Answer:
See below....the question is unclear....pick the answer you think they want
Explanation:
Car goes from 30 m/s to 24 m/s in 10 seconds
acceleration = change in velocity/change in time
= -6 m/s / 10 s = - 3/5 m/s^2
The wording of the question is not very good.....perhaps they meant to say that after the 5 seconds the velocity is now 24 m/s ?
a1 *10 + a2 *5 = -6 m/s
( 6 m/s is the change in velocity from 30 to 24 m/s)
a1/a2 = 1.5 so a2 = a1/1.5 (substitute this in)
10 a1 + 5 ( a1/1.5) =-6
15 a1 + 5 a1 = -9
a1 = - .45 m/s^2
The velocity of the car at the end of the initial ten-second interval, given that the car further slows down for the next five seconds, is 25.5 m/s
How to determine the velocity of the car at the end of the 10 s interval?From the first statement, we have:
Initial velocity (u₁) = 30 m/sTime (t₁) = 10 secondsVelocity at the end of 10 s (v₁) = ?v₁ = u₁ + a₁t₁
v₁ = 30 + (a₁ × 10)
v₁ = 30 + 10a₁ ......(1)
From the second statement, we have:
Time (t₂) = 5 sFinal velocity (v₂) = 24 m/sRation of acceleration (a₁/a₂) = 1.5Initial velocity (u₂) = Velocity at the end of 10 sv₂ = u₂ + a₂t₂
24 = u₂ + (a₂ × 5)
24 = u₂ + 5a₂ .......(2)
But,
u₂ = v₁ = 30 + 10a₁
Thus, we have:
24 = 30 + 10a₁ + 5a₂
But,
a₁/a₂ = 1.5
a₁ = 1.5a₂ ..... (3)
Thus, we have:
24 = 30 + 10a₁ + 5a₂
24 = 30 + 10(1.5a₂) + 5a₂
24 = 30 + 15a₂ + 5a₂
24 = 30 + 20a₂
Collect like terms
24 - 30 = 20a₂
-6 = 20a₂
Divide both sides by 20
a₂ = -6 / 20
= -0.3 m/s²
Substituting the value of a₂ into equation 3, we have
a₁ = 1.5a₂
= 1.5 × -0.3
= -0.45 m/s²
Substitute the value of a₁ into equation 1 to obtain the velocity, v₁ at the end of the initial to 10 s
v₁ = 30 + 10a₁
= 30 + (10 × -0.45)
= 30 - 4.5
= 25.5 m/s
Thus, velocity of the car at the end of the initial ten-second interval is 25.5 m/s
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what is the output voltage of a transformer if the input is 240volts, and the number of turns on the primary coil is 1200 and on the secondary coil is 200.
The output voltage of a transformer is 40V.
What is an output voltage?An output voltage is the voltage released by a device, such as a voltage regulator or a generator.
The formula to calculate Output voltage of transformer is:
[tex]\frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }[/tex]
here, [tex]V_{s}[/tex] is the secondary voltage, [tex]V_{p}[/tex] is the primary voltage, [tex]N_{s}[/tex] is the number of secondary windings and [tex]N_{p}[/tex] is the number of primary windings.
According to the question.
[tex]N_{p}[/tex] =1200 , [tex]N_{s}[/tex]=200 , [tex]V_{p}[/tex]=240V ,[tex]V_{s}[/tex]= ?
By using the formula of Output voltage,
[tex]{V_{s} } = \frac{V_{p}N_{s} }{N_{p} }[/tex]
=[tex]\frac{240*200}{1200}[/tex]
[tex]=40V[/tex]
Therefore, 40V is the output voltage of a transformer.
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What’s the allowable ampacity of a No. 12 copper wire with type THHN insulation installed in a raceway with 35 wires? Question 3 options: A) 10 A B) 15 A C) 8 A D) 12 A
The allowable ampacity of a No. 12 copper wire with type THHN insulation installed in a raceway with 35 wires is approximately 12 amperes. This is best represented by option D.
