A constant electric field with magnitude 1.50 ✕ 103 N/C is pointing in the positive x-direction. An electron is fired from x = −0.0200 m in the same direction as the electric field. The electron's speed has fallen by half when it reaches x = 0.190 m, a change in potential energy of 5.04 ✕ 10−17 J. The electron continues to x = −0.210 m within the constant electric field. If there's a change in potential energy of −9.60 ✕ 10−17 J as it goes from x = 0.190 m to x = −0.210 m, find the electron's speed (in m/s) at x = −0.210 m.

Answer:

5.68 meters

Explanation:

hope this helps!

Answer:

5.68

Explanation:

to convert cm to m you  move the decimal point 2x to the left

Answer:

1.6 secs

Explanation:

In a circus act, an acrobat upwards from the surface of a trampoline

At that same moment another acrobat perched 9.0m above him

A ball is released from rest

While still in motion the acrobat catches the ball

He left the ball with a trampoline of 5.6m/s

Since the ball is falling downwards from a distance then acceleration will be negative

a= -9.8

s= d

s= 1/2at^2

= 1/2 × (-9.8)t^2

= 0.5× (-9.8)t^2

d = -4.9t^2

Therefore the time the acrobat stays in the air before catching the ball can be calculated as follows

9 - 4.9t^2= 5.6t + 1/2(-9.8)t^2

9 - 4.9t^2= 5.6t + (-4.9)t^2

9 - 4.9t^2= 5.6t - 4.9t^2

9= 5.6t

t= 9/5.6

t= 1.6 secs

Answer:

a) 105935.7 Pa

b) 103630.35 Pa

Explanation:

The volume of the container = 0.025 m^3

The radius of the container = 13 cm = 0.13 m

We have to find the height of the tank

From the equation for finding the volume of the cylinder,

V = [tex]\pi r^2h[/tex]

where

V is the volume of the cylinder

h is the height of the cylinder

substituting values, we have

0.025 = 3.142 x [tex]0.13^2[/tex] x h

0.025 = 0.0531h

h = 0.025/0.0531 = 0.47 m

Pressure at the bottom of the tank P = ρgh

where

ρ is the density of water = 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

h is the depth of water which is equal to the height of the tank

substituting values, we have

P = 1000 x 9.81 x 0.47 = 4610.7 Pa

atmospheric pressure = 101325 Pa

therefore, the pressure in the tank bottom above atmospheric pressure = 101325 Pa + 4610.7 Pa = 105935.7 Pa

b) For half way down the container, depth of water will be = 0.47/2 = 0.235 m

pressure P = 1000 x 9.81 x 0.235 = 2305.35 Pa

This pressure above atmospheric pressure = 101325 Pa + 2305.35 Pa = 103630.35 Pa

(a) The pressure exerted by water on the sides of the container at the bottom is 4606 Pa.

(b) The pressure exerted by water on the sides of the container halfway down from the top is of 2303 Pa.

Given data:

The volume of cylindrical container is, [tex]V = 0.025 \;\rm m^{3}[/tex].

The radius of container is, r = 13 cm = 0.13 m.

(a)

When the container is full, the pressure that the water exerts on the sides of the container is given as,

[tex]P = \rho gh[/tex]

Here, [tex]\rho[/tex]  is the density of water, g is the gravitational acceleration and h is the height of container and its value is obtained as,

[tex]V = \pi r^{2}h\\\\0.025= \pi \times (0.13)^{2} \times h\\\\h = 0.47 \;\rm m[/tex]

Then pressure is,

[tex]P = 1000 \times 9.8 \times 0.47\\\\P=4606 \;\rm Pa[/tex]

Thus, the pressure exerted by water on the sides of the container at the bottom is 4606 Pa.

(b)

For the ides of the container halfway down from the top, the height is,

h' = h/2

h' = 0.47/2 = 0.235 m

Then the pressure is obtained as,

[tex]P' = \rho \times g \times h'\\\\P' = 1000 \times 9.8 \times 0.235\\\\P'=2303 \;\rm Pa[/tex]

Thus, the pressure exerted by water on the sides of the container halfway down from the top is of 2303 Pa.

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Recall that

[tex]{v_f}^2-{v_i}^2=2a\Delta x[/tex]

where [tex]v_i[/tex] and [tex]v_f[/tex] are the initial and final velocities, respecitvely; [tex]a[/tex] is the acceleration; and [tex]\Delta x[/tex] is the change in position.

