Answer:
False
Explanation:
It would be a screw
The amount of kinetic energy an object has depends on which feature of the object?
Answer:
Mass and speed.
Explanation:
The amount of kinetic energy of an object depends on the object's mass and speed.
Answer:
its a motion hope this helps
Explanation:
A mountain lion jumps to a height of 3.25 m when leaving the ground at an angle of 43.2°. What is its initial speed (in m/s) as it leaves the ground?
Recall that
[tex]{v_f}^2={v_i}^2+2a\Delta y[/tex]
where [tex]v_i[/tex] and [tex]v_f[/tex] are the lion's initial and final vertical velocities, [tex]a[/tex] is its acceleration, and [tex]\Delta y[/tex] is the vertical displacement.
At its maximum height, the lion has 0 vertical velocity, so we have
[tex]0={v_i}^2-2gy_{\rm max}[/tex]
where g is the acceleration due to gravity, 9.80 m/s², and we take the starting position of the lion on the ground to be the origin so that [tex]\Delta y=y_{\rm max}-0=y_{\rm max}[/tex].
Let v denote the initial speed of the jump. Then
[tex]v_i=v\sin(43.2^\circ)=\sqrt{2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(3.25\,\mathrm m)}\implies\boxed{v\approx11.7\dfrac{\rm m}{\rm s}}[/tex]
The initial speed will be "11.7 m/s".
Speed and Displacement:Given:
Height = 3.25 mAngle = 43.2°Acceleration due to gravity = 9.8 m/s²We know,
→ [tex]vf^2=v_i^2+2a\Delta y[/tex]
At max. height, vertical height be zero, then
→ [tex]0 = v_i^2-2gy_{max}[/tex]
or,
→ [tex]\Delta y = y_{max} -0 = y_{max}[/tex]
now,
The initial speed,
→ [tex]v_i = v \ Sin(43.2^{\circ})[/tex]
By substituting the values,
[tex]= \sqrt{1\times 9.8\times 3.25}[/tex]
[tex]= 11.7 \ m/s[/tex]
Thus the solution above is correct.
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An object travels due North and covers 500 miles in 5 hours. Which one of the following is the average velocity of the object?
a) 100 mph
b) 2500 mph
c) 2500 mph due North
d) 100 mph due North
Answer:
100 mph.
Explanation:
Given that,
Distance covered by an object is 500 miles in 5 hours.
We need to find the average velocity of the object. It can be given by :
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500\ \text{miles}}{5\ \text{hour}}\\\\v=100\ \text{mph}[/tex]
Hence, the average velocity of the object is 100 mph.
Which statement describes a controlled experiment?
A. It includes more than one control group.
B. It includes a control group and an experiment group.
C. It includes only the control group.
D. It includes only an experimental group.
Answer:
B
Explanation:
I think this is right.
If it is Good luck!
The controlled experiment includes a control group and an experiment group, this statement describes a controlled experiment, therefore the correct answer is option B.
What is the scientific investigation?Scientific discovery is the method of finding solutions through in-depth analysis and discovering them through the outcomes of experiments.
True experimental outcomes that can be backed up by data are incredibly important to scientific inquiry.
A regulated investigation where all sensors to measure have been held constant and the scientific element is utilized as a factor associated.
Since the statement depicts a controlled experiment with a control group and an experiment group, option B is the appropriate response.
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A 50.0-g Super Ball traveling at 25.5 m/s bounces off a brick wall and rebounds at 21.0 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 4.45 ms, what is the magnitude of the average acceleration of the ball during this time interval
Answer:
The magnitude of the average acceleration of the ball during this time interval is 10,449.44 m/s²
Explanation:
Given;
mass of super ball, m = 50 g
initial velocity of the ball, u = 25.5 m/s
final velocity of the ball, v = -21 m/s (re-bouncing backward)
time in contact with the wall, t = 4.45 ms = 0.00445 s
The average acceleration of the ball during this time interval is given by
[tex]a = \frac{dv}{dt} = \frac{v-u}{t} \\\\a = \frac{-21-25.5}{0.00445}\\\\a = -10449.44 \ m/s^2\\\\|a| = 10,449.44 \ m/s^2[/tex]
Therefore, the magnitude of the average acceleration of the ball during this time interval is 10,449.44 m/s²
An ideal monatomic gas initially has a temperature of T and a pressure of p. It is to expand from volume V1 to volume V2. If the expansion is isothermal, what are the final pressure pfi and the work Wi done by the gas? If, instead, the expansion is adiabatic, what are the final pressure pfa and the work Wa done by the gas? State your answers in terms of the given variables.
Answer:
Isothermal : P2 = ( P1V1 / V2 ) , work-done [tex]pdv = nRT * In( \frac{V2}{v1} )[/tex]
Adiabatic : : P2 = [tex]\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }[/tex] , work-done =
W = [tex](3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)[/tex]
Explanation:
initial temperature : T
Pressure : P
initial volume : V1
Final volume : V2
A) If expansion was isothermal calculate final pressure and work-done
we use the gas laws
= PIVI = P2V2
Hence : P2 = ( P1V1 / V2 )
work-done :
[tex]pdv = nRT * In( \frac{V2}{v1} )[/tex]
B) If the expansion was Adiabatic show the Final pressure and work-done
final pressure
[tex]P1V1^y = P2V2^y[/tex]
where y = 5/3
hence : P2 = [tex]\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }[/tex]
Work-done
W = [tex](3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)[/tex]
Where [tex]T2 = T1V1^(2/3)/V2^(2/3)[/tex]
Why does wine go sour faster
it the cork is removed from the
bottle
Convert a speed of 4.50 km/h to units of ft/min. (1.00 m = 3.28 ft).a. 165 ft/min.b. 82.3 ft/min.c. 886 ft/min.d. 246 ft/min.e. 0.246 ft/min.
Answer:
246ft/min
Explanation:
In this problem we are faced with unit conversion.
We are expected to convert from km/h to ft/min
Given that
1.00 m = 3.28 ft
1km(1000m)= 3280 ft
But we need to convert 4.5km to ft
Hence in ft 4.5km= 3280*4.5
= 14760ft
We now convert hour to minutes
60min make 1 hour
Therefore the convert form km/h to ft/min is
= 14760/60= 246ft/min
The answer is 246ft/min
Newtons first law of motion describes
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
How can you serve the community through NSTP subject
Answer:
The answer is below
Explanation:
NSPT is an acronym for the National Service Training Program. It deals with the individual's role in society building. Most specifically, the youths in areas such as physical, ethical, virtuous, intellectual, and social well-being.
One can serve the community through the NSTP subject, by involving in creating awareness in literacy and social welfare undertakings, mostly during emergencies and mishaps, or be part of the Citizen Armed Force.
Which laboratory activity involves a chemical change?
Answer:
A: leaving a copper penny in vinegar until it turns green
Explanation:
The corrosion is from oxidation -- a chemical reaction between the metal and oxygen, water, and carbon dioxide in the air. Rust is the term used to describe this process when it happens to iron instead of other metals. I also took it on E2020. If you need further explanation, please comment below.
The laboratory activity which involves a chemical change is leaving a copper penny in vinegar until it turns green.
What are chemicals?The chemicals are the artificially prepared or purified and a distinct compound or substance.
The corrosion is the result of oxidation that is a chemical reaction between the metal and oxygen, water, and carbon dioxide in the air. Rust is the term used to describe the corrosion process.
Corrosion also takes place in copper due to which the copper turns green when oxidized.
Thus, The laboratory activity which involves a chemical change is leaving a copper penny in vinegar until it turns green.
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Question 1 (1 point)
Meliodas gets up in the morning and then follows his per pig Hawk a distance of 12 km away from his home. They stop, have a picnic, look as
some butterflies, and talk about their epic adventures, They make it halfway back before the food they are (Meliodas made it) makes them feel
sick so they stop to camp for the night,
How far did they travel (their distance)?
How far are they from home (their displacement)?
Answer:
Travelled 18 km, they are 6 km from home.