According to the National Electrical Code Table (NEC), a derating factor must be applied for any raceway with more than three current-carrying conductors (in our case, copper wires). In a raceway with 31-40 current-carrying conductors, the derating factor is 50%. Because the ampacity of a No. 12 copper wire usually is 25 amperes (A), we can multiply this by our derating factor to find that:
25 • 0.50 = 12.5
The exact allowable ampacity of this copper wire is 12.5 amperes; however, we can round down to find that the closest answer is 12 A.
Hence, option D represents the best answer.
Answer:
D) 12 A
Explanation:
You want to know the allowable ampacity of AWG 12 type THHN copper wire in a raceway with 35 wires.
Nominal ampacityTable 310.15(B)(16) of the 2017 National Electrical Code gives the nominal rating of AWG 12 type THHN copper wire as 30 A when installed in an environment with a temperature of 30 °C or less.
DeratingTable 310.15(B)(3)(a) gives the adjustment factor when there are more than three conductors in a raceway or cable. For 31–40 conductors, the ampacity must be derated to 40% of its nominal value.
In a raceway with 35 wires, the allowable ampacity of THHN AWG 12 wire is ...
(30 A)(0.40) = 12 A
__
Additional comment
For environmental temperatures above 30 °C, Table 310.15(B)(2)(a) gives additional derating factors. The adjustment factor for temperatures up to 50 °C (122 °F) is 0.82, which would bring the allowable ampacity down to about 9.8 A.
Need help with this question
Answer:
1. 92, 138, 92
2. 7, 7, 7
3. 17, 18, 17
4. 29, 34, 29
Explanation:
the number on the bottom is always going to be the atomic number, or the number of protons.
the number on the top is going to be the atomic mass number, which is the sum of the number of protons and neutrons.
there is always going to be the same number of electrons as protons, because that was the overall charge of each atom is 0.
for example, for the first one:
there are 92 protons
there are 230 - 92 = 138 neutrons
there are 92 electrons
A car moves with the speed of 40km/hr for the first half distance and 60km/hr for second half distance.find average speed of car?
Answer:
50km/h
Explanation:
average = (a + b) / 2
average = (60 + 40) / 2
average = 50
Bianca is helping the theatre director at her school with lighting, sound, and set design for a school play. She will be choosing the materials that will be used on stage and on the walls of the theatre. After she reads the script and makes observations inside the theatre, she makes the following list of the factors to consider in her design.
The echoes throughout the theatre need to be reduced.
The set should not reflect too much light into the audience’s eyes.
The only lights available are white, purple, and yellow. The filters available are red and blue.
The blue sky on the set should appear black for Act 2.
Bianca draws a detailed illustration of her plan to show the theatre director. She labels it with the materials she plans to use.
Design Solutions: Based on Bianca’s criteria and model, which materials would you change on stage? Explain your reasoning
Bianca is helping the theatre director at her school with lighting, sound, and set design for a school play. She will be choosing the materials that will be used on stage and on the walls of the theatre the materilas neee to be changes is The only lights available are white, purple, and yellow.
What is echo ?A proper echo is a single mirrored image of the sound source. The phrase echo derives from the Greek ἠχώ (ēchō), itself from ἦχος (ēchos), "sound". Echo withinside the Greek peoples tale is a mountain nymph whose cappotential to talk changed into cursed, leaving her capin a position handiest to copy the ultimate phrases spoken to her.
Bianca draws a detailed illustration of her plan to show the theatre director. She labels it with the materials she plans to use the only lights available are white, purple, and yellow should be removed as to avoid the light refraction.
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A boat moves with a velocity of 15m/s, N in a river which flows with a velocity of 8.0m/s, Calculate the boat’s resultant velocity with respect to North
The boat’s resultant velocity with respect to North is determined as 17 m/s.
