The statement is false. A particle traveling around a circle at constant speed will definitely experience an acceleration.
What is tangential acceleration?An object in constant circular motion is actually accelerating. It accelerates because the direction of the velocity vector changes. To explain this, it is necessary to consider that acceleration is necessary to describe a circular trajectory when a particle undergoes a change in direction of velocity that is characteristic of circular motion.
Since the speed is constant, the tangential acceleration of the body is zero. However, because its velocity is constantly changing, there is an acceleration called centripetal acceleration that always points towards the center of its orbit.
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A steel wire in a piano has a length of 0.700 0 m and a
mass of 4.300 x 10^-3 kg. To what tension must this wire
be stretched so that the fundamental vibration corre-
sponds to middle C ( f^c = 261.6 Hz on the chromatic musical scale)?
The magnitude of tension must be 3.64 N on the wire.
What is frequency?In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.
Given parameters:
Length of the piano wire: L = 0.700 m.
Mass of the piano wire: m = 4.300 × 10⁻³ kg.
Fundamental frequency of it: f = 261.6 Hz.
We have to find: the tension applied on it T = ?
We know that:
Fundamental frequency is given by:
f = (2π/L)√(T/m)
rearranging the formula, we get:
T = (fL/2π)²m
= ( 261.6 × 0.7000/2π)²× 4.300 × 10⁻³N.
=3.64 N.
Hence, The magnitude of tension must be 3.64 N on the wire.
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How much force in Newtons is required to accelerate a shotput weighing 4kg at 21 m/s2?
Answer:
[tex] \Huge{\boxed{84 N}} [/tex]
Explanation:
The amount of force required here can be found by using the formula
force = mass × accelerationwhere
mass is in kg
acceleration in m/s²
From the question
mass = 4 kg
acceleration= 21 m/s²
We have
force = 4 × 21 = 84
We have the final answer as
84 NHow does heat transfer happen in conduction?
(A) A hotter object passes thermal energy to a colder object by touching it so their particles bump into each
other.
(B) A hotter object reaches thermal equilibrium and gives its extra heat particles away to nearby objects.
(C) A hotter object is placed on one side of an insulator and a colder object is placed on the other side of
the insulator.
(D) A hotter object has particles that spread through the air as gases and warm the air near the colder
object.
Answer:
(A) conduction implies that the objects are in contact
WILL GIVE BRAINLIEST!!!! The model represents how electromagnetic radiation transmits energy. f What does the model show? A. An electric field and a magnetic field vibrating parallel to each other B. Two light waves vibrating parallel to each other C. An electric field and a magnetic field vibrating perpendicular to each other D. Two light waves vibrating perpendicular to each other
This model represents how electromagnetic radiation transmits energy and it shows: C. an electric field and a magnetic field vibrating perpendicular to each other.
What is an electromagnetic energy?In Science, an electromagnetic energy can be defined as form of energy that is primarily carried by electromagnetic waves such as:
Gamma raysx-rays.This ultimately implies that, an electromagnetic energy simply refers to a form of energy that typically moves as particles at the speed of light, which is about three hundred million meters per seconds (3 × 10⁸ m/s) and they are always perpendicular to each other.
Based on the model shown in the image attached below, we can logically deduce that a single light wave travels away from a source within an electric field and a magnetic field that are vibrating perpendicular to each other.
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an air sample contains 3.5 x 10-6 g/l (grams per liter) of carbon monoxide. how would you express this concentration of carbon monoxide in lb/ft3 (pounds per cubic foot)? note: 1 pound
2.225 x [tex]10^{-7}[/tex] lb/[tex]ft^3[/tex] concentration of carbon monoxide in lb/[tex]ft^{3}[/tex]
Conc. of CO in air = 3.5x[tex]10^{-6}[/tex] [tex]\frac{g}{L}[/tex]
454g = 1 lb
1g = [tex]\frac{1}{454}[/tex] lb
3·5 × [tex]10^{-6}[/tex] g = 1/454 x 3.5 x [tex]10^{-6}[/tex] lb
= 0.007709x[tex]10^{-6}[/tex] lb
= 7.70 x [tex]10^{-9}[/tex] lb
1 L = [tex]10^{3}[/tex] [tex]cm^{3}[/tex]
=[tex]10^{3}[/tex] x [tex](0.3930) ^3[/tex]
=[tex]10^{3}[/tex] x [tex]0.00069 in^3[/tex]
=[tex]10^{3}[/tex] x 0.060 x [tex](0.083ft) ^3[/tex] (1 in = 0.0833ft)
=[tex]10^{3}[/tex] x 0.060 x 0.000571 [tex]ft^3[/tex]
=[tex]10^{3}[/tex] x 6.06 x [tex]10^{-2}[/tex] x 5.71 x [tex]10^{-4}[/tex] [tex]ft^3[/tex]
=34.60 x [tex]10^{-3}[/tex] [tex]ft^3[/tex]
So, 3.5 x[tex]10^{-6}[/tex] g/L = 7.70 x [tex]10^{-9}[/tex] lb / 34.60 x 10
=0.2225 x [tex]10^{-6}[/tex] lb/[tex]ft^3[/tex]
=2.225 x [tex]10^{-7}[/tex] lb/[tex]ft^3[/tex]
Colorless, lethal, odorless, tasteless, and combustible gas with the chemical formula CO, carbon monoxide is a little less dense than air. One carbon atom and one oxygen atom bound together by three bonds make up carbon monoxide. The oxocarbon family's simplest molecule is this one. The carbon monoxide ligand in coordination complexes is referred to as carbonyl. It is a crucial component in numerous industrial chemistry processes.
There are a lot of biological and environmental factors that produce a lot of carbon monoxide as well. It is crucial for the creation of numerous compounds, such as medicines, fragrances, and fuels.
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What is the equation for density d d/m over V?.
The equation for the density is D = m/v.
Density is the substance's mass consistent with the unit of quantity. The symbol most customarily used for density is ρ, despite the fact that the Latin letter D can also be used. Density is the size of ways tightly a cloth is packed together. it's far defined as the mass consistent with unit quantity.
ρ = m/V, wherein ρ is the density, m is the mass of the item and V is the quantity of the object.
The density of a liquid is a measure of how heavy it is for the quantity measured. in case you weigh the same amounts or volumes of two one-of-a-kind beverages, the liquid that weighs extra is greater dense.
The density is of two types, one is absolute density, and the alternative is relative density. Relative density is also called unique gravity, which is the ratio of the density of a material to the density of a reference material. typically, the reference fabric is water.
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The moon is held in its orbit around Earth by gravity. The moon also feels a gravitational pull from the sun. Which of the following is true? a The force of the moon acting on the sun is equal to the force of the sun acting on the moon. b The force of the sun acting on the moon is greater than the force of the moon acting on the sun. c The force of the sun acting on the moon is less than the force of the moon acting on the sun. d The force of the is moon acting on the sun is greater than the force of the sun acting on the moon.
Answer:
Explanation:
The moon is held in its orbit around Earth by gravity. The moon also feels a gravitational pull from the sun. Which of the following is true?
According to Newton's third law, the interaction forces are the same.
(a) The force of the moon acting on the sun is equal to the force of the sun acting on the moon.
The acceleration of an object is ____________ related to the mass of the object.
Answer:
the acceleration of an object is directly related to the mass of the object
a rectangular current loop with a clockwise current is in a uniform magnetic field. what is the direction of the net force on the loop?
The direction of the magnetic force on the loop is going inside the loop. If the loop place on the paper, the magnetic force going through the paper.
If a loop of wire is electrified there will be a uniform magnetic field. We use the right-hand rule for loops to calculate the direction of the magnetic field. The rules are
Curl your fingers according to the direction of the current flows.Thumb points in the direction of magnetic force.Imagine a loop on paper. A clockwise current on the loop, curl your fingers, and go in a clockwise direction.
Your thumb gonna points down and the magnetic force going inside the paper.
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A 0.87 kg projectile is fired into the air from the top of a 8.52 m cliff above a valley. Its initial velocity is 9.1 m/s at 49◦ above the horizontal. How long is the projectile in the air? The acceleration due to gravity is 9.8 m/s.
Answer in units of s.
By adding the time of flight at the top of the cliff and the time taken down the hill, the ball spent 2.72 s of time in air.
What is a Projectile ?A projectile can be a stone or a ball or any object that can be projected. The object projected will take a trajectory path.
Given that acceleration due to gravity is 9.8 m/s and a 0.87 kg projectile is fired into the air from the top of a 8.52 m cliff above a valley. Its initial velocity is 9.1 m/s at 49◦ above the horizontal. To know how long the projectile will be in the air, we will calculate the total time of flight at the top of the cliff and the time taken down the hill
Time of flight T = 2usinФ/g
Where
g = m/s²Ф = 49°h = 8.52 mu = 9.1 m/st = ?m = 0.87 kgSubstitute all the necessary parameters into the formula
T = (2 × 9.1sin49)/ 9.8
T = 13.74/9.8
T = 1.40 s
The time taken down the cliff can be found with formula
h = ut + 1/2gt²
where u = 0
8.52 = 0 + 1/2 × 9.8 × t²
8.52 = 4.9t²
t² = 8.52/4.9
t² = 1.738
t = √1.738
t = 1.32 s
Time for the projectile in the air = T + t
Time in air = 1.40 + 1.32
Time = 2.72 s
Therefore, the projectile will be in the air for 2.72 seconds long.
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calculate the initial volume of NH3 gas at 0°C that is changed to 731 centimeter cube by cooling it to "-14°C" at constant pressure.
The initial volume can be calculated using Charles's law. The initial volume of the ammonia gas was 770 cm³.
What is Charles's law?According to Charles's law, at constant pressure, the volume and temperature of a gas is directly proportional. Thus, v/t = a constant.
V1/T1 = V2/ T2
Given that the final volume and temperature are 731 cm³ and -14 degree Celsius or 269 K respectively. Thus the volume of the gas at 0 degree Celsius or 273 K is :
volume V1 = V2 T1 / T2
= (273 K × 731 cm³ ) /269 K
= 770 cm³.
Thus, the initial volume of the gas was 770 cm³.
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explain the difference between the velocity and acceleration of an object.
Answer:
See below
Explanation:
Velocity is how fast an object is moving....acceleration is how fast the velocity is changing .
Mercury has an orbital period of about 88 Earth days. Find the semimajor axis of its
orbit. Remember that the mass of the sun is 1.988 x 1030 kg.
Answer:Since Mercury's period is 88 days (page 182), the period of this hypothetical planet would be 0.354 ´ 88 = 31 days
Explanation: I hope this is correct
The prices of the different units of volume and mass of mercury are as follows as the Price of one pound of mercury = $2.059
What is the price of the intermediate volumes of Mercury?The price of the intermediate volumes of Mercury are determined as follows:Price of 1 g of mercury = $0.00454, Price of 1 cm³ of mercury = $0.0614 and Price of 1 in³ of mercury is $0.996 and Price of 1 g of mercury = $0.00454, Price of 1 cm³ of mercury = $0.0614 and Price of 1 in³ of mercury is $0.996
b. 1 pound = 453.592 g
76 pounds = 76 * 453.592 g = 34473 gPrice of 1 g of mercury = $156.50/34473 Price of 1 g of mercury = $0.00454
Volume of 34473 g of mercury = 34473/13.534
Volume of 34473 g of mercury = 2547.14 cm³
Price of 1 cm³ of mercury = $156.50/2547.14 cm³
Price of 1 cm³ of mercury = $0.0614 Price of 1 in³ of mercury:
1 cm³ = 0.0610 in³
2547.14 cm³ = 2547.14 * 0.0610 in³
2547.14 cm³ = 157.02 in³
Price of 1 in³ of mercury = 156.5/157.02
Price of 1 in³ of mercury = $0.996
In conclusion, the prices of the different units of volume and mass of mercury are found by conversion.
Therefore, Mercury has an orbital period of about 88 Earth days.
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consider a tug-of-war where scales are at opposite ends of the rope. is it possible for the scales to have different readings when participants pull?
There are two forces at play in a tug of war. The force produced by stretching the rope is indeed called tension. This power drives these people forward.
Another force acting on them is the friction of the soles of the feet. In tug-of-war, if two teams exert the same force on the rope, the net force on the rope is zero, so the rope stays in the same place. A rope has zero tension when both ends of the rope are pulled by two opposing forces of 100 N each. This is because both forces have the same magnitude but act in opposite directions on the same object and cancel each other out.
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a piston has an external pressure of 8.00 atm . how much work has been done in joules if the cylinder goes from a volume of 0.130 liters to 0.650 liters?
Work done by the piston is 421.40 J
What is work done?Work is the energy transferred to or from an object by applying a force along a displacement. In its simplest form, if the constant force is aligned with the direction of travel, it equals the product of the force and the distance traveled.
The formula for calculating the work done is:
W = -P × ΔV
P = pressure
ΔV = change in volume
Substitute the values in the formula:
W = -P × ΔV
W = -8 × (0.65 - 0.13)
W = -8 × 0.52
W = -4.16 atm L
1 atm L = 101.3 J
-4.16 atm L = -4.16 × 101.3 J
= 421.40 J
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a model helicopter pulls into a tight circular curve of radius 30.0 m. the 300 g helicopter is traveling at 90.0 km/h. what is the helicopter's centripetal force?
The centripetal force on the model helicopter is 6.25N.
The radius of the curve of the model helicopter is 30m and the mass of the helicopter is 300g, it is travelling with a speed of 90km/h.
Converting the speed into m/s, speed is 25m/s.
The centripetal force on a body is given by,
F = Mv²/r
Where,
F is the force,
V is the speed,
r is the radius,
So, putting values for helicopter,
F = 0.3 x 25 x 25/30
F = 6.25 N.
So, the centripetal force is 6.25 N.
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a woman stands on a bathroom scale in a motionless elevator. when the elevator begins to move, the scale briefly reads only 0.87 of her regular weight.
The elevator accelerates with an acceleration of a=-2.45 m/s2 in a downward direction.
What is the speed at which it is accelerating?Any vector's magnitude, represented by its unit and pointing in the direction of the vector, is its length. As a result, the acceleration's magnitude is equal to the length of the acceleration vector and it is pointed in the same direction. For any vector quantity, this is true.
What is the acceleration's direction?Three situations can be distinguished when figuring out the direction of acceleration: when picking up speed, the acceleration is in the direction of movement; when slowing down, the acceleration is in the opposite direction to the direction of movement; and when driving around a corner at a constant speed, the acceleration is in the direction of movement.
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in this experiment you will be studying projectile motion. in general, what can be said about the horizontal velocity in this type of motion?
To known the motion and horizontal velocity.
What is motion?
In physics, motion changes over time depending on a body's position or orientation. Translation is the action of moving along a line or curve. Rotation is the term used to describe motion that modifies a body's orientation.
What is horizontal velocity?
The speed of a projectile is constant in the horizontal plane.Gravity causes a vertical acceleration that is 9.8 m/s/s downward. Each second, a projectile's vertical velocity changes by 9.8 m/s, A projectile's horizontal motion exists independently of its vertical motion.
If we perform an experimented see that the only force acting on the projectile is the gravity which acts vertically (neglecting air resistance). The component of gravitational force along horizontal direction is zero. Thus, there is no force acting horizontally acceleration in horizontal direction is zero.
Therefore, velocity in horizontal direction remains constant.
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a 43- kgkg child stands on the edge of a 270- kgkg playground merry-go-round that is turning at the rate of 1 rev every 2.2 ss . he then walks to the center of the platform. part a if the radius of the platform is 1.5 mm , what is its rotational speed once he arrives at the center?
The rotational speed is 5.8 rad/s.
This is a rotational system related to rotational motion and the system is made up of the merry-go-round and the child, for which we write the moment of two instants
Initial
L₀ = I₀ w₀
Final
L_{f} = I w
L₀ = L_{f}
I₀ w₀ = I_{f} w
.w = I₀/I_{f} w₀
The initial moment of inertia is
I₀ = 0.0011 kg. m2
The final moment of inertia
l_{f} = 0.0011 + m r²
I_{f} = 0.0011 + (43) (1.5)²
I_{f} = 4160.25 kg m²
Initial angular velocity
w₀ = 0.22 rad / s
Let's calculate
rotational speed = (0.0011/4160) 0.22
rotational speed = 5.81 rad / s
Therefore, the rotational speed when the child arrives at center is 5.81 rad/s.
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a thin wire is stretched horizontally between two walls. if a weight, w, is hung on the wire, what is true about the tension, t, in the wire?
Find the wire tension is true or not.
What is tension?
The force transmitted through a rope, string, or wire when it is pulled by forces acting from opposite sides is referred to as tension. The bodies at each end of the wire are subjected to an equal amount of tension force that is applied along the entire length of the wire.
What is force?
The force that a rope, cord, or other similar object applies to an object is known as the force of tension. Horizontally, two walls are separated by a thin wire. What holds true about the tension T in the wire if a weight W is suspended from it? It is impossible to establish the connection between T and W.
Therefore, it is impossible to establish the connection between T and W.
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what is the net force acting on a 1.0-kg ball moving at a constant velocity
The net force acting on a 1.0-kg ball moving at a constant velocity will be zero
Since , ball is moving at a constant velocity , that means there is no acceleration as acceleration is equal to change in velocity divided by time . Here velocity is constant hence no change in velocity is taking place .
since, there exist no acceleration which means there exist no external force . Hence , net force on the ball is zero in this system .
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please help ASAP and I need get the independent and dependent variables
The amount of time is the independent variable, while the water phase change is the dependent variable.
What is the independent variable?The independent variable is any variable in the experiment that does not change along the experiment but whose values are associated with the modification in the dependent variable (such as in this case time to observe water phase change).
Therefore, with this data, we can see that the independent variable does not change along the experimental procedure and is known to be the cause of the change in the dependent variable.
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an athlete runs with velocity 12 km/h for 4 minutes, 14 km/h for the next 4 minutes, and 19 km/h for other 5 minutes. compute the total distance traveled.
Total distance travelled by an athlete is approx 4 km.
We have given following information, let the total distance travelled by an anthlete be x km
An athlete runs first part of total distance (x) with a velocity 12 km/ h for 4 minutes.
the next part of x km is travelled by an anthlete with 14 km/h for 4 minutes.
one other part of x km is travelled by an anthlete with 19 km/h for 5 minutes
Change the time units from minutes to hours
1 hour = 60 min => 4 minutes = 4/60 h = 1/15 h
and 5 minutes = 1/12 h
Now use the velocity formula ,
velocity = distance/ time
=> distance = velocity × time
so, total distance (x ) = 12 km/h × 1/15 h + 14 km/h × 1/15 h + 19 km/h × 1/12 h = (12/15 + 14/15 + 19/12)
= 3.91 km ~ 4 km
therefore, total distance travelled by an anthelete is 4km.
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A ball weighing 20 newtons rolls 20 meters in a straight line on a leve surface. What is its change in potential energy?
A 0J
B 1J
C 40J
D 400 J
Answer:
A
Explanation:
Potential energy = m g h unless h changes there is zero PE change
what is the maximum total force exerted on a astronaut by her seat during the launch of a space shuttle?
The maximum total force exerted on an astronaut by her seat during the launch of a space shuttle is about 3gs.
The weight of the cargo a rocket is carrying determines how much g-force it can generate. A manned mission is constrained by what a human being can withstand. High g-forces can harm the body, and at about 9 gs, most people pass out as their blood struggles to get to their brains. During a rocket launch, astronauts typically feel a maximum g-force of about 3gs. The force of gravity is equivalent to three times what people ordinarily experience on Earth, but the passengers can withstand it. Astronauts undergo high-g training, don g-suits, and need to be properly outfitted.
When a mass accelerates, there is a force (F=ma). While moving at any speed, there is no inherent force that is perceived. Whenever velocity changes, force is sensed. Since the definition of acceleration is the change in velocity over time (dv/dt), we can rewrite the force equation as F=m(dv/dt).
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What happens to the gravitational force between two particles if the distance between them is doubled?.
If the gap between them doubles, the gravitational pull will be reduced to one-fourth of its current strength.
The inverse of the square of the factor that affects separation distance is the factor that affects electrostatic force. Therefore, the electrostatic force is reduced by a factor of four when the separation distance doubles.The square of the distance between the two charges has an inverse relationship with the force's size. As a result, when the gap between two charges is doubled, the attraction or repulsion weakens and drops to one-fourth of its initial strength.The force is smaller the further apart the masses are. The gravitational force does not decrease by half when the distance between two masses is doubled because it is proportional to 1/d2, but rather by 1/4.
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What is the angle θ with respect to north made by the velocity vector of the two cars after the collision?.
The final speed of the joined cars after the collision as stated in the question is; [tex]v_f[/tex] = (v/2)√(5 - 4sin ϕ)
From the law of conservation of linear momentum, we know that;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where;
m₁ = mass of car 1
u₁ = Initial velocity of Car 1
m₂ = mass of car 2
u₂ = initial velocity of car 2
v₁ = final velocity of car 1
v₂ = final velocity of car 2
We are told that before the collision, one car was traveling in the northern direction while the second car was traveling in the southeastern direction at an angle ϕ.
We are given the initial speed of the first car = 2v.
Thus;
The horizontal component of the initial velocity of the first car; u₁ₓ = 0
The vertical component of the initial velocity of the first car; u₁y = 2v j^
Similarly, for the second car, we are given initial speed = v
Thus;
The horizontal component of the initial velocity of 2nd car; u₂ₓ = v cos ϕ
Vertical component of initial velocity of first car; u₂y = v sin ϕ (-j^)
Since both of their masses are m, after collision since they travel together, their combined masses will be 2m.
They now move together in a northeastern direction at an angle θ.
Thus, resolving the final velocities gives us;
vₓ = [tex]v_f[/tex]sin θ (i^)
[tex]v_y[/tex] = [tex]v_f[/tex] cos θ (j^)
Thus, along the x-axis, we now have;
m₁u₁ₓ + m₂u₂ₓ = 2mvₓ
Plugging in the relevant values, we have;
m(0) + m(v cos ϕ) = 2m([tex]v_f[/tex] sin θ (i^))
v cos ϕ = 2(v_f sin θ (i^)) ---(eq 1)
Similarly, along the y-axis, we have;
m(2v j^) + m(v sin ϕ (-j^)) = 2m([tex]v_f[/tex] cos θ (j^))
⇒ 2v - v sin ϕ = 2v_f cos θ ---(eq 2)
We will square both eq 1 and eq 2 and add to each other to get;
v² cos² ϕ + (2v - v sin ϕ)² = 4([tex]v_f[/tex])² (sin²θ + cos²θ)
⇒ v² cos² ϕ + (2v - v sin ϕ)² = 4([tex]v_f[/tex])²
⇒ v² cos² ϕ + 4v² - 4v² sin ϕ + v²sin²ϕ = 4([tex]v_f[/tex])²
⇒ v²(cos² ϕ + sin²ϕ) + 4v² - 4v² sin ϕ = 4([tex]v_f[/tex])²
cos² ϕ + sin²ϕ = 1. Thus;
⇒ v² + 4v² - 4v² sin ϕ = 4([tex]v_f[/tex])²
⇒ 5v² - 4v² sin ϕ = 4([tex]v_f[/tex])²
[tex]v_f[/tex] = (v/2)√(5 - 4sin ϕ)
Velocity is the direction in which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time (for example, 60 km/h northbound). In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea
A physical vector quantity called velocity must have both a magnitude and a direction in order to be defined. Speed is the scalar absolute value (magnitude) of velocity; it is a coherent derived unit whose quantity is measured in meters per second (m/s or m/s1) in the SI (metric system). In contrast to "5 meters per second east," which is a vector, "5 meters per second," for instance, is a scalar.
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The diagram shows a 2.0-kilogram cart traveling at a constant speed in a horizontal circle of radius 3.0 meters. The magnitude of the centripetal force of the cart is 24
newtons. What is the speed of the cart?
a) 6.0 m/s
b) 16 m/s
c) 36 m/s
d) 4.0 m/s
A 2.0-kilogram cart traveling at a constant speed in a horizontal circle of radius 3.0 meters. The magnitude of the centripetal force of the cart is 24 newtons. The speed of the car is 6 m/s. Thus, Option A is the correct answer.
To find the speed, the given values are,
Mass m = 2 Kg
Radius r =3 meters
Centripetal force = 24 Newtons.
What is Centripetal force?A centripetal force is the force which is made up of two Latin words centrum which means center and peterum which means to seek.
It is defined a force which make a body to follow a curved path. The direction of this force is always orthogonal to the body's motion and it is always towards the fixed point which is instantaneous center of the path's curvature.
Centripetal force is expressed according to the formula;
F = mv²/r
m is the mass of the body
v is the speed of the cart
r is the radius
Substituting the values into the formula and get v,
24 = 2v²/3
24×3 = 2v²
72 = 2v²
v² = 72/2
v² = 36
v =√36
v = 6m/s
Hence, the speed of the cart is 6m/s. Thus, Option A is the correct answer.
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a 0.70-m-diameter wheel accelerates uniformly from 130 rpm to 280 rpm in 4.0 s. determine (a) its angular acceleration, (b) the linear velocity of a point on the edge of the wheel 2.0 s after it has started accelerating, (c) the radial and tangential components of the linear acceleration of this point at this moment, (d) how many revolutions the wheel has turned during this 2.0 s.
The linear acceleration is 82.45 m/sec².
Linear acceleration is described as uniform acceleration because of a transferring body in a straight line. There are three equations that are essential in linear acceleration relying upon the parameters like initial and final pace, displacement, time, and acceleration.
Whilst linear acceleration is implemented to a frame, the whole body is affected by the acceleration (or the force) at the same time. Fee of exchange in pace consistent with unit of time even as on an instant route. that is linear acceleration. Angular acceleration is the rotational acceleration felt by using an object on approximately an axis.
Calculation:-
Given,
diameter = 0.70 m
= 0.3
The angular acceleration = 2π (280 - 130)/4
= 235.575
linear acceleration = r × 235.575.
= 0.35 × 235.575.
= 82.45 m/sec²
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An ice crystal falls vertically from a cloud.
What happens to the acceleration of the ice crystal as it falls?
Answer: It decreases because of air resistance.
Explanation:
