A higher credit score reduces your fixed costs because you ____.

A. will pay lower interest rates
B. can have more credit cards
C. are able to carry more debt
D. can reduce the amount you need to borrow

Sam started with £5.

Now, we need to find out how much money Sam has left after spending £4.50 on chocolate and £3.00 on cold coffee. To do this, we can add the two amounts that he spent and subtract the total from his original amount of money:

£4.50 + £3.00 = £7.50

Original amount - £7.50 = Two-fifths of the original amount

Now, we know that Sam has two-fifths of his original amount of money left. We can use this information to set up an equation:

2/5 x Original amount = Amount of money left

We can solve for the original amount by multiplying both sides by 5/2:

Original amount = (5/2) x Amount of money left

Plugging in the amount of money Sam has left, we get:

Original amount = (5/2) x Amount of money left

Original amount = (5/2) x (Original amount - £7.50)

Simplifying the right side of the equation, we get:

Original amount = (5/2) x Original amount - (5/2) x £7.50

Original amount - (5/2) x Original amount = (5/2) x £7.50 (3/2) x Original amount = (15/2)

Original amount = £5

Therefore, Sam started with £5.

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1/5 = 200 pennies

5/5 = 1000 pennies

Answer:

tan (A) = 1/2. tan (B) = 2

Step-by-step explanation:

tan θ = opposite/adjacent

for tan(A), the opposite is 5. adjacent is 10. hypotenuse is 5√5.

tan (A) = 5/10 = 1/2.

for tan (B), the opposite is 10, adjacent is 5. hypotenuse is 5√5.

tan(B) = 10/5 = 2

When we use Gauss-Jordon elimination method, the final product is as follows

[tex]\left[\begin{array}{cccc}1&0&0&-1\\0&1&0&-3\\0&0&1&-2\end{array}\right][/tex]

The augmented matrix that represents a linear equation is as follow;

-5  7   7   -30

1    -4   4    3

2   -4   6    -2

Using Gauss-Jordon elimination method, we reduce every number to zero's and 1 except the values at the edge;

Divide row 1 by -5           Subtract row 1 from row 2

1   -7/5   -7/5   6                 1   -7/5    -7/5   6

1    -4      4      3                 0  -13/5   27/5  -3

2   -4      6     -2                 2    -4       6      -2

 R₃ - 2R₁                                    R₂ = -5R₂ ÷ 13

1    -7/5     -7/5     6                   1    -7/5     -7/5     6

0  -13/5    -27/5   -3                   0     1      -27/13   15/13

0   -6/5    44/5   -14                  0   -6/5    44/5   -14

R₁ + 7R₂ ÷ 5                                   R₃ + 6R₂÷5

1     0     -56/13  99/13                1     0     -56/13  99/13  

0     1    -27/13   15/13                 0     1    -27/13   15/13

0   -6/5    44/5   -14                   0     0    82/13    -164/13

   13R₃/ 82                                     R₁ + 56R₃/13

1     0    -56/13  99/13                  1     0     0        -1

0     1    -27/13   15/13                  0    1   -27/13  15/13  

0     0      1          -2                      0     0      1      -2

R₂ + 27R₃/13

1     0     0        -1

0     1     0        -3

0     0      1      -2

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Answer:

47
Step-by-step explanation:

The federal government spends slightly more on defense than Social Security.

We have,

The federal government spends different amounts of money on different programs and services every year, so there is no fixed answer to this question.

However, based on recent data, we can make some general statements about federal spending on defense and Social Security.

In the United States, defense spending typically makes up a significant portion of the federal budget, usually around 15-20%.

Social Security spending is also a major component of the federal budget, making up about 24% of total federal spending in recent years.

Thus,

Based on these figures, we can say that the federal government spends slightly more on Social Security than on defense.

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28.

Arc BC = 107 degrees

---Since the given angle is on the center of the circle, the arc has the same measure.

Angle BAC = 53.5 degrees

---Since this is an inscribed angle, the measure of the angle is half of the corresponding arc.

29.

Arc BC = 92 degrees

---Since we are given an inscribed angle, the corresponding arc is double the measure of the angle.

Hope this helps!

