A few million years ago, volcanic eruptions caused a large region to be covered by lava. The lava eventually cooled, which resulted in the formation of large amounts of igneous rock. Most of the rock formed was basalt. Today, this region is covered by soil, most of which is a soil known as laterite. Which geologic process caused the rock to change into soil?
A.
deposition
B.
erosion
C.
transportation
D.
weathering

Explanation:

The photo is the net ionic equation for the Calcium ions

The net ionic equation for the reaction is [tex]3Ca^{+2} + 2PO^{-3}_2----- > Ca_3(PO_4)_2[/tex]

A chemical reaction is the chemical transformation of one set of chemical substances into another.

When chemical bonds between the atoms are formed or broken, chemical reactions occur.

The substances that initiate a chemical reaction are known as reactants, and the substances that result from the reaction are known as products.

Plants grow, start producing fruit, and decompose to become compost for new plants through chemical reactions.

The reaction for the given scenario is,

[tex]3Ca^{+2} + 2PO^{-3}_2----- > Ca_3(PO_4)_2[/tex]

Thus, above mentioned is the chemical reaction.

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Answer:

2Mg, 2 02, MgO

Answer:

6.68 x 10^-4

Explanation:

131g ÷ 261.337g/mol = 0.5012685 moles

0.5012685 moles ÷ 750.0 liters =

0.5012685÷ 750.0=0.000668358

6.68 x 10^-4

Answer:

B

Explanation:

A mixture in which the composition is not uniform throughout.

Same thing letter B says.

The pressure in atmospheres of the given mole and volume of helium gas is 4.7atm.

Given the data in the question;

Pressure in atmosphere; [tex]P = \ ?[/tex]

The Ideal gas law emphasizes on the behavior of a hypothetical ideal gas. It states that pressure P multiply by volume V is equal to moles times temperature and the universal gas constant.

It is expressed;

[tex]PV = nRT[/tex]

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant.( [tex]R = 0.08206Latm/molK[/tex] ).

To determine the pressure in atmosphere, we substitute our values into the expression above.

[tex]PV = nRT\\\\P = \frac{nRT}{V} \\\\P = \frac{1.92mol\ *\ 0.08206Latm/molK\ *\ 298.15K}{10.0L} \\\\P = \frac{46.975Latm}{10.0L}\\\\P = 4.7atm[/tex]

Therefore, the pressure in atmospheres of the given mole and volume of helium gas is 4.7atm.

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Answer:

The correct answer to first question is C

I only know this one.

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

I also kno wtge answer to question 7 is A

Answer:

A. They repel more strongly than the bonding pairs, pushing the bonding pairs closer together.

Explanation:

Lone pairs are in simple terms just pairs of electrons on the atom. Negative does not attract negative so it repels from the bonds. I put it in the most simple terms possible. Like with magnets north and north don't attract. Same concept

Answer:

D

Explanation:

Potassium metal and chlorine gas combine to form potassium chloride. The balanced equation is 2K (s) + Cl2 (g)→2KCl (s) There are two chlorine atoms on the left-hand side (LHS) and one chlorine atom on the right-hand side (RHS).

1129.9 grams of rock salt, NaCl needs to be added to a 3.78 kg of ice, to get the temperature to drop to -19C .

Freezing point depression refers to a property of solutions where addition of a solute lowers the normal freezing point of the solvent.

The Blagden's Law given as the equation above is used to determine the freezing point depression of ice:

where;

For NaCl, i = 2

Kf for water/ice = 1.86 °C kg/mol

molalityof NaCl = (mass/molar mass

l)/kg of ice

molar mass of NaCl = 58.5

mass of ice = 3.78 kg

Let molality of NaCl = m

ΔT = 19 °C

Substituting the values:

19 = 2 x 1.86 °C kg/mol x m

m = 5.11 mol/kg

mass of NaCl = 5.11 × 3.78 × 58.5

mass of NaCl = 1129.9 g

Therefore, the mass in grams of rock salt, NaCl that needs to be added to a 3.78 kg of ice, to get the temperature to drop to -19C is 1129.9 g

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So

Moles of Oxygen:-

3 mol of O_2 produces 2 mol SO_2

1 mol of ao_2 produces 2/3=0.6mol So_2

1.396 mol produces 0.8376mol SO_2

Mass of SO_2

Answer:

BaS would be a stable neutral molecule!

