A 110 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.220 m/s. How much work must be done on the hoop to stop it

Answers

Answer 1

Answer:

the work that must be done to stop the hoop is 2.662 J

Explanation:

Given;

mass of the hoop, m = 110 kg

speed of the center mass, v = 0.22 m/s

The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;

W = ΔK.E

W = ¹/₂mv²

W = ¹/₂ x 110 x 0.22²

W = 2.662 J

Therefore, the work that must be done to stop the hoop is 2.662 J

Answer 2

The amount of work that must be done to stop a hoop of mass 110 kg moving with s speed of 0.220 m/s is 2.662 J

Work can be defined as the ability or the capacity to perform work. Work is also the measure of energy of a body. The S.I unit of work is Joules (J)

From the question,                                                                                     The kinetic energy of the hoop = The energy required to stop the hoop.

Formular for kinetic energy of the hoop is

EK = mv²/2.................... Equation 1

Where EK = Kinetic energy of the hoop, m = mass of the hoop, v = velocity of the hoop.

Given: m = 110kg, v = 0.220 m/s.

Substitute these values into equation 1

EK = 110(0.22)²/2

Ek = 2.662 J.

 

Therefore, The amount of work that must be done on the hoop to stop it is

Learn more about Work here: https://brainly.com/question/12106685


Related Questions

an astronaut must journey to a distant planet, which is 300 light years from earth. what speed will be necessary if the austronaut wishes to age only 12 years during the round trip

Answers

Answer:

First, if you are inside a spaceship that travels with a relativistic speed, your inner time does not change. So your cells and DNA feel the time exactly as how they would feel it on Earth. This means that if you spend 12 years travelling on your spaceship, you will age those 12 years, while the ones that are still in Earth may be experienced time in a different way (The ones on Earth may measure the time between your departure and your arrival as 15 years, for example, so they feel the time in a different way).

Then we only need to solve the equation:

Distance/time = speed

Distance = 300 Light years.

Time = 12 years:

300 light-years/12 years  = speed = 25*C

where C is the speed of light:

C = 3*10^8 m/s

From this, we can conclude that you would need to travel a lot faster than the speed of light.

Then the speed is:

speed = 25*3*10^8 m/s= 7.5*10^9 m/s.

Find the speed (in m/s) needed to escape from the solar system starting from the surface of Neptune. Assume there are no other bodies involved, and do not account for the fact that Neptune is moving in its orbit.

Answers

Answer:

The speed needed to escape from the solar system starting from the surface of Neptune is approximately 23557.615 meters per second.

Explanation:

The escape speed needed to escape from the gravitational influence of a planet ([tex]v_{e}[/tex]), measured in meters per second, is derived from Newton's Law of Gravitation and Principle of Energy Conservation and defined by the following formula:

[tex]v_{e} = \sqrt{\frac{2\cdot G\cdot M}{R} }[/tex] (1)

Where:

[tex]G[/tex] - Gravitational constant, measured in cubic meters per kilogram-square second.

[tex]M[/tex] - Mass of Neptune, measured in kilograms.

[tex]R[/tex] - Radius from the center to surface, measured in kilograms.

If we know that [tex]G = 6.672\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]M = 1.024\times 10^{26}\,kg[/tex] and [tex]R = 24.622\times 10^{6}\,m[/tex], then the escape speed needed is:

[tex]v_{e} =\sqrt{\frac{2\cdot \left(6.672\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (1.024\times 10^{26}\,kg)}{24.622\times 10^{6}\,m} }[/tex]

[tex]v_{e} \approx 23557.615\,\frac{m}{s}[/tex]

The speed needed to escape from the solar system starting from the surface of Neptune is approximately 23557.615 meters per second.

the reading on a mercury barometer at mombasa is 760mms.calculate the pressure at mombasa(density of mercury=1.36x10 power 4kg/m3​

Answers

Answer:

The pressure at Mombasa is 101.396 KPascal.

