What are some INDIRECT applications of centripetal force in real life?
Answer:
The circular turning of roads
Explanation:
please mark brainliest
Answer:
Explanation:
The circular turning of roads
Driving on Curves
Select all the correct answers.
A worker is holding a filled gas cylinder still. Which two sentences are true about the energy of the filled gas cylinder?
it has no energy because it's being held still
It has gravitational potential energy because of its height.
its atoms and molecules have thermal energy
It has motion energy because it will fall if let go
its kinetic energy is being converted to potential energy
ghts reserved
it has no energy because its being held still
it has motion energy because it will fall if let go
Burns are a particular safety hazard when handling
Answer:
flammable liquids
Explanation:when it catches on fire your going to get burned.hope this helps.
BRAINLIEST
1. What does the percent difference between GPE and KE tell you about the efficiency of energy transformations in this experiment?
2. Use a computer or graphing calculator to graph the percent difference in data table 1 versus mass, and the percent difference in data table 2 versus change in height (Δh). Based on your results that you see plotted for the two rounds of experiments, how would you adjust the mass and height so that the design of the system leads to GPE and KE values that are as close as possible? Explain why you think this design would achieve the desired result.
btw are my datas in the graph right? i added the gpe ke and %diff
The percent difference between GPE and KE in the experiment illustrates that the higher the percentage, the more efficient the energy transfer.
What is energy transformation?It should be noted that energy transformation simply means the process of changing energy from one form to another form.
In this case, the percent difference between GPE and KE in the experiment illustrates that the higher the percentage, the more efficient the energy transfer.
Also, the mass and height should be adjusted in such a way that the design of the system leads to GPE and KE values that are as close as possible.
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The experiment's percent difference between GPE and KE shows that the efficiency of energy transfer increases with percentage.
Thus, It should be emphasized that the term "energy transformation" simply refers to the act of altering energy's form.
The experiment's percent difference between GPE and KE in this instance demonstrates that the more significant the percentage, the more effectively energy is transferred.
The experiment's percent difference between GPE and KE in this instance demonstrates that the more significant the percentage, the more effectively energy is transferred.
Thus, Energy is capable of changing its forms. For instance, your body stores chemical energy from the food you eat until you can use it as kinetic energy when working or playing.
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#SPJ6
Calculate the wavelength (in m) of the note middle "C" (frequency = 256 Hz) in air at room temperature and pressure.
hi you need to stop it get some help okay hope that worked
The wavelength (in m) of the note middle "C" (frequency = 256 Hz) in the air at room temperature and pressure will be 1171875 m.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The relationship between the wave's wavelength, time, and speed is given as;
[tex]\rm \lambda = \frac{c}{v} \\\\ \rm \lambda = \frac{3 \times 10^8}{256} \\\\ \lambda=1171875 \ m[/tex]
Hence the wavelength (in m) of the note middle "C" (frequency = 256 Hz) in the air at room temperature and pressure will be 1171875 m.
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A uniformly charged insulating rod is bent into the shape of a semicircle of radius R = 5 cm. If the rod has a total charge of Q = 3.10-9C, find the magnitude and direction of the electric field at O, the center of the circle.
Hi there!
We can begin by using Coulomb's Law:
[tex]E = \frac{kq}{r^2}[/tex]
k = Coulomb's Constant (8.99 × 10⁹ Nm²/C²)
E = Electric field strength (N/C)
r = distance from point (m)
q = charge (C)
Since this is a continuous charge, we must use calculus.
We can express this as the following:
[tex]q = \lambda L[/tex]
λ = Linear charge density (C/m)
L = Length of rod (m)
Now, since this is an arc, L = s (arc length). Additionally, we must find the differential elements of each:
[tex]dq = \lambda ds\\\\dq = \lambda rd\theta[/tex]
Our new equation is:
[tex]dE = \frac{kdq}{r^2}\\\\dE = \frac{k\lambda rd\theta}{r^2}[/tex]
However, we will only take the cosine component of the electric field since the vertical components will cancel out. (Electric fields are a vector). Therefore:
[tex]dE = \frac{k\lambda rd\theta}{r^2}cos\theta\\\\dE = \frac{k\lambda}{r}cos\theta d\theta[/tex]
Integrate. For a semicircle, the bounds will be from -π/2 to π/2.
