8. Expand, then simplify: (2 Points) (2a – 3) (a2 + 3a - 5) ​

Answers

Answer 1

Hello

just a second

people reading this please complete because you will help me a lot.

I am an Indian girl my name is Lamer and am 13 years old.

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Related Questions

The angle measurements in the diagram are represented by the following expressions.

Answers

Answer:

114 degrees

Step-by-step explanation:

6x+12=3x+63

-3x -12 -3x  -12

3x=51

x=17

6(17) +12 = 114

Part A: A store had a 20% off
Black Friday sale. One item was
originally $75. How much was it on
sale for? Part B: if that same store gave an extra 10% off for using their credit card, what’s the final cost of the item (not including tax)

Answers

Answer:

Part A: $60

Part B: $54

Step-by-step explanation:

There are 60 students eating lunch in the cafeteria five-tenths of them brought lunches from home. How many students brought lunches from home?

Answers

Five-tenths is equal to a half and half of 60 is 30 so the answer would be 30 students!:)

Answer: 30   Hope this helps please mark brainliest! Thanks!

Step-by-step explanation:

Five tenths=5/10=50%=1/2

So basically it's 30 out of 60 students brought lunch from home.

So the answer is 30!

PLEASEEEEE HELP…
In Exploration 3.1.2 you went through a procedure that helped you see how a formula
with n compounds per year relates to the formula for compounding continuously. Select
the appropriate answers to model what you did in the exploration.
Annual growth Rate
A (t) = P(1 + r)
n compounds per year
nt
A () = (1+ a)
a =
[Select]
n
let z = -
7
A (t) = P(1 + [b])"
b = (Select)
let n = ar
Ict
C =
[Select)
A (0) P(1)
110) - P{(x - 2)
+
2

Answers

The growth amount is given by the growth rate the duration of the growth

and how the rate is applied to each period.

The correct selections are;

a = n[tex]\displaystyle b = \frac{1}{x}[/tex]c = x·r[tex]\displaystyle \lim_{x \to \infty} \left(1 + \frac{1}{x} \right)^x \to 1[/tex]

Reasons:

First part;

The given formula for the annual growth rate is; [tex]A(t) = \mathbf{P \cdot \left(1 + r)^t}[/tex]

[tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{r}{[a]} \right)^{n \cdot t}}[/tex]

Where;

P = The principal

r = The rate per period

n = The number of compounding per period

t = The number of periods

In the above formula, we have that the number of compounding per periods = n

Therefore;

a = n

Which gives the fraction of the interest applied to each period as [tex]\displaystyle \frac{r}{n}[/tex]

Which gives;

[tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{r}{n} \right)^{n \cdot t}}[/tex]

Second part;

When [tex]x = \displaystyle \frac{n}{r}[/tex], we have; [tex]A(t) = \mathbf{P \cdot \left(1 + [b])^{n \cdot t}}[/tex]

[tex]\displaystyle A(t) = P \cdot \left (1 + \frac{r}{n} \right)^{n \cdot t}[/tex]

Therefore;

[tex]\displaystyle b=\frac{r}{n}[/tex]

[tex]\displaystyle \frac{1}{x} = \frac{1}{\left(\frac{n}{r} \right)} =\frac{r}{n}[/tex]

Which gives;

[tex]\displaystyle b=\frac{r}{n} = \mathbf{\frac{1}{x}}[/tex]

[tex]\displaystyle \underline{ b = \frac{1}{x} }[/tex]

Third part;

Where, n = x·r, and [tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{1}{x} \right)^{[c] \cdot t}}[/tex]

We have;

[tex]\displaystyle x= \frac{n}{r}[/tex]

[tex]\displaystyle \frac{1}{x}=\frac{r}{n}[/tex]

[tex]\displaystyle A(t) = P \cdot \left (1 + \frac{1}{x} \right)^{[c] \cdot t} = \mathbf{P \cdot \left (1 + \frac{r}{n} \right)^{[c] \cdot t}}[/tex]

Which gives;

c = n = x·r

c = x·r

Fourth part;

If x is a really large number, we have; [tex]\displaystyle \mathbf{\left(1 + \frac{1}{x} \right)^x}[/tex]

Where x approaches ∞, we have;

[tex]\displaystyle \frac{1}{\infty}=0[/tex]

Which gives;

[tex]\displaystyle \displaystyle \left(1 + \frac{1}{x} \right)^x= \left(1 + \frac{1}{\infty} \right)^\infty = \displaystyle \left(1 + 0\right)^\infty = 1 ^\infty = 1[/tex]

[tex]\displaystyle \underline{\lim_{x \to \infty} \left(1 + \frac{1}{x} \right)^x \to 1}[/tex]

Learn more about growth rate formula here:

https://brainly.com/question/2284816

Tres profesores compraron libros: uno de ellos pago $845 por 3 libros de Algebra, 5 libros de Geometría Analítica y 2 libros de Cálculo Diferencial. Otro pago $580 por 2 libros de Geometría Analítica, 4 libros de Algebra y 1 libro de Cálculo Diferencial. El último de ellos pago $605 por un libro de Algebra, 3 libros de Geometría Analítica y 3 de Cálculo Diferencial. ¿Cuál es el costo de cada libro según su tema?

