A pole vaulter runs, plants their pole, bends the pole, and barely clears the bar as seen in the following figure. Describe the energies at each location indicated.

The correct answer is A. The star changes too quickly.

A planet around a massive star is unlikely to evolve complex life because the star changes too quickly.

Massive stars burn through their fuel much more quickly than smaller stars, causing them to evolve much faster.

They also have a much shorter lifespan, typically only lasting a few million years compared to billions of years for smaller stars like the sun.

This means that any planet in the habitable zone around a massive star would have a very short window of opportunity for life to evolve before the star runs out of fuel, explodes as a supernova, or becomes a white dwarf.

Additionally, massive stars produce intense radiation, which can be harmful to life on nearby planets.

They may also be more likely to experience frequent flares or coronal mass ejections that could strip away a planet's atmosphere or damage any life that may have evolved.

While a planet around a massive star may be able to support life for a time, the rapid changes and short lifespan of the star make it much less likely that complex life could evolve and thrive over the long term.

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The electron static force between two objects is determined by the charges on the objects and the distance between them. Therefore, if the magnitude of the charge on each of two negatively charged objects is halved, the electron static force between them will also be halved.

However, the things are positively charged, meaning they lack electrons and negative charges.

If we suppose the items are negatively charged and halve their charges, the electron static force between them will also halve. According to Coulomb's law, the force is directly proportional to the product of the charges (q1 and q2) and inversely proportional to the square of the distance (r).

F ∝ (q₁ ˣ q₂) / r²

If we reduce the magnitude of each charge by half, the force would be:

F' = (q₁' ˣ q₋') / r²

where q₁' and q₂' represent the halved magnitudes of the charges.

Since q₁' = q₁ / 2 and q₂' = q₂ / 2, we can substitute these values into the equation:

F' = ((q₁ / 2) ₓ (q₁ / 2)) / r²

Simplifying further, we have:

F' = (q1 * q2) / (4 * r²)

Therefore, if the magnitude of the charge on each of two negatively charged objects is halved, the electron static force between them will also be halved.

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When the radius of the wire loop is doubled and the current is quadrupled, the torque experienced by the loop increases by a factor of 8.

The torque τ on a circular wire loop spinning in a uniform magnetic field is given by the formula τ = μBsinθ, where μ is the magnetic moment, B is the magnetic field strength, and θ is the angle between μ and B. The magnetic moment μ is given by the product of the current I, the area A of the loop, and the number of turns n (μ = nIA). Since the area of the circle is proportional to the square of the radius (A = πr²), doubling the radius will quadruple the area.

Meanwhile, quadrupling the current will increase the magnetic moment by a factor of 4. Thus, when both the radius and current are changed as described, the magnetic moment increases by a factor of 4 × 4 = 16. Since torque is directly proportional to the magnetic moment (τ ∝ μ), the torque on the loop will increase by a factor of 8, considering that sinθ remains constant.

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If the net external force acting on a system of bodies is zero, then the momentum of the system remains the same. The correct option is C

The law of conservation of momentum, which states that the overall momentum of an isolated system remains constant in the absence of external forces, is a fundamental principle of physics.

Therefore, If the net external force acting on a system of bodies is zero, then the momentum of the system remains the same

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When a bone is caused to twist about a longitudinal axis, the mechanical stress on the bone is known as torsion. Torsion is a type of loading in which a structural element is subjected to twisting about its longitudinal axis. It is characterized by the development of shear stresses that cause the material to twist and deform.

The effect of torsion on a bone depends on its orientation with respect to the direction of the twist. When the bone is subjected to torsion, shear stresses develop on the surface of the bone, leading to deformation. If the torsion is too severe, it can lead to fracture.

Torsion can occur in bones due to a variety of reasons, such as during sports or other physical activities that involve rapid twisting movements. It can also occur due to the weakening of the bone structure, which can result from various medical conditions.

In summary, torsion is a type of mechanical stress that occurs when a bone is twisted about its longitudinal axis, leading to the development of shear stresses and deformation.

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The ball was thrown at an angle of 42.0 degrees (measured from the horizontal) in order to travel 3.30 m across the field at an initial speed of 6.50 m/s.

The projectile motion equations. We know that the ball was thrown horizontally, so its initial vertical velocity is zero.
d = vit + 1/2at^2
3.30 = (6.50)(t) + 1/2(-9.81)(t^2)
t = 0.611 s
and
vf = vi + at
0 = vi + (-9.81)(0.611)
vi = 6.00 m/s

Now we can use trigonometry to find the angle at which the ball was thrown. Since we know the initial horizontal velocity (which is also 6.50 m/s, since the ball was thrown horizontally),
tan θ = vi / vh
tan θ = 6.00 / 6.50

θ = 42.0 degrees

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The strength of the electrostatic force between an electron and a proton is much stronger than the strength of the gravitational force between them. The electrostatic force is about 10^36 times stronger than the gravitational force. This is because the electrostatic force is caused by the electromagnetic interaction between the charged particles, while the gravitational force is caused by the gravitational interaction between the masses of the particles.

Therefore, the electrostatic force dominates at the atomic level, while the gravitational force dominates at the astronomical level. The strength of the electrostatic force between an electron and a proton is significantly stronger than the strength of the gravitational force between them.

Electrostatic force follows Coulomb's Law, while gravitational force follows Newton's Law of Universal Gravitation. Due to the larger proportionality constants and charges in the electrostatic interaction, the electrostatic force is approximately 10^36 times stronger than the gravitational force between an electron and a proton.

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The appropriate responses are;

1. A temperature of -5 K is not possible

2. Radiation

3. Conduction

4. Heat

5. Air

6. Pot B has a higher thermal energy than Pot A

7. The particles are closer together in solids

8. Conduction

The average kinetic energy of the particles in a substance is measured by its temperature. The amount to which an object or environment is hot or cold is a fundamental physical quantity.

Simply said, temperature is a measurement of the amount of heat energy in a system.

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The charge on the oil drop is -4.8x10^-19 C. We know that the charge on an electron is -1.6x10^-19 C. Therefore, to find the number of excess electrons on the oil drop, we divide the charge on the drop by the charge on an electron:

(-4.8x10^-19 C) / (-1.6x10^-19 C/electron) = 3 electrons

Hence, the oil drop has an excess of 3 electrons. This means that the oil drop has gained 3 electrons and now has an overall negative charge.

Electrons are negatively charged particles that orbit the nucleus of an atom. In this case, the excess electrons on the oil drop are responsible for its negative charge.

Understanding the number of excess electrons on an object is important in various fields, such as physics and electrical engineering.

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The intensity of the approaching subway train sound is 10,000 times greater than the intensity of a normal conversation.

To determine the intensity ratio of the two sounds, we need to use the formula:
Intensity ratio = 10^(difference in decibels/10)

The difference in decibels between the approaching subway train (100 dB) and a normal conversation (60 dB) is 40 dB.

So, the intensity ratio of the two sounds would be:
Intensity ratio = 10^(40/10)
Intensity ratio = 10^4

It is important to note that decibels are a logarithmic unit of measurement, which means that each increase in 10 decibels corresponds to a 10-fold increase in sound intensity. Therefore, a 100 dB sound is not simply twice as loud as a 50 dB sound but rather 10,000 times louder. The intensity ratio formula can be used to compare different sounds and determine their relative loudness levels. In this case, the intensity ratio of the approaching subway train sound to a normal conversation is 10,000:1, which demonstrates the significant difference in sound intensity between these two scenarios.

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The latent image in a flat-panel detector is formed by trapped electrons. The correct option is A.

