8. Peter and his partner are conducting a physics experiment on pendulum motion. Their 30-cm


pendulur traverses an arc of 15 cm. To the nearest degree, how many degrees of rotation did


the pendulum swing?

Answer:

u=6

Step-by-step explanation:

One rule in algebra is what you do to one side, you do it to other side. So if you multiply a number in one side, multiply the same number in other side. Here in this question, you are trying to find the value of the variable u. Variable is called so because the value of it varies depending on different question. Here u is going to be a constant number which when multipled by 3 and then subtracted by 3 equals 15.

So first step is we try to get constants on one side. So we add 3 on both sides to get rid of 3 on left.

3u - 3 + 3= 15+3

3u= 18

Now we divide by 3 on both sides to get u by itself.

3u/3 = 18/3

u= 6

Answer:

The calculated value t = 1.57736 < 1.9845 at 5 % level of significance

Null hypothesis is accepted at 5 % level of significance

There is no significance difference between Design A and Design B

Step-by-step explanation:

Given  sample size of design A

                                            n₁ = 50

sample mean of design A x⁻₁ = 4.1 minutes

Sample standard deviation S₁ = 2.2 minutes

Given  sample size of design B

                                            n₂ = 50

sample mean of design A x⁻₂ = 3.5 minutes

Sample standard deviation S₂ = 1.5 minutes

Null Hypothesis : H₀ : There is no significance difference between Design A and Design B

Alternative Hypothesis : H₁:There is  significance difference between Design A and Design B

Level of significance ∝ = 0.05

Test statistic

[tex]t = \frac{x^{-} _{1}- x^{-} _{2} }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} }) } }[/tex]

where

[tex]S^{2} = \frac{n_{1} S_{1} ^{2} +n_{2} S^2_{2} }{n_{1} +n_{2} -2}[/tex]

[tex]S^{2} = \frac{50 (2.2)^{2} +50(1.5)^2}{50+50-2}[/tex]

On calculation , we get

S² = 3.6173

Test statistic

                   [tex]t = \frac{4.1-3.5}{\sqrt{3.617(\frac{1}{50} +\frac{1}{50} }) }[/tex]

On calculation , we get

   t = 1.57736

Degrees of freedom

ν = n₁ + n₂ -2 = 50 +50 -2 =98

t₀.₀₂₅ ,₉₈ = 1.9845

The calculated value t = 1.57736 < 1.9845 at 5 % level of significance

null hypothesis is accepted

Answer:

a)3145 x 0.01 = 31.45  3145- 31.45 = 3113.55

Compute the sample correlation 3113.55 -? we find the least square pressing at least 15x on the calculator then minus this from 3113.55 to find a better fit and minimum regression.

We add the differences of units then divide by distribution as seen below.

b) unsure.

c) = (see below) just test each number shown unit sold per day / price then x can show the differences in each number from day 1 to day 2.

d) = 16 sold.

Step-by-step explanation:

a) We count the units up and deduct from it from the equation p is recognized as units sold. R1 is cost R2 is total days.

b) The line of best fit is described by the equation ŷ = bX + a, where b is the slope of the line and a is the intercept (i.e., the value of Y when X = 0).

c) r 2= decimal ; the regression equation has accounted for percentage of the total sum of squares. You cna do this one.

d) = 16 sold at $28 each. - Why ? We using 7 day data and prove a how many units can be sold p/d if the price of flash drive is set to $28 each per unit.

Day 1 = 34  /  28  =  1      =    1.21428571429 = 1 no difference day prior.

Day 2 = 336   / 28   = 12  = 12 = difference day prior is 11

Day 3 = 432  / 28  = 15    =  15.4285714286   = 15 difference day prior is 3

Day 4 = 635  / 28 =  23   =  22.6785714286  = 23 difference day prior is 8

Day 5  = 530  /  28 = 19    =  18.9285714286  = 19 difference day prior is minus - 4

Day 6 = 938  / 28  =  34   = 33.5 = 34 difference day prior is 15

Day 7 = 240  / 28  =   9    =   8.57142857143 = 9 difference day prior is minus -25

Total days 7 = Total revenue / price = average units sold

Average units sold total = 1+ 12+15 +23 +19+34+9 = 113 rounded.