Explanation:

Given: Reading on barometer = 760 mm

                                                  = 0.76 m

           Density of mercury = 1.36 x [tex]10^{4}[/tex] kg/[tex]m^{3}[/tex]

In this case, the pressure can be expressed as:

P = σhg

Where: σ is the density of mercury, h is height of mercury in the barometer, and g is the acceleration due of gravity.

But, g = 9.81 m/[tex]s^{2}[/tex]

So that,

P = 1.36 x [tex]10^{4}[/tex] x 0.76 x 9.81

  = 101396.16 Pascal

P = 101.395 KPascal

The pressure at Mombasa is 101.396 KPascal.

15. If friction was completely removed from the track, what affect would this have on the roller coaster ride?

A. Without friction, the roller coaster ride would last forever!

B. The coaster would eventually stop because the coaster would still lose energy.

C. The coaster would use hills and flat sections to stop instead.​

Answers

Answer:
A

Explanation:
The coaster wouldn’t eventually stop because there’s no fiction to stop it. In order for a object to stop, there must be a opposing force ( in this case, fiction).
It is true that the coaster could use hills to stop, but the coaster can’t use flat section to stop.
So what I think is that the answer is A.

Fun Fact:
It would be really tough just to stand up without friction.

I hope this help and have a nice day :)

PLEASE HELP!! URGENT!!

Answers

I think it’s the mass

So as the mass of either object increases, the force of gravitational attraction between them also increases. If the mass of one of the objects is doubled, then the force of gravity between them is doubled. If the mass of one of the objects is tripled, then the force of gravity between them is tripled.

A 1100 kg car strikes a wall with a force of 4000 N in 0.35 seconds. What is the change in the

velocity of the car?

Answers

Answer:

(v-u) = 1.27 m/s

Explanation:

Given that,

Mass of a car, m = 1100 kg

Force with which the wall strikes, F = 4000 N

Time, t = 0.35 s

We need to find the change in velocity of the car.

The net force acting on the car is given by :

F = ma

a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\(v-u)=\dfrac{Ft}{m}\\\\(v-u)=\dfrac{4000\times 0.35}{1100}\\\\(v-u)=1.27\ m/s[/tex]

(v-u) is the change in velocity. Hence, the change in the velocity of the car is 1.27 /s.

find the potential energy of an aircraft weighing 10000 bs at 5000 ft true altitude and 125 kts true air speed

Answers

Answer:

[tex]U=5*10^7ft.Ib[/tex]

Explanation:

From the question we are told that

Weight  [tex]W= 10000bs[/tex]

Altitude [tex]H=5000ft[/tex]

Speed    [tex]V=125kts\\1kts=0.514m/s\\V=125*0.514=>64.25m/s[/tex]

Generally the equation for Potential energy ids mathematically given as

[tex]Potential\ Energy\ U=mgh[/tex]

[tex]U=Wh[/tex]

[tex]U=10000*5000[/tex]

[tex]U=5*10^7ft.Ib[/tex]

Starting from rest, a car takes 2.4 s to travel the first 15 m. Assuming a constant acceleration, how long will it take the car to travel the next 15 m?
A) 1.0s
B) 3.6s

Answers

Answer:

letter B.

Explanation:

Answer: A

0.1

Explanation: I did this

a bug is flying with a velocity of 10m/s into a wind at 3m/s what is the resultant velocity of the bug?

Answers

10m/s - 3m/s = 7m/s

The resultant velocity is 7m/s

QUESTION 7
How much force is required to bring a car of mass 1,126 kg, initially traveling at 20.4 m/s, to rest in 7.4 s?

Answers

Answer:

The force required is 3,104 N

Explanation:

Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = ma

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

[tex]v_f=v_o+at[/tex]

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

Solving for a:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:

[tex]\displaystyle a=\frac{0-20.4}{7.4}[/tex]

[tex]a=-2.757\ m/s^2[/tex]

The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:

[tex]F = 1,126\ kg * 2.757\ m/s^2[/tex]

F= 3,104 N

The force required is 3,104 N

Nepal has high potential for producing hydroelectricity however it is difficult too give one reason of each​

Answers

Answer:

due to the land structure of Nepal

(KInda need some help here. fast perferable) What is a controlled experiment? A. An experiment with one dependent variable and one experimental variable B. An experiment with only experimental variables C. An experiment with no controlled variables D. An experiment with no variables

Answers

Answer: A controlled experiment is a scientific test done under controlled conditions, meaning that just one (or a few) factors are changed at a time, while all others are kept constant. In some cases, there is no good way to test a hypothesis using a controlled experiment  I hope this helps you

Explanation:

Weight _____. A) is related to mass, but not the same. B) changes as mass changes C) depends upon gravitational pull D) all of the above

Answers

Answer:

D) all of the above

Explanation:

All of the given choices are correct definition of what weight of a substance implies.