[tex]E = \frac{k\lambda}{r}\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}} {cos\theta} \, d\theta\\\\E = \frac{k\lambda}{r}sin\theta\left \|{\frac{\pi}{2}} \atop {-\frac{\pi}{2}}} \right. \\\\E = \frac{k\lambda}{r}(1 - (-1)) = \frac{2k\lambda}{r}[/tex]
We need to solve for λ, which is Q/ L:
[tex]\lambda = \frac{3.10 \times 10^{-9} C}{\pi (0.05)} = 1.9735 \times 10^{-8} \frac{C}{m}[/tex]
Now, plug and solve for the electric field strength:
[tex]E = \frac{2(8.99\times 10^9)(1.9735\times 10^{-8})}{0.05} = \boxed{7096.783 \frac{N}{C}}[/tex]
**A diagram was not provided, but if the hemisphere's focus was to the right, the electric field would be to the right, and etcetera.
A hanging weight, with a mass of m1 = 0.365 kg, is attached by a string to a block with mass m2 = 0.825 kg as shown in the figure below. The string goes over a pulley with a mass of M = 0.350 kg. The pulley can be modeled as a hollow cylinder with an inner radius of R1 = 0.0200 m, and an outer radius of R2 = 0.0300 m; the mass of the spokes is negligible. As the weight falls, the block slides on the table, and the coefficient of kinetic friction between the block and the table is k = 0.250. At the instant shown, the block is moving with a velocity of vi = 0.820 m/s toward the pulley. Assume that the pulley is free to spin without friction, that the string does not stretch and does not slip on the pulley, and that the mass of the string is negligible. Using energy methods, find the speed of the block (in m/s) after it has moved a distance of 0.700 m away from the initial position shown.
The speed of the block after it has moved the given distance away from the initial position is 1.1 m/s.
Angular Speed of the pulley
The angular speed of the pulley after the block m1 fall through a distance, d, is obatined from conservation of energy and it is given as;
K.E = P.E
[tex]\frac{1}{2} mv^2 + \frac{1}{2} I\omega^2 = mgh\\\\\frac{1}{2} m_2v_0^2 + \frac{1}{2} \omega^2(m_1R^2_2 + m_2R_2^2) + \frac{1}{2} \omega^2( \frac{1}{2} MR_1^2 + \frac{1}{2} MR_2^2) = m_1gd- \mu_km_2gd\\\\\frac{1}{2} m_2v_0^2 + \frac{1}{2} \omega^2[R_2^2(m_1 + m_2)+ \frac{1}{2} M(R_1^2 + R_2^2)] = gd(m_1 - \mu_k m_2)\\\\[/tex]
[tex]\frac{1}{2} m_2v_0 + \frac{1}{4} \omega^2[2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)] = gd(m_1 - \mu_k m_2)\\\\2m_2v_0 + \omega^2 [2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)] = 4gd(m_1 - \mu_k m_2)\\\\\omega^2 [2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)] = 4gd(m_1 - \mu_k m_2) - 2m_2v_0^2\\\\\omega^2 = \frac{ 4gd(m_1 - \mu_k m_2) - 2m_2v_0^2}{2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)} \\\\\omega = \sqrt{\frac{ 4gd(m_1 - \mu_k m_2) - 2m_2v_0^2}{2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)}} \\\\[/tex]
Substitute the given parameters and solve for the angular speed;
[tex]\omega = \sqrt{\frac{ 4(9.8)(0.7)(0.365 \ - \ 0.25\times 0.825) - 2(0.825)(0.82)^2}{2(0.03)^2(0.365 \ + \ 0.825)\ \ +\ \ 0.35(0.02^2\ + \ 0.03^2)}} \\\\\omega = \sqrt{\frac{3.25}{0.00214\ + \ 0.000455 } } \\\\\omega = 35.39 \ rad/s[/tex]
Linear speed of the blockThe linear speed of the block after travelling 0.7 m;
v = ωR₂
v = 35.39 x 0.03
v = 1.1 m/s
Thus, the speed of the block after it has moved the given distance away from the initial position is 1.1 m/s.
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nts
A force diagram of a tennis ball flying through the air toward the right is shown in the diagram
below. The arrows show the direction of the gravitational force (Fgrav), the drag force (Fdrar), the lift
force (Flift), and the direction of movement of the tennis ball.
Force Diagram for a
Flying Tennis Ball
Fe = 0.27 N
12
kly
ary
F = 0,64 N
drag
direction of
motion
Fyw = 0,56 N
Which pair of statements is a valid description and explanation of the motion of the ball based on
evidence from the diagram?
