A hot rod of mass 1200 kg, starting from rest
reaches a speed of 110 m/s in only 18.3 s.
What is the average output power?

If the earth is 5 times as massive and the radius 5 times its present value, your weight will be 130 N.

Weight is the amount of gravitational force acting on an object as a result of the gravitational attraction of the Earth.

Assuming gravitational force = [tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

where G = 6.67 x 10⁻¹¹m³/kgs², a universal constant.

m = masses of two objects and

r = distance of two objects.

Given that W = 650 N

m₁ = 5Me, new mass of earth

r = 5re, new radius of earth

Then [tex]650 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]

Let the new weight be [tex]F = \frac{GM m}{r^{2} }[/tex]

Substituting the new mass and radius;

[tex]F = \frac{G(5M_{E}) m}{(5r_{E})^{2}}[/tex]

[tex]F = \frac{5}{25} \frac{GM_{E} m}{r^{2}_{E}}[/tex]

Knowing that [tex]650 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]

[tex]F = \frac{5}{25}(650 N)[/tex] = 0.2 x 650N

F = 130 N

When the earth is 5 times its radius and 5 times its mass a weight of 650N will become 130 N.

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D. Gravity, weak nuclear force, electromagnetic force, strong nuclear force

The four fundamental forces in the universe, in order of increasing magnitude, are:

Gravity: This is the weakest of the four fundamental forces. It is the force that holds everything together and is responsible for the attraction between masses.

Weak Nuclear Force: This force is responsible for certain types of radioactive decay and the fusion of nuclei in stars. It is about 10^25 times weaker than the strong nuclear force.

Electromagnetic Force: This force is responsible for electric and magnetic interactions, such as the forces between charges, the forces between magnets, and the forces between electric currents.

Strong Nuclear Force: This is the strongest of the four fundamental forces. It holds the protons and neutrons in an atom's nucleus together, and it is about 10^38 times stronger than the electromagnetic force.

Therefore, the correct order of the four fundamental forces in terms of increasing magnitude is D: Gravity, weak nuclear force, electromagnetic force, strong nuclear force

This is the equations for a hyperbola if we plot mass as both the independent variable & acceleration as such dependent variable, again understanding Newton's second law.

The measured reaction is the dependent variable. The dependent variable is dependent on the variation in the independent variable, to put it another way.

In a scientific experiment, variables are the two most crucial variables. The independent variable is the one that is under the experimenter's control. The variable that adapts to the explanatory variables is known as the dependent variable.

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Answer:

Option a. The baton's center of mass is closer to the larger sphere, making the lever arm distance between your hand and the center of mass longer in option a than in option b. The longer lever arm distance gives you finer control.

The electric field strength in volts per meter is 380 V. Option D is the correct answer.

This refers to the physical field that encloses electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It can also be called the physical field for a system of charged particles or ( E-field).

The electric field strength (E) can be calculated using the  b the formula:

E = V / d,

where,

V = the potential difference (in volts)

d = the distance (in meters) between the plates.

Calculating the electric:

V = 15.0 V

d = 0.04 m (4.0 cm converted to meters).

Hence,

E = 15.0 V

      0.04 m

= 375 V/m.

E ≈ 380 V

Hence The electric field strength (E) is 380 V.

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Answer:

Explanation:

Answer: B. 3.63 E 6 km

The equation for gravitational force is F = G*m1*m2/r2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them. We can rearrange the equation to solve for r: r = (G*m1*m2/F)1/2.

Using the given values, we can calculate the distance between the Earth and the moon at the closest point: r = (6.67 E−11 N*m2/kg2 * 5.97 E24 kg * 7.35 E22 kg / 2.22 E 20 N)1/2 = 3.63 E 6 km.

Therefore, the answer is B. 3.63 E 6 km.

The pressure of the oxygen gas is 2.95 x 10⁵ Pa.

The pressure of the oxygen gas is calculated by applying the following formula as shown below.

Mathematically, the formula for the pressure of a gas at given root mean square pressure is given as

P ( O₂ ) = [ ( n R ( v² M / 3R ) / ( VO₂ ) ]

where;

P ( O₂ ) = [ ( n x  v² M ) / (3 x VO₂ ) ]

The pressure of the oxygen gas is calculated as follows;

P ( O₂ ) = [ ( 12 x 480²  x 0.032 ) / ( 3 x 0.1 ) ]

P ( O₂ ) = 2.95 x 10⁵ Pa

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Answer:

1.98×1020 N 1.98 × 10 20 N

Explanation:

The gravitational force between the Earth and the Moon is 1.98×1020 N 1.98 × 10 20 N.