So we have

[tex]\left(21\dfrac{\rm m}{\rm s}\right)^2-{v_i}^2=2\left(0.853\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)[/tex]

[tex]\implies v_i\approx\boxed{15.4\dfrac{\rm m}{\rm s}}[/tex]

(Normally, this equation has two solutions, but we omit the negative one because the car is moving in one direction.)

Performing experiments that have never been done before is most likely to lead to improving a scientific theory. The correct option is D.

A theory is a well-thought-out elaboration for natural-world observational data that has been built using the scientific process and incorporates many facts and hypotheses.

A theory not only helps to explain established information; it also allows scientists to predict what they will see if the hypothesis is correct.

Scientific theories can be tested. Emerging data should be consistent with an existing theory.

To improve a scientific theory, conduct novel experiments on it. This will provide greater clarity on the theory.

It may reveal the limitations of this theory, as well as aspects of the theory that can be improved.

Thus, the correct option is D.

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Explanation:

The force on an object due to it's mass and gravity.

Explanation:

observation is something what you could observe from your organs like eyes ears etc and also it is what you observed during an event for an experiment but inference is what you decide to do after observation or an event.

the act of inferring (to derive by reasoning). Observation = an act or instance of noticing or perceiving.

Thank u!

Answer:

The value is     [tex] P_G  =  2.925 *10^{5} \  Pa[/tex]

Explanation:

From the question we are told that

   The  volume of the bottle is  [tex]v  =  2 \  L  =  2 *  10^{-3} \  m^3[/tex]

   The gauge pressure of the air is [tex]P_g  =  340 \  kPa  =  340 *10 ^{3}  \  Pa[/tex]

Generally the volume of air before the bottle is turned upside down is  

      [tex]V_a  =  \frac{3}{4}  * V[/tex]

       [tex]V_a  =  \frac{3}{4}  *  2 *10^{-3}[/tex]

       [tex]V_a  =  0.0015 \  m^3 }[/tex]

Generally the volume air when the bottle is turned upside-down is

      [tex]V_u  =  \frac{5}{6}  *  2 *10^{-3}[/tex]

       [tex]V_u  =  0.00167 \  m^3 [/tex]

From the the mathematical relation of adiabatic process we have that

     [tex]P_g *  V_a^r  =  P_G *  V_u^r[/tex]

Here r is a constant with  a value  r =  1.4

So

      [tex] 340 *10 ^{3}  *  0.0015^{1.4}  =  P_G *  0.00167^{1.4}[/tex]

        [tex] P_G  =  2.925 *10^{5} \  Pa[/tex]

Newton's second law allows us to find the result for the effect of building a lower mass bike is:

Newton's second law states that force is equal to the product of mass and acceleration of the body.

          ∑ F = m a

Where the bold letters indicate vectors, m is the mass and  a the acceleration.

They indicate that the bicycle is made of bamboo, so it has less mass, therefore the acceleration is:

          [tex]a = \frac{\sum F}{m}[/tex]

if the mass decreases, more acceleration is recorded, therefore from the kinematic reactions the bicycle reaches higher speeds.

         v = v₀ + a t

The bicycles parts of the rest.

          v = a t

In conclusion, using Newton's second law we can find the result for the effect of building a bicycle with alower mass is:

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Answer:5

Explanation:

You do change in y over change in X

Answer:

The term 'mettaloid' is normally applied to a group of between six and nine elements ;

are found near the center of the P-block or main block of the periodic table.

Explanation:

Answer:

I am fairly certain the answer is 2m/s^2

Explanation:

Answer:

. the point charge is moved off center (but still inside the sphere) the point charge is moved to allocation just outside the sphere.

Explanation:

Because

Gaussian surface is given as

ϕ= qclose/E0

​So Q enclosed charge will be same if w the charge inside the Gaussian surface is moved, so flux will not change.

​

Answer:

6957.04N

Explanation:

Using

vf2=vi2+2ad

But vf = 0 .

So convert 50km/hr to m/s, and you need to convert 61 cmto m

(50km/hr)*(1hr/3600s)*(1000m/km) = 13.9m/s

61cm * (1m/100cm) = .61m

So n

0 = (13.9m/s)^2 + 2a(.61m)

a = 158.11m/s^2

So

using F = ma

F = 44kg(158.11m/s^2) = 6957.04N

Answer:

6.95 kN

Explanation:

Given that

Speed of the car, u = 50 kmph

Distance moved by the passenger, s = 61 cm = 0.061 m

Mass of the passenger, m = 44 kg

Converting the initial velocity from km/h to m/s, we have

50 kmph = 50 * 1000/3600

50 kmph = 13.89 m/s

Using one of the equations of motion,

v² = u² + 2as, where v = 0,making a the subject of formula

a = -u²/2s

a = -(13.89²) / 2 * 0.61

a = -192.93 / 1.22

a = -158 m/s²

The force acting on the passenger's leg, F = m.a, so

-F = 44 * -158

F = 6952 N, or 6.95 kN

Answer:

a) b = -5

b) slope = 3/2

Explanation:

a) The equation of a line is given as y = mx + b, where m is the slope of the line and b is the intercept on the y axis.