Average units sold total = 1.21428571429 + 12 + 15.4285714286

+ 22.6785714286

+18.9285714286

+ 33.5

+ 8.57142857143 =  112.321428572 units sold weekly when priced at $28

To answer D we divide this by 7  to show;

112.321428572/ 7 = 16.0459183674

Daily units sold = 16

the answer is A: 146 ≤ 9c + 10

Answer:

The total number of marbles in the bag is 50.

Step-by-step explanation:

Here, we have n trials, without replacement. So the hypergeometric distribution is used.

The mean of the hypergeometric distribution is:

[tex]E(X) = \frac{n*k}{N}[/tex]

In which n is the number of items in the sample, k is the number of items in the population that are classified a success and N is the size of the population.

15 marbles are drawn:

This means that [tex]n = 15[/tex]

A bag contains some number of marbles. It is known that 20 of them are red.

This means that [tex]k = 20[/tex], since a success is drawing a red marble.

Assuming E(X)=6 red, what is the total number of marbles in the bag?

We have to find N when [tex]E(X) = 6[/tex]

So

[tex]E(X) = \frac{n*k}{N}[/tex]

[tex]6 = \frac{15*20}{N}[/tex]

[tex]6N = 300[/tex]

[tex]N = \frac{300}{6}[/tex]

[tex]N = 50[/tex]

The total number of marbles in the bag is 50.

Answer:

a = 29.3785

Step-by-step explanation:

Given ∠A = 46° and ∠B = 105°

we know that ∠A +∠B+∠C = 180°

                       46° + 105° +∠C = 180°

                      ∠C = 180 - 46 -105

                     ∠ C = 29°

By using sine rule

[tex]\frac{a}{sin A} = \frac{b}{Sin B} = \frac{c}{Sin C} = 2 R[/tex]

[tex]\frac{a}{sin A} = \frac{c}{Sin C}[/tex]

Given ∠A = 46° and  ∠ C = 29° and c = 19.8

[tex]\frac{a}{sin 46} = \frac{19.8}{Sin 29}[/tex]

on cross multiplication , we get

[tex]a = \frac{19.8 X sin 46}{Sin 29}[/tex]

a = 29.3785

Answer:

The answer is A: ( - ∞, 1 )

Step-by-step explanation:

Answer:

[tex]P(X<3) =[/tex] [tex]0.9619[/tex]

Step-by-step explanation:

From the given information;

the probability of getting returned p = 0.1

If eight rings are sold today, what is the probability that fewer than three will be returned;

According to binomial distribution

Binomial distribution is the probability of success or failure of an outcome of an experiment under observation which is usually repeated several trials. Binomial experiments are random experiment with fixed number of repeated experiment. If we cannot predict before head, the outcome of an experiment , the experiment is called a random experiment.

So , using binomial distribution to determine the probability that fewer than three will be returned;

i.e

[tex]P(X<3) =[/tex] [tex]\sum_{x=0}^{2}\binom{8}{x}(0.1)^{x}(1-0.1)^{8-x}[/tex]

[tex]P(X<3) =[/tex] [tex]0.9619[/tex]

The image of P(-2,1) after it is rotated 90° is (-1,-2).

Answer:

(1) 4x + 28 (2) 18x- 27

Step-by-step explanation:

the first question 4(x + 7) can be simplified by multiplying the number outside the parenthesis (4) by both of the values inside:

4x + 28 or the last answer choice

in the second question you can use the same method:

9 (2x) = 18x

9 ( -3) = -27

therefore the correct answer choice is 18x - 27

hope this helps :)

Answer:

You would move 10 units to the right from zero on the x-axis.

