A bag contains some number of marbles. It is known that 20 of them are red. When 15 marbles are drawn, without replacement, we get 6 red. Assuming E(X)=6 red, what is the total number of marbles in the bag?

Complete question is:

Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.

Answer:

Probability = 0.0277

Step-by-step explanation:

We are given;

Mean: μ = 32

Standard deviation;σ = 7

Random sample number; n = 34

To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.

Thus;

z = (29.7 - 32)/(7/√34)

Thus, z = -2.3/1.200490096

z = -1.9159

From the standard z table and confirming with z-calculator, the probability is 0.0277

Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277

Answer:

18×18×36

Step-by-step explanation:

According to the Question

108≥ 4h + w

Volume V is given by

V = wh^2

⇒V= (108-4h)h^2

⇒V= 108h^2 - 4h^3

Now differentiating and keeping = 0 we get

V' = 216h - 12h^2 = 0

h = 216/12 = 18

w = 108 - 4×18 = 36

V = 36×18^2 = 11664 from a box of 18×18×36.

Answer:

4z + 2 - 5/2z

Step-by-step explanation:

8z^2 + 4z -5

divided by 2z

8z^2 /2z = 4z

4z/2z =2

5/2z = 5/2z

Putting them back together

4z + 2 - 5/2z

Answer:

A   4z + 2 - 5/2z

Step-by-step explanation:

Answer:

Lucas groups the polynomial (12x^3 + 8x) + (–6x^2 – 4) to factor → 2 (2 x - 1) (3 x^2 + 2)

Step-by-step explanation:

Factor the following:

12 x^3 - 6 x^2 + 8 x - 4

Hint: | Factor out the greatest common divisor of the coefficients of 12 x^3 - 6 x^2 + 8 x - 4.

Factor 2 out of 12 x^3 - 6 x^2 + 8 x - 4:

2 (6 x^3 - 3 x^2 + 4 x - 2)

Hint: | Factor pairs of terms in 6 x^3 - 3 x^2 + 4 x - 2 by grouping.

Factor terms by grouping. 6 x^3 - 3 x^2 + 4 x - 2 = (6 x^3 - 3 x^2) + (4 x - 2) = 3 x^2 (2 x - 1) + 2 (2 x - 1):

2 3 x^2 (2 x - 1) + 2 (2 x - 1)

Hint: | Factor common terms from 3 x^2 (2 x - 1) + 2 (2 x - 1).

Factor 2 x - 1 from 3 x^2 (2 x - 1) + 2 (2 x - 1):

Answer: 2 (2 x - 1) (3 x^2 + 2)

Answer:

Both students are correct because polynomials can be grouped in different ways to factor. Both ways result in a common binomial factor between the groups. Using the distributive property , this common binomial term can be factored out. Each grouping results in the same two binomial factors.

Step-by-step explanation:

this is the sample response provided by edge

Answer:

[tex] P= 2*Lenght + 2*Width[/tex]

Since the perimeter is 56 inches we can solve for the lenght with this equation:

[tex] 56 in = 2*12in + 2*Length[/tex]

And solving for the length we got:

[tex] Length = \frac{56in -24 in}{2} 16 in[/tex]

So then the lenght = 16 inhes and the width of 12 inches

Step-by-step explanation:

For a rectangle of width 12 inches and lenght y inches we know that the perimeter is given by:

[tex] P= 2*Lenght + 2*Width[/tex]

Since the perimeter is 56 inches we can solve for the lenght with this equation:

[tex] 56 in = 2*12in + 2*Length[/tex]

And solving for the length we got:

[tex] Length = \frac{56in -24 in}{2} 16 in[/tex]

So then the lenght = 16 inhes and the width of 12 inches

Answer:

product = 40

Step-by-step explanation:

The conjugate of (-2 + 6i) is (-2 - 6i)

You just need to change the sign

(-2 + 6i) (-2 - 6i)

Expand:

4 + 12i + -12i - [tex]36i^{2}[/tex]

4 + 12i + -12i + 36

product = 40

Answer:

127.5

Step-by-step explanation:

Multiply 170 by 0.75

127.5

Answer:

3 divided by 4 = 0.75 = 3/4

0.75 x 170 = 127.5

or

170/1 x 3/4 = 510/4 = 127 1/2

1/2 = 0.5 = 1 divided by 2

127 + 0.5 = 127.5

127.5 is the answer

Hope this helps

Step-by-step explanation:

Answer: The new price of  the car is $41856

Step-by-step explanation:

So we know the the original price as 43,600 which is 100% and is being dropped by 4%  so you would have to subtract 4% from a 100% and multiply it by the original price.

