A ball is thrown straight up and passes point B (at a height of 56.8 m above its starting point O) in 5.8 s. What was its initial speed? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s

Answer:

B:It states a fact about how nature works.

C:It is based on observations of nature.

F:It will most likely remain true even when scientists work with new experiments.

Explanation:

Good luck :)

These are characteristics of a scientific law that states a fact about how nature works. It is based on observations of nature and  It will most likely remain true even when scientists work with new experiments. therefore the correct options are options B, C, and F

Scientific claims are statements made in science based on an experiment.

These Scientific claims are backed by the experimental data and their true results obtained from scientific investigation and experimentation.

scientific law states a fact about how nature works, based on observations of nature. It often changes over time with new experiments and technology and will most likely remain true even when scientists work with new experiments.

Thus, These qualities define a scientific law that establishes a fact about how nature functions. It is based on observations of nature, and even if scientists conduct additional tests, it will probably continue to be true. Hence, choices B, C, and F are the best choices.

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Answer:

Part A:    [tex]\mathbf{Q =94 \ J}[/tex] to two significant figures

Part B:    [tex]\mathbf{Q =160 \ J}[/tex] to two significant figures

Part C:    [tex]\mathbf{Q =220 \ J}[/tex] to two significant figures

Explanation:

Given that :

mass of the hydrogen = 0.30 g

the molar mass of hydrogen gas molecule = 2 g/mol

we all know that:

number of moles = mass/molar mass

number of moles = 0.30 g /2 g/mol

number of moles = 0.15 mol

For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule = [tex]C_v=\dfrac{3}{2}R[/tex]

For Part A:

[tex]Q = mC_v\Delta T[/tex]

[tex]Q= 0.15 \ mol (\dfrac{3}{2})(8.314 \ J/mole.K )(100-50)K[/tex]

[tex]Q= 0.15 \times (\dfrac{3}{2}) \times (8.314 \ J )\times (50)[/tex]

[tex]Q=93.5325 \ J[/tex]

[tex]\mathbf{Q =94 \ J}[/tex] to two significant figures

Part B. For hot temperature, [tex]C_v=\dfrac{5}{2}R[/tex]

[tex]Q = mC_v\Delta T[/tex]

[tex]Q= 0.15 \ mol (\dfrac{5}{2})(8.314 \ J/mole.K )(300-250)K[/tex]

[tex]Q= 0.15 \times (\dfrac{5}{2}) \times (8.314 \ J )\times (50)[/tex]

[tex]Q=155.8875 \ J[/tex]

[tex]\mathbf{Q =160 \ J}[/tex] to two significant figures

Part C. For an extremely hot temperature, [tex]C_v=\dfrac{7}{2}R[/tex]

[tex]Q = mC_v\Delta T[/tex]

[tex]Q= 0.15 \ mol (\dfrac{7}{2})(8.314 \ J/mole.K )(2300-2250)K[/tex]

[tex]Q= 0.15 \times (\dfrac{7}{2}) \times (8.314 \ J )\times (50)[/tex]

[tex]Q=218.2425 \ J[/tex]

[tex]\mathbf{Q =220 \ J}[/tex] to two significant figures

Part A)  Heat needed to change the temperature of the gas from 50 K to 100 K is 94J.

Part B) Heat needed to change the temperature of the gas from 250 K to 300 K is 160J.

Part C) Heat needed to change the temperature of the gas from 2250 K to 2300 K is 220J.

The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.

Given is the mass of the hydrogen = 0.30 g and the molar mass of hydrogen gas molecule = 2 g/mol

Then, number of moles = mass/molar mass

number of moles = 0.30 g /2 g/mol = 0.15 mol

Part A) For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule Cv =3/2R

Q =m Cv ΔT

Q = 0.15 mol x 3/2 x 8.314 x (100 - 50)

Q = 93.5325 Joules.

Q = 94 J to two significant figures.

Part B) For hot temperature, Cv = 5/2 R

Heat needed, Q =m Cv ΔT

Q = 0.15 mol x 5/2 x 8.314 x (300 - 250)

Q = 155.8875Joules.

Q = 160 J to two significant figures.

Part C) In case of extremely hot temperature, Cv =7/2R

Heat needed to change the temperature from 2250 K to 2300 K

Q = 0.15 mol x 7/2 x 8.314 x (2300 - 2250)

Q = 218.2425 J

Q = 220J

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Answer:

Explanation:

The electric charges are placed on a line .

1 a )      q1= +1 nC       q2= -1 nC         q3= -1 nC

here q₁ will be attracted by both q₂ and q₃ so net force on q₁ will be positive

2 a )      q1= -1 nC       q2= +1 nC         q3= + 1 nC

here q₁ will be attracted by both q₂ and q₃ so net force on q₁ will be positive

3 a )      q1= +1 nC       q2= +1 nC         q3= + 1 nC

here q₁ will be repelled  by both q₂ and q₃ so net force on q₁ will be negative.

4 a )      q1= +1 nC       q2= +1 nC         q3= - 1 nC

q2 will repel and q3 will attract so net force will be towards left but it will be weakened .

5 a )      q1= -1 nC       q2= -1 nC         q3= - 1 nC

Both q₁ and q₂ will repel so net force will be towards left and negative .

6 a )      q1= +1 nC       q2= -1 nC         q3= + 1 nC

q2 will attract and q3 will repel   so net force will be towards right  but it will be weakened . It will be positive .

Largest positive force to lowest positive force

2  a ) = 1 a ) >  6 a )

Largest negative  force to lowest positive force

5a )= 3 a ) > 4a )

Answer:

988.39 N/C

Explanation:

First, we start by finding the magnitude of the electric dipole moment, as it's going to be needed

p = 4.40*10^-9 * 3.10*10^-3

p = 1.364*10^-11 Cm

The charges are in a uniform electric field E whose direction makes an angle of 36.4° with the line connecting the charges.

Magnitude of torque exerted on the dipole,

t = 8.0×10−9 N.m

pEsinO = t, making E subject of formula

E = t / psinO

E = 8.0*10^-9/1.364*10^-11 (sin36.4)

E = 8.0*10^-9/1.364*10^-11 * (0.5934)

E = 8.0*10^-9 / 8.094*10^-12

E = 988.39 N/C

the magnitude of this field is E = 988.39 N/C

Answer:

14

Explanation:

The total no of protons and neutrons in an atomic nucleus is called mass number, nucleon number or atomic mass number. It is denoted by A.

In this problem, we need to find the nucleon number of carbon-14 i.e. mass number of carbon -14. 14 with carbon shows its mass number.

Hence, the nucleon no of carbon-14 is 14.

Answer:

750 miles / hour

Explanation:

velocity = distance / time

             = 4500 miles / 6 hours

             = 750 miles / hour

Given:-

To Find: Speed (v) of the particle (airplane).

We know,

s = vt

where,

Similarly,

v = s/t

→ v = (4500 miles)/(6 hours)

→ v = 750 miles/hour ...(Ans.)

The protective covers on wires are called insulation and they are typically made out of plastic or rubber. The purpose for this insulation is so the wire doesn't come in contact with other conductors. It also protects it from having electrical leaks or threats to the environment.

Best of Luck!

Answer:

c.  Cos θ =  [tex]A_{x}[/tex] / [tex]\sqrt{(A_{x} ^{2} + A_{y} ^{2}) }[/tex]

Explanation:

A vector is any quantity that has both magnitude and direction. The given vector A has components [tex]A_{x}[/tex] and [tex]A_{y}[/tex], and makes angle  θ with +x axis.

Thus;

Resultant of the vector, A = [tex]\sqrt{(A_{x} ^{2} + A_{y} ^{2}) }[/tex]

Therefore, the components, angle and resultant of vector A can be represented in magnitude and direction by the three sides of a right angled triangle.

Applying the appropriate trigonometric function to the triangle for vector A, we have;

Cos θ =  [tex]A_{x}[/tex] ÷   [tex]\sqrt{(A_{x} ^{2} + A_{y} ^{2}) }[/tex]

⇒   Cos θ =  [tex]A_{x}[/tex] / [tex]\sqrt{(A_{x} ^{2} + A_{y} ^{2}) }[/tex]

The correct option is C.

Answer:

speed = distance ÷ time.

speed=50÷ 5

=10m/s

A bike moves 50 meters in 5 seconds, then the speed of the bike would be 10 m/s.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.

As given in the problem a bike moves 50 meters in 5 seconds. This means the total distance covered by the bike is 50 meters, and the total time taken by the bike is 5 seconds.

The total distance covered by the bike = 50 meters

The total time taken to cover the 5 meters = 5 seconds

speed = the total distance covered by the bike/the total time

           = 50 meters/5 seconds

           = 10 m/s

Thus, the speed of the bike comes out to be  10 m/s.

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Answer:

The average speed of a neon atom is 414.04 m/s

Explanation:

Given;

energy of the neon gas, E = 1200 J

mass of the neon gas, m  = 14 g = 0.014 kg

The speed of the neon atom is given by Maxwell-Boltzmann;

E = ¹/₂mv²

where;

v is the average speed of the neon atom

1200 = ¹/₂(0.014)v²

2 x 1200 = 0.014v²

2400 = 0.014v²

v² = 2400 / 0.014

v² = 171428.57

v = √ 171428.57

v = 414.04 m/s

Therefore, the average speed of a neon atom is 414.04 m/s

The average speed of a neon atom will be 414.04 m/s.

The total distance traveled by an object divided by the total time taken is the average speed.

The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.

The given data in the problem is;

E is  the energy of the neon gas, = 1200 J

m is the mass of the neon gas= 14 g = 0.014 kg

v is the speed of the neon atom=?

From the Maxwell-Boltzmann equation;

[tex]\rm E= \frac{1}{2} mv^2 \\\\ v=\sqrt{\frac{2E}{m} } \\\\ v=\sqrt{\frac{2 \times 1200 }{0.014} } \\\\ v= 414.04 \ m/s[/tex]

Hence the average speed of a neon atom will be 414.04 m/s.

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Answer:

The answer is 6, because 2×y is equal to 12.

Answer:

question, report, observe, research, draw conclusions, hypothesize, test hypothesis, experiment

Explanation:

Answer:

Nutritional intake:)Hope this helps.

Explanation:

Answer: the picture is the answer

Explanation:

Answer:

18.8m

Explanation:

This implies calculating the relative speed first then find the distance d

So

relative speed = 2.75- 1.25 = 1.5 m/s

So assume the distance between them to be say d

so, d/1.5= 12.5

d = 18.8m

Malleability

★ Malleability: The property which allows the metal to be hammered into thin sheets is called malleability.

★ Brittleness: The property due to which non-metals break down on hammering is called brittleness .

★ Ductility: The property which allows the metal to be drawn into wires is called dutility.

Answer:

The answer to this question is malleability.

Answer:

The accuracy percentage for 50000 ft is 0.47%.

The accuracy percentage for 100000 ft is 0.92%.

Explanation:

Given that,

Height = 50000 ft and 100000 ft

We need to calculate the new acceleration due to gravity

Using newtonian gravitational formula

[tex]g'=g\times(1-\dfrac{h}{R})^{-2}[/tex]

Where, g = acceleration due to gravity

h = height

R = radius

Put the value into the formula

[tex]g'=9.81\times(1-\dfrac{50000}{20.9\times10^{6}})^{-2}[/tex]

[tex]g'=9.857[/tex]

We need to find the accuracy percentage

Using formula for accuracy

[tex]accuracy\ percentage=\dfrac{g'-g}{g}\times100[/tex]

Put the value into the formula

[tex]accuracy\ percentage=\dfrac{9.857-9.81}{9.81}[/tex]

[tex]accuracy\ percentage=0.47\%[/tex]

Now, For other height,

We need to calculate the new acceleration due to gravity

Using newtonian gravitational formula

[tex]g'=g\times(1-\dfrac{h}{R})^{-2}[/tex]

Put the value into the formula

[tex]g'=9.81\times(1-\dfrac{100000}{20.9\times10^{6}})^{-2}[/tex]

[tex]g'=9.90[/tex]

We need to find the accuracy percentage

Using formula for accuracy

[tex]accuracy\ percentage=\dfrac{g'-g}{g}\times100[/tex]

Put the value into the formula

[tex]accuracy\ percentage=\dfrac{9.90-9.81}{9.81}[/tex]

[tex]accuracy\ percentage=0.92\%[/tex]

Hence, The accuracy percentage for 50000 ft is 0.47%.

The accuracy percentage for 100000 ft is 0.92%.

Answer and Explanation: Kinetic energy is related to movement: it is the energy an object possesses during the movement. it is calculated as:

[tex]K=\frac{1}{2}mv^{2}[/tex]

For the object thrown in the air:

[tex]K=\frac{1}{2}.2.[v(t)]^{2}[/tex]

[tex]K=(-9.8t+24)^{2}[/tex]

[tex]K=96.04t^{2}-470.4t+576[/tex]

Kinetic energy of the object as a function of time: [tex]K=96.04t^{2}-470.4t+576[/tex]

Potential energy is the energy an object possesses due to its position in relation to other objects. It is calculated as:

[tex]U=mgh[/tex]

For the object thrown in the air:

[tex]U=9.8.2.h(t)[/tex]

[tex]U=9.8.2.(-4.9t^{2}+24t+60)[/tex]

[tex]U=-96.04t^{2}+470.4t+1176[/tex]

Potential energy as function of time: [tex]U=-96.04t^{2}+470.4t+1176[/tex]

Total kinetic and potential energy, also known as mechanical energy is

TME = [tex]96.04t^{2}-470.4t+576[/tex] + ([tex]-96.04t^{2}+470.4t+1176[/tex])

TME = 1752

The expression shows that total energy of an object thrown in the air is constant and independent of time.

Explanation:

Given that,

Mass of a puck, m = 8 kg

Initial velocity, u = 10i m/s

Final velocity, v = (10i+12j) m/s

Time, t = 8 s

(a) Force acting on an object is given by the product of mass and acceleration.

F = ma

a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{8\times (10i+12j-10i)}{8}\\\\F=12j\ \text{N}[/tex]

(b) The magnitude of force is given by :

[tex]F=\sqrt{12^2+0^2} \\\\F=12\ N[/tex]

Hence, the component of force is 12j N and its magnitude is 12 N.

Answer:

1: 2

2: 1

3: 3

Explanation:

Answer:Federal System->Power Is divides between state, local etc.

Branches of government-> Power is divided among legislative, executive

Constitutional democracy-> Government power

Explanation:

Answer:

the trajectory for the missile [tex]\mathbf{r(t) = \langle1000t,1400t, 368t -16t^2 \rangle}[/tex]

the downrange of the missile R =  39570.6973 ft

Explanation:

Suppose the initial velocity v(0) = <1000, 1400, 368 > ft/sec

The single force which is acting over the missle is the gravitational force.

a (t) = <0, 0, -32>  ft/sec²

We are to  determine the trajectory and the downrange for the missle

Consider the motion  of a given object r(t) to be:

[tex]r(t) = v_it + \dfrac{1}{2}at^2[/tex]

[tex]r(t) = \langle1000,1400,368 \rangle t + \dfrac{1}{2} \langle 0,0, -32\rangle t^2[/tex]

[tex]r(t) = \langle1000t,1400t,368t \rangle + \langle 0,0, -16 t^2 \rangle[/tex]

[tex]r(t) = \langle1000t,1400t, 368t -16t^2 \rangle[/tex]

Thus, the trajectory for the missile [tex]\mathbf{r(t) = \langle1000t,1400t, 368t -16t^2 \rangle}[/tex]

To determine the downrange of the missile,

[tex]v(0) = \langle 1000,1400,368 \rangle[/tex]

where;

the horizontal vel. of the missle [tex]v_h= \sqrt{1000^2+1400^2}[/tex]

= 1720.4651 ft/s

the vertical vel. of the missile is [tex]v_v = 368 \ ft/s[/tex]

The time required to reach the ground [tex]t =\dfrac{2 \times v_v}{g}[/tex]

[tex]t =\dfrac{2 \times 368}{32}[/tex]

t = 23 sec

Finally, the downrange of the missile [tex]R = v_h \times t[/tex]

R = 1720.4651  × 23

R = 39570.6973 ft

The trajectory of the missile as a function of time is obtained as

[tex]r(t)= <100t, 1400t, 368t-16t^2>[/tex].

Given that the initial velocity is;

[tex]v(0) = <1000, 1400, 368>\,ft/sec[/tex]

The acceleration of the missile is provided by the gravitational force.

[tex]a = g = <0, 0, -32>\,ft/sec^2[/tex]

The trajectory of the object at time 't' is given by;

[tex]r(t)=v(0)\,t+\frac{1}{2} at^2= <100, 1400, 368>t\,+\frac{1}{2} <0, 0, -32>t^2[/tex]

[tex]\implies r(t)= <100t, 1400t, 368t-16t^2>[/tex]

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Answer: as fast as lightning

300,000,000 meters per second

Lightning is the flash of light that occurs when charge separation occurs. Like other forms of light, the light emitted from the lightning travels near the speed of light.

Answer: A. New, high-tech materials are used to make prosthetic limbs for  people who need them

Explanation:

Engineering is an immensely important science to us as humans for through its development of tools, machines, engines and structures, human lives have been made better in just about every field.

One of these fields is the medical field. In the past people who lost limbs could say good bye to a normal life or at least a semblance of one but now, due to advancements in Engineering, high-tech materials can now be used to make prosthetic limbs for people who need them.

Answer:

Yes, change of height affect the g.

Explanation:

As gravity is indirectly proportion to height. So when,height increases gravity decrease and when the height decrease gravity increase.

Answer:

0.5 m.

Explanation:

From the question given above, the following data were obtained:

Force (F) = 5 N

Work done (W) = 2.5 J

Distance (s) =?

Workdone is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:

Work done (W) = Force (F) × Distance (s)

W = F × s

With the above formula, we can obtain the distance to which the book has moved as follow:

Force (F) = 5 N

Work done (W) = 2.5 J

Distance (s) =?

W = F × s

2.5 = 5 × s

Divide both side by 5

s = 2.5/5

s = 0.5 m

Therefore, the book moved 0.5 m when the force was applied.

Answer:

a) 1225 kPa, 0.41 m³

b) 0.643

c) -17.86 kJ, 50 kJ, 854 kJ, -854 kJ

Explanation:

See attachment

Answer:

4 kilometers

Explanation: