A certain number has exactly 8 factors, including 1 and itself. If two of these factors are 21 and 35, what is the number?

Answer:

f(g(x)) = 2x² + 4

Step-by-step explanation:

to evaluate f(g(x)) substitute x = g(x) into f(x) , that is

f(g(x))

= f(10x² + 5)

= [tex]\frac{10x^2+5}{5}[/tex] + 3

= [tex]\frac{10x^2}{5}[/tex] + [tex]\frac{5}{5}[/tex] + 3

= 2x² + 1 + 3

= 2x² + 4

11 00 11 00 = 204

nice :)

The equivalent expression for [tex][(\frac{5}{7}) ^{2}*(\frac{1}{3} )^{-3} ] ^{-1}[/tex] is [tex](\frac{7}{5}) ^{2}*(\frac{1}{3} )^{3}[/tex] (option D)

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value(s) for the variable(s).

Given: [tex][(\frac{5}{7}) ^{2}*(\frac{1}{3} )^{-3} ] ^{-1}[/tex] is the expession.

Now, multiplying (-1) power within the brackets,

=[tex](\frac{5}{7}) ^{-2}*(\frac{1}{3} )^{3}[/tex]

If power is in negative, fraction can be reciprocated to make the power positive. So,

=[tex](\frac{7}{5}) ^{2}*(\frac{1}{3} )^{3}[/tex]

Option D

Hence, the equivalent expression for [tex][(\frac{5}{7}) ^{2}*(\frac{1}{3} )^{-3} ] ^{-1}[/tex] can be written as [tex](\frac{7}{5}) ^{2}*(\frac{1}{3} )^{3}[/tex].

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Answer:x=1.

Step-by-step explanation:

3x-x+2=4

Infinitely many others are possible.

=================================================

Explanation:

Replace x with 0 and simplify to get...

y = 3x-5

y = 3(0)-5

y = 0-5

y = -5

When x = 0, it leads to y = -5

One ordered pair is (x,y) = (0, -5)

Let's repeat those steps for x = 1

y = 3x-5

y = 3(1)-5

y = 3-5

y = -2

Another ordered pair is (1, -2)

As you can see, we can pick anything we want for x to get some paired y output. There are infinitely many x values to pick from. This means there are infinitely many ordered pairs for (x,y).

When it comes to graphing, you only need two points at minimum to form a straight line.

Answer:

y+8=1/6(x+9)

Step-by-step explanation:

point slope: y - y1 = m ( x - x1 )

use the point and the slope and plug in the values in the point slope equation

Answer:

J and I

Step-by-step explanation:

If possible use a graphing calculator this is from Desmos

If you are not allowed to then use the rise over run rule or Rise/run

if the constants or numbers Infront of x match then the lines are parallel for these kinds of lines. The black line was added to show that it is parallel with the same constant

The estimated result of 219 ÷ 15, by first rounding each number and then dividing, we get the result as 11.

We are given the expression:

219 ÷ 15

We need to estimate the result by first rounding off the digits to nearest tens and then performing division to get the answer.

So, we will first do the round off.

219 will be rounded off to 220

15 will be rounded off to 20

So, the expression will become:

220 ÷ 20

So, now performing the division, we get that:

= 11

Therefore, the estimated result of 219 ÷ 15, by first rounding each number and then dividing, we get the result as 11.

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Answer:

The domain of this function is (in order of least to greatest) is [-2,-1,0,3.5,4,5.5, and 8]

The range of this function is (in order from greatest to least) is [6,5.5,4,0,-1, and -3.5]

Step-by-step explanation:

To find the domain you need to look at all of you input or x values so the question is asking to name the values of x for your domain. You look at the table to where x is and name the numbers listed in this case it's [-2,-1,0,3.5,4,5.5, and 7]

To find the range you need to look at the listed outputs or y values. You are essentially doing the same steps but instead you looking at y for the listed values. Generally when it comes to domains that have the same range (for example (4,-1) and (5.5,-1)) you would only write it once in the list of ranges so like [6,5.5,4,0,-1, and -3.5]

[tex]\begin{array}{ccll} US\$&CA\$\\ \cline{1-2} 0.77 & 1\\ 200& c \end{array} \implies \cfrac{0.77}{200}~~=~~\cfrac{1}{c} \\\\\\ 0.77c=200\implies c=\cfrac{200}{0.77}\implies c\approx 259.74[/tex]

From pie chart, responses of community for each category is

a. One fourth of community chosen by cat category.

b. Approximately 30% of community chosen cat or other.

c. If 6% chosen None then dog was chosen by approximately 18%.

As given,

From pie chart ,responses of community for each category is

Bird>cat>dog>fish>none>other

Fish+ none +other +cat=Approximately 50%

a. Cat chosen by approximately 25%.

b. Cat or Other= Approximately 30%

c. If 6% chosen None then dog

    Approximately three times of none=6×3

                                                               = 18%.

Therefore, from pie chart

a. One fourth of community chosen by cat category.

b. Approximately 30% of community chosen cat or other.

c. If 6% chosen None then dog was chosen by approximately 18%.

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Answer:

What are the options I can choose from?

Step-by-step explanation:

Answer:

Step-by-step explanation:

The domain of the function is [-3,5]

The range of the function is [-16,infinity)

X=3 is a zero of the function

X = -3 is a zero of the function  

Answer: 80 degrees ==> 3rd option

Step-by-step explanation:

m<5=m<2   ==> angles 5 and 2 are opposite interior angles, so they're congruent.

m<2=38 degrees

m<2+m<6+m<3=180 degrees

38+62+m<3=180

100+m<3=180

m<3=80 degrees ==> 3rd option

4 and 3.14 are the constant of proportionality .

What does the arithmetic word proportional mean?

2×4 = 8

2×3.14=6.28

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The probability that a club member owns neither a house nor a car is 0.08 or 8%.

As per the survey of a club's members-

percentage of members who own a home 40% = 0.4

percentage of members who own a car → 90% = 0.9

Further, 95% of the homeowners also own a car

⇒ percentage of members who own a car as well as a home = 95% of 40%

= 95/100 x 40/100

= 3800/10000

= 0.38

Let P(A) be the probability that a member owns a home and P(B) be the probability that a member owns a car

we have,

P(A) = 0.4

P(B) = 0.9

also P(A∩B) = 0.38

we need to find the probability that a club member owns neither a house nor a car, that is, P(A'∩B')

According to the rules of probability-

P(AUB) = P(A) + P(B) - P(ANB)

⇒ P(AUB) = 0.4 +0.9 -0.38

P(AUB) = 0.92

Thus, P(A'U B') = 1 - 0.92

= 0.08

Thus, the probability that a club member owns neither a house nor a car is 0.08 or 8%.

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Answer:

20 dollars

Step-by-step explanation:

Because there is 3 people according to where it said the amount of names there are and they each had to pay 6 dollars. 6 x 3 is 18. That is the price after discount. The coupon is 2 dollars so 18 + 2 is 20 dollars. That is the final price.

Answer:

f(n) = 59,000(1.08m - 1)

Step-by-step explanation:

Answer:

its the first one

146 r 6

hope this helped! :)

Answer:

False. If a factor of the denominator of a rational function cancels with a factor of the numerator, the zero of the canceled factor should not be included in the solution for the inequality.

Step-by-step explanation:

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A. The grams of rice served for 64 portion is 8960 grams.

B. The expression for the total weight in grams of rice needed for p portions is  140p.

C. The portion when a total weight of 11340 grams was served is 81 portion

D. The expression  for the number of portions served if the total rice weighed t grams is t / 140

The school cafeteria serves portions of fried rice that are 140 grams each.

A.

64 portions of rice are served. The grams of rice served is as follows:

1 portion = 140 grams

64 portions = ?

cross multiply

grams of rice served = 64 × 140

grams of rice served = 8960 grams

B.

The expression for the total weight in grams of rice needed for p portions is as follows:

total weight = 140p

C.

The portion when a total weight of 11340 grams was served is as follows:

140 grams = 1 portion

11340 grams = ?

portion = 11340 / 140

portion = 81 portion

D.

The expression  for the number of portions served if the total rice weighed t grams is as follows:

portion = t / 140

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The equation has infinite solutions.

The value of x that makes the equation true is: 2. After substitution, we would have: 8 = 8

Another value of x that makes the equation true is: 3. After substitution, we would have: 10 = 10

If an equation has infinite solutions, it means that any value of the variable in the equation would make the equation true.

Given the equation, 2(x + 2) = 2x + 4, the value of x that makes the equation true is: 2.

Substitute x = 2 into the equation and simplify it would make both sides equal:

2(2 + 2) = 2(2) + 4

8 = 8

Another value of x that makes the equation true is: 3.

Substitute x = 3 into the equation and simplify it would make both sides equal:

2(3 + 2) = 2(3) + 4

10 = 10

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Answer:

-4×(2×1)=8x-2-4

solve in ( )

-4×3=8x-2-4

multiply -4 to 3

-12=8x-2-4

add 2 and 4 to both sides

-6=8x

divide -6 to 8 and you will get the answer

x=-0.75

Answer:

x = -0.25 (or) -1/4

Step-by-step explanation:

Let's solve the problem,

→ -4 × (2 × 1) = 8x - 2 - 4

→ -4 × 2 = 8x - 6

→ -8 = 8x - 6

→ 8x = -8 + 6

→ x = -2/8

→ [ x = -0.25 ]

Thus, solution is -0.25.

Use the definition of absolute value to rewrite each equation or inequality.

[tex]|x| = \begin{cases} x & \text{if } x\ge0 \\ -x & \text{if }x < 0 \end{cases}[/tex]

1. (E) From the definition it follows that

[tex]x-4 \ge 0 \implies |x-4| = x-4 = 8 \implies x = 12[/tex]

[tex]x-4 < 0 \implies |x-4| = -(x-4) = 4-x = 8 \implies x = -4[/tex]

Then the solution set contains exactly 2 elements, and we write it as shown in choice (E), [tex]x\in\{-4,12\}[/tex].

2. (D) We solve the inequality in essentially the same way as in (1), we just need to keep track of the direction of the inequality.

[tex]x-4\ge0 \implies|x-4|=x-4\ge8 \implies x\ge12[/tex]

[tex]x-4<0 \implies|x-4|=4-x\ge8 \implies x\le-4[/tex]

Note the inclusion of [tex]x=12[/tex] and [tex]x=-4[/tex]. We write this as a union of two half-closed intervals, [tex]x\in(-\infty,-4]\cup[12,\infty)[/tex].

3. (C) This follows from the same steps as in (2). This time the inequality is strict, so we exclude the endpoints and with open intervals write [tex]x\in(-\infty,4)\cup(12,\infty)[/tex].

4. (A) Since [tex]|x|[/tex] always returns a non-negative number, any real number [tex]x[/tex] satisfies the inequalty [tex]|x-4|<\infty[/tex]. We write the solution set as the entire real line, [tex]x\in(-\infty,\infty)[/tex].

5. This leaves us with (B) for the last solution set. This inequality is complementary to the one in (3), which means the solution set to [tex]|x-4|\le8[/tex] is the complement of the set we found in (3). That interval removes everything between and including -4 and 12 from the real line. So the solution in this case is what we omit from the solution to (3), and we write [tex]x\in[-4,12][/tex].

Answer: A quarter turn

Step-by-step explanation:

The value of 8+3e when e=2 will be 14.

It should be noted that the equation or expression is given as:

8 + 3e

Therefore, we will put the value of E as 2 int the equation. This will be:

8 + 3e

= 8 + 3(2)

= 8 + 6

= 14

The value is 14.

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Answer:

.06%

Step-by-step explanation:

multiply the number by 100 to get it as a percentage

Answer:

0.0006 = 0.06%

Hope this helps :)

Hope this helps :)Explanation below.

Step-by-step explanation:

To convert a decimal to a percent, move the decimal 2 times to the right.

0.0006 = 0.06%

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