a 50 kg boy runs at 3 m/s. how much momentum does he have

Answer:

Almost winter so fall

Explanation:

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A) The rotation rate of the ball in rev/secs is ;  10.79 rev/secs

B) The total kinetic energy of in pound-feet ignoring the finger holes is : 37.6157 pound-feet

Given data :

mass of ball = 12 Ib

diameter of ball = 8.5 inches

Radius = 4.25 inches = 0.10795 m

Time = 5 secs

distance travelled = 60 ft  = 18.288 m

First step : calculate the velocity of ball

V = distance / time

  = 18.288 / 5 = 3.66 m/s

Next step :

angular velocity ( w ) = V / r  

                                  = 3.66 / ( 0.10795 ) = 33.90 rad/sec

convert to rev/sec = 33.90 / π

                               = 10.79 rev/secs

given that ball rolls without slipping

Vcon = Rw

Total K.E = 1/2 IW² + 1/2 mv²

               = 7/10 MR²W²

Total K.E = 7/10 *  5.44 * ( 0.10795 )² * 33.90²

               = 50.99 ≈ 51 J

convert to pound-feet = 37.6157 pound-feet

Hence we can conclude that The rotation rate of the ball in rev/secs is ;  10.79 rev/secs  and The total kinetic energy of in pound-feet ignoring the finger holes is : 37.6157 pound-feet.

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Since the frequency of sound in a medium is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.

A dispersive medium is a medium which spreads out or disperses a substance passing through it.

Since CO2 is a dispersive medium, it means sound waves passing through it would be dispersed based on wavelength.

The note of a sound depends on its frequency, the higher the frequency, the higher the note.

Frequency of sound is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.

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Answer:

algebraic sum of moments of all the forces acting on the body about the axis of rotation is zero, the body is in equilibrium. According to the principle of moments, in equilibrium: Sum of anticlockwise Moments = Sum of clockwise moments.

Condition:

For an object to be in equilibrium, it must be experiencing no acceleration.

Hope it may helpful to you

The magnitude of the centripetal acceleration of the air plug on a car tire is 308.43 m/s².

Centripetal acceleration of an object is the rate of change of object's velocity with time, and it is directed inwards.

The magnitude of the centripetal acceleration of the air plug on a car tire is calculated as follows;

ac = ω²r

where;

[tex]\omega = 250 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} \\\\\omega = 26.18 \ rad/s[/tex]

ac = (26.18)² x 0.45

ac = 308.43 m/s²

Thus, the magnitude of the centripetal acceleration of the air plug on a car tire is 308.43 m/s².

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Answer:

The π is from the initial formula of period T=2π/omega

Answer:

i beleave cuz of the Earth is spherical

Explanation:

Answer:

Helium, Water, Glass, Diamond

Explanation:

light travels slowest though a diamond

Answer:

Total displacement will be 120m

Explanation:

Since displacement is shortest distance travelled

Td= 150m east - 30m west ( Since they are opposite in direction)

Td= 120m East

Answer:

false

Explanation:

because no machines have 100% efficient

Answer:

1/8 = (1/2)^3

This implies the sample has decayed for 3 half lives

3 * 5730 yrs = 17,200 years

200 Joules should be supplied in the circuit.

Here the output is 30J and input is missing

[tex]\sf \dfrac{30}{I} * 100 = 15[/tex]

multiplied with 100, to covert it into percentage

[tex]\sf 3000 = 15(I)[/tex]

[tex]\sf I = \dfrac{3000 }{15}[/tex]

[tex]\sf I = 200J[/tex]

Let that be X

[tex]\\ \rm\Rrightarrow \dfrac{30}{x}(100)=15[/tex]

[tex]\\ \rm\Rrightarrow 3000=15x[/tex]

[tex]\\ \rm\Rrightarrow x=200J[/tex]

Answer:

22583.5J

Explanation:

KE=1/2 mv^2

=1/2*47Kg*(31m/s^2)

=23.5Kg * 961m/s^2

=22583.5J

Answer:

South of East

Explanation:

If vector A points north and vector B points east, then vector C, calculated as C = B - A, will point in the direction of the resultant vector when subtracting vector A from vector B. Vector C points in the northeast direction.

Since vector A points north and vector B points east, we can visualize this on a coordinate plane. Let's assume that vector A has a magnitude of 1 and vector B has a magnitude of 1 as well. Vector A would be pointing directly upward (north), and vector B would be pointing directly to the right (east).

When subtracting vector A from vector B (C = B - A), we can visualize it by starting at the tail of vector A and drawing the resultant vector to the head of vector B. The resultant vector C would be a diagonal vector pointing northeast, forming a 45-degree angle with the positive x-axis. Therefore, vector C points in the northeast direction.

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Answer:

It has gravitational energy because of its height above some reference point.

It also contains thermal energy due to the motion of the contained atoms and molecules.

Answer:

b and c :)

Explanation:

Answer: 3V

Explanation:

If the capacitor is connected to a 3V battery:

[tex]\bold{V = \frac{Q}{C} }[/tex]

The potential difference is also 3V on the capacitor

Answer:

The body develops a blood clot over the fractured bone in the first few days of a fracture to protect it and deliver the requisite cells for healing. Then, around the fractured bone, a field of healing tissue grows. This is referred to as a callus.

Explanation:

Answer:

Bone heals by making cartilage to temporarily plug the hole created by the break. This is then replaced by new bone. Many people think of bones as being solid, rigid, and structural. Bone is, of course, key to keeping our bodies upright, but it is also a highly dynamic and active organ

Explanation:

Explanation:

[tex]\longmapsto\: \red{ hello \: mate}[/tex]

OPTION (C) 3

is the angle of refraction

Answer:

Option C. 3

Explanation:

Refraction is the change in direction of light passing from one medium to another. Angle 1 and 2 are reflection due to the bouncing of light.

Answer:

Explanation:

A rocket designed to place small payloads into orbit is carried to an altitude of 12.0 km above sea level by a converted airliner. When the airliner is flying in a straight line at a constant speed of 850 km/h, the rocket is dropped. After the drop, the airliner maintains the same altitude and speed and continues to fly in a straight line. The rocket falls for a brief time, after which its rocket motor turns on. Once its rocket motor is on, the combined effects of thrust and gravity give the rocket a constant acceleration of magnitude 3.00g directed at an angle of 30.0° above the horizontal. For reasons of safety, the rocket should be at least 1.00 km in front of the airliner when it climbs through the airliner’s altitude. Your job is to determine the minimum time that the rocket must fall before its engine starts. You can ignore air resistance. Your answer should include (i) a diagram showing the flight paths of both the rocket and the airliner, labeled at several points with vectors for their velocities and accelerations; (ii) an x-t graph showing the motions of both the rocket and the airliner; and (iii) a y-t graph showing the motions of both the rocket and the airliner. In the diagram and the graphs, indicate when the rocket is dropped, when the rocket motor turns on, and when the rocket climbs through the altitude of the airliner.

(a) The torque acting on the disk is 66 Nm.

(b) The moment of inertia of the disk is 0.05 kgm².

(c) The angular acceleration is produced by the torque is 1,320 rad/s².

(d) The final angular velocity of the disk is  3,960 rad/s.

(e) The angle of rotation of the disk is 5,940 rad.

The torque acting on the disk is calculated as follows;

τ = Fr

τ = 300 x 0.22

τ = 66 Nm

The moment of inertia of a solid disk is calculated as follows;

I = ¹/₂MR²

I = ¹/₂ x 2 x (0.22)²

I = 0.05 kgm²

The angular acceleration of the disk is calculated as follows;

τ = Iα

[tex]\alpha = \frac{\tau }{I} \\\\\alpha = \frac{66}{0.05} \\\\\alpha = 1,320 \ rad/s^2[/tex]

ωf = ωi + αt

ωf = 0 + (1320 x 3)

ωf = 3,960 rad/s

ωf² = ωi²+ 2αθ

(3,960)² = 0 + 2(1320)θ

θ = (3,960²) / (2 x 1320)

θ = 5,940 rad

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Answer:

Newton's third Law

Explanation:

Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Answer:

true

Explanation:

Friction helps your vehicle stop quickly. this statement ids true. Hence option A us correct. A vehicle can stop more rapidly because to friction. The brake pads rub on the turning braking discs or drums when the brakes are applied.

The friction slows the moving vehicle down and eventually causes it to halt by converting its kinetic energy into heat energy.  The effectiveness of the braking action will increase with the level of friction between the brake parts. For rapid stops, friction between the tyre and the road is also important.

The vehicle's forward motion is opposed by friction created by the tyres' gripping action on the road surface, which helps in stopping and decelerating. Rapid vehicle stopping would be incredibly difficult and risky without friction.

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Answer:

Lightning

Explanation:

Lightning during a thunderstorm is an example of electrical energy. It is the visible discharge of atmospheric electricity. As lightning heats the air, it creates a shock wave that causes the sound of thunder.

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Explanation:

Water is wet, in the sense of being a liquid which flows easily, because its viscosity is low, which is because its molecules are rather loosely joined together.

Answer:

Liquid water is not itself wet, but can make other solid materials wet.

Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.

Whether an object is wet or dry depends on a balance between cohesive and adhesive forces. Cohesive forces are attractive forces within the liquid that cause the molecules in the liquid to prefer to stick together. Cohesive forces are also responsible for surface tension. If the cohesive forces are very strong, then the liquid molecules really like to stay close together and they won't spread out on the surface of an object very much. On the contrary, adhesive forces are the attractive forces between the liquid and the surface of the material. If the adhesive forces are strong, then the liquid will try and spread out onto the surface as much as possible. So how wet a surface is depends on the balance between these two forces. If the adhesive forces (liquid-solid) are bigger than the cohesive forces (liquid-liquid), we say the material becomes wet, and the liquid tends to spread out to maximize contact with the surface. On the other hand, if the adhesive forces (liquid-solid) are smaller than the cohesive forces (liquid-liquid), we say the material is dry, and the liquid tends to bead-up into a spherical drop and tries to minimize the contact with the surface.

Water actually has pretty high cohesive forces due to hydrogen bonding, and so is not as good at wetting surfaces as some liquids such as acetone or alcohols. However, water does wet certain surfaces like glass for example. Adding detergents can make water better at wetting by lowering the cohesive forces . Water resistant materials such as Gore-tex fabric is made of material that is hydrophobic (water repellent) and so the cohesive forces within the water (liquid-liquid) are much stronger than the adhesive force (liquid-solid) and water tends to bead-up on the outside of the material and you stay dry.

A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. The new interference pattern seen on the screen compared to the original interference pattern is the spacing between the bright fringes will increase. Thus, the correct option is A.

Interference is the net effect of the combination of two or more wave forms or trains which are moving on intersecting or coincident paths in a medium. The effect of this pattern is that of the addition of the amplitudes of the individual waves at each point which are affected by more than one wave in the medium.

A scientist when decreases the wavelength of the light used in a double-slit experiment and it keeps every other aspect of the wave the same. The new interference pattern seen on the screen as compared to the original interference pattern is that the spacing between the bright fringes will increase.

Therefore, the correct option is A.

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The pictorial diagram with a rocket launched straight upward, showing the first three positions of the rocket with equal spacing between them, best illustrates projectile motion. In this case, the rocket is projected upward into the air, and its path follows a parabolic trajectory due to the influence of gravity.

Projectile motion refers to the motion of an object that is thrown, launched or otherwise projected into the air and then moves under the influence of gravity alone. In this type of motion, the object moves along a curved path, called a parabola, due to the combined effect of its initial velocity and the force of gravity acting on it.

When a rocket is launched straight upward, it experiences a projectile motion. The rocket's initial velocity is upwards, but gravity causes it to decelerate until it eventually stops at the highest point of its trajectory. The rocket then starts to fall back down, accelerating due to gravity until it reaches the ground. If we take three equal intervals of time, we can show the rocket's positions at those times. Initially, the rocket will be moving upwards with a decreasing velocity, then it will reach its maximum height before falling back down with an increasing velocity.

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Answer: I believe it should be the final answer,

A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground

Explanation:

Answer:

power is measured in watts and its the messure of work over time.

Explanation:

Answer:

Explanation:

You can use [tex]\Delta E=\frac{\hbar c}{\lambda} \rightarrow \lambda =\frac{\hbar c}{E} = \frac{1240 eV.nm}{0.0141 eV} \approx 87943.26[/tex] in nm.

Here the hc = 1240 eV.nm in eV and nanometer unit.

Answer:

[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]

Explanation:

Given:

Force between pair of charges= 900 newtons

The distance between the charges = 0.01 meters

Strength of Charge first q1 = 2e-10 Coulomb

To find:

Strength of Charge second q2 = ____ Coulomb?

Solution:

We know that,

Force between two charges separate by distance r is given by the equation,

[tex]|F| = K_e \frac{q1 \cdot \: q2}{ {r}^{2} } \\ 900 =K_e \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times {10}^{ - 4} = K_e {(2e - 10)\cdot \: q2} \\ q2 = \frac{9 \times {10}^{ - 2} }{(2e - 10) K_e} \\ \\ \fbox{We \: know \: that \: e = 2.71 } \\ substituting \: the \: value \: \\ q2 = \frac{9 \times {10}^{ - 2} }{(2 \times 2.71 - 10)K_e} \\ q2 = \frac{0.09}{ - 4.58 K_e} \\ q2 = \frac{-0.0196}{K_e}\: coulomb[/tex]

[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]

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