The given point is 10 units from zero, when you move on the x-axis to reach the point (10, 8).

A coordinate plane is a two-dimensional surface formed by two number lines. It is formed when a horizontal line (the X-axis) and a vertical line (the Y-axis) intersect at a point called the origin. The numbers on a coordinate grid are used to locate points.

The given coordinate point (10, 8).

The distance of any point from the x-axis is called the x-coordinate.

In the point (10, 8), 10 units from the x-axis

Therefore, the given point is 10 units from zero, when you move on the x-axis to reach the point (10, 8).

Learn more about the coordinate plane here:

https://brainly.com/question/24134413.

#SPJ6

Answer:

7.He borrowed $1853.33

8.She received $28990.936

Step-by-step explanation:

7.Let x be the amount borrowed by Tyson

Rate of interest = 7.5%

Time = 2.5 years

Simple Interest = 347.50

Formula : [tex]Si = \frac{P \times T \times R}{100}[/tex]

Where SI = simple interest

P = Principal

T = Time

R = Rate of interest

Substitute the values in the formula :

[tex]347.50=\frac{x \times 2.5 \times 7.5}{100}\\\frac{347.50 \times 100}{2.5 \times 7.5}=x\\1853.33=x[/tex]

Hence he borrowed $1853.33

8) Principal = 20000

Rate of interest = 9.5%

No. of compounds per year = 2

Time = 4 years

Formula : [tex]A=P(1+\frac{r}{n})z^{nt}[/tex]

Where A= amount

r = Rate of interest

n = no. of compounds

t = time

Substitute the values in the formula :

So, [tex]A=20000(1+\frac{9.5}{200})^{2(4)}[/tex]

A=28990.936

Hence she received $28990.936

Answer: 0.007

Step-by-step explanation:

Suppose that you have a ticket.

We have 3 prizes, and 300 tickets.

After the first tiket is drawn, someone win a prize, so now we have 299 tikets left and 2 prizes left.

Then, for the next draw, you have p = 1/299 of wining a prize.

If you did not win there, the probability for the third price is p = 1/298 (because there are 2 less tickets now)

Then the probability of winning at least one prize is:

P = 1/299 + 1/298 = 0.007

Answer:

Step-by-step explanation:

Hello!

Given the data for the variables:

Y: Selling price of a house on the shore of Tawas Bay

X₁: Number of bathrooms of a house on the shore of Tawas Bay.

X₂: Square feet of a house on the shore of Tawas Bay.

X₃: Number of bedrooms of a house on the shore of Tawas Bay.

The multiple regression model is Y= α + β₁X₁ + β₂X₂ + β₃X₃ + εi

a. Using software I've entered the raw data and estimated the regression coefficients:

^α= a= -5531.01

Represents the mean selling price of the houses when 0 bathrooms, 0 square feet and 0 bedrooms.

^β₁= b₁= -1386.21

Represents the modification of the mean selling price of the houses when the number of bathrooms increases in one unit and the square feet and number of bedrooms remain unchanged.

^β₂= b₂= 60.28

Represents the modification of the mean selling price of the houses when the square feet increase in one unit and the number of bathrooms and bedrooms remain unchanged.

^ β₃= b₃= 54797.08

Represents the modification of the mean selling price of the houses when the number of bedrooms increase in one unit and the number of bathrooms and square feet of the houses remain unchanged.

^Y= -5531.01 -1386.21X₁ + 60.28X₂ + 54797.08X₃

b)

R²= 0.55

R²Aj= 0.49

The coefficient of determination gives you an idea of how much of the variability of the dependent variable (Y) is due to the explanatory variables. Each time you add another explanatory variable to the regression the coefficient increases regarding of real contribution of the new variable. This could lead to thinking (wrongly) that the new variables are good to explain the dependent variable.  

The adjusted coefficient of determination is a correction made to the raw coefficient of determination to have a more unbiased estimation of the effect the independent variables have over the dependent variable.