Answers

Usando un sistema de ecuaciones, se encuentra que

$96.875 es el costo de un libro de Algebra.$23.125 es el costo de un libro de Geometría Analítica.$146.25 es el costo de un libro de Calculo Diferencial.

Para el sistema, hay que:

x es el costo de un libro de Algebra.y es el costo de un libro de Geometría Analítica.z es el costo de un libro de Calculo Diferencial.

$845 por 3 libros de Algebra, 5 libros de Geometría Analítica y 2 libros de Cálculo Diferencial, o sea:

[tex]3x + 5y + 3z = 845[/tex]

$580 por 2 libros de Geometría Analítica, 4 libros de Algebra y 1 libro de Cálculo Diferencial, o sea:

[tex]4x + 2y + z = 580[/tex]

$605 por un libro de Algebra, 3 libros de Geometría Analítica y 3 de Cálculo Diferencial, o sea:

[tex]x + 3y + 3z = 605[/tex]

Reemplazando la segunda equación en las otras duas:

[tex]z = 580 - 4x - 2y[/tex]

[tex]3x + 5y + 3z = 845[/tex]

[tex]3x + 5y + 3(580 - 4x - 2y) = 845[/tex]

[tex]-9x - y = -895[/tex]

[tex]9x + y = 895[/tex]

[tex]y = 895 - 9x[/tex]

[tex]x + 3y + 3z = 605[/tex]

[tex]x + 3y + 3(580 - 4x - 2y) = 605[/tex]

[tex]-11x - 3y = -1135[/tex]

[tex]11x + 3y = 1135[/tex]

[tex]y = 895 - 9x[/tex], por eso:

[tex]11x + 3(895 - 9x) = 1135[/tex]

[tex]-16x = -1550[/tex]

[tex]x = \frac{1150}{16}[/tex]

[tex]x = 96.875[/tex]

[tex]y = 895 - 9x = 895 - 9(96.875) = 23.125[/tex]

[tex]z = 580 - 4(96.875) - 2(23.125) = 146.25[/tex]

$96.875 es el costo de un libro de Algebra.$23.125 es el costo de un libro de Geometría Analítica.$146.25 es el costo de un libro de Calculo Diferencial.

Un problema similar, que también envuelve un sistema de ecuaciones, es dado en https://brainly.com/question/24646137

In the figure given, what is the (numerical) value of x?
(5a)
(4a)

Answers

Do you mean the value of a?

Systems of elimination for
2w-3q=8
3w-7q=7

Answers

i guess is by multiplying 3by the first equation and multiply 2by the second equation

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

Answers

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

[tex]\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}[/tex]

Then

[tex]Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\[/tex]

Note that since

[tex]F \cap R=\varnothing[/tex], [tex]Perm(F)\cap Perm(R)\ne \varnothing[/tex]

But since

[tex]B \cap R \ne \varnothing[/tex], [tex]Perm(B)\cap Perm(R)= \varnothing[/tex]

and

[tex]B \cap F \ne \varnothing[/tex] , [tex]Perm(B)\cap Perm(F)= \varnothing[/tex]

Since

[tex]|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\[/tex]

where [tex]|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}[/tex]

and

[tex]|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}[/tex]

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

[tex]|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}[/tex]

This link contains another solved problem on permutations:

https://brainly.com/question/7951365

Lia has 72 green grapes that are shared equally between 8 of her friends. Darrel adds 41 green grapes to his share. How many grapes does Darrel have in all

Answers

The answer would be 49 because 72 divided by 8 would be 9 and you add 41 you get 49

Darrel has 50 grapes in all.

Lia has 72 green grapes, and she shares them equally between 8 friends. To find out how many grapes each friend receives, divide the total number of grapes by the number of friends:

Number of grapes each friend receives = 72 / 8 = 9

Now, Darrel adds 41 green grapes to his share, so the total number of grapes he has is:

Total grapes for Darrel = Number of grapes Darrel received initially + Additional grapes added by Darrel

Total grapes for Darrel = 9 + 41 = 50

To know more about grapes:

https://brainly.com/question/22694731

#SPJ2

Anyone know how to answer this

Answers

Answer:

21

Step-by-step explanation:

The average rate of change of function f(x) from x = a to x = b is

[tex] \dfrac{f(b) - f(a)}{b - a} [/tex]

Here we have

a = -1

b = 2

f(a) = f(-1) = 1

f(b) = f(2) = 64

[tex] \dfrac{f(b) - f(a)}{b - a} = [/tex]

[tex] = \dfrac{f(2) - f(-1)}{2 - (-1)} = [/tex]

[tex] = \dfrac{64 - 1}{2 + 1} [/tex]

[tex] = \dfrac{63}{3} [/tex]

[tex] = 21 [/tex]

A baseball tournament begins with 128 teams. After each round of games, only half of the teams are left. How many teams will be left after three rounds of games?

Answers

Answer:

End of round 1:

128 ÷ 2 = 64

End of round 2:

64 ÷ 2 = 32

End of round 3:

32 ÷ 2 = 16

Step-by-step explanation:

Answer: 16

Step-by-step explanation: i think :)

Twelve football teams are playing in a league. Each team played each of the other teams exactly once. How many matches were played in the league? *
1 point
a. 72
b. 66
c. 11
d. 132

Answers

Each team will play with 11 other teams. Hence each team plays 11 games. Hence a total of 11*12 =132 games but since each game involves two teams divide 132/2 = 66 so B

1. The coordinates tell you that every 12 seconds 5 gallons of water runs from the
hose into a bucket
How many gallons of water were in the bucket after 1 second

Answers

Answer:

5/12 of a gallon

Step-by-step explanation:

5 divided by 12 is 5/12

Which two integers is 129 between?

Answers

Answer:

128 130

Step-by-step explanation:

128 129 130

at breakfast yusef drinks 16 ounces of water

Answers

Answer:

Step-by-step explanation:

K, but what's the question?

ANSWER QUICKLY WILL GIVE BRAINLIEST

Answers

Answer:

\sqrt(3)[cos((4\pi )/(45))+isin((4\pi )/(45))]

Step-by-step explanation:

The first one.

f(c)=x²-3x
find f (-8)

Answers

Answer:

88

Step-by-step explanation:

Given function:

f(x) = x² - 3x

Find f(-8):

f(-8) = (-8)² - 3(-8) = 64 + 24 = 88

f(-8)

(-8)²-3(-8)64+2488

four more than the price ,p

Answers

What? What do you need help with?

At a charity fund-raiser, adult tickets were sold for $7 each and children's tickets were sold for $2 each. Write an algebraic expression for the total amount of
money raised from the sale of tickets. How much money was raised if the fundraiser fsold 246 adult tickets and 380 children's tickets?
Let a = the number of adult tickets and let c = the number of child tickets. Then, an algebraic expression for the total money raised from the sale of tickets is

Answers

Answer:

x is amount of money

c + a = 646

2c + 7a = x

2(380) + 7(246) = 2486

x = $2486

Which inequality is best represented by the following number line?

Answers

Answer:

A

Step-by-step explanation:

Answer:

solve:

-3x+10<dividing22

-3x< 12

by a negativie flips sign

x>4

So A is correct because the because its an open circle  on number line

there are 16 children and 24 adults what percent are children and what percent are adults

Answers

Answer:

60% adult

40% children

Reasoning:

Add the adults and children first.

Then find the ratios of the children and parent percentages.

16:40 children

24:40 adult

16/40=2/5=0.4=40% children

24/40=3/5=0.6=60% adult

Answer:

40% is children and 60% in adults

Step-by-step explanation:

so if you add the two you have 40, 100% of 40 is 40 and 50% is 20, so we know that the children percent is less than 50, if you go through you will find that 40% of 40 is 16 therefor leaving the rest (aka 60%) to be adults

dividing 0.68÷0.6936

Answers

The correct answer is 0.9803

Answer:

0.9804

Step-by-step explanation:

0.68 ÷ 0.6936 = 0.98039215686275

A line passes through the points (1, 4) and (3 -4). Which is the equation of the line?

Answers

Answer:

Step-by-step explanation:

(-4 - 4)/(3 - 1)= -8/2= -4

y - 4 = -4(x - 1)

y - 4 = -4x + 4

y = -4x + 8

answer is option 1

The Clark family bought 8 crates of eggs last week. Each crate had 12 eggs. Since then, they have eaten 28 of the eggs. How many eggs are left?

Answers

8 • 12 -28

96 - 28

68

68 eggs are left.