Weight is the vertical force on a body due to the gravitational attraction or pull.

  Weight  = mass x acceleration due to gravity

Mass of a body is directly proportional to its weight and so also is the gravity.

Mass is the amount of matter within a substance.

Weight is the force of gravity exerted by a body on another or a surface.

The reason why the weight of a body changes from place to place is mainly due to the gravitational pull

A spring is attached to the ceiling, and when a mass is suspended from the spring at rest, it stretches by 50 cm. If instead two identical copies of the same spring are attached to the mass and the ceiling, the springs will stretch by:

Answers

Answer:

25 cm

Explanation:

Given that :

Displacement, x = 50 cm

In a spring, the force is given thus ;

F = kx ; where, F = Force, k = spring constant

Hence,

F = 50k - - - (1)

If two identical springs are attached to the mass ;

Fnet = F1 + F2

Fnet = F = kx' + kx'

x' = Displacement

Spring constant k and x' will be the same in the two springs ;

Hence,

F = 2kx' - - - (2)

Equating (1) and (2)

F = F

50k = 2kx'

50 = 2x'

x' = 50 / 2

x' = 25

Hence, the spring will stretch by 25cm

Answer:

25m

Explanation:


Suppose that you cut a sugar cube into smaller and smaller parts. If you
could separate out one molecule, which of these describes what you have?
A. a carbon atom.
B. a molecule without atoms.
C. a molecule with no mass.
D. a molecule of sugar.

Answers

Answer:

c

Explanation:

jsjdkksddssddddddmekekwkkwkekeke

an object is moving with constant velocity downwards on a frictionless inclined plane that makes an angle of

Answers

An object is moving with constant velocity downwards on a frictionless inclined plane that makes an angle of θ with the horizontal.

1. Which direction does the force of gravity act on the object?

2. Which direction does the normal force act on the object?

Which force is responsible for the object moving down the incline?

Answer:

The answer is below

Explanation:

1. When an object is moving with a constant velocity, the direction the force of gravity act on the object is DIRECTLY DOWN.

2. When an object is moving with a constant velocity, the direction the normal force act on the object "perpendicular to the surface of the plane."

3. When an object is moving with a constant velocity, the force that is responsible for the object moving down the incline is "the component of the gravitational force parallel to the surface of the inclined plane."

What is the target heart rate for a 24 year old?

Answers

Answer:

196

Explanation:

subtract 24 from 220 to get your answer.

Answer:

100 beats for minute

Explanation:

Adults ( age 18 and over) 60 - 100 beats per minute

When a high voltage is applied to a low-pressure gas causing it to glow, it will generate which type of spectrum

Answers

Answer:

Line emission.

Explanation:

According to Isaac Newton, he postulated that light consists of little (tiny) particles which typically travels in a straight line and from his experimental investigation he observed that white light comprises of a mixture of colors.

Sir Newton observed that, when light shines on a piece of metal, the metal releases electrons because the energy of the tiny light particles are greater than the binding energy of the electrons residing in the metal. This theory is known as the particle model of light.

A line emission would appear in a spectrum when specific wavelength is being emitted by the source of light.

When a high voltage is applied to a low-pressure gas causing it to glow, it will generate line emission.

For example, if a sample of hydrogen gas at low-pressure undergoes or experiences a high voltage electrical discharge, the isolated hydrogen gas would generate a red light (line emission).

A ship's boiler steam comes out at 112 C and pushes through the system, exiting into the condenser,

which is kept at 20 C by circulating seawater. What is the ideal efficiency of the ship's boiler? Round to

the nearest thousandth.