Answer:

I need this message as well so please ket me know when you have it

A potter’s wheel moves from rest to an angular speed of the angular acceleration is 0.006 rad/s^2.

What is acceleration ?

Acceleration is the rate of change of velocity over time. It is the rate at which an object's speed, or the magnitude of its velocity, changes over time. Acceleration can be positive, negative, or zero depending on the direction of the velocity. For example, if an object is moving in a straight line and its speed increases,

it is said to have a positive acceleration; if its speed decreases, it has a negative acceleration. If the object's speed does not change, then the object is said to have a zero acceleration. Acceleration is a vector quantity, meaning it has both magnitude and direction.

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Answer:

do it your self like who does that

According to the question: the net force on the roof is 8.45 kN.

The vector sum of the forces operating on a particle of object is known as the net force in mechanics. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force. In accordance with Newton's second rule of motion, it causes the particle to accelerate at a rate equal to the sum of all those actual forces.

The net force on the roof is equal to the air pressure multiplied by the surface area of the roof. The air pressure is equal to the density of the air multiplied by the wind speed squared. Therefore, the net force on the roof can be calculated as follows:
Force = (density x wind speed²) x surface area
Force = (1.29 kg/m² x (40 m/s)²) x (250 cm²)
Force = 8.45 kN
Therefore, the net force on the roof is 8.45 kN.

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Answer:

Explanation:

1. Heat: Re-entry into Earth’s atmosphere generates a huge amount of heat due to friction between the object and the atmosphere. This is especially true for objects traveling at high speeds, like a spacecraft. The heat generated from re-entry can cause the object to break apart due to the extreme temperatures.

2. Air Resistance: Re-entry into Earth’s atmosphere also generates a great deal of air resistance. This air resistance can cause the object to slow down or even change direction. This can be dangerous if the object is traveling too fast or if the air resistance is too great.

3. Drag Force: Drag force is the force generated by the air molecules around the object. This force is responsible for slowing down the object as it re-enters the atmosphere. The amount of drag force depends on the size and shape of the object, as well as the speed and direction of the object.

4. Angle of Attack: The angle of attack is important in determining how an object enters the atmosphere. If the angle of attack is too high, the object can be destroyed due to the extreme heat and air resistance. If the angle of attack is too low, the object can skip off the atmosphere and continue in its original trajectory.

5. Ablative Heat Shield: Ablative heat shields are commonly used to protect objects from the extreme heat and air resistance encountered during re-entry. These shields are made of specialized materials that can withstand the extreme temperatures and ablate (or burn away) as the object re-enters the atmosphere.

The features of a Desert Climate sare mainly associated with the absence of precipitation and high solar radiation (question a), plants adapt to live in that type of climate due to the close of stomata and avoiding the presence of many leaves that lose too much water and or succulence in the plant shoot (questions b and c).

The relationship between desert conditions and plant adaptations in terms of evolution is based on certain anatomical and or physiological features used by these organisms to avoid the excessive loss of water under extreme desertic conditions such as the presence of small leaves and close stomata.

Therefore, with this data, we can see that plant adaptations in terms of evolution in desert environments are mainly associated with small leaves and also close stomata for gas exchange.

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Answer:

d. 16 kg-m/s

Explanation:

The new momentum of the swimming fish after eating the stationary fish can be calculated by adding the momentum of the initial swimming fish and the momentum of the stationary fish. Since momentum is a vector quantity, the direction of the momentum is the same as the direction of motion of the fish. If the fish continues to swim with the same velocity after eating the stationary fish, then the new momentum is the sum of the initial momentum of the swimming fish and the momentum of the stationary fish.

Initial momentum of swimming fish = 8 kg-m/s

Momentum of stationary fish = 2 kg * 0 m/s = 0 kg-m/s

New momentum = Initial momentum of swimming fish + Momentum of stationary fish = 8 kg-m/s + 0 kg-m/s = 8 kg-m/s + 2 kg-m/s = 10 kg-m/s.

So, the correct answer is (d) 16 kg-m/s.