100% - 4% = 96%

Now 96% of the original price is the new price.

96% * 43,600= ?

0.96 * 43,600 = 41856

Answer:2

Step-by-step explanation:

3y+ 7= 13

3y= 13 - 7

3y= 6

Y = 6/3

Y= 2

Answer:

D: 17 times

Step-by-step explanation:

Volume of tank = 36×13×24

= 11,232 cubic inches

Now

Bucket = 693 cubic inches

Number of time Valeria will use the bucket = 11232/693

= 16.2

≈ 17

Answer:

There were 30 people attending at the start of the concert

Step-by-step explanation:

The coefficient of the value raised to an exponent in these types of functions is always the "starting" value. In your case, '30' is the coefficient, so it is the starting value. FYI: 1.10 is the rate at which the people increase, t is time passed, 20 is a constant, and P is the total number of people after the time goes by.

Answer:

There were 30 people attending at the start of the concert.

Step-by-step explanation:

30 is the coefficient, so that's your starting point, basically.

Answer:

B

Step-by-step explanation:

Answer:

Coefficient of variation (weight) = 15%

Coefficient of variation (volume) = 25%

Step-by-step explanation:

Let's begin by listing out the given information:

Population = 200, Average weight = 26 lb,

standard deviation (weight) = 3.9 lb,

Average volume = 8.8 ft³,

standard deviation (volume) = 2.2 ft³

Based on the data given, the manager will have to make a deduction by comparing the relative scatter of both variables due to the different units of measuring weight (pounds) and volume (cubic feet).

To compare the variation of the weight and volume, we use the coefficient of variation given by the formula:

Coefficient of Variation = (Standard deviation ÷ Mean) * 100%

⇒ [tex]C_{v}[/tex] = (σ ÷ μ) * 100%

For weight

σ = 3.9 lb, μ = 26 lb

[tex]C_{v}[/tex] (weight) = (3.9 ÷ 26.0) * 100% = 15%

[tex]C_{v}[/tex] (weight) = 15%

For volume

σ = 2.2 ft³, μ = 8.8 ft³

[tex]C_{v}[/tex] (volume) = (2.2 ÷ 8.8) * 100% = 25%

[tex]C_{v}[/tex] (volume) = 25%

∴ the relative variation of the volume of the package is greater than that of the weight of the package

Answer:

[tex]x=35^\circ[/tex]

Step-by-step explanation:

From the diagram which I have drawn and attached below:

[tex]56^\circ+y+51^\circ=180^\circ$ (Sum of Angles on a Straight Line)\\y=180^\circ-(56^\circ+51^\circ)\\y=73^\circ[/tex]

Next, in the triangle, the sum of the three interior angles:

[tex]y+x+72^\circ=180^\circ\\$Since y=73^\circ\\73^\circ+x+72^\circ=180^\circ\\x=180^\circ-(73^\circ+72^\circ)\\x=35^\circ[/tex]

The value of angle x is 35 degrees.

Answer:

x = -7.33        OR         x = [tex]\frac{-22}{3}[/tex]

y = 13

Step-by-step explanation:

→You can use the substitution method. First, make y by itself in (-2 + 2y = 24):

-2 + 2y = 24

2y = 26

y = 13

→Then, plug in 13 for y into the other equation:

3x + 2y = 4

3x + 2(13) = 4

3x + 26 = 4

3x = -22

x = -7.33        OR         x = [tex]\frac{-22}{3}[/tex]

Answer:  C

Step-by-step explanation:

In order to find the inverse, transpose the matrix then find the determinant of each 2 x 2 matrix within it.