⇒ As you can see both coefficient are around 50%, which means that these explanatory variables

c)

The standard error estimate, this is the estimate of the population variance of the errors. In the ANOVA is represented by the Mean Square of the errors (MME)

Se²= MME= 3837640577.01

Se= 61948.6931

d) and f)

For the hypotheses tests for each slope the t- and p-values are:

α: 0.05

β₁: [tex]t_{H_0}= \frac{b_1-\beta_1 }{Sb_1}[/tex] t= -0.06; p-value: 0.9528 ⇒ Do not reject H₀, the test is not significant.

β₂: [tex]t_{H_0}= \frac{b_2-\beta_2 }{Sb_2}[/tex] t= 2.56; p-value: 0.0180 ⇒ Reject H₀, the test is significant.

β₃: [tex]t_{H_0}= \frac{b_3-\beta_3 }{Sb_3}[/tex] t= 2.28; p-value: 0.0326 ⇒ Reject H₀, the test is significant.

e)

H₀: β₁= β₂= β₃

H₁: At least one βi is different from the others ∀ i=1, 2, 3

α: 0.05

F= 9.03

p-value: 0.0004

⇒ Reject H₀, the test is significant.

I hope it helps!

Answer:

The correct answer to the following question will be Option A (67.9%).

Step-by-step explanation:

As we know,

The number of total employees will be:

= 480

The number of employees having normal or low BP will be:

= 96 + 230

= 326

Hence, the percentage of low or normal BP workers will be:

= [tex](\frac{326}{480} )\times 100 \ percent[/tex]

= [tex]67.9 \ percent[/tex]

Note:- % (percent)

Answer:

Step-by-step explanation:

1) d

2) c

1) 3 hearts, 7 other shapes that isn't hearts

2) 2 triangs, 5 circles

Answer:

1) d

2) c

Step-by-step explanation:

looks like i was wrong last time lol, this is right for sure tho, i see what i did wrong, sorry

Answer:

   9 in

Step-by-step explanation:

For an n-sided polygon, the length of the apothem is ...

  a = r·cos(180°/n)

We assume your problem statement is saying the radius is 10 inches. For a hexagon, n=6 and we have ...

  a = (10 in)cos(30°) ≈ 8.66 in

Rounded to the nearest inch, the apothem is 9 in.

Answer:

$638641.33

Step-by-step explanation:

Adam earns $45,000 in his first year.

His salary increases by 3% each successive year. Therefore, his salary the next year is 103% of his previous year.

This is a geometric sequence where the:

(a)

Sum of  geometric series[tex]=\dfrac{a(r^n-1)}{r-1}[/tex]

Substituting the given values, Adam's total earnings over n years

[tex]=\dfrac{45000(1.03^n-1)}{1.03-1}\\\\$Adam's Total Earnings=\dfrac{45000(1.03^n-1)}{0,03}[/tex]

(b)When n=12 years

[tex]\text{Adam's Total Earnings for the first 12 years=}\dfrac{45000(1.03^{12}-1)}{0.03}\\=\$638641.33$ (correct to the nearest cent)[/tex]

Answer:

(a)No. The probability of drawing a specific second card depends on the identity of the first card.

(b)4/663

(c) 4/663

(d) 8/663

Step-by-step explanation:

(a)The events are not independent because we are drawing cards without replacement and the probability of drawing a specific second card depends on the identity of the first card.

(b) P(ace on 1st card and jack on 2nd).

[tex]P$(Ace on 1st card) =\dfrac{4}{52}\\ P$(Jack on 2nd card)=\dfrac{4}{51}\\\\$Therefore:\\P(ace on 1st card and jack on 2nd) =\dfrac{4}{52}\times \dfrac{4}{51}\\=\dfrac{4}{663}[/tex]

(c)P(jack on 1st card and ace on 2nd)

[tex]P$(Jack on 1st card) =\dfrac{4}{52}\\ P$(Ace on 2nd card)=\dfrac{4}{51}\\\\$Therefore:\\P(jack on 1st card and ace on 2nd) =\dfrac{4}{52}\times \dfrac{4}{51}\\=\dfrac{4}{663}[/tex]

(d)Probability of drawing an ace and a jack in either order.

We can either draw an ace first, jack second or jack first, ace second.

Therefore:

P(drawing an ace and a jack in either order) =P(AJ)+(JA)

From parts (b) and (c) above:

[tex]P$(jack on 1st card and ace on 2nd) =\dfrac{4}{663}\\P$(ace on 1st card and jack on 2nd) =\dfrac{4}{663}\\$Therefore:\\P(drawing an ace and a jack in either order)=\dfrac{4}{663}+\dfrac{4}{663}\\=\dfrac{8}{663}[/tex]

Answer:

c) Yes, because the p-value = 0.0172

Step-by-step explanation:

The following table is obtained:

Categories       Observed(fo)        Expected (fe)        (fo-fe)²/fe

NW Oregon        3109           4357*0.727=3167.539       1.082

SW Oregon        902             4357*0.207=901.899           0

Central Oregon    244          4357*0.048=209.136         5.812

Eastern Oregon    102           4357*0.028=121.996         3.277

Sum =                    4357        4357                                   10.171

(1) Null and Alternative Hypotheses

The following null and alternative hypotheses need to be tested:

H0​:p1​=0.727,p2​=0.207,p3​=0.048,p4​=0.028

Ha​: Some of the population proportions differ from the values stated in the null hypothesis

This corresponds to a Chi-Square test for Goodness of Fit.

(2) Rejection Region

Based on the information provided, the significance level is α=0.05, the number of degrees of freedom is df=4−1=3, so then the rejection region for this test is R={χ2:χ2>7.815}.

(3) Test Statistics

The Chi-Squared statistic is computed as follows:

[tex]X^2=\sum^n_{i=1}\frac{(O_i-E_i)^2}{y} \\\\= 1.082+0+5.812 +3.277 = 10.171[/tex]

(4) Decision about the null hypothesis

Since it is observed that

[tex]X^2 = 10.171 > X_c^2 = 7.815[/tex]

it is then concluded that the null hypothesis is rejected.

(5) Conclusion

It is concluded that the null hypothesis H_o is rejected. Therefore, there is enough evidence to claim that some of the population proportions differ from those stated in the null hypothesis, at the α=0.05 significance level.

Answer:

The distribution pattern that will have variance greater than mean is one where the population of species is clustered and thus far from the mean abundance of species per unit area.

This distribution pattern can be found, using the POISSON distribution.

Step-by-step explanation:

Variance is a measure of dispersion while Mean is a measure of central tendency.

The mean is the average of all values (in this case, the abundance or concentration of species per unit area). It is the sum total of all values, divided by the number of values there are.

The variance of a given set of data, on the other hand, is a measure of the spread or distance or dispersal of the data from the mean. It measures the spread between each datum/value and the mean value.

The relationship between mean and variance surely reflects the pattern that the distribution will take. The kind of distribution pattern that will have a greater variance than mean is a Poisson distribution. Sample size is usually large here. Since the variance is greater than the mean, the population is a clustered or clumped distribution.

Answer:

  a.  235°

  b. 146.03 km

  c. 105 km

  d. 193 km

Step-by-step explanation:

a. The bearing of E from A is given as 55°. The bearing in the opposite direction, from E to A, is this angle with 180° added:

  bearing of A from E = 55° +180° = 235°

__

b. The internal angle at E is the difference between the external angle at C and the internal angle at A:

  ∠E = 134° -55° = 79°

The law of sines tells you ...

  CE/sin(∠A) = CA/sin(∠E)

  CE = CA(sin(∠A)/sin(∠E)) = (175 km)·sin(55°)/sin(79°) ≈ 146.03 km

  CE ≈ 146 km

__

c. The internal angle at C is the supplement of the external angle, so is ...

  ∠C = 180° -134° = 46°

The distance PE is opposite that angle, and CE is the hypotenuse of the right triangle CPE. The sine trig relation is helpful here:

  Sin = Opposite/Hypotenuse

  sin(46°) = PE/CE

  PE = CE·sin(46°) = 146.03 km·sin(46°) ≈ 105.05 km

  PE ≈ 105 km

__

d. DE can be found from the law of cosines:

  DE² = DC² +CE² -2·DC·CE·cos(134°)

  DE² = 60² +146.03² -2(60)(146.03)cos(134°) ≈ 37099.43

  DE = √37099.43 ≈ 192.6 . . . km

  DE is about 193 km

Answer:

sale prices = $252

Step-by-step explanation: 280 - (280 x 10%) = 280 - 28 = $252

Answer:

$189

Step-by-step explanation:

10% of 210 = 21

210 - 21  = 189

Answer:

[tex] r =\frac{D}{2}=\frac{18mm}{2}= 9mm[/tex]

The area is given by:

[tex]A= \pi r^2[/tex]

And replacing we got:

[tex] A=\pi (9mm)^2 =81\pi mm^2[/tex]

So then we can conclude that the area of the coin is [tex] 81\pi[/tex] mm^2

Step-by-step explanation:

For this case we know that we have a coin with a diamter of [tex] D =18mm[/tex], and by definition the radius is given by:

[tex] r =\frac{D}{2}=\frac{18mm}{2}= 9mm[/tex]

The area is given by:

[tex]A= \pi r^2[/tex]

And replacing we got:

[tex] A=\pi (9mm)^2 =81\pi mm^2[/tex]

So then we can conclude that the area of the coin is [tex] 81\pi[/tex] mm^2

Answer:

Half-life of the goo is 49.5 minutes

[tex]G(t)= 300e^{-0.014t}[/tex]

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let [tex]M_0\,,\,M_f[/tex] denotes initial and final mass.

[tex]M_0=300\,\,grams\,,\,M_f=37.5\,\,grams[/tex]

According to exponential decay,

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt[/tex]

Here, t denotes time and k denotes decay constant.

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014[/tex]

So, half-life of the goo in minutes is calculated as follows:

[tex]\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes[/tex]

Half-life of the goo is 49.5 minutes

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}[/tex]

So,

[tex]G(t)= M_f=M_0e^{-kt}[/tex]

Put [tex]M_0=300\,\,grams\,,\,k=0.014[/tex]

[tex]G(t)= 300e^{-0.014t}[/tex]

Put t = 32 minutes

[tex]G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams[/tex]

Answer:

B: It takes too much time

Step-by-step explanation:

Once the points have been calculated and then graphed, the solutions to y = 0 can be found. Look for y = 0 and the solutions are -5 and -1. But that takes a lot of time. There must be an easier way, and fortunately, there is.

Answer:

D. 5/13

Step-by-step explanation:

Cosin is adjacent/hypotenuse so, the adjacent would be 5 and the hypotenuse is 13 since it is the longest side. This is viewed from angle B.

Answer:

5/13 (answer D)

Step-by-step explanation:

cos beta = adjacent side / hypotenuse = 5 / 13 (answer D)

Answer:

The correct answer to the following question will be "No". The further explanation is given below.

Step-by-step explanation:

Probability (Keeping the disease out of 1 contact)

= [tex]0.5[/tex]

Probability (not keeping the disease out of 1 contact)

= [tex]1-0.5[/tex]

= [tex]0.5[/tex]

Now,

Probability (not keeping the disease out of 2 contact)

= Keeping the disease out of 1 contact × not keeping the disease out of 1 contact

On putting the estimated values, we get

= [tex]0.5\times 0.5[/tex]

= [tex]0.25[/tex]

So that,

Probability (Keeping the disease out of 2 contact)

= [tex]1-0.25[/tex]

= [tex]0.75 \ i.e., 75 \ percent[/tex]

∴  Not 100%