State what additional information is required in order to know that the triangles are congruent for the reason given. If possible, write the triangle congruence statement.

refer to attachment

Answers

Answer:

SU ≅ RPΔPQR ≅ ΔUTS

Step-by-step explanation:

For SSS congruence, all three pairs of sides must be marked as congruent. That is, there needs to be 3 hash marks on sides SU and RP. (Note the order of the vertices.)

  needed: SU ≅ RP

If we label the triangles in order by hash marks, the congruence statement becomes ...

  ΔPQR ≅ ΔUTS

the first term of an AP is 2,and the last term is 59.if the sum of the first terms is 610,Find the common difference​

Answers

Answer:

d = 3

Step-by-step explanation:

The sum to n terms of an AP is

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] ( a + l)

where a is the first term and l the last term

Here a = 2, l = 59 and sum = 610 , then

[tex]\frac{n}{2}[/tex] (2 + 59) = 610

[tex]\frac{n}{2}[/tex] × 61 = 610 ( divide both sides by 61 )

[tex]\frac{n}{2}[/tex] = 10 ( multiply both sides by 2 to clear the fraction )

n = 20

Then the sequence has 20 terms with a₂₀ = 59

The nth term of an AP is

[tex]a_{n}[/tex] = a + (n - 1)d

where d is the common difference , then

2 + 19d = 59 ( subtract 2 from both sides )

19d = 57 ( divide both sides by 19 )

d = 3

please this is half my grade!!!
Benjamin has a ladder that is 15 ft long. He wants to lean the ladder against a vertical wall so that the top of the ladder is 13.8 ft above the ground. What is the angle, rounded to the nearest tenth, that the ladder makes with the ground? Show your work
2. What is the length of side YZ to the nearest tenth? Show your work.
side XY is 11 feet, and angle Z is 35 degrees(this is a right triangle)



3. What are the exact measures of the other two sides of the triangle? Use special right triangles ratios and show your work.
Side AC is 14 feet, this is a right triangle, and angle A is 30 degrees

Answers

The special right triangle is the right triangle that have acute angle values

that simplify the process of finding its dimensions.

The correct values are;

1. The angle the ladder makes with the ground, is approximately 66.93°

2. The length of YZ is approximately 19.18 ft.

3. CB = 7 ft. and AB = 7·√3 ft.

Reasons:

1. The length of the ladder = 15 ft.

Height of the ladder above the ground, h = 13.8 ft.

Required:

The angle the ladder makes with the ground.

Solution:

The angle the ladder makes with the ground is given by the equation;

[tex]sin(\theta) = \dfrac{Length \ of \ the \ ladder}{Height\ of \ the \ ladder \ above the \ ground} = \dfrac{13.8}{15} = 0.92[/tex]

[tex]\theta = arcsin\left(0.92 \right) \approx 66.93^{\circ}[/tex]

2. The given parameters are;

XY = 11

∠Z = 35°

YZ = Required

In a right triangle, the side facing the acute angle is a leg of the triangle.

Therefore;

XY is the opposite side to ∠Z

[tex]sin(\angle Z) = \dfrac{XY}{YZ}[/tex]

Which gives;

[tex]sin(35^{\circ}) = \dfrac{11}{YZ}[/tex]

[tex]YZ= \dfrac{11}{sin(35^{\circ}) } \approx 19.18[/tex]

YZ ≈ 19.18 ft.

3. AC = 14 ft.

∠A = 30

Required:

The length of the other two sides

Solution:

Where by AC is the hypotenuse side, we have;

CB = AC × sin(∠A)

Therefore;

CB = 14 × sin(30°) = 7

CB = 7 ft.

AB =  AC × cos(∠A) = 14 × cos(30°) = 7·√3

Learn more here:

https://brainly.com/question/12237712

1. The angle the ladder makes with the ground, is approximately 66.93°

2. The length of YZ is approximately 19.18 ft.

3. CB = 7 ft. and AB = 7·√3 ft.

A sixth grade class has 12 boys and 24 girls.

For every 2 boys, there are 4 girls. Do you agree with this statement? Explain.

Answers

Answer:

Yes

Step-by-step explanation:

The best way to solve this question is to use ratios. The first ratio to make is 12:24. This represents how there are 12 boys for 24 girls. Ratios remain equivalent as long as both sides of the ratio are simplified by the same number. So, you can divide both sides by 6. When you divide both sides you get 2:4. Therefore, there are 2 boys for 4 girls.

What number president was john quincy adams.

Answers

Answer:

6

Step-by-step explanation:

john quincy adams was the 6th president

Guys please help asap i don't want to fail
Consider the sequence shown.

Answers

Answer:

The answer is option D

Step-by-step explanation:

f (n)=-2. (-5)^n-1. Jesus loves you

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