O 0.643

O 0.523

O 0.703

O 0.239

Answers

Answer:

D: 0.239

Explanation:

Equation for ideal efficiency is;

η = 1 - (T_c/T_h)

We are told that;

steam comes out at 112° C. Thus, T_h = 112°C. Converting to Kelvin gives; T_h = 112 + 273 = 385 K

The one exiting into the condenser is kept at 20°C. Thus; T_c = 20 + 273 = 293 K

Thus;

η = 1 - (293/385)

η = 0.239

please do this . will mark as brainlest;)

Answers

Answer:

no, not all three contains iron

no, not all three also contain magnets

Explanation:

a has the magnet

b and c have pieces of iron

The graph below shows the force required to stretch a spring various distances. Review the graph below.

What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 3.0 meters?

Answers

Explanation:

Elastic string constant (k)

= Slope of the graph F/x

= 15.0N/10.0m = 1.50N/m

Hence,

EPE = 0.5kx² = 0.5(1.50N/m)(3.0m)² = 6.75J.

Answer:

6.8

Explanation:

3.) A family travels by car cross country 6,200 km in 80 hours. In meters per 1 point
second, how fast did the family travel? (3600 seconds = 1 hour) (Show ALL
work!) *

Answers

Answer:

v = 21.52 m/s

Explanation:

Given that,

The distance covered by the car, d = 6200 km

Time taken by the car, t = 80 hours

We need to find the speed of the car. The speed of an object is given by total distance dividing total time.

[tex]v=\dfrac{6200\times 10^3\ m}{80\times 3600}\\\\v=21.52\ m/s[/tex]

So, the speed of the car is 21.52 m/s.

What is the daily use of the deltoid?

Answers

Answer:

In our everyday life, the deltoids take on most of the work in rotating our arms, but besides that the deltoid muscle also allows us to carry objects at a safe distance from the body. It is also responsible from stopping a dislocation or injury to the humerus when we carry something heavy.

Answer:

Lifting, pushing and pulling

Explanation:

it uses it

please I really need help, I will mark you brainliest
A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.
1. Calculate the impulse delivered to the ball.
2. What was the change in momentum of the ball?
3. What was the velocity of the ball as it left the tennis racket?
4. What would happen to the ball's velocity if it remained on the tennis racket longer than .05 s?

Answers

Explanation:

I am not sure about this question sry but u can try asking a tutor u don't need to use any points

Which of the following is not a true statement?
v=at
O art

Answers

Answer:

t = Δa / v

Explanation:

To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:

Acceleration = change in velocity / time

a = Δv / t ..... (1)

But

Δv = v₂ – v₁

Substitute the value of Δv into equation (1)

a = Δv / t

a = v₂ – v₁ / t ....... (2)

From equation (1), make Δv the subject of the equation.

a = Δv / t

Cross multiply

Δv = at .... (3)

From equation (1), make t the subject of the equation.

a = Δv / t

Cross multiply

at = Δv

Divide both side by a

t = Δv /a ...... (4)

From circular motion, centripetal's force is given by:

F = mv²/r

F = ma꜀

Therefore,

ma꜀ = mv²/r

Cancel out m

a꜀ = v²/r

SUMMARY:

a = Δv / t

a = v₂ – v₁ / t

Δv = at

t = Δv /a

a꜀ = v²/r

Considering the options given in question above, t = Δa / v is not a true statement.

Answer:

Option 4

Explanation:

A wave is traveling at a speed of 15 m/s and it's wavelength is 5 m. Calculate the waves frequency

Answers

Answer:

The frequency of this wave is [tex]3\; \rm Hz[/tex].

Explanation:

The frequency [tex]f[/tex] of a wave is the number of wavelengths that this wave covers in unit time (typically a second.)

The wave in this question travels at [tex]v = 15\; \rm m \cdot s^{-1}[/tex]. In other words, this wave covers [tex]15\; \rm m[/tex] in unit time (a second.) How many wavelengths [tex]\lambda[/tex] would that [tex]15\; \rm m\;[/tex] correspond to?

The question states that the wavelength of this wave is [tex]\lambda = 5\; \rm m[/tex]. Therefore, there would be [tex]15 / 5 = 3[/tex] wavelengths in the [tex]15\; \rm m[/tex] span that this wave covered in the unit time of one second ([tex]1\; \rm s[/tex].) Hence, the frequency of this wave would be [tex]3\; \rm s^{-1}[/tex] (three per second,) which is equivalent to [tex]3\; \rm Hz[/tex] (three Hertzs.)

In general, the frequency [tex]f[/tex] of a wave with speed [tex]v[/tex] and wavelength [tex]\lambda[/tex] would be:

[tex]\displaystyle f = \frac{v}{\lambda}[/tex].

For the wave in this question:

[tex]\begin{aligned}f &= \frac{v}{\lambda} \\ &= \frac{15\; \rm m \cdot s^{-1}}{3\; \rm s} = 3\; \rm s^{-1} = 3\; \rm Hz\end{aligned}[/tex].

Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. Through what angle will it have turned after time 2t?

Answers

Answer:

After time 2t, the wheel will turn through an angle of 100 rad.

Explanation:

Given;

initial velocity of the wheel, [tex]\omega_i = 0[/tex]

time of motion, t = t

angular distance, θ = 25 rad

The constant angular acceleration is calculated as;

[tex]\theta = ut + \frac{1}{2}at^2\\\\\theta = 0 + \frac{1}{2}at^2\\\\2\theta = at^2\\\\a = \frac{2\theta }{t^2} \\\\a = \frac{2\ \times \ 25 }{t^2}\\\\a = \frac{50}{t^2} \\\\when \ t = 2t\\\\\theta = \frac{1}{2}at^2\\\\\theta = \frac{1}{2}(\frac{50}{t^2})(2t)^2\\\\\theta =\frac{1}{2}(\frac{50}{t^2})(4t^2)\\\\\theta = 100 \ rad[/tex]

Therefore, after time 2t, the wheel will turn through an angle of 100 rad.

The angle of the wheel would have turned after time 2t is equal to 100 rad.

Given the following data:

Initial angular velocity = 0 rad/s (since the wheel starts from rest).Time = t secondsAngle = 25 rad

To determine the angle of the wheel would have turned after time 2t:

First of all, we would determine the angular acceleration of the wheel by using the second equation of rotational motion.

[tex]\theta = ut + \frac{1}{2} at^2\\\\25 =0(t) + \frac{1}{2} at^2\\\\25=\frac{1}{2} at^2\\\\50=at^2\\\\a=\frac{50}{t^2} \;rad/s^2[/tex]

Next, we would determine the angle the wheel would have turned after time 2t:

[tex]\theta = ut + \frac{1}{2} at^2\\\\\theta = 0(2t) + \frac{1}{2} (\frac{50}{t^2} )(2t)^2\\\\\theta = \frac{25}{t^2} \times 4t^2\\\\\theta = 25\times 4\\\\\theta = 100\;rads[/tex]

Read more: https://brainly.com/question/8898885

Who pays for Government workers that work on alcohol impaired driving cases?

Answers

Answer: Taxpayers

Explanation:

Taking alcohol before driving or while driving is dangerous and has resulted in lots of accidents and deaths. Alcohol tampers with the normal functioning of the brain, and also impairs ones reasoning.

Alcohol impaired driving cases handled by government officials are paid for by the taxpayers. A tax is the levy that the people in the country pays. Those funds are used in handling different government objectives and this is one of such ways.

A force does 128-J of work on a 4-kg cart. What mus be the velocity of the cart?

Answers

Answer:

v = 8[m/s]

Explanation:

In this case, the work that is exerted on the cart is the kinetic energy that allows the movement, so we can use the following equation of kinetic energy.

[tex]E_{kin}=Work\\E_{kin}=\frac{1}{2} *m*v^{2}[/tex]

Now replacing:

[tex]128=0.5*4*v^{2} \\v=\sqrt{64} \\v=8[m/s][/tex]

Explain the meaning of the error​

Answers

Answer:

a mistake

Explanation:

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