Reason:- All of the above.

Explanation:

In order to form a neutral molecule it's necessary to balance their charge first, The given components i.e. Ba2+(cation) and S2-(anion) have equal and opposite charges, when they combine they form predominantly ionic compound i.e. Sulphur partly shares it's 2 electrons with Barium and forms Barium sulphide.

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Answer:

yes it does look correct. good job.

Post- lab the percent sugar 46%, and the molar mass of sugar is 342 g/mol,  the mass of dissolved sugar to moles is 0.00497 moles of sugar to molecules of sugar is  2.992934 × 10^21 molecules, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double  0.00994 moles.

moles is the unit of the molecule and it is defined as the number of molecules participating in a chemical reaction and value of one mole is equal to Avogadro constant that is 2.303 × 10²³

Sugar percentage = mass of sugar / mass of gum × 100  = 1.7 / 3.7 × 100 =  45.94 (46%)

Molar mass of sugar = C12H22O11 = C=12×12=144 + H=1×22=22  + O=16×11=176 = 342 g/mol  

Mass of dissolved sugar to moles = 1.7 g ÷ 342 g/mol = 0.00497 moles

The moles of sugar to molecules of sugar = 0.00497 mole × 6.022 × 10^23 = 2.992934 × 10^21 moleculesIn the given theory using four pieces of gum will exactly be the same to the mass of sugar.2 ÷ 342 g/mol × 1.7 = 0.00994 moles

The mass of the saliva alter the experimental data because it is not possible to remove all the saliva from the surface as it gets stick to the paper which changes the amount of sugar.

Therefore, the percent sugar 46%, and the molar mass of sugar is 342 g/mol, the mass of dissolved sugar to moles is 0.00497 moles of sugar to molecules of sugar is  2.992934 × 10^21 molecules, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double  0.00994 moles.

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The formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1. as shown below:

Ammonia gas is formed from the reaction between nitrogen gas and hydrogen gas.

Three moles of hydrogen gas will react with 1 mole of nitrogen gas to form 2 moles of ammonia gas.

The equation of the reaction is given below as:

[tex]N_2 + 3H_2 \rightarrow 2NH_3[/tex]

Therefore, the formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1.

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Explanation:

hello

the answer is b

O or oxygen has 16 molar mass and C or carbon has 12

so CO2 or carbon dioxide=(2×O)+C=(2×16)+12=46

Taking into account the definition of a system of linear equations and molar mass, the molar masses of elements A and B are 26.778 [tex]\frac{g}{mole}[/tex] and 17.998[tex]\frac{g}{mole}[/tex] respectively.

A system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.

Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied. That is to say, the values ​​of the unknowns must be sought, with which when replacing, they must give the solution proposed in both equations.

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

Being the molar masses of the compounds:

and considering the definition of molar mass of a compound, the system of equations to be solved is

[tex]\left \{ {{3mA + mB=98.33\frac{g}{mole} } \atop {mA + 2mB=62.77\frac{g}{mole} }} \right.[/tex]

where mA and mB are the molar masses of elements A and B respectively.

There are several methods to solve a system of equations, it is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.