Explanation:
12/2 (halfway) is 6km. So, 6 + 12 would be 18 km, total amount travelled. The total distance of the trip would be 24 km (12 km out, 12km back) if they travelled 12+6 (18km) then they only have 6 km more to go.
A basketball is shot. After the ball leaves the player's hand, in which direction does the ball accelerate?
A)It always accelerates in the opposite direction that the object is moving.
B) It always accelerates in a upward direction.
C) It always accelerates in a downward direction.
D) It accelerates upward when the ball is rising and downward when it is falling.
Answer: Always accelerates in a downward direction
Explanation: Gravity is pulling the ball downward
A car speeds up from 12.0 M/S to 16.0 M/S in 8.00 S what is the acceleration of the car
We have,
Initial velocity,u = 12 m/s
Final velocity,v = 16 m/s
Time taken,t = 8 s
Now,
[tex] \sf \: a = \frac{v - u}{t} [/tex]
[tex] \bf \implies \: a = \frac{16 - 12}{8} [/tex]
[tex] \bf \implies a = \frac{4}{8} [/tex]
[tex] \bf \implies \: a = 0.5 \: m {s}^{ - 2} [/tex]
Where do the local stall patterns occur for a Rectangular wing with no sweep?
a. Wing Tip
b. Wing Root
c. Leading Edge
a. Mean Aerodynamic Chord
Answer:
The answer is "Option b"
Explanation:
The root of the wing is also known as the wing portion of its airframe nearest to a chamfer or winged spaceship. It's typically helpful to identify either a basic monoplane layout.
The use of floats often known as "wing fillets", that was popularised within the first half of the 20th Century, in such a bid to reduce interference here between wings and fuel tank. It used in fasteners achieved more desirable flying property at both higher and lower speeds.For a point charge, how does the potential vary with distance from the point charge, r?
b. r.c. 1/r.d. 1/r2.e. r2.
For a point charge, how does the potential vary with distance from the point charge, r?
a constant
b. r.
c. 1/r.
d. [tex]1/r^2[/tex].
e. [tex]r^2[/tex].
Answer:
The correct option is C
Explanation:
Generally for a point charge the electric potential is mathematically represented as
[tex]V = \frac{k Q }{r }[/tex]
Here we can deduce that the electric potential varies inversely with the distance i.e
[tex]V \ \alpha \ \frac{1}{r}[/tex]
So
The potential should vary with distance from the point charge r should be option c. 1/r.
What is a point charge?The point charge with respect to the electric potential should be expressed in
V = KQ/r
Here we can say that the electric potential should be varied oppositely with the distance
Here is the electric file with respect to the point charge should be obtained from the Coulomb law. It should be radially outward from the point charge in all types of directions.
Therefore, the option c is correct.
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You collect some data on horse racing along a straight track. You are able to fit the motion of the horse to a function during this interval, where you’ve chosen a particular spot on the track to be your origin and started your clock (t = 0) when you started collecting this new data.Required:a. What is the horse’s velocity as a function of time? Does the horse ever turn around during this time?b. What is its acceleration as a function of time?
Answer:
The equation is missing in the question. The equation is [tex]$10 m + 5(m/s^2)t^2+3(m/s^3)t^3$[/tex]
a). [tex]$v=10 t +9t^2$[/tex] , the horse will not turn.
b). a(t) = 10 + 18t
Explanation:
Given :
[tex]$x(t)=10 m + 5(m/s^2)t^2+3(m/s^3)t^3$[/tex]
∴ At t =0, x = 10 m
a). Velocity as a function of time
[tex]$v = \frac{dx}{dt} $[/tex]
= [tex]$10 t +9t^2$[/tex]
Turning velocity must be zero.
v(t) = 0
[tex]$10 t +9t^2=0$[/tex]
[tex]$\therefore t = 0 \text{ or}\ t =-\frac{10}{9}$[/tex]
Taking the positive value of time.
The horse will not turn.
b). Acceleration as a function of time.