O description: the ball slows down as it moves to the right because the horizontal forces are unbalanced, with
the larger force acting to the left.
explanation: The ball speeds up as it moves downward because the vertical forces are unbalanced, with the
larger force acting downward.
O description: The ball speeds up as it moves to the right because the horizontal forces are unbalanced, with
the larger force acting to the right.
explanation: The ball speeds up as it moves downward because the vertical forces are unbalanced, with the
larger force acting downward.
O description: The ball moves at a constant speed to the right because the horizontal forces are unbalanced,
with the larger force acting to the left.
explanation: The ball moves at a constant speed to the right because the horizontal forces are unbalanced,
with the larger force acting to the left.
O description: The ball slows down as it moves to the right because the horizontal forces are unbalanced, with
the larger force acting to the right.
explanation: The ball moves at a constant speed downward because the vertical forces are unbalanced, with
the larger force acting upward.
Given that the magnitude of the forces is greater towards the left; the ball slows down as it moves to the right because the horizontal forces are unbalanced.
Balanacing of forcesWe have to know that force is a vector quanty. The direction in which the ball will move is dependent on the direction and magnitude of the resultant force.
Now considering the statements, the pairs of statements that are true are;
description: the ball slows down as it moves to the right because the horizontal forces are unbalanced, with the larger force acting to the left.
explanation: The ball speeds up as it moves downward because the vertical forces are unbalanced, with the larger force acting downward.
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A rocket weighing 220,000 N is taking off from Earth with a total thrust of
500,000 N at an angle of 20 degrees, as shown in the image below. What is
the approximate vertical component of the net force that is moving the rocket
away from Earth?
20°
Vertical
Component
of Net Force
Thrust
500,000 N
Weight
220,000 N
The vertical component of the net force that is moving the rocket away from Earth is determined as 171,010.1 N.
Vertical component of the lift force
The vertical component of the net force that is moving the rocket away from Earth is determined as follows;
Fy = Fsinθ
where;
F is applied forceθ is the angle of inclinationFy = 500,000 x sin(20)
Fy = 171,010.1 N
Thus, the vertical component of the net force that is moving the rocket away from Earth is determined as 171,010.1 N.
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Answer:
250,000
Explanation:
A turntable is switched from 11.3 rad/s to 1.9 rad/s, and the platter goes through an angle of 17.95 radian in reaching the new angular speed. What is the angular acceleration of the platter?
Hi there!
We can use the angular equivalent of the following kinematic equation:
[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta[/tex]
ωf = final angular velocity (1.9 rad/s)
ωi = initial angular velocity (11.3 rad/s)
α = angular acceleration (? rad/s²)
θ = angular displacement (17.95 rad)
We can rearrange the equation to solve for angular acceleration.
[tex]\omega_f^2 - \omega_i^2 = 2\alpha \theta\\\\\alpha = \frac{\omega_f^2 - \omega_i^2}{2\theta}[/tex]
Plug in the given values and solve.
[tex]\alpha = \frac{1.9^2 - 11.3^2}{2(17.95)} = \boxed{3.456 \frac{rad}{s}}[/tex]
An output gear has 10 teeth and an input gear has 40 teeth. What is the mechanical advantage of this gear combination?
Answer:
4
Explanation:
We know that :
Mechanical Advantage = Input / OutputSolving
MA = Input / OutputMA = 40 / 10MA = 4You just took a bit of you favorite food. Tell a story what happens as the food passes through the alimentary canal from the foods point of view (you are the food). Discuss all the structures in which you come into contact with in the digestive system and their functions for helping digest foods. Don't forget about peristalsis, the accessory organs, and their functions as well.
Answer:
The digestive system is made up of the gastrointestinal tract—also called the GI tract or digestive tract—and the liver, pancreas, and gallbladder. The GI tract is a series of hollow organs joined in a long, twisting tube from the mouth to the anus. The hollow organs that make up the GI tract are the mouth, esophagus, stomach, small intestine, large intestine, and anus. The liver, pancreas, and gallbladder are the solid organs of the digestive system.The small intestine has three parts. The first part is called the duodenum. The jejunum is in the middle and the ileum is at the end. The large intestine includes the appendix, cecum, colon, and rectum. The appendix is a finger-shaped pouch attached to the cecum. The cecum is the first part of the large intestine. The colon is next. The rectum is the end of the large intestine
Explanation:
how to make sure a snow leopard does not escape?
build a fence.....................
above
3. DIRECTIONS: Read the following two statements carefully and choose the correct options.
Statement 1: In a room containing air, heat can go from one place to another by radiation only.