Resultant velocity of the boatThe boat’s resultant velocity with respect to North is calculated as follows;
R² = Va² + Vb²
where;
R is resultant velocityVa is velocity of boatVb is velocity of riverR = √(Va² + Vb²)
R = √(15² + 8²)
R = 17 m/s
Thus, the boat’s resultant velocity with respect to North is determined as 17 m/s.
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the 3kg object in figure is released from rest at height of on a curved frictionless ramp. at the foot of the ramp is a spring of force constant 400N/m. the object slides down the ramp and into the spring,compressing it a distance x before coming momentarily to rest.
a) find x
b) describe the motion of the object (if any) after the block momentarily comes to rest?
(a) The compression of the spring is 7.4 cm.
(b) When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
Compression of the spring [ x ]
The compression of the spring is calculated by applying Hooke's law as follows;
F = kx
x = F/k
x = (mg)/k
x = (3 x 9.8)/400
x = 0.074 m
x = 7.4 cm
When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
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How much work does a football player do in the weight room when he squats 150 kg up a distance of 1 meter?
How much work does he do if he does 3 sets of 10 squats in a row?
Answer:
See below
Explanation:
The work done equals the increase in Potential Energy
PE = mgh
= 150 * 9.81 * 1 = 1471.5 j
3 sets of 10 is 30 times this = 44145 j
The amount of work done by a football player in the weight room when he squats 150 kg will be equal to 1471.5 J.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship among different components. When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the floor as opposed to falling to the ground, it has more potential energy. It is capable of carrying out additional work when raised.
Potential energy is a feature of systems rather than of particular bodies or particles; for instance, the system created up of Earth and the elevated ball has more energy stored as they become further apart.
Potential energy develops in systems components whose configurations, or spatial arrangement, determine the amount of the forces they apply to one another.
As per the instructions given in the question,
Work performed is equivalent to Potential Energy Increase,
PE = mgh
= 150 × 9.81 × 1
PE = 1471.5 J
Also,
3 sets of 10 are 30 times this = 44145 J
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the following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
(a) The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 10 m/s.
(b) The velocity and acceleration at any time t is v = (2ati + bj) m/s and a = 2ai m/s²
(c) The average acceleration in the time interval given in part (a) is 4 m/s².
Position of the particlex = at²i + btj
x = 2t²i + tj
Average velocity, at t₁=2sec and t₂=3secΔv = Δx/Δt
x(2) = 2(2)²i + 2j
x(2) = 8i + 2j
|x(2)| = √(8² + 2²) = 8.246
x(3) = 2(3)²i + 3j
x(3) = 18i + 3j
|x(3)| = √(18² + 3²) = 18.248
Δv = (18.248 - 8.246)/(3 - 2)
Δv = 10 m/s
Velocity and acceleration at any time, tx = at²i + btj
v = dx/dt
v = (2ati + bj) m/s
a = dv/dt
a = 2ai m/s²
Average accelerationa = 2ai m/s²
a = 2(2)(1)
a = 4 m/s²
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the question in photo
Answer:
a
Explanation:
Suppose astronomers find an earth-like planet that is twice the size of Earth. What must be the mass of this planet such that the gravitational force at the surface would be identical to Earth’s?
This planet's mass must be four times that of Earth in order for the gravitational pull at its surface to be comparable to Earth's.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
The planet's mass is directly related to its mass at the surface and inversely proportional to the square of its radius;
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
The astronomers discovered a planet twice the size of Earth that resembles Earth.
This planet's mass must be four times that of Earth in order for the gravitational pull at its surface to be comparable to Earth's.
Hence the masses of this planet will be 4 times that of Earth.
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What is the wavelength of a compression wave with a speed of 500 m/s and a frequency of 250 Hz?
Use this formula: λ = s/f
Select one:
a. 2 m
b. 1.25 m
c. 250 m
d. 750 m
Answer:
a (2m)
Explanation:
according to wavelenght = speed / frequency,
the wavelength is 2 m
During World War II, it was found that r, the radius of the shockwave produced during an atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density, .
The atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.
What is an atomic bomb?An atomic bomb is type of nuclear weapon that releases a vast amount of energy upon explosion in the form of fission reaction.
During an explosion of atomic bomb, a cloud of mushroom fire is formed which vaporises anything found within it. The extent of destruction depends on:
energy released, W, the elapsed time, t, and the air density.Therefore, the atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.
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A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.
The acceleration of this sled can be calculated by doing: option A, B, E and F.
How to calculate the acceleration?The acceleration of this sled can be calculated by using Newton's Second law of motion. Mathematically, the acceleration of an object is given by this formula:
Net force = Mass × acceleration
Deductively, the acceleration of this sled can be calculated by doing the following:
The force of gravity must be broken into its parallel and perpendicular components.Acceleration can be found by dividing the net force by mass.Trigonometry can be used to solve for the magnitude of the force components.Net force must be found before acceleration can be found.Read more on acceleration here: brainly.com/question/14344386
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Complete Question:
A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.
A. The force of gravity must be broken into its parallel and perpendicular components.
B. Acceleration can be found by dividing the net force by mass.
C. Acceleration can be found by multiplying the net force by mass.
D. The magnitude of the force components must be multiplied by gravity.
E. Trigonometry can be used to solve for the magnitude of the force components.
F. Net force must be found before acceleration can be found.
Answer:
To find the acceleration, you do 20N/50kg = 0.4 m/s^2
Explanation:
example: a = F/m = 10/2 = 5 m/s2
A house has a roof (colored gray) with the dimensions shown in the drawing. Determine the magnitude of the net force that the
atmosphere applies to the roof when the outside pressure drops suddenly by 13.2 mm of mercury, before the pressure in the attic can
adjust.
The magnitude of the net force that the atmosphere applies to the roof when the outside pressure drops suddenly is 1.9 x 10⁵ N.
What is pressure?The pressure is the amount of force applied per unit area.
Pressure p = Force/Area
Given is a house has a roof (colored gray) with the dimensions shown in the drawing. The outside pressure drops suddenly by 13.2 mm of mercury, before the pressure in the attic can adjust.
The pressure difference ΔP = 13.2 mm of Hg
The length of the roof l = 14.5m
the breadth of the roof h = 4.21m
The force exerted by pressure is
Force, F = P x A
= (13.2 mm of Hg) [(133 N/m²) /1 mm of Hg ](14.5 x 4.21)
= 107,170.6 N
Then the net vertical force
Fnet = 2F cos30
Fnet = 2 ( 107,170.6) cos30
Fnet = 185625 N
Fnet =1.9 x 10⁵ N
The direction of the force is downwards, since the horizontal components of the forces cancel each other.
Hence, magnitude of the net force is 1.9 x 10⁵ N
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A car and a truck, starting from rest, have the same acceleration, but the truck moves twice the length of time. Compared with the car, the truck will travel
Compared with the car, the truck will travel four times as far.
The initial velocity of car and truck, u = 0
The acceleration of both the truck and car = a
The length of time for the acceleration = t
Let the time the truck accelerated be 2t
How to calculate the distance traveled by car and truck?The distance traveled by car is calculated as;
s = ut + ¹/₂at²
s₁ = 0(t) + ¹/₂at²
s₁ = ¹/₂at²
The distance traveled by truck
s = ut + ¹/₂at²
s₂ = 0(2t) + ¹/₂a (2t)²
s₂ = ¹/₂a x 4t²
s₂ = 4 (¹/₂at²)
s₂ = 4(s₁)
We can conclude that the Truck distance is four times the car distance.
Therefore, Compared with the car, the truck will travel four times as far.
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The following table contains financial information for Trumpter Inc. before closing entries:
Cash
Supplies
Prepaid Rent
Salaries Expense
Equipment
Service Revenue
Miscellaneous Expenses
Dividends
Accounts Payable
Common Stock
Retained Earnings
$13,100
6,000
3,800
5,000
65,900
28,000
20,100
4,000
3,100
66,100
20,700
What is the amount of Trumpter's total assets?
The Total assets based on the given table is $88,800.
What are assets?An asset refers to a resource owned by an individual or company which has tangible value and whose value is expected to rise in the future.
The Total assets based on the table = Cash + Supplies + Prepaid rent + Equipment
Total assets = 13,100 + 6,000 + 3,800 + 65,900
Total assets = $88,800
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What does Charles Darwin’s theory of natural selection state about traits?
A.
Traits that increase the survival rate of a population are rarely passed on to future generations since they can affect reproduction.
B.
Traits that prevent people from reproducing are passed on to future generations to ensure their survival.
C.
Traits that make it more likely for a species to survive or reproduce become less common in a population over time.
D.
Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations.
Charles Darwin's theory of natural selection states that features that offer survival or reproductive advantage are more likely to be handed down to subsequent generations.
What are traits?A trait is a distinctive pattern of behavior or conscious motivation that may be evaluated by peers or oneself.
Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations is Charles Darwin’s theory of natural selection state traits.
Hence option D is correct.
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Answer: option d
Explanation:
If a jet is travelling horizontally at 100m/s at a height of 500m above the ground and a jet drops a bomb to the ground. Where does the bomb strike the ground relative to the point atwhich it is released ?A.100m B.1km C.500m D.5km
The bomb strike the ground relative to the point at 1km . B
How to determine the distanceUsing the equation
h = 1/2 gt^2
500 = 1/2 * 10* t^2
500 = 5t^2
t = √500/5
t = √100
t = 10seconds
To find the distance,
Distance = velocity * time
Distance = 100 ÷ 10
Distance = 1000m = 1km
Therefore, the bomb strike the ground relative to the point at 1km . B
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If the Moon had twice as much mass and still orbits Earth at the same distance, ocean bulges on Earth would be
smaller.
larger.
unequal in size.
not significantly different.
none of the available options
Ocean bulges on Earth would be bigger if the Moon had twice as much mass and yet orbited the planet at the same distance. Option B is correct.
What is ocean bludge?The fluid and moveable ocean water are drawn towards the moon by the gravitational attraction between the moon and the Earth.
The ocean nearest to the moon experiences a bulge as a result, and as the Earth rotates, the affected seas' locations shift.
The Moon's bulges in the oceans would be larger if it had twice the mass and orbited Earth at the same distance.
Hence option B is corect.
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A railroad cart with a mass of m1 = 11.6 t is at rest at the top of an h = 10.9 m high hump yard hill.
After it is pushed very slowly over the edge, it starts to roll down. At the bottom it hits another cart originally at rest with a mass of m2 = 23.2 t. The bumper mechanism locks the two carts together. What is the final common speed of the two carts? (Neglect losses due to rolling friction of the carts. The letter t stands for metric ton in the SI system.)
The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.
What is the law of conservation of momentum?According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
Unit conversion:
1 metric tons = 1000 kg
Given data;
m₁= 11.6 metric ton =11600 kg
m₂ = 23.2 metric ton = 23200 kg
Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.
Considering energy conservation;
[tex]\rm m_1 g h = \frac{1}{2} m_1 \times u^2 \\\\ u^2 = 2gh\\\\ u^2 = 2 \times 9.8 \times 10.6 \\\\ u = 207.972 \ m/s[/tex]
From the conservation of momentum principle;
[tex]\rm m_1 \times u = (m_1 + m_2) v\\\\ 11600 \times 207.972 = (11600 + 23200) \times v \\\\ v = 69.3 \ m/s[/tex]
Hence, the final common speed of the two carts will be 69.3 m/sec.
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A small sphere of mass 10 kg
is released from rest at a height of
15.0 m above the ground level.
The sphere experiences a constant
resistive force (due to air
resistance) of magnitude R = 10.0
N.
a) Calculate the speed of the
sphere after it has fallen
through a distance of 5.00 m
bCalculate the speed of the ball just before a it hits the gound.
Answer:
Approximately [tex]9.39 \; {\rm m\cdot s^{-1}}[/tex] after the sphere has travelled a distance of [tex]5\; {\rm m}[/tex].
Approximately [tex]16.3\; {\rm m\cdot s^{-1}}[/tex] right before touching the ground (a distance of [tex]15\; {\rm m}[/tex].)
Assumption: [tex]g = 9.81\; {\rm N\cdot kg^{-1}}[/tex].
Explanation:
Weight of the sphere: [tex]m\, g = 9.81\; {\rm N \cdot kg^{-1}} \times 10\; {\rm kg} = 98.1\; {\rm N}[/tex], downwards.
Drag on the sphere: [tex]10.0\; {\rm N}[/tex] upwards.
Net force on the sphere: [tex]98.1\; {\rm N} - 10\; {\rm N} = 88.1\; {\rm N}[/tex] downwards.
Acceleration of the sphere: [tex]a = F_\text{net} / m = 88.1\; {\rm N} / (10\; {\rm kg}) = 8.81\; {\rm m\cdot s^{-2}}[/tex].
Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex], where [tex]v[/tex] is the final velocity, [tex]u[/tex] is the initial velocity ([tex]0[/tex] in this case, as the sphere was released from rest,) and [tex]x[/tex] is the distance (displacement) that the sphere has travelled so far.
Rearrange this equation to obtain an expression for [tex]v[/tex]:
[tex]\displaystyle v = \sqrt{2\, a\, x + u^{2}}[/tex].
For example, after the ball travelled a distance of [tex]5.00\; {\rm m}[/tex], [tex]x = 5.00 \; {\rm m}[/tex]:
[tex]\begin{aligned} v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 8.81\; {\rm m\cdot s^{-2}} \times 5.0\; {\rm m} + 0} \\ &\approx 9.39\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
Similarly, [tex]x = 15.0\; {\rm m}[/tex] right before landing, such that:
[tex]\begin{aligned} v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 8.81\; {\rm m\cdot s^{-2}} \times 15.0\; {\rm m} + 0} \\ &\approx 16.3\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
What is the weight of a 0.145kg baseball on the moon if the gravitational acceleration on the moon is approximately 1.625 m/s2
Answer:I would say that it would be about 2/3rds as fast as the moon and i have seen a similar question but it asked different info about it. I also believe that the basketball would have a lower weight due to it being in space. I feel bad saying this but i know that i got some info off this website when working with this and i hope it helps.
Explanation:
Note- I am new to Brainly so sorry if this isn't as helpful as you expected this to be.
Velocity (m/s)
50
40
30
20
10
0
A
Velocity vs Time
B
C
1 2 3 4 5 6 7 8 9 10
Time (s)
Use the information presented in the graph to answer
the questions.
Which segments show acceleration?
Which segment indicates that the object is slowing
down?
What is the velocity of segment B?
What is the acceleration of segment B?
Explanation:
⠀
⠀
(a) The segment A shows acceleration as velocity increases with the increase in time.
⠀
⠀
⠀
(b) The segment C shows the object is slowing down as the time increases in segment C, the velocity decreases and afterwards it comes to rest.
⠀
⠀
⠀
(c) The velocity is segment B is 40m/s. And in the diagram there is no change in velocity.
⠀
⠀
⠀
(d) The acceleration of segment B is zero. As there in no change in curve and it is moving with uniform velocity.
⠀
⠀
⠀
[tex] \: [/tex]
Thank you!Answer:
1 A and C
2 C
3 40m/s
4 zero
Explanation:
A skier is standing on a horizontal patch of snow. She is holding onto a horizontal tow rope, which is about to pull her forward. The skier’s mass is 59 kg, and the coefficient of static friction between the skies and the snow is 0.14. What is the magnitude of the maximum force that the tow rope can apply to the skier without causing her to move?
The magnitude of the maximum force that the tow rope can apply to the skier without causing her to move will be 81.03 N,
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
It is defined as the product of the coefficient of friction and normal reaction.
On resolving the given force and acceleration. Mathematically aion in the different components and balancing the equation gets. Components in the x-direction.
The normal force is balanced by weight;
N = mg
The magnitude of the maximum force that the tow rope can apply to the skier without causing her to move is;
F = μN
F= μmg
F=0.14 × 59 kg × 9.81 m/s²
F = 81.03 N
Hence, the magnitude of the maximum force will be 81.03 N,
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A force of looN acts upwards on a mass of 50 kg, another of
80N acts on the Same Mass downwards. Calculate the acceleration?
of the body and in which direction will be th acceleration?
Answer:
a force of acts on a body of mass 50 kg for 10 sec when the first of acting on the body the body covers 80 and in the next 10 second
Answer:
a = 0.4 ms⁻²
Explanation:
• First calculate the resultant force on the body:
If we consider upwards to be the positive direction and downwards to be the negative direction, then the resultant force will be:
F = +100 + (-80)
= +20 N
The resultant force is positive, so it will act upwards.
• Next calculate the acceleration:
F = ma
a = F/m
a = 20/ 50
a = 0.4 ms⁻²
As the force is acting upwards, the acceleration will also be upwards.
11. Trait theory claims that
O A. people from the same locations
share the same personality type.
B. you always behave the way your
personality type says you will.
O C. your personality is made up of a
number of traits.
O D. you have one characteristic that
defines your entire personality.
An upward force is applied to a 6.0–kilogram box. This force displaces the box upward by 10.00 meters. What is the work done by the force on the box?
Answer:
588J
Explanation:
Work done = Fd
=wh=mgh
=6×9.8×10
=558J
A room has a 60 Watt, a 100 Watt and a 150 Watt light bulb. How much does it
cost to use all the lamps for 2.5 hours at $0.08/ kWh?
The cost to use all lamps is $62.
room has 60 watts, 100 watts, and 150 watt light bulbs.Duration of using bulbs=2.5 hours power =$0.08kWh
power=energy/time
(60+ 100+150)=energy/2.5
energy=775 joule
cost for 1 hour=$0.08
= 775 * 0.08
= $62
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Answer:
6.2 cents
Explanation:
(60+100+150/1000)*2.5*8=6.2 cents
What is speed?
What is the difference between speed and velocity?
What could an object be doing if it is accelerating ?
What is inertia . Give an example.
What are some common forces in action ? Explain.
What are balanced forces ? Explain.
What is the relationship between work and power ?
Speed can be defined as the change in distance with respect to time.
The speed is the change in distance with the time and velocity is the change in displacement with the time. Speed is a scalar quantity having magnitude only and Velocity is a vector quantity having magnitude as well as direction.
If the velocity of the object is changing, it shows that the object is accelerating.
Inertia is a resistance of an object to resist a change in its state of motion or of rest. If a ball is rolled, it will continue rolling unless friction or something else stops it by force.
Some common forces are gravitational forces, electric forces, magnetic forces, nuclear forces, etc. Gravitational forces act between the earth and the object, it is an attraction force. Similarly, there is an electric force, which acts between the two charges, it can be attractive or repulsive.
The forces that are opposite in direction and equal in size, are known as balanced forces. This can be explained as forces acting horizontal, and the forces are balanced, so the left-sided forces and right-sided forces must be equal.
Power can be defined as the measure of the amount of work that can be done in a given amount of time. Power is work done per unit time.
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