A plant is thrown straight
down from a balcony 7.01 m
high at 8.84 m/s. How long
does it take the plant to hit
the ground?

The temperature reading in Fahrenheit scale when reading 310 K is  98.6F

Temperature is the degree of hotness or coldness of the object.

Given is a temperature in Kelvin scale = 310 K

Temperature on centigrade scale = 310 -273 = 37°C

Temperature conversion from Centigrade to Fahrenheit is

C/5 = F -32/9

Plug the value, we get

37/5 = F-32/9

66.6 = F -32

F = 32+66.6 =

F = 98.6

Thus, the temperature of 310 K in Fahrenheit is 98.6F.

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(a) The equilibrant C for force of vector A and B is 3.43 N.

(b) The equilibrant C for fx of vector A and B is 2.1 N.

(c) The equilibrant  C, for fy of vector A and B is 2.12 N.

An equilibrant force is a single force that will bring other bodies into equilibrium.

Vector A: mass = 0.2 kg, θ = 20⁰

Vector B: mass = 0.15 kg, θ = 80⁰

Fx = mg cosθ

Fy = mg sinθ

where;

Force of A due to its weight

F(A) = mg

F(A) = 0.2 x 9.8 = 1.96 N

Fx = (0.2 x 9.8) cos(20) = 1.84 N

Fy = (0.2 x 9.8) sin(20) = 0.67 N

R = √(0.67² + 1.84²)

R = 1.96 N

Force of B due to its weight

F(B) = mg

F(B) = 0.15 x 9.8

F(B) = 1.47 N

Fx = (0.15 x 9.8) cos(80) = 0.26 N

Fy = (0.15 x 9.8) sin(80) = 1.45 N

R = √(0.26² + 1.45²)

R= 1.47 N

Equilibrant force:

Force, C = 1.96 N + 1.47 N

Force, C = 3.43 N

Equilibrant FX:

Fx, C = Fx(A) + Fx(B)

Fx, C = 1.84 N + 0.26 N = 2.1 N

Equilibrant FY:

Fy, C = Fy(A) + Fy(B)

Fy, C =0.67 N + 1.45 N = 2.12 N

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Answer:

the anser is b

Explanation:

If the force applied on the object is in the direction of its motion, the speed of the object increases. If the force is applied in the direction opposite to the direction of motion, then it results in a decrease in the speed of the object.

[tex]q = -21 * 10^{-6} C[/tex]

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 m/s at sea level on the Earth.

As we know that charge and its sign that remains in equilibrium is under gravity must be such that it will balance the gravitational force by electric force,

mg =qE

[tex]1.45 * 10^{-3}(9.80)=q(600)\\\\q = 21 *10^{6} C\\\\[/tex]

and its sign must be negative so that it will have upward electric force

so it is

[tex]q = -21 * 10^{-6} C[/tex]

The charge of a particle of mass is [tex]-21 * 10^{-6} C[/tex]

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The work done by the force on the box 588 Joule.

It is the energy that is stored in an object due to its position relative to some zero position.

According to the question,

Given mass of the box (m)  = 6.0 kg

Given displacement of the box =  10.00 m

Hence , the height of the box  (h) = 10.00 m

Acceleration due to gravity (g)  =  9.8 m/s²

Since ,

The upward force was applied to the box, the box moves up to the height.

Therefore, the work done by the ball is the potential energy gained by the ball.

By using the formula of potential energy

P.E. = mgh

= 6 × 9.8 × 10 Joule  = 588 Joule

As we know .

Work done (W) = Potential energy (P.E.)

Work done (W) = 588 Joule

Thus,  588 Joule is the work done by the force on the box.

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Answer:

[tex]\textsf {v = 20 m/s}[/tex]

[tex]\mathsf {a = 16 m/s^2}[/tex]

Explanation:

[tex]\textsf {To find velocity, let's differentatiate x :}[/tex] [tex]\implies \mathsf {v = \frac{dx}{dt} }[/tex]

⇒ [tex]\mathsf {v = \frac{d}{dx}(t^{3}+2t^{2}+4) }[/tex]

⇒ [tex]\mathsf {v = 3t^{2} +4t +0 }[/tex] [tex]\textsf {(By applying law of differentiation)}[/tex]

[tex]\textsf {Substitute t = 2 :}[/tex]

⇒ [tex]\mathsf {v = 3(2)^{2} + 4(2) }[/tex]

⇒ [tex]\textsf {v = 12 + 8}[/tex]

⇒ [tex]\textsf {v = 20 m/s}[/tex]

[tex]\textsf {To find acceleration, let's differentatiate v :}[/tex] [tex]\implies \mathsf {a = \frac{dv}{dt} }[/tex]

⇒ [tex]\mathsf {a = \frac{d}{dx}(3t^{2}+4t) }[/tex]

⇒ [tex]\textsf {a = 6t + 4}[/tex]

[tex]\textsf {Substitute t = 2 :}[/tex]

⇒ [tex]\textsf {a = 6(2) + 4}[/tex]

⇒ [tex]\textsf {a = 12 + 4}[/tex]

⇒ [tex]\mathsf {a = 16 m/s^2}[/tex]

The force exerted by student A with his scooter is 306 N and that of student B is 204 N.

The force exerted by each student is calculated from Newton's second law of motion.

F = ma

where;

F(A) = 127.5 x 2.4

F(A) = 306 N

F(B) = 120 x 1.7

F(B) = 204 N

Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.

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The motion of the elevator can best be described as motion against gravity with negative acceleration.

Motion refers to a change in position of an object when it moves from one point another along a reference frame.

An object moving in a downward direction is moving in a positive direction and its velocity increases relative to the earth since gravity acts downwards.

An object moving in a upward direction is moving in a negative direction and its velocity decreases relative to the earth since gravity acts downwards.

Therefore, the motion of the elevator can best be described as motion against gravity with negative acceleration.

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The work function in eV for the given cutoff frequency is  5.05 eV.

The work function is related to the frequency as

Wo = h x fo

where, fo = cutoff frequency and h is the Planck's constant

Given is the cutoff frequency for a certain element is 1.22 x 10¹⁵ Hz

Wo = 6.626 x 10⁻³⁴ x  1.22 x 10¹⁵ Hz / 1.6 x 10⁻¹⁹

Wo = 5.05 eV

Thus, the work function is  5.05 eV

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Answer:

i believe the answer is true

Gravity and normal forces act on the toy car.

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a. Ball P

Density is define as mass per unit volume or the quantity per unit volume, unit area, or unit length.

If [tex]m_{1}[/tex] is mass ,  [tex]V_{1}[/tex] is volume and [tex]D_{1}[/tex]  is density of ball P

[tex]m_{2}[/tex]  is mass ,  [tex]V_{2}[/tex] is volume and [tex]D_{2}[/tex] is density  of ball Q

It is given that  ,

[tex]V_{1}[/tex] = [tex]V_{2}[/tex];

But  [tex]m_{1}[/tex]= [tex]2m_{2}[/tex]

Based on above equation we have:

[tex]\frac{D_{1} }{D_{2} } = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{2m_{2} }{V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 2[/tex]

Thus, density of ball P is twice that of Q.

Therefore ,

Ball  P will have a greater density than Q

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Answer:

i don't know sorry

i know a good website that may help you

it's called https://skyandtelescope.org/observing/telescope-calculator/

Explanation:

Answer:

suna bro i am nepali and nepali are pro

Answer:

Explanation:

The formula for Speed is distance per time.

Data

D = 40 m

T = 10 sec

S = ?

To find the speed , divide the distance by the time.

Note : the unit for Speed is meter /second

Therefore the speed of the wave, the surfer is riding on is 4 m/s.

The distance covered by an accelerating object starting from rest is

D = (1/2 of acceleration) x (time²).

In this question,

D = 100 m

time = 3.8 s

100 = (1/2 acceleration) x (3.8s²)

100 = (1/2 a) x (14.44)

100/14.44  =  1/2 a

200/14.44  =  a

a = 13.85 m/s²

The total distance traveled by the gardener is 8 meters. the magnitude of total displacement is approximately 7 meters.

                                                                      = 8 meters

For the magnitude of displacement, we will take the shortest path for the gardener movement.

                              for displacement-

                                       [tex]=\sqrt{( 0-4^{2}) +( 6-0^{2} )}\\=\sqrt{52} \\=7[/tex](approximately)

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Answer:

di

Explanation:

The prefix is di. CO2 is carbon dioxide. di means 2.

Hi there!

The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.

Initially, we only have kinetic energy:

[tex]KE = \frac{1}{2}mv^2[/tex]

KE = Kinetic Energy (J)
m = mass (1060 kg)
v = velocity (14.6 m/s)

Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:

[tex]U_s = \frac{1}{2}kx^2[/tex]

k = Spring Constant (1.14 × 10⁷ N/m)

x = compressed distance of bumper (? m)

Since energy is conserved:

[tex]E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2[/tex]

We can simplify and solve for 'x'.

[tex]mv^2 = kx^2\\\\x = \sqrt{\frac{mv^2}{k}}[/tex]

Plug in the givens and solve.

[tex]x = \sqrt{\frac{(1060)(14.6^2)}{(1.14*10^7)}} = \boxed{0.0198 m}[/tex]

Answer:

The force between two objects is calculated through the equation,

                       F = Gm₁m₂/d²

where m₁ and m₂ are the masses of the objects. In this case, an unknown mass and Earth. d is the distance between them and G is the universal gravitation constant.

In the second case, if the force is to become 2.5 times the original and all the variables are constant except d then,

                      2.5F = Gm₁m₂ / (D²)

                               D = 0.623d

Subsituting the known value of d,

                               D = 0.623(6.9 x 10^8) = 4.298 x 10^8 m

The net force on the crate will be 99 N.Option B is correct.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N). it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration.Mathematically in the different components and balancing the equation gets.Components in the x-direction.

When all the forces get resolved the y-direction of forces are;

300 sin 10° +N = 445

N = 445-295.4

N = 392.9 N

The normal force is 392.9 N.

The net force on the crate is found by resolving the force in the x-direction;

F = 300 cos 10° - μN

F= 295.44-196.45

F= 98.99

F=99

Hence, the net force on the crate will be 99 N.Option B is correct.

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A beta particle or an electron is released during beta decay. The charges can be positive or negative. Co changes to Ni, Fe to Mn, Pb to Tl, and Pu to Am.

Beta-decay is the radioactive decay that involves the release of the beta particle or the positron or the electron. The larger nucleus splits during nuclear fission and releases smaller nuclei.

The nuclear reactions are shown as:

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(a) The initial speed must the object be launched so that it reaches

the surface of Planet 2 with zero speed is  √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) An inequality between M₁ and M₂ that represents when (a)

can occur is { M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

(c)  if R₁ = R₂, then M₁ must be greater than M₂ is proved.

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/R²

Given, Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius R₂. The two planets are a distance of L apart, measured from surface to surface. An object is launched with some initial speed from the surface of Planet 1 directly towards Planet 2. For this problem, assume that Planets1 and 2 are stationary.

If v is the launch velocity, then initial total energy will be

T.E  = 1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L)

The final total energy will be

T.E  =0 + ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

From energy conservation principle, we get

1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L) = ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

v = √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) an inequality between M₁ and M₂  so that object reaches the surface of Planet 2 with zero speed is

[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}] =0

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

Thus, this is an inequality between M₁ and M₂.

(c) If R₁ = R₂, then

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L) / R (R+L)   ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L)  ≥ 0

M₁L - M₂L  ≥ 0

M₁ ≥ M₂

M₁ must be greater than M₂.

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Answer:hight

Explanation:

The force is reasonable for making fusion possible in the Sun is heat energy.

When the slow moving neutrons are bombarded with the heavy radioactive nuclei, the product is the more number of neutrons are produced with the large amount of energy. This multiplying process is called nuclear fusion.

The amount of energy produced in such a reaction can be calculated using the equivalence of mass and energy relationship.

E = mc²

The same happens in nuclear fusion where large amount of energy is needed to make more heavy nuclei.

Thus, fusion requires heat energy to continue the reaction.

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Answer:

As electrical power is measured in Watts (W), therefore it must be also be measured in Joules per Second. So we can correctly say that: 1 watt = 1 joule per second (J/s).

Explanation:

The acceleration of Karla's I IPhone being thrown from Mr. Higley's classroom at 0 m/s will be 29.16 m/s²

The rate of velocity change concerning time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.

The given data in the problem is given by ;

u is the initial speed =  0 m/sec

v is the final speed= 35  m/sec

t is the time interval= 1.2 second

a is the acceleration=? m/sec²

The formula for acceleration is;

[tex]\rm a=\frac{v-u}{t} \\\\ a= \frac{35-0}{1.2} \\\\ a= 29.16 \ m./s^2[/tex]

Hence, the acceleration of Karla's iPhone being thrown from Mr. Higley's classroom at 0 m/s will be 29.16 m/s²

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The most electronegative atoms are located in the seventeenth group of the periodic table.

The term electronegativity refers to the ability of an atom to attract the electrons of a bond towards itself.  The more electronegative atom will have the electron pairs closer to itself.

Hence, in this case, the blue atom is more electronegative. The most electronegative atoms are located in the seventeenth group of the periodic table.

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Answer:

coplanar When all forces are acting in the same 

resultunt the single force and associated torque obtained by combining a system of forces and torques acting on a rigid body via vector addition