The probability of exactly 5 occurrences is (Rounding to three Decimal places), we get P(X ≤ 3) ≈ 0.251.

a) The probability of exactly 5 occurrences is given by the Poisson probability mass function:

P(X = 5) = (e^(-λ) * λ^5) / 5! = (e^(-5.1) * 5.1^5) / 120 ≈ 0.1755

Rounding to four decimal places, we get P(X = 5) ≈ 0.1755.

b) The probability of more than 6 occurrences can be calculated as the complement of the probability of 6 or fewer occurrences:

P(X > 6) = 1 - P(X ≤ 6) = 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6))

Using the Poisson probability mass function and the given value of λ, we can calculate each of the probabilities:

P(X = 0) ≈ 0.006

P(X = 1) ≈ 0.031

P(X = 2) ≈ 0.079

P(X = 3) ≈ 0.135

P(X = 4) ≈ 0.174

P(X = 5) ≈ 0.1755

P(X = 6) ≈ 0.1493

Substituting these values into the formula, we get:

P(X > 6) ≈ 1 - (0.006 + 0.031 + 0.079 + 0.135 + 0.174 + 0.1755 + 0.1493) ≈ 0.249

Rounding to three decimal places, we get P(X > 6) ≈ 0.249.

c) The probability of 3 or fewer occurrences is given by the cumulative distribution function:

P(X ≤ 3) = ∑ P(X = k), for k = 0, 1, 2, 3.

Using the Poisson probability mass function and the given value of λ, we can calculate each of the probabilities:

P(X = 0) ≈ 0.006

P(X = 1) ≈ 0.031

P(X = 2) ≈ 0.079

P(X = 3) ≈ 0.135

Adding these probabilities, we get: P(X ≤ 3) ≈ 0.251

Rounding to three decimal places, we get P(X ≤ 3) ≈ 0.251.

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part a.

The average velocity on the interval [0,2] is -16 ft/sec

part b.

The instantaneous velocity when t=2  is found as -48 ft/sec

part c.

Time taken to reach the ground is 3 seconds.

part d.

velocity of the ball when it hits the ground is found as  80 ft/sec downward.

The average velocity on the interval [0,2] is determined by :

average velocity = change in distance / change in time

change in distance :

s(2) - s(0) = (-16(2)^2 + 16(2) + 96) - (-16(0)^2 + 16(0) + 96) = -32

where the change in time:

2 - 0 = 2

average velocity = -32/2

average velocity = -16 ft/sec

b. The instantaneous velocity :

s'(t) = -32t + 16

and  t=2:

s'(2) = -32(2) + 16 =

s'(2)=  -48 ft/sec

the velocity of the ball when it hits the ground is at time = 3

s'(t) = -32t + 16

s'(3) = -32(3) + 16 =

s'(3)  =  -80 ft/sec

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The length of side p is approximately 21.67

In triangle PQR, we are given the values of sin P, sin R, and the length of side r. We need to find the length of side p.

We can use the law of sines to solve this problem. The law of sines states that the ratio of the length of a side of a triangle to the sine of the opposite angle is constant. Mathematically, it can be represented as:

p / sin P = r / sin R

Plugging in the given values, we have:

p / 0.5 = 13 / 0.3

Cross-multiplying, we get:

0.3p = 13 * 0.5

0.3p = 6.5

Dividing both sides by 0.3, we find:

p ≈ 21.67

Therefore, the length of side p is approximately 21.67.

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The vertices of the triangle XYZ after a dilation with a scale factor of [tex]4[/tex] are [tex]X'(-8, 4)[/tex], [tex]Y'(12, -4)[/tex], and [tex]Z'(4, 16)[/tex].

To find the vertices of the image after a dilation with a scale factor of [tex]4[/tex], we need to multiply the coordinates of each vertex by the scale factor.

Given the triangle with vertices [tex]X(-2,1), Y(3,-1), and \ Z(1,4)[/tex], we can apply the dilation to each vertex.

Let's start with vertex [tex]X(-2,1)[/tex]:

The new x-coordinate,[tex]\(x'\)[/tex], can be obtained by multiplying the original x-coordinate by the scale factor: [tex]\(x' = 4 \times (-2) = -8\)[/tex].

Similarly, the new y-coordinate, [tex]\(y'\)[/tex], is obtained by multiplying the original y-coordinate by the scale factor: [tex]\(y' = 4 \times 1 = 4\)[/tex].

Thus, the image of vertex X is [tex]X'(-8, 4)[/tex].

Now let's apply the same process to vertices [tex]Y(3,-1) \ and \ Z(1,4):[/tex]

For vertex Y:

[tex]\(x' = 4 \times 3 = 12\)\\\y' = 4 \times (-1) = -4\)[/tex]

The image of vertex Y is Y'(12, -4).

For vertex Z:

[tex]\(x' = 4 \times 1 = 4\)\\\(y' = 4 \times 4 = 16\)[/tex]

The image of vertex Z is [tex]Z'(4, 16)[/tex].

Therefore, the vertices of the triangle XYZ after a dilation with a scale factor of [tex]4[/tex] are [tex]X'(-8, 4)[/tex], [tex]Y'(12, -4)[/tex], and [tex]Z'(4, 16)[/tex].

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The other zero of the function given that one zero is 4 include: B. 8.

The correct graph of the quadratic function represented in the table is: graph A.

