A ladder and a ramp are one analogy for quantized vs, continuous theories of energy. 'Think of another analogy to compare the two theories and draw a diagram to represent it.

The percent dissociation of hydrocyanic acid under these conditions is 11.81 %.

Balanced equation of hydrocyanicacid acid dissociation in water:

HCN(aq) → H⁺(aq) + CN⁻(aq)

pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.

pH(HCN) = 2.33

c(H⁺) = 0.467 M; concentration of hydrogen ions

c(H⁺) = c(CN⁻); from the chemical equation

c(HCN) = 4.420 M; concentration of the hydrocyanic acid

percent dissociation = (concentration of H⁺/concentration of acid) x 100%

the percent dissociation = (0.467 M / (4.420 M - 0.467 M)) × 100%

the percent dissociation = 11.81 %.

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Answer:

Covalent

Explanation:

3-bromo-1-butene is the end product of adding 1 equivalent of HBr to 1,3-butadiene.

The alkene butene, often known as butylene, has the chemical formula C4H8. Any of the several chemicals may be referred to by the word "butene." They are odorless gases that are found in crude oil in trace amounts that are insufficient for practical extraction.

In the manufacturing of rubber and gasoline, 1-butene is used to create a wide range of compounds. Alkylate and polymer gasoline are used to make more than half of the butene produced worldwide. A third is utilized directly as fuel, primarily as fuel gas or blendstock for gasoline, without any conversion.

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The pH of the acid solution after the chemist has added 172.mL of the KOH solution to it is 12.6.

When potassium hydroxide and benzoic acid mix to make benzoate, the reaction produces a weak acid and its conjugated base, which causes the solution to function as a buffer. Benzoic acid, which has a molarity of 0.8700 M and a volume of 60.5 ml, is mentioned in the question. As a result, the moles of benzoic acid

Moles are determined by dividing the molarity by the volume of the solution.

=60.50 ml * 0.8700 M or 52.365 mmol, or 0.052365 mole

only 52.365 m mol of KOH will react with the benzoic acid. The moles of KOH, which remain unreactive is,  

61.92 m moles - 52.365 m moles = 9.285 m moles or 0.009285 moles

The formula for calculating molarity is amount of moles / volume of solution in liters

The total volume of the solution is 172 ml + 60.5 ml = 232.5 ml or 0.2325 L

The molarity of KOH will be,  

Molarity = 0.009285 moles / 0.2325 L = 0.0395 M

The dissociation of KOH takes place completely to produce hydroxide ion.  

pOH = -log[0.0395] = 1.4

pH + pOH = 14

pH = 14 - 1.4 = 12.6

The complete question is,

An analytical chemist is titrating 60.5mL of a 0.8700M solution of benzoic acid HC6H5CO2 with a 0.3600M solution of KOH . The pKa of benzoic acid is 4.20 . Calculate the pH of the acid solution after the chemist has added 172.mL of the KOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round your answer to 2 decimal places.

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Answer:

The net force on a car is zero in both the horizontal and vertical directions

Given that an average person burns about 100 calories when running a mile, after eating a candy bar, you must run 2.55 miles to burn it off.

The amount of energy in an item of food or drink is measured in calories.

If a candy bar has 30 g of sugar (which has 4 calories/g) and 15 g of fat (which has 9 calories/g), then the total calories each candy bar has is:

sugar : 30g(4 calories/g) = 120 calories

fat : 15g(9 calories/g) = 135 calories

candy bar = 120 + 135 = 255 calories

If you eat a candy bar that has 255 calories, and an average person can burn 100calories/mile running, then,

x = 255 calories/(100calories/mile)

x = 2.55 miles

where x = number of miles you need to run to burn off the calories

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Only a few locations on an enzyme, with or without a substrate, can be occupied by a noncompetitive inhibitor at one time.

This is due to the fact that it alters an enzyme's conformation as well as its active site, which prevents the substrate from binding to the enzyme properly and lowers the enzyme's effectiveness.

When an inhibitor binds to an enzyme away from the active site, it changes or distorts the structure of the enzyme, which reduces the effectiveness of the active site even though the substrate can still bind. Most of the time, the inhibitor is also reversible.

Examples of non-competitive inhibition include the inhibitory effects of heavy metals, cyanide on cytochrome oxidase, and arsenate on glyceraldehyde phosphate dehydrogenase.

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The aldol condensation product crystals was washed with a solution of 4% acetic acid in 95% ethanol. Because this combination eliminates the base used in the reaction, it has the ability to slow down the self-condensation process of the carbonyl compound in the aldol reaction.

The aldol reaction is accompanied by the dehydration reaction, which produces conjugated enone. It also contributes to the creation of a carbon-carbon bond. The aldol condensation reaction is an organic synthesis that accounts for the formation of?-hydroxyketone or ?-hydroxyaldehyde  from the reaction of  an enol or an enolate ion and a carbonyl compound.

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Density in si = 1.99  slug/ft3 = 1.99 * 515.3788 kg/m³ = 1025.60 kg/m³

Specific weight is 1025.60 kg.

What is density?

The definition of density is the mass of a substance per unit volume. The ratio of mass to volume is known as density, or mass per unit volume. It gauges how much material an object contains in relation to its volume (cubic metre or cubic centimeter). In essence, density is a measurement of how closely together matter is packed.

1 slug/ft3 = 515.3788184 kg/m3.

1 slug = 14.5939029372 kg

Thus, 1.99  slug/ft3 = 1.99 * 515.3788 kg/m³ = 1025.60 kg/m³

Specific weight is 1025.60 kg.

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To prepare 1 M, 850 ml boric acid solution, 52.7 gm solute is reported.

What is stock solution?

Simply said, a stock solution is a concentrated form of the "working solution" you used to conduct your experiment. This is typically done if the more diluted working solution degrades or decomposes quickly over time.

Stock solutions are used to speed up the preparation process, save time and resources, free up space in storage, and increase the precision with which working lower concentration solutions are made. The main benefits of adopting stock solutions are that they are easier to measure and save time when manufacturing solutions.

We know that,

Molarity (M) = Moles of solute ÷ liters of solution

Let's assume to prepare 1M, 850 ml (= 0.85 liter) boric acid solution, X mole solute is required.

So,  1 = X ÷ 0.85

Or,.  X = 0.85

Molecule weight of boric acid  62 gm.

So,

    1 mole boric acid = 62 gm boric acid

   0.85 mole boric acid = 62×0.85 gm. Boric acid

                                     = 52.7 gm.

To prepare 1 M, 850 ml boric acid solution, 52.7 gm solute is reported.

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Answer:

In explanation

Explanation:

1. 2, 2, 1

2. 2, 4, 1

3. 2, 1, 1

Explanation:

Ionic compounds are compounds composed of ions held together by electrostatic force called ion bounding.

The approximate mass percent of hydrogen in propyne 10%.

One carbon atom has mass of 12 amu (unified atomic mass). One unified atomic mass unit is approximately the mass of one nucleon (proton or neutron).

m(C) = 12 amu; mass of the carbon atom

m(H) = 1 amu; mass of the hydrogen atom

m(C₃H₄) = 3 × m(C) + 4 × m(H)

m(C₃H₄) = 3 × 12 amu + 4 × 1 amu

m(C₃H₄) = 40 amu; mass of the propyne molecule

ω(H) = 4 × m(H) ÷ m(C₃H₄) × 100%

ω(H) = 4 × 1 amu ÷ 40 amu × 100%

ω(H) = 10%; the approximate mass percent of hydrogen in propyne

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The chemical element lithium has the symbol Li and atomic number 3. A delicate, silvery-white alkali metal, it is. It is the least dense solid element and the least dense metal under typical conditions.

What happens to the solid lithium when the temperature was decreased?

"Nothing changed."

With their high energy and power densities, lithium-ion batteries (LIBs) perform well in a variety of applications. However, the effect of temperature still has an impact on LIB performance. Normal operating range for LIBs is between 20 °C and 60 °C. Outside of this range, both low and high temperatures will result in decreased performance and permanent harm, such as thermal runaway and lithium plating.

At low temperatures, the components of a lithium-ion battery are also less compatible. The "vulnerability" of lithium-ion batteries at low temperatures is due to this. If a lithium-ion battery is overworked (high current charging and discharging), the resistance will increase and the capacity will decrease even more quickly. A "cold" lithium-ion battery will operate with greater resistance (increased resistance) and less effectively (rapid reduction in actual capacity).

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