Isolating the variable mB from the first equation:

mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3mA

and substituting in the second equation, you get:

mA + 2× (98.33 [tex]\frac{g}{mole}[/tex] - 3mA)=62.77[tex]\frac{g}{mole}[/tex]

Solving:

mA + 2× 98.33 [tex]\frac{g}{mole}[/tex] - 2×3mA=62.77[tex]\frac{g}{mole}[/tex]

mA + 196.66 [tex]\frac{g}{mole}[/tex] - 6mA=62.77[tex]\frac{g}{mole}[/tex]

mA - 6mA=62.77[tex]\frac{g}{mole}[/tex] - 196.66 [tex]\frac{g}{mole}[/tex]

(-5)mA= - 133.89 [tex]\frac{g}{mole}[/tex]

mA= (- 133.89 [tex]\frac{g}{mole}[/tex] )÷ (-5)

mA= 26.778 [tex]\frac{g}{mole}[/tex]

Remember that mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3mA, replacing the value of mA:

mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3×(26.778 [tex]\frac{g}{mole}[/tex])

mB= 80.334 [tex]\frac{g}{mole}[/tex]

mB= 17.998 [tex]\frac{g}{mole}[/tex]

Finally, the molar masses of elements A and B are 26.778 [tex]\frac{g}{mole}[/tex] and 17.998[tex]\frac{g}{mole}[/tex] respectively.

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Using the stoichiometry of the balanced chemical reaction, the mass of the Ti is 144Kg.

The term chemical reaction refers to the combination of two or more substances to yiled one or more products.

The reaction equation here is; 4Na(s) + TICI4---->Ti(s) + 4NaCl(s)

Number of moles of TiCl4 = 570  * 10^3g/190 g/mol = 3000 moles

If 1 mole TiCl4 produces 1 mole of Ti

3000 moles of TiCl4 produces 300o moles of Ti

Mass of Ti produced = 3000 moles * 48 g/mol = 144Kg

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Answer: 1. Mineral

Explanation:

       Calcite is a "white or colorless mineral consisting of calcium carbonate" (Oxford Languages).

       By this definition, the answer to your question is option 1.

The image attached is from geology.com and is a picture of calcite.

Answer:

Zinc with copper is Brass, Zinc is alloyed with Lead and Tin to make solder.

The volume in litres occupied by 1.59 Kg of ethyl alcohol given the data from the question is 2.03 L

Mole = mass / molar mass

Mole of ethyl alcohol = 78.5 / 46.07

Mole of ethyl alcohol = 1.7 mole

Mole = mass / molar mass

Mole of ethyl alcohol = 1590 / 46.07

Mole of ethyl alcohol = 34.5 moles

V₁ / n₁ = V₂ / n₂

0.1 / 1.7 = V₂ / 34.5

Cross multiply

1.7 × V₂ = 0.1 × 34.5

Divide both side by 1.7

V₂ = (0.1 × 34.5) / 1.7

V₂ = 2.03 L

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Answer:

0.1 moles

Explanation:

3.4 g * (1 mol/34 g) = 0.1 moles

Answer:

Grignard reagents are made through the addition of magnesium metal to alkyl or alkenyl halides. The halide can be Cl, Br, or I (not F). It’s slightly easier to make Grignards from the iodides and bromides, however. Note what’s happening here – the magnesium is “inserting” itself between the carbon and the halide. This halide the “X” referred to when we refer to Grignard reagents as “RMgX”.

formation-of-grignard-reagents-from-alkyl-or-alkenyl-halides

Reaction Of Grignard Reagents With Aldehydes To Give Secondary Alcohols

One of the most common uses of Grignard reagents is in their reaction with aldehydes and ketones to form alcohols. In the first step, the Grignard forms the carbon-carbon bond. This results in an alkoxide (the conjugate base of an alcohol). To form the alcohol, it’s necessary to add acid at the end of the reaction (in what’s called the “workup” step). This is shown here as “H3O+” (the “X” is just the counter-ion, a spectator here)

reaction-of-grignard-reagents-with-aldehydes-to-give-secondary-alcohols

Reaction Of Grignard Reagents With Ketones To Give Tertiary Alcohols

The reaction behaves similarly with ketones. Again, there’s nothing special about the Cl here – it all depends on how you made the Grignard in the first place.