[tex]$a(t)=\frac{dv}{dt}$[/tex]
= 10 + 18t
∴ a(t) = 10 + 18t
A hot air balloon is ascending straight up at a constant speed of 6.60 m/s. When the balloon is 11.0 m above the ground, a gun fires a pellet straight up from ground level with an initial speed of 30.0 m/s. Along the paths of the balloon and the pellet, there are two places where each of them has the same altitude at the same time. How far above ground level are these places
Answer:
[tex]H_1 =39.05 \ m[/tex] OR [tex]H_2 =14.5 \ m)[/tex]
Explanation:
From the question we are told that
The constant speed of the balloon is [tex]v = 6.60 \ m/s[/tex]
The height of the balloon is [tex]h = 11.0 \ m[/tex]
The initial speed of the pellet is [tex]u = 30 \ m/s[/tex]
Generally the height of the balloon at the point it is the same altitude with the pellet is mathematically represented as
[tex]H = h + v * (t)[/tex]
Note: vt is the distance covered by the balloon before the pellet got to it
Generally the height of the pellet when it is the same height with the balloon is mathematically represented using kinematics equation
[tex]s = ut + \frac{1}{2} gt^2[/tex]
So
H = s
=> [tex] ut + \frac{1}{2} gt^2 = h + v * (t)[/tex]
=> [tex] 30t + \frac{1}{2} *( -9.8)t^2 = 11 + 6.60t[/tex]
=> [tex] 4.9t^2 -23.4t + 11= 0[/tex]
using the quadratic formula to solve the above equation
From the quadratic formula calculation
[tex]t_1 = 4.25 \ s[/tex]
OR
[tex]t_1 = 0.529 \ s[/tex]
So the height of this two place above the ground is mathematically evaluated as
[tex]H_1 = h + v * (4.25)[/tex]
[tex]H_1 = 11 + 6.60 * (4.25)[/tex]
[tex]H_1 =39.05 \ m[/tex]
OR
[tex]H_2 = h + v * ( 0.529)[/tex]
[tex]H_2 = 11 + 6.60 * (0.529)[/tex]
[tex]H_2 =14.5 \ m)[/tex]
Draw two unique free body diagrams that each show a net force of 30 N to the left.
Answer:
just trace a picture of it.
Problem: You and your friend are discussing last week’s recitation problem, in which an electron falling down a tunnel through a uniformly charged earth exhibits simple harmonic motion. Instead of being uniformly charged, imagine that the Earth is given a spherically symmetric charge density ⍴(r)=b/r, where b is a constant. If an electron is released from rest inside this tunnel at some initial distance from the center, find an expression for the acceleration of the electron inside the tunnel (ignore gravity). If the electron is released from rest at the surface, what value of b will ensure that the electron reaches the center of the Earth in 12 seconds? ………………………………………………………………………………………
Answer:
a. a = eb/2ε₀m b. b = 8.91 × 10⁻¹⁸ kg/V
Explanation:
a. Using Gauss' law
ε₀∫E.dA = q where E = electric field and q = charge enclosed.
Now , the charge has a spherical symmetric charge density ⍴(r) = b/r, the total charge enclosed at distance r is given by
q = ∫∫∫ρ(r)r²sinθdrdθdΦ
q = ∫∫∫(b/r)r²sinθdrdθdΦ
q = ∫∫∫brsinθdrdθdΦ
we integrate r from 0 to r, θ from 0 to π and Φ from 0 to 2π
q = ∫∫br[∫sinθdθ]drdθdΦ
q = ∫∫br[-cosθ]drdΦ
q = ∫∫br-[cosπ - cos0]drdΦ
q = ∫∫br-[-1 - 1]drdΦ
q = ∫2brdr∫dΦ
q = ∫2brdr[Φ]
q = ∫2brdr[2π - 0]
q = 4πb∫rdr
q = 4πb[r²/2]
q = 4πb[r²/2 - 0]
q = 2πbr²
The let side of the equation is
ε₀∫E.dA = ε₀E∫dA = ε₀E4πr² since there is spherical symmetry
Equating both sides of the equation
ε₀E4πr² = 2πbr²
E = 2πbr²/ε₀4πr²
E = b/2ε₀
Now, the force acting on the electron , F = ma where m = mass of electron and a = acceleration of electron.
F also equal F = eE where e = electron charge and E = electric filed acting on electron
So, eE = ma
a = eE/m
a = eb/2ε₀m
b. I(f the electron is released from rest and is to reach the center of the earth, it covers a distance of the radius of the earth. Using s = ut + 1/2at² where s = radius of earth = R = 6400 km = 6.4 × 10⁶ m , u = initial velocity = 0 m/s. and a = eb/2ε₀m. Substituting these values into s we have
R = 0t + 1/2(eb/2ε₀m)t²
R = ebt²/4ε₀m
making b subject of the formula, we have
b = 4ε₀mR/et²
when t = 12 s and e = 1.609 × 10⁻¹⁹ C, ε₀ = 8.854 × 10⁻¹² F/m and m = 9.109 × 10⁻³¹ kg.
Substituting these values into b we have
b = (4 × 8.854 × 10⁻¹² F/m × 9.109 × 10⁻³¹ kg × 6.4 × 10⁶ m)/(1.609 × 10⁻¹⁹ C × 12²)
b = 2064.67/ 231.696 × 10⁻¹⁸
b = 8.91 × 10⁻¹⁸ Fkg/C
b = 8.91 × 10⁻¹⁸ kg/V
As a science project, you drop a watermelon off the top of the Empire State Building, 320 m above the sidewalk. It so happens that Superman flies by at the instant you release the watermelon. Superman is headed straight down with a constant speed of 35 m/s. How fast is the watermelon going when it passes Superman
Answer:
70 m/s
Explanation:
The watermelon will go pass superman at the instance when they are at the same distance from the top of the building.
Superman flies by with a constant velocity = 35 m/s
This distance where he will be overtaken by the watermelon will be = vt
where v is his velocity
t is the time the watermelon and superman are side by side
For the watermelon,
the initial velocity u = 0 m/s (since it starts from rest)
The distance where it is side by side with superman will be gotten from the equation
s = ut + [tex]\frac{1}{2}gt^2[/tex]
where is the distance down at which they meet
g is the acceleration due to gravity = 9.81 m/s^2
t is the time they meet
ut = 0, since u = 0 m/s
Equating this distance that they meet, we'll have
vt = [tex]\frac{1}{2}gt^2[/tex]
substituting values, we have
35t = [tex]\frac{1}{2}*9.81*t^2[/tex]
35 = 4.905t
t = 35/4.905 = 7.135 s
The watermelon's speed at this instant can be calculated from
v = u + gt
where v is the velocity at this instant
u = initial speed of the watermelon = 0 m/s
g is the acceleration due to gravity = 9.81 m/s^2
t is the time they meet side by side = 7.135 s
substituting values, we have
v = 0 + 9.81(7.135)
v = 69.99 ≈ 70 m/s
A liquid thermometer can be used to test for fevers. When body temperature increases, the liquid inside the thermometer expands and
rises to show a higher
temperature reading. Which of the following explanations best describes the changes in thermal energy of the
particles during this specific example of heat transfer?
A. The tip of the thermometer is heated by radiation from the person's body. The particles of the thermometer tip then transfer heat
by convection through the liquid inside of it. The particles inside the liquid then convect heat causing the warmer particles to slow
down, rise, and expand.
B. The tip of the thermometer is heated by conduction from the person's body. The particles of the thermometer tip then transfer heat
by convection through the liquid inside of it. The particles inside the liquid then convect heat causing the warmer particles to slow
down, rise, and expand.
© C. The tip of the thermometer is heated by convection with the person's body. The particles of the thermometer tip then transfer heat
by conduction with the liquid inside of it. The particles inside the liquid then conduct heat causing the warmer particles to speed up,
rise, and expand
© D The tip of the thermometer is heated by conduction with the person's body. The particles of the thermometer tip then transfer heat
by conduction with the liquid inside of it. The particles inside the liquid then convect heat causing the warmer particles to speed up,
rise, and expand
Answer:
A
Explanation:
dafdfsfsf
The tip of the thermometer is heated through radiation from the person's body. The particles of the thermometer tip then transfer heat by the convection of heat through the liquid inside of it. The particles inside the liquid then convert heat which causes the warmer particles to slow down, rise, and expand. Thus, the correct option is A.
What is Convection?The process of heat transfer from one part of a fluid to another part of the system or fluid through the actual movement of the particles of the fluid substance is called convection. Liquid and gas particles are heated through the process of convection.
The tip of the thermometer is heated by radiation from the person's body. The particles of the thermometer tip then transfer heat energy through convection of heat through the liquid inside of the thermometer. The particles inside the liquid then convert heat causing the warmer particles to slow down, rise, and expand in the thermometer.
Therefore, the correct option is A.
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Which chemical reaction shows photosynethesis?
Answer: Endothermic Reaction
Explanation: Photosynthesis requires energy right, making it an endothermic reaction. Light, generally sunlight, is the source of this energy. The process converts the sun's electromagnetic energy into chemical energy, which is then stored in chemical bonds in the plant. Which then leads to Photosynthesis occuring.
What statements are true regarding the skydivers jump and fall to Earth?
Regardless of their weight, before opening their parachutes, the guys felt at the same velocity.
According to the data, the acceleration due to gravity is 9.8m/s/s.
Once the parachutes were opened, all five skydivers continued to fall at exactly the same velocity
Opening the parachutes provided air resistance and changed their velocity
By free-falling for a longer period of time, the skydivers would have changed the acceleration due to
gravity
Answer: Regardless of their weight, before opening their parachutes, the guys fell at the same velocity.
According to the data, the acceleration due to gravity is 9.8 m/s/s
Opening the parachutes provided air resistance and changed their velocity.
Explanation:
When in free fall, mass does not affect the speed of moving objects (only gravitational force is acting upon it).
If you take a look at the data, you can see that the velocity is increasing at a constant rate in intervals of 9.8. This is the acceleration which makes sense because acceleration is the change of velocity divided by time.
Think about it: parachutes slow down the object that is falling because it creates a barrier between the object falling and the gravitational force it encounters. The change in the effects of the gravitational force will alter the velocity.
I hope this was helpful. Have a nice day!
n engineer is given the task of comparing the fuel efficiency of four car models. She reports the following findings: Model 1, 14 kilometers per liter. Model 2, 9 miles per liter. Model 3, 56 kilometers per gallon. Model 4, 1600 meters per liter. The data for which two models consistently follow the use of SI units?
D because it uses meters
You toss a ball straight up with an initial speed of 30m/s. How high does it go, and how long is it in the air (neglecting air resistance)?
Explanation:
Given that,
A ball is tossed straight up with an initial speed of 30 m/s
We need to find the height it will go and the time it takes in the air.
At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :
v = u +at
Here, a = -g
v = u -gt
i.e. u = gt
[tex]t=\dfrac{u}{g}\\\\t=\dfrac{30\ m/s}{9.8\ m/s^2}\\\\t=3.06\ s[/tex]
So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds
Let d is the maximum distance covered by it.
[tex]d=ut-\dfrac{1}{2}gt^2[/tex]
Putting all values
[tex]d=30(3.06)-\dfrac{1}{2}\times 9.8\times (3.06)^2\\\\d=45.91\ m[/tex]
Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.
To understand the electric force between charged and uncharged conductors and insulators. When a test charge is brought near a charged object, we know from Coulomb's law that it will experience a net force (either attractive or repulsive, depending on the nature of the object's charge). A test charge may also experience an electric force when brought near a neutral object. Any attraction of a neutral insulator or neutral conductor to a test charge must occur through induced polarization. In an insulator, the electrons are bound to their molecules. Though they cannot move freely throughout the insulator, they can shift slightly, creating a rather weak net attraction to a test charge that is brought close to the insulator's surface. In a conductor, free electrons will accumulate on the surface of the conductor nearest the positive test charge. This will create a strong attractive force if the test charge is placed very close to the conductor's surface.Consider three plastic balls (A, B, and C), each carrying a uniformly distributed charge equal to either +Q, -Q or zero, and an uncharged copper ball (D). A positive test charge (T) experiences the forces. The test charge T is strongly attracted to A, strongly repelled from B, weakly attracted to C, and strongly attracted to D. Assume throughout this problem that the balls are brought very close together. What is the nature of the force between balls A and B? a. Strongly attractive b. Strongly repulsive c. Weakly attractive d. Neither attractive nor repulsive
Answer:
the correct is a Strongly ATTRACTIVE
Explanation:
For this exercise we must use that charges of the same sign repel and charges of the opposite sign attract, the attraction is strong if they are charged or weak if the charges are induced.
Let's apply this to our case.
The test load T is attracted by the sphere A, this implies that the charges are of different sign
the test charge T is repelled by the sphere B, therefore the charges are of equal sign
As the test charge cannot change the sign, this implies that the spheres A and B are of different sign, therefore attractive forces.
Now let's analyze the intensity, as in the exercise they indicate that spheres A and B are charged and are insulators, these charges cannot move, so the attraction must be Strong.
When reviewing the statements, the correct one is a Strongly ATTRACTIVE
Which of these will have the same units if acceleration is multiplied by time? Force Time velocity Pressure
Answer:
Velocity
Explanation:
Velocity equals the original velocity... Plus
the acceleration is multiplied by time.
If the acceleration is multiplied by time then we get velocity as a result, therefore velocity has the same unit.
What is pressure?Pressure is measured as the amount of force applied in the one-meter of area. Pascal is used as the SI unit of it. The amount of pressure can be calculated by dividing the amount of force by the area of force applied. In relation to atmospheric pressure, the pressure is measured. Pressure does not represent any direction, so it comes under a scalar quantity. Many scientific and day-to-day life equipment use pressure principles like gauge meter thermometers in designing cars, ships, and every mechanical part.
We know that acceleration has an SI unit of m /[tex]s^{2}[/tex] So if we multiply the time with an acceleration whose unit is second we will get m / s which is the unit of velocity.
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Consider a monochromatic electromagnetic plane wave propagating in the x direction. At a particular point in space, the magnitude of the electric field has an instantaneous value of 941 V/m in the positive y-direction. What is the instantaneous magnitude of the Poynting vector at the same point and time? The speed of light is 2.99792 x 108 m/s, the permittivity of free space is 8.85419 x 10-12 C2/N/m2 and the permeability of free space is 47 x 10-7 T N/A.
What is the direction of the instantaneous magnetic field?
1. B = - 2.
2. B = +î.
3. B = +j.
4. B = - j.
5. B = +k.
6. B = -k.
7. The magnetic field vector does not have an instantaneous direction.
What is the direction of the instantaneous Poynting vector?
1. Ŝ= -î.
2. Ŝ= -k
3. The Poynting vector does not have an instantaneous direction.
4. Ŝ = tî.
5. Ŝ = +Î.
6. Ŝ= -Î.
7. Ŝ= +ê.
Answer:
a) S = 2.35 10³ J/m²2 ,
b)and the tape recorder must be in the positive Z-axis direction.
the answer is 5
c) the direction of the positive x axis
Explanation:
a) The Poynting vector or intensity of an electromagnetic wave is
S = 1 /μ₀ E x B
if we use that the fields are in phase
B = E / c
we substitute
S = E² /μ₀ c
let's calculate
s = 941 2 / (4π 10⁻⁷ 3 10⁸)
S = 2.35 10³ J/m²2
b) the two fields are perpendicular to each other and in the direction of propagation of the radiation
In this case, the electro field is in the y direction and the wave propagates in the ax direction, so the magnetic cap must be in the y-axis direction, and the tape recorder must be in the positive Z-axis direction.
the answer is 5
C) The poynting electrode has the direction of the electric field, by which or which should be in the direction of the positive x axis
how was the atomic bomb different from conventional bombs?
Answer:
A conventional bomb releases most of its energy in the form of blast. Atomic bombs on the other hand, release 50 per cent energy as blast, 35 per cent as heat and 15 per cent as nuclear radiation.
Explanation:
A conventional bomb releases most of its energy in the form of blast. Atomic bombs on the other hand, release 50 per cent energy as blast, 35 per cent as heat and 15 per cent as nuclear radiation.