Statement 2: In convection, heat is transferred from one place to other by actual motion of the
molecules in the heated material.
A) Statement (1) is correct while statement (2) is incorrect.
B) Statement (2) is correct while statement (1) is incorrect.
C) Both statements are correct
D) Both statements are incorrect.
Which points in the diagram would have Spring tides?
points A and B
points A and C
points C and D
points B and D
Answer:
If the Sun was on the left side of the diagram it would be points A and C
Explanation:
Spring tides are when the Sun, Earth, and Moon are aligned together. Neap tides occur when when the Sun, Earth, and Moon are forming a right angle.
Answer:
C and d mark mwe braliest
Explanation:
What is refractive index?
[tex] \huge \mathbb \red{HEY \: THERE ♡}[/tex]
Refractive Index:The ratio of the sine of angle of incidence to the sine of angle of refraction in case of lens for light of a given colour and given pair of media is constant. Note** It is also called Snell's Law of Refraction. [tex] \mathsf \orange{\frac{sine \: i}{sine \: r} = constant}[/tex][tex] \huge \mathbb\pink{HOPE \: IT \: HELPS}[/tex]
What is the wavelength of the wave pictured above?
Answer:
its counting by 4 the multi 4,8,12,16
(a) Calculate the capacitance of a parallel-plate capacitor whose plates are 30. cm x 5.0 cm and are separated by a 3.0-mm air gap. (b) What is the charge on each plate if a 6-V battery is connected across the two plates? (c) What is the electric field between the plates? (d) Estimate the area of the plates needed to achieve a capacitance of 5F, given the same air gap d.
The answers to your questions are as written below
A) capacitance of a parallel plate capacitor = 442.5 * 10⁻¹³ F
B) The charge on each plate is = 2655 * 10⁻¹³ C
C) The electric field between the plates is ; 2 * 10³ N/C
D) The estimated area of the plates is ; 1.695 * 10⁹ m²
A) Calculate the capacitance of a parallel plate capacitor
Plate dimension = 30 cm * 5 cm
Air gap ( d ) = 3 mm = 3 * 10⁻³ m
First step : calculate the area of the plate
Area of plate = 30 * 10⁻²m * 5 * 10⁻² m
= 150 * 10⁻⁴ m²
Next step : determine the capacitance
Capacitance = ε₀A / d
= ( 8.85 * 10⁻¹² * 150 * 10⁻⁴ ) / 3 * 10⁻³
= 442.5 * 10⁻¹³ F
B) Calculate the charge on each plate if a 6-V battery is connectedcharge on each plate can be calculated with the formula below
Q = CV
= 442.5 * 10⁻¹³ * 6
= 2655 * 10⁻¹³ C
C) Determine the electric field between the platesElectric field between plates ( E ) = V / d
= 6 / 3 * 10⁻³
= 2 * 10³ N/C
D) Estimate the area of the platesRequired capacitance = 5 F
Air gap ( d ) = 3 * 10⁻³ m
applying the equation below
C = ε₀A / d -----
5 = ( 8.85 * 10⁻¹² * A ) / 3 * 10⁻³
Therefore A :
A = ( 5 * 3 * 10⁻³ ) / 8.85 * 10⁻¹²
= 15 * 10⁻³ / 8.85 * 10⁻¹²
= 1.695 * 10⁹ m²
Hence we can conclude that the answers to your questions are as written above.
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a person have a kinetic energy = 32, if the mass increase two times and the velocity decrease four times, What would be the kinetic energy?
Answer:
4 J
Explanation:
Original KE
KE = 1/2mv²⇒ 32 = 1/2mv²Mass increases x 2
KE ∝ mm x 2 ∝ KE x 232 x 2KE' = 64Velocity decreases x 4
KE' ∝ v²KE' x (1/4)² ∝ (1/4)²KE' x 1/16 = 64 x 1/16 = 4 J1 If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed?
a The screen would remain dark because no radiation would reach the screen.
b One bright band would appear in the center of the screen.
c A series of light and dark bands would appear on the screen.
d Two bright bands would appear on the screen in line with the slits.
2 Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true?
a Waves that make up the radiation collide with each other so that they add together or cancel each other out.
b Particles that make up the radiation collide with each other and scatter randomly.
c Particles that make up the radiation collide with each other so that they add together or cancel each other out.
d Waves that make up the radiation do not interact with each other.