Answer:

C

Explanation:

Using law of conservation of momentum of the system

Momentum before = momentum after

         8 kg m/s       = 8 kg m/s

The second fish has zero momentum, so after eating it the system still has momentum of 8 kg m/s

As per the problem statement the average angular acceleration is 4.7/4.5 = 1.78 rad/s2

The rate at which the angular velocity of an item changes over time is known as its angular acceleration. It is a vector quantity that describes the rate of change in angular velocity, which is the rotational equivalent of linear acceleration. It is the angular equivalent of linear acceleration, which is the rate of change of linear velocity over time. Angular acceleration is typically expressed in units of radians per second squared (rad/s2).  It is also referred to as angular je rk, angular deceleration, or angular frequency.

The average angular acceleration is 1.78 rad/s2.
This is calculated by taking the change in angular speed (8.1 - 3.4 = 4.7) and dividing it by the time interval (4.5 s).
Thus, the average angular acceleration is 4.7 / 4.5 = 1.78 rad/s 2.

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There could be several explanations for the discrepancies in the number of aggressive behaviors observed by the research assistants, but the most likely explanation is that the observations were subjective and prone to bias.

1. Observer bias: The research assistants may have different definitions of what constitutes aggressive behavior, or they may have different levels of sensitivity to detecting aggressive behaviors. This can lead to different interpretations of the same behavior and result in different counts.

2. Different focus: The research assistants may have focused on different aspects of the gaming session and paid attention to different details, resulting in different counts.

3. Fatigue: The research assistants may have become less attentive or less accurate in their counting as the gaming session progressed, which could explain why some of the counts are higher than others.

4. Confirmation bias: Research assistants may have been more likely to notice behaviors that confirm their preconceptions about the gamer, leading to counts that are higher or lower than what was actually observed.

5. Different cultural background: Research assistants from different cultural background may have different understanding of what is aggressive behavior.

The compressive force that would be enough to produce a fracture is 4000 N.

We know that the femur is one of the most important bones that we have in the human body. In this case, we have been told that In the human femur, bone tissue is strongest in resisting compressive force, approximately half as strong in resisting tensile force, and only about one- fifth as strong in resisting shear force.

Then we know that;

Tensile force = 8000

The compressive force would be half of this magnitude as such;

Compressive force = 4000 N

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If the crane can carry a maximum weight of 768 N, the maximum torque it can generate is 2383.4 N

The axis of rotation is the point at which the item rotates, and torque is the twisting force that causes rotation. Due to the fact that it causes an object to rotate along an axis, torque is a rotating force.

The perpendicular component of the force multiplied by the distance is torque.

T = F _|_ T

Part One

T = (768 N cos 13.9°) (16.0 m)

T = 10,368 Nm

Part Two

10368 Nm = (F cos 27.0°) (16.0 m)

F = 2383.4 N

Hence, maximum torque can the crane with-stand if the maximum load the crane can handle is 768 N is 2383.4 N

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Answer:

Biotic

Explanation:

In a particular ecosystem, caterpillar and parts of the soil are biotic components

I hope this helps - please mark as brainliest!

Answer:

1Vacuum, 2Gas, 3Liquid, 4Solid.

Explanation:

300,000  273,400  205,600  116,878

Answer:

Solids - fastest

Liquids - faster

Gases - slowest

Vacuum - Not at all

Explanation:

Sound waves have different speed in different mediums because:

different mediums have different densities so that's why speed is different (because speed of sound depends on density of mediums).

( 1) The net gravitational force between the 74.8 kg mass is  8.09 x 10⁻⁵ N.

( 2) The distance from the from the 494 kg mass where the middle mass experiences net zero force is 0.258 m.

The net gravitational force between the 74.8 kg mass is calculated by applying Newton's law of universal gravitation as shown below.