In Mathematics and Geometry, the standard form of a quadratic function is represented by the following equation;

ax² + bx + c = 0

Next, we would create a system of equation by using the data points provided in the table above;

a(2)² + b(2) + c = 12

4a + 2b + c = 12     .....equation 1.

a(6)² + b(6) + c = -4

36a + 6b + c = -4     .....equation 2.

a(7)² + b(7) + c = -3

49a + 7b + c = -3     .....equation 3.

By solving the system of equations simultaneously, the values of a, b, and c are as follows;

a = 1

b = -12

c = 32

Therefore, the required quadratic function is given by;

ax² + bx + c = 0

x² - 12x + 32 = 0

x² - 8x - 4x + 32 = 0

x(x - 8) - 4(x - 8) = 0

(x - 4)(x - 8) = 0

x = 4 or x = 8

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The correct statement is D. The inequality that represents the price, p, of each of the discounted tickets is p > 9.50.

Georgia wants to go to a concert.

The concert offers discounted tickets to groups that buy more than 12 tickets.

The price of each discounted ticket is less than the regular price of $9.50.

Now, let's break down each statement:

A. The inequality that represents the number of tickets, t, Georgia can buy at the discounted price is t > 12.

This statement is not necessarily true based on the information given. We know that the concert offers discounted tickets to groups that buy more than 12 tickets, but it doesn't provide any information about the maximum number of tickets Georgia can buy at the discounted price. The number of tickets Georgia can purchase could be more or less than 12.

B. The inequality that represents the number of tickets, t, Georgia can buy at the discounted price is t < 9.50.

This statement is incorrect. The inequality t < 9.50 doesn't make sense in this context because it implies that the number of tickets Georgia can buy is less than the price of a ticket, which is not relevant.

C. The inequality that represents the price, p, of each of the discounted tickets is p < 12.

This statement is incorrect as well. The inequality p < 12 suggests that the price of each discounted ticket is less than 12, but we don't have any information about the exact discount amount or the range of prices for the discounted tickets.

D. The inequality that represents the price, p, of each of the discounted tickets is p > 9.50.

This is the correct statement. We know that each discounted ticket costs less than the regular price of $9.50. Therefore, the price of each discounted ticket, represented by p, must be less than $9.50. Hence, the correct inequality is p < 9.50, or equivalently, p > 9.50.

In summary, the correct statement is D. The inequality that represents the price, p, of each of the discounted tickets is p > 9.50.

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Answer:

Step-by-step explanation:

132 + 106 + 81 + x = 360

319 + x = 360

x = 41

Answer:

the correct answer is the fifth one 1-3x

a)  Note that the the probability that on a given day, no machines break down is 0.3487

b) the probability that all printing   requirements on a particular day will be met is 0.2323

a) To find the probability that no machines break down, we can use the binomial distribution with

n = 10 (number of machines) and

p = 0.1 (probability of a machine breaking down).

The probability of no breakdowns  is

P(X = 0), where X is the number of breakdowns.

Using the binomial distribution formula: P(X = k) = (n choose k) * [tex]p^{k}[/tex] * (1 - p)[tex]^{n-k}[/tex]

P(X = 0) = (10 choose 0) * 0.1⁰ * 0.9¹⁰ = 0.3487

So it is right to stay that  the probability that on a given day, no machines break down is 0.3487

(b)

P(8 or more machines are functioning) = P(X = 8) + P(X = 9) + P(X = 10)

P(X = 8) = (10 choose 8) * 0.1⁸ *   0.9² = 0.1937

P(X = 9) = (10 choose 9) * 0.1⁹ * 0.9¹ = 0.0386

P(X = 10) = (10 choose 10) * 0.1¹⁰ * 0.9⁰ = 0.0000001

P(8 or more machines are functioning) = 0.1937 + 0.0386 + 0.0000001 = 0.2323

Hence, the probability that all printing requirements on a particular day will be met is 0.2323 or approximately 23.23%.

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The value of x, y and z in the system equation is (1, 2, 3).

The solution of the equation can be determined by using Cramer's rule as follows;

[-5    -6      0] = [ -17]

[-3     -5     5]    [2   ]

[-6    -5      1]     [-13 ]

The determinant of the matrix is calculate as;

Δ = -5 (-5 + 25) + 6(-3 + 30) + 0(15 + 30)

Δ = 62

The x-determinant of the matrix is calculated as follows;

Δx = -17(-5 + 25) + 6(2 + 65) + 0

Δx = 62

The y-determinant of the matrix is calculated as follows;

Δy = -5(2 + 65) + 17(-3 + 30) + 0

Δy = 124

The z-determinant of the matrix is calculated as follows;

Δz = -5(65 + 10) + 6 (39 + 12) - 17(15 - 30)

Δz =  186

The value of x, y and z is calculated as follows;

x = Δx/Δ = 62/62 = 1

y = Δy/Δ = 124/62 = 2

z = Δz/Δ = 186/62 = 3

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The maximum, minimum, and median values include the following: D. maximum = 8, minimum = –8, median = 4.

