g(x + 1)

5 = 5x + 6

5x = 5 - 6

5x = -1

x = -1/5.

The function of f(4) = g(x+1) gives the value of x that is -1/5.

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Using the z-distribution, it is found that 3,007 passengers must be surveyed.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

In this problem, we desired a margin of error of M = 0.015, with no prior estimate, hence [tex]\pi = 0.5[/tex], then we solve for n to find the minimum sample size.

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.015 = 1.645\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.015\sqrt{n} = 1.645(0.5)[/tex]

[tex]\sqrt{n} = \frac{1.645(0.5)}{0.015}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.645(0.5)}{0.015}\right)^2[/tex]

n = 3007.

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We can make 64 different equations using the power of ten.

The power of a number identifies how many times that particular number is multiplied by itself.

Here, let us assume that the different equations = x

Using a power of 10, we have 10x making a total of 640.

Divide both sides by 10

10x/10 = 640/10

x = 64

Therefore, we can conclude that we can make 64 different equations using the power of ten.

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Answer:

[tex]\tan(\beta)[/tex]

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

[tex]{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}[/tex]    and   [tex]{\sec(\theta)}={\dfrac{1}{\cos(\theta)}[/tex]

Recall the following reciprocal identity:

[tex]\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}[/tex]

So, the original expression can be written in terms of only sines and cosines:

[tex]\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)[/tex]

[tex]\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }[/tex]

[tex]\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}[/tex]

[tex]\sin(\beta) *\dfrac{1 }{\cos(\beta) }[/tex]

[tex]\dfrac{\sin(\beta)}{\cos(\beta) }[/tex]

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to [tex]\tan(\beta)[/tex].

The pounds of corn in the second month is 390

We have:

First month, a = 300

Rate, r = 35%

The pounds of corn in the second month is calculated using:

Pound = a * (1 + r)

So, we have:

Pound = 300 * (1 + 30%)

Evaluate the sum

Pound = 300 * 1.3

Evaluate the product

Pound = 390

Hence, the pounds of corn in the second month is 390

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If the scale factor is 1/2. Then the coordinate of the pre-image will be (-1, 1), (0, 1), (1, 0), (0, -1), and (-1, -1).

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Dilation does not change the shape, but changes the size of the geometry.

On a coordinate plane, an image has points (-2, 2), (0, 2), (2, 0), (0, -2), and (-2, -2).

The scale factor is 1/2. Then the coordinate of the pre-image will be

(-1, 1), (0, 1), (1, 0), (0, -1), and (-1, -1).

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Answer:D (-4) (-4)

Step-by-step explanation:

Answer: 2

Step-by-step explanation:

[tex]g(-2)=-2\\\\g(1)=4\\\\\frac{g(-2)-g(1)}{-2-1}=\frac{-2-4}{-3}=\boxed{2}[/tex]

Answer:

y=3x-21

Step-by-step explanation:

Given points A(2,5) and B(8,3), line AB must contain them.

To calculate the slope, [tex]m_{\text{AB}}[/tex], of line AB, use the slope formula:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m_{\text{AB}}=\dfrac{(3)-(5)}{(8)-(2)}[/tex]

[tex]m_{\text{AB}}=\dfrac{-2}{6}[/tex]

[tex]m_{\text{AB}}=-\frac{1}{3}[/tex]

Since the slope isn't undefined, line AB must cross the y-axis somewhere.  To find the y-intercept, build and equation in slope-intercept form:

[tex]y=m_{\text{AB}}x+b_{\text{AB}}[/tex]

[tex]y=\left(-\frac{1}{3} \right) x+b_{\text{AB}}[/tex]

Substituting values for a known point (point A) on line AB...

[tex](5)=\left(-\frac{1}{3} \right) (2)+b_{\text{AB}}[/tex]

[tex]5=-\frac{2}{3} +b_{\text{AB}}[/tex]

[tex](5)+\frac{2}{3} =(-\frac{2}{3} +b_{\text{AB}})+\frac{2}{3}[/tex]

Finding a common denominator...

[tex]\frac{3}{3}*5+\frac{2}{3} =b_{\text{AB}}[/tex]

[tex]\frac{15}{3}+\frac{2}{3} =b_{\text{AB}}[/tex]

[tex]\frac{17}{3}=b_{\text{AB}}[/tex]

So, the equation for line AB is  [tex]y=-\frac{1}{3} x +\frac{17}{3}[/tex]

Since line AB and line BC form a right angle, they are perpendicular.  Perpendicular lines have slopes that are opposite (opposite sign) reciprocals (fraction flipped upside-down) of each other.  Stated another way, the slopes multiply to make negative 1.