Given that y = 3x + b and it passes through the point (2, 1). Hence when x = 2, y = 1. Therefore, substituting for x and y:

1 = 3(2) + b

1 = 6 + b

b = 1 - 6

b = -5

b) The equation of a line passing through two points ([tex]x_1,y_1[/tex]) and [tex]x_2,y_2[/tex] is given by:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

The equation of the line passing through the two points (0,3) and (4,9) is:

[tex]y-3=\frac{9-3}{4-0}(x-0)\\ \\y-3=\frac{3}{2}x\\ \\y = \frac{3}{2}x+3[/tex]

Comparing y = (3/2)x + 3 with y = mx + b, the slope (m) is 3/2

Answer:

a. Question

Explanation:

The statement above is more of a question rather than a hypothesis or the other options. Consider, the statement has no direct initial assumption or hint of personally researching for answers.

In other words, the speaker could be asking another individual his opinion whether the amount of homework completed has an effect on science test scores.

The ball's height at time t is

y = (20.0 m/s) t - 1/2 g t²

where g is the acceleration due to gravity, with magnitude 9.80 m/s².

Also, recall that

v² - u² = 2 a ∆y

where u is the initial velocity, v is the final velocity, a is the acceleration, and ∆y is the change in height. Let Y be the maximum height. At this height, v = 0, so

- (20.0 m/s)² = 2 (-g) Y

==>  Y ≈ 20.408 m

Plug this into the first equation and solve for t :

Y = (20.0 m/s) t - 1/2 (9.80 m/s²) t²

==>  t ≈ 2.04 s

The ball's velocity at time t is

v = 20.0 m/s - g t

After t = 3.0 s, its velocity will be

v = 20.0 m/s - (9.80 m/s²) (3.0 s)

v = -9.40 m/s

or 9.40 m/s in the downward direction.

Answer:

The  value  is  [tex]t  =29.2  \  s [/tex]

Explanation:

From the question we are told that

Generally the average velocity of the train is mathematically represented as

          [tex]v  =  \frac{u +  v}{2}[/tex]

substituting  82.4 km/h for  u and   16.4 km/h. for  v

       [tex]v  =  \frac{82.4 + 16.4}{2}[/tex]

          [tex]v  =  49.4 \  km/h[/tex]

Generally the time taken is mathematically represented as

     [tex]t  =  \frac{ L}{v}[/tex]

substituting   49.4 \  km/h for  v and  [tex]4.00 * 10^2 \  m  =  0.400 \  km[/tex]

         [tex]t  =  \frac{ 0.400}{49.4}[/tex]

          [tex]t  = 0.00809 \  h [/tex]

converting to seconds

         [tex]t  = 0.00809 * 3600  [/tex]

          [tex]t  =29.2  \  s [/tex]

Answer: His acceleration is -18.66m/s^2

Explanation:

Ok, the initial speed is 2.8m/s. (we can define the initial direction as the positive direction).

And he wants to stop, so he must accelerate in the opposite direction as the initial movement, then we would have:

a(t) = -A.

So we have a constant, and negative acceleration.

Now, if we want to find the velocity we must integrate over time, and we will get:

v(t) = -A*t + V0

where V0 is the initial velocity, we know that it is 2.8m/s, and t is the time in seconds.

Then the velocity is:

v(t) = -A*t + 2.8m/s.

Now we know that John is brought to rest in 0.15 seconds after he starts slowing down, this means that at t = 0.15 seconds, his velocity is equal to zero.

v(0.15s) = 0m/s = -A*0.15s + 2.8m/s

2.8m/s = A*0.15s

2.8m/s/0.15s = 18.66m/s^2 = A.

So his acceleration is -A, then we have that:

His acceleration is -18.66m/s^2

Answer:

4.61 m away

Explanation:

No, the owl will not fall into the nest.