In Mathematics and Statistics, a box plot is sometimes referred to as box-and-whisker plot and it can be defined as a type of chart that can be used to graphically or visually represent the five-number summary of a data set with respect to locality, skewness, and spread.

Based on the information provided about the data set, the five-number summary for the given data set include the following:

Minimum (Min) = -8.

First quartile (Q₁) = -4.

Median (Med) = 4.

Third quartile (Q₃) = 6.

Maximum (Max) = 8.

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Check the picture below.

[tex]60+\stackrel{ \measuredangle ABC }{(3x+15)}+(20x-10)~~ = ~~180\implies 65+23x=180 \\\\\\ 23x=115\implies x=\cfrac{115}{23}\implies x=5 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \measuredangle EBF }{(3x+15)}\implies 3(5)+15\implies \text{\LARGE 30}^o[/tex]

The fully simplified product of (b minus 2 c)(negative 3 b + c) can be found by using the distributive property and combining like terms. The product is -3b^2 + 7bc - 2c^2, which has 3 terms.

Therefore, the statement "The simplified product has 2 terms" is false and the statement "The simplified product has 4 terms" is also false. The degree of each term is the sum of the exponents of the variables,

so the degree of the product is the highest degree among the terms. In this case, the highest degree is 2, which means that the statement "The simplified product has a degree of 2" is true and the statement "The simplified product has a degree of 4" is false.

Lastly, we can count the number of negative terms in the product to determine if the statement "The simplified product, in standard form, has exactly 2 negative terms" is true. We see that there are two negative terms, -3b^2 and -2c^2, so this statement is true.

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Answer: 35, 48, 63

Step-by-step explanation:

This sequence is known as an arithmetic progression sequence.

      3 - 0 = 3

      8 - 3 = 5

      15 - 8 = 7

      24 - 15 = 9

Using this pattern, we will add 11 to 24 for the next term in the sequence. Then, we will continue this pattern for the next two terms.

➜ The pattern is resulting odd numbers from subtracting two terms in a row; 3, 5, 7, 9, [11], [13], [15].

      24 + 11 = 35

      35 + 13 = 48

      48 + 15 = 63

Answer:

Part A

The amplitude of a cosine function is the distance between its highest and lowest points. In this case, the highest point is 8 feet and the lowest point is 8 - 12 = -4 feet, so the amplitude is 8 - (-4) = 12 feet.

The period of a cosine function is the time it takes for the function to complete one cycle of its movement. In this case, the bird completes one cycle of its movement every 16 seconds, so the period is 16 seconds.

Part B

The cosine function that could represent the situation is:

y = 6 cos(2πt / 16) + 8

This function has an amplitude of 6 feet and a period of 16 seconds. It also passes through the point (0, 8) when t = 0, which is the condition given in the problem.

Part C

The bird will reach its lowest height when the cosine function is equal to -6. This happens when 2πt / 16 = π / 2, or t = 4 seconds.

Here is a graph of the function:

[Image of a cosine function with an amplitude of 6 feet and a period of 16 seconds. The graph reaches its lowest point at t = 4 seconds.]

I hope this helps! Let me know if you have any other questions.

Step-by-step explanation:

Answer:

y = 5x + 17

Step-by-step explanation:

gradient of perpendicular = - 1/ (-1/5) = - (-5) = 5.

equation of line, gradient 5, through (-2, 7) is

y - 7 = 5 (x - -2) = 5 (x + 2) = 5x + 10

y = 5x + 10 + 7

y = 5x + 17

If the spread of data set X is greater than the spread of data set Y, and the data sets are normally distributed. The statement that  is true is: C. The standard deviation of data set X is greater than the standard deviation of data set Y.

A data set standard deviation is often used to calculate its spread. As a result the standard deviation of data set X will be higher than the standard deviation of data set Y if the spread of data set X is bigger than the spread of data set Y.

The standard deviation may or may not have the same distribution as the the following :

Therefore the correct option is C.

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Answer:

Step-by-step explanation:

There are 5 marbles

From the figure, the blanks are filed as follows

Common internal tangent: is matched to line HJ

point of tangency: is matched to G

Center: is matched to A

chord: is matched to line GK

secant: is matched to line CD

diameter: is matched to line EF

common external tangent = line KF

radius: is matched to line BF

semi-circle = arc EGF

Major arc: is matched to arc CDK

Minor arc: is matched to arc CK

In geometry the point of tangency is the point where a line or curve touches a circle or other curved shape at exactly one point without crossing over or intersecting it at another point.

At the point of tangency the tangent line is perpendicular to the radius of the circle that intersects it.

In the figure, the point of tangency is at F E G and K

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