[tex]m_{\text{AB}}*m_{\text{BC}}=-1[/tex]

[tex]\left( -\frac{1}{3} \right) *m_{\text{BC}}=-1[/tex]

[tex]-3*\left( -\frac{1}{3} *m_{\text{BC}} \right) =-3*(-1)[/tex]

[tex]m_{\text{BC}} =3[/tex]

Since the slope isn't undefined, line BC must also cross the y-axis somewhere.  To find the y-intercept, build and equation in slope-intercept form:

[tex]y=m_{\text{BC}}x+b_{\text{BC}}[/tex]

[tex]y=(3) x+b_{\text{BC}}[/tex]

Substituting values for a known point (point B) on line BC...

[tex](3)=3 * (8)+b_{\text{BC}}[/tex]

[tex]3=24+b_{\text{BC}}[/tex]

[tex](3)-24=(24+b_{\text{BC}})-24[/tex]

[tex]-21=b_{\text{BC}}[/tex]

So, the equation for line BC is  [tex]y=3 x -21[/tex]

Answer:

10

Step-by-step explanation:

Answer:

Total Miles he  drives first day      = 8 miles

Total Miles he drive second day   = 12miles

Total Miles he drives third day    =    18miles

Total Miles he drives fourth day    =  27 miles

Step-by-step explanation:

This is a problem of linear equations in 1 variable:

The linear equations in one variable is an equation which is expressed in the form of ax + b = 0, where a and b are two integers, and x is a variable and has only one solution.

It is given in the question that ,

This week his goal is to drive bike about 65 total miles over four days. Each day, he wants to ride 1.5 times as far as he rode the day before.

Let, on the first day, he drives x miles. On second day, he drives 1.5x. On the third day, he drives 1.5(1.5x) and on the fourth day, he drives 1.5(1.5(1.5x)).

So the equation is :

x +1.5x + 1.5(1.5x) + 1.5(1.5(1.5x)) = 65miles

x + 1.5x + 2.25x + 3.375x   = 65miles

            8.125x   =    65 miles

                  x   =  65/8.125  miles

                  x   = 8 miles

so after solving the equation we get, on the first day Gavin drives 8 miles

similarly, on the second day he drives 12miles

               on third day 18 miles

   and     on the fourth day  27miles

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Answer:

C

Step-by-step explanation:

a = 4

b = 5

c = 2

C = arccos((a² + b² - c²) / 2ab)

C = arccos((16 + 25 - 4) / 2(4)(5))

C = arccos(37 / 40)

C = 22.33°

2abcosC

2(4)(5)cos(22.33)

40(0.925)

37

Option C is correct, if the law of cosines is a² + b² - 2abcosC = c² then the value of 2abcosC is 37.

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

We have from law of cosines that a² + b² - 2abcosC = c²

We have to find the value of 2abcosC.

Now let us find the value of C

C = arccos((a² + b² - c²) / 2ab)

C = arccos((16 + 25 - 4) / 2(4)(5))

C = arccos(37 / 40)

C = 22.33°

Now plug in the value of C in  2abcosC.

2abcosC

=2(4)(5)cos(22.33)

=40(0.925)

=37

Hence, option C is correct, if the law of cosines is a² + b² - 2abcosC = c² then the value of 2abcosC is 37.

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Adding 2x to both sides, we get [tex]\boxed{2x+y=5}[/tex]

Answer:

9

Step-by-step explanation:

The Pythagorean Theorem is a² + b² = c². c² is the hypotenuse while a² and b² are the legs.

So plugging it into the equation,

a² + 12² = 15²

a² + 144 = 225

a² = 81

a = 9

steps:

1. square the values

2. isolate the missing value

3. take the square root of both sides

Answer:

4/2 is the wrong answer

Step-by-step explanation:

because it is

Answer:

y = 4(x+6)(x-2)

Step-by-step explanation:

y = 4x² + 16x - 48, factor out the 4

y = 4(x² + 4x - 12), find factors of 12

Factors of 12:

1*12, 2*6, 3*4; find a pair that sums to 4x or 4

6-2 = 4, since 12 is a negative number, a number in the factor must be negative, in this case, making 2 negative, would make 6-2 = 4

y = 4(x+6)(x-2)

Answer:

[tex] {( \sqrt{ {x}^{ - 3} }) }^{5} = ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5} \\ \\ = {x}^{ - 3 \times \frac{1}{2} \times 5} = {x}^{ - \frac{15}{2} } = \frac{1}{ {x}^{ \frac{15}{2} } } [/tex]

Or ;

[tex] {( \sqrt{ {x}^{ - 3} } )}^{5} = {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5} = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5} \\ \\ = ( { \frac{1}{ \sqrt{x} \sqrt{ {x}^{2} } } })^{5} = ({ \frac{1}{ x\sqrt{x} }})^{5} \\ \\ = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) = \frac{1}{ {x}^{5} \times {x}^{ \frac{1}{2} \times 5 } } \\ \\ = \frac{1}{ {x}^{5} \times {x}^{ \frac{5}{2} } } = \frac{1}{ {x}^{5} \sqrt{ {x}^{5} } } \\ \\ = \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1} } } = \frac{1}{ {x}^{5} \sqrt{x} \sqrt{( { {x}^{2} })^{2} } } \\ \\ = \frac{1}{ {x}^{5} {x}^{2} \sqrt{x} } = \frac{1}{ {x}^{7} \sqrt{x} } = \frac{ \sqrt{x} }{ {x}^{8} } [/tex]

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: x = 25°[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: 4x - 13 = 2x + 37[/tex]

[ Alternate Exterior Angle ]

[tex]\qquad \tt \rightarrow \: 4x - 2x = 37 + 13[/tex]

[tex]\qquad \tt \rightarrow \: 2x = 50[/tex]

[tex]\qquad \tt \rightarrow \: x = \cfrac{50}{2} [/tex]

[tex]\qquad \tt \rightarrow \: x = 25 \degree[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

After all the conditions you applied from the statement given you will get the original number as 16.08.

An algebraic equation is when two expressions are set equal to each other, and at least one variable is included.

Given that, if you subtract 0.3 from a certain number, add 0.4 times the original number to the result and then add another 2.78, you'll get 25.

We need to find the original number.

Let us take the original number as x.

Now, subtract 0.3 from the original number.

That is x-0.3.

0.4 times the original number is 0.4x.

Add 0.4 times the original number to the result.

That is, x-0.3+0.4x=1.4x-0.3

Now, add 2.78 to the result. That is 1.4x-0.3+2.78=1.4x+2.48.

As a result, you'll get 25. That is 1.4x+2.48=25

⇒1.4x=22.52

⇒x=16.08

There, the original number is 16.08.

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Answer:

Step-by-step explanation:

The domain is the set of x values, and the range is the set of y values.

Answers:

=======================================================

Work Shown:

n = number of sides = 26

S = sum of the interior angles of a polygon with n sides

S = 180(n-2)

S = 180(26-2)

S = 180(24)

S = 4320 degrees is the sum of the interior angles.

i = measure of one interior angle of a regular polygon

i = S/n

i = 4320/26

i = 166.1538 approximately

i = 166.15 degrees is the approximate measure of each interior angle.

Side note: The formula to determine the interior angle i only works for regular polygons. This is because each angle is the same measure.

Answer:

[tex]1)\text{ Friday}\\2)\text{ }7:00\\3a)\text{ }0\\3b)\text{ }4\\3c)\text{ }0\\4a)\text{ }6\\4b)\text{ }4\\4c)\text{ }2[/tex]

Answer:

CI = $182.25

Step-by-step explanation:

Compound interest formula:

[tex]Compound \space\ Interest= P(1 + \frac{r}{100})^{n} - P[/tex]  ,

where P is the principal amount ($4000), r is the interest rate (2%), and n is the time period (2 years and 3 months = 2.25 years).

Using formula:

CI = [tex]4000(1 + \frac{2}{100} )^{2.25} - 4000[/tex]

CI = $182.25

Answer:

A. $60.25

B. 76 miles

C. 216 miles

Step-by-step explanation:

x is miles

y is total amount spent

For A, 57 miles is the x value. Plug that in to x.

y= 46 + .25(57)

y= 60.25

For B, the total is the y. So plug 65 in for y.

65 = 46 + .25x   Subtract 46 from both sides

19 = .25x             Divide by .25

76 = x

For C, the maximum you can spend is $100. Plug that in for y.

100 = 46 + .25x   Subtract 46 from both sides

54 = .25x             Divide by .25

216 = x

The answer for part a is $60.25, for part b the answer is 76 miles, and for part c the answer is 216 miles.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The equation to represent the cost would be y=46+0.25x

x is the number of miles.

a) What is your cost if you travel 57 miles?

Plug x = 57 in the above equation:

y = 46 + 0.25(57)

y = $60.25

b) If your cost was $65.00, how many miles were you charged for traveling?

Plug y = 65 in the equation:

65 = 46 + 0.25x

x = 76 miles

c) Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?

Plug y = 100 in the equation:

100 = 46 + 0.25x

x = 216 miles

Thus, the answer for part a is $60.25, for part b the answer is 76 miles, and for part c the answer is 216 miles.

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