The correct answer is Trapped electrons because in a flat-panel detector, such as in digital radiography or digital mammography systems, the latent image is formed by trapping electrons in a semiconductor material, typically amorphous selenium or silicon. When X-rays pass through the detector, they generate photoelectrons in the semiconductor, which are then trapped in the material due to its electrical properties. These trapped electrons form the latent image, which is later read out and processed to produce the final image.

Explanation for why the other options are not true:

B. Charged capacitors: Charged capacitors can store electrical energy but are not directly involved in forming the latent image in a flat-panel detector. Capacitors are commonly used in electronic circuits for energy storage and signal processing but do not play a role in capturing X-rays or creating the latent image.

C. Electrical resistance: Electrical resistance is a property of materials that determines how easily they allow the flow of electric current. While resistance is involved in the functioning of electronic components, it does not directly contribute to the formation of the latent image in a flat-panel detector. The latent image is created through the interaction of X-rays with the semiconductor material and the trapping of electrons, rather than through changes in electrical resistance.

Therefore, option A is the correct answer.

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The bullet will hit the building at a height of 5.27 meters above the ground. To solve this problem, we need to use the equations of motion in two dimensions.

First, we need to find the time it takes for the bullet to reach the building. Using the formula d = vt + 1/2at^2, where d is the distance, v is the initial velocity, a is the acceleration (which is zero in this case), and t is time, we can rearrange the formula to get t = d/v. Plugging in the values, we get t = 0.288 seconds.

Next, we need to find the height of the bullet when it reaches the building. We can use the formula h = v*sin(theta)*t - 1/2*g*t^2, where h is the height, theta is the angle above the horizontal, and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we get h = 5.27 meters. Therefore, the bullet will hit the building at a height of 5.27 meters above the ground.

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Quantization of electron energy states in an atom is a fundamental concept in atomic physics and quantum mechanics. It refers to the discrete and distinct energy levels that an electron can occupy in an atom.

This quantization is better understood in terms of the electron's wave-like nature. The electron behaves like a wave, and its energy is related to the wavelength and frequency of the wave.
The wave-like behavior of the electron was first proposed by Louis de Broglie in 1924, and it was later confirmed by experiments. According to de Broglie's theory, electrons have wave-particle duality, meaning that they can exhibit both wave-like and particle-like behavior. When an electron is confined to an atom, its wave-like behavior leads to the quantization of energy levels.
The quantization of energy levels in an atom arises from the fact that electrons can only occupy specific orbitals around the nucleus. These orbitals have specific energies associated with them, and the electron can only exist in one of these energy levels. When an electron absorbs or emits energy, it must do so in discrete packets or quanta, which correspond to the energy difference between the energy levels.
In summary, the quantization of electron energy states in an atom is a consequence of the wave-like nature of the electron. It arises from the fact that electrons can only occupy specific orbitals around the nucleus, and their energies are quantized in these orbitals. This concept is fundamental to our understanding of atomic structure and has important implications for a wide range of fields, including chemistry, materials science, and electronics.

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If a fish looks upward at 45 degrees with respect to the water's surface, it will see option a, the sky and possibly some hills.

When a fish looks upward at a 45-degree angle with respect to the water's surface, it will see the sky and possibly some hills. This is because light rays refract when they pass from one medium to another with different optical densities.

As light travels from air to water, it slows down, and its path bends towards the normal, which is perpendicular to the water's surface. This bending of light is called refraction. When the fish looks upwards, it sees the light that has been refracted by the water, and this light carries information about the sky and the surrounding landscape.

However, the amount of refraction depends on the angle of incidence of the light ray, so the fish will not see the entire sky but only a portion of it. At a 45-degree angle, the fish will see a wider view of the sky and possibly some hills, depending on the surrounding topography. Therefore, the fish will not see the bottom of the pond, which is below its line of sight.

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The net torque on the 2.0-meter-long uniform beam is 0 Nm when the axis of rotation is at point C, the center of mass.

To calculate the net torque on the beam, we need to determine the torques created by each force around point C and sum them up. Since the beam is uniform, its center of mass is exactly in the middle of the beam, at a distance of 1 meter from both ends.

Torque is calculated as the product of force and the perpendicular distance from the axis of rotation (τ = F × d). The forces acting on the beam are balanced, meaning their torques around the center of mass cancel each other out, resulting in a net torque of 0 Nm.

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The Linear perspective creates the illusion of depth in the graphic on the first page. Linear perspective creates depth using parallel lines. Railroad tracks illusion shows this by converging lines.

Lines converge into the distance, forming a point on the horizon, which our brain interprets as depth perception cues. The white bar seems further and larger due to linear perspective manipulation. The white bar seems smaller due to its perceived proximity and the brain's interpretation of converging lines as depth indicators.

Using linear perspective, the graphic tricks our brain into perceiving size and distance differently, showing the importance of visual cues in determining depth and size.

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Answer:-720j.

Explanation:

The kinetic energy of the merry-go-round can be calculated by using the formula for the kinetic energy of a rotating object, which depends on its moment of inertia and angular velocity.

In this case, considering the given force, radius, and time, the kinetic energy of the merry-go-round after 3.0 seconds is 6750 J.

The merry-go-round is a solid cylinder, so we can use the formula for the moment of inertia of a solid cylinder:

I = (1/2) * m * r^2

where m is the mass of the cylinder and r is its radius.

To find the mass of the cylinder, we can use the formula for force:

F = m * a

where F is the applied force and a is the acceleration. Since the merry-go-round is started from rest, the acceleration is equal to the tangential force divided by the mass:

a = F / m

Substituting the given force of 50.0 N, we can solve for the mass:

m = F / a = 50.0 N / a

Next, we calculate the moment of inertia using the mass and radius:

I = (1/2) * m * r^2 = (1/2) * (50.0 N / a) * (1.5 m)^2 = 1.125 / a

Now, we need to find the angular velocity (ω) of the merry-go-round after 3.0 seconds. Since the merry-go-round starts from rest and has a constant angular acceleration, we can use the equation:

ω = α * t

where α is the angular acceleration and t is the time. The angular acceleration is determined by dividing the tangential force by the moment of inertia:

α = F / I = 50.0 N / (1.125 / a) = 44.44 a / N

Substituting the given time of 3.0 seconds:

ω = (44.44 a / N) * 3.0 s = 133.32 a / N s

Finally, we can calculate the kinetic energy using the formula:

KE = (1/2) * I * ω^2

Substituting the moment of inertia and angular velocity:

KE = (1/2) * (1.125 / a) * (133.32 a / N s)^2 = 0.25 * 1.125 * (133.32)^2 = 6750 J

Therefore, the kinetic energy of the merry-go-round after 3.0 seconds is 6750 J.

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The flow rate is constant, the pressure exerted by water in a confined pipe will remain constant, regardless of the velocity of the water.

When water flows through a confined pipe, it experiences frictional forces against the inner walls of the pipe. These forces lead to a pressure drop in the direction of flow. According to Bernoulli's principle, as the velocity of the water increases, the pressure it exerts against the inner walls of the pipe decreases. This is because the increase in velocity results in a decrease in pressure energy, as the kinetic energy of the water molecules increases.

However, if the flow rate of water is constant, the velocity of the water will remain constant as well. Therefore, the pressure it exerts against the inner walls of the pipe will also remain constant, as long as the pipe is of a uniform diameter and there are no obstructions in the pipe.

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True. Each actin molecule is shaped like a golf club, with a straight portion ending in a globular head.

Actin is a protein that makes up the structural framework of cells, providing the ability to move and change shape. The actin molecule consists of a long, twisted chain of amino acids that forms a filament. The globular head of the actin molecule is responsible for binding to other proteins, such as myosin, to generate the force needed for movement. The straight portion of the actin molecule provides stability and flexibility to the filament. Understanding the structure of the actin molecule is important in understanding the mechanisms behind cell movement and muscle contraction. We can say that the actin molecule is an important part of cell structure. It forms filaments that help cells move and change shape. Each actin molecule is shaped like a golf club, with a straight portion that provides stability and flexibility and a globular head that binds to other proteins to generate force. Knowing the structure of the actin molecule is important in understanding how cells move and how muscles contract.

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If there is no water coming out of the cooling water discharge outlet after starting an outboard engine, there are a few steps you can take to troubleshoot the issue:

Check the water intake: The first thing to check is the water intake. Ensure that it is not clogged or blocked by any debris. If there is an obstruction, clear it out and try again.
Check the water pump impeller: The water pump impeller is responsible for pumping water through the engine's cooling system. If it is damaged or worn out, it may not be able to pump water effectively. Inspect the impeller and replace it if necessary.

Check the water pump housing: The water pump housing can also become clogged or corroded over time, preventing the water from flowing through the system. Inspect the housing and replace it if necessary.
Check the thermostat: If the engine's thermostat is stuck closed, it can prevent water from flowing through the cooling system. Check the thermostat and replace it if necessary.

It's important to address any cooling system problems as soon as possible to prevent damage to the engine.

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The <input> element is used to mark the form controls that are designed to receive user responses.

The <input> element is a self-contained element in HTML that creates a form control widget. It can be used to create a wide variety of form controls, including text boxes, password fields, checkboxes, radio buttons, and many others.

By specifying different attributes on the <input> element, developers can customize the appearance and behavior of the form controls, such as setting a default value, defining a maximum length, or specifying a validation pattern.

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The squirrel's velocity vector changes both in magnitude and direction as it moves in the park.

We are given the position vector of a squirrel running in a park. The position vector is given as r⃗ =[(0.280m/s)t+(0.0360m/s²)t2]i^+ (0.0190m/s³)t3j^, where i^ and j^ are the unit vectors in the x and y directions, respectively.

To find the x-component of the velocity of the squirrel as a function of time, we need to take the derivative of the x-component of the position vector with respect to time. This is because velocity is the rate of change of position with respect to time.

So, we differentiate the x-component of the position vector with respect to time as follows:

vx(t) = d[x(t)]/dt

       = d[(0.280m/s)t+(0.0360m/s²)t2]/dt  

       = (0.280m/s) + (0.0720m/s²)t

Here, we have used the fact that the derivative of t^n is nt^(n-1).

Similarly, to find the y-component of the velocity of the squirrel as a function of time, we need to take the derivative of the y-component of the position vector with respect to time. So, we differentiate the y-component of the position vector with respect to time as follows:

vy(t) = d[y(t)]/dt

       = d[(0.0190m/s³)t3]/dt

       = (0.0570m/s²)t2

Here, we have used the fact that the derivative of t^n is nt^(n-1) and the constant coefficient drops off since its derivative is zero.

Hence, we have found the x-component and y-component of the velocity of the squirrel as a function of time. The x-component is given by vx(t) = (0.280m/s) + (0.0720m/s²)t, and the y-component is given by vy(t) = (0.0570m/s²)t2.

The x-component of the velocity of the squirrel increases at a constant rate of 0.0720 m/s² since the position of the squirrel is given by a quadratic function of time. The y-component of the velocity of the squirrel increases at a varying rate since the position of the squirrel is given by a cubic function of time.

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The resistance of wire W2 can be determined by using the formula for resistance, which depends on the resistivity, length, and cross-sectional area of the wire.

Since wire W1 and W2 are made from the same metal, their resistivity is the same. Considering the given length and cross-sectional area, the resistance of W2 is 8Ω.

The resistance of a wire can be calculated using the formula:

R = (ρ * l) / A

where R is the resistance, ρ is the resistivity of the material, l is the length of the wire, and A is the cross-sectional area of the wire.

Since wire W1 and W2 are made from the same metal, they have the same resistivity, denoted as ρ. Therefore, the resistivity is constant for both wires.

For wire W2, the length is given as l2 and the cross-sectional area is 2A. Substituting these values into the resistance formula:

R2 = (ρ * l2) / (2A) = (1/2) * [(ρ * l2) / A]

Since we know the resistance of W1 is 16Ω, we can substitute this value into the resistance formula for W1:

16Ω = (ρ * l) / A

Simplifying, we have:

ρ * l = 16Ω * A

Substituting this into the expression for R2:

R2 = (1/2) * [(ρ * l2) / A] = (1/2) * [(16Ω * A) / A] = 8Ω

Therefore, the resistance of wire W2 is 8Ω.

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The density of air at the bottom of a deep mine shaft would be slightly higher than the density of the atmosphere at the surface of the ground. This is because air density is affected by pressure, and pressure increases with depth. At sea level, the atmospheric pressure is about 101.3 kPa, but for every 10 meters of depth, the pressure increases by about 14.5 kPa. This increase in pressure causes air molecules to be pushed closer together, resulting in an increase in density.

Therefore, at the bottom of a deep mine shaft, where the pressure is much higher than at the surface, the density of air would be higher. This increase in air density could have various effects on the behavior of sound, light, and other phenomena, which would need to be taken into account when designing and operating equipment in such environments.

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The correct option is d of the following processes has added heat to Earth's interior during or after its formation.

All of these processes have added heat to Earth's interior during or after its formation. The collision of asteroids and meteoroids with Earth during the early stages of its formation caused the planet to heat up due to the impact energy. The formation and sinking of masses of iron and nickel towards the Earth's core during the planet's differentiation process caused the release of gravitational potential energy that also contributed to the heat in the Earth's interior. Lastly, radioactive decay of isotopes such as uranium, thorium, and potassium generates heat as a byproduct and has been an ongoing process since the Earth's formation. All these processes have added heat to Earth's interior, which plays a crucial role in the planet's geology, plate tectonics, and the existence of a magnetic field.

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Answer:

The momentum of the system is conserved if net external force is zero.

The mass of a star is a crucial factor in determining its life cycle and eventual fate. Scientists classify stars based on their mass because this classification helps them predict the life cycle and ultimate fate of a star.

A star's mass determines its luminosity, surface temperature, and the amount of fuel available for nuclear fusion reactions. These fusion reactions release energy that counteracts the force of gravity, which would otherwise cause the star to collapse.

The more massive a star, the more energy it produces, and the faster it consumes its fuel. This means that higher mass stars have shorter lifetimes than lower mass stars.

Stars are typically divided into three groups: low-mass stars, intermediate-mass stars, and high-mass stars. Low-mass stars, which are less than 2 times the mass of the sun, have the longest lifetimes and eventually evolve into white dwarfs.

Intermediate-mass stars, between 2 and 8 times the mass of the sun, evolve into neutron stars or black holes. High-mass stars, which are more than 8 times the mass of the sun, burn through their fuel quickly and end their lives in supernova explosions, leaving behind neutron stars or black holes. Thus, mass is a critical factor in determining a star's life cycle and ultimate fate.

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The virtual inverted image will be formed 2.4324 cm inside the ball.

The mirror formula gives the relation between the distance of the image from the mirror and the focal length. expression for the mirror formula is

1/f = - 1/u + 1/v

where: f = focal length of the mirror

u = object distance from the mirror

v = image distance from the mirror

Given: diameter of ball, d = 9.0 cm

object distance from the mirror, u = - 30.0 cm

d = 4f

f = d/4

f = 9/4

f = 2.25 cm

using the mirror formula,

1/f = - 1/u + 1/v

1/2.25 = 1/30 + 1/v

solving the above equation, we get

v = 2.4324 cm

Therefore, the virtual inverted image will be formed 2.4324 cm inside the ball.

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