F = ( GmM ) / ( R² )

where;

The force between the first mass and the middle mass is calculated as;

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( 0.198² )

F' = 1.8 x 10⁻⁵ N

The force between the third mass and the middle mass is calculated as;

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.198² )

F'' = 6.29 x 10⁻⁵ N

The net gravitational force on the middle mass;

F (net)  = 6.29 x 10⁻⁵ N + 1.8 x 10⁻⁵ N

F ( net ) = 8.09 x 10⁻⁵ N

Let the distance of zero net force = d

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( d² )

F' = 0.704 x 10⁻⁶ / d²

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.396 - d )²

F'' = 2.47 x 10⁻⁶ / ( 0.396 - d )²

for zero net force, the two forces must be equal

0.704 x 10⁻⁶ / d²  = 2.47 x 10⁻⁶ / ( 0.396 - d )²

0.704 (0.396 - d )² = 2.47d²

(0.396 - d )²  = ( 2.47d² ) / ( 0.704 )

(0.396 - d )²  = 3.51d²

0.396 - d = √ ( 3.51d² )

0.396 - d = 1.87d

1.87d + d = 0.396

d (1.87 + 1) = 0.396

d (2.87) = 0.396

d = 0.396 / 2.87

d = 0.138 m

The distance from the 494 kg mass = 0.396 - 0.138 m = 0.258 m

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The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.

To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:

d = vt + 1/2at²

where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.

Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.

Assume that the time at which they meet is t, then:

d₁ = 1/2 * 2.4t²

And the equation for the displacement of the second body:

d₂ = 1/2 * 4.8t²

If d₁ = d₂

then, 1/2 * 2.4t² = 1/2 * 4.8t²

Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2

So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.

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If  the maximum acceleration is equal to maximum velocity, then frequency of applied force is equal to natural frequency of the vibrating body.

A simple harmonic motion is characterized by this changing acceleration that always is directed toward the equilibrium position and is proportional to the displacement from the equilibrium position.

Mathematically, the formula for the maximum acceleration of a simple harmonic motion is given as;

a ( max ) = ω²A

where;

Resonance vibration is a type of forced vibration in which the natural frequency of vibration of the body is the same as the impressed frequency of external applied force and the amplitude of forced vibration is maximum.

Thus, we can conclude that, the natural frequency of the vibrating body or object is equal to the frequency of the applied force, hence the term resonant vibration.

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The magnitude of the tension in the rope is 12.2625 N, and the rope is being pulled horizontally to the left by the wind force..

What is tension?

Tension is the force transmitted through a string, rope, cable or wire when it is pulled tight by forces acting on it from opposite ends. It is a force that is directed along the length of the string, rope, cable or wire and is always directed away from the object that is creating the tension.

When an object is suspended from a rope or cable, the tension in the rope or cable must be equal to the weight of the object in order for the object to remain stationary or move at a constant velocity. If the tension is less than the weight of the object, the object will fall, and if the tension is greater than the weight of the object, the object will rise.

Tension plays an important role in many areas of physics and engineering, such as in the design of suspension bridges, elevator systems, and the motion of satellites in orbit.

To find the tension in the rope and the rope's angle from the vertical, we can start by drawing a free body diagram of the object:

       Tension (upwards)

                   |

                   |

                   |

                   |

        Weight (downwards)

                   |

                   |

                   |

                   |

Wind force (to the right)

where Tension is the tension in the rope, Weight is the weight of the object, and Wind force is the horizontal force due to the wind.

The object is in equilibrium, so the net force on it is zero. We can write two equations based on the forces in the vertical and horizontal directions:

Vertical equilibrium:

             Tension - Weight = 0

                Tension = Weight

Horizontal equilibrium:

   Wind force = Tension * sin(theta)

where theta is the angle between the rope and the vertical.

We can solve these equations for the tension and theta:

Weight = m * g = 1.25 kg * 9.81 m/s^2 = 12.2625 N

Tension = Weight = 12.2625 N

sin(theta) = Wind force / Tension = 18.3 N / 12.2625 N = 1.492

Since sin(theta) is greater than 1, there is no solution for theta. This means that the rope is not making an angle with the vertical, and is instead being pulled directly to the left by the wind force.

Therefore, the magnitude of the tension in the rope is 12.2625 N, and the rope is being pulled horizontally to the left by the wind force.

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The time spent after dropping the reward snack is

Generally, To determine how long it takes Frici to arrive at his plate after the treat is dropped, we need to calculate the time it takes for the sound of the treat hitting the plate to reach Frici, and then add the time it takes for Frici to run back home.

Sub-question 1: The time it takes for the treat to fall from a height of 125 cm can be calculated using the formula:

t = √(2h/g)

where

t = √(2*1.25/10)

= 0.5 seconds

Sub-question 2: The time it takes for the sound to reach Frici can be calculated using the formula:

t = d/s where d is the distance

30 meters + 300 meters = 330 meters

and s is the speed of sound (330 m/s).

