A shipment of 20 DVDs has arrived at a video rental store. Based on past experience, the manager knows that 10% of all new DVDs sent to the store have a visible defect. The manager tells you to begin inspecting the new DVDs one at a time at random until you find the first DVD that has a defect. If 10% of the DVDs have a visible defect in the new shipment, what is the probability that the first DVD that has a defect is the 3rd one that you inspect? (Round your answer to 3 decimal places.)

Answer for 1.a is 6. 6 is in the thousands place.

Answer for 1.b is 9. 9 is in the thousandths place.

Answer:

8.8

Step-by-step explanation:

speed=distance/time

speed- ?

distance- 200m

time- 22.75s

?=200/22.75

?= 8.791...

round it so that it becomes 8.8

Answer:

Eight-hundred thousand plus six-thousand plus three hundred plus two  

The answer equals Eight-hundred six thousand three hundred two  

Hopefully this helps! Feel free to mark brainliest!

Answer:

eight-hundred six-thousand three-hundred and two

Step-by-step explanation:

[tex]800,000+6000+300+2[/tex] in word form

Let's separate everything.

[tex]800,000=[/tex] eight-hundred thousand

[tex]6,000=[/tex] six thousand

[tex]300=[/tex] three hundred

[tex]2=[/tex] two

So let's combine everything and make it proper.

Eight-hundred six-thousand three-hundred and two

Hope this helps!

Answer:

37

Step-by-step explanation:

Answer:

[tex] \boxed{\sf x\degree = 67\degree} [/tex]

Step-by-step explanation:

Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.

So,

⇒ 43° + 70° + x° = 180°

43° + 70° = 113°:

⇒ 113° + x° = 180°

Substracting 113° from both sides:

⇒ 113° - 113° + x° = 180° - 113°

113° - 113° = 0°:

⇒ x° = 180° - 113°

180° - 113° = 67°:

⇒ x° = 67°

The general form of a solution of the differential equation is already provided for us:

[tex]y(x) = c_1 \textrm{e}^x + c_2\textrm{e}^{-x},[/tex]

where [tex]c_1, c_2 \in \mathbb{R}[/tex]. We now want to find a solution [tex]y[/tex] such that [tex]y(-1)=3[/tex] and [tex]y'(-1)=-3[/tex]. Therefore, all we need to do is find the constants [tex]c_1[/tex] and [tex]c_2[/tex] that satisfy the initial conditions. For the first condition, we have:[tex]y(-1)=3 \iff c_1 \textrm{e}^{-1} + c_2 \textrm{e}^{-(-1)} = 3 \iff c_1\textrm{e}^{-1} + c_2\textrm{e} = 3.[/tex]

For the second condition, we need to find the derivative [tex]y'[/tex] first. In this case, we have:

[tex]y'(x) = \left(c_1\textrm{e}^x + c_2\textrm{e}^{-x}\right)' = c_1\textrm{e}^x - c_2\textrm{e}^{-x}.[/tex]

Therefore:

[tex]y'(-1) = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e}^{-(-1)} = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e} = -3.[/tex]

This means that we must solve the following system of equations:

[tex]\begin{cases}c_1\textrm{e}^{-1} + c_2\textrm{e} = 3 \\ c_1\textrm{e}^{-1} - c_2\textrm{e} = -3\end{cases}.[/tex]

If we add the equations above, we get:

[tex]\left(c_1\textrm{e}^{-1} + c_2\textrm{e}\right) + \left(c_1\textrm{e}^{-1} - c_2\textrm{e} \right) = 3-3 \iff 2c_1\textrm{e}^{-1} = 0 \iff c_1 = 0.[/tex]

If we now substitute [tex]c_1 = 0[/tex] into either of the equations in the system, we get:

[tex]c_2 \textrm{e} = 3 \iff c_2 = \dfrac{3}{\textrm{e}} = 3\textrm{e}^{-1.}[/tex]

This means that the solution obeying the initial conditions is:

[tex]\boxed{y(x) = 3\textrm{e}^{-1} \times \textrm{e}^{-x} = 3\textrm{e}^{-x-1}}.[/tex]

Indeed, we can see that:

[tex]y(-1) = 3\textrm{e}^{-(-1) -1} = 3\textrm{e}^{1-1} = 3\textrm{e}^0 = 3[/tex]

[tex]y'(x) =-3\textrm{e}^{-x-1} \implies y'(-1) = -3\textrm{e}^{-(-1)-1} = -3\textrm{e}^{1-1} = -3\textrm{e}^0 = -3,[/tex]

which do correspond to the desired initial conditions.

Answer

7 chocolates.

Step-by-step explanation:

42÷6=7

Answer:21 obviously it’s actually (19) don’t tell anyone

Step-by-step explanation:

Answer:

-5

Step-by-step explanation:

The opposite would be 5, but since we need the opposite of the opposite, the opposite of 5 is -5. Hope this helped and wasn't too confusing!

Answer: (C). There are 200 animals, and the cost is $8,000 daily.

Step-by-step explanation: We already know (x) is the number of animals measured in hundreds and it would go on the x axis. And that would mean that (f) is going to be on the y axis. Go over on the x axis 2 then for the y axis go up 8 on the y axis and you would get (2,8)= (200 animals, $8,000 a day)

There are 200 animals, and the cost is $8,000 daily

Answer:

14

Step-by-step explanation:

According to order of operations (PEMDAS), you should multiply the numbers on the two sides of the addition sign first. So:

-4 x -5 = 20

and

2 x -3 = -6

Then you add those two numbers together:

-6 + 20 = -14

Answer: 4 + (-n) and -n+4

==========================================================

Explanation:

Adding a negative is the same as subtracting. For example, 10-7 = 10+(-7)

So that's why 4-n is the same as 4 + (-n)

---------

Then we go from 4 + (-n) to -n+4 because we can add two items in any order.

Example: 2+3 = 3+2 = 5

Answer: The answer is 17

Step-by-step explanation:

Because math is easy

Answer:

No.

Step-by-step explanation:

8 doesn't equal 0 on the very right, which means it's not a solution to the equation.  So therefore, it is false based on the equation.

Answer:

Paloma and Abdul combined spent 4 hours more working on the project than Ben and Min combined.

Step-by-step explanation:

Note: This question is not complete as the bar chart is not included. The bar chart is therefore included before answering the question. Please, see the attached jpeg file for the bar chart.

The explanation to the answer is now given as follows:

From the bar chart, we have the number of hours each student spends working on the group project as follows:

Numbers of hours spent by Paloma = 21 hours

Numbers of hours spent by Adbul = 18 hours

Numbers of hours spent by Ben = 13 hours

Numbers of hours spent by Min = 22 hours

The number of hours each group spent working on the group project is calculated as follows:

Numbers of hours spent by Paloma and Abdul = Numbers of hours spent by Paloma + Numbers of hours spent by Paloma = 21 hours + 18 hours = 39 hours

Numbers of hours spent by Ben and Min = Numbers of hours spent by Ben + Numbers of hours spent by Min = 13 hours + 22 hours = 35 hours

Th number of hours Paloma and Abdul spend working on the project combined more than Ben and Min combined = Numbers of hours spent by Paloma and Abdul - Numbers of hours spent by Ben and Min = 39 hours - 35 hours = 4 hours

Therefore, Paloma and Abdul combined spent 4 hours more working on the project than Ben and Min combined.

Answer:

1.   75 degrees

2.  105 degrees

3.  35 degrees

Step-by-step explanation:

Hope this helps! :)

Answer:

acute

Step-by-step explanation:

its less then 90 degree

The ratio of number of girls and boys in a class of 30 students is 7:8

The ratio of number of girls and boys if 5 new boys admit in the class.

Let the number of students be x.

According to the question,

7x + 8x = 30

or, 15x = 30

or, x = [tex] \large {\tt {\frac{30}{15}}} [/tex]

or, x = 2

7x = 7(2) = 14

8x = 8(2) = 16

There were 14 boys and 16 girls in the school.

After admitting 5 new boys, we get

14 + 5 = 19

The ratio of number of girls and boys now is 16:19.

16:19

Answer:

x is a 33° angle

Step-by-step explanation:

The two angles are supplementary meaning the measure of both angles adds up to 180°. You can tell they are supplementary because the angle is a straight line. so all you need to do is subtact 147 from. 180 to get the measure of x .

Answer:

x+147=180 ( sum of supplementary angle)

or, x = 180-147

or, x = 33

so the value of x is 33°

Answer:

A is point ( 6, -3, 6)

Step-by-step explanation:

Here in this question, we are concerned with finding the coordinates of point A.

Since we do not know the coordinates of point A, let’s represent them as (x,y,z)

By vector properties; Mathematically ;

AB = (7,4,4) - (x , y, z)

Thus; AB = (7-x)i + (4-y)j + (4-z)k

From the question, we are told that AB is also i + 7j -2k

By comparison;

(7-x)i = i

7-x = 1

x = 7-1

x = 6

(4-y)j = 7j

4-y = 7

4-7 = y

y = -3

and lastly

(4-z)k = -2k

4-z = -2

4 + 2 = z

z = 6

So the coordinates of A are (6, -3, 6)

Answer:

D

Step-by-step explanation:

An exponential model is appropriate because the relationship between period and the log of subscribers is roughly linear and the residual plot shows no distinct pattern.

Answer:

its D

Step-by-step explanation:

By the chain rule,

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}[/tex]

It looks like we're given

[tex]\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}[/tex]

where a and b are presumably constant.

Recall that

[tex]\cos^2t=\dfrac{1+\cos(2t)}2[/tex]

[tex]\sin^2t=\dfrac{1-\cos(2t)}2[/tex]

so that

[tex]\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}[/tex]

Then we have

[tex]\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t[/tex]

[tex]\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t[/tex]

[tex]\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}[/tex]

[tex]\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}[/tex]

where the last reduction follows from dividing through everything by [tex]\cos(2t)\cos^2t[/tex] and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

Answer:

a) The standard form of [tex]z = 4\cdot (\cos 60^{\circ}+i\cdot \sin 60^{\circ})[/tex] is [tex]z = 2 + i\cdot 2\sqrt{3}[/tex], b) [tex]z = (2+i\cdot 3)^{6} = 1219.585 + i \cdot 1829.381[/tex].

Step-by-step explanation:

a) The standard form of the complex number is [tex]z = a + i\cdot b[/tex], [tex]\forall \,a,b \in \mathbb{R}[/tex]. If we get that [tex]z = 4\cdot (\cos 60^{\circ}+i\cdot \sin 60^{\circ})[/tex], whose standard form is obtained by algebraic means:

1) [tex]z = 4\cdot (\cos 60^{\circ}+i\cdot \sin 60^{\circ})[/tex] Given

2) [tex]z = (4\cdot \cos 60^{\circ})+i\cdot (4\cdot \sin 60^{\circ})[/tex] Distributive and Associative properties.

3) [tex]z = 2 + i\cdot 2\sqrt{3}[/tex] Multiplication/Result.

The standard form of [tex]z = 4\cdot (\cos 60^{\circ}+i\cdot \sin 60^{\circ})[/tex] is [tex]z = 2 + i\cdot 2\sqrt{3}[/tex].

b) The De Moivre's Theorem states that:

[tex]z = (a+i\cdot b)^{n}= r^{n}\cdot (\cos \theta + i\cdot \sin \theta)[/tex]

Where:

[tex]r =\sqrt{a^{2}+b^{2}}[/tex] and [tex]\theta = \tan^{-1} \left(\frac{b}{a}\right)[/tex].

If we know that [tex]z = (2+i\cdot 3)^{6}[/tex], then:

[tex]r = \sqrt{2^{2}+3^{2}}[/tex]

[tex]r =\sqrt{13}[/tex]

[tex]r \approx 3.606[/tex]

[tex]\theta = \tan^{-1}\left(\frac{3}{2} \right)[/tex]

[tex]\theta \approx 56.310^{\circ}[/tex]

The resulting expression is:

[tex]z = 3.606^{6}\cdot (\cos 56.310^{\circ}+i\cdot \sin 56.310^{\circ})[/tex]

[tex]z = 1219.585+i\cdot 1829.381[/tex]

Therefore, [tex]z = (2+i\cdot 3)^{6} = 1219.585 + i \cdot 1829.381[/tex].

Though I prefer to eat fruit, I enjoy vegetables too.

A homophone is a word that is pronounced the same as another word but differs in meaning.

Homophones may consist of two or more words, although pairs are more common than three or more words that sound the same. Examples of homophones that have three words are to, too, and two, and their, there, and they're.

here, we have,

Though I prefer to eat fruit, I enjoy vegetables too.

A homophone is a word that is pronounced the same as another word but differs in meaning.

Learn more about homophones here

brainly.com/question/7449238

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Answer:

12

Step-by-step explanation:

4+4+4=12

Answer:

Hi there!

Your answers are:

1) 2^4 = 2×2×2×2 = 16

2) 2^3= 2×2×2= 8

3) 2^2 = 2×2 = 4

4) 2^1 = 2

5)2^0 = 1

6)2^ -1 = .5

7) 2^ -2 = .25

8) 2^ -3 = .125

9) 2^ -4= .0625

Hope this helps