The vertical component of the velocity, v of mouse after travelling vertical distance of 12 m is given by

v² - (4 * sin 32)² = 2 * 9.81 * 12

v² - (4 * 0.53)² = 235.44

v² - 4.494 = 235.44

v² = 235.44 + 4.494

v² = 239.934

v = 15.49 m/s

The time taken to travel the said 12 m downwards =

(15.49 - 4 * sin 32) / 9.81

(15.49 - 4 * 0.53) / 9.81

(15.49 - 2.12) / 9.81

13.37 / 9.81 = 1.36 s

Horizontal distance traveled in this time = 4 * (cos 32) * 1.36

= 4 * 0.848 * 1.36

= 4.61 m

Therefore, the horizontal position of the mouse is 4.61 m away from the point of release.

At the time when the sun pulls on earth should be large so it should be pulled on each other equally.

Here the gravitational force that lies between two masses should be proportional with respect to the product of mass that should be divided via the square of the distance that lies between them. The acceleration should be measured when the force should be divided by the mass. Here the two forces should be equal and opposite

Therefore, the option b is correct.

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Answer:

1½ hours

Explanation:

Let the amount of time she drove at 85.5 km/hr be t, then

The distance that she rode would be 85.5 * t

This is means Emily has traveled the same distance at 68.8 km/hr without any stoppage whatsoever. Thus, we can create an equation as such

85.5 * t = 68.8 (t + 22/60), the 22/60 being, converting 22 minutes into hours. We proceed further as

85.5t = 68.8t + 1513.6/60, multiplying all sides by 60, we have

5130t = 4128t + 1513.6, now we collect like terms

5130t - 4128t = 1513.6

1002t = 1513.6

t = 1513.6/1002

t = 1.51 hrs, or in minutes, 1.51 * 60

t = 90.63 minutes. 1 hour and 36 minutes

So the total time the trip took, 22 minutes in addition, or say, 1 hour 58 minutes.

Answer:

Earth's tilted axis causes the seasons. Throughout the year, different parts of Earth receive the Sun's most direct rays. So, when the North Pole tilts toward the Sun, it's summer in the Northern Hemisphere. And when the South Pole tilts toward the Sun, it's winter in the Northern Hemisphere.

Explanation:

Answer:

Explanation:

When a body is held against a vertical wall , to keep them in balanced position , normal force is applied on their surface . this force creates normal reaction which acts against the normal force and it is equal to the normal force as per newton's third law . Ultimately friction force is created which is proportional to normal force and it acts in vertically upward direction . It prevents the body from falling down .

Hence normal force = reaction force .

From second law also net force is zero , so if  normal force is N and reaction force is R

R - N = mass x acceleration = mass x 0 = 0

R = N .

Ranking normal force from  highest  to smallest

150 N , 130 N , 120 N

B )

Frictional force is equal to the weight of the body because the body is held at rest .

Ranking of frictional force form largest to smallest

7 kg , 5 kg , 3 kg , 1 kg .

Here frictional force is irrespective of the normal force acting on the body  because frictional force adjusts itself so that it becomes equal to weight in all cases here because it always balances the weight of the body .

Based on the magnitude of normal force acting on them, the ranking from largest to smallest will be:

Based on the masses, the frictional force acting on the boxes will be such that the ranking from largest to smallest will be:

The normal forces acting on the box will depend on the force acting on the box. This means that the larger the force acting on the box, the larger the normal force.

This is why the box with a force of 150 N will be have the highest normal force acting on it.

The frictional force acting on the boxes will depend on the mass. Boxes will lager masses will have more frictional force acting on them.

The boxes of 7kg will therefore have the largest frictional forces acting on them.

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I think it might be Either A or B im thinking B

Answer:

The answer is C.

Explanation:

Answer:

Rotational inertia decreases proportional to the decrease in the radius of rotation.

Explanation:

The rotational inertia decreases proportional to the decrease in the

radius of rotation.

Rotational inertia is directly proportional to the angular momentum of the object and inversely proportional to its angular velocity.

[tex]I = \frac{L}{\omega}[/tex]

where;

The angular momentum is given as;

[tex]L = mvr[/tex]

where;

The new rotational inertia equation becomes;

[tex]I = \frac{mvr}{\omega}[/tex]

A 10% closer to the Earth, means a decrease in the radius of the satellite by 10%.

Thus, a decrease in the rotational inertia as well.

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Answer:

The answer is

Explanation:

The net force acting on an object when given the mass and acceleration can be found by using the formula

From the question

mass of backpack = 12 kg

acceleration = 0.5 m/s²

So the force is

Force = 12 × 0.5

We have the final answer as

Hope this helps you