So, t = 330/330

= 1 second

Sub-question 3: Frici's reaction time is 0.1 seconds and he runs at a speed of 6.6 m/s, so the time it takes for him to reach his plate can be calculated using the formula:

t = d/s

where

d is the distance (30 meters) and s is his running speed (6.6 m/s).

So,

t = 30/6.6

= 4.55 seconds

Therefore, the total time it takes for Frici to arrive at his plate is: 0.11 seconds (time for treat to fall) + 1 second (time for sound to reach Frici) + 4.55 seconds (time for Frici to run back) = 5.66 seconds

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The temperature increase over the last 60 years is  4.35 * 10¹⁰ K, the volumetric expansion over this temperature increase is 1.24 * 10¹⁶ km³ and the height of the ocean is increased by 3.44*10¹⁰ km

Heat transfer refers to the movement of thermal energy from a high-temperature body to a low-temperature body. There are three main types of heat transfer: conduction, convection, and radiation.

a) To find the temperature increase of ocean water on average over the last 60 years, we can use the formula for heat energy:

q = mcΔT

Where:

q = heat energy acquired by the oceans (228*1021J)

m = mass of the ocean water (density x volume)

c = specific heat of sea water (approximately 3850 J/(kg K))

ΔT = change in temperature

Given that the area of the ocean is 361106 km² and the average depth of the ocean is 3.682 km, the volume of the ocean can be calculated as:

V = A x D = 361106 km² x 3.682 km = 1.329*10⁶ km³

Given that the density of sea water is 1023.6 kg/m³, the mass of the ocean water can be calculated as:

m = V x ρ = 1.329 * 10⁶ km³ x 1023.6 kg/m³ = 1.36 * 10⁹ kg

Now, we can substitute these values into the equation for heat energy to find the change in temperature:

q = mcΔT

ΔT = q / (m x c)

Substituting the values we get:

ΔT = (228*10²¹J) / (1.36 *10⁹ kg x 3850 J/(kg K)) = 4.35 * 10¹⁰ K

Therefore, the temperature increase of ocean water on average over the last 60 years is 4.35 * 10¹⁰ K.

b) To find the volumetric expansion of the ocean as a result of this temperature increase, we can use the formula for volume expansion due to temperature change:

ΔV = βVΔT

Where:

ΔV = change in volume

V = initial volume of the ocean

β = coefficient of volume expansion

ΔT = change in temperature

Given that the coefficient of volume expansion can be taken to be 0.21*10⁻³ C⁻¹, we can substitute the values we have into the equation:

ΔV = 0.21*10⁻³ C⁻¹ * 1.36*10⁹ km³ * 4.35 * 10¹⁰ K = 1.24 *10¹⁶ km³

Therefore, the volumetric expansion of the ocean as a result of this temperature increase is 1.24 * 10¹⁶ km³

c) If the area of the ocean is considered constant, we can use the volumetric expansion to find the change in height of the ocean surface. The change in height can be calculated by:

ΔH = ΔV / A

Where:

ΔH = change in height

ΔV = change in volume

A = area of the ocean

Substituting the values we get:

ΔH = (1.24 * 10¹⁶ km³) / (361106 km2) = 3.44 *10¹⁰ km

Therefore, the average height of the ocean surface has increased by 3.44*10¹⁰ km due to this heat influx.

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Answer:

4300N

Explanation:

Based on the free body diagram, the friction (fFr in the attached diagram) is dependent on the reaction force (Rn in the attached diagram) acting on the object, in this case a car. The frictional force will always act against the direction of movement (DOM in the attached diagram.)

Given the condition is dry,

Summation of forces in the vertical direction (Positive for upward forces) = 0

Reaction Force - Weight of car = 0

Reaction Force = Weight of car = 14000N

Since the friction is dependent on the reaction force with the formula: Coefficient of friction X Reaction Force,

Friction (Dry Condition) = 0.7 * 14000N = 9800N

Now given the condition is wet,

We will use the same formula but with a change to the coefficient of friction.

Friction (Wet Condition) = 0.4 * 14000N = 5600N

Difference between them = 9800N - 5600N = 4300N.

Answer:

Charles law and Boyle's law, Dalton law of partial pressure, Graham law of diffusion of gases.

Explanation:

let's hangout sometime