eaction-of-grignard-reagents-with-ketones-to-give-tertiary-alcohols

Grignards Add Twice To Esters And Acid Halides

Grignard reagents will also add to esters. What makes these reactions a little more complicated is that they add twice. The net result (after addition of acid) is a tertiary alcohol. This is also the case for acid halides (acyl halides) and anhydrides. One notable exception is carboxylic acids (more on that below).

reaction-of-grignard-reagents-with-esters-to-give-tertiary-alcohols-double-addition

reaction-of-grignard-reagents-with-acid-halides-to-give-tertiary-alcohols-double-addition

Addition Of Grignard Reagents To Epoxides

Another important reaction of Grignard reagents is that they will add to epoxides to form carbon-carbon bonds. One thing to keep in mind here is that the tendency is for them to add to the less substituted end of the epoxide – that is, the less sterically hindered end. You can think of this reaction as being essentially similar to an SN2 reaction. After addition of acid, an alcohol is obtained.

reaction-of-grignard-reagents-with-epoxides-to-give-alcohols

Reaction Of Grignard Reagents With Carbon Dioxide To Give Carboxylic Acids

Grignard reagents also add to carbon dioxide (CO2) to form carboxylates, in a reaction similar to their reactions with ketones and aldehydes. The carboxylates are converted to carboxylic acids after addition of acid (such as our trusty H3O(+) ).

reaction-of-grignard-reagents-with-co2-carbon-dioxide-to-give-carboxylic-acids

Grignard Reagents Are Strong Bases – Protonation (And Deuteration)

Finally, since Grignard reagents are essentially the conjugate bases of alkanes, they’re also extremely strong bases. This means that sometimes acid-base reactions can compete with their nucleophilic addition reactions. One common situation where this crops up is when Grignard reagents are added to carboxylic acids. It’s easy to forget that carboxylic acids… are acids. This means that instead of adding to the carbonyl, they react with the proton instead and form the carboxylate salt.

reaction-of-grignard-reagents-with-acidic-hydrogens-acids-to-incorporate-h-and-deuterium

This can also be used to convert alkyl halides to alkanes. First you treat it with magnesium, and then you treat the Grignard with a strong acid. This gives you the alkane. You can also use this to introduce deuterium (D) into molecules! The first step is to make the Grignard reagent. The second is to treat that Grignard with a deuterated acid such as D2O. This gives you the deuterated alkane!

Mechanism: Addition Of Grignard Reagents To Aldehydes And Ketones

So how does it work? The key to the Grignard reagent is actually very simple. When you think about the relative electronegativities of carbon (2.5) and magnesium (1.1), the bond between carbon and magnesium is polarized toward carbon. That means that carbon is more electron rich than magnesium and is actually nucleophilic! Here’s a closer look.

mechanism-for-addition-of-grignard-reagents-to-aldehydes-or-ketones

In the reaction of Grignards with aldehydes, the carbon attacks the carbonyl carbon and performs a 1,2-addition to give an alkoxide. In the second step, acid is added to give you the alcohol.

Answer:

The student needs to increase the length of the heating element

Explanation:

Increasing the length of the heating elements helps to increase the surface area of the heating elements which allows for more water to come in contact with the heating element

The true statements about activation energy are as follows:

Activation energy is the minimum amount of energy that reactants in a chemical reaction must possess so as to get converted into products.

In a chemical reaction, reactants form products, hence, certain bonds must be broken in the reactant molecules to form the products.

The energy needed to break the bonds of the reactants is known as activation energy.

Therefore, the true statements about activation energy are as follows:

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atomic mass for N = 7

electron configuration: 1s²2s²2p³

orbital diagram:

↑↓   ↑↓    ↑ ↑ ↑

1s²  2s²      2p³

Answer:

The answer to this question is A.

hope it helps :)

Answer:

14.23

Steps given below in the picture

I hope my answer helps you.

Answer:

A

Explanation:

it can occur between two hydrogen bonds

For the absorbance of the solution in a 1.00 cm cell at 500 nm  is mathematically given as

A’ = 0.16138

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138

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