Taking into account the definition of calorimetry, the mass of the coffee is 253.33 g.
CalorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.c is the specific heat sudstance.ΔT is the temperature variation.Mass of coffeeIn this case, you know:
Q= 190 caloriesc= 1 [tex]\frac{cal}{gC}[/tex]m= ?ΔT= 0.75 CReplacing in the equation that allows to calculate heat exchanges is:
190 cal = 1 [tex]\frac{cal}{gC}[/tex]× m× 0.75 C
Solving:
m= 190 cal÷ (1 [tex]\frac{cal}{gC}[/tex]× 0.75 C)
m=253.33 g
Finally, the mass of the coffee is 253.33 g.
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An upward force is applied to a 6.0–kilogram box. This force displaces the box upward by 10.00 meters. What is the work done by the force on the box?
The work done by the force on the box 588 Joule.
What is Potential energy ?It is the energy that is stored in an object due to its position relative to some zero position.
According to the question,
Given mass of the box (m) = 6.0 kg
Given displacement of the box = 10.00 m
Hence , the height of the box (h) = 10.00 m
Acceleration due to gravity (g) = 9.8 m/s²
Since ,
The upward force was applied to the box, the box moves up to the height.
Therefore, the work done by the ball is the potential energy gained by the ball.
By using the formula of potential energy
P.E. = mgh
= 6 × 9.8 × 10 Joule = 588 Joule
As we know .
Work done (W) = Potential energy (P.E.)
Work done (W) = 588 Joule
Thus, 588 Joule is the work done by the force on the box.
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Ivan exerts 20 N of force to lift a basket 2 m. He then carries the basket 5 m across a room to place it on a shelf.
Ivan does work when he
.
The amount of work he does is
The amount of the work done will be 100 J. Work done is denoted by W.
What is work done?Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative.it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.
The given data in the problem is;
F is the force applied = 20 N
d is the displacement = 5.0 m
The work done is found as;
W = F × d
W = 20 N × 5
W= 100 J
Hence, the amount of work done will be 100 J.
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Answer:
lifts the basket, 40J
Explanation:
Which two of the following statements best describe the similarity between elements and compounds? 1. Elements and compounds are listed in the periodic table. 2. Elements and compounds are both pure substances. 3. Elements and compounds are both made of different kinds of atoms. 4. Elements and compounds cannot be broken down by physical changes.
A point charge is placed 3m from a 4uc charge what is the strength of the electric field on the point charge at this distance round to the nearest thousand
The strength of the electric field on the point charge at this distance will be 4000 V/m.
What is the strength of the electric field?
The strength of the electric field is the ratio of electric force per unit charge.
The given data in the problem is;
Qis the unit charge = 4.0 × 10⁻⁶ C
E is the strength of the electric field
R is the distance from point charge = 3 m
The strength of the electric field is;
[tex]\rm E = \frac{KQ}{R^2} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6} \ C}{3^2} \\\\ E= 4000 V/m[/tex]
Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.
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The amplitude of the wave in the picture below is... Select one: a. 1 cm b. 1.5 cm c. 2 cm d. 3 cm
Answer:
1cm
Explanation:
The amplitude of a wave is the distance from the center line (in this case the 1 cm marker on the vertical ruler) to the highest or lowest point. For this image the highest point is 2 cm, 2cm-1cm=1cm. The lowest point is 0cm, 1cm-0cm=1cm.
The amplitude of the wave is 1 cm. So, the correct option is a.
What is meant by amplitude of a wave ?A point on a vibrating body or wave can move up to its maximum distance or displacement when measured from its equilibrium position, which is known as the amplitude. It is equivalent to the length of the vibration path divided in half.
Here,
The crests and trough of a wave is given. Amplitude can also be defined as the peak distance of the crest or trough of the wave.
From the given diagram, we can say that the sum of heights of the crest and trough is given as 2 cm. So, that will be the total vibration path. So, half of its length will give the amplitude of the wave.
Therefore, the amplitude of the wave,
A = 2/2 = 1 cm
Hence,
The amplitude of the wave is 1 cm. So, the correct option is a.
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An m = 6.11 g bullet is fired into a 365 g block that is initially at rest at the edge of a table of h = 1.08 m height as shown in the figure.
1. The bullet remains in the block, and after the impact the block lands d = 1.84 m from the bottom of the table. How much time does it take the block to reach the ground once it flies off the edge of the table?
2. What is the initial horizontal velocity of the block as it flies off the table?
3. Determine the initial speed of the bullet.
(a) The time taken the block to reach the ground once it flies off the edge of the table is 0.47 s.
(b) The initial horizontal velocity of the block as it flies off the table is 3.91 m/s.
(c) The initial speed of the bullet is 237.5 m/s.
Time of motion of the blockThe time of motion of the block is calculated as follows;
h = ¹/₂gt²
where;
h is height of the tablet is time of motiont = √(2h/g)
t = √( (2 x 1.08) / 9.8)
t = 0.47 s
Initial horizontal velocity of the blockx = vt
v = x/t
v = (1.84)/(0.47)
v = 3.91 m/s
Initial speed of the bulletm1u1 + m2u2 = v(m1 + m2)
where;
m1 is mass of bulletm2 is mass of blocku1 is initial velocity of the bulletu2 is the initial velocity of the blockv is initial horizontal velocity of the block as it flies off the table0.00611(u1) + 0.365(0) = 3.91(0.00611 + 0.365)
0.00611u1 = 1.451
u1 = 1.451/0.00611
u1 = 237.5 m/s
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Water's specific heat capacity is 4.184 J/(g · °C). How does this compare to the heat capacities of most common substances?
Answer:
Explanation:
Comment
It's high. It takes quite a bit of heat to get water to change its heat content. Most substances don't reach much more the 0.5 J/(gram*oC)
22. On a day the wind is blowing toward the south at 3m/s, a runner jogs west at 4m/s. What is the velocity of the air relative to the runner?
The velocity of the air relative to the runner is 5 m/s.
What is the relative velocity?We must recall that velocity is a vector quantity and the relative velocity must be obtained vectorially. Thus we know that;
Velocity of the runner = 4m/s. due west
Velocity of the wind = 3m/s due south
The relative velocity is;
Vr = √(4)^2 + (3)^2
Vr = 5 m/s
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Which sentence uses the subjunctive mood correctly?
A. Americans take fewer vacations than people in many other
nations.
OB. It's best that Marci learns how to do her own laundry.
C. It is important that she apologize to her sister for what she said.
D. Be sure to put your dirty clothes in the hamper, not next to it.
The sentence that uses the subjunctive mood correctly is as follows:
Be sure to put your dirty clothes in the hamper, not next to it.Thus, the correct option is D.
What is Subjunctive mood?Subjunctive mood may be defined as statements or actions that are in the probable situation of doubt and suspicion.
Except for the sentence fourth, the rest all indicates the factual concept with the appropriate condition.
Therefore, the correct option for this question is D.
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Answer:
C. it is important that she apologize to her sister for what she said
Explanation:
test approved
In infrared satellite images, land appears _________ and clouds appear _________. A. red, yellow B. white, black C. black, white D. yellow, red
In infrared satellite images, land appears black and clouds appear white. C
What are infrared satellite images?Infrared satellite images are images produced as a result of electromagnetic radiations reflected or emitted from a target surface in the infrared position of the electromagnetic spectrum.
On infrared images, the clouds emit very bright white color because of the low temperature and the land appears to be black because of the hot temperature.
Therefore, in infrared satellite images, land appears black and clouds appear white. C
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A squirrel sitting on the ground starts to run with an acceleration of 5.1 m/s².
How fast is the squirrel going after 0.25 seconds?
O A. 20.4m/s
OB. 0.49 m/s
OC. 3.1 m/s
OD. 1.28 m/s
Answer:
0.159
Explanation:
the formula to find its is 1÷2*gt^2
Answer:
D
Explanation:
v= a t
= 5.1 * .25 = 1.275 m/s
a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
The focal length of given concave lens will be -26.85 cm
The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.
Given concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.
We have to find focal length
The focal length can be found out by following way:
Magnification = m = +1.75
m = hi/h
hi = -47 cm
1.75 = -47/h
h = -26.85 cm
So the focal length of given concave lens will be -26.85 cm
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Answer:
26.85
Explanation: I got it right on Acellus.
Two identical 3.0-kg cubes are placed on a horizontal surface in
contact with one another. The cubes are lined up from left to
right and a force F₁ is applied to the left side of the left cube
causing both cubes to move at a constant speed v. If the
coefficient of kinetic friction between the cubes and the
surface is 0.3, what is the magnitude of the force exerted by the
left cube on the right cube?
(3
The magnitude of the force exerted by the left cube on the right cube is 17.64N.
What is frictional force?When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction.
Two identical 3.0-kg cubes are placed on a horizontal surface in contact with one another. The cubes are lined up from left to right and a force F₁ is applied to the left side of the left cube causing both cubes to move at a constant speed v. The coefficient of kinetic friction between the cubes and the surface is 0.3.
From the equilibrium of forces in vertical direction
Normal force N= 2m x g
friction force f = μN =μ(2m)g
From the equilibrium of forces in horizontal direction
F₁ =ma =0
using Newton's third law of motion, we get
F₁ - f =0
F₁ =f = μ(2m)g
Put the values, we get
F₁ = 17.64N
Thus, magnitude of the force exerted by the left cube on the right cube is 17.64N.
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Tectonic plates are large segments of the earth's crust that move slowly. Suppose one such plate has an average speed of 5.5 cm per year.
(a) What distance does it move in 51 seconds at this speed?
m
(b) What is its speed in miles per million years?
mi/My
The distance and speed are as follows:
Distance = 8.89 * 10⁻⁶ cmSpeed = 34.2 miles per million years.What is speed of a body?Speed of a body is the ratio of the distance covered by a body and the time it takes to cover that distance,
Speed = distance/timeThe number of seconds in a year = 365.25 * 24 * 3600 = 31557600 second
a) Distance covered in 51 seconds = 5.5/31557600 * 51
Distance = 8.89 * 10⁻⁶ cm
b) 5.5 cm = 3.4175 * 10⁻⁵ miles
Sped in miles per million years = 3.42 * 10⁻⁵ miles/1 * 10⁻⁶ million years
Speed = 34.2 miles per million years.
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Two masses, m and 2m, approach each along a path at right angles to each other. After collision, they stick together and move of at 2m/s at angle 37⁰ to the original direction of the mass m. What where the initial speeds of the two particles?
The initial speed of the object with mass "m" is 4.79 m/s and the initial speed of the object with mass "2m" is 1.81 m/s.
Initial speed of the two massesThe initial speed of the two masses is calculated by applying the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
let m be in horizontal directionlet 2m be in vertical directionangle between the two masses = 90 degreesin y - direction[tex]m_1u_1sin(\theta_1) + m_2u_2sin(\theta_2) = (m_1 + m_2)vsin(\theta_3)\\\\mu_1sin(0) + 2mu_2sin(90) = (m + 2m)(2)sin(37)\\\\2mu_2 = 3.61m\\\\u_2 = \frac{3.61 m}{2m} \\\\u_2 = 1.81 \ m/s[/tex]
in x - direction[tex]m_1u_1sin(\theta_1) + m_2u_2sin(\theta_2) = (m_1 + m_2)vsin(\theta_3)\\\\mu_1cos(0) + 2mu_2cos(90) = (m + 2m)(2)cos(37)\\\\mu_1 = 4.79 m\\\\u_1 = 4.79 \ m/s[/tex]
Thus, the initial speed of the object with mass "m" is 4.79 m/s and the initial speed of the object with mass "2m" is 1.81 m/s.
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While a substance is heated it reaches its boiling point. What happens if heating continues while it is boiling?
Answer:
liquid turns into vapor when the liquid molecules achieves the energy to break down the form or when gets highly excited. The temp required for this is called latent heat of vaporization. As the liquid molecules attain this energy through heat it suddenly changes form into vapor , and when the heat is continued , molecule after molecule receives this energy and changes to vapor .So if you continue heating the liquid all the liquid will change form to vapor state leaving residue , ie the dissolved particles .
liquid turns into vapor when the liquid molecules achieves the energy to break down the form or when gets highly excited. The temp required for this is called latent heat of vaporization. As the liquid molecules attain this energy through heat it suddenly changes form into vapor , and when the heat is continued , molecule after molecule receives this energy and changes to vapor .So if you continue heating the liquid all the liquid will change form to vapor state leaving residue , ie the dissolved particles .I’m no expert but this is what i think happens …
6. A metal block increases in temperature from 15 °C to 60 °C when supplied with 13 500 J of heat energy.
a) Calculate the heat capacity of the metal.
b) Calculate the specific heat capacity of the metal, if this sample has a mass of 0.75 kg.
Answer:
Since 1 cal = 4.19 J the heat Q received by the metal is
Q = 13,500 J * 1 C / 4.19 J = 3,222 calories
S = ΔQ / (ΔT * ΔM) = 3222 cal / (45 deg C / 750 gm)
S = .095 cal / gm deg C
Note that specific heat capacity for Cu is .093 cal / gm deg C
A metallic spoon is placed in a hot cup of coffee. If the coffee gives away 190 calories to the spoon to cool down by 0.75°C, what is the mass of the coffee? (Assume that ccoffee = 1.0 cal/gC°.)
According to the definition of calorimetry, the mass of the coffee is 253.33 g.
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
so, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.
c is the specific heat substance.
ΔT is the temperature variation.
Mass of coffee
In this case, Given is :
Q= 190 calories
c= 1
m= ?
ΔT= 0.75 C
Replacing in the equation that allows to calculate heat exchanges is:
190 cal = 1 × m× 0.75 C
Solving:
m= 190 cal÷ (1 × 0.75 C)
m=253.33 g
Finally, the mass of the coffee is 253.33 g.
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the work function for magnesium is 3.70 ev. what is its cutoff frequency?
The cutoff frequency for magnesium is 8.93 x 10¹⁴ Hz.
What is cutoff frequency?The work function is related to the frequency as
W0 = h x fo
where, fo = cutoff frequency and h is the Planck's constant
Given is the work function for magnesium is 3.70 eV.
fo = 3.7 x 1.6 x 10⁻¹⁹ / 6.626 x 10⁻³⁴
fo = 8.93 x 10¹⁴ Hz.
Thus, the cut off frequency is 8.93 x 10¹⁴ Hz.
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a person walk at first constant speed 5 m/s then back alone the straight line from B to A at a constant speed 3 m/s a) what is his average speed over the entire trip b) what is his average velocity over the entire trip
Answer:
3.75 m/s
Explanation:
Comment
Let's deal with the second question first. The average velocity is 0 because the displacement (distance between the starting point and ending point) is 0.
The first question is a little harder. You don't seem to have enough information. When that happens, you can just make things up. Now there's an interesting solution. You could do it with algebra, but it is easier to see with numbers.
Givens
d = 150 m. between A and Br1 = rate from A to B = 5 m/sr2 = rate from B to A = 3 m/stime A to B = t1time B to A = t2Formulas
t1 = d / r1
t2 = d/r2
average rate = total distance / total time
Solution
t1 = 150 m / 5 m/s = 30 seconds
t2 = 150 m / 3 m/s = 50 seconds
Total distance = 150 m + 150 m = 300 m
Total time = 30 seconds + 50 seconds = 80 seconds
Average speed = 300 m / 80 s
Answer
Average speed = 3.75 m/s
A 50 g bullet moving horizontally at a velocity of 400 m/s collides and embeds itself in a 25 kg block that rests on a rough horizontal surface and is attached to a spring with a spring constant of 180 N/m. The impact causes a compression of 12 cm in the spring. What is the coefficient of friction between the block and the surface?
The coefficient of friction between the block and the surface is determines as 0.1.
Final velocity of the block and the bulletApply the principle of conservation of linear momentum;
0.05(400) = v(0.05 + 25)
20 = 25.05v
v = 0.8 m/s
Coefficient of frictionApply the principle of conservation of energy
P.E - K.E = Ux
μmgx - ¹/₂mv² = ¹/₂kx²
μ(25.05)(9.8)(0.12) - 0.5(25.05)(0.8)² = 0.5(180)(0.12)
29.459μ - 8.016 = 10.8
29.459μ = 2.784
μ = 0.1
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The flux through the coils of a solenoid changes from 2.57.10-5 Wb to 9.44.10-5 Wb in 0.0154 s. If 4.08 V of EMF is generated, how many loops does the solenoid have? (No unit)
Hello!
We can use Faraday's Law of Electromagnetic Induction to solve.
[tex]\epsilon = -N \frac{d\Phi_B}{dt}[/tex]
ε = Induced emf (4.08 V)
N = Number of loops (?)
[tex]\Phi_B[/tex] = Magnetic Flux (Wb)
t = time (s)
**Note: The negative sign can be disregarded for this situation. The sign simply shows how the induced emf OPPOSES the current.
Now, we know that [tex]\frac{d\Phi_B}{dt}[/tex] is analogous to the change in magnetic flux over change in time, or [tex]\frac{\Delta \Phi_B}{\Delta t}[/tex], so:
[tex]\epsilon = N \frac{\Delta \Phi_B}{\Delta t}\\\\\epsilon = N \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}[/tex]
Rearrange the equation to solve for 'N'.
[tex]N = \frac{\epsilon}{ \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}}[/tex]
Plug in the given values to solve.
[tex]N = \frac{4.08}{ \frac{9.44*10^{-5} - 2.57*10^{-5}}{0.0154}} = 914.585 = \boxed{915 \text{ coils}}[/tex]
**Rounding up because we cannot have a part of a loop.
Tennis balls experience a large drag force. A tennis ball is hit so that it goes up and then comes back straight down.
A tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.
How object move upward and downward?We know that objects move upward due to application of force on it while on the other hand, object comes to the ground because of the attraction of earth which we called gravity.
So we can conclude that a tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.
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if you were to draw a 3rd harmonic of a tube open at both ends, what would you draw at the ends of the tube?
A 3rd harmonic of a tube open at both ends will have displacement antinodes at both ends.
In a tube of length L with two open ends, the longest standing wave has displacement antinodes (pressure nodes) at both ends. The fundamental or first harmonic is what it is known as. The second harmonic is the longest standing wave in a tube of length L with two open ends.
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Please I need help fast. Assignment is due soon.
1) A ball is thrown from the top of a building with an initial speed of 8.0 m/s at an angle of 35° above the horizontal. The building is 18 m tall.
a) How long is the ball in the air?
b) How far from the building does the ball land?
c) What is its impact speed?
2) A 65-kg person driving a car hits the gas, accelerating the car at a rate of 3.9 m/s^2. Find the magnitude and direction of the force exerted by the seat on the person's body. Remember to include both the horizontal and the vertical components.
(a) The time spent in the air by the ball is 1.5 seconds.
(b) The horizontal distance of the ball is 9.83 m.
(c) The impact speed of the ball is 20.37 m/s.
(2) The magnitude of the force is 253.5 N in horizontal direction.
Time of motion of the ball
The time of motion of the ball is calculated as follows;
h = vt + ¹/₂gt²
18 = 8sin(35)t + (0.5)(9.8)t²
18 = 4.589t + 4.9t²
4.9t² + 4.589t - 18 = 0
solve the quadratic equation using formula method,
t = 1.5 s
Horizontal distance of the projectileX = vcosθ(t)
X = 8cos(35) x 1.5
X = 9.83 m
Impact speed of the projectilevyf = vyi + gt
vyf = 8sin(35) + 9.8(1.5)
vyf = 19.289 m/s
vxf = vxi
vxf = 8 x cos(35)
vxf = 6.55 m/s
Resultant speed = √(19.289² + 6.55²) = 20.37 m/s
Magnitude of the force exerted by the seat on the personF = ma
F = 65 x 3.9
F = 253.5 N
Since the motion is horizontal, the angle of the motion is zero.
Fx = 253.5cos(0) = 253.5 N
Fy = 253.5sin(0) = 0 N
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It just so happens that regardless of the material, when objects are heated up they will start to glow and change colors at near identical temperatures. The plot that you see is called a blackbody spectrum. This plot tells us the intensity or the “amount” of light that an object will emit at different wavelengths (or “colors”). The visible wavelengths are marked by their colors on the plot. To the right of the visible band is lower energy infrared light. To the left of this band is higher energy ultraviolet (UV) light.
Click the + button that is to the left of the intensity scale (far left side of the screen) such that the top of the scale is at 1x10-3 (in the picture above, the top of the scale says 100).
Now use the temperature slider to the right, and take the temperature all the way down to 300 Kelvin (80 Fahrenheit).
Now slowly begin to raise the temperature. At approximately what temperature would a heated material (metal, wood, etc.) begin to give off visible light at a deep red color?
Answer: the plot that you see is called a blackbody spectrum. This plot tells us the intensity or the amount of light that an object will emit at different wavelenths.
Explanation: i hope that this helps
You turn on a cars radio, what energy transformation is taking place?
Answer:
C probably
Explanation:
think c because when you first start the car the first thing you hear electrical sound.
A skater starts from rest v1=0, from the top of an h=6m hill and travels d=20m until it gets to the bottom of the hill where its speed is v2=1.2m/s. If the skater has m=50kg, what is the friction force?
The friction force is 1.5N
skater's initial velocity v1=0height of the hill=20mskater's final velocity=1.2m/sMass of the skater=50kg
Now, using the third equation of motion-
[tex]v^{2}= u^{2} +2as[/tex]
v=final velocity
u=initial velocity
a=acceleration
s=distance
substitute the values in the above equation
1.2=0+ 2a×20
a=1.2/40
a=0.03
friction force=mass ×acceleration
=50×0.03
=1.5N
hence, The friction force is 1.5N
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A ball A of mass 0.5 kg moving with a Velacity of 10 m/s a head on Collision with a ball B of mass 2kg moving with a Velocity of 1ms in the oppoite direction. If A and B stick together after Collision, Calculate the Common Velocity in the direction of A
Answer:
The common velocity v after collision is 2.8m/s²
Explanation:
look at the attachment above ☝️
Entropy is how quickly things get messy.
O A. True
OB. False
Answer : False
Answer:
false
Explanation:
it cant defined the messy and clean states
