(a) The second stone hit after 2.91 seconds
(b) The initial velocity of the second stone must be 15.8 m/s vertically downward.
(c) The velocity of each stone when they reach the water is: First stone : -30.7 m/s Second stone: -34.5 m/s
The height and velocity of the stones can be calculated using the following equations:
y = y0 + v0 · t + 1/2 · g · t²
v = v0 + g · t
Where:
y = height at time "t".
y0 = initial height.
v0 = initial velocity.
t = time.
g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).
v = velocity at time "t".
a) If we place the origin of the frame of reference on the water, then, the height of both stones when they hit the water will be 0. Using the equation of height for the first stone, we can obtain the time when the height is 0:
y = y0 + v0 · t + 1/2 · g · t²
0 = 50.0 m -1.91m/s · t - 1/2 · 9.81 m/s² · t²
0 = 50.0 m - 1.91 m/s · t - 1.6 m/s² · t²
Solving the quadratic equation:
t = 2.91 s
The two stones hit the water 2.91 s after the release of the first stone.
b) The second stone reaches the water in (2.91 s - 1.00 s) 1.91 s after released (remember that it was released 1.00 s after the first stone but both reached the water simultaneously). Then, using the equation of height, we can obtain the initial velocity knowing that at t = 1.91 s, y = 0:
y = y0 + v0 · t + 1/2 · g · t²
0 = 48.0 m + v0 · 1.91 s - 1/2 · 9.81 m/s² · (1.91 s)²
(-48.0 m + 1/2 · 9.81 m/s² · (1.91 s)²) / 1.91 s = v0
v0 = -15.8 m/s
The initial velocity of the second stone must be 15.8 m/s vertically downward.
c) We have to use the equation of velocity for each stone. We already know the time when the stones reach the water and the initial velocities:
First stone:
v = v0 + g · t
v = -2.18 m/s - 9.81 m/s² · 2.91 s
v = -30.7 m/s
Second stone:
v = v0 + g · t
v = -15.8 m/s - 9.81 m/s² · 1.91 s
v = -34.5 m/s
The velocity of each stone when they reach the water is:
First stone : -30.7 m/s
Second stone: -34.5 m/s
Therefore, the velocity of the first and second stones are -30.7 m/s and -34.5 m/s.
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An athlete at the gym holds a 2.5kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg
a)
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor?
Express your answer to two significant figures- Newton meter
b)
What is the magnitude of the torque about his shoulder if he holds his arm straight, but 55? below horizontal?
Express your answer to two significant figures - newton meter.
torque τ = 25.24 N-m
torque τ = 12.68 N-m
given data in the qstion:mass of the ball is= 2.5 kg
arm length is l = 70 cm = 0.7 m
mass of arm is = 4 kg
solution by using data:-we get here center of mass that is
center of mass = (m1+m2) rcm =m1 r1+m2 r2
center of mass = 0.44545 m
and
the torque will be
torque τ = F × r ×sinθ
torque τ = (4+2.5)9.8 × 0.4454 × sin90
torque τ = 25.24 N-m
and now we get the magnitude of the torque
magnitude of the torque is τ = F × r ×sinθ
magnitude of the torque is τ = (4+2.5)9.8 × 0.4454 × sin60
magnitude of the torque is τ = 12.68 N-m
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of the following options, which is not one of the temperaments first proposed by thomas and chess (1977)? a. the easy babyb. the difficult babyc. the slow to warm up babyd. the secure baby
The following options, the secure baby is not one of the temperaments first proposed by Thomas and chess (1977)
Thomas and Chess said that there are three general types of temperaments in children:
• Easy,
• Slow-to-warm
• Difficult.
1. Easy children are generally happy, active children from birth and adjust easily to new situations and environments.
2. Slow-to-warm children are generally mellow, less active babies from birth, and can have some difficulty adjusting to new situations.
3. Difficult children do have not regular habits and biological routines (examples-eating, sleeping), have difficulty adjusting to new conditions, and often show negative moods very intensely. As the category name suggests, these children are the most difficult for caregivers to satisfy and maintain the energy and happiness to care for on a daily basis.
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The ______ model develops knowledge to observe, analyze, and critique physical activity and sport issues and topics in a variety of contexts.
The Cultural Studies model develops knowledge to observe, analyze, and critique physical activity and sports issues and topics in a variety of contexts.
Cultural Studies:
The science of comprehending contemporary society, with a focus on politics and power, is known as cultural studies. It is an all-encompassing phrase that is used to discuss a variety of topics, such as media studies like journalism and film, sociology, industrial culture, globalization, and social theory. By pursuing this field, one is attempting to unravel the human condition.
Students who want to work in the media or politics find this profession to be quite popular due to the variety of disciplines it offers. Understanding culture in connection to power is one of the goals of science. It examines the varied social and political systems found in many nations as well as how they relate to one another and the rest of the world.
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astronomers observe galaxies and categorize them according to four different kinds of shapes: elliptical, spiral, barred-spiral, and irregular. in addition to shape, each of the four different galaxy types can be described by other common characteristics. match the following characteristics with their corresponding galaxy type.
Matching of the characteristics with their corresponding galaxy type is as follows.
Elliptical galaxy (E): Round, no disk, very little gas and dust, only old stars.
Spiral galaxy (S): Central bulge, flattened disk, spiral arms, gas, dust, young stars.
Barred-spiral galaxy (SB): Elongated central structure, flattened disk, spiral arms, gas and dust, young stars.
Irregular galaxy (Irr): Asymmetric, often with gas, dust, and young stars.
Galaxies are huge collections of gas, dust, and stars. Gravity and dark matter shape and held them together. Scientists have segmented galaxies into 4 main types. These are of spiral, elliptical, peculiar, and irregular shape.
In the given question two columns of matching are not given. The rest part of the question is
Drag the appropriate items to their respective bins.
-Round, no disk, very little gas and dust, only old stars.
-Central bulge, flattened disk, spiral arms, gas, dust, young stars.
-Elongated central structure, flattened disk, spiral arms, gas and dust, young stars.
-Asymmetric, often with gas, dust, and young stars.
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when a car moves towards a listener, the sound of its horn seems relatively group of answer choices low pitched (low frequency) high pitched (high frequency) normal (no change in frequency)
When an automobile approaches a listener, the noise of its horn appears to be somewhat higher in pitch than usual.
When someone hears the horn of an approaching automobile, the frequency you hear is higher than the frequency heard by a passenger in the car because the sound you hear has wave crests that are wider apart due to the distance that the car covers in one period.
The Doppler effect is a shift in sound wave frequency that happens when the originator of the sound waves moves relative to a motionless listener. As the generator of sound waves gets closer to the listener, the frequency & pitch of the sound increase.
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Seperate visual images may appear continues due to
Separate visual images may appear continuous due to iconic memory.
option A is the correct answer.
What is Iconic memory?
Iconic memory is the visual sensory memory register which stores visual images after the extinction of a physical stimulus.
Iconic memory is part of the visual memory system, which includes long-term memory and visual short-term memory.
Images are processed in the iconic memory in the following ways. Once the stimulus of a perceived image is seen or perceived, iconic memory begins.
The automatic recognition of the visual stimulus display is processed by the occipital lobe and transferred to iconic memory, where it remains for only milliseconds before being transferred to visual working memory or being discarded.
The persistence of vision in known to be caused by iconic memory.
Thus, we can conclude that separate visual images may appear continuous due to persistence in vision caused iconic memory. So option A is the correct answer.
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131 53i is an artificially made radioactive isotope of iodine, produced during the operation of nuclear power plants and the detonation of nuclear bombs. exposure to high concentrations of 131 53i represents a serious risk for human health. however, small doses of this radioactive isotope are put to good use in medical studies. 131 53i is widely used in treating thyroid cancer and in diagnosis of abnormal liver and kidney function.
Part A
What is emitted when the radioactive nucleus of 131 53I decays to form the stable isotope of xenon 131 54Xe?
part B
What is the energy Q released when 131 53Idecays and 131 54Xe is formed? The atomic mass of 131 53I is 130.906118 u and the atomic mass of 131 54Xe is 130.90508 u.
Part C
The newly formed xenon nucleus is left in an excited state. Thus, when it decays to a state of lower energy a gamma ray is emitted. If the wavelength of the emitted gamma ray is 3.44×10−12 m , what is the decrease in mass, ΔmXe, of the xenon nucleus as a result of this decay?
A . The emitted particle is β⁻.
The radiactive isotope ¹³¹ I ₅₃ decays into ¹³⁵Xe₅₄ by emitting a beta particle and an information .
¹³¹ I ₅₃ --> ¹³⁵Xe₅₄+ β⁻ +v + Q
Therefore, The emitted particle is β⁻.
B .the energy Q released when 131 53I decays and 131 54 Xe is formed is 0.966MeV
Q= Δmc²
= (130.906118u - 130.90508u - 0.32*10⁻⁴u)(931.5MeV/c²)
= 0.966MeV
C . the decrease in mass, ΔmXe, of the xenon nucleus is 3.87*10⁻⁴ u.
= hc/λ
= [tex]\frac{(6.625*10^{-34} )(3*10^{8} m/s)}{3.44*10^{-12} }[/tex]
= 0.3605 MeVj
Δm = (0.3065)MeV([tex]\frac{1u}{931.5Mev/c^{2} }[/tex])
= 3.87*10⁻⁴ .
Mass is a quantitative measure of inertia in physics and a fundamental property of all matter. In effect, it is the resistance that an object offers to changes in velocity or position when a force is applied. The greater the mass of an object, the smaller the change caused by an applied force.
Mass can be experimentally defined as the inertia of a body, a measure of its resistance to acceleration (change in velocity) when a net force is applied. An object's mass also determines the strength of its attraction to other bodies. size. A 2kg cast iron weight used for scales. The decrease in mass, ΔmXe, of the xenon nucleus is 3.87*10⁻⁴ u
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a bat flies towards a moth at 8.0 m/s while the moth is flying towards the bat at 4.6 m/s. the bat emits a sound wave of 50.4 khz. ef picup part description answer save status a. what is the frequency of the wave detected by the bat after the wave reflects off the moth? (include units with answer) format check click here to check your answer 9.09 pts.100% 2% try penalty 1 hint available
the frequency of the wave detected by the bat after the wave reflects off the moth is 54.24 KHz .
Calculation :
given ,
speed of sound(v) = 343 m/s
speed of bat(v bat) = 8.0 m/s
speed of moth (V moth) = 4.6 m/s
real frequncy of moth = 50.4 KHz
the first apparent heard by moth is :
f moth = [tex]\frac{V+Vmoth}{V-Vbat}*f[/tex]
apparent frequently heard by the bat when the sound is reflected from the moth :
fbat : [tex](\frac{V+Vbat}{V-Vmoth}) (\frac{V+Vmoth}{V-Vbat} )f[/tex]
f bat = [tex](\frac{343+8}{343-4.6} )(\frac{343+4.6}{343-8} )(50.4)[/tex]
= 54.24
Frequency is the number of occurrences of a repeating event per unit time. [1] For clarity, also called temporal frequency, which is different from angular frequency. Frequency is measured in Hertz (Hz) and corresponds to one event per second. Duration is the reciprocal of frequency because duration is the time interval between events. [2]
For example, if the heart beats 120 times per minute (2 hertz), the period T (the interval between repeated beats) is 0.5 seconds (60 seconds divided by 120 beats). value). Frequency is an important parameter used in science and engineering to describe the speed of vibrations and vibrational phenomena such as mechanical vibrations, audio signals (sound), radio waves, and light.
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when zero external work is being done on a system, which of the following statements are necessarily true about that system?
Since there was no work done, there was also no applied force. Given that Force = Mass × Acceleration and that the mass is still not zero, the acceleration must be zero.
Describe a force:Any action that modifies or sustains an object's motion is referred to as a force. 2) Describe how Newton's laws of motion relate to force. Newton's laws of motion are frequently used to explain the concept of force.
How does the magnitude of the force relate to the object's weight?The weight of a item determines the size of the force. When dragged or pushed by hand, flexible materials can alter their form. When opposed to pulling, pulling a empty sledge took less force.
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According to the video, which of the following is not a tool that scientists use to monitor air pollution?
thermometer
The following is not tool that scientists use to monitor air pollution is the thermometer.
Air quality is measured using the Air Quality Index or AQI. AQI works like a thermometer with a range of 0-500 degrees. However, AQI is a way of showing changes in the amount of air pollution, not changes in temperature. Avoid using petrol-powered lawns and gardening supplies.
Motor vehicle emissions of fuel oil and natural gas used to heat homes by-products of manufacturing and power generation especially coal-fired power plants and smoke from chemical production are major sources of man-made air pollution. This is the main cause. Reduce the number of trips by car. Reduce or eliminate the use of fireplaces and wood stoves. Do not burn leaves garbage or other objects.
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the theory that explains why and how continents move is called; the first motion of an earthquake begins at the; tectonic plates are blocks of; the first motion of an earthquake begins at the ______________________; a terrane becomes part of a continent in a process called; why so many earthquakes right now; the most conclusive proof for continental drift was provided by; convection, ridge push, and slab pull work together to produce what?
The theory that explains about the movement of continents is called continental drift. It states that the earth's continents have moved over time, relative to each other.
Earthquake is one of the major natural disasters. It causes a huge loss of life and property around the world. It occurs due to the shaking of the surface of the earth due to the sudden release of energy in the earth's crust. The first motion of an earthquake begins at the focus. It is the place inside the earth's crust where the earthquake originates.
A terrane becomes a part of a continent in a process called accretion.
Alfred Wegener produced evidence in 1912 that continents are in motion but as he could not explain what forces could move them geologists rejected his ideas. Almost 50 years later, Harry Hess confirmed Wegener's ideas by using the evidence of seafloor spreading to explain his statements.
Convection, ridge push and slab pull work together to produce constant plate tectonic motion.
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a radioactive material produces 1390 decays per minute at one time, and 4.1 h later produces 150 decays per minute. What is its half-life?
The half-life of the radioactive material is about 2.75 hours.
To determine the half-life of a radioactive substance, we need to determine the time it takes for the number of decays per minute to decrease by a factor of two.
You can set up an expression that relates decays per minute at two time points.
1390 decays/min ×(1/2)^(t/(half-life)) = 150 decays/min
where t is the elapsed time between two measurements (4.1 hours) and (1/2)^(t/(half-life)) is the decay factor, dividing the number of decays per minute by half. reduce to
By rearranging the equation, we can solve for the half-life.
half-life = t ×log(2) / log((1390/150)^(1/t))
Substituting the values of t and the number of decays per minute at the two time points, we get
half-life = 4.1 ×log(2) / log((1390/150)^(1/4.1))
This simplifies to:
half-life = 4.1 × 0.693 / log (9.27)
=2.747 hours.
Therefore, the half-life of the radioactive material is about 2.75 hours.
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9.4 the average pressure and shear stress acting on the surface of the 1-m-square flat plate are as indicated in fig. p9.4. determine the lift and drag generated. determine the lift and drag if the shear stress is neglected. compare these two sets of results.
The lift and drag if the shear stress is neglected, than the values of forces F0 = 1.1955 KN & F1 = 8.014 KN.
The average pressure and shear stress acting on the surface of the 1-m-square flat plate.
P1 = 2.3 * 3 = 6.9 KN/m^2
P2 = -1.2 KN/m^2
T1 = 7.6 * 10^-2 * 2 = 0.152 KN/m^2
T2 = 0.058 KN/m^2
Now,
Drag force
F0 = F1sinα - F2sinα + FS1cosα+FS2cosα
= P1Asinα - P2sinα + T1Acosα + T2Acosα
= Asinα(P1-P2) + Acosα(T1 + T2)
= 1.sin(T)[6.9-(-1.2)] + 1. cos (T)[0.152 + 0.058]
= 0.98714 + 0.20843
= 1.1955 KN
Lift force
F1 = F1cosα - F2cosα - FS1sinα - FS2sinα
= P1cosα - P2Acosα - T1Asinα - T2Asinα
= Acosα(P1 - P2) - A.sinα(T1 + T2)
= 1. cos(T)(6.9 - (-1.2)) - 1. sin(T)(0.152 + 0.058)
= 8.014 KN
Therefore, the lift and drag if the shear stress is neglected, than the values of forces F0 = 1.1955 KN & F1 = 8.014 KN.
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all points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to all points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to general plane motion translation rotation about a fixed axis none of the above
All points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to general plane motion.
The general plane motion refers to the movement of a rigid body in two dimensions, where the body can translate (move in a straight line) and rotate about a fixed axis. When a rigid body is subjected to general plane motion, all points on the body will move with the same velocity and acceleration, as the body is rigid and does not deform.
This is in contrast to translation, which refers to movement in a straight line, and rotation about a fixed axis, which refers to rotation around a fixed point. In these cases, the points on the body will not necessarily move with the same velocity and acceleration, as the body is able to deform and rotate.
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in the two-string problem, tying the pliers to one of the strings best represents a(n)___state.
In the two-string problem, tying the pliers to one of the strings best represents an intermediate state.
Describe the two-string problem?
In the two string problem, the subjects are shown two strings hanging from the ceiling and are instructed to tie the strings together.
The strings are placed apart so that the subjects are unable to grasp both strings simultaneously.
In order to get the solution of the two-string problem, it involves the use of items which are available in the vicinity of the strings.
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using energy considerations, calculate the average force (in n) a 60.0 kg sprinter exerts backward on the track to accelerate from 2.00 to 5.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 n against him. (enter a number.)
The average force is 55.62 Newtons
If acceleration from 2 meters per second to 5 meters per second is necessary within 25 meters against an average force of 30 Newtons, the sprinter must exert the force of approximately 55.62 Newtons.
Force:
A force is an influence that can alter an object's motion according to physics. A force can cause an object with mass to accelerate when it changes its velocity, such as when it moves away from rest. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F.Since forces are perceived as pushes or pulls, this can offer a simple explanation of how forces are described.
Complete question:
Using energy considerations, calculate the average force (in N) a 61.0 kg sprinter exerts backward on the track to accelerate from 2.00 to 5.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 N against him. (Enter a number.)
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if you were drawing an imaginary solar system which of the following would most likely be best to use to determine which planet has the most moons revolving about it?
Mass and distance between planets
The acceleration of a planet in its orbit around the Sun depends upon the mass of the Sun and the inverse square of the planet's distance from the Sun. As the planet moves further away in its orbit around the Sun, the gravitational force exerted by the Sun on the planet decreases.But a planet's size is not necessarily proportional to its mass. In the end, how massive a planet is has more to do with its composition and density. So while a planet like Mercury may be smaller in size than Jupiter's moon Ganymede or Saturn's moon Titan, it is more than twice as massive than they are.
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this is the distance from the peak to a peak of a successive wave.; this the bottom, or lowest point, of a wave.; this is the material in which a mechanical wave travels; this is the constructive or destructive overlap of waves.; a rhythmic disturbance that carries energy through matter or space.; the point where a sound or other wave originates.; the complete range of light waves organized by wavelength/frequency.; this is the peak, or highest point, of a wave.
The peak to peak distance of successive wave is the wavelength, trough is the bottom of the wave, the wave travels in a medium, the constructive or destructive overlap of the Waves is interference, disturbance in space is called wave, the point where the wave originate is called source, the complete range of the light wave is called electromagnetic spectrum and the peak of the wave is called crest.
A wave carries a lot of information about itself.
The peak to peak distance between the two successive wave is called the wavelength of the wave.
The material in which the mechanical wave travels is called medium.
The interference of two waves can be constructive or destructive overlap of the waves.
A wave is basically a rhythmic disturbance that carries energy through matter or space where a sound or other waves originate is called a source while the complete range of light wave which when organised in a complete manner on the basis of wavelength and the frequency is said to be a electromagnetic spectrum the peak what the highest point of a wave is called the crest of the wave.
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in comparing two unequal forces on a rigid body, is it possible to have the larger force produce less torque than the smaller force?
It is not possible to have the larger force produce less torque than the smaller force for a rigid body because they will produce the same zero torque.
What is torque?
Torque can be defined as a rotational effect caused by an applied force on an object.
In other words torque refers to the twisting force that causes motion or the the turning effect of an applied force.
Mathematically, the formula for an applied torque is given as;
τ = Fr
where;
F is the applied forcer is the perpendicular distance of the objectFor a rigid body, the resultant torque applied to such body will be zero. Hence, both large force and small force will produce the same torque (twisting effect).
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The jumper has a mass of 55 kg, and the bridge's height above the river is 150 m. The rope has an unstretched length of 8 m and stretches a distance of 5 m before bringing the jumper to a stop. Determine the maximum speed of the jumper and the spring constant of the rope. In your calculation, use g 10 N/kg. m/s Vmax k = N/m E.
Now suppose the jumper has a mass of 80 kg. Do you think the maximum speed of the jumper will increase, decrease, or stay the same? Will the rope need a larger, smaller, or the same spring constant to bring the jumper to a stop in the same distance as part D?
The speed of jumper is 54.22 m/s and spring constant of the rope is 6468N/m.
Given data:
The mass of jumper is, m = 55 kg.
The height of bridge above the river is, h = 150 m.
The length of unstretched rope is, L = 8m.
The stretched length is, L' = 5m.
In this problem, when the jumper will jump then the only potential energy of the jumper will get converted into the spring potential energy of the rope. So we can say that the relation will be,
potential energy of jumper = spring potential energy of rope.
Here, k is the spring constant.
Solving as,
mgh = 1/2 KI²
55 × 90.8 × 150 = 1/2 × k × 5 × 5k
k = 6468 N/m
Now, apply the third kinematic equation of motion to calculate the final speed of jumper as,
v² = U² + 2as
We get U= 54.22 m/s.
Thus, we can conclude that the speed of jumper is 54.22 m/s and the spring constant of the rope is 9187.5 N/m.
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At temperatures near room temperature, the temperature dependence of the conductivity for intrinsic germanium is found to be given by o = CT-3/2 exp(- 2KT where C is a temperature-independent constant and T is in Kelvins. Using the above equation to calculate the intrinsic electrical conductivity of germanium at 175 °C
Df/dp<0 means rate of change of decomposition with respect to pressure increase with increasing pressure.
4f^2p/(1-f^2)= k
4f^2p=k(1-f^2)
Taking derivative with respect to p
D/dp(4f^2p)=d/dp(k(1-f^2))
4f^2+8fpdf/dp=-2kfdf/dp
(K+4p)df/dp=-2f
Df/dp=-2f/k+4p
Form eq 4f^2p/1-f^2=k
4f^2p=k(1-f^2)
F^2= k/4p+k
Put it in last eq we can say that df/dp <0
Step 1: Calculate the temperature in Kelvins. To do this, add 273.15 to the given temperature in Celsius:
T = 175 + 273.15 = 448.15 K
Step 2: Calculate the temperature-independent constant C. This can be found by plugging in the given temperature (in Kelvins) and conductivity (o) into the equation:
o = CT-3/2 exp(- 2KT
C = o / (T-3/2 exp(- 2KT))
Step 3: Plug in the values for T and C into the equation and solve for the conductivity (o):
o = CT-3/2 exp(- 2KT
o = (C)(448.15)-3/2 exp(- 2K(448.15))
o = (C)(448.15)-3/2 exp(- 896.3K)
o = (C)(448.15)-3/2 (5.5 x 10-395)
o = (C)(2.48 x 10-397)
Therefore, the intrinsic electrical conductivity of germanium at 175 °C is
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Can someone help solve this, and explain if you're able to.
The net electric force on particle q₂ is determined as 27.94 N.
What is the net force of particle q₂?
The net force of particle q₂ is determined by applying Coulomb's law of electrostatic force.
The electric force between particle q₁ and q₂ is the attractive force and the magnitude is calculated as;
F₁₂ = kq₁q₂ / r²
where;
K is the Coulomb's constantq₁ is the magnitude of charge 1q₂ is the magnitude of charge 2r is the distance between charge 1 and charge 2F₁₂ = (9 x 10⁹ x 18.1 x 10⁻⁶ x 11.2 x 10⁻⁶) / (0.28²)
F₁₂ = 23.27 N
The electric force between particle q₃ and q₂ is the attractive force and the magnitude is calculated as;
F₂₃ = kq₃q₂ / r²
F₂₃ = (9 x 10⁹ x 5.67 x 10⁻⁶ x 11.2 x 10⁻⁶) / (0.35²)
F₂₃ = 4.67 N
The net force on the particle q₂ is calculated as;
F (net) = F₁₂ + F₂₃
F (net) = 23.27 + 4.67
F (net) = 27.94 N
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the state of stress on a thin-walled cylindrical vessel can be found through equilibrium equations and the assumption that the stresses in the wall thickness have a uniform distribution. summing the forces in the longitudinal direction can obtain the axial stress. this axial stress can be represented by which of the following equations?
In a thin wall pressure vessel, two stresses exist: the longitudinal stress and the hoop stress .
A cylinder is said to be "thin walled" if its radius to thickness (r/t) ratio is at least 10. The internal pressure that is still present in this region of the cylinder is depicted by the pressure field below. The pressure remains steady during the whole cut of the cylinder. Thick wall pressure vessels are determined by the relationship between the mean radius of the vessel and the wall thickness. If this ratio is greater than 10, the vessel is categorized as a thin wall pressure vessel.
A pressure vessel with a thick wall is one in which the ratio is less than 10.
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A venturi meter is measuring the flow of water in a pipe having cross-sectional area
of 0.0038 m², a throat with cross-sectional area of 0.00031 m² is connected to it.
If the pressure difference is measured to be 2.4 kPa, what is the speed of the water
in the pipe?
The speed of the water is 0.069 m/s
How do you determine the speed of the water?To determine the speed of the water in the pipe, you can use the Bernoulli equation, which relates the pressure, velocity, and height of a fluid in a system. In this case, the Bernoulli equation can be written as:
P + 1/2*rho*v^2 + rho*g*h = constant
where P is the pressure, rho is the density of the water, v is the velocity of the water in the pipe, g is the acceleration due to gravity, and h is the height of the fluid above a reference point.
Since the pressure difference between the two points in the pipe is known, you can rearrange the Bernoulli equation to solve for the velocity of the water in the pipe:
v = √((2*(P1 - P2))/rho)
where P1 is the pressure at the throat and P2 is the pressure at the cross-sectional area of the pipe.
Plugging in the values given in the question, we have:
v = √((2*(2.4 kPa - 0))/1000 kg/m^3)
= √(4.8 kPa/1000 kg/m^3)
= √(0.0048 Pa/kg/m^3)
= 0.069 m/s
Therefore, the speed of the water in the pipe is approximately 0.069 m/s.
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A 17.0-m-high and 11.0-m-long wall under construction and its bracing are shown in Figure 9.32. The wall is in stable equilibrium without the bracing but can pivot at its base. Calculate the force exerted by each of the 10 braces if a strong wind exerts a horizontal force of 630 N on each square meter of the wall. Assume that the net force from the wind acts at a height halfway up the wall and that all braces exert equal forces parallel to their lengths. Neglect the thickness of the wall.
The force exerted by each of the 10 braces is 2.0534 x 10⁴ N.
The force is defined as the shear stress or pressure applied per unit area.
Mathematically, F = P/ASI unit of force is Newton (N).The wall is 17.0-m-high and 11.0-m-long
Its bracing is under construction
The force is exerted by each of the 10 braces, if a strong wind exerts a horizontal force of 630 N on each square meter of the wall.
Let the net force from the wind acts at a height halfway up the wall and that all braces exert equal forces parallel to their lengths.
Considering the pivot at the base of wall.
From the equilibrium of forces, we have
r₁ * Fwind = r₁ * Fbsinθ
By substituting the values,
Fb = Fwind /10sin35°.............(1)
The wind force is also given by
Fwind = Horizontal force or pressure * Area
Fwind = F/A * hw
Fwind = 630 x 17 x 11
F wind = 117810 N
From equation (1), we have
Fb = Fwind /10sin35°
Fb = 117810 /10sin35°
Fb = 20539.54 N
0r Fb = 2.0534 x 10⁴ N
Thus, the force exerted on each of the 10 braces is 2.0534 x 10⁴ N.
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please help and explain
King Kong carries Fay Wray up the 321-meter high Empire State Building. At the top of the skyscraper, Fay Wray’s shoe falls from her foot.
Neglecting air resistance, how long does it take for the shoe to reach the ground?
The time taken for the shoe to reach the ground is 8.1 seconds.
What is the time of motion of the shoe?
The time taken for the shoe to reach the ground is known as the time of motion of the shoe.
The value of the time of motion of the shoe is calculate using the following kinematic equation.
h = vt + ¹/₂gt²
where;
h is the height of fall of the shoev is the initial vertical velocity of the shoeg is acceleration due to gravityt is the time taken for the shoe to hit the groundThe initial vertical velocity of the shoe = 0
The new equation becomes;
h = 0 + ¹/₂gt²
t = √(2h/g)
t = √(2 x 321 / 9.8)
t = 8.1 seconds
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a lightweight rope is wrapped around a 100 lb drum, passes over a frictionless pulley, and is attached to a weight w (see below). the coefficient of friction between the drum and the surfaces is 0.50. determine the maximum amount of weight that can be supported by this arrangement.
The forces that are present when there is physical contact are referred to as the contact force and the forces that are present when there is no physical contact as the field force or non-contact force.
On the hanging weight since it is the constant speed we can assume that object is in equilibrium and
Tension = m*g
Where m = mass and g = acceleration due to gravity
On the drum since it is also moving with constant angular speed net torque on it will be zero.
τ - TR =0
Where τ = torque, T= tension and R= Radius of drum = 0.5 m
Replacing the expression for Tension of the rope in above equation:
τ(torque) = mgR
Solving for m using R = 0.5m, g = 10 m/ s2 and τ = 358 N.m
m = = 179 kg
Therefore the mass is -179 kg of the torque produced by the rope.
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The distance around Earth's equator is about 24,000 miles. Use the formula in Question 4 to calculate the approximate rotational velocity at Earth's equator mph (using the fellowing formula: Velocity = Distance/Time miles/hour)
The distance around Earth's equator is about 24,000 miles. Thus, rotational velocity at Earth's equator is 1000 miles/hour.
What is rotational velocity?Every point on an object that is revolving about an axis has the same angular velocity. The tangential velocity of points distant from the axis of rotation is, nevertheless, different from that of points closer to the axis of rotation. Rotational velocity and an angular frequency vector are other names for angular velocity.
Given that,
The distance around Earth's equator is about 24,000 miles.
Time to complete one Rotation = 24 hours.
Thus, velocity = distance/time
or, velocity = 24,000 miles / 24 hours
or, velocity = 1000 miles/hour.
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which of the following is not a vector? the diameter of earth the force that represents your weight the unbalanced force from two people pushing a cart in opposite directions your displacement from walking five blocks to the north the velocity of a baseball in flight
The earth's diameter is not a vector.
Weight: Is it a vector quantity?A body's weight is a measurement of the gravitational force acting on it. Given that a force has both magnitude and direction, and since we refer to such a quantity as a vector quantity, we can infer that weight is also a vector quantity.
Which of the following is not a vector object?Response and Justification: All other quantities, with the exception of mass, have both a magnitude and a direction. Mass, however, only has a magnitude. Therefore, mass is not an illustration of a vector quantity but rather a scalar number.
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fgure 24-30 shows a system of three charged particles. if you move th particle of charge from pooint a to point d
A) Moving the three-particle system from A to D has no effect on its electric potential energy.
B) When a particle is transferred from A to D, the total electric force exerted on it produces negative work.
C) When your force is shifted from A to D, it does not produce any work.
D) The values will be zero, negative, and zero if the particle is transferred from B to C.
comprehension of the potential energy idea.The total energy resulting because of all the charges present in the system determines the total potential energy for moving a charge from one location to another. Therefore, total potential energy is positive for two positive charges.
recognizing the idea of completed work.or work done, we just take into account the polarity of charges. The effort completed for equal polarity is found to have a positive regardless of its value. Our force's course determines the job that is accomplished by our force. The work done will be negative for the opposing path and force direction.
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The complete question is -
The figure shows a system of three charged particles. If you move the particle of charge from point A to point D, are the following quantities positive, negative, or zero: (a) the change in the electric potential energy of the three-particle system, (b) the work done by the net electric force on the particle you moved (that is, the net force due to the other two particles), and (c) the work done by your force? (d) What are the answers to (a) through (c) if, instead, the particle is moved from B to C?