[tex]Q=\left[\begin{array}{ccc}2&2&3\\1&1&1\\3&2&1\end{array}\right] \qquad \rightarrow \qquad Q^T=\left[\begin{array}{ccc}2&1&3\\2&1&2\\3&1&1\end{array}\right][/tex]

[tex]det\left[\begin{array}{cc}1&2\\1&1\end{array}\right] =\bold{-1}\qquad det\left[\begin{array}{cc}2&2\\3&1\end{array}\right]=\bold{-4}\qquad det\left[\begin{array}{cc}2&1\\3&1\end{array}\right] =\bold{-1}\\\\\\\\det\left[\begin{array}{cc}1&3\\1&1\end{array}\right] =\bold{-2}\qquad det\left[\begin{array}{cc}2&3\\3&1\end{array}\right]=\bold{-7}\qquad det\left[\begin{array}{cc}2&1\\3&1\end{array}\right] =\bold{-1}\\[/tex]

[tex]det\left[\begin{array}{cc}1&3\\1&2 \end{array}\right] =\bold{-1}\qquad det\left[\begin{array}{cc}2&3\\2&2\end{array}\right]=\bold{-2}\qquad det\left[\begin{array}{cc}2&1\\2&1\end{array}\right] =\bold{0}[/tex]

[tex]Q^{-1}=\large\left[\begin{array}{ccc}1&-4&1\\-2&7&-1\\-1&-2&0\end{array}\right][/tex]

Answer:

(a)r=15-b

11.9 Inches

(b)See attached

Step-by-step explanation:

Length of the candle =15 inch

Let b represent the burned length of the candle (in inches)

Let r represent the remaining length of the candle (in inches).

Therefore:

(a) r+b=15

r=15-b

When b=3,1 Inches

Remaining Length, r=15-3.1=11.9 Inches

(b)The graph showing te relationship between r and b is shown below.

r is plotted on the y-axis while b is plotted on the x-axis as labelled.

Formula that express r in terms of b is

[tex]r=15-b[/tex]

Remaining length of candle is 11.9 inches

Given :

A 15-inch candle is lit and steadily burns until it is burned out

Let b represent the burned length   and let r represent the remaining length  

We need to write the formula

remaining length = initial length - burned length

[tex]r=15-b[/tex]

When 3.1 inches have burned from the candle, the remaining length of the candle is inches.

b is 3.1

remaining length [tex]r=15-3.1=11.9[/tex] inches

now we graph the relationship

Graph is attached below.

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Answer:

The best estimate of the mean of the population is 50,000 miles, which is the sample mean.

To make a better inference, we know that the 95% confidence interval for the mean is (49,306; 50,694).

Step-by-step explanation:

The unbiased point estimation for the population mean tread life is the sample mean (50,000 miles), as it is the only information we have.

Although, knowing the standard deviation, we can calculate a confidence interval to make a stronger inference.

We calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=50000.

The sample size is N=100.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3500}{\sqrt{100}}=\dfrac{3500}{10}=350[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=100-1=99[/tex]

The t-value for a 95% confidence interval and 99 degrees of freedom is t=1.98.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=1.98 \cdot 350=694.48[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 50000-694.48=49306\\\\UL=M+t \cdot s_M = 50000+694.48=50694[/tex]

The 95% confidence interval for the mean is (49306, 50694).

Answer:

B. Complements of congruent angles are congruent.

Step-by-step explanation:

Angles <DCF and <FEG have angles measures that are complementary to to angles E and C.

Answer:

George is 43.20 ft East of his starting point.

Step-by-step explanation:

Let Paula's speed be x ft/s

George's speed = 9 ft/s

Note that speed = (distance)/(time)

Distance = (speed) × (time)

George takes 50 s to run a lap of the track at a speed of y ft/s

Meaning that the length of the circular track = y × 50 = 50y ft

George and Paula meet 14 seconds after the start of the run.

Distance covered by George in 14 seconds = 9 × 14 = 126 ft

Distance covered by Paula in 14 seconds = y × 14 = 14y ft

But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track

That is,

126 + 14y = 50y

50y - 14y = 126

36y = 126

y = (126/36) = 3.5 ft/s.

Hence, Paula's speed = 3.5 ft/s

Length of the circular track = 50y = 50 × 3.5 = 175 ft

So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of

9 × 240 = 2160 ft.

2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.

Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft

So, 60 ft along a circular track subtends an angle θ at the centre of the circle.

Length of an arc = (θ/360°) × 2πr

2πr = total length of the circular track = 175

r = (175/2π) = 27.85 ft

Length of an arc = (θ/360) × 2πr

60 = (θ/360°) × 175

(θ/360°) = (60/175) = 0.343

θ = 0.343 × 360° = 123.45°

The image of this incomplete lap is shown in the attached image,

The distance of George from his starting point along the centre of the circular track = (r + a)

But, a can be obtained using trigonometric relations.

Cos 56.55° = (a/r) = (a/27.85)

a = 27.85 cos 56.55° = 15.35 ft

r + a = 27.85 + 15.35 = 43.20 ft.

Hence, George is 43.20 ft East of his starting point.

Hope this Helps!!!

Answer:

[tex]x=2+\sqrt{11},\:x=2-\sqrt{11}[/tex]

Step-by-step explanation:

[tex]x^2-4x-7=0\\\mathrm{Solve\:with\:the\:quadratic\:formula}\\Quadratic\:Equation\:Formula\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\mathrm{For\:}\quad a=1,\:b=-4,\:c=-7:\quad x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}\\x=\frac{-\left(-4\right)+\sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}:\quad 2+\sqrt{11}[/tex]

[tex]x=\frac{-\left(-4\right)-\sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}:\quad 2-\sqrt{11}\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\x=2+\sqrt{11},\:x=2-\sqrt{11}[/tex]

Answer:

  the sum is 01011000₂ = 88

Step-by-step explanation:

For numbers of magnitude less than 128, it is convenient to use an 8-bit representation. I find it works will to convert back and forth through the octal (base-8) representation, as each base-8 digit converts nicely to three (3) base-2 bits.

  61 = 8·7 +5 = 075₈ = 00 111 101₂

  27 = 8·3 +3 = 033₈ = 00 011 011₂

Then ...

  [tex]\begin{array}{cc|ccc}&61&&00111101\\+&27&+&00011011\\ &\overline{88}&&\overline{01011000}\end{array}[/tex]

__

Starting from the right, we can convert the binary back to octal, then to decimal by considering 3 bits at a time:

  01 011 000₂ = 130₈ = 1·8² +3·8 +0 = 64 +24 = 88

The binary sum is the same as the decimal sum.

Answer:

Probability = 4%

Step-by-step explanation:

For each answer, there are only two possible outcomes. Either it is correct, or it is not. The probability of an answer being correct is independent of other answers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Each question has 5 possible answer:

The person guesses, so [tex]p = \frac{1}{5} = 0.2[/tex]

2 questions:

This means that [tex]n = 2[/tex]

Find the probability that both responses are correct.

This is P(X = 2).

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{2,2}.(0.2)^{2}.(0.8)^{0} = 0.04[/tex]

As a percent:

Probability = 4%

Answer: Point slope form is y-y1=m(x-x1)

Step-by-step explanation:

Here y1=4

x1=-11

m i.e slope=-2

And there you go.

Answer:

Read below.

Step-by-step explanation:

Questions are underlined

Answers are bolded

Which of the following statements is true?

If two polygons are similar then the corresponding sides are proportional and the corresponding angles are proportional.

If two polygons are similar, then the corresponding sides are proportional and  the corresponding angles are congruent.

If two polygons are similar, then the corresponding sides are congruent and the corresponding angles are proportional.

None of the choices are correct.

Which of the following sides are corresponding if ΔABC is similar to ΔMNL?

AC and ML, BC and NL, AB and MN is the correct answer but the answer choices are:

AB and MN, BC and NL, AC and ML

AC and MN, BC and NL, AB and ML

AB and ML, BC and NL, AC and MN

None of the choices are correct.

Answer:

(d - 4) / c

Step-by-step explanation:

The slope of the line in terms of c and d is (d - 4) / c.

Here, we have,

To find the slope of the line in terms of the coordinates of the point (c, d), we can use the slope-intercept form of a line, y = mx + b, where m represents the slope.

In the given equation, y = kx + 4, we can see that the coefficient of x is k, which represents the slope of the line.

Since the line contains the point (c, d), we can substitute these values into the equation:

d = kc + 4

To isolate the slope term, we rearrange the equation:

d - 4 = kc

Now, divide both sides by c:

(d - 4) / c = k

Therefore, the slope of the line in terms of c and d is (d - 4) / c.

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Answer:

(A)Decay

(b)0.8

(c)First Term

(d)[tex]f(t)=2000(0.8)^t[/tex]

(e)$819.20

Step-by-step explanation:

The exponential function for modelling growth or decay is given as:

[tex]A(t)=A_o(1\pm r)^t[/tex],

Where:

Plus indicates growth and minus indicates decay.

[tex]A_o$ is the Initial Value\\r is the growth/decay rate\\t is the time period[/tex]

For a powerful computer that was purchased for $2000, but loses 20% of its value each year.

(a)Since it loses value, it is a decay.

(b)Multiplier

Its value decays by 20%.

Therefore, our multiplier(1-r) =(1-20&)=1-0.2

Multiplier =0.8

(c)$2000 is our First term (or Initial Value [tex]A_o[/tex])

(d)The function for this problem is therefore:

[tex]f(t)=f_o(1- r)^t\\f(t)=2000(1- 0.2)^t\\\\f(t)=2000(0.8)^t[/tex]

(e)Since we require the worth of the computer after 4 years,

t=4 years

[tex]f(4)=2000(0.8)^4\\f(4)=\$819.20[/tex]

Answer:

part a: 52%

part b: 0.4

part c: 0.24

Step-by-step explanation:

For part one, you find the frequency of the number of people that are less that 20. You add the number of tics in each bar and you divide by the total.

so for part a it is (7+6+9+4)/ (7+6+9+4+4+12+8)

for part b you add up the values that are greater than 25(less than 35)

(12+8)/total

part c you find the number of people between 25 and 30

that's 12

over total

12/total

Answer:

The area of the shaded region between [tex] \\ z = 1.23[/tex] and [tex] \\ z = 0.86[/tex] is [tex] \\ P(0.86 < z < 1.23) = 0.08554[/tex] or 8.554%.

Step-by-step explanation:

To solve this question, we need to find the corresponding probabilities for the standardized values (or z-scores) z = 1.23 and z = 0.86, and then subtract both to obtain the area of the shaded region between these two z-scores.

We need to having into account that a z-score is given by the following formula:

[tex] \\ z = \frac{x - \mu}{\sigma}[/tex]

Where

A z-score indicates the distance of x from the mean in standard deviations units, where a positive value "tell us" that x is above [tex] \\ \mu[/tex], and conversely, a negative that x is below [tex] \\ \mu[/tex].

The standard normal distribution is a normal distribution with [tex] \\ \mu = 0[/tex] and [tex] \\ \sigma = 1[/tex], and has probabilities for standardized values obtained using [1]. All these probabilities are tabulated in the standard normal table (available in any Statistical book or on the Internet).

Using the cumulative standard normal table, for [tex] \\ z = 1.23[/tex], the corresponding cumulative probability is:

[tex] \\ P(z<1.23) = 0.89065[/tex]

The steps are as follows:

Following the same procedure, the cumulative probability for [tex] \\ z = 0.86[/tex] is:

[tex] \\ P(z<0.86) = 0.80511[/tex]

Subtracting both probabilities (because we need to know the area between these two values) we finally obtain the corresponding area between them (two z-scores):

[tex] \\ P(0.86 < z < 1.23) = 0.89065 - 0.80511[/tex]

[tex] \\ P(0.86 < z < 1.23) = 0.08554[/tex]

Therefore, the area of the shaded region between [tex] \\ z = 1.23[/tex] and [tex] \\ z = 0.86[/tex] is [tex] \\ P(0.86 < z < 1.23) = 0.08554[/tex] or 8.554%.

We can see this resulting area (red shaded area) in the graph below for a standard normal distribution, [tex] \\ N(0, 1)[/tex], and  [tex] \\ z = 0.86[/tex] and [tex] \\ z = 1.23[/tex].