Chemistry College

A 20 N force pulls to the right and friction pulls 5 N. If the mass is 5 kg, find acceleration

Answers

Answer 1

Answer:

Explanation:

Force = Mass x Acceleration

(20 - 5)N = 5kg x Acceleration

Acceleration = 15/5

                     = 3 N/kg

Related Questions

Read the information in the table below:



Which type of reaction is represented by B? (5 points)
Endothermic reaction
Exothermic reaction
Reaction between liquids
Reaction between solids

Answers

Answer:

it's exothermic reaction, becasue it have negative energy and the temperature increases

A bone taken from a garbage pile buried under a hill-side had 14C/12C ratio 0.477 times the ratio in a living plant or animal. What was the date when the animal was buried?​

Answers

Answer:

The date when the animal was buried can be estimated by using the decay rate of Carbon-14. The half-life of Carbon-14 is 5,730 years, so the date when the animal was buried can be estimated by taking the half-life and multiplying it by the logarithm of the ratio of the 14C/12C ratio of the bone and the 14C/12C ratio of a living plant or animal. In this case, 5,730 years x log(0.477) = 45,906 years ago.

Explanation:

a solution containing 1.00 g of an unknown nonelectrolyte liquid and 9.00 g of water has a freezing point of -3.33 *C. Calculate the molar mass of the unknown liquid in g/mol.

Answers

The depression in freezing point of water here is 3.33 °C. Then the molality of the solution is 1.79. From number of moles of solute is calculated as 0.0161. Then , the molar mass of the solute is 62.11 g.

What is depression in freezing point ?

The addition of a non-volatile salt into a solvent will decrease the freezing point of the solution than the pure solvent. The change in freezing point is proportional to the molality of the solution.

ΔTf = Kf m

Kf is called molal depression constant.

Kf for water = 1.86 °C Kg/mol

given ΔTf = 3.33 (0 - (-3.33))

then m = ΔTf /Kf =  3.33/ 1.86 °C Kg/mol = 1.79

Now, mass of water= 9 g = 0.009 kg

then number of moles = molality × mass of solvent

n = 0.009 kg × 1.79 = 0.0161.

mass of solute taken = 1 g

then, molar mass = 1/0.0161 = 62.11 g.

Therefore, the molar mass of the solute is 62.11 g.

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For the reaction 2HNO3 + Mg(OH)2 → Mg(NO3)2 + 2H₂O, how many grams of magnesium nitrate are produced from 9 grams of nitric acid, HNO3 ?​

Answers

This should be the answer


I’ll put the last part here


So, 10.52 grams of magnesium nitrate are produced from 9 grams of nitric acid, HNO3.

For the following reactions, calculate the ionization constant of each reaction. CH3COOH (aq) + H2O (l) equation H3O+ (aq) + CH3COO-(aq); [CH3COOH] = 0.8M, [H3O+] = 7.6M, [CH3COO-] = 16.4MKa =

Answers

Ionization constant of a reaction is the ratio of the molar concentration of product to that of reactants. For the given  reaction, the ionization constant is 155.8 .

What is ionization constant ?

A compound or element gets ionized to form its anion or cation by the gain or lose of electrons.

Here, acetic acid, CH₃COOH ionizes to form hydronium ion and acetate ion. The ratio of product of molar concentrations of products to the product of molar concentrations of the reactants is called the reaction constant.

The ionization constant of the given reaction is written as:

K = [H₃O]⁺ [CH₃COO-]/[CH₃COOH]

Given, [CH₃COOH] = 0.8 M

[CH₃COO-] = 16.4 M

and  [H₃O]⁺ = 7.6 M.

then, K = 7.6 M × 16.4 M/ 0.8 M = 155.8

Therefore, the ionization constant of the reaction is 155.8.

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