3 Which statement about the observed results of the double-slit experiment is true?
a Waves that are out of phase constructively interfere to create bright bands.
b Waves that are in phase destructively interfere to create bright bands.
c Waves that are out of phase constructively interfere to create bright bands.
d Waves that are in phase constructively interfere to create bright bands.
4 Which statement about the observed results of the double-slit experiment is true?
a Waves that are in phase constructively interfere to form dark bands.
b Waves that are out of phase constructively interfere to form dark bands.
c Waves that are in phase destructively interfere to form dark bands.
d Waves that are out of phase destructively interfere to form dark bands.
5 A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true about the new interference pattern seen on the screen compared to the original interference pattern?
a The spacing between the dark fringes will increase.
b The spacing between the bright fringes will increase.
c The spacing between the bright fringes will decrease.
d The spacing between the dark fringes will remain the same.
6 Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light?
a 789 nm
b 420 nm
c 581 nm
d 591 nm
Answer:
1. Two bright bands would appear on the screen in line with the slits.
2. Waves that make up the radiation collide with each other so that they add together or cancel each other out.
3. Waves that are in phase constructively interfere to create bright bands.
4. Waves that are out of phase destructively interfere to form dark bands.
5. The spacing between the bright fringes will decrease.
6. 581 nm
Explanation:
What does the term wavelength refer to?
the distance between the equilibrium position and a crest
the distance between the equilibrium position and a trough
the time taken to complete one cycle
the distance between two consecutive crests or troughs
Answer:
the distance between two consecutive crests or troughs
What is the gravitational potential energy of a 2100 kg car at the top of an 18 m parking garage?
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Gravitational Potential of an object with mass m, and height of h metre is :
[tex]\qquad \sf \dashrightarrow \:mgh[/tex]
Now, if the mass of object is 2100 kg, height of 18 m is placed in there, then it's gravitational potential energy is ~
[tex]\qquad \sf \dashrightarrow \:2100 \times 10 \times 18[/tex]
[tex]\qquad \sf \dashrightarrow \:378000 \: \: joules[/tex]
[tex]\qquad \sf \dashrightarrow \:3.78 \times 10 {}^{5} \: \: joules[/tex]
I need help with this please
Answer:
Rahman was a little bit 5AM but I think he was just try and the guy was the one who just got a a??ze and you know how are you to me that you
I need help with my earth and space science, ASAP! can someone please help?
Answer:
from what i got it is B
Hope This Helps
Friction between our feet and the surface we walk on is desirable. True False
Answer:
True
Explanation:
Can objects (aside from light/photons) travel the same speed or faster than the speed of light and still have Special Relativity work? Why or why not?
Answer:
who can apply for the award
What are your ideas about how humans can reduce the amount of carbon dioxide and methane they add to the atmosphere?
Answer:
Find the heavy processes of CO2 and methane.
Explanation:
Step #1 Find a very reliable energy source.
Step #2 Find the heavy processes of CO2 and methane like in many factories and places with high carbon emissions.
Step #3 Shut down each of the heavy processes even 10 per day would do a lot.
Step #4 Use the renewable energy source as a replacement for the attempts to generate energy using carbon emissions.
A proton in the nucleus of an atom has an electrical charge of:
neutral
-
+
zero
Answer:
proton is positively charged changechar
Explanation:
Once you have possession of the disk, you can run only 5 steps before you have to pass it to a teammate.
true
false
Answer:
If this is for Ultimate Frisbee, then FALSE
Explanation:
According to the rules, "In order for the disc to go from one player to another, it must at some time be in the air. No player may walk, run, or take steps in possession of the disc. The momentum of the receiver, however, must be taken into consideration." (crec.unl.edu) This means that if the player is already moving, they may take a maximum of two steps to come to a stop. (www.csun.edu).
.
.
.
Hope that helps?
A wave is sent back and forth along a rope 4 m long with a mass of 0.6 kg by exerting a force a force of 30 N. Calculate the linear mass density of the rope (in kg/m).
The linear mass density of the rope in the given motion of the wave is 0.15 kg/m.
Linear mass density of the ropeThe linear mass density of the rope in the given motion of the wave is determined by dividing the mass of the rope with the length of the entire rope.
The linear mass density of the rope is calculated as follows;
μ = m/L
μ = 0.6 kg / 4 m
μ = 0.15 kg/m
Thus, the linear mass density of the rope in the given motion of the wave